A grocery store had 38 employees but then they hired 4 more people. What is the percent change in their staff?

Refer to the figure given below while reading the solution.

Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.

And then position B when traveled 5 m towards the right turning 90°.

We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).

Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).

Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.

So, the average of the shortest distances of B from each side is [tex]\frac{(AC-AD)+44-(AC-AD)+(AC+AD)+44-(AC+AD)}{4}=\frac{44+44}{4}=22[/tex]

Hence, the average of the shortest distance of B from each side is 22 m

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Answer:

x-intercept: (-5, 0)

y-intercept: (0, -4)

Step-by-step explanation:

The x-intercept is as the name implies when the line intersects the x-axis (the horizontal axis) or when y is equal to 0. If you look at the graph it intersects the x-axis at (-5, 0). The y-intercept follows the same concept except it's when it intersects the y-intercept (vertical axis) or when x is equal to 0. If you look at the graph it, it intersects the y-axis at (-4, 0).

The particle's velocity at time [tex]t[/tex] is equal to the first derivative of its position at that time, and acceleration is the second derivative.

We have

[tex]s(t) = -4\sin(t) - \dfrac t2 + 10 \implies s'(t) = -4\cos(t) - \dfrac12 \implies s''(t) = 4\sin(t)[/tex]

Find when the velocity is zero:

[tex]s'(t) = -4\cos(t) - \dfrac12 = 0 \implies \cos(t) = -\dfrac18 \implies t = \cos^{-1}\left(-\dfrac18\right) \approx 1.696[/tex]

At this time, the acceleration of the particle is approximately

[tex]s''(1.696) \approx \boxed{3.969}[/tex]

(B)

Answer:

20

Step-by-step explanation:

the inverse of

y=1/2x + 10

is

x=1/2y+10

from here you just solve for y

x-10 = 1/2y

2(x-10) = y

2x-20 = y

Answer:

Show the process

Answer:

19

Step-by-step explanation:

Answer:

87 = <1

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the two opposite interior angles.

124 = 37 + <1

Subtract 37 from each side

124 -37 = <1

87 = <1

Answer:

1728 cm³

Step-by-step explanation:

 Finding the volume of a cube is a simple process that is easy to remember. The formula for finding the volume of a cube is commonly taught as L × W × H (Length × Width × Height). This formula also works with finding the volume of rectangular prisms.

 Since the shape you're finding the volume of is cube, the length is equal to its width as well as its height.

 The first step of this problem is to plug in known values to the formula. Since length L = 12 cm, width W and height H are also equal to 12 cm.

 12 × 12 × 12 is the new expression. The next step is to simplify this expression by multiplying.

 Based on times tables, 12 × 12 = 144. So, the expression can be partially simplified to 144 × 12 for easier multiplication.

 144 × 12 can be split into an addition problem based on the Distributive Property of Multiplication:

144 × (10 + 2)              Expand the expression to remove parentheses.

144 × 10 + 144 × 2       Multiply 144 × 10 and 144 × 2.

1440 + 288                 Add the two addends.

1728                            Remember to add back the units!

1728 cm³

The volume of a cube with side lengths of 12cm is 1728 cm³.

Note:

This step-by-step explanation is for better understanding how to do this mentally or without a calculator. In a calculator, finding the volume of a cube can be found by inputting either of these:

(Side Length) × (Side Length) × (Side Length) =

(Side Length) [(x³) or (³), depending on the model of calculator] =

Option B is correct for the given system of equations.

The given system of equations 13(v-w)=52 and 12(v+w)=72.

In mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.

Now, 13(v-w)=52⇒v-w=4-----(1) and 12(v+w)=72⇒v+w=6------(2).

By adding (1) and (2), we get

v-w+v+w=4+6⇒2w=10⇒w=5

By substituting w=5 in equation (1), we get v-5=4⇒v=9.

Thus, the statement "Andy flew his model aeroplane at full speed straight into the wind for 13 seconds before turning it around and flying directly with the wind for 12 seconds. The aeroplane flew 72 yards on the way out and 52 yards on the way back" is correct for the given system of equations.

Therefore, option B is correct for the given system of equations.

