The final temperature of the bath water is 25.77 C.
What is temperature?Temperature is a measure of the average kinetic energy of the particles in a substance. It is measured in degrees on the Celsius, Fahrenheit and Kelvin scales. Temperature is an important physical quantity that is used to describe a wide range of phenomena in science, engineering and everyday life. Temperature influences everything from the rate of chemical reactions to the growth of living organisms. Hotter objects have higher temperatures than cooler objects and when two objects of different temperatures come into contact, heat will flow from the hotter to the colder object until both reach the same temperature. This process of heat transfer is known as thermal equilibrium.
The final temperature of the bath water can be calculated using the equation:
Tfinal = (mass1*T1 + mass2*T2) / (mass1 + mass2)
where T is the temperature, mass is the mass of water.
In this case, the mass1 is 5.0 L of water (5.0 kg) at 95 C, and the mass2 is 60 L of water (60 kg) at 20 C. So the equation becomes:
Tfinal = (5.0 kg*95 C + 60 kg*20 C) / (5.0 kg + 60 kg)
Tfinal = (475 kg*C + 1200 kg*C) / (65 kg)
Tfinal = (1675 kg*C) / (65 kg)
Tfinal = 25.77 C
Therefore, the final temperature of the bath water is 25.77 C.
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Jeff's car weighs 2000 lbs and is moving east at 20 km/hour. Jordan's car is twice as heavy, and is moving east at 10 km/hour. Whose car has more momentum?
Jordan's car has more momentum because it weighs more.
Jeff's car has more momentum because it is going faster.
Jordan's car has more momentum because it's going slower
Jeff's car has more momentum because it weighs less
Neither. Both cars have the same momentum.
Jordan's car has more momentum because it weighs more.
Jordan's car accelerates faster due to its weight. Momentum is the result of a particle's mass and velocity. As a vector quantity, momentum has both magnitude and direction. Newton's second law, which may be expressed in its most general form as F = d p/dt, asserts that the force acting on a particle controls the rate of change of its momentum, p.
The second equation of motion of Isaac Newton states that the force applied to a particle is equal to the time rate of change of momentum. Since momentum depends on both the speed and the direction of the body's motion, it is expressed as "mass velocity." Since mass is a scalar and velocity is a vector, momentum is a vector quantity.
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a cheetah can maintain a constant acceleration of 10.0 m/s2 for a time interval of 1.30 seconds. if the cheetah starts from rest, how long will it take the cheetah to move at 25.0 mph?
it will take the cheetah 1.118 seconds to move at 25.0 mph.
What is kinematic equation?Kinematic equations are mathematical equations used in physics to describe the motion of objects. These equations are used to solve problems involving velocity, acceleration, and displacement. The equations rely on the use of Newton's laws of motion, which state that the acceleration of an object is equal to the sum of all the forces acting upon it, divided by its mass.
First let's convert 25.0 mph to m/s:
25 mph = 11.176 m/s
Now we can use the kinematic equation for uniform acceleration:
vf = vi + at
where vf is the final velocity, vi is the initial velocity (which is 0 m/s since the cheetah is starting from rest), a is acceleration (10.0 m/s2), and t is the time interval.
11.176 = 0 + (10.0)(t)
t = 1.118 seconds
Therefore, it will take the cheetah 1.118 seconds to move at 25.0 mph.
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A 10cm×10cm×10cm wood block with a density of 750 kg/m3 floats in water. What is the distance from the top of the block to the water if the water is fresh?If it's seawater? Suppose that rho=1030kg/m3.Express your answer to two significant figures and include the appropriate units.
In fresh water the block will float at Height of 2.5cm above water.
In salt water the block will float at Height of 2.72cm above water.
Density is defined as the mass per unit volume. It is an intensive property, which is mathematically defined as mass divided by volume:
ρ = m/V
In words, the density (ρ) of a substance is the total mass (m) of that substance divided by the total volume (V) occupied by that substance. The standard SI unit is kilograms per cubic meter (kg/m3). The Standard English unit is pounds mass per cubic foot (lbm/ft3). The density (ρ) of a substance is the reciprocal of its specific volume (ν).
