A grinding wheel of radius 0.350 m rotating on a frictionless axle is brought to rest by applying a constant friction force tangential to its rim. The constant torque produced by this force is 76.0 N m. Find the magnitude of the friction force.

Answers

Answer 1

The magnitude of the constant friction force applied tangential to the rim of the grinding wheel is 217.14 N.

What is the constant friction?

Friction force is a type of force that opposes the motion of two surfaces that are in contact.

This type of force tends to stop an object in motion from moving or sometimes it tends to stop an object at rest from moving.

The magnitude of the constant friction force applied tangential to the rim of the grinding wheel is calculated by applying the formula for torque as shown below.

τ = F r

where;

τ is the torque produce by the force of frictionr is the radius of the grinding wheel

F = τ / r

F = ( 76 N m ) / ( 0.35 m )

F = 217.14 N

Thus, the magnitude of the friction force applied tangential to the rim of the grinding wheel is a function of the torque produced and the radius of the wheel.

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Related Questions

A sound wave travels in air at a speed of 345 m/s. What would be the wavelength of a sound wave of frequency 1200 hz

Answers

Answer:

0.29 meters, or 29 centimeters.

Explanation:

The wavelength of a sound wave is related to its frequency and the speed at which it travels. The relationship between these quantities is given by the equation:

wavelength = speed / frequency

Plugging in the values given, we get:

wavelength = 345 m/s / 1200 Hz

This gives us a wavelength of approximately 0.29 meters, or 29 centimeters.

It's important to note that this is an approximate value, as the speed of sound can vary depending on the temperature, humidity, and other factors of the air through which it is traveling.

you are watching a new bridge being built near your house. you notice during the construction that two concrete spans of the bridge of total length li

Answers

The construction that two concrete spans of the bridge of total length  is 2.55m.

What is Linear expansion coefficient ?

The coefficient of linear expansion may be defined as the increase in length per unit length when the temperature is raised 1°C. Thus if the temperature of a rod of length l0 is raised from 0°C to t°C, the new length, lt, will be given by. (21.1)

Linear expansion coefficient of concrete is, [tex]$\alpha=1.2 \times 10^{-5} /{ }^{\circ} \mathrm{C}$[/tex]

Final length of the bridge,

[tex]$$\begin{aligned}& L=L_i(1+\alpha \Delta T)=260 \times\left(1+\left(1.2 \times 10^{-5} \times 16\right)\right)=260.04992 \mathrm{~m} \\& y=\frac{1}{2} \sqrt{L^2-L_i^2}=\frac{1}{2} \times \sqrt{(260.04992)^2-260^2}=2.55 \mathrm{~m}\end{aligned}$$[/tex]

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Which of the following could not be determined by an observation that only uses spectroscopy?
the chemical composition of a distant star
the angular size of a distant galaxy
the speed at which a distant galaxy is moving away from us
the surface temperature of a distant star
the rotation rate of a distant star

Answers

The angular size of a distant galaxy cannot be determined by an observation that only uses spectroscopy.

Astronomical spectroscopy can be used to examine the different wavelengths of light or radiation coming from matter found in space. Astronomical spectra can be observed to determine the chemical composition of stars and galaxies. Continuous spectrum can be examined by a researcher to determine the temperature of the star.

The angular size or angular diameter of a distant galaxy can be measured by Fourier technique. It is a technique that is based on the interference of light. Spectroscopy uses the dispersion of light to calculate a quantity.

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the atmospheric density at an altitude of 2500 km is about 1 molecule/cm3 . (a) assuming the molecular diameter of 2.0 x 10-8 cm, find the mean free path predicted by the equation:

Answers

The mean free path equation is  0.19 X 10⁻⁸ cm.

The mean free path is average distance an object will move between collisions. The actual distance a particle, such as a molecule in a gas, will move before a collision, called free path, cannot generally be given because its calculation would require knowledge of the path of every particle in the region.