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If we evaluate at infinity, we have:

                        [tex]\bf{\displaystyle L = \lim_{x \to \infty}{\frac{\log(x^8 - 5)}{x^2}} = \frac{\infty}{\infty} }[/tex]

However, the infinity of the denominator has a higher order. Therefore, we can conclude that  [tex]\boldsymbol{L = 0.}[/tex]

However, proving that the limit is 0 without using L'Hopital or the "order" criterion is complicated. To do so, let us denote:

                           [tex]\boldsymbol{\displaystyle f(x) = \frac{\log(x^8 - 5)}{x^2} }[/tex]

To find the limit, we must look for two functions h(x) and g(x) such that h(x)≤ f(x)≤ g(x) and

                               [tex]\boldsymbol{\displaystyle \lim_{x \to \infty}{h(x)} = 0, \qquad \lim_{x \to \infty}{g(x)} = 0}[/tex]

If we find these functions, then we can conclude that [tex]\bf{\lim_{x \to \infty}{f(x)} = 0.}[/tex]

First, let's note that when x⁸ - 5 > 1, then log(x⁸ - 5) > 0 (and this is true when x is large). Likewise, we have that x² > 0 for x > 0. Therefore, we have:

                                   [tex]\boldsymbol{\displaystyle f(x) = \frac{\log(x^8 - 5)}{x^2} \geq 0}[/tex]

when x "is big enough". Thus, we have h(x) = 0 where it is clear that [tex]\bf{\lim_{x \to \infty}{h(x)} = 0.}[/tex]

To find the second function, let's first note that \log is an increasing function, so since x⁸ ≥ x⁸ - 5, then log(x⁸) ≥ log(x⁸ - 5). So we have to

                [tex]\boldsymbol{\displaystyle \frac{\log(x^8 - 5)}{x^2} \leq \frac{\log(x^8)}{x^2} }[/tex]

now, if we take y = e^y, then we can write

                  [tex]\boldsymbol{\displaystyle \frac{\log(x^8)}{x^2} = \frac{\log(e^{8y})}{e^{2y}} = \frac{8y}{e^{2y}}}[/tex]

A very important property about the exponential function is

                    [tex]\boldsymbol{\displaystyle e^x > \frac{x^n}{n!}}[/tex]

For any n [tex]\bf{n \in \mathbb{N}}[/tex] and x > 0. If we take n = 2, then we have

                    [tex]\boldsymbol{\displaystyle e^{2y} > \frac{(2y)^2}{2!} = \frac{4y^2}{2} = 2y^2}[/tex]

From this it follows that

                     [tex]\boldsymbol{\displaystyle \frac{1}{e^{2y}} < \frac{1}{2y^2} }[/tex]

Therefore, we have to

                    [tex]\boldsymbol{\displaystyle \frac{\log(x^8 - 5)}{x^2} \leq \frac{\log(x^8)}{x^2} < \frac{8y}{2y^2} = \frac{4}{y} = \frac{4}{\log x} }[/tex]

yes, [tex]\bf{g(x) = 4/\log x}[/tex] where [tex]\bf{\lim_{x \to \infty}{g(x)} = 0}[/tex]. Also, [tex]\bf{h(x) \leq f(x) < g(x)}[/tex]. Therefore, [tex]\bf{\lim_{x \to \infty}{f(x)} = 0}[/tex].

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\sf{\purple{Pisces04}}}}}}}[/tex]

The circumcenter is the center of the circle which goes through the triangle's vertices, so the circumcenter of the triangle and the center of that circumscribed circle MUST be the same point.

The same goes for the incenter and the center of the inscribed circle, though these will not, in general, be the same point as the circumcenter.

Answer: Another name of circumcenter is, " Circumscribed circle ". The circumcenter is the center point of the circumcircle drawn around a polygon. The circumcircle of a polygon is the circle that passes through all of the polygon's vertices & the center of that circle is called the circumcenter. All polygons that have circumcircles are known as cyclic polygons. However, all polygons does not have a circumcircle. Only regular polygons, triangles, rectangles, and right-kites can have the circumcircle and thus the circumcenter as well.

You may find that the circumcenter of a triangle as the most common thing asked in exams and it is generally what schools begin with. So, some brief information about the circumcenter of a triangle is given below. You may safely ignore them if you haven't learned them yet.

