Vtb xe máy là:
v=s : t= 500 : 25=20(m/s)
Desperate Please Hurry
What was the evidence that Earth was round before there were photos from space?
Answer:
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Explanation:
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Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
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The true statement about Dan is that "he also helps families make use of early intervention services."
Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.
If Dan is working as a family resources coordinator, then a true statement about him is that "he also helps families make use of early intervention services."
Learn more about family resource coordinator: https://brainly.com/question/8949872
Answer:
-He also helps families make use of early intervention services.
-He also helps families with children who have special needs to uphold the rights of the children
Explanation:
Got it right on plato.
Tom pulls a muscle. He has to stop working to get an ice pack. Claudia continues to work and soon finishes her pile.
Power is the rate of doing work. It's calculated by dividing work by time (power = work = time). Who had more power in
this scenario? Why?
Answer:
Tom
Explanation:
if for example both their work is 40 and Tom stops working after 2 hours but Claudia continues and stops after 3 hours when you divide their work by their time Claudia will get a lower number of power.
(in your explanation maybe use different numbers based on you book or notes)
Answer:
Claudia had more power. She did more work than Tom, and she did it in less time.
Explanation:
sample answer on edmentum. maybe change it up. hope this helps:)
I need help with this physics question
Answer:
its B hope you have a good Day
what happens to light when it travels from air into water
Answer:
Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.
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A seashell is suspended in the air at rest by two strands of spider silk. Each strand of silk makes an angle of 75 degrees above the horizontal, and experiences a tension of 1.42 N.
What is the mass of the seashell?
The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
Tension on each strand of silk, T = 1.42 NAngle of inclination of each strand, θ = 75⁰The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;
[tex]\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0[/tex]
where;
W is the weight of the seashellThe weight of the seashell is calculated as;
[tex]1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N[/tex]
The mass of the seashell is calculated as follows;
[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg[/tex]
Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
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I was walking with Ruby in a garden from rest in a straight line with uniform acceleration so that we covered 0.25 m in the fifth second of our motion. Calculate our acceleration.
Answer:
0.02m/s^2
Explanation:
Which of the following is the goal of physical fitness test? *
a. to determine the level of fitness.
b. to identify the area of development/improvement.
c. all of the above
d. to identify strengths and weaknesses.
Answer
C
hope this helps!!
*please mark brainliest if correct!! Trying to level up!!
Help please!
3. A 75 kg linebacker moving at 6 m/s is running towards an 80 kg tackle moving 4 m/s. If they collide and stick together, how fast will they be moving after the collision?
5. A 6 kg bowling ball and a 4 kg bowling ball are rolled toward each other. The 6 kg ball is initially moving at 5.1 m/s and the 4 kg ball is moving in the opposite direction at 1.3 m/s. If the 6 kg ball slows to 1.5 m/s, what is the final speed of the 4 kg ball?
3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:
(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v
where v is the velocity of the combined players. Solve for v :
450 kg•m/s - 320 kg•m/s = (155 kg) v
v = (130 kg•m/s) / (155 kg)
v ≈ 0.84 m/s
4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that
(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v
where v is the new velocity of the 4-kg ball. Solve for v :
30.6 kg•m/s - 5.2 kg•m/s = 9 kg•m/s + (4 kg) v
v = (16.4 kg•m/s) / (4 kg)
v = 4.1 m/s
what do i do on this rubixs cube
Answer:
You solve it
Explanation:
Answer:
you just spin it and spin it and spin it and spin it
and spin it
and spin it
and spin it
and spin it
until you get mad then throw it at the wall
Explanation:
ya then you look up a vid that is called rubix cube meme and there should be a pink animal its funny you should watch it!!!!!!!!!
What is the centripetal acceleration?
Answer:
centripetal acceleration is when an object accelerates going in a circular motion.
Suppose you drop a 10-pound weight and a 5-pound weight on the Moon, both from the same height at the same time. What will happen? The 10-pound weight will hit the ground before the 5-pound weight. The 5-pound weight will hit the ground before the 10-pound weight. Both weights will float freely because everything is weightless on the Moon. Both will hit the ground at the same time.
