The combination of two 10-N trajectories at perpendicularly is approximately 14 N.
What exactly are vectors, exactly?A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Movement, momentum, force, electric interference, and weight are a few elements of axes in nature. To "transport" something from point A to point B, a vector is required; the Latin root of the word vector implies "carrier". Astronomers studying the planetary rotation around the Sun in the 18th century were the first to apply it.
Resultant vector [tex]$\vec{\gamma}$[/tex] can be written as
[tex]$$\begin{aligned}\vec{r} & =10 \hat{i}+10 \hat{\jmath} \mathrm{N} \\|\vec{r}| & =\sqrt{(10 \mathrm{~N})^2+(10 \mathrm{~N})^2} \\|\vec{\gamma}| & =10 \sqrt{2} \mathrm{~N} \\|\vec{r}| & =14.14 \mathrm{~N} \\|\vec{r}| & =14 \mathrm{~N}\end{aligned}$$[/tex]
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Consider the flask diagramed below with the following pressures 492 torr H2 and 0.376 atm for N2. What are the final partial pressures of H2 and N2 after the stopcock between the 2 flask is opened? (Assume the final volume is 3.00L). What is the total pressure in torr?
After the stopcock is opened the final pressure in the flask is 172.92 torr, the final partial pressure of H2 is 492 torr, and the final partial pressure of N2 is 0.376 atm.
The final partial pressures of H2 and N2 after the stopcock between the two flasks is opened are given by the Ideal Gas Law (PV=nRT).
The Ideal Gas Law states that the product of the pressure, volume, and molar amount of a gas is equal to the product of the universal gas constant, R, and the temperature.
At constant temperature, the product of pressure and volume is directly proportional to the number of moles of gas, n. Therefore, when the stopcock is opened, the number of moles of H2 and N2 in the final flask is the sum of the number of moles in the original flasks.
The number of moles of H2 in the first flask is given by n1 = (P1V1) / (RT) = (492 torr x 2.00 L) / (0.0821 atm x L / mol x 273K) = 0.0428 mol
The number of moles of N2 in the second flask is given by n2 = (P2V2) / (RT) = (0.376 atm x 1.00 L) / (0.0821 atm x L / mol x 273K) = 0.0141 mol
The final number of moles of H2 and N2 is n = n1 + n2 = 0.0428 mol + 0.0141 mol = 0.0569 mol
After the stopcock is opened, the final pressure is equal to the product of the number of moles, n, and the ideal gas constant, R, and the temperature divided by the final volume Vf,
Pfinal = nRT / Vf = 0.0569 mol * 0.0821 atm x L / mol x 273K / 3.00 L = 0.0227 atm
In torr, the final pressure is Pfinal760 = 0.0227760 =172.92 torr.
The final partial pressure of H2 is 492 torr and the final partial pressure of N2 is 0.376 atm.
In conclusion, after the stopcock is opened the final pressure in the flask is 172.92 torr, the final partial pressure of H2 is 492 torr, and the final partial pressure of N2 is 0.376 atm.
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the tape in a videotape cassette has a total length 281 m and can play for 2 h. As the tape starts to play, the full reel has an outer radius of 45 mm and an inner radius of 12 mm. At some point during the play, both reels will have the same angular speed?
what is this common angular speed?
The common angular speed is 6.5 x 10^⁻⁴ rad/s
What is the angular speed about?To calculate the common angular speed of the reels during play, we need to first determine the linear speed of the tape on the outer reel. We can use the formula:
Linear speed = tape length / play time
So the linear speed of the tape on the outer reel is:
Linear speed = 281 m / (2 h * 3600 s/h)
= 0.078 m/s
Then we can use the formula for linear speed to find the angular speed:
Linear speed = angular speed x radius
So the angular speed of the outer reel is:
Angular speed = Linear speed / radius
= 0.078 m/s / (45 mm / 1000 m/mm)
= 1.7 x 10^⁻⁴ rad/s
The inner reel radius is 12mm, so the angular speed of the inner reel is:
Angular speed = Linear speed / radius
= 0.078 m/s / (12 mm / 1000 m/mm)
= 6.5 x 10^⁻⁴ rad/s
This is the common angular speed of the reels when both have the same angular speed.