The circumcenter of triangle can be found out as the intersection of the perpendicular bisectors (the lines that are at right angles to the midpoint of each side) of all sides of the triangle. This means that the perpendicular bisectors of the triangle are concurrent (meeting at one point). All triangles are cyclic and hence, can circumscribe a circle, therefore, every triangle has a circumcenter.

Property 1: All the vertices of the triangle are equidistant from the circumcenter.

Property 2: All the new triangles formed by joining O to the vertices are Isosceles triangles.

Property 3: Circumcenter lies at the midpoint of the hypotenuse side of a right-angled triangle

Property 4: In an acute-angled triangle, circumcenter lies inside the triangle

Property 5: In an obtuse-angled triangle, it lies outside of the triangle

Note- Location for the circumcenter is different for different types of triangles.

The circumcenter of any triangle can be constructed by drawing the perpendicular bisector of any of the two sides of that triangle. The steps to construct the circumcenter are:

P(X, Y) = [(x1 sin 2A + x2 sin 2B + x3 sin 2C)/ (sin 2A + sin 2B + sin 2C), (y1 sin 2A + y2 sin 2B + y3 sin 2C)/ (sin 2A + sin 2B + sin 2C)]

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Answer:

2(0.4)^-2 = 12.5

Step-by-step explanation:

do math noob

The correct statements are options C and option D.

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than.

The inequality is -3(2x - 5) < 5(2 - x)

At first, simplify each side

-3(2x - 5) = -3(2x) + -3(-5)

Remember (-)(-) = (+)

-3(2x - 5) = - 6x + 15

5(2 - x) = 5(2) + 5(-x)

Remember (+)(-) = (-)

5(2 - x) = 10 - 5x

- 6x + 15 < 10 - 5x

Subtract 15 from both sides

- 6x < -5 - 5x

Add 5x to both sides

- x < - 5

Remember the coefficient of x is negative, then when you divide both sides by it you must reverse the sign of inequality

The coefficient of x is -1

Divide both sides by -1

x > 5

Therefore the correct statements are options C and option D.

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Answer:

I will assume the equation is supposed to be f(x) = x^2 – 5x + 12 since it is said to be a quadratic equation.

Step-by-step explanation:

See attached graph.

The value of f(–10) = 82     False

      f(-10) = (-10)^2 - 5*(-10) + 12

       f(-10) = (100) +50 + 12

      f(-10) = 162

The graph of the function is a parabola.  True

The graph of the function opens down.   False

The graph contains the point (20, –8).      False

The graph contains the point (0, 0).          False

The inverse function of g(x) will be g⁻¹(x) = (4x + 3) / 2. Then the value of the inverse function, at x = -3, will be 4.5.

Let the function will be

f: X → Y

Then the inverse function will be

f⁻¹: Y → X

The function is given below.

g(x) = (2x – 3) / 4

Then the inverse function of g(x) will be

g⁻¹(x) = (4x + 3) / 2

Then the value of the inverse function, at x = -3, will be

g⁻¹(-3) = [4(-3) + 3] / 2

g⁻¹(-3) = -4.5

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Answer:

4 days

Step-by-step explanation:

1) Derive a formula.

Let b = bicycle

Let x = the number of days

A set up equation: b = 6x + 15

2) If she pays 39 to hire a bicycle, substitute 39 into b, then solve for x.

39 = 6x + 15

39 - 15 = 6x

24 = 6x

24/6 = x

4 = x

x = 4

Since x is the number of days, she hired the bicycle for 4 days.

Answer:

The answer for this question is c

The value of x from the quadratic term equation is x = ( -11/2 ) ± ( 5√5 ) / 2

A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

where ( b² - 4ac ) is the discriminant

when ( b² - 4ac ) is positive, we get two real solutions

when discriminant is zero we get just one real solution (both answers are the same)

when discriminant is negative we get a pair of complex solutions

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

x² + 11x + 121/4 = 125/4

Subtracting ( 125/4 ) on both sides , we get

x² + 11x + ( 121 - 125 ) / 4 = 0

x² + 11x - 1 = 0   be equation (1)

On simplifying , we get

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

So , x = [ -11 ± √ ( 11 )² - 4 ( 1 ) ( -1 ) ] / 2

On further simplification , we get

x = -11 ± √ ( 121 + 4 ) / 2

x = [ -11 ± √125 ] / 2

x = ( -11/2 ) ± ( 5√5 ) / 2

Therefore , the roots of the equation are x = ( -11/2 ) ± ( 5√5 ) / 2

Hence , the quadratic equations are solved

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Answer:

  (a)  18%

Step-by-step explanation:

The debt to credit ratio is found by dividing his debt by his credit limit.