Density = Mass per unit volume = N/V = 1 molecule/cm³

Altitude = 2500 Km

Diameter = d = 2 X 10⁻⁸ cm

Mean free path = λ =

= λ = 1 / [√(2πd²(N/V))]

= λ = 1 / [√(2 X 3.14 X ( 2 X 10⁻⁸ )²X (1))]

= λ = 1 / √ (25.12 X 10⁻¹⁶ )

= λ = 1 / 5.011 X 10⁻⁸

= λ = 0.19 X 10⁻⁸ cm

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Suppose that 5 J of work is needed to stretch a spring from its natural length of 24 cm to a length of 41 cm. (a) How much work is needed to stretch the spring from 32 cm to 37 cm? (Round your answer to two decimal places.) (b) How far beyond its natural length will a force of 10 N keep the spring stretched? (Round your answer one decimal place)

Answers

Stretching the spring from 32 cm to 37 cm requires 0.99J of labor.

A force of 10 N will extend a spring to its normal length of 363 cm.

These are the characteristics of a spring's spring constant, k.

1) It takes force kx to extend the spring's length.

2) A spring with length x stretched has energy kx²/2.

You can calculate k using the information provided in the manner shown below.

Work of 5J gave the spring energy k(39-28)²/2.

Therefore

5 = k(39-28)²/2

k = 10/121 N/cm

(a)

At 33cm the spring has energy k(33-28)²/2.

At 35cm the spring has energy k(35-28)²/2.

The extra energy needed is

(10/121)(35-28)²/2 - (10/121)(33-28)²/2 = 120/121 = 0.99J

(b)

30 = kx

x = 30/k = 363cm

An elastic device known as a spring is used to store mechanical energy and release it in response to the removal of an opposing force. Without the aid of motors or other powered devices, if you need to exert effort to move something or keep it in place.

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A barbell consists of two small balls, each with mass m at the ends of a very low mass rod of length d. The barbell is mounted on the end of a low-mass rigid rod of length b. This apparatus is started in such a way that while the rod rotates clockwise with angular speed , the barbell rotates clockwise about its center with an angular speed wg. What is the total angular momentum of this system about point B?

Answers

The total angular momentum of the system about point B is [tex]L=m_1r_1\omega_1+m_2r_2\omega_2[/tex]

Angular momentum, also known as moment of momentum or rotational momentum, is the rotating counterpart of linear momentum.

A rigid object's angular momentum is defined as the product of its moment of inertia and its angular velocity. If there is no external torque on the object, it is analogous to linear momentum and is subject to the fundamental constraints of the conservation of angular momentum principle. The vector quantity angular momentum It is derived from the expression for a particle's angular momentum.

Given,

mass of ball 1 = m1

m₂ mass of ball 2=m2

v₁ is the velocity of ball=r₁ω₁

v₂ is the velocity of ball 2=r₂ω₂

The total angular momentum is given as;

[tex]V_{total}=r_1\omega_1+r_2\omega_2\\\\L=m_1r_1\omega_1+m_2r_2\omega_2[/tex]

Hence the total angular momentum  will be [tex]L=m_1r_1\omega_1+m_2r_2\omega_2[/tex]

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a 10.0 gram mass is tied to a string. the string is connected to a 500.0 g mass by a string that passes over a pulley. the 10.0 gram mass is suspended over the floor. there is no friction on the table. a. draw a fbd for each mass and of the system

Answers

In physics and engineering, a free frame diagram (FBD; also referred to as a force diagram) is a graphical instance used to visualize the applied forces, moments, and ensuing reactions on a frame in a given situation.

A free-body diagram is a sketch of an item of interest with all the surrounding items stripped away and all of the forces acting on the frame shown. The drawing of an unfastened-body diagram is a critical step in the solving of mechanics issues because it helps to visualize all the forces appearing on an unmarried object.

A free-body diagram is a graphic, dematerialized, symbolic representation of the body (structure, element, or segment of an element) wherein all connecting "pieces" have been removed. An FBD is a convenient method to model the structure, structural detail, or phase that is under scrutiny.

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student uses a heavy ball attached to a rope as a pendulum in an experiment. the ball is hanging so the rope is vertical. the student pulls the ball back and releases it from rest, as shown. comparing the measured value to the expected value of the speed of the ball at the lowest point of its swing, the student finds that the ball is moving slower than expected. which of the following may account for the slower-than-expected speed?
the speed of the ball lowest point of its swing, the student finds A. The student measured the mass of the ball to be higher than it actually is. B. The student did not account for the mass of the rope. С. The angle of the swing was so high that air resistance had a significant effect. D. The ball was accidentally given a small push when it was released. E. The student did not account for the stretch of the rope caused by the weight of the ball.