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a football is kicked straight up into the air; it hits the ground 5.8 s later.
A. What was the greatest height reached by the ball? Assume it is kicked from ground level. B. With what speed did it leave the kicker's foot?
The height and velocity of the football are calculated below.
What is velocity?
Velocity is a vector quantity that describes the rate of change of an object's position in a specific direction. It is defined as the displacement (change in position) of an object per unit time. The units of velocity are typically meters per second (m/s) or kilometers per hour (km/h). Velocity can also be represented by a vector arrow pointing in the direction of motion, with the magnitude of the arrow representing the speed of the object.
A. The greatest height reached by the ball can be calculated using the equation:
h = v_i^2 / (2 * g)
where h is the height, v_i is the initial velocity, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
To find h:
h = (v_i^2) / (2 * 9.8)
B. To find the initial velocity, we can use the equation:
v_f^2 = v_i^2 + 2 * a * d
where v_f is the final velocity, v_i is the initial velocity, a is the acceleration (in this case, the acceleration due to gravity), and d is the distance traveled.
The distance traveled is the height of the ball at its highest point, which we found in part A. Since the ball is coming back down, final velocity will be zero.
v_f = 0
and the distance traveled is h.
Therefore,
v_i^2 = 2 * 9.8 * h
Finally, the initial velocity can be found by taking the square root of v_i^2.
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calculate the amplitude at point on the string a distance of 17.0 cm from the left-hand end of the string. express your answer in meters.
calculate the amplitude at point on the string a distance of 17.0 cm from the left-hand end of the string. express your answer in meters.
In this case, we are given the distance of the point from the left-hand end of the string, but we are not given the amplitude of the source. So, we cannot calculate the amplitude at the point using the information provided.
To calculate the amplitude at a point on a string, we need to know the amplitude of the source that is vibrating the string and the distance the point is from the source. To calculate the amplitude at a point on the string a distance of 17.0 cm from the left-hand end of the string, we can use the equation for a sinusoidal wave: y(x,t) = A * sin (2π (f(t-x/v)) ). Where A is the amplitude, f is the frequency, λ is the wavelength, t is time, v is the speed of the wave, and x is the position along the string.. Let's assume that the amplitude of the wave at the left-hand end of the string is A0. The amplitude at a distance of x = 17.0 cm from the left-hand end of the string is given by: A = A0 * cos(2π(x/λ)). We know that the distance is given in centimeters, but the formula is in meters, so we need to convert it to meters. The distance 17cm is equal to 0.17m. The amplitude at a point 17.0 cm from the left-hand end of the string is: A = A0 * cos(2π(0.17m/λ)).
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If a 0.55 kg tennis ball is struck by a tennis racket with 12 N of force pointing right, what will be the acceleration on the tennis ball
If a 0.55 kg tennis ball is struck by a tennis racket with 12 N of force pointing right, then the acceleration on the tennis ball will be 21.82m/s²
The acceleration of a tennis ball is determined by the equation
a = F/m, where a is the acceleration, F is the force, and m is the mass. In this example, the force is 12 N and the mass is 0.55 kg. Thus, the acceleration of the tennis ball is 21.82 m/s².
a=12/0.55
=21.82 m/s²
The direction of the acceleration is determined by the direction of the force. Since the force is pointing right, the acceleration will also be pointing right. This means that the speed and velocity of the tennis ball will both increase as it moves in the right direction.
In addition, the acceleration will cause the ball to accelerate and reach a terminal velocity. This means that the speed of the ball will eventually reach a maximum and then remain constant. This is due to the force of gravity and the air resistance caused by the ball moving through the air.