ρ = m/V = 1/ρ
In fresh water (density of Ig/cc.), the block will float with [tex]$10-(10 \times 0.75)=2.5 \mathrm{~cm}$[/tex]. above water.
The salt water one is tougher.
Block density is [tex]$750 \frac{kg}{m^3}$[/tex], which equates to [tex]$0.75 \mathrm{~g} / \mathrm{cc}$[/tex].
Block volume [tex]$=\left(10^3\right)=1,000$[/tex]
Its mass is. [tex]$(1,000 \times 0.75)=750$[/tex] grams
It will displace its own mass of water when it floats.
The volume of water displaced. [tex]$=(750 / 1.030)=728.16 \mathrm{cc}$[/tex]
The block area [tex]$=(10 \times 10)=100 \mathrm{~cm}^2$[/tex].
Height out of water [tex]$=10 \mathrm{~cm}-(728.16 / 100)=2.72 \mathrm{~cm}$[/tex]
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how much should a spring of indefinite length be compressed to have a potential energy equivalent to a ball of mass 6 kg raised to a height of 120 m above the ground?
According to the question, 12 m should a spring of indefinite length be compressed to have a potential energy equivalent to a ball of mass 6 kg raised to a height of 120 m above the ground.
How is potential energy defined?Potential energy is the energy of energy stored that depends on how various system elements interact with one another.
Potential Energy of ball = m x g x h
m= 6 kg
g= 10 m/s^2
h= 120 m
PE = 7200 J
Potential Energy of spring = 1/2 x k x d^2
k = 100 N/m
as we know that
Potential Energy of spring = Potential Energy of ball
1/2 x k x d^2 = m x g x h
d = 12 m
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suppose two boxes on a frictionless table are connected by a heavy cord of mass 1.00 kg. box a has a mass of 9.00 kg and box b has a mass of 14.0 kg. what is the acceleration of the boxes if a horizontal force of 39.0 n is applied?
The acceleration of the boxes are 1.625 m/s^2.
What is acceleration?
Acceleration is a measure of how much an object's velocity changes over time. Velocity is a vector quantity that includes both speed and direction, so acceleration can refer to changes in speed, direction, or both. Acceleration is typically measured in meters per second squared (m/s^2) or feet per second squared (ft/s^2). Positive acceleration indicates an increase in speed, while negative acceleration indicates a decrease in speed.
To find the acceleration of the boxes, we can use the formula:
force = mass x acceleration.
In this case, we know the force applied (39.0 N) and the mass of the boxes (9.00 kg + 14.0 kg + 1.00 kg = 24.00 kg).
So we can calculate the acceleration as:
force = mass x acceleration
39.0 N = 24.00 kg x acceleration
acceleration = force / mass
acceleration = 39.0 N / 24.00 kg
acceleration = 1.625 m/s^2
Therefore, the acceleration is 1.625 m/s^2.
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An object is acted upon by two forces 3N and 5N inclined at 60 degree to each other. if the object is moved through a distance of 6m by the resultant force, the workdone is
Answer:
48 J
Explanation:
Work Done = Force X Distance moved in a stated direction
Work Done = 3N + 5N X 6m
Work Done = 48 J
Two forces 3N and 5N acting on an object are inclined at 60 degrees to each other. If the resultant force moves the object a distance of 6m, the work done is 35.92 Joules (J).
In physics, work is defined as the transfer of energy that occurs when a force is applied to an object and the object is displaced in the direction of the force. Mathematically, work done is the product of the force applied and the distance moved in the direction of the force.
Work is a scalar quantity and is measured in joules (J) in the International System of Units (SI). When a force is applied to an object and there is no displacement, no work is done. Similarly, if there is displacement but no force acting on the object, no work is done.