Answers

Answer:-(E)

The speed of ball is slower than expected speed due to stretch in length of string. The swing rate, or frequency, of the pendulum is determined by its length. The longer the pendulum, whether it is a string, metal rod or wire, the slower the pendulum swings. Conversely the shorter the pendulum the faster the swing rate.

Mass of rope or ball does not effect speed,time period or frequency.The air resistance has no significant effect on speed of ball.

Frequency is the number of occurrences of a repeating event per unit time.  For clarity, also called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to one event per second. Duration is the reciprocal of frequency because duration is the time interval between events.

For example, if the heart beats 120 times per minute (2 hertz), the period T (the interval between repeated beats) is 0.5 seconds (60 seconds divided by 120 beats). value). Frequency is an important parameter used in science and engineering to describe the speed of vibrations and vibrational phenomena such as mechanical vibrations, audio signals (sound), radio waves, and light.

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Germanium, element 32 on the Periodic Table, is shown here. If a proton is added to the nucleus of germanium, what outcome(s) would occur? Select ALL That apply.A) The atom would increase in mass but would remain germanium.
B) The atom would become arsenic and have different properties.
The atom would remain germanium, but it would have a positive charge.
D) The atom would increase in mass and have different elemental properties.
E) The atom would expel a neutron to maintain a constant mass and chemical properties.

Answers

If a proton is added to the nucleus of germanium, the atom would increase in mass and have different elemental properties (option D).

What is mass number?

Mass number of an element is the total number of protons and neutrons in an atomic nucleus. The atomic number of the element is the number of protons contained in the nucleus of the atom.

Elements are arranged in an hierarchical order on the periodic table, which is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).

According to this question, germanium is an element on the periodic table with atomic number of 32. This means that germanium has 32 protons in its nucleus. The number of protons of an atom represents the identity of that element.

This means that adding a proton to the nucleus of germanium atom will increase it to 33, hence, changing the identity of the element.

Therefore, option D correctly describes what will happen if a proton is added to germanium atom.

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(b) What name is given to the energy needed to change the state of the liquid coolant?​

Answers

Answer:

Specific Latent Heat

Explanation:

The specific latent heat of a substance is the amount of energy needed to change the state of 1 kg of the substance without changing its temperature.

A force of 600 newtons will compress a spring of 0.5 meters. What is the spring constant of the spring?

Answers

Answer:

1200 N/m

Explanation:

k = spring constant = 600 N / .5 m = 1200 N / m

an empty, isolated parallel plate capacitor has stored energy of 1.34 J. Then a material with a dielectric constant of 7.20 is inserted between the plates. How much energy is now stored in the capacitor.

Answers

The energy stored in the capacitor after the dielectric material is inserted is approximately 9.648 joules.

How do you calculate the stored energy?

The energy stored in a capacitor is given by the formula:

E = 1/2 * C * V^2

Where E is the energy stored in the capacitor (in joules), C is the capacitance of the capacitor (in farads), and V is the voltage across the capacitor (in volts).

When a material with a dielectric constant of 7.20 is inserted between the plates of the capacitor, the capacitance of the capacitor increases by a factor of 7.20. This means that the energy stored in the capacitor also increases by a factor of 7.20.

Therefore, the energy stored in the capacitor after the dielectric material is inserted is:

E = 1.34 J * 7.20 = 9.648 J

So the energy stored in the capacitor after the dielectric material is inserted is approximately 9.648 joules.

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Nancy is running around a circular track encircling the reservoir where she grew up in Boston. As she's running, which of the following is true?
A. Her shoes need to exert a small, radially inward force on the ground to keep her body moving along the circular track.
B. Her shoes need to exert a small, radially outward force on the ground to keep her body moving along the circular track.
C. Her shoes do not need to exert any force in the radial direction to keep her moving around the circle.

Answers

Option B; Her shoes need to exert a small, radially outward force on the ground to keep her body moving along the circular track.

A body can change its state of rest or motion when an external force acts on it. It is directed and has a magnitude. Force is applied at a location known as the application, and the direction in which it is applied is referred to as the force's direction. Force is the pushing or pulling of an object. When objects interact with one another, push and pull are generated. You can also describe force using words like stretch and squeeze.

