Answer:
1 W
Explanation:
Power is the ratio of the total work done by the body to the time it will takes to do the work.
Therefore Power = total work done ÷ timeTotal Work done = Potential energy (P.E) = mgh
Total work done = mgh
Total work done = 1kg × 10m/s² × 1m
Total work done = 10 J
Therefore Total Work done is 10J.
And then time is 10 s.
Power = Total Work done divided by time
Power = 10 J÷ 10 s = 1 W
Therefore Power is 1WA teacher wants to demonstrate that the radioactive source emits alpha beta and gamma radiation. Describe a method the teacher could use (IMPORTANT REPLAY ASAP) I will give Brainly
By using an electric field, it is feasible to differentiate between these different forms of radiation.
What is a radioactive source?A source that emits radiation like gamma, beta, and alpha rays is said to be radioactive. Using an electric field, we can discriminate between these different forms of radiation.
The field does not deflate the gamma rays, but it does deflate the alpha and beta rays, with the alpha being deflated to the field's negative portion and the beta to its positive part.
Hence, by using an electric field, it is feasible to differentiate between these different forms of radiation.
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How many significant digits should the answer to the following problem have? (2.49303 g) * (2.59 g) / (7.492 g) =
The number of significant digits to the answer of the following problem is four.
What are the significant digits?The number of digits rounded to the approximate integer values are called the significant digits.
The following problem is
(2.49303 g) * (2.59 g) / (7.492 g) =
On solving we get
= 0.86184566204
The answer is approximated to 0.86185
Thus, the significant digits must be four.
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A 545 N sled is pulled a distance of 385 m. The task is done by pulling on a rope with a force of 1225 N at an angle of 19° with the horizontal. How much work is done in pulling the sled? What is the acceleration in the x direction, assuming that friction is negligible? Assuming the sled started at rest, how long does it take to pull the sled 185 m?
The work done in pulling the sled is 445,930.2 Joules.
The acceleration in the x direction, assuming that friction is negligible, is 20.85 m/s².
Time taken to pull the sled 185 m is 4.21s.
What is work done?Work done is equal to product of force applied and distance moved.
Given is a 545 N sled is pulled a distance of 385 m. The task is done by pulling on a rope with a force of 1225 N at an angle of 19° with the horizontal.
Work = Force x Distance x cos(angle)
W= 1225 x 385 x cos 19°
W = 445,930.2 Joules
Thus, the work done in pulling the sled is 445,930.2 Joules
From the Newton's second law of motion, we have'
F = ma
acceleration, a = 1225cos19° / ( 545 /9.81)
a = 20.85 m/s²
Thus, the acceleration in the x direction is 20.85 m/s²
Using the second equation of motion, we get
s = ut+ 1/2 at²
Substitute the values, we have
185 m = 0 +1/2 x 20.85 x t²
t = 4.21 s
Thus, the time taken to pull the sled 185 is 4.21s.
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Two particles P and Q each moves towards ther along Straight Line (M)(N), 51m long. P starts from M with velocity 5m/s and constant acceleration Of 1m/s². Q Starts from N at the Same time with velocity 6m/s and at a Constant acceleration of 3m/s². find the time when the
a) Particles are 30m apart, 13
b) Particles meet
c) velocity of P is ¾ of the velocity of Q
The time required by the particles are as follows:
a. t = 1.5 seconds
b. t = 3 seconds
c. t = 0.4 seconds
What is the time required?The time required for the particles to be at several distances apart is calculated using the equation of motion given below:
[tex]S = ut + \frac{1}{2}at^{2}[/tex]
a) Time required to be 30 m apart:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51 - 30
S1 + S2 = 21
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 21
2t^2 + 11t - 21 = 0
Solving for time, t by factorization, t = 1.5 seconds
b) Time required to meet:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 51
2t^2 + 11t - 51 = 0
Solving for time, t by factorization, t = 3 seconds
c) Time required for velocity of P is ¾ of the velocity of Q:
Using the equation of motion: V = u + at
Vp = 3/4 Vq
4Vp= 3Vq
Substituting the values:
4(5 + t) = 3(6 + 3t)
5t = 2
t = 0.4 seconds
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A person who falls between introversion and extroversion is
Answer:
the answer is ambivert have a good fourth of July
Answer:
i believe the answer is ambivert
If the frequency of a FM wave is 8.85 × 107 hertz, what is the period of the FM wave?