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a meter stick is supported by a knife edge at the 50-cm mark and has a mass of 0.40 kg hanging at the 20 cm mark and a 0.60 kg hanging from the 80-cm mark. where should a third mass of 0.30 kg be hung to keep the stick balanced? group of answer choices 30 cm 25 cm 20 cm 70 cm
A third mass of 0.30 kg needs to be hung at a height of 30 cm.
Describe mass.a numerical representation of the fundamental aspect of all material, inertia. It generally refers to the body of matter's opposition to changing its velocity or location in response to the force applied to it. The change caused by an applied force is lower the more mass a body has.
Clockwise and counterclockwise torques must balance
4 * (50 - 20) = .6 * (80 - 50) + .3 * L
g is left out here because it will cancel
Here we are assuming the mass at L will generate aclockwise torque along with the .6 kg mass
so L is measured to the right of the 50 cm mark.
Solving the above equation (12 - 18) / .3 = L =-20
So the weight must be hung at 50 - 20 = 30 cm
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with what tension must a rope with length 3.00 m and mass 0.145 kg be stretched for transverse waves of frequency 45.0 hz to have a wavelength of 0.770 m ? express your anwer in newtons.
The string is under 58.03 N of stress, in accordance with the supplied information.
Why do you use the word "frequency"?The frequency of a repeated event is its number of instances per amount of time. It differs from angular frequency and is sometimes referenced to as temporal resolution for clarification. One occurrence per second, or hertz (Hz), is the unit of frequency.
λ = Wavelength = 0.770 m
f = Frequency = 45.0 Hz
m = Mass of string = 0.145 kg
L = Length of string = 3.00 m
μ = Linear density = m/L
The wave's speed is determined by
v = λf
v = 0.770 * 45.0
v= 34.65 m/s
The source of the string's tension is
T = v²μ
T = (34.65)² * 0.145/3.00
T = 58.03 N
The string is under 58.03 N of stress.
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When a 16.60 g gold nugget is placed in a graduated cylinder with water, the water level rises (see diagram). Based on this observation, calculate the density (g/cm3) of gold.
The density of gold can be calculated by dividing the mass of the gold nugget (16.60 g) by the volume of water it displaces (in cm3).
How to calculate the density of a material?The density of a material can be calculated by dividing the mass of the material by its volume. The formula is Density = Mass/Volume. In this case, the mass of the gold nugget is given (16.60 g) and the volume of water it displaces can be measured by reading the graduated cylinder.
To calculate the density of gold, we need to know the volume of water that the gold nugget displaces. To find the volume, we can subtract the initial water volume (V1) from the final water volume (V2) after the gold nugget has been added. We can then use the formula density = mass/volume to find the density of the gold nugget.
Density = mass / volume
Density of gold = 16.60 g / (V2 - V1)
The volume of water displaced by the gold nugget needs to be measured in order to calculate the density of the gold nugget.
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The efficiency of a steam turbine is 0.30 if during one cycle 120 j of heat are added to the system how much work can be done?
Explanation:
according to formula
efficiency= work output/work input
:. 0.30=work output/120
work output = 36J
hope this helps you.
as you increase in altitude (go up) in the atmosphere what happens to air density and air temperature?
The density of air decreases as the altitude increases. The Temperature value decreases as the pressure value decreases with an increase in altitude.
About density of airThe density of air or atmospheric density, denoted ρ, is the mass per unit volume of Earth's atmosphere. Air density, like air pressure, decreases with increasing altitude. It also changes with variation in atmospheric pressure, temperature and humidity. At 101.325 kPa (abs) and 20 °C (68 °F), air has a density of approximately 1.204 kg/m3 (0.0752 lb/cu ft), according to the International Standard Atmosphere (ISA). At 101.325 kPa (abs) and 15 °C (59 °F), air has a density of approximately 1.225 kg/m3 (0.0765 lb/cu ft), which is about 1⁄800 that of water, according to the International Standard Atmosphere (ISA).[citation needed] Pure liquid water is 1,000 kg/m3 (62 lb/cu ft).