A mass-containing object's velocity changes when a push or pull is applied, according to the definition of force in physics.

Motion in physics is characterised as a shift in position with respect to time. Motion is just the movement of something, as opposed to

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A 50 g rock is launched vertically in the air by a slingshot. The slingshot exerts an average force of 53 N on the rock over a distance of 0.750 m.

Answers

The work done by the average force is 39.75 J.

What is the work done by the average force?

The work done by the average force of the slingshot is calculated by applying the following equation as shown below.

Mathematically, the formula for work done is given as;

W = Fd

where;

F is the average forced is the displacement of the rock

The given parameters include;

average force, f = 53 Ndisplacement, d = 0.75 m

The work done by the average force is calculated as follows;

W = 53 N x 0.75 m

W = 39.75 J

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A wave has peaks and troughs that can move matter up and down when the wave interacts with matter. The frequency of a wave is (Ch 5)
the number of peaks passing by any point each second.

Answers

The frequency of a wave is calculated as the number of peaks passing by any point each second.

What is Wavelength ?

Wavelength is the distance between two peaks of a wave. It is represented as λ. The formula of the wavelength is

λ = v/f

where,

λ = wavelength

v = velocity

f = frequency

What is frequency ?

Frequency of a wave is measured by calculating the number of peaks a wave covers per second.

The peaks of a wave are the points where the wave has the highest energies. The peak can also be defined as the point where a wave has the highest amplitude.

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a diving board of length 3.00 m is supported at a point 1.00 m from the end, and a diver weighing 450 n stands at the free end (figure 1). the diving board is of uniform cross section and weighs 260 n. a) Find the magnitude of the force at the support point?
b) Find the direction of the force at the support point? (upward or downward)
c) Find the magnitude of the force at the left-hand end?
d) Find the direction of the force at the left-hand end. (upward or downward)

Answers

a)The magnitude of force at the support point is 1455 N.

b)The direction of the force at the supporting point is in equilibrium.

c)The magnitude of force at the left-hand end is 1030 N.

d)The direction of force at the left-hand end is equilibrium.

Given,

length of board = 3m

distance of pivot = 1.0m

weight of diver = 450N

weight of diving board = 260N

a)

The force at the support point is the sum of all forces multiplied by their distance.

[tex]F_s=f_1d_1+f_2d_2\\[/tex]

here,

f1 = force applied by diver=450 N

d1=distance covered by diver i.e. 1.5 m(half the distance of diving board, because as diver it standing at the centre of board/centre of gravity)

f2=force applied by diving board =260 N

d2=distance covered by diving board = 3m

Now,

[tex]F_s=(450*1.5)+(260*3)\\\\F_s=675+780=1455 N[/tex]

c)

The total torque is zero then,

[tex]f_ld_l-f_1d_1-f_2d_2=0[/tex]

here,[tex]d_1 =1.5-1=0.5m,\d_2=2\ and\ d_l=1m[/tex]

[tex]f_ld_l=f_1d_1+f_2d_2\\\\f_l=(260*0.5)+(450*2)=1030N[/tex]

b) and d)

Because the diver exerts force on both sides at the free end, there is no net force exerted on an object, and it is said to be in equilibrium .Thus, the direction of acting force acting is balanced.

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What Are Balanced and Unbalanced Forces?

Answers

Balanced forces are equal in size and opposite in direction, whereas unbalanced forces are not equal in magnitude.

When forces are balanced, there's no alter in motion. In one of your circumstances within the last section, you pushed or pulled on an object from opposite directions but with the same force. To have unbalanced forces implies that the force applied in one direction is greater than the force applied within the opposite direction. When unbalanced forces are acting on an object, there's an alteration in speed and/or direction. By applying an unequal force, you'll be able to alter the motion of an object. Unbalanced forces can make an object at rest begin moving, make a moving object halt, or alter the direction and speed of the object.

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A beam of protons moves in a circle of radius 0.25 m. The protons move perpendicular to a 0.44-T magnetic field. (a) What is the speed of each proton? (b) Determine the magnitude of the centripetal force that acts on each proton.

Answers

(a) Each proton travels at a speed of V= 6.898*106 m/s.