__

  ratio = debt/credit limit = $1551.42/$8619.00 ≈ 0.18 = 18%

Quentin's debt to credit ratio is 18%.

Let's set up some variables:

Let's set up some equations based on the informative given:

             (Mathematical form) g = 12b

             (Mathematical form) g = b + 77

Let's put the equation together:

 g = 12b         -- equation 1

 g = b + 77     -- equation 2

  (equation 2)'s value of g into (equation 1)

  12b = b + 77

   11b = 77

    b = 7

There are 7 boys.

Answer: 7 boys

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The LCM of the given numbers have been determined.

LCM stands for Least Common Multiple .

For two numbers , LCM is the number that is the smallest number of which they both are a factor.

It is asked to determine

LCM of 6 and 9

6 = { 6 , 12 , 18 , 24 , 30 , 36 , 42 .....}

9 = { 9 , 18 ,27 .....}

The LCM of 6 , 9 is 18

LCM of 8 and 12

8 = { 8,16,24,32....}

12 = {12 , 24 ,36....}

The LCM of 8 and 12 is 24

LCM of 4 , 6 and 8

4 = {4 , 8 , 12 , 16 , 20,24,28 ....}

6 = { 6 ,12 ,18,24......}

8 = {8 , 16,24 .....}

The LCM of 4,6 and 8  is 24

The LCM of 6 and 15 is 30  

The LCM of 20 and 30 is  60

The LCM of 25,30 and 75 is 150

The image of the solution is attached .

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Each pizza cost $ 12.65

An Equation is used in determination of unknown variables in an expression .

It is given that

Brian ordered 3 large cheese pizzas and a salad.

The salad cost $4.95

Total amount spend = $47.60

Tip = $5

The amount spend in food is $ 47.60-5

= $42.60

Let the price of Pizza is x then the equation that can be formed to determine the price of pizza is

3x + salad = 42.60

3x + 4.95 = 42.60

3x = 37.65

x = $12.65

Therefore each pizza cost $ 12.65

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Answer:

12.55

Step-by-step explanation:

Answer:

35$

Step-by-step explanation:

You multiply $2 x 10 = 20$ then add 15$ + 20$ = 35$

The figure is the combination of trapezoid and square. Then the area of the figure will be 39 square meters.

The complete question is attached below.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The figure is the combination of trapezoid and square.

Then the area of the geometry will be

Area = Area of trapezoid + Area of square

Area = 1/2 x (3 + 9) x 5 + 3 x 3

Area = 30 + 9

Area = 39 square meters

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Answer:

Just simply input in your calculator arcsin of -5/6. Arcsin is the sign that looks like sin to the power of -1, even though it doesn't mean sin to the power of -1. This comes out to 303.6 degrees. So, it actually isn't in quadrant 3, it's in quadrant 4.

Step-by-step explanation:

Answer: C. 7.5%

Solve as decimal

0.5*0.15=0.075

Move two decimal points over

0.075 -> 7.5

Change back to percent

7.5%

Answer:

C

Step-by-step explanation:

We have

y - 5 = -2(x + 4)

Expanding the RHS by multiplying by 2 gives us

y - 5 = -2x -8

Moving -5 from LHS to RHS (reverses sign)
y = -2x -8 + 5   or
y = -2x -3

C. y=-2x - 3 , equation describes the same line as y- 5 = -2(x+4).

Here, we have,

We have been given an equation in point-slope form and we are asked to find the equation of same line.

y- 5 = -2(x+4)

Upon using distributive property , we will get,

=> y- 5 = -2x - 8

We have

y - 5 = -2(x + 4)

Expanding the RHS by multiplying by 2 gives us

y - 5 = -2x -8

Moving -5 from LHS to RHS (reverses sign)

y = -2x -8 + 5   or

y = -2x -3

Therefore, the equation y = -2x -3 represents the same line as our given equation.

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Answer:

distance between -5 to 0 = 5 units