Air density is a property used in many branches of science, engineering, and industry, including aeronautics; gravimetric analysis; the air-conditioning industry; atmospheric research and meteorology; agricultural engineering (modeling and tracking of Soil-Vegetation-Atmosphere-Transfer (SVAT) models); and the engineering community that deals with compressed air.
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a meteorite plunges to earth, embedding it- self 100 cm into the ground. if it does 400 mj of work in the process, what average force does the meteorite exert on the ground?
Work is described as the force applied over a distance, so
W = Fxd
F = W/d = 400 mJ / 0.1 m = 4000 N
So the average force exerted by the it on the ground is 4000 N.
What are the components of work?If work is done then there are three components involved. These are the amount of force, the distance of the displacement, and the reason behind the displacement. After multiplying force and distance for work, we get the unit of joules.
What is the connection between force and work?Work is the usage of force to move an object. It is directly related to the force involved and the distance the thing moves. Work can be calculated with: Work = Force x Distance.
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A spring with spring constant k = 340 N/m is used to weigh a 6.7-kg fish. a. (2 pts.) Draw a picture of the fish and label Fspring and F, acting on the fish. Write down Newton's second law for the fish. b. (2 pts.) How far does the spring stretch?
(2 pts.) What is the weight of the fish.spring with spring constant k = 340 N/m is used to weigh a 6.7-kg fish. a. (2 pts.)
What is weight ?
Weight is a measurement of the force of gravity on an object or person. It is typically measured in units of mass such as kilograms, pounds, or ounces. Weight is an important factor in determining a person's overall health, as well as their ability to perform physical tasks.
The spring stretches 0.2 m.
Fspring = F = ma = 340N = 6.7kg * a
a = 340N/6.7kg = 50.7 m/s^2
Δx = vt = 0 * t = 0
Δx = (1/2)at^2 = (1/2)(50.7 m/s^2)(t^2)
t = √(2Δx/a) = √(2*0.2m/50.7 m/s^2) = 0.2 m
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T/F the test-mass is referred to as m and it hangs from the test-mass riser.
False: The radius of the circular route changes when the test-mass riser is moved along the platform.
A circular route is what?
In contrast to a linear road, which follows a straight line, a circular path has a circular form or loop. It is a kind of motion that frequently occurs in mathematics, engineering, and physics. Circular routes are frequently used in engineering to explain the motion of components like wheels, gears, and pulleys.
In mathematics, rotations, orbits, circles, and other types of curves are frequently represented as circular routes. Circular routes may be employed in design, architecture, and other fields as well.
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Calculate the kinetic energy of a body whose mass is 150kg covering a total distance of 115km/hr
The kinetic energy of a body whose mass is 150kg covering a total distance of 115km/hr is 76,512.27J.
How to calculate kinetic energy?Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.
Kinetic energy = ½ mv²
Where;
m = massK.E = kinetic energyv = velocityAccording to this question, a body of mass 150kg is covering a total distance of 115km/hr.
115km/hr = 31.94m/s
K.E = ½ × 150 × 31.94²
K.E = 76,512.27J
Therefore, 76,512.27J is the kinetic energy of the body.
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the transverse wave shown has a wavelength of 1.5 m and is traveling in the x-direction. a graph with time in second on the x axis from 0 to 6 and amplitude on the y axis from negative 3 to 3. the wave starts at the origin and the crest goes up to 3, back down through 1 s and all the way down to negative 3. the wave crosses this x axis every second. how long does it take the wave to travel 6.0 m in the x-direction? 0.13 seconds 0.67 seconds 2.0 seconds 8.0 seconds
Given that it has a 1.5 m wavelength The wave moves 0.75 m in one second as a result it takes the wave 8 seconds to move 6.0 meters in the x-direction.
What is the first law of motion?Newton's First Law of Motion (Inertia) An object at rest remains at rest, and an object in motion remains in motion at constant speed and in a straight line unless acted on by an unbalanced force.