(b) The magnitude of a centripetal force acting on each proton is Fc = 3.97*1013.

What force has centripetal motion?

Centripetal or centrifugal are the forces produced when rotating objects. An object is kept moving in a circle by the centripetal force, which is always directed to towards the center of the circle.

Three instances of centripetal acceleration is?

The stress on the rope pushes the object toward the center when you spin a ball around a string or twirl a lasso. When a car is spinning, the force between the earth and also the wheels produces the centripetal force.

Briefing:

r = 0.25

q = 1.6 * 10⁻¹⁹C

B = 0.44 T

m = 1.67 * 10⁻²⁷ kg

Fb = Fc

qvB = mv²/r

qB= mv/r

(1.6 * 10⁻¹⁹)*0.44 = 1.67 * 10⁻²⁷ * v/2

v= 6.898* 10⁶ m.s⁻¹

centripetal force, Fc = m*v2/r

Fc = 1.67 * 10⁻²⁷ * (6.898* 10⁶)2/0.2

Fc = 3.97*10⁻¹³

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Please choose from the bold
1. The mass of a 4/2He nucleus is (greater than / equal to / less than ) the sum of the masses of two protons and two neutrons, all separated from each other.
2. The mass of a 3/2 He nucleus is (greater than / equal to / less than ) the sum of the masses of a 1/1H
nucleus and a 2/1H nucleus, separated from each other.
3. The mass of a 235/92 U nucleus is (greater than / equal to / less than ) the sum of the masses of a 141/56 Ba
nucleus and a 92/36 Kr nucleus, and two neutrons, all separated from each other.
4. The mass of a 56/26 Fe nucleus is (greater than / equal to / less than ) the sum of the masses of a 26/12 Mg
nucleus and a 30/14 Si nucleus, separated from each other.
Thanks

Answers

1) Nucleus is less than the sum of the masses of two protons and two neutrons. 2)  Nucleus is less than the sum of the masses of a nucleus. 3) The third option is greater than. 4) The fourth option is equal to.

1) The mass of a ₂⁴He nucleus is less than the sum of the masses of two protons and two neutrons, all separated from each other.

2) The mass of a ³₂He nucleus is less than the sum of the masses of a ¹₁H nucleus and a ²₁H nucleus, separated from each other.

3) The mass of a ²³⁵₉₂U nucleus is greater than the sum of the masses of a ¹⁴¹₅₆Ba nucleus and a ⁹²₃₆Kr nucleus, and two neutrons, all separated from each other.

4) The mass of a ⁵⁶₂₆Fe nucleus is equal to the sum of the masses of a ²⁶₁₂Mg nucleus and a ³⁰₁₄Si nucleus, separated from each other.

Therefore, 1) Nucleus is less than the sum of the masses of two protons and two neutrons. 2)  Nucleus is less than the sum of the masses of a nucleus. 3) The third option is greater than. 4) The fourth option is equal to.

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light striking a metal surface causes electrons to be emitted from the metal via the photoelectric effect. part a in a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased? check all that apply. view available hint(s)for part a in a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?check all that apply. the work function of the metal decreases. the number of electrons emitted from the metal per second increases. the maximum speed of the emitted electrons increases. the stopping potential increases.

Answers

The correct answer is that the number of electrons emitted from the metal per second increases as the intensity of the incident light is increased.

This is due to the fact that more energy is being absorbed by the metal and so more electrons can be excited to a higher energy level and then emitted through the photoelectric effect. The work function of the metal remains constant, as does the temperature of the metal.

The maximum speed of the emitted electrons and the stopping potential will increase as the intensity of the incident light increases since more energy is being absorbed and more electrons will be emitted with higher kinetic energy.

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Two vectors A and B have components (0, 1) and (-1, 3), respectively. What are the components of the sum of these two vectors?

Answers

The x and y components of the sum of these two vectors are -1 unit and 4 unit respectively.

What is vector?

In physics, a vector is a quantity with both a magnitude and a direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

Given that the two vectors A and B have components (0, 1) and (-1, 3), respectively.

Hence,

The x component of the sum of these two vectors is = 0+ (-1)unit  = -1 unit.

the y component of the sum of these two vectors is = 1 + 3 unit  = 4 unit.

