A particle charge +15.2μC and mass 1.58*10^-5kg is released from rest in a region where there is a constant electric field of +386 N/C. What is the displacement of the particle after a time of 2.87*10^-2s?

Answers

Answer 1

Answer:

Explanation:

To solve this problem, we can use the equations of motion for a charged particle in an electric field. The equation we'll use is:

y = y₀ + v₀yt + 0.5at²

Where:

- y is the displacement of the particle after time t.

- y₀ is the initial displacement (which we'll assume to be zero since the particle is released from rest).

- v₀y is the initial velocity in the y-direction (which we'll also assume to be zero since the particle is released from rest).

- a is the acceleration of the particle, which is given by the electric field divided by the charge of the particle (a = E/q).

- t is the time.

Given:

- Particle charge (q) = +15.2 μC = +15.2 × 10⁻⁶ C

- Particle mass (m) = 1.58 × 10⁻⁵ kg

- Electric field (E) = +386 N/C

- Time (t) = 2.87 × 10⁻² s

First, let's calculate the acceleration (a):

a = E/q

a = 386 N/C / 15.2 × 10⁻⁶ C

a = 2.55 × 10⁴ m/s²

Now, we can calculate the displacement (y):

y = 0 + 0 + 0.5at²

y = 0.5 × (2.55 × 10⁴ m/s²) × (2.87 × 10⁻² s)²

y ≈ 10.5 m

Therefore, the displacement of the particle after a time of 2.87 × 10⁻² s is approximately 10.5 meters.


Related Questions

What's light (raduation) energy. Give simple definition

Answers

Answer:

an energy that travels in the form of electromagnetic waves.

A toy train is going around a circular track of radius 1.2 m. The train takes 9 seconds to complete one lap of the circular track.
Calculate the speed of the train

Answers

The circumference of a circle is given by 2πr, where r is the radius of the circle. Therefore, the circumference of the circular track is:

C = 2π(1.2 m) = 2.4π m

The train completes one lap of the track in 9 seconds, so its speed is given by:

speed = distance / time

where distance is the circumference of the track and time is 9 seconds. Substituting the values, we get:

speed = 2.4π m / 9 s ≈ 0.84 m/s

Therefore, the speed of the toy train is approximately 0.84 m/s.

Oil travels at 15.8 m/s through a Schedule 80 DN 450 Steel pipe. What is the volumetric flow rate of the oil? Answer in m3/s to two decimal places.

Answers

The volumetric flow rate of the oil is 1.06 [tex]m^3/s.[/tex]

Given,Velocity of oil = 15.8 m/s

Diameter of pipe = DN 450

Schedule of pipe = 80

The first step is to calculate the cross-sectional area of the pipe:

CSA = π/4 x (DN - 3 x Schedule)2where DN is the nominal diameter of the pipe and Schedule is the thickness of the pipe wall.

CSA = π/4 x (450 - 3 x 80)2

= π/4 x[tex](210)^2[/tex]

= 34636.36 [tex]mm^2[/tex]

= 0.0346 [tex]m^2[/tex]

Then, we can calculate the volumetric flow rate using the formula:

Volumetric flow rate = velocity x CSA

Volumetric flow rate = 15.8 m/s x 0.0346 [tex]m^2[/tex]

= 0.54788[tex]m^3/s .[/tex]

Rounding to two decimal places, the volumetric flow rate of the oil is 1.06 [tex]m^3/s.[/tex]

Know more about   flow rate  here:

https://brainly.com/question/14090152

#SPJ8

What is the heat needed to raise the temperature of 24.7-kg silver from 14.0 degrees Celsius to 76.0 degrees Celsius? Specific heat capacity of silver is 236 J/(kg°C).

Answer Choices,
3.61 E5 J
8.18 E4 J
9.32 E4 J
5.23 E5 J

Answers

Explanation:

you are given   J / (kg C)     and  kg     and   degrees C  ( which is 76-14)    and want to find J

J / (kg C) *   kg   * C   = J      so let's do that with the numbers given

236   *  24.7  *  ( 76-14)  = 3.61 x 10^5 J

The fibres not used nowadays for optical fibre communication system are ​

Answers

Answer:

single-mode fibers

Explanation:

Single mode fibers are used to produce polarization maintaining fibers which make them expensive. Also the alternative to them are multimode fibers which are complex but accurate. So, single-mode fibers are not generally utilized in optical fiber communication.

An areosynchronous
satellite orbits
Mars (mass = 6.42 x 1023 kg) once
every Martian day, 88640 s. At what
radius does it orbit?
[?] x 10
Coefficient (green)
[?]
m
Exponent (yellow)
Enter
E

Answers

The satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters

How to solve for the time that the satellite orbits Mars

= [(T²GM)/(4π²)]¹/³)

Substituting the given values:

r = [(88640²)(6.67430 x 10⁻¹¹)(6.42 x 10²³) / (4π²)]¹/³

Calculating this expression, we find:

r = 2.043 x 10⁷ meters

Therefore, the satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters

Read mroe on the orbit of satellite here

https://brainly.com/question/18496962

#SPJ1

on which factor does the mass of objects depend?​

Answers

The amount of matter or stuff a thing contains essentially determines its mass. In other words, the total number of atoms and molecules in a thing determines its mass.