Answer:
Both will hit the ground at the same time.
Convert 8 m/s to miles per hour
Answer:
17.8954903 or 17.9 mph
Explanation:
m/s is meters per second. 1609.344 meters is one mile. There are 3,600 seconds in an hour. 8 meters *3600 seconds= 28,800. 28,800/1609.344 = 17.8954903. Simplify to 17.9
Hi, please help! •_•
One workman is measured as having a power of 528W. His weight is 800N. He can develop the same power climbing a ladder, whose rungs are 30cm apart. How many rungs can he climb in 5s?
Answer:
He can climb 11 rungs
Explanation:
Power = 528W, Force = 800N, Time= 5s Total Distance moved = 30x cm or 0.3x m, where x is the number of rungs he climbed
Power = Work done/time
Work done = Power × time
= 528 × 5
= 2640Joules
Also Work done = Force × total distance moved
Total Distance moved = Work done/force
0.3x = 2640/800
0.3x = 33
x = 3.3/0.3
x = 11
NEED HELP ASAP 40 POINTS L!!!! Jaden is interested in learning more about the basics of astrono ny and looking more closely at the sky all by himself. He wantS to get a basic starter telescope to help him with this endeavor, and his teacher SuggestS an organization that might be able to help him with this. What organization is Jaden's teacher likely referring to? The Little Astronomers Celestial Sightseeing Group The Beginning Astronomy Organization Astronomers Without BordersS
What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2?
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
When a projectile is launched horizontally, what is true of its acceleration as it travels through the air?
How many volts would it take to push 1 amp through a resistance of 1 ohm?
Answer:
[tex]1\; \rm V[/tex].
Explanation:
Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:
[tex]V = I \, R[/tex].
It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].
Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)
Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:
[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].
I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?
Answer:
The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²
Explanation:
An object’s mechanical energy is
a
its energy of motion.
b
the sum of its potential (position) energy and kinetic (motion) energy.
c
the waste energy it produces by friction.
d
not related to the object’s mass.
Explanation:
the sum of its potential (position) energy and kinetic (motion) energy.
If an input force of 202N is applied to the handles of the wheelbarrow in the sample problem how large is the output force that just lifts the load?
For this case, the relationship between the two forces is given by:
F1 = nF2
Where,
F1: output strengthF2: input forcen: mechanical advantageThen, replacing the values we have:
F1 = (2.2)(202)
Having the calculations we have:
F1 = 444.4N
Answer: The output force that only lifts the load is F1 = 444.4N.
A weightlifter lifts a 350 N set of weights over his head a vertical distance of 2.5 meters above the floor. Calculate the work the athlete does on the weights, assuming he lifts them at a constant speed.
A. 525 J
B. 750 J
C. 1005 J
D. 700 N•m
E. 875 J
The region of the globe directly beneath the Sun is warmer because it ____. A. sees more intense wavelengths reaching the surface B. is closer to the Sun C. has more yearly daylight than other parts of Earth D. receives direct sunlight
1) A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of
the light as the cart moves with constant velocity?
How do I solve this?
Option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
At constant velocity, the change in displacement with time is uniform. The displacement of the given object in motion increases at equal rate.
At constant velocity, the initial velocity is equal to the final velocity.
v₁ = v₂
The acceleration of the object at constant velocity is zero, because the change in velocity with time will be zero.
[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]
Thus, from the given options we can conclude that option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
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What is the magnitude of the resultant of
a 3.0-
meter displacement and a 4.0-meter
displacement as shown in the diagram?
A. 1.0 meter
4.0 meters
B. 5.0 meters
3.0 meters
C. 7.0 meters
D. 12 meters
Answer:b. 5.0 meters
Explanation: d² = 3²+4²
d² = 9+16
d² = 25
d = √25
d = 5m
The magnitude of the displacement is 5 m as shown in the diagram. Option B is correct.
