A paramedic maintains a time card for hours she works on the rescue squad. How many hours did she work per week ?

The integral of [tex]f(x)[/tex] over the interval [tex][-a,a][/tex] corresponds to the area of a semicircle of radius [tex]a[/tex], so

[tex]\displaystyle \int_{-a}^a f(x) \, dx = \frac{\pi a^2}2[/tex]

The integral over [tex][a,3a][/tex] corresponds to the negative area of a trapezoid with height [tex]a[/tex] and base lengths [tex]2a[/tex] and [tex]a[/tex], so

[tex]\displaystyle \int_a^{3a} f(x) \, dx = -\frac{a(2a+a)}2 = -\frac{3a^2}2[/tex]

Then combining the integrals, we have

[tex]\displaystyle \int_{-a}^{3a} f(x) \, dx = \frac{\pi a^2}2 + \left(-\frac{3a^2}2\right) = \frac{(\pi-3)a^2}2[/tex]

When [tex]a=9[/tex], the integral evaluates to

[tex]\displaystyle \int_{-9}^{27} f(x) \, dx = \frac{(\pi-3)\times81}2 \approx \boxed{5.7345}[/tex][/tex]

Answer:

vector VW= w - v

vector WV= v - w

Step-by-step explanation:

there are no figures to solve the question so i'll just write the formula..

vector VW= w - v

vector WV= v - w

Answer:

c6

Step-by-step explanation:

justjustcancacanjustadda0totheproduct of5cxwewtogetthesameresultasx1totoandtimes

3) Number: 640,700

   the value of 4 in this number is 40,000

Number: 64,070

the value of 4 in this number is 4,000

So, times greater: 40,000 ÷ 4,000 = 10 times greater.

4)

The multiplication, 5 × 12 = 60. So, 5 × 120 = 600.

There is an extra zero at the very last of the result as '120' was multiplied with 5 instead of '12' which does not have zero at last which changes the result.

Similar cases with: 5 × 10 = 50. So, 5 × 100 = 500.

Answer:

10000×(1+5%)^(15×2)=43219.4238

Answer:

J Trump has to be a great day of school and I have a great

Step-by-step explanation:

you thank you thank you thank you thank you thank you thank you thank you thank you thank you thank you for your loss of school and I have a great day of school ii

Answer:

Step-by-step explanation:

Jakub wants to build a new shed.

The area of the shed is 37 m².

The width of the shed is 5 m.

What is the length of the shed?

to find the side, having the area, you need to use the inverse formula Area = W * L

so

L = A: W

L = 37 : 5 = 7.4 m

If the area of the shed is 37 m²,width of the shed is 5 m as a result the length of the shed will be 7.4 m.

It is defined as two-dimensional geometry in which the angle between the adjacent sides is 90 degrees. It is a type of quadrilateral. The area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that, the area of the shed is 37 m². The width of the shed is 5 m.

Since the shed is rectangular. The length of width is found as,

Area = length × width

A = l × w

l=A/w

l=37/5

l=7.4 m

Thus, if the area of the shed is 37 m², the width of the shed is 5 m as a result the length of the shed will be 7.4 m.

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thomas age:44

huilan age: 29

Step-by-step explanation:

h = t + 15

t + t + 15 = 73

2t = 73 - 15

2t = 58

t = 29

Answer:

the answer is c. the row is chili, the column is no cheese

The zeroes of the quadratic function f(x) = 6x² + 12x – 7 will be given below. Then the correct option is A.

The quadratic function is given as ax² + bx + c = f(x).

For finding the zeroes of the polynomial we have to find the roots of the polynomial , The value of f(x) = 0

The given function is f(x) = 6x² + 12x – 7

Then the zeroes of the quadratic function will be

[tex]roots = \dfrac {-b \pm \sqrt{b^2 -4ac}}{2a}\\\\[/tex]

Here a =6 , b = 12 ,c = -7

Therefore the zeroes are

[tex]\rm roots = \dfrac {-12 \pm \sqrt{12^2 -4 * 6 * (-7)}}{2 *6}\\\\[/tex]

[tex]\rm root_1 = -1 + \sqrt{\dfrac {13}{6}}\\\\\rm root_2 = -1 - \sqrt{\dfrac {13}{6}}[/tex]

Therefore the correct option is A.