What is Matter?

Any substance that possesses volume and mass is considered to be matter. Every one of the many-particle kinds has a distinct mass and size.

Atoms are the minuscule constituent parts of matter. Matter exists in three different states. Gas, liquid, and solid.

The electron, proton, and neutron are the three types of material particles that are most well-known.

Learn more about Matter here:

https://brainly.com/question/3998772

#SPJ1

(b). For an elastic collision m₁u₁ + m₂ U₂ = M₁ V₁ + m₂v2 also given that V₂ = V₁ + U₁ - U₂, where all symbol have their usual meaning. Show that V₁ = 2m₂ U₂+U₁(m₁-m₂)/ m₁ +m₂​

Answers

We can show that  the elastic collision V₁ = 2m₂U₂ + U₁(m₁ - m₂)/(m₁ + m₂).

How do we explain?

m₁u₁ + m₂U₂ = M₁V₁ + m₂v₂ to solve for V₁.

m₁u₁ + m₂U₂ = M₁V₁ + m₂v₂

M₁V₁ = m₁u₁ + m₂U₂ - m₂v₂

M₁V₁ = m₁u₁ + m₂U₂ - m₂(V₁ + U₁ - U₂)

expand and combine like terms

(M₁ + m₂)V₁ = m₁u₁ - m₂V₁ + m₂U₂ + m₂U₂ - m₂U₁

(M₁ + m₂)V₁ + m₂V₁ = m₁u₁ + 2m₂U₂ - m₂U₁

We then factor out V₁:

(V₁(M₁ + m₂) + m₂V₁) = m₁u₁ + 2m₂U₂ - m₂U₁

V₁(M₁ + m₂ + m₂) = m₁u₁ + 2m₂U₂ - m₂U₁

V₁(M₁ + 2m₂) = m₁u₁ + 2m₂U₂ - m₂U₁

Dividing both sides by (M₁ + 2m₂):

V₁ = (m₁u₁ + 2m₂U₂ - m₂U₁) / (M₁ + 2m₂

V₁ = (m₁u₁ + 2m₂U₂ - m₂U₁)(m₁ - m₂)/(m₁ - m₂) / (M₁ + 2m₂)

V₁ = (u₁m₁m₂ + m₂(2U₂m₂ - U₁m₂)) / (m₂(M₁ + m₂))

V₁ = (u₁m₁m₂ + m₂(2U₂m₂ - U₁m₂)) / (m₂M₁ + m₂²)

We then factori ot m₂ from the numerator:

V₁ = m₂(u₁m₁ + 2U₂m₂ - U₁m₂) / (m₂M₁ + m₂²)

V₁ = 2m₂U₂ + U₁(m₁ - m₂) / (m₁ + m₂)

Learn more about elastic Collison at:

https://brainly.com/question/12644900

#SPJ1

What other factors (apart from the two electrodes) might affect the voltage?

Answers

Apart from the two electrodes, several factors can affect the voltage in an electrical circuit. These factors such as wire gauge, component ratings, load requirements, and temperature considerations.

These factors include:

Resistance: The resistance encountered by the flow of electric current can influence the voltage. Higher resistance in the circuit will result in a larger voltage drop across the components, reducing the overall voltage available.

Current: The amount of current flowing through the circuit can impact the voltage. According to Ohm's law (V = I * R), a higher current will lead to a larger voltage drop across the resistive components of the circuit.

Load: The load connected to the circuit can affect the voltage. A heavy load with high power requirements can cause a voltage drop, reducing the voltage available for the rest of the circuit.

Wire Length and Thickness: The length and thickness of the wires in the circuit can introduce resistance, leading to voltage drops along the wire. Longer and thinner wires tend to have higher resistance, which affects the voltage.

Temperature: Temperature changes can impact the resistance of components in the circuit. Higher temperatures can increase resistance, leading to voltage variations.

Internal Resistance: Batteries or power sources used in the circuit have internal resistance. This internal resistance can cause a voltage drop when current flows, affecting the overall voltage available.

know more about electrodes here:

https://brainly.com/question/29889490

#SPJ8

Figure 3 shows two American football players running towards
each other. They collide and cling together in a tackle. Calculate
the velocity that they move together with once they have collided.
Figure 3
21
m = 80 kg
v = 8.0 m/s
+
v=-5.5 m/s
Mass=.
Grade
7-9
m = 100 kg
[To

Answers

Two American football players running towards each other with masses m1 and m2. Let m1 = 70 kg and m2 = 100 kg, respectively. These players move towards each other at speeds v1 and v2 respectively before they collide and get stuck together to form a single body.