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A hiker of mass 69 kg is going to climb to the top of Mount Tam, which has an elevation of 2.574 ft. 4 50% Part (n) If the hiker starts climbing at an elevation of 395 ft what will their change in gravitational potential energy be, in joules, once they reach the top? Assume the zero of gravitational potential energy is at sea level AV- Grade Summary Deductions 0 Potential 100 Soheissions Atempts remaining: e per attempt detailed view sino cos tan cotano asino acos atan acotano sinho cosh tanho cotanho Degrees O Radians ( 7 8 9 ET 4 5 6 123 + - 0 vo Submit Hini I give up! Hints: deduction per hint. Hints remaining: Feedback deduction per feedback A 50% Part (b) Repeat the above calculation for the change in gravitational potential energy, but assume the gravitational potential is zero at the top of the mountain

Answers

a. The gravitational potential energy change is 449.105 kJ

b. The gravitational potential energy change is 449.105 kJ

What is gravitational potential energy?

Gravitational potential energy is the energy due to the position of an object. It is given by U = mgh where

m = mass of object, g = acceleration due to gravity and h = height of object

Part (a) If the hiker starts climbing at an elevation of 395 ft what will their change in gravitational potential energy be, in joules, once they reach the top?

Since the mountain is 2574 ft high, the gravitational potential energy change is given by ΔU = mg(h' - h) where

m = mass of man = 69 kgg = acceleration due to gravity = 9.8 m/s²h = height at top of mountain = 2574 ft = 2574 × 0.3048 m = 784.56 m and h' = height where he starts climbing = 395 ft = 395 × 0.3048 m = 120.40 m

Substituting the values of the variables into the equation, we have

ΔU = mg(h' - h)

ΔU = 69 kg × 9.8 m/s²(784.56 - 120.40) m

ΔU = 69 kg × 9.8 m/s² × 664.16 m

ΔU = 449104.992 J

ΔU = 449.104992 kJ

ΔU ≅ 449.105 kJ

So, the gravitational potential energy change is 449.105 kJ

Part (b) Repeat the above calculation for the change in gravitational potential energy, but assume the gravitational potential is zero at the top of the mountain?

We know that the gravitational potential energy change is ΔU = U' - U = mg(h' - h) where

U' = gravitational potential energy at top = 0, U' = gravitational potential energy at starting point, m = mass of man = 69 kg g = acceleration due to gravity = 9.8 m/s²h = height at top of mountain = 2574 ft = 2574 × 0.3048 m = 784.56 m and h' = height where he starts climbing = 395 ft = 395 × 0.3048 m = 120.40 m

Substituting the values of the variables into the equation, we have

ΔU = U - U' = mg(h' - h)

ΔU = 0 - U' = 69 kg × 9.8 m/s²(784.56 - 120.40) m

ΔU = 69 kg × 9.8 m/s² × 664.16 m

ΔU = 449104.992 J

ΔU = 449.104992 kJ

ΔU ≅ 449.105 kJ

So, the gravitational potential energy change is 449.105 kJ

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Consider the following weighted, directed graph, representing the state space for a search problem. The weight between two nodes (u, v) indicates the cost of moving from node u to node v. The heuristic function value h(n) for each node n is also shown next to the node. The node S is the start state, and the node G is the goal state. h = 2 2 A 2 h = 3 h = 4 S 3 2. B 3 G) h = 0 h = 1 5 D 2 h = 2 Consider the following statement: 'The heuristic function his admissible' The statement is Select one: O True O False

Answers

True; The heuristic function his admissible.

When there are no specific solutions or the time required to find a solution is too great, a heuristic function (algorithm) or simply a heuristic is a shortcut to issue solving. We can infer that the objective is to locate a quicker or more approximate solution, even if it is not the best one. In other words, while applying a heuristic, we compromise accuracy for solution speed.

For instance, greedy algorithms typically result in speedy but inadequate answers. In the following tree, a greedy algorithm that seeks the highest sum would take the red path, but the green path is the best one

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which of the following statements about a mercury barometer are correct? select all that apply. multiple select question. the atmospheric pressure is proportional to the height of the mercury in the tube. the space above the mercury in the inverted tube contains air at atmospheric pressure. the mercury tube is sealed at the top. the barometer contains a tube filled with mercury that is inverted in a container of mercury.