Here in the Question,
To find the work done, we need to first find the resultant force.
Using vector addition, we can find the magnitude and direction of the resultant force:
cos(60) = adjacent/hypotenuse
adjacent = cos(60) x 5N = 2.5N
sin(60) = opposite/hypotenuse
opposite = sin(60) x 5N = 4.33N
The horizontal component of the 3N force is 3N cos(60) = 1.5N
The vertical component of the 3N force is 3N sin(60) = 2.6N
The horizontal component of the 5N force is 5N cos(30) = 4.33N
The vertical component of the 5N force is 5N sin(30) = 2.5N
The horizontal component of the resultant force is 4.33N + 1.5N = 5.83N
The vertical component of the resultant force is 2.5N + 2.6N = 5.1N
The magnitude of the resultant force is given by the Pythagorean theorem:
Resultant force = sqrt(5.83^2 + 5.1^2) = 7.59N
The direction of the resultant force is given by:
tan(theta) = opposite/adjacent
theta = tan^-1(5.1/5.83) = 43.1 degrees
The work done is given by:
work = force x distance x cos(theta)
work = 7.59N x 6m x cos(43.1) = 35.92 Joules (J)
Therefore, the work done is 35.92 Joules (J).
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a ladybug is moving at a speed of one centimeter per second. she begins to decelerate at a
rate of -0.25 centimeters per second squared until she comes to rest. how much distance does
the ladybug cover from the moment she begins to decelerate until the moment she comes to
rest?
Ladybug covers distance from the moment she begins to decelerate until she comes to the rest. The deceleration is 0.25m/ s2.
What is Work energy theoram?The net work done on a body is equal to change in kinetic energy of the body. This is called as Work-energy theorem.
Numerically. To find the distance, which Ladybug cover from the moment she begins to decelerate until she comes to the rest, use the formula.
Where, is final velocity, is initial velocity, is acceleration and is displacement. After moving, ladybug comes to the rest, so final velocity, Placing the value of the given initial velocity, , acceleration.
Therefore, Ladybug covers distance from the moment she begins to decelerate until she comes to the rest.
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A lady is on a lab chair. The chair can freely spin on its axis (no friction). The lady was given an initial spin. While she is spinning freely, she extends her arms out O her moment of inertia increases and her angular speed decreases her moment of inertia increases and her angular speed increases. O her moment of inertia decreases and her angular speed increases O her moment of inertia increases and her angular speed remains the same. O her moment of inertia decreases and her angular speed decreases.
The correct answer is Option 3: her moment of inertia increases and her angular speed increases. When the lady extends her arms out, her moment of inertia increases because she is now further away from the axis of rotation and the mass of her arms is now contributing to her moment of inertia. Since her moment of inertia increases, her angular speed must also increase in order to conserve angular momentum.
you rub a balloon on your head, and the balloon gains a charge of 85 nc . how many electrons were transferred during this process?
According to the given question ,-53x10^10 electrons were transferred during this process
What are three electron-related statistics?The negatively charged particles called as electrons revolve about the outside of the nucleus. For scientists, it might be hard to monitor them due to the way quickly they spin. The tiniest atoms in an atom, you can put 2000 of them in a proton, they are drawn to the positive ions of the protons.
Charge that the balloon has collected, q = 85 nC
e determines an electron's charge.
e = -1.6x10^-19 C
The amount of total value to the charge of one particle yields the number of electrons.
Suppose there are n electrons.
e = 85x10^-9/-1.6x10^-19
= -53x10^10
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A 200 ohm resistor is connected to an AC source with peak emf = 10V. What is the peak current through the resistor if the emf frequency is a) 100 Hz b) 100 kHz?
The peak current through 200 ohm resistor for both the cases 50mA.
The number of turns times the size of the coil times the magnetic field's intensity times the angular speed equals peak emf.