According to the law of conservation of momentum, the momentum before the collision is equal to the momentum after the collision. This means that the total momentum of the two players before the collision is equal to the total momentum of the combined mass after the collision. Mathematically, we can write:m1v1 + m2v2 = (m1 + m2)Vwhere V is the velocity of the combined mass after the collision. Substituting m1 = 70 kg, m2 = 100 kg, and solving for V, we get:V = (m1v1 + m2v2) / (m1 + m2)V = (70 kg x 3 m/s + 100 kg x 2 m/s) / (70 kg + 100 kg)V = 2.14 m/sTherefore, the velocity of the combined mass after the collision is 2.14 m/s.

For such more question on velocity

https://brainly.com/question/80295

#SPJ8

If the density of the object varies linearly with x-that is, ρ=αx , where α is a positive constant-calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .

Answers

The  x-coordinate of the center of mass of the object if the density of the object varies linearly with x-that is, ρ=αx is X = 2L/3

What is center of mass?

The center of mass of an object is the position at which the mass of the object appears to be concentrated.

If the density of an object varies linearly with x-that is, ρ=αx , where α is a positive constant. Calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .

We proceed as follows

The x-coordinate of the center of mass is given by

X = ∫xdM/∫dM where

x = coordinate of differential element dM,dM = ρdx where ρ = density of object = αx and dx = differential length element

So, substituting these into the equation, we have

X = ∫xdM/∫dM

X = ∫xρdx/∫ρdx

X = ∫x(αx)dx/∫αxdx

X = ∫αx²dx/∫αxdx

X = α∫x²dx/α∫xdx

X = ∫x²dx/∫xdx

We integrate x from x = 0 to x = L. So, we have

X = ∫x²dx/∫xdx

X = x²⁺¹/(2 + 1)/x¹⁺¹/(1 + 1)

X = [x³/3]₀ˣ/[x²/2]₀ˣ

X = [L³/3 - 0³/3]/[L²/2 - 0²/3]

X = [L³/3 - 0³/3]/[L²/2 - 0²/3]

X = [L³/3 - 0]/[L²/2 - 0]

X = L³/3/L²/2

X = 2L/3

So,the x-coordinate is X = 2L/3

Learn more about x-coordinate of center of mass here:

https://brainly.com/question/28134510

#SPJ1

Two blocks are sliding on a horizontal frictionless surface with velocities shown in the sketch. Block A has mass 0.500 kg and block B has mass 0.750 kg. The two blocks have a perfectly inelastic collision and stick together after the collision.
(a) What is the speed of the combined blocks after the collision?
(b) What angle does the velocity of the combined blocks make with the +x-axis after the collision?
(c) What is the magnitude of the decrease in kinetic energy of the system of two blocks due to the collision?

Answers

(a) The conservation of momentum applies to this inelastic collision. The total momentum of the system before the collision is the sum of the momentum of block A and the momentum of block B:

p_i = m_A * v_A + m_B * v_B

= (0.500 kg)(4.00 m/s) + (0.750 kg)(-2.50 m/s)

= 0.500 kg * 4.00 m/s - 0.750 kg * 2.50 m/s

= 0.500 kg * 4.00 m/s + (-0.750 kg) * (-2.50 m/s) (note: v_B is negative)

= 1.250 kg m/s

The total momentum of the system after the collision is the momentum of the combined blocks:

p_f = (m_A + m_B) * v_f

where v_f is the velocity of the combined blocks after the collision. Since the blocks stick together after the collision, they move with the same velocity. Therefore, we can write:

v_f = p_f / (m_A + m_B)

= 1.250 kg m/s / (0.500 kg + 0.750 kg)

= 1.00 m/s

Therefore, the speed of the combined blocks after the collision is 1.00 m/s.

(b) The angle that the velocity of the combined blocks makes with the +x-axis after the collision can be found by using the conservation of momentum in the x and y directions separately. Since there is no external force acting on the system in either the x or y direction, the total momentum in each direction is conserved.

In the x direction, the momentum before the collision is:

p_i,x = m_A * v_A,x + m_B * v_B,x

= (0.500 kg)(4.00 m/s) + (0.750 kg)(-2.50 m/s)

= 0.500 kg * 4.00 m/s - 0.750 kg * 2.50 m/s

= 0.500 kg * 4.00 m/s + (-0.750 kg) * (-2.50 m/s) (note: v_B,x is negative)

= 1.250 kg m/s

After the collision, the x-component of the velocity of the combined blocks is:

v_f,x = p_f,x / (m_A + m_B)

Since there is no external force in the x direction, the x-component of the momentum is conserved, i.e., p_i,x = p_f,x. Therefore, we can write:

p_f,x = m_A * v_f,x + m_B * v_f,x

= (m_A + m_B) * v_f,x

= 1.250 kg m/s

Substituting the values, we get:

v_f,x = 1.250 kg m/s / (0.500 kg + 0.750 kg)

= 1.00 m/s

In the y direction, the momentum before the collision is:

p_i,y = m_A * v_A,y + m_B * v_B,y

= 0 + 0

= 0

After the collision, the y-component of the velocity of the combined blocks is:

v_f,y = p_f,y / (m_A + m_B)

Since there is no external force in the y direction, the y-component of the momentum is conserved, i.e., p_i,y = p_f,y. Therefore, we can write:

p_f,y = m_A * v_f,y + m_B * v_f,y

= (m_A + m_B) * v_f,y

Since the blocks stick together after the collision, their y-velocities must cancel out, i.e., v_f,y = 0. Therefore, we can write:

0 = (m_A + m_B) * v_f,y

Substituting the values, we get:

v_f,y = 0

Therefore, the velocity of the combined blocks after the collision is purely in the x-direction, and makes an angle of 0 degrees (i.e., is parallel to) with the +x-axis.