Answer:
1.1299 x 10^-8 second
Explanation:
Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8 sec
Which has more mass - a 5-kg bag of feathers or a 5-kg
cannon ball?
Answer:equal mass
Explanation:the mass of both is 5kg
What type of power plant burns material to make electricity?
O A. Geothermal
OB. Hydroelectric
OC. Fossil fuel
OD. Radiant
The type of power plant burns material to make electricity is Fossil fuel. The correct option is C.
What is energy?Energy is the ability to do work.
There are different kind of energies like kinetic energy, potential energy, gravitational energy and heat energy.
The energy obtained from burning different type of materials like Coal, gas and oil and produces heat.
Fossil fuel power plants burn coal or oil to create heat and generate steam to run turbines which generate electricity.
Thus, the correct option is C.
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Resolve the vector shown below into its components.
Answer:
D. s=3x+4y
Explanation:
The line is at the 3rd column in the 4th row.
What quantity is represented by a unit called a newton (N)?
A. Inertia
B. Acceleration
C. Force
D. Mass
[tex]\textsf {C. Force}[/tex]
[tex]\textsf {The quantity which is represented by a unit called Newton (N)}\\\textsf {is Force.}[/tex]
A uniform, 255 N rod that is 1.80 m long carries a 225 N weight at its right end and an unknown weight W toward the left end. When W is placed 60.0 cm from the left end of the rod, the system just balances horizontally when the fulcrum is located 75.0 cm from the right end.
Part a) Find W.
Part b) If W is now moved 20.0 cm to the right, how far must the fulcrum be moved to restore balance? Δx = ?
Part c) If W is now moved 20.0 cm to the right, in what direction must the fulcrum be moved to restore balance?
(a)The value of W for the given condition will be 237.3 N.
(b)The distance must the fulcrum be moved to restore balance will be 0.070 m.
What is the center of mass?A location is established in relation to an object or set of objects in the center of mass. It is the system's average position across all of its components.
Given data;
Weight is applied to the right end of the rod, W₁= 225 N
Rod's weight,W₂ = 255
W₃ is the Weight at "x" distance from the left end.
x1 is the location of W₁ with respect to the left end, where L = 1.80 m
m is the location of the rod's center of mass from the left end.
The position of W from the left end; x₃ = 50 cm = 0.50 m
Xcm is the position of the center of gravity of the rod at the fulcrum from the left end;
Given that the fulcrum is balanced in this situation, the rod's center of gravity will be there.
Xcm= L - 75 cm
Xcm=1.80 m - 0.75 m
Xcm= 1.05 m
The value of x₂
x₂= 1.80 m/2 = 0.90 m
Currently, the horizontal center of gravity is determined by
[tex]\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3*x_3)}{(W_1 + W_2 + W_3)}[/tex]
Substitute the values we get;
[tex]\rm 1.05 = \fraca{ (225 \times 1.80 + 255\times 0.90 + W\times 0.50)}{(225 + 255 + W)}\\\\ W = \frac{ (225\times 1.80 + 255\times 0.90 - 480 \times 1.05)}{(1.05 - 0.50)}\\\\ W = 237.3 \ N[/tex]
After moving the fulcrum 20.0 cm to the right,
The location of the W from the left end;
x₃ = .50 cm + 20 cm
x₃ = 70 cm
x₃ = 0.70 m
W₁, W₂, W, x₁, and x₂ have fixed values. Therefore, based on these values, the new center of gravity will be:
[tex]\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3*x_3)}{(W_1 + W_2 + W_3)}[/tex]
[tex]\rm X_{cm} = \frac{(225\times 1.80 + 255\times 0.90 + 237.3\times 0.70)}{(225 + 255 + 237.3)}\\\\ X_{cm} = 1.12 m[/tex]
Fulcrum must be shifted by;
Y = (1.12 - 1.05)
Y= 0.070 meters.
