Physics College

a man on a motorcycle plans to make a jump off of a ramp. if he leaves the ramp with a speed of 38.0 m/s and has a speed of 36.1 m/s at the top of his trajectory, determine his maximum height (h) (in m) above the end of the ramp. ignore friction and air resistance.

Answers

Answer 1

According to Newton's second law, there is no acceleration in the horizontal plane because there is no net force operating in that direction.4.63 m is the highest height attained.

Determine his maximum height ?

The man's initial speed (u) is 31.0 m/s.

The trajectory's top speed is 29.5 m/s.

Gravitational acceleration (g) equals 9.8 m/s²

The vertical component of velocity becomes zero as the man reaches the top of the trajectory, leaving just the horizontal component to affect him.

Additionally, according to Newton's second law, there is no acceleration in the horizontal plane because there is no net force operating in that direction.As a result, the horizontal component of velocity never changes.

Thus, the horizontal component of beginning velocity is all that is referred to as speed at the top of the trajectory.where Ux and Uy are the man's initial vertical and horizontal velocities, respectively.

To find "H," enter the value from equation (1) and 9.8 for "g."

H = 90.75/2*9.8

H = 4.63 as a result.

As a result, 4.63 m is the highest height attained.

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