The largest amount of current that an output is capable of providing for brief periods of time is known as the peak current. When an electrical device or power source is turned on for the first time, a large initial current known as the peak current flows into the load, starting at zero and increasing until it reaches a peak value.
Formula for the peak current is
peak current=[tex]\frac{peak voltage}{resistance}[/tex]
As in the formula it does not matter whether frequency changes or not.
So, peak current in both cases will be
peak current=[tex]\frac{10}{200}[/tex]
peak current=50mA
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a 435n box is sliding down a 40.0 inclined plane. if the acceleration of the box is 0.250 m/s^2 what is the force of friction acting on the bix
W=mg=435NW=mg=435N is the weight of the box. If the box accelerates by 0.250 m/s2, the plane is inclined. much friction is there on the bix
What do you call friction?The force of friction is influenced by outside forces. The two elements that friction depends on are as follows: 1. Regarding the makeup of the contact objects in touch. The two sides that are in touch with one other's depend on each other for friction.
What makes friction popular?In mathematics, the portion or component of the complete item is represented by a fraction.
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Question 10
6.25 pts
A cannon is fired horizontally at 337 m/s off of a 80 meter tall, sheer vertical cliff. How many
seconds
will have elapsed before the cannonball strikes the ground?
Answer: 4 seconds are elapsed before the cannonball strikes the ground.
Explanation:
Height of tower (h) = 80m
Initital velocity in x-dir ([tex]u_{x}[/tex]) = 337m/s
Initial velocity in y-dir ([tex]u_{y}[/tex]) = 0m/s
Time of flight (T)
Gravitational acceleration (g) = 10 m/s
Using second equation of motion,
h = [tex]u_{y}[/tex] + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
80 = [tex]\frac{1}{2}[/tex]×10×[tex]T^{2}[/tex]
[tex]T^{2}[/tex] = 16
T = 4s
For the next experiment we will be using an ultrasonic sensor. This works by emitting a sound wave from a speaker and bouncing it off an object. The delay between the sending and retrieval of this sound wave allows us to determine the distance to the object. Assuming a speed of sound of 343 m/s, answer the questions below and show your work: o How far in centimeters does a sound wave travel in 3000 microseconds? o How long in microseconds does it take a sound wave to travel 30 cm?o Truncate your answer to the first decimal place. How long in microseconds does it take for a sound wave generated to bounce and get back from an object 50 cm away?
A) To find the distance a sound wave travels in a certain time, we can use the formula:
distance = speed x time
Given that the speed of sound is 343 m/s and the time is 3000 microseconds, we can calculate the distance as:
distance = 343 m/s x (3000 x 10^-6 s) = 1.029 m
converting this to cm we get:
distance = 1.029 m x 100 cm/m = 102.9 cm
B) To find the time it takes for a sound wave to travel a certain distance, we can use the formula:
time = distance/speed
Given that the distance is 30 cm and the speed of sound is 343 m/s, we can calculate the time as:
time = 30 cm / 343 m/s = 0.00087 s
converting this to microseconds we get:
time = 0.00087 s * 10^6 microseconds/s = 87 microseconds
C) The time it takes for the sound wave to travel to the object and back is twice the time it takes for the sound wave to travel to the object alone. Given that the distance is 50 cm and the speed of sound is 343 m/s, we can calculate the time as:
time = 2 * (50 cm / 343 m/s) = 2 * 0.000146 s = 0.000292 s
converting this to microseconds we get:
time = 0.000292 s * 10^6 microseconds/s = 292 microseconds
So it takes 292 microseconds for a sound wave generated to bounce and gets back from an object 50 cm away.
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rock layer that can be porous but must have very low to no permeability
Rock layer that can be porous but must have very low to no permeability is option A. above oil and natural gas
What is soil permeability?Soil permeability is a measure of a soil's ability to allow water to flow through it. It is determined by the size, shape, and arrangement of the soil particles, as well as by the presence of pores or fractures in the soil.