W has been moved in the appropriate direction, thus the fulcrum should likewise be moved in the appropriate direction.
Hence, the value of W for the given condition will be 237.3 N. and the distance must the fulcrum be moved to restore balance will be 0.070 m.
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Erbium-165 has a half-life of 10.4 hours. If you start with 1,000 grams of
erbium-165, how much time will it take to have 125 grams of erbium-165 left
in the sample?
A. 41.6 hours
OB. 20.8 hours
C. 31.2 hours
D. 10.4 hours
The amount of time it will take to have 125 grams of erbium-165 left
in the sample is; C: 31.2 hours
How to calculate decay time?The formula for amount of substance after decay is;
N(t) = N₀(¹/₂)^(t/t_¹/₂)
We are given;
Half life; t_¹/₂ = 10.4 hours
Initial amount; N₀ = 1000 g
Amount left; N(t) = 125 g
Thus;
125 = 1000 * (¹/₂)^(t/10.4)
125/1000 = (¹/₂)^(t/10.4)
In 0.125 = (t/10.4) In 0.5
-2.08 = -0.693(t/10.4)
t/10.4 = -2.08/-0.693
t = 10.4 * 3
t = 31.2 hours
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Can anyone solve? Thank you
Answer:
The rod is stretched because there is a larger gravitational force on the mass closest to mass M.
F = G M m / r^2 - G M m / (r + l)^2 the difference of the forces on m's
F = G M m [1 / r^2 - 1 / (r + l)^2]
[1 / r^2 - 1 / (r + l)^2] = (r^2 + 2 r l + l^2 - r^2 / [r^2 (r + l)^2]
= (2 r l + l^2) / [r^2 (r + l)^2]
if l is small compared to r = (2 r l ) / [r^2 (r + l)^2]
= (2 r l ) / [r^4 + 2 r^3 l ]
One mole of a substance contains 6.02 × 1023 protons and an equal number of electrons. If the protons could somehow be separated from the electrons and placed in very small, individual containers separated by a million meters, what would be the magnitude of the electrostatic force exerted by one box on the other?
Explanation:
it is almost zero .this is because the distance and the electrostatic force are inversely proportional
A 17.0-m-high and 11.0-m-long wall and its bracing under construction are shown in the figure. Calculate the force, in newtons, exerted by each of the 10 braces if a strong wind exerts a horizontal force of 655 N on each square meter of the wall. Assume that the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths. Neglect the thickness of the wall.
The force, in newtons, exerted by each of the 10 braces is 2.135 x 10⁴ N.
What is force?The force is defined as the shear stress or pressure applied per unit area.
F = P/A
Given is a 17.0-m-high and 11.0-m-long wall and its bracing under construction are shown in the figure(attached). The force is exerted by each of the 10 braces, if a strong wind exerts a horizontal force of 655 N on each square meter of the wall. Assume that the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths.
Considering the pivot at the base of wall.
From the equilibrium of forces, we have
r₁ x Fwind = r₁ x Fbsinθ
Put the values, we get
Fb = Fwind /10sin35°.............(1)
The wind force is also given by
Fwind = Horizontal force or pressure x Area
Fwind = F/A x hw
=655 x 17 x 11
F wind = 122,485 N
From equation (1), we have
Fb = Fwind /10sin35°
Fb = 122,485 /10sin35°
Fb = 21,354.6080 N
0r Fb = 2.135 x 10⁴ N
Thus, the force exerted on each of the 10 brace is 2.135 x 10⁴ N.
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Where are electrons located in an atom?