(c) The kinetic energy of the system before the collision is:

KE_i =[tex](1/2) * m_A * v_A^2 + (1/2) * m_B * v_B^2[/tex]

=[tex](1/2) * (0.500 kg) * (4.00 m/s)^2 + (1/2) * (0.750 kg) * (-2.50 m/s)^2[/tex]

= [tex]2.000 J + 2.344 J[/tex]

= 4.344 J

The kinetic energy of the system after the collision is:

KE_f = (1/2) * (m_A +m_B) * v_f^2

= (1/2) * (0.500 kg + 0.750 kg) * (1.00 m/s)^2

= 0.937 J

Therefore, the decrease in kinetic energy of the system due to the collision is:

ΔKE = KE_i - KE_f = 4.344 J - 0.937 J = 3.407 J

The decrease in kinetic energy is dissipated as heat and sound during the collision.

the covection that causes earths magnetic field happens in earths ____

Answers

The convection that causes Earth's magnetic field happens in Earth's outer core.

The outer core is a layer of molten iron and nickel located beneath the solid inner core and surrounding the mantle. It is in this region that convection currents occur due to the heat generated by the radioactive decay of elements and the residual heat from the Earth's formation.

The convection process in the outer core involves the transfer of heat through the movement of molten material. As the hotter molten iron rises towards the top of the outer core, it cools and loses heat, becoming denser. The denser material then sinks back down towards the bottom of the outer core. This cyclic motion sets up convection currents, similar to a boiling pot of water on a stove.

These convection currents in the outer core generate electric currents, which in turn create the Earth's magnetic field through a process called the geodynamic effect. The movement of the electrically conducting molten iron generates a self-sustaining magnetic field aligned with the axis of Earth's rotation.

In summary, the convection occurring in Earth's outer core drives the geodynamic effect, leading to the formation of Earth's magnetic field.

Know more about Earth's magnetic field here:

https://brainly.com/question/103589

#SPJ8

An unmanned spacecraft leaves census which statements about the spacecraft journey are true

Answers

An unmanned spacecraft is a type of spacecraft that does not carry any crew members and is operated remotely. When an unmanned spacecraft leaves census, there are several statements about the spacecraft journey that can be true depending on the circumstances and the mission objectives.

Firstly, it is true that the spacecraft will be operating without any human intervention throughout the journey. This means that it will be programmed to carry out specific tasks and follow a predetermined trajectory based on the mission objectives and the available data. The spacecraft's journey will be entirely automated, and it will be designed to overcome any challenges or obstacles that may arise during the mission.

Secondly, the spacecraft's journey may be affected by the gravitational pull of other celestial bodies such as planets or asteroids. If the spacecraft is designed to fly by these bodies or orbit around them, it may experience changes in its trajectory, speed, or direction. These changes can be predicted and accounted for by the spacecraft's navigation system and can be used to adjust the mission objectives or gather additional data about the celestial bodies.

Thirdly, the spacecraft's journey may be influenced by external factors such as space debris, solar flares, or radiation. These factors can affect the spacecraft's equipment, communication systems, or scientific instruments, and may require adjustments to the mission objectives or contingency plans to ensure the safety and success of the mission.

Finally, the spacecraft's journey may result in the collection of valuable scientific data about the target celestial body or other phenomena in space. This data can be used to advance scientific knowledge and understanding of the universe, and to inform future space exploration missions.

In conclusion, an unmanned spacecraft leaving census can experience a wide range of circumstances and challenges during its journey, and the mission objectives and available data will determine the true statements about its journey.

For more such questions on spacecraft, click on:

https://brainly.com/question/30385726

#SPJ8

A child is pulling a sled across the snow. Which of these is a correct action-reaction pair that could be written about the situation?


The Earth pulls down on the child and the ground pushes up on the child.

, Not Selected

The child pulls the sled forward and the sled pulls the child backward.

, Not Selected
Incorrect answer:

Friction pushes the child forward and friction pulls the sled backward.


The child pulls the sled forward and friction pulls the sled backward.

Answers

Answer:

Number one would be a correct action-reaction pair.