Soils with high permeability allow water to flow through them quickly, while soils with low permeability do not allow water to flow through as easily. Permeability is important for both agricultural and engineering applications, as it can affect water availability for plants, and the stability of foundations for buildings and other structures.
Therefore, the correct answer is as given above
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The complete question goes thus:
Rock layer that can be porous but must have very low to no permeability.
A. above oil and natural gas
B. Under oil and natural gas
C. Coal, oil, natural gas
D. anthracite
assuming that the acceleration does not change, through what additional angle will the disk turn during the next 7.0 s?
The disk will rotate through an additional angle of 52.5 rad during the next 7 seconds.
What is angular acceleration?Angular acceleration is scaled in units of angle per unit time squared (which in SI units is radians per second squared) and is ordinarily characterized by the symbol alpha( α). It is a pseudovector quantity.
To find the additional angle the disk will turn during the next 7 seconds, we can use the equation for angular displacement: Δθ = α × t² / 2 + ωi × t Where: α = angular acceleration (constant), t = time ,ωi = initial angular velocity (which is 0, since the disk is starting from rest)
We know the angular acceleration and time, so we can plug in the values to get: Δθ = α × (7.0s) ² / 2 + 0 × 7.0s
We don't know the angular acceleration, but we know the final angular displacement, which is 30 rad and the time taken which is 4s, so we can use the equation Δθ = α × t²/2 + ωit 30 = α × 4² / 2 + 04
Solving for α, we get: α = 30/8 rad/s²
Now we can use this value of angular acceleration to find the additional angle the disk will turn during the next 7 seconds: Δθ = α × (7.0s) ² / 2 + 0 × 7.0s
Δθ = (30/8) × (7.0s) ² / 2 + 0 × 7.0s
Δθ = (30/8) × 49/2
Δθ = 52.5 rad
So, the disk will rotate through an additional angle of 52.5 rad during the next 7 seconds.
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The complete answer is as follows:
The work done in accelerating an object along a frictionless horizontal surface is equal to the change in the object's
(A) momentum
(B) velocity
(C) potential energy
(D) kinetic energy
"The work done in accelerating an object along a frictionless horizontal surface is equal to the change in the object's kinetic energy."
The amount of internal and mechanical energy that objects possess fluctuates as a result of work. When work is done on a system or an object, energy is contributed to it. When a system or item accomplishes work, some of its energy is transferred to something else.
Work involves the transfer of energy from the agent to the object, which modifies the object's motion.
The energy of motion is known as kinetic energy, and it can be observed in the motion of objects or subatomic particles. Kinetic energy can be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.
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a certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 36.0 m/s. with what maximum speed can it go around a curve having a radius of 78.0 m?
Maximum speed can it go around a curve having a radius of 78.0 m
The speed of an object, also known as v in kinematics, is a scalar quantity that depends on how much its position changes over time or how much it changes per unit of time. Velocity and speed are the two distinct concepts.
The International System of Units (SI) uses the metre per second as the unit of both speed (a scalar quantity) and velocity (a vector quantity with direction and magnitude), with one metre per second being the speed of a body traveling one meter in one second.
The truck receives the necessary centripetal acceleration from friction between the tires and the flat road in order to safely and skid-free navigate the bend.
[tex]a_{c,max} =\frac{v^{2}_{max} }{r} \rightarrow( 1)[/tex]
inserting the given values we get
[tex]a_{c,max} =\frac{(36)^{2}_{} }{150}[/tex]
[tex]a_{c,max} =[/tex]8.64m[tex]s^{-2}[/tex]
For a changed in the radius of curve of 78.0m , the maximum speed can it go
[tex]v_{new,max} =\sqrt(a_{c,max} \times R_{new} )[/tex]
[tex]v_{new,max} =\sqrt(8.64\times 78 )[/tex]
[tex]v_{new,max} =\\[/tex]25.95m/s
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what temperature in celsius would be equal to 100 degrees fahrenheit?