A. in the nucleus
B. outside the nucleus
C. Either inside or outside the nucleus?
Answer for brainlist
Answer:
B. Outside the nucleus.
Explanation:
Electrons orbit the nucleus of the atom.
A ball is projected with initial velocity 50m/s at an angle of elevation of 37 degrees from the top of a cliff 55 m high. Calculate the total time the ball is in the air and the maximum horizontal distance covered.
The total time the ball is in the air is 1.47 s and the maximum horizontal distance covered is 58.7 m.
Time of motion of the ball
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
55 = (50sin37)t + ¹/₂(9.8)t²
55 = 30.1t + 4.9t²
4.9t² + 30.1t - 55 = 0
Solve using formula method;
t = 1.47 s
Horizontal distance of the ballX = vxt
where;
vx is the horizontal velocityt is time of motionX = (50 x cos37) x 1.47
X = 58.7 m
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What is the energy of a photon of blue light with a frequency of 6.53 × 10¹4 Hz?
Answer:
V = 6.53 × 10^14
h = 6.626 × 10^-34
E = hV
E = (6.626 × 10^-34) (6.53 × 10^14)
E = 4.33 × 10^-19
If the velocity of an object doubles and it’s mass triples, the objects momentum increases by how much? A)1.5 times B)2 times C)3 times D)6 times
Answer:
(D)6 times
Explanation:
Hello !
Because when we see the equation of momentum P=mv, where p=momentum
m=mass of the object&
v=velocity of the object
And, p is directly propositional to both mass and velocity.
Thus, p=mv
p=3m.2v....giving on the valuesp=6(mv)Therefore, we can conclude by when the mass is tripled and the velocity is doubled the momentum is increased by 6 units.
n Step 5, you will calculate H+/OH– ratios for more extreme pH solutions. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 2. Then divide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C.
What is the concentration of H+ ions at a pH = 2?
mol/L
What is the concentration of OH– ions at a pH = 2?
mol/L
What is the ratio of H+ ions to OH– ions at a pH = 2?
: 1
At pH = 2 the ratio of the concentration of the hydrogen to the hydroxide ion is 10¹⁰. The hydrogen ion concentration at pH, 2 is 10⁻² and the hydroxide ion is 10⁻¹².
What is pH?The parameter of measuring the concentration of the hydroxide and the hydrogen ion in the solution in order to determine the basic and the acidic nature is known as pH.
The concentration of H⁺ ions is calculated as:
pH = -log [H⁺]
2 = -log [H⁺]
[H⁺] = 10⁻²
The concentration of OH⁻ ions is calculated as:
pH + pOH = 14
pOH = 14 - 2
pOH = 12
Solving further:
pOH = -log [OH⁻]
12 =-log [OH⁻]
[OH⁻] = 10⁻¹²
At a pH = 2, the ratio of hydrogen ions to hydroxide ions:
10⁻² ÷ 10⁻¹² = 10¹⁰
Therefore, at pH = 2 the ratio is 10¹⁰.
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An object is released from an aeroplane which is diving at an angle of 30° from the horizontal with a speed of 50m/s. If the plane is at a height of
4000m from the ground when the object is released, find
(a) the velocity of the object when it hits the ground.
(b) the time taken for the object to reach the ground.
please I need the solution urgently.
a)The velocity of the object when it hits the ground will be 1.12 × 10⁵ m/sec
b) The time taken for the object to reach the ground will be 11.4 × 10³ sec.
What is projectile motion?The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The velocity in the x-direction;
[tex]\rm v_x = (vcos \theta)^2 +2gh \\\\ v_x = (50 cos 30)^2+ 2 \times 9.81 \times 4000 \\\\ v_x = 80355 m/sec[/tex]
Velocity in y-direction;
[tex]\rm v_ y = (vsin \theta)^2 + 2gh \\\\ v_ y = (25)^2+2 \times 9.81 \times 4000 \\\\ v_y =79105 \ m/sec[/tex]
The resultant velocity is found as 1.12 × 10⁵ m/sec.