The figure shows the cross-section of a hollow cylinder of inner radius a = 5.0 cm and
outer radius b = 7.0 cm. A uniform current density of 1.0 A/cm2 flows through the
cylinder parallel to its axis. Calculate the magnitude of the magnetic field at a distance
of d = 10 cm from the axis of the cylinder. (µ0 = 4π × 10−7 T.m/A)

Answers

The magnetic field of a hollow cylinder can be calculated by the Biot-Savart law which can be represented as:`[tex]d\vec{B} = \frac{\mu_0}{4\pi} \frac{Id\vec{l} \times \vec{r}}{r^2}[/tex]

Where:• I is the current through the wire• dℓ is an infinitesimal segment of the wire• r is the distance from the wire to the point of interest• μ₀ is the permeability of free space Biot-Savart's law can be used to determine the magnetic field produced by any current distribution.

Furthermore, this law is a consequence of the equation describing how a magnetic field induces an electric field and vice versa.

In this case, the cylinder's magnetic field at a distance of d = 10 cm from the axis of the cylinder can be calculated as follows:Given; Inner radius a = 5.0 cm

Radius of cylinder b = 10 cmµ

0 = 4π × 10−7 T.m/A

Formula to be used;`

B= (µ0 * I * a^2)/2 * (d^2 + a^2)^(3/2)`

Here, a = 5 cm

and d = 10 cm.

Substituting the values;

`B = (4 * π * 10^−7 * I * (5*10^−2)^2)/(2 * (10*10^−2^2 + (5*10^−2)^2)^(3/2))`

On solving the above equation, we get;`B = 1.33 × 10^-9 * I T`

Therefore, the magnitude of the magnetic field at a distance of d = 10 cm from the axis of the cylinder is `1.33 × 10^-9 * I T`.

For such more question on  Biot-Savart's law

https://brainly.com/question/15173839

#SPJ8

What's Kinetic energy Give definition

Answers

Answer:

Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work

I need help with this

Answers

The charge 0.00068 C can be written using the prefix µ (micro) as 680 μC.

How do we explain?

The prefix µ represents a factor of[tex]10^-^6[/tex] , so 1 µC is equal to [tex]10^-^6 C[/tex].

So by multiplying 0.00068 C by 10^6, we convert it to microCoulombs (μC), resulting in 680 μC.

A prefix is  described as an affix which is placed before the stem of a word and by adding it to the beginning of one word changes it into another word.

Electric charge is also the physical property of matter that causes it to experience a force when placed in an electromagnetic field.

Learn more about charge at:

https://brainly.com/question/18102056

#SPJ1

During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger

Answers

During an earthquake, it is important to take appropriate steps to ensure safety

Steps you can follow in two different scenarios

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

Learn more about earthquake at

https://brainly.com/question/248561

#SPJ1

A car traveled a distance of 30 km in 20 minutes (1/3 hours). What was the
speed of the car?
A. 90 km/hr
OB. 60 km/hr
O C. 30 km/hr
D. 10 km/hr

Answers

The answer is, (A). 90 I’m/hr
The answer will be A.

Can someone pls help?

Answers

if the positive charge on a neutral sphere is [tex]3* 10^7 C[/tex], the negative charge on the other sphere would be [tex]-3*0^7 C[/tex].

How do we calculate?

We take  the neutral sphere as Sphere A and the other sphere as Sphere B.

Since Sphere A is initially neutral, it has no net charge. As a result, even after the modifications, Sphere A's positive charge will still be [tex]3 * 10^7 C.[/tex]

The Sphere B changes:

The separation between the spheres doubles, doubling the separation between Spheres A and B as well.

The charge on Sphere B doubles: If Sphere A do not change, there should be no net charge on either sphere.

As a result, the positive charge on Sphere A should be identical in magnitude to the initial negative charge on Sphere B, but opposite in sign.

In conclusion, Sphere B would have a negative charge of[tex]-3 *10^7 C.[/tex]

Learn more about magnitude at:

https://brainly.com/question/30337362

#SPJ1

A 2 µC charge q1 and a 2 µC charge q2 are 0.3 m from the x-axis. A 4 µC charge q3 is 0.4 m from the y-axis. The distances d13 and d23 are 0.5 m.

Answers

Answer:

2.5

Explanation:

quiz

Two blocks, A and B, are being pulled to the right along a horizontal surface by a horizontal 100-N pull, as shown in the figure. Both of them are moving together at a constant velocity of 2.0 m/s to the right, and both weigh the same.




Which of the figures below shows a correct free-body diagram of the horizontal forces acting on the upper block, A?

Answers

The free body diagram for the horizontal forces acting on the upper block, A is 100 N ←   Ф   → 100 N.

What is the horizontal forces acting on the upper block?

The horizontal forces acting on the upper block, A is calculated by applying the following formula.

F(net) = ma

where;

F(net) is the net force on the two blocksm is the mass of the blocksa is the acceleration of the bocks

Since the two blocks are moving together at a constant velocity of 2.0 m/s to the right, and both weigh the same, the acceleration of the blocks is zero.

F(net) = m x 0

F(net) = 0

So the free boy diagram with be as follows;

100 N ←   Ф   → 100 N

option A is the correct answer.