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Answer:

[tex] \frac{1}{7} [/tex]

The graph of the function is shown in the attached image.

Answer: [tex]2\left(x-\frac{1}{4} \right)^{2}[/tex]

Step-by-step explanation:

[tex]2x^{2}-x+\frac{1}{8}\\\\=2\left(x^{2}-\frac{1}{2}x \right)+\frac{1}{8}\\\\=2\left(\left(x-\frac{1}{4} \right)^{2}-\frac{1}{16} \right)+\frac{1}{8}\\\\=2\left(x-\frac{1}{4} \right)^{2}-\frac{1}{8}+\frac{1}{8}\\\\=\boxed{2\left(x-\frac{1}{4} \right)^{2}}[/tex]

Answer:

y≤x²+4x-1.

Step-by-step explanation:

1) to define the equation of the given graph; it is y=x²+4x-1 (its vertex is (-2;-5));

2) to define inequation accorging to the given graph (the area outside of the parabola means ≤).

[tex]z_{2}-3i=(-4+i)-3i=-4-2i\\\\z_{1}+2=(3-4i)+2=5-4i\\\\(z_{1}+2)-(z_{2}-3i)=(5-4i)-(-4-2i)=9-4i+4+2i=9-2i[/tex]

which corresponds with point C

The expression which is the result of subtracting (z2-3i) from (z1+2) is 9-2i.

Given On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. Point A is (1, -2), B is (1, -6), C is (9,- 2), D is (9, - 6), z 1 is (3, - 4), and z 2 is (- 4, 1).

Coordinate plane is a two dimensional plane formed by the intersection of two number lines. One is horizontal line and one is vertical. On horizontal line x values are denoted and on vertical line y values are written. There can be three dimensional plane also.

z2-3i=(-4+i)-3i=-4-2i

z1+2=(3-4i)+2=5-4i

(z1+2)-(z2-3i)=(5-4i)-(-4-2i)

=9-4i+4+2i

=9-2i

Hence for the expression (z1+2)-(z2-3i)=9-2i

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According to second equation of kinematics

Take positive value

Answer:

2.7 s  (1 d.p.)

Step-by-step explanation:

Use the Constant Acceleration Equations where:

Given:

[tex]\begin{aligned}\text{Using }s & =ut+\dfrac{1}{2}at^2\\\implies 55 & =11.8t+\dfrac{1}{2}(6.39)t^2\end{aligned}[/tex]

Rearrange the equation to equal zero:

[tex]\implies 3.195t^2+11.8t-55=0[/tex]

Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Use the quadratic equation to solve for t:

[tex]\implies a=3.195, \quad b=11.8, \quad c=-55[/tex]

[tex]\implies t=\dfrac{-11.8 \pm \sqrt{11.8^2-4(3.195)(-55)} }{2(3.195)}[/tex]

[tex]\implies t=2.694780675, -6.388051411[/tex]

As time is positive:

[tex]\implies t=2.694780675... \:\text{s}[/tex]

[tex]\implies t=2.7 \: \text{s (1 d.p.)}[/tex]

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The amount of the  interest revenue that  Princess will record in 2022 on this lease is:$413,553.82.

First step

Lease value payments after first payment:

Lease value payments=  $5,588,516- $716,000

Lease value payments= $4,872,516

Second step

Lease value payments after second payment:

Lease value payments=$4,872,516+ ($4,872,516×9%) - $716,000

Lease value payments=$4,872,516+$438,526.44-$716,000

Lease value payments=$4,595,042.44

Third step

2022 Interest revenue=$4,643,787.6×9%

2022 Interest revenue=$413,553.8196

2022 Interest revenue=$413,553.82 (Approximately)

Therefore the amount of the  interest revenue that  Princess will record in 2022 on this lease is:$413,553.82.

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If f(x)=x²+2 and g(x)=x²+5 then the domain of  the (fog) (x) is (-∞,∞).