The time taken to reach the ground is found as;
[tex]\rm v = u+gt \\\\ 1.12 \times 10^5 \ m/sec = 50 \ m/sec + 9.81 \times t \\\\ t = 11.4 \times 10^3 \ sec[/tex]
Hence, the velocity of the object when it hits the ground will be 1.12 × 10⁵ m/sec, and the time taken for the object to reach the ground will be 11.4 × 10³ sec.
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In a small village in southern Italy, childbirth is considered?
Answer:
a community event
Explanation:
Jon and Jim push a dead car forward to the gas station. Jon pushes with 90N while Jim pushes 80 N.
The resultant of the two forces is about 170 N.
What is the resultant force?The term resultant force has to do with the single force that has the same magnitude and direction as two or more forces acting together.
In this case, the both forces are acting in the forward direction. This implies that the resultant force is 90 N + 80 N = 170 N.
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For which length of wire are the reading of resistance most precise
Answer:
Explanation:
There are different ways to investigate the factors that affect resistance. In this practical activity, it is important to:record the length of the wire accuratelymeasure and observe the potential difference and currentuse appropriate apparatus and methods to measure current and potential difference to work out the resistance
Can i use a 1000mAh battery instead of 600mAh Battery?
please tell me quickly
To deliver more power or voltage in the circuit use a battery with more current rating which is 1000 mAh.
Power generated in a circuitThe power generated in a circuit is directly proportional to the current flowing in the circuit.
P = IV
where;
I is currentV is voltageVoltage in the circuit also increases with increase in the current flowing in the circuit.
Thus, to deliver more power or voltage in the circuit use a battery with more current rating which is 1000 mAh.
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How to put a new command in the command prompt
Typing in the commands and instructions and pressing enter will put a new command in the command prompt.
What is a Command?This refers to a words or phrase which causes the computer to execute certain tasks or functions.
Typing the exact instruction and entering it will ensure that the chosen tasks are found in the command prompt.
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A trolley is moving at constant speed in a friction compensated track. Some plasticine is dropped on the trolley and sticks on it. State with a reason what is observed about the motion of the trolley.
Answer:
Since the momentum of the body remains constant ( conserved) the trolley slows down (its velocity reduces) since its mass increases.
_____ is a force which is applied to an object by another object or a person. __________ is a force that always opposes the motion of an object and is frequently ignored. a. Tensional force, friction c. Applied force, air resistance b. Friction, applied force d. None of the above. Please select the best answer from the choices provided A B C D
Answer:
Fritional force
Explanation:
Fritional force is a force that always opposes the motion of an object and is frequently ignored
C
Explanation:
Applied force, air resistance
An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin to carry it is 5.0 newtons. If he covers a distance of 10 meters, what work has he done on the javelin?
Answer:
50J
Explanation:
Work done=Fd
=5×10
=50J
A small mass of m = 187 g hangs from a string of length l = 1.21 m.
Calculate the initial speed v the mass m should be given at the bottom, so that the string reaches a maximum angle of θ = 36.5°?
The initial speed v, the mass m should be given at the bottom, so that the string reaches a maximum angle is 2.16 m/s.
What is mechanical energy?The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
Given is a small mass of m = 187 g hangs from a string of length l = 1.21 m. The string reaches a maximum angle of θ = 36.5. The acceleration due to gravity, g = 9.8 m/s²
The vertical height of the point mass h = l- lcosθ
h = 1.21 - (1.21cos 36.5°)
h = 0.2373 m
The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.
Kinetic energy = Potential energy
1/2 mv²= mgh
Substituting the values, we have
1/2 x v² = 9.8 x 0.2373
v = sqrt [2 x9.8 x 0.2373]
v= 2.16 m/s
Thus, the initial speed v the mass m should be given at the bottom, so that the string reaches a maximum angle is 2.16 m/s.
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