Answers

The mercury tube is sealed at the top, and ambient pressure is inversely proportional to the height of the mercury within.

On Mercury, are people still alive?

Living on Mercury wouldn't be simple, but it might not be impossible. Remember that you wouldn't last very long without a space suit because there isn't any atmosphere up there. On top of all of this, Mercury experiences one of the Solar System's biggest temperature variations.

What makes Mercury so valuable?

Mercury is frequently utilized in numerous devices, including switches and batteries, since it is an effective electrical conductor. In small-scale mining operations, it is utilized to amalgamate gold and silver because it easily joins with other metals.

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if electronmagnetic radiatn a has a lower frequency than electromagnetic radion then b, then compared to the wavelegnth of a is ____.

Answers

As the frequency of radiation A is lower than that of radiation B. Then the wavelength of A will be more than that of radiation B.

The formula for the wavelength of radiation is

                    λ = v/f

where λ is the wavelength of the radiation

          c is the speed of the radiation

          f is the frequency of this radiation.

Both the frequency and wavelength were indirectly proportional to each other. The longer the wavelength, the lower will be the frequency and vice versa. The speed at which a wave propagates is equal to the product of its frequency and wavelength, justifying the link between these two parameters.

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Two sinusoidal waves traveling in opposite directions interfere to produce a standing wave with the following wave function, where x is in meters and t is in seconds.y = (1.50 m) sin(0.900x) cos(900t)Determine the wavelength of the interfering waves.mWhat is the frequency of the wave?HzFind the speed of the wave.m/s

Answers

The speed of the wave is 0m/s.

What is speed?

The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.

we can see that k = 0.9

wavelength = 2pi/k = 2pi/0.9=6.98

w = 900

f = w/2pi=900/2pi=143.2

v = w/k = 900/0.9=1000 m/s

If you look at the expression you must see a wave.

y = sin(0.3.x)

the wavelength 0.3.x = 2.pi gives x = 20.9 m

the frequency of the wave is the number of times the wave makes a full cycle per second. So every time 300.t = 2.pi makes a cycle. gives t = 2.pi/300 = 0.021

the frequency = 1/t = 47.8 sec^(-1) or 47.8 Hz

As it is a standing wave the speed is 0.

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A heavy piece of hanging sculpture is suspended by a 90
c
m
long 5.0
g
steel wire. When the wind blows hard, the wire hums at its fundamental frequency of 95
H
z
.
What is the mass of the sculpture?

Answers

The sculpture measures 16.70 kg, which is in accordance with the requirement.

Why would one use wire?

Wires, often in the form of a wire rope, are used to transport mechanical loads. In the realm of electricity with telecoms transmissions, a "wire" might be an electrical cable. The "solid core" of this kind of cable might be formed of a wired connection or numerous strands that have been braided or stranded together.

Briefing:

Use the string's tautness' fundamental frequency as a formula.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where,

f= frequency in Hertz =95Hz

T = String tension equals Mg

M represents the sculpture's mass, thus what is it?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

Mass density is equal to mass of string divided by string length.

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

95 = 1/(2*0.9) √(T/0.0056)

171 = √(T/0.0056

Square both sides

29241 = T/0.0056

T= 163.74N

Recall that T =Mg

116.12= M * 9.8

M=163.74/9.8

M= 16.70kg

Consequently, the sculpture weighs 16.70kg.

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Danger Through Electromagentism Just for fun, you decide to build a powerful hand-held electromagnet that can generate a field strength of 0.5 T. You realize that by using a solenoid with a ferromagnetic core, you can achieve the desired field using a current of only 0.20 amps in the solenoid. You wind a copper wire several hundred times around an iron core, to build a solenoid with a resistance of 30 ohms and selfinductance of 0.50 H. You hook up the solenoid in series with a suitable emf, along with a simple on/off toggle switch. When you flip the switch on, you realize that a 0.5 T magnet is MUCH too strong to handle safely, so you quickly switch it back off againâbut when you do, you receive a really nasty electrical shock from the switch. On the way back from the ER, you wonder what average voltage was generated across the switch, just after it was opened. A quick internet search tells you that a typical current requires about 250 microseconds to die off to zero, after a toggle switch is opened.