Given the f(x)=x²+2 and g(x)=x²+5

We have to find the domain of  the (fog) (x)

The domain of a function is the set of all possible inputs for the function. For example, the domain of f(x)=x² is all real numbers, and the domain of g(x)=1/x is all real numbers except for x=0.

then,(fog) (x)= (x²+5)²+ 2

                    =x⁴+25+10x²+2

                    = x⁴+27+10x²

Now on any real value of x the value of (fog) (x) exists therefore (fog) (x) can take all the values of the real number.

So domain (fog) (x)= (-∞,∞).

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The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

[tex]A = \frac{\theta}{360} * \pi r^2[/tex] --- sector area

[tex]L = \frac{\theta}{360} * 2\pi r[/tex] ---- arc length

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

[tex]A = \frac{\theta}{360} * \pi r^2[/tex]

So, we have:

[tex]A = \frac{160}{360} * \frac{22}{7} * 5^2[/tex]

Evaluate

A = 34.92

The arc length is:

[tex]L = \frac{\theta}{360} * 2\pi r[/tex]

So, we have:

[tex]L = \frac{160}{360} * 2 * \frac{22}{7} * 5[/tex]

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

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The graphed trigonometric function is the one in option a.

The key parts that we can see on the graph are:

From this we know that the correct option is either a or b.

Now we can evaluate options a and b in x = 0 and see which one is equal to zero.

for a:

y = sin(0 - pi/2) + 1 = sin(-pi/2) + 1 = -1 + 1 = 0

for b:

y = cos(0 + pi/2) + 1 = 0 + 1 =  1

Then we can see that option a is the correct option.

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Answer:

1/7

Step-by-step explanation:

Alternative Form: 0.142857, 7^-1

step-by-step explanation:

#1: simplify both sides of the equation.

2(x+3)−4x=x

(2)(x)+(2)(3)+−4x=x

2x+6+−4x=x

(2x+−4x)+(6)=x

−2x+6=x

−2x+6=x

***

#2: subtract x from both sides.

−2x+6−x=x−x

−3x+6=0

***

#3: subtract 6 from both sides.

−3x+6−6=0−6

−3x=−6

***

step 4: divide both sides by -3.

−3x/-3 = -6/-3

solution x = 2

Answer:

Step-by-step explanation:

The domain is the set of x-values and the range is the set of y-values.

Answer:

The balance after 37 years is $3869.99

Step-by-step explanation:

Given:

The Amount (A),

A = P (1 + [tex]\frac{R}{100n}[/tex][tex])^{nt}[/tex]        if compound n times per year

Amount (A) at 37 years,

A = ($2,520) (1 + [tex]\frac{1.16}{100(12)}[/tex][tex])^{12 x 37}[/tex]

A = ($2,520) (1 + [tex]\frac{1.16}{1,200}[/tex][tex])^{444}[/tex]

A = ($2,520) (1.00096667 [tex])^{444}[/tex]

A = ($2,520) (1.5357)

A = $3869.9944

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Answer:

19 small frames and 3 large frames

Step-by-step explanation:

follows the steps in the attached

Answer:

D.  [tex](4x^2 + 3)(x + 2)[/tex]

Step-by-step explanation:

Hello!

We can group the first two terms and the last two terms and factor each group.

Now we can combine the like factors:

The answer is Option D.

he value of x and y from the given figure are 49/5 and 49/15

From the given similar triangles, the following expression is true

21/30 = 7/15 = k

Also, x/21 = y/7 = 7/15

Equate

x/21 = 7/15

15x = 7 * 21

5x = 7 * 7

x = 49/5

Similarly

y/7 = 7/15

15y = 49

y = 49/15

Hence the value of x and y from the given figure are 49/5 and 49/15

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Answer:

[tex]\frac{2}{3}|2-x|=\frac{1}{15}[/tex]

Step-by-step explanation:

[tex]\frac{1}{5} + \frac{2}{3} |2-x| = \frac{4}{15} \\\\\frac{1}{5}*(\frac{3}{3}) = \frac{3}{15}\\\\\frac{3}{15}-\frac{3}{15} + \frac{2}{3}|2-x| =\frac{4}{15}-\frac{3}{15}\\\\\frac{2}{3}|2-x|=\frac{1}{15}[/tex]