Answer:
Mark me please as brainliest
Explanation:
A length of pipe will weigh the most when O A. part dimensions are such that the pipe is in the MMC. O B. the OD and ID are at the minimum allowable limit. OC. the OD and ID are at the maximum allowable limit. OD.part dimensions are such that the pipe is in the LMC
Answer:
Part dimensions are such that the pipe is in the MMC.
Explanation:
why the power factor is Low in no load test in induction motor ?
The reason for low power factor in no load test in induction motor is high rotor reactance at lower loading since the rotor reactance value gets decreased with increased loading on induction motor
Usually at no load, the Cosine of the phase angle between the stator current(I1) and the stator applied voltage(V1) is the power factor of an induction motor.
In conclusion, the reason for low power factor in no load test in induction motor is high rotor reactance at lower loading since the rotor reactance value gets decreased with increased loading on induction motor
Read more about induction motor
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How to calculate total photon flux incident on the photodiode
Answer:
Use this PDF file it should help you calculate total photon flux incident on the photodiode.
Explanation:
It's a file on lecture notes that help people learn about engineering and maybe in the lecture notes it might have information about how to calculate total photon flux incident on the photodiode
Consider an FSM with 1024 states and a 2-bit input (00, 01, 10, 11). How many flip-flops will you need to construct the FSM
Answer:
468
Explanation:
The first three terms of a geometric series are 15,7.5 and 3.75. find the representation of the n th term of tge sequence
Answer:
30 1/2
Explanation:
You work for REV, Incorporated, and check your work email on your mobile phone. According to these documents, if you cannot find your phone, what should you do first?
Answer:
In case whereby you work for rev and check your work email on your mobile phone and You have decided to resign your job and take a position with a different company. Regarding rdm on your mobile phone, you should B. Take your phone to IT Services, and they will wipe it clean.
What is expected to do when leaving the company?
It is expected from you to return anything that belong to the company before leaving the company, but in the case whereby there is still a rdm on your mobile phone, then you can work to the IT services so they can wipe it away.
Find out more on IT Services
at brainly.com/question/21210308
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Missing options:
A. Turn your phone to IT Services
B. Take your phone to IT Services, and they will wipe it clean
C. Download RDM to your personal computer
D. Call IT Services for support, and they will assist
E. Nothing. IT Services will automatically remove all data
Can I have free money? I want to get a new pc
Answer:
NO!
Explanation:
1 . How are encoders used in the measurement of speed? Explain the encoder with a neat diagram.
The most common use for encoders is to measure angular or linear distance, but encoders can also be used to perform speed or velocity measurements. In other words, as the encoder rotates faster, the pulse frequency increases at the same rate
when the electrical connection to the alternator from the battery is not tight, it can cause?
Answer:
affects the flow of electricity
Explanation:
A loose battery terminal affects the flow of electricity. There is less power going to the electrical systems and the vehicle will not start or start sluggishly. Also, a loose battery terminal causes the car's electrical components like navigation, car lights, and audio among others to dim or fail completely.
what is the relationship between the voltages of the output and adjust pins of LM1117 when in normal operation
Based on the engineering analysis, the relationship between the voltages of the output and adjust pins of LM1117 when in normal operation is "the LM1117 adjustable version establishes a 1.25V reference voltage, (VREF) between the output and the adjust terminal."
The LM1117 generally has a 1.2V at 800mA of load current.
The LM1117 is known to be a progression of low dropout linear voltage regulators. It is adjustable and be assigned between the output voltage of 1.25 to 13.8 V using just two external resistors.
Hence, in this case, it is concluded that the correct answer is "the LM1117 adjustable version establishes a 1.25V reference voltage, (VREF), between the output and the adjust terminal.
Learn more here: https://brainly.com/question/25646477
locate the centroid of the shaded area between the two curves
9514 1404 393
Answer:
(x, y) = (5.76, 1 5/7)
Explanation:
The location of the centroid in the x-direction is the ratio of the first moment of area about the y-axis to the total area. Similarly, the y-coordinate of the centroid is the first moment of area about the x-axis, divided by the area.
For the moment about the y-axis, we can define a differential of area as ...
dA = (y2 -y1)dx
where y2 = √(x/k2) and y1 = k1·x^3
The distance of that area from the y-axis is simply x.
So, the x-coordinate of the centroid is ...
[tex]\displaystyle c_x=\frac{a_x}{a}=\frac{\int{x\cdot dA}}{\int{dA}}\\\\a_x=\int_0^{12}{x(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{5k_2^{1/2}}\cdot12^{5/2}-\frac{k_1}{5}12^5\\\\a=\int_0^{12}{(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{3k_2^{1/2}}\cdot12^{3/2}-\frac{k_1}{4}12^4\\[/tex]
For k1 = 4/12^3 and k2=12/4^2, these evaluate to ...