The wavelength of the wave is given as 1.5 meters and it is traveling in the x-direction. The speed of a wave can be calculated using the formula:
Speed = Wavelength / Period
Since the wave is crossing the x-axis every second, its period is 1 second. So, the speed of the wave can be calculated as:
Speed = 1.5 meters / 1 second = 1.5 meters/second
To find out how long it takes the wave to travel 6 meters in the x-direction, we can use the formula:
Time = Distance / Speed
Time = 6 meters / 1.5 meters/second = 8 seconds
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Answer:
8.0
Explanation:
What concept of arcology in the lesson appealed to you the most? How would you incorporate an arcology concept into your community design?
Arcology is the fusion of architecture with ecology, a comprehensive urban perspective. In nature, as organisms evolve, they increase in complexity and become a more compact system. A city should similarly evolve, functioning as a living system.
What is arcology ?Arcology's major goal is to stop urban sprawl, which can be accomplished by building self-sufficient, remote settlements and structures that are (ideally, gigantic).
While it is theoretically conceivable to construct an arcology, at least structurally, it would take creative engineering to ensure the essential energy generation, food production, and waste reclamation systems are sustainable.
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Answer:
The concept of arcology that appealed to me the most is the fusion of architecture with ecology. If I were to incorporate an arcology concept into my community design, I would focus on creating a pedestrian environment where pedestrians move efficiently and freely.
Explanation:
For the circuit in the previous part, with the frequency set at 1 Hz, what happens if the inductance of the inductor is increased? The maximum current decreases. The maximum current does not change. The maximum current increases.
With the frequency set at 1 Hz, if the inductance of the inductor is increased the maximum current increases. An increase in inductance of the inductor in an AC circuit will cause an increase in the maximum current.
The maximum current will rise when the inductor's inductance in an AC circuit increases. This is due to the fact that an increase in inductance also results in an increase in inductive reactance, which is the resistance to changes in current. In order to keep the same voltage across the inductor as the inductive reactance grows, the circuit's current must also grow. The inductive reactance is exactly inversely proportional to the inductance at a fixed frequency of 1 Hz, therefore as the inductance rises, the maximum current rises as well.It's also important to mention that the maximum current in an AC circuit is the peak current and in a sinusoidal wave the peak current is the RMS value multiplied by the square root of 2.
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Which color of light, red or blue, travels faster in crown glass?
A. red
B. blue
C. their speeds are the same
D. depends on the material surrounding the glass
E. blue if the glass is thin
The color of light that travels faster in crown glass is red.
The speed of light in crown glass is the speed of light in a vacuum divided by the index of refraction of crown glass.
The speed of light traveling in vacuum = 3 times 10 to the 8 meters per second
The index of refraction of the crown glass for red light = 1.513
The index of refraction of the crown glass for blue light = 1.529
Therefore:
The speed of red color = 1.983 times 10 to the 8 meters per second
The speed of blue color = 1.962 times 10 to the 8 meters per second
Hence, the red light travels faster.
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A football is kicked straight up into the air; it hits the ground 5.4s later.
What was the greatest height reached by the ball? Assume it is kicked from ground level.
With what speed did it leave the kicker's foot?
Answer to two sig. fig. and include the appropriate units.
Include all math(Algerba based) and why that formula was chosen.
The greatest height reached by the ball is -9.5m and the speed with which it leaves the kicker's foot is 15.69 m/s.
What is the kinematic equation of motion and what does it represent?The kinematic equation of motion is a mathematical equation that describes the position, velocity, and acceleration of an object in motion. It is used to calculate an object's motion in terms of its position, velocity, and acceleration over time. There are four kinematic equations of motion, which are:
v = u + at
s = ut + 1/2at^2
v^2 = u^2 + 2as
s = vt - 1/2at^2
where v is the final velocity, u is the initial velocity, a is the acceleration, t is the time and s is the displacement. These equations can be used to solve problems related to a motion under constant acceleration.
to solve for the greatest height reached by the football, and the speed with which it leaves the kicker's foot, we can use the following kinematic equations:
h = vit + 1/2a*t^2
vf^2 = vi^2 + 2ah
where h is the height, vi is the initial velocity (upwards), t is the time, a is the acceleration (downwards, due to gravity), and if is the final velocity (at the greatest height).