Answers

Initial magnetic flux through the coil = LI

where L = inductance and I current through the coil

Final magnetic flux when the switch was opened =0

Flux change = LI -0=LI

Average voltage generated across the switch just after it was opened

= |LI/dt|

Given L = 0.50 H

        I = 0.20 Amp

       dt = 250*10^-6 Sec

Voltage generated = (0.50*0.20)/(250*10^-6)=400 volt

Voltage, also called electromotive force, is surely the energy in line with unit charge. In other phrases, voltage is the difference in electric powered capacity among two factors. Cutting-edge is simply the price of drift of electrical charge.

We outline voltage as the amount of capability electricity among  points on a circuit. One point has greater charge than any other. This distinction in fee among the 2 points is referred to as voltage.

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400 volt

Initial magnetic flux through the coil = LI

where L = inductance and I current through the coil

Final magnetic flux when the switch was opened =0

Flux change = LI -0=LI

Average voltage generated across the switch just after it was opened

= |LI/dt|

Given L = 0.50 H

        I = 0.20 Amp

       dt = 250*10^-6 Sec

Voltage generated = (0.50*0.20)/(250*10^-6)=400 volt

Magnetic Flux:

Specifically in electromagnetism, the magnetic flux through a surface is the integral of the normal component of the magnetic field B across that surface. Usually displayed as Φ or ΦB. The SI unit of magnetic flux is Weber and the CGS unit is Maxwell.

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Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed on a screen that is 2.42 m from the grating. In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 2.86 mm. What is the difference between these wavelengths?

Answers

The difference between these wavelengths is 15.85 nm.

What is wavelengths?

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

The number of lines on the grating N= 900 cm

Distance between screen grating L= 2.24 m

Order number = 1

Distance y = 3.20 mm

We need to calculate the width of the slit

Using formula of width

[tex]d=\frac{1}{N}$$[/tex]

Put the value into the formula

[tex]$$\begin{aligned}d & =\frac{1}{900} \\d & =0.00111=1.11 \times 10^{-5} \mathrm{~m}\end{aligned}$$[/tex]

We need to calculate the angular distance

[tex]$$\theta=\frac{\lambda}{d}$$[/tex]

The angular separation for different wavelength is

[tex]$$\Delta \theta=\frac{\lambda_1-\lambda_2}{d}$$[/tex]

We know that,

Linear separation is

[tex]$$\Delta y=\Delta \theta L$$[/tex]

We nee to calculate the difference between these wavelengths Put the value into the formula of angular separation

[tex]\begin{aligned}& \Delta y=L\left(\frac{\lambda_1-\lambda_2}{d}\right) \\& \lambda_1-\lambda_2=\frac{\Delta y \times d}{L} \\& \lambda_1-\lambda_2=\frac{3.20 \times 10^{-3} \times 1.11 \times 10^{-5}}{2.24} \\& \lambda_1-\lambda_2=1.585 \times 10^{-8} \\& \lambda_1-\lambda_2=15.85 \mathrm{~nm}\end{aligned}[/tex]

Hence, The difference between these wavelengths is 15.85 nm.

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Pulley Block A of mass 4m is attached by a light string to block B of mass 2m. The string passes over a pulley with negligible friction and of negligible mass. Block A is held a distance h above the ground, as shown. The blocks are released from rest, and block A reaches the ground two seconds later. The value of h is most nearly
a. 13.3 m b. 6.7 m c. 3.3m d. 2 m

Answers

The value of h is most nearly 6.7 m.  option B is the correct answer

From the question, we have

Body mass m1 = 4 kg

mass of the body on the ground m2 = 2 kg

descent time t = 2s

From Newton's second law,

         T - W₁ = m₁ a

        -T + W₂ = m₂ a

Solving, we get

a = -3.27 m / s²

y = y₀ + v₀ t + ½ a t²

0= y₀ + 0  +½ a t²          

y₀ = ½ 3.27 2²

y₀ = 6.54 m

The value of height is most nearly 6.7 m

Kinematics:

The net force, the mass, and the acceleration of a body are related by Newton's second law.

     ∑ F = m a

Kinematics investigates how objects move while searching for connections between position, speed, and acceleration.

y = v₀ t + ½ a t²

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