[tex]a_x=115.2\\a=20\\c_x=5.76[/tex]
The y-coordinate of the centroid requires we find the distance of the differential of area from the x-axis. We can use (y2 +y1)/2 for that purpose. Then the y-coordinate is ...
[tex]\displaystyle c_y=\frac{a_y}{a}\\\\a_y=\int_0^{12}{(\frac{y_2+y_1}{2}(y_2-y_1))}\,dx=\frac{1}{2}\int_0^{12}{(\frac{x}{k_2}-(k_1x^3)^2)}\,dx\\\\a_y=\frac{12^2}{4k_2}-\frac{k_1^212^7}{14}=\frac{240}{7}\\\\c_y=\frac{12}{7}\approx1.7143[/tex]
The centroid of the shaded area is ...
(x, y) = (5.76, 1 5/7)
Dilute countercurrent immiscible extraction
A feed of 100.0 kg/min of a 1.2 wt % mixture of acetic acid in water is to be extracted with 1-butanol at 1 atm pressure and 26.7°C, we desire an outlet concentration of 0.1 wt % acetic acid in the exiting water. We have available solvent stream 1 that is 44.0 kg/min of pure 1-butanol and solvent stream 2 that is 30.0 kg/min of 1-butanol that contains 0.4 wt % acetic acid. Devise a scheme to do this separation, find the outlet flow rate and concentration of the exiting 1-butanol phase, and find the number of equilibrium contacts needed.
In Example we assumed that we were going to use all of the solvent available. There are other alternatives. Determine if the following alternatives are capable of producing outlet water of the desired acetic acid concentration.
a. Use only the pure solvent at the bottom of the extractor.
b. Mix all of the pure and all of the impure solvent together and use them at the bottom of the column.
c. Mix all of the pure and part of the impure solvent together and use them at the bottom of the column.
Consider a 25-mm-diameter and 15-m-long smooth tube that is maintained at a constant surface temperature. Fluids enter the tube at 50°C with a mass flow rate of 0.01 kg/s. Determine the tube surface temperatures necessary to heat water, engine oil, and liquid mercury to the desired outlet temperature of 150°C
Answer: ⚠this is not my answer it from hamzaahmeds⚠
Water: h = 35.53 W/m².k
Engine oil: h = 18.84 W/m².k
Mercury: h = 1.19 W/m².k
Explanation:
Assuming the steady state, one-dimensional heat flow, it is clear that the added to the fluid by tube heat will be equal to the heat transfer through convection outside the tube.
Therefore,
mCΔT = hAΔT
mC = hA
h = mC/A
where,
h = convection coefficient
m = mass flow rate = 0.01 kg/s
C = specific heat capacity of fluid
A = surface area of tube = 2πrL = 2π(0.0125 m)(15 m) = 1.178 m²
FOR WATER:
C = 4186 J/Kg.k
Therefore,
h = (0.01 kg/s)(4186 J/Kg.k)/(1.178 m²)
h = 35.53 W/m².k
FOR ENGINE OIL:
C = 2220 J/Kg.k
Therefore,
h = (0.01 kg/s)(2220 J/Kg.k)/(1.178 m²)
h = 18.84 W/m².k
FOR LIQUID MERCURY:
C = 140 J/Kg.k
Therefore,
h = (0.01 kg/s)(140 J/Kg.k)/(1.178 m²)
h = 1.19 W/m².k
How much work, in Newtons, is required to lift a 20.4-kg (45lb) plate from the ground to a stand that is 1.50 meters up?
ASAP PLS
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81 [tex]\frac{N}{kg}[/tex] · 1.50m
= 35.316 [tex]\frac{N}{m}[/tex]
= 35.316 W
Hierarchy of hazard control
Answer:
A system for controlling risk in the workspace.
Describe three differences between liquids and gases in fluid power systems.
Answer:
Liquids have less force of attraction between molecules than solids and more than gases; gases have a very weak force of attraction between the molecules which is the least amongst the three states of matter.
Explanation:
why people act like that
Answer:
i dob't know
Explanation:
ai lm dc bài tập môn cơ học vật liệu ko ạ
Answer:
What's that
Explanation:
Please brainlest me
Beyond providing a visual representation of an object for the creator, what are the advantages of using CAD software to create 3D digital models of engineering prototypes (compared to physical drawings)? Identify at least two advantages.
Answer:
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Explanation:
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