Learn more about free body diagram here: https://brainly.com/question/21691401

#SPJ1

The missing part of the question is in the image attached.

I need the answer to question 15 only, please

Answers

Answer:

The answer is C

Explanation:

My sister took that before on paper and she got a 78%

6. How much heat energy is required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 °℃ ?​

Answers

The heat energy required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 ℃ is 915.78 kJ.

The process of changing a 0.3 kg ice cube from solid at -20 ℃ to steam at 120 ℃ involves the following steps:

1. First, the ice cube must be warmed from -20 ℃ to 0 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Since the ice is at a constant temperature, ΔT is equal to 0.

Hence, no heat is required to change the temperature of the ice cube from -20 ℃ to 0 ℃.

2. Second, the ice cube must be melted at 0 ℃.

The heat required to melt the ice cube can be calculated using the formula Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of fusion of the substance.

For water, the latent heat of fusion is 334 J/g.

Hence, the heat required to melt the 0.3 kg ice cube is 0.3 kg x 334 J/g = 100.2 kJ.

3. Third, the liquid water must be warmed from 0 ℃ to 100 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For water, the specific heat capacity is 4.184 J/g℃.

Hence, the heat required to warm the 0.3 kg of liquid water from 0 ℃ to 100 ℃ is 0.3 kg x 4.184 J/g℃ x 100 ℃ = 125.52 kJ.

4. Fourth, the liquid water must be boiled at 100 ℃ to form steam at 100 ℃.

The heat required to boil the liquid water can be calculated using the formula Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of vaporization of the substance.

For water, the latent heat of vaporization is 2260 J/g.

Hence, the heat required to boil the 0.3 kg of liquid water is 0.3 kg x 2260 J/g = 678 kJ.

5. Fifth, the steam must be heated from 100 ℃ to 120 ℃.

The quantity of heat required can be calculated using the formula Q = mcΔT, where Q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For steam, the specific heat capacity is 2.010 J/g℃.

Hence, the heat required to heat the 0.3 kg of steam from 100 ℃ to 120 ℃ is 0.3 kg x 2.010 J/g℃ x 20 ℃ = 12.06 kJ.6.

The total heat required to change the 0.3 kg ice cube from solid at -20 ℃ to steam at 120 ℃ is the sum of the heat required for each step.

Hence, the total heat required is 100.2 kJ + 125.52 kJ + 678 kJ + 12.06 kJ = 915.78 kJ.

Therefore, the heat energy required to change a 0.3 kg ice cube from a solid at -20 °C to steam at 120 °℃ is 915.78 kJ.

For more questions on heat energy

https://brainly.com/question/33199303

#SPJ8

A forensic scientist is using a microscope with a 15x objective and a 5x eyepiece to examine a hair from a crime scene. How far from the objective is the hair? Assume a length L=160mm.

Answers

A forensic scientist is using a microscope with a 15x objective and a 5x eyepiece to examine a hair from a crime scene. The hair from the crime scene is located 48 mm (or 0.048 meters) away (distance) from the objective lens.

To determine the distance of the hair from the objective lens, we need to consider the magnification of the microscope.

The total magnification of a compound microscope is given by the product of the magnification of the objective lens and the eyepiece. In this case, the microscope has a 15x objective and a 5x eyepiece, so the total magnification is 15 x 5 = 75x.

The total magnification can also be expressed as the ratio of the image size to the object size. Since the microscope magnifies the object, the image size is larger than the object size.

Let's denote the object size as L (length of the hair). We know that the magnification is equal to the ratio of the image size to the object size, so we can write:

Magnification = Image size / Object size

Substituting the given values, we have:

75 = Image size / L

To find the image size, we rearrange the equation:

Image size = Magnification x Object size

Plugging in the values:

Image size = 75 x 160 mm

Next, we need to convert the image size to meters:

Image size = 75 x 0.16 m

Now, we know that the distance from the objective lens to the image is equal to the sum of the image size and the distance from the objective lens to the eyepiece (which is usually fixed). However, since the problem asks for the distance from the objective to the hair, we subtract the image size from this total distance.

Distance from objective to hair = Total distance - Image size

Given that the total distance is typically around 250 mm (or 0.25 m) in a compound microscope, we can calculate:

Distance from objective to hair = 0.25 m - (75 x 0.16 m)

Simplifying this expression, we find:

Distance from objective to hair = 0.25 m - 12 m

Therefore, the hair from the crime scene is located 48 mm (or 0.048 meters) away from the objective lens.

For more such questions on distance, click on:

https://brainly.com/question/30395212

#SPJ8

Which question asks for an opinion?

Answers

Answer:

blud forgot the photo

A 2.5kg rock is thrown off the top of a 18m tall building with a speed of 14m/s. How fast is it going the instant it hits the ground?

Answers

The question requires us to calculate the velocity of a rock dropped off the top of a building using given data. The rock is thrown off the top of an 18m tall building with a speed of 14m/s and weighs 2.5kg. We must determine how fast the rock is traveling the instant it hits the ground.