What is displacement?
Displacement can be defined as the total change in the position of the object. It is a vector quantity.
From the Pythagorean theorem,
[tex]d =\sqrt { 3^2 +4^2}\\\\d = \sqrt {25}\\\\d = 5[/tex]
Therefore, the magnitude of the displacement is 5 m.
Learn more about Displacement:
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Chapter Name :- Vector
Question :-
A car is moving at Vc speed. Rain is falling vertically at a speed of 10 m / s. What is the value of Vc in this case,if the front glass of the car will get wet?
Answer :- Vc ≥ 10
I need Explanation! Please Don’t do copy from net! If you don’t know then no need to answer!
The value of the speed of the car, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
The given parameters:
Speed of the car, = VcSpeed of the rain, = 10 m/sThe relative velocity of the car with respect to the falling rain is calculated as;
[tex]V_{C/R} = V_C- V_R[/tex]
If the speed of the car equals the speed of the rain, the rain will fall behind the car.If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.If the speed of the car is greater than speed of the rain, the rain will fall on the car.Thus, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
Learn more about relative velocity here: https://brainly.com/question/24337516
a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
Formula
F = E×Q .......................... Equation 1
Where:
F = Force on the chargeE = Electric FieldQ = chargeFrom the question,
Given:
E = 200 N/CQ = -0.06 CSubstitute these values into equation 1
F = 200(-0.06)F = -12 NNote: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
Learn more about Electric Field here: https://brainly.com/question/14015797
Answer: A edge 202694020
Explanation:
10. What do you think the effect is of jet airplanes on global warming?
Answer:
Like other emissions resulting from fossil fuel combustion, aircraft engines produce gases, noise, and particulates, raising environmental concerns over their global effects and their effects on local air quality.[2]Jet airliners contribute to climate change by emitting carbon dioxide (CO2), the best understood greenhouse gas, and, with less scientific understanding, nitrogen oxides, contrails and particulates. Their radiative forcing is estimated at 1.3–1.4 that of CO2 alone, excluding induced cirrus cloud with a very low level of scientific understanding. In 2018, global commercial operations generated 2.4% of all CO2 emissions.
Between 1940 and 2018, aviation CO2 emissions grew from 0.7% to 2.65% of all CO2 emissions.[1]
Jet airliners have become 70% more fuel efficient between 1967 and 2007, and CO2 emissions per Revenue Ton-kilometer (RTK) in 2018 were 47% of those in 1990. In 2018, CO2 emissions averaged 88 grams of CO2 per revenue passenger per km. While the aviation industry is more fuel efficient, overall emissions have risen as the volume of air travel has increased. By 2020, aviation emissions were 70% higher than in 2005 and they could grow by 300% by 2050.
Aircraft noise pollution disrupts sleep, children's education and could increase cardiovascular risk. Airports can generate water pollution due to their extensive handling of jet fuel and deicing chemicals if not contained, contaminating nearby water bodies. Aviation activities emit ozone and ultrafine particles, both of which are health hazards. Piston engines used in general aviation burn Avgas, releasing toxic lead.
Aviation's environmental footprint can be reduced by better fuel economy in aircraft or Air Traffic Control and flight routes can be optimised to lower non-CO2 effects on climate from NO
x, particulates or contrails. Aviation biofuel, emissions trading and carbon offsetting, part of the ICAO's CORSIA, can lower CO2 emissions. Aviation usage can be lowered by short-haul flight bans, train connections, personal choices and aviation taxation and subsidies. Fuel-powered aircraft may be replaced by hybrid electric aircraft and electric aircraft or by hydrogen-powered aircraft.
moving east with a constant velocity of 30 m/s for 5 seconds. What is the object's
acceleration?
a. O m/s/s
C. 30 m/s/s
b. 6 m/s/s
d. 150 m/s/s
What is an example of bad energy efficiency but good energy conservation?
Answer:
Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.
Explanation:
hope this helps