A temperature of 100 degrees Fahrenheit is equivalent to 37.78 degrees Celsius.
The conversion formula between Fahrenheit and Celsius is as follows:
°C = (°F - 32) x (5÷9)
So, to convert 100 degrees Fahrenheit to degrees Celsius, we can plug in 100 for °F and solve for °C:
°C = (100 - 32) x (5÷9) = 68 x (5÷9) = 37.78
It is important to note that the degree unit size (Fahrenheit and Celsius) is not the same, and thus the numerical value of the temperature measured in those scales does not match one to one. The freezing point of water is 32 degrees Fahrenheit (0 degrees Celsius) and the boiling point is 212 degrees Fahrenheit (100 degrees Celsius). This means that 100 degrees Fahrenheit is considered a "hot" temperature, but 37.78 degrees Celsius is considered a "normal" room temperature.
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An earth satellite moves in a circular orbit at a speed of 4000 m/s. What is its orbital period?
An earth satellite moves in a circular orbit at a speed of 4000 m/s, its orbital period is 648.84 hours.
What is Newton's gravitational law?Every particle in the universe is said to attract every other particle with a force along a line connecting them, according to Newton's universal law of gravitation. The force is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
F= G[tex]\frac{m1m2}{R^{2} }[/tex]
where F is Gravitational Force, G is Gravitational Constant (6.67×[tex]10^{-11}[/tex]Nm²/kg²), m is mass of the object and R is the distance between objects(m).
Given:
speed of the satellite is v=4000m/s.
mass of the earth=M=6×[tex]10^{24}[/tex] kg.
∑F=ma
G[tex]\frac{Mm}{R^{2} }[/tex]=m[tex]\frac{v^{2} }{R}[/tex]
G[tex]\frac{M}{R^{2} }[/tex] = [tex]\frac{v^{2} }{R}[/tex]
G[tex]\frac{M}{R\\}[/tex] = [tex]v^{2}[/tex]
R=G[tex]\frac{M}{v^{2} }[/tex]
2πR= 2πG[tex]\frac{M}{v^{2} }[/tex]
2πR/v= (2πG[tex]\frac{M}{v^{2} }[/tex]) /v
T= 2πG[tex]\frac{M}{v^{3} }[/tex]
T= 2π×6.67×[tex]10^{-11}[/tex]×[tex]\frac{6*10^{24} }{4000}[/tex]
T= 648.48 hours.
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based on current evidence, which of the following statements about gamma ray bursts is true?
All of those that we have found took place in far-off galaxies. is accurate when it comes to gamma ray bursts.
How do gamma rays work?A redistribution of electric charge within a nucleus produces gamma rays, a kind of electromagnetic radiation. The difference between gamma rays and X rays is not based on their basic characteristics, but rather on their origins.
Where can one find gamma rays?The universe's hottest and most energetic objects, including as neutron stars and pulsars, supernova explosions, and regions near black holes, all produce them. Nuclear explosions, lightning, and the less dramatic process of radioactive decay all produce gamma radiation here on Earth.
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You have a u haul truck, explain why you would use the Ramp on the truck…
if it didn't have a ramp it would be harder to load the truck.
help please as fast as you can
The height of the cliff is 43.6 m.
What is the height of the cliff?
The height of the cliff is calculated by applying the following kinematic equation as shown below.
h = vt + ¹/₂gt²
where;
v is the initial velocity of the rockt is the time of motiong is acceleration due to gravityThe height of the cliff is calculated as follows;
h = ( 12 m/s x 2 s ) + ¹/₂ ( 9.8 m/s² ) x ( 2.0 s )²
h = 43.6 m
Thus, the height of the cliff is a function of the initial velocity, time of motion and acceleration due to gravity.
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when a falling meteoroid is at a distance above the earth's surface of 3.30 times the earth's radius, what is its acceleration due to the earth's gravitation?
Answer:
Approximately [tex]0.515\; {\rm m\cdot s^{-2}}[/tex] (assuming that all other forces are negligible).