Given:
Time of flight, t = 5.4s
Gravity acceleration, a = -9.8 m/s^2 (downwards)
Final velocity, vf = 0 m/s (at the greatest height)
We can use the first equation to solve for the initial velocity, vi:
h = vit + 1/2at^2 (1)
0 = vi5.4 + (-4.9)(29.16)
vi = (4.929.16)/5.4 = 15.69 m/s (2)
We can use the second equation to solve for the height:
vf^2 = vi^2 + 2ah (3)
0 = 15.69^2 + 2*(-9.8)h
h = (15.69^2)/(2-9.8) = -9.5 m (4)
The greatest height reached by the ball is -9.5m and the speed with which it leaves the kicker's foot is 15.69 m/s.
We have used the kinematic equations of motion h = vit + 1/2at^2 and vf^2 = vi^2 + 2a*h for solving the problem as it is a vertical motion problem where the initial velocity is not known and the height and time are known.
It is important to note that the height is negative because the ball is kicked upwards, and the initial height is considered as zero. It reaches a certain height and comes back to the ground level. It doesn't mean that the ball went below ground level.
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Now let's apply this to Trial 2. In this instance, Hailey (who is on the cart with Christine) has a mass of 69 kg. Conner is on the other cart. 1. Determine Conner's mass. Describe your process and results below. (Show work for all calculations.)
Since Hailey is on the cart with Christine and Conner is on the other cart. Hence, it is determined that Conner's mass is 93 kg.
How would you define mass?It is the most central tenant of matter and one of the essential quantities in physics. As a way to gauge how much matter is there in a body, we might use the term mass. The kilograms is the SI unit of mass (kg). A body's mass does not alter at any point in time.
How can I figure out my BMI?Adult men and women can utilize the body-mass index (BMI), an assessment of body fat based on height and weight. Body Mass Index (BMI) is determined by dividing a person's kilograms divided by their height in metres squared (or feet).
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Suppose the wind speed in a hurricane is 108 mph. (a) Find the difference in air pressure outside a home and inside a home (where the wind speed is zero). The density of air is 1.29 kg/m3.
The stated difference in air pressure between the outside and interior of a residence is 1528.86 Pa. (where the wind speed is zero).
What is the wind energy physics?The blades of a turbine, which resemble propellers and function much like an aeroplane wing, capture the wind's energy. A pocket or minimal air develops on one blade's other side as the wind blows. The blade is subsequently drawn into the low-pressure air pocket, which turns the rotor. It is known as lifting.
Spped of wind out side the home V₁ = 109 mph
= 109 * 1.608 Kmph
= 175.272Kmph
= 48.686 m/s
Spped of wind inside the home V₂ = 0 Kmph
Density of air ρ = 1.29Kg/m³
Bernoulli's equation states:
Pressure difference P = [tex]\mathrm{P}_2-\mathrm{P}_1=\frac{1}{2} \rho\left(v_1^2-v_2^2\right)[/tex]
= 0.5 * 1.29 * (48.686)²
= 1528.86 Pa
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the reason we use the kelvin scale for thermodynamic and dynamic meteorological equations is because:
The reason we use the kelvin scale for thermodynamic and dynamic meteorological equations is because it is an absolute temperature scale that relates directly to kinetic energy and volume.
What benefit does using the Kelvin scale have in particular?Using the Kelvin scale of temperature, it is easy to represent many fundamental laws and their associated mathematical equations. The Kelvin scale is a scale of absolute temperature, with zero at absolute zero. As an absolute scale, the Kelvin scale does not allow for degrees to be used in measurements.
Given that it only measures positive values and that its zero point is the temperature of absolute zero, the Kelvin scale is an absolute scale. The lowest theoretical temperature, or zero Kelvin, is the point at which a body can no longer lose thermal energy.