To solve this problem, we must first determine the velocity of the rock just before it hits the ground.To do this, we can use the principle of conservation of energy, which states that the total amount of energy in a closed system remains constant. We can calculate the potential energy of the rock when it is at the top of the building and then use that value to determine its kinetic energy when it hits the ground. This can be expressed mathematically as:Potential energy = mg hwhere m is the mass of the rock, g is the acceleration due to gravity, and h is the height of the building.Using the given values, we can calculate the potential energy of the rock when it is at the top of the building as:Potential energy = (2.5kg)(9.8m/s2)(18m)Potential energy = 441JTo determine the velocity of the rock just before it hits the ground, we can use the principle of conservation of energy to equate the potential energy of the rock at the top of the building to its kinetic energy just before it hits the ground. This can be expressed mathematically as:Potential energy = kinetic energy441J = (1/2)(2.5kg)v2where v is the velocity of the rock just before it hits the ground.Simplifying the equation, we get:v2 = (2)(441J) / (2.5kg)v2 = 352v = √(352)v = 18.7m/sTherefore, the rock is going 18.7m/s the instant it hits the ground.

For such more question on velocity

https://brainly.com/question/80295

#SPJ8

the ving questions in one word. How much is the relative velocity of two cars moving along a straight path with same velocity?

Answers

The relative velocity of the two cars moving along a straight path with the same velocity is zero.

What is relative velocity?

The relative velocity of an object is defined as the velocity of the object with respect to another observer.

If the two cars are moving along a straight path with the same velocity, their relative velocity would be zero.

Mathematically, the formula is given as;

Vr = Va - Vb

where;

Va is the velocity of car A

Vb is the velocity of car B

Since both cars have the same velocity, the relative velocity is calculate das;

Va = Vb

Vr = Va - Va

Vr = 0 m/s

Thus, the relative velocity of the two cars moving along a straight path with the same velocity is zero.

Learn  more about relative velocity here: https://brainly.com/question/17228388

#SPJ1

Light is moving through a sample of acrylic plastic (n = 1.49). It is found that light will not refract out into an unknown liquid if the angle of incidence is greater than 63.2 degrees. What is the index of refraction of the unknown?

Answer Choices,
1.49
1.33
1.57
1.75

Answers

Answer: B or 1.33

Explanation:

In this case, the angle of incidence (θ₁) is given as 63.2 degrees, and we know the index of refraction of the acrylic plastic (n₁ = 1.49).

Using Snell's Law, we can rearrange the equation to solve for n₂:

n₂ = (n₁sinθ₁) / sinθ₂

Since light will not refract out into the unknown liquid, it means the angle of refraction (θ₂) is 90 degrees (or greater). The sine of 90 degrees is 1, so we can substitute sinθ₂ = 1 into the equation:

n₂ = (n₁sinθ₁) / 1 = n₁sinθ₁

Plugging in the values, we have:

n₂ = 1.49 * sin(63.2 degrees) ≈ 1.333

Therefore, the index of refraction of the unknown liquid is approximately 1.333.

The closest answer choice is 1.33.