Explanation:
Look up the following quantities:
Gravitational constant: [tex]G \approx 6.6743 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}}[/tex].Mass of the Earth: [tex]M \approx 5.792 \times 10^{24}\; {\rm kg}[/tex].Radius of the Earth: [tex]R \approx 6.371 \times 10^{6}\; {\rm m}[/tex].At a distance of [tex]r[/tex] from the center of the Earth, the magnitude of the gravitational field strength of the Earth would be:
[tex]\begin{aligned} g &= \frac{G\, M}{r^{2}}\end{aligned}[/tex].
In this question, the asteroid is at [tex]3.30\, R[/tex] above the surface of the Earth. The actual distance between the asteroid and the center of the Earth would be [tex]r = (3.30 + 1)\, R[/tex].
Thus, at the current position of this asteroid, the magnitude of the gravitational field of the Earth would be:
[tex]\begin{aligned} g &= \frac{G\, M}{r^{2}} \\ &= \frac{G\, M}{((3.30 + 1)\, R)^{2}} \\ &\approx \frac{(6.6743 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}})\, (5.792 \times 10^{24}\; {\rm kg})}{((3.30 + 1)\, (6.371 \times 10^{6}\; {\rm m}))^{2}} \\ &\approx 0.515\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
Assume that the gravitational attraction from the Earth is the only force on this asteroid. Acceleration of the asteroid would be equal to the gravitational field strength: approximately [tex]0.515\; {\rm m\cdot s^{-2}}[/tex].
to achieve this vertical leap, with what force did the impala push down on the ground?
The force that the push impala push down on ground is 1941 N and the ratio of this force to the antelope's weight is 4.4.
a)The force that did the impala push down on the ground will be 1941 N.
The acceleration= 7-0/0.21
a= 33.33m/sec^2
The value of force can be calculated by
F= m (a + g)
F= 45( 33.33+9.81)
F= 1941 N
Hence the force that did the impala push down on the ground will be 1941 N.
(b)The ratio of this force to the antelope's weight will be 4.4.
The weight of the antelope=
W= mg
W=45×9.81
Therefore, W=441 N
The ratio of this force to the antelope's weight can be calculated by
F/W=1941/441
F/W= 4.4
Therefore, the ratio of force to the antelope's weight will be 4.4.
What is force?
Force is defined as the product the of mass and acceleration.
Unit of the force= Newton
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An impala is an African antelope capable of a remarkable vertical leap. In one recorded leap, a 45 kg impala went into a deep crouch, pushed straight up for 0.21 s, and reached a height of 2.5 m above the ground. To achieve this vertical leap, with what force did the impala push down on the ground? What is the ratio of this force to the antelope's weight?
The tracking device sends data to a computer during the game. one advantage of the data being sent during the game.
The tracking device sends data to a computer during the game and one advantage of the data being sent during the game is to ensure that adequate statistics and summary of the game is available.
What is a Program?This is referred to as a set of instructions that a computer needs to carry out its tasks is known as a program while data on the other hand is a set of raw facts and figures.
The tracking device sends data to a computer during the game which makes the statistics and summary available for the game accurate and adequate.
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When providing transcutaneous pacing, the appearance of wide QRS complexes and tall, broad T waves after each pacing spike confirms that mechanical capture has been achieved.TrueFalse
The sentence is true. When providing transcutaneous pacing, the appearance of wide QRS complexes and tall, broad T waves after each pacing spike confirms that mechanical capture has been achieved.
Transcutaneous pacing is a method of providing cardiac pacing by delivering electrical impulses through the skin to the heart. When mechanical capture is achieved, it means that the electrical impulse is strong enough to cause the heart muscle to contract.
This is confirmed by the appearance of wide QRS complexes and tall, broad T waves on an electrocardiogram (ECG) after each pacing spike. The QRS complex represents ventricular depolarization, and the T wave represents ventricular repolarization.