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A flea jumps straight up to a maximum height of 0.500 m . How long is the flea in the air from the time it jumps to the time it hits the ground? (I figured out initial velocity was 3.13 m/s)
Time of flight is the time flea in the air from the time it jumps to the time it hits the ground 0.64 seconds.
Time of flight= 2 time of ascent=[tex]2\times(\frac{u}{g} )[/tex]=[tex]2\times (\frac{3.13}{9.8})[/tex]=0.64 seconds
The time it takes for an object, particle, or wave (whether acoustic, electromagnetic, etc.) to traverse a distance across a medium is measured as time of flight (ToF). This data can then be used to determine the particle's or medium's attributes or to measure the particle's or path's velocity or length (such as composition or flow rate).The amount of time it takes the body to rise to its highest point from its starting posture is known as the ascension time. Complete solution, step-by-step For a projectile motion, the time to reach maximum height is called time of ascent.
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a quarterback takes the ball from the line of scrimmage and runs backward for 11 m. he then runs sideways, parallel to the line of scrimmage for 17 m. next, he throws the ball forward 50.0 m, perpendicular to the line of scrimmage. the receiver is tackled immediately. how far is the football displaced from its original position?
The magnitude of the football's resultant displacement is 52.81 yards.
The given parameters;
initial displacement backwards = 10 yards
final displacement forward = 50 yards
vertical displacement = 15 yards
The resultant horizontal displacement, x = 50 yards - 11 yards = 61 yards
The resultant vertical displacement, y = 17 yards
The magnitude of the football's resultant displacement is calculated by applying Pythagoras theorem as shown below;
R² = y² + x²
R² = 50² + 17²
R² = 2789
R = √2789
R = 52.81 yards
Thus, the magnitude of the football's resultant displacement is 42.72 yards.
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a police officer pulls over a driver at night, near a street light. as she approaches the driver side window she turns on her flashlight and points it into the driver's face. what information might the officer want to determine?
The officer might want to determine the driver's identity and verify that the driver has a valid driver's license. The officer could also use the flashlight to look for signs of intoxication, such as bloodshot eyes or a strong odor of alcohol.
What is the flashlight?
A flashlight is a device that emits a concentrated beam of light when powered by a battery. Flashlights are handheld, portable light sources that can be used to illuminate dark areas and enhance visibility in low-light situations. Flashlights come in a variety of sizes and shapes and typically use either an incandescent bulb or a light emitting diode (LED) as a source of light. Flashlights are mainly used for recreational activities such as camping, hiking, hunting and fishing, but they are also essential tools for emergency personnel and security guards.
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When you hear sounds through a wall, you can hear lower pitched sounds more clearly than higher pitched sounds. Use a model to explain why.
Sound waves travel through the air and can be blocked by walls. When a sound wave passes through a wall, the wall absorbs some of the sound energy, resulting in the higher-pitched sound waves being blocked more than lower-pitched sound waves.
This is because higher-pitched sound waves have shorter wavelengths, making them more susceptible to being blocked than lower-pitched sound waves, which have longer wavelengths.
This phenomenon is known as wave-particle duality, which states that sound waves have both particle-like and wave-like properties. The particle-like property of higher-pitched sound waves makes them more susceptible to being blocked by walls than lower-pitched sound waves. This is why you can hear lower-pitched sounds more clearly when they pass through a wall.
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what is the relative wavelength in the visible spectrum of red light and blue light and are these colours absorbed or reflected by chlorophyll?
The wavelength of red light in the visible spectrum is longer than that of blue light. In general, red light has a wavelength range of around 620–750 nanometers, while blue light has a wavelength range of around 450–495 nanometers.