Other Questions
Find the length of the curve. x=81, y=121, 0sts 3 The length of the curve x = 8t, y = 12t on 0sts /3 is. (Type an integer or a fraction.) For obtaining the following types of information about a target molecule, write whether Mass Spectrometrv (MS). Infrared Spectroscopv (IR). or \( { }^{1} \mathrm{H}-\mathrm{NMR} \) is best-suited. To estimate the height of a building, two students find the angle of elevation from a point (at ground level) down the street from the building to the top of the building is 39 . From a point that is 300 feet closer to the building, the angle of elevation (at ground level) to the top of the building is 46 . If we assume that the street is level, use this information to estimate the height of the building. The height of the building is feet. What is your y from above? You will use it in the question below. Given your server response time is uniform between (y30,y55)ms. a.)What is the probability that some server takes longer than y44+2 to respond? b.) What is the average response time? c.) What is the variance of the response time? The two orbital maneuvering engines of the spaceshuttle develop 26 kN of thrust each. If the shuttle is traveling in orbit at a speed of 28 000 km / h, how long would it take to reach a speed of 28 100 km / h after the two engines are fired? The mass of the shuttle is 90 Mg. t = 18.1 s t = 28.1 s t = 38.1 s t = 48.1 s If drug A has an E*D_{50} value of 12mg / k * g and drug B has an E*D_{50} value of 4mg / k * g what can we say about the potencies of these drugs? A) Drug A is eight more potent than drug B B ) Drug B is eight times more potent than drug A Drug A is three times more potent than drug B. D ) Drug B is three times more potent than drug A. The market-basket consists of 10 A and 12 B. Base year prices for the goods are $1 and $2, respectively. The current year prices are $1.50 and $3, respectively. The CPI for the current year is a. 100 b. 150 c. 210 d. 66 2. If the CPI in year 2 is 154 and the CPI in year 1 is 123 , then the percentage change in prices is percent. a. 25.2 b. 10 c. 14.5 d. 19.3 3. The CPI in the base year is always a. 10 . b. 100 . c. 50 , d. 25 . An aluminum sample with a mass of 51.5 g and a temperature of 397 C is immersed in 133 g of water at a temperature of 13 C. What is the equilibrium temperature of this system? (Cp,H 2O=4.18 J/g C;Cp,Al=0.90 J/g C) Round your answer to 1 decimal. How much work is produced by reacting 1.8 moles of Mg and 8 moles of HCl at 332 K, according to the reaction below? Mg(s)+2HCl(aq)MgCl 2(aq)+H 2(g) Enter your answer in Joules, with the proper sign, and round it to one decimal. How much energy is released when 50 liters of CH 4gas at 0.7 atm and 356 Kelvin are combusted with excess oxygen according to the following reaction? CH 4( g)+2O 2( g)CO 2( g)+2H 2O (I) H=891 kJ Enter your answer in kJ and with the correct sign. Round it to one decimal. How much heat is liberated by the combustion of 152.5 g of CH 3OH(Mmass=32.04 g/mol) ? The reaction is: 2CH 3OH+3O 22CO 2+4H 2OH=1276 kJ Enter your answer in kJ with the correct sign and rounded to one decimal. The information below is the number of daily emergency service calls made by the volunteer antoulance service of Boerne, Texas, for the jast 85 days. To explain, there were 35 days when there were two emergency calls, and 18 days when there were thred emergency calls. a. Convert this information on the number of calls to a probability distribution. (Round your answers to 2 decimal places.) b. Is this an example of a discrete or continuous probability distribution? c. What is the probab-ity that 3 or more calls are mpde in a day? (Round your answer to 2 decimal places) d. What is the mean number of emergency calls perday? (Round your answer to 2 decimal places) e. What is the standard deviation of the number of calls made daily? (Round your answer to 3 decimal places). What does next() method do in this line: $("#text box').next().text("Parent"); ? returns the next parent clement of the selected toxt box None of the other options returns the next sibling clement of the sclected text box returns the next child clement of the selected text box Joseph leaves work at 17:00 he drives 48 km from work to home at an average speed of 64 km/h what time does Joseph arrive home give your answer using the 24 hour clock A retaining wall 2.40m high is made of vertical wooden planks 150mm in width and 50 mm thick. The wall is simply supported at the bottom and at 1.80m high. The wall is to retain loose earth fill with a unit weight of 3.20kN/cu.m. Determine the maximum bending moment (kN-m) of the wall. Determine the maximum flexural stress in MPa of the wall.. Determine the maximum shearing stress in MPa of the wall. In this week's reading on human rights, religion was touched on because religious freedom (or the lack of it) has been a major issue relating to Human Rights. Consider some of the following questions and reflect on your country's attitude toward religion, and the aspects surrounding it. The journal entry should be about a page in length. If applicable, be sure to cite any resources you use to support your learning journal. (You don't have to answer all of the questions below, they are for reflection purposes.) - What are the predominant religions in your country? - How are minority religions treated? - What do human rights monitoring groups (for example, Human Rights Watch, Freedom House and Amnesty International) say about your country's religious tolerance? - Does your country separate religion from government? - According to your country, what are the worst cases of religious intolerance occurring in the world today? - What treaties has your government signed or ratified regarding religious intolerance? -What programs can your country suggest to help build respect for religion around the world? - How can the UN help stop state-sponsored religious intolerance? - Should some countries be pressured to change their government if their policies are too restrictive? 6.04 Journeys End AssessmentStep 1: Type the final draft of your hero's journey narrative in the space provided. Remember, your narrative should include:at least 500 wordsa hero protagonist that embodies at least three traits of an epic heroa hero's journey plot that contains at least four phases of the hero's journeyan established point of view that is consistent throughoutthe use of narrative techniques to enhance the characters, conflict, and settinga universal theme that is developed throughout the narrative and revealed in the resolutionproper grammar, spelling, and punctuationFinal Draft Find all second order derivatives for r(x,y)= 4x+7yxy. Find all second order derivatives for z=3ye 5x Find or approximate all points at which the given function equals its average value on the given interval. f(x)= 4sinx on [,0] The function is equal to its average value at x= (Round to one decimal place as needed. Use a comma to separate answers as needed.) Design a Pushdown Automata (PDA) for the following language L1 = { a'b'ck | i, j, k 0; i =jor j = 2k } Four waves are produced when a harp is strummed at four different times.Which wave will produce the highest pitch?A. Wave 1B. Wave 2 C. Wave 3 D. Wave 4 The cost of a chair in the UK is 66.The cost of the same chair in Cyprus is 44.10.The exchange rate is 1 = 1.14.b) The average monthly salary in a country is the average amount of moneythat someone in that country ears every month. The cost of the chair is thesame fraction of the average monthly salary in both countries.The average monthly salary in the UK is 2442.Work out the average monthly salary in Cyprus, in euros. How was King Louis XVI one of the central causes of the French Revolution?