A list is sorted in ascending order if it is empty or each item except the last one is less than or equal to its successor. HERES THE CODE:

def isSorted(input_list):
if len(input_list)==0 or len(input_list)==1:
return True
else:
for i in range(len(input_list)):
for j in range(i, len(input_list)):
if input_list[j] < input_list[i]:
return False
return True

def main():
lyst = []
print(isSorted(lyst))
lyst = [1]
print(isSorted(lyst))
lyst = list(range(10))
print(isSorted(lyst))
lyst[9] = 3
print(isSorted(lyst))


if __name__ == "__main__":
main()

Answers

Answer 1

Using the knowledge of computational language in python it is possible to write a code that writes a list and defines the arrange.

Writing code in python:

def isSorted(lyst):

if len(lyst) >= 0 and len(lyst) < 2:

return True

else:

for i in range(len(lyst)-1):

if lyst[i] > lyst[i+1]:

return False

return True

def main():

lyst = []

print(isSorted(lyst))

lyst = [1]

print(isSorted(lyst))

lyst = list(range(10))

print(isSorted(lyst))

lyst[9] = 3

print(isSorted(lyst))

main()

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A List Is Sorted In Ascending Order If It Is Empty Or Each Item Except The Last One Is Less Than Or Equal

Related Questions

Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.

a. M
b. L / T
c. M L / T^2
d. M / (L T^2)
e. No dimensions

Answers

Correct answer is option E. No dimensions

As we know formula Pressure (P) is [tex]\frac{F}{A}[/tex]

also,

Dimensional formula of Pressure is [tex]M^{1}L^{-1}T^{-2}[/tex]Dimensional formula of length is L Dimensional formula of mass is MDimensional formula  of velocity is [tex]L^{1} T^{-1}[/tex]

So, as given W=[tex]\frac{P*L^{3} }{M*V^{2} }[/tex]

Dimensional formula of W =[tex]\frac{M^{1}L^{-1}T^{-2} L^{3} }{M^{1} L^{2}T^{-2} }[/tex]

since all terms get cancelled

Work is dimensionless i.e no dimensions

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Brown bears can weigh half a ton (500 kilograms). The piston on the left has a cross-sectional
area of 1 square meter. The piston on the right has a cross-sectional area of 4 square meters.
How much force has to be exerted on the left piston to lift the bear? Show your work and
specify units.

Answers

In order to lift the Bear, a force of 1226.25 N has to be exerted on the left piston,

What is pressure is on the piston carrying the Bear?

The pressure on the piston carrying the Bear is calculated as follows:

Pressure = force/area

Force of the Bear = 500 kg * 9.81 m/s² = 4905 N

Pressure on the right piston = 4905 N / 4 m² = 1226.25 N/m²

To lift the Bear, the pressure on  both sides must be equal.

Force to be applied on the left piston = pressure * area

Force = 1226.25 N/m² * 1 m² = 1226.25 N

Therefore, a force of 1226.25 N has to be exerted on the left piston to lift the bear.

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A bridge a mass of 800 kg and is able to support up to 4 560 kg. What is its structural efficiency?

Answers

Answer:4560÷800=5.4

Explanation:

Est = DL / W

EST=4560/800=5.7

11. What are restrictions when building or completing a challenge?

Answers

Explanation:

The minimum exterior open spaces around buildings that are 55 metres or more, should be 16 metres. On sides where no habitable rooms face, a minimum space of 9 metres shall be left for heights above 27 metres.

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