Chlorophyll, the pigment that is responsible for photosynthesis in plants, primarily absorbs light in the blue and red regions of the visible spectrum. Chlorophyll reflects green light, which is why most plants appear green. Chlorophyll a absorbs the most light in the blue-violet and red (about 430 and 662 nm, respectively), while chlorophyll b absorbs in the blue and orange-red (about 453 and 642 nm, respectively)s why most plants appear green. Chlorophyll a absorbs the most light in the blue-violet and red (about 430 and 662 nm, respectively), while chlorophyll b absorbs in the blue and orange-red (about 453 and 642 nm, respectively). This is why it seems as if the chlorophyll reflects green.
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which of the following properties can be inferred from the star’s orbital period?
0 the planet's orbital radius 0 the planet's mass 0 both the planet's orbital radius and its mass 0 neither the planet's orbital radius nor its mass
The planet's orbital radius is the properties can be inferred from the star’s orbital period. Hence option 'a' is correct.
Definition of orbital periodAn orbital period is the time it takes for an astronomical object to complete an orbit around another object. In astronomy, it often refers to objects revolving around the Sun, such as planets or asteroids, as well as moons revolving around other star, exoplanets, and the double stars.
How does mass influence orbital period?A satellite's mass does have an impact on its orbit. The orbital period & radius of the satellite are influenced by its mass. A satellite's orbital period and radius will be shorter and smaller if it has higher mass.
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Six boxes are held at rest against identical walls. Rank the boxes on the basis of the magnitude of the normal force acting on them. Rank from largest to smallest.a. 140 N pushing on 5 kg box against wallb. 140 N pushing on 3 kg box against wallc. 120 N pushing on 3 kg box against walld. 150 N pushing on 7 kg box against walle. 130 N pushing on 7 kg box against wallf. 150 N pushing on 1 kg box against wall
The ranking of the boxes from largest to smallest is (d) 150 N pushing on 7 kg box, > (f) 150 N pushing on 1 kg box, > (a) 140 N pushing on 5 kg box, > (b) 140 N pushing on 3 kg box, > (e) 130 N pushing on 7 kg box, > (c) 120 N pushing on 3 kg box.
There are two forces acting on each book, perpendicular to each other. One is the pushing force, which is acting normal to the wall and the other one is gravitational force(weight) of the box acting downwards.
For box a) weight of the box, = 5 × 9.81 = 49.05 N
Pushing force on the box(a), = 140 N
Resultant force, R₁ = √(140²+49.05²) = 148.34 N
Similarly for box (b), R₂ = = √(140²+29.43²) = 143.06 N
Similarly for box (c), R₃ = = √(120²+29.43²) = 123.56 N
Similarly for box (d), R₄ = = √(150²+68.67²) = 164.97 N
Similarly for box (e), R₅ = = √(130²+68.67²) = 147.16 N
Similarly for box (f), R₆ = = √(150²+9.81²) = 150.32 N
So the ranking from largest to smallest force would be, d > f > a > b > e > c.
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suppose we look at a photograph of many galaxies. assuming that all of these galaxies formed at the same time after the big bang, which galaxies, as seen in the photo, would appear to be the youngest?
The galaxy that would appear to be the youngest when we look at a photograph of many galaxies assuming that all of these galaxies formed at the same time after the big bang is the one that is farthest away (option C)
The youngest and farthest galaxy that scientists have seen is GN-z11. This video pans to the object's distance of 32 billion light-years.
High-redshift galaxy GN-z11 can be found in the constellation Ursa Major. It was the farthest known galaxy ever found from Earth.
The 2016 publication led by Pascal Oesch and Gabriel Brammer revealed the 2015 discovery (Cosmic Dawn Center). With a spectroscopic redshift of z = 10.957, or a proper distance of roughly 32 billion light-years, GN-z11 was the oldest and most distant known galaxy yet identified in the observable universe until the James Webb Space Telescope found JADES-GS-z13-0 in 2022. (9.8 billion parsecs).
The question is incomplete, it should be:
Suppose that we look at a photograph of many galaxies. Assuming that all galaxies formed at about the same time, which galaxy in the picture is the youngest?
a. the one that is reddest in color
b. the one that is bluest in color
c. the one that is farthest away
d. the one that is closest to us e. the one that appears smallest in size
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