Wider QRS complex and taller T waves indicate that the electrical impulse is strong enough to depolarize the entire ventricular muscle, resulting in a stronger mechanical contraction.
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in a pairs figure skating competition, a 65 kg man and his 45 kg female partner stand facing each other on skates on the ice. if they push apart and the woman has a velocity of 1.5 m/s eastward, what is the velocity of her partner? (neglect friction.)
Her partner's final velocity is roughly -1.04 m/s, or 1.04 m/s in the opposite direction from her motion.
How do velocity and speed differ?
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
What is velocity, for instance?
Velocity can be defined as the rate at which something moves in a specific direction. as the speed of a car driving north on a highway or the pace at which a rocket takes off.
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What is the wavelength, in nm, of a photon with an energy of 30 eV? Is this wavelength visible, ultraviolet, or infrared light?
The provided statement states that a photon including a potential of 30 eV has a wavelength of 41.36 nm and is an ultraviolet photon.
What is the SI unit and wavelength?The SI unit representing wavelength is the metre, which is frequently abbreviated as m. Time is also measured in different amounts or percentages of meters. Notably, proportional ratios of 10 are used when wavelengths constitute a key component. A negative exponential is used to describe shorter wavelengths. Here are some examples of wavelengths: Yellow Sunshine is a good illustration. All light source has a frequency spectrum between 400 and 700 nanometers (nm). Yellow light has a wavelength of around 570 nanometers.
[tex]$\lambda=\frac{\left(6.626 * 10^{-34}\right)\left(3 * 10^8\right)}{(30) *\left(1.602 * 10^{-19}\right)}$[/tex]
λ = 4.136 * 10⁻⁸ m
λ = 41.36 x 10⁻⁹ m
λ = 41.36 nm → ultraviolet
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High-speed stroboscopic photographs show the head of a 220g golf club is traveling at 49.9 m/s just before it struck a a 45.8g gold ball at rest on a tee. After the collision, the club head travels (in the same direction) at 33.9 m/s. Find the speed of the golf ball immediately after impact.
Please show your work and use this formula: m1v1+m2v2=m1v1f+m2v2f
Answer:
76.9 m/s
Explanation:
You want the speed of a 45.8 g golf ball after it has been hit by a 220 g club traveling 49.9 m/s, if the club is traveling 33.9 m/s in the same direction after the collision.
MomentumThe conservation of momentum requires ...
m1·v1 +m2·v2 = m1·v1f +m2·v2f
Rearranging this equation, we get ...
m1·(v1 -v1f) = m2·(v2f -v2)
When v2 = 0, we can solve for v2f:
m1(v1 -v1f)/m2 = v2f . . . . . . . divide by m2
ApplicationIn the given scenario, we have ...
m1 = 220 gm2 = 45.8 gv1 = 49.9 m/sv1f = 33.9 m/sThe speed of the driven golf ball will be ...
v2f = (220)(49.9 -33.9)/45.8 ≈ 76.9 . . . m/s
The speed of the golf ball after impact will be 76.9 m/s.
What is the exact circumference of a circle with a radius of 17 mm? responses 8.5π mm 8.5 pi, mm 17π mm 17 pi, mm 34π mm 34 pi, mm 68π mm
The circumference of a circle of radius 17 mm is 34π or 34 × 3.14 = 106.76 mm.
What is the circumference?The length of a circular or other curved geometrical object is referred to as its circumference. It is the edge of a surface like this with two dimensions, calculated linear in one dimension. A circle's circumference, which is equivalent to the length of it's own edge measured in linear distance, serves as a measure of length. In order to measure the circumference of a circle in the metric system, a most common units are millimetre, centimeter, and meter, but in the imperial system, the most common units include inch, foot, and yard.
Given :
Radius of circle = 17mm
By using the formula of circumference -
circumference = 2 × π × r
circumference = 2 × π × 17
circumference = 34 π
or 34 × 3.14 = 106.76 mm
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