Function for MX the cost for X megabytes of data used in a month is -
m(x) = {0.149.8,ifr>2
{10,ifr≤2
What is a function?A function in mathematics from a set X to a set Y allocates precisely one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.
• Data exceeding 2 MB is charged at a rate of $0.10 per MB; one-time fee is $10;
The cost per month for x MB of data is:
1. Up to 2 Mb of data utilized; $10
2. Data use of over 2 MB
• m(x) = 10+ 0.1(x-2)= 10+ 0.1x 0.2 0.1x + 9.8 m(x) = 0.1x + 9.8
Thus, the function is:
m(x) = = {0.1x+9.8, if r>2
{ 10,ifr≤2
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58000Thousands= millions
Using the mathematical operation of multiplication, the value, 58000Thousands = 58 million.
What are mathematical operations?Mathematical operations are the ways mathematical expressions and values can be manipulated.
The basic mathematical operations include addition, subtraction, division, and multiplication.
Data and Calculations:58000Thousands converted into millions
= 58,000,000 (58,000 x 1000)
= 58 million
Thus, using the mathematical operation of multiplication, the value, 58000Thousands = 58 million.
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A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement, and its complement
The measure of the angle is 72°, its supplement is 108° and its compliment is 18° .
A pair of supplementary angles is defined as two angles which add up to 180°. They are also called linear pair.
A pair of angles which add up to 90° is called complimentary angles.
let us consider the given angle be x .
Compliment of given angle=90°- x
Supplement of the given angle=180°-x
The supplement is 6 times the compliment .
Therefore we can construct a linear equation of the form:
6(90°- x)=180°-x
or, 540°-6x=180-x
or, -6x+x=180-540
or, -5x=-360
or, x=72
Hence the angle is 72°
Compliment of 72°=90°-72°=18°
Supplement of 72°=180°-72°=108°
Therefore the required angle is 72°, its supplement is 108° and its compliment is 18° .
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your answer is 36. create an equation using the values a=0,b=1,c=2,d=3,e=4,f=5,g=6,h=7,k=8,l=9,m=10,n=11
Answer:
Here is your answer: 36 Now create an equation using the values below:A =0 B=1C=2D=3E=4F=5G=6H=7K=8L=9M=10N=11
example: If the answer is 12, there are several possible equations:
2D+G=12 , 2(3)+6=12
4C+H-D , 4(2)+ 7-3
D(2C) , 3(2 x 2)
Step-by-step explanation:
Answer:
l(k +g +f +d +c -h -b -a)(n -m)/e = 36
Step-by-step explanation:
You want to use the numbers 0 through 11 to create an equation that evaluates to 36.
ApproachWe will create an equation that simplifies to 4×9 = 36. This will make use of the identity properties of multiplication and addition, and will use the fact that 16/4 = 4.
Pieces9 = 9×1 = 9×(11 -10) = l(n-m)
0 = 8 -8 = (8 -7 -1 - 0) = k -h -b -a
16 = 8 +8 = 6 +5 +3 +2 = g +f +d +c
WholeThen the whole expression becomes ...
(16 +0)/4×9 = (g +f +d +c +k -h -b -a)/e×l(n -m) = 36
Help plsss••••••••••••••••••••
Answer:
Step-by-step explanation:
64 / 0.16 = 400 square cm
Which expression is equivalent to (5-².35) ²?
O
O
33
0-30
O
54
54
310
54
310
Answer:
О [tex]\frac{5^{4} }{3^{10} }[/tex]
Step-by-step explanation:
(5⁻² * 3⁵) ⁻²
= 1 / (5⁻² * 3⁵)²
= 1 / ((5⁻²ˣ²)(3⁵ˣ²))
= 1 / ((5⁻⁴)(3¹⁰))
= 5⁴ / 3¹⁰
The frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 12, 38, 50. The third column is labeled not looking for a job with entries 28, 72, 100. The fourth column is labeled total with entries 40, 110, 150. Which shows the conditional relative frequency table by column? A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.3, nearly equal to 0.33, 1.0. The third column is labeled not looking for job with entries 0.7, nearly equal to 0.65, 1.0. the fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column is blank with entries currently employed, not currently employed, total. The second column is labeled Looking for a job with entries 0.12, 0.38, 050. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.00. The fourth column is labeled total with entries 0.4, 1.1, 1.5. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 0.08, nearly equal to 0.25, nearly equal to 0.33. The third column is labeled not looking for a job with entries nearly equal to 0.19, 0.48, nearly equal to 0.67.
The relative frequency table is given at the end of the question.
What is a relative frequency?A relative frequency is given by the number of desired outcomes divided by the number of total outcomes.
For this problem, we have that out of 150 people, 40 and currently employed and 110 are not, hence the relative frequencies are given as follows:
Currently employed: 40/150 = 0.27.Not currently employed: 0.73.Of those 40 currently employed, 12 are looking for jobs and 28 are not, hence the relative frequencies are given as follows:
Looking for a job: 12/150 = 0.08.Not looking for a job: 28/150= 0.19.Of those 110 that are not currently employed, 38 are are looking for jobs and 72 are not, hence the relative frequencies are given as follows:
Looking for a job: 38/150 = 0.35.Not looking for a job: 72/150 = 0.48.Hence the frequency table is given at the end of the question.
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h(t)=\t+2\+3;find h(6)
For the given function, the value of h(t)=\t+2\+3 is for f(6) = 7
What is a function?A function is a means to explain what takes place with an input variable to produce an output result. We may find a set of output values if we consider a straightforward function, like multiply by three. Algebra can be used in place of Function = multiply by 3.
Before the t and after the 2, I'm going to presume that's an absolute value sign.
Absolute value brackets are treated similarly to parentheses, with the exception that the negative sign is removed once the contents have been thoroughly simplified. (If you still have variables, don't do that.)
In this instance, t equals 6 plus 2 equals 8. 8 has an absolute value of 8. Add 3 is 11.
so,
h(6) = 11.
What is H(-6) now?2 + -6 equals -4. 4 is -4's absolute value. Add 3 is 7.
so,
h(-6) is 7.
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Debra runs 4 miles in 30 minutes. At the same rate, how many miles would she run in 48 minutes?
========================================================
Work Shown:
(4 miles)/(30 minutes) = (x miles)/(48 minutes)
4/30 = x/48
4*48 = 30x
30x = 4*48
x = 4*48/30
x = 6.4
10C5 use the formula for nCr to evaluate given expression.
Answer:
The value of ¹⁰C₅ using [tex]\;^nC_r[/tex] formula is 252.Step-by-step explanation:
Given that
¹⁰C₅To find
The value of ¹⁰C₅ using [tex]\;^nC_r[/tex] formula.So according the question
We know that,
Combination, also known as [tex]\;^nC_r[/tex], is the process of choosing r objects from a group of n objects so that the order of the objects is irrelevant. The following is the formula to find combinations of r objects from n objects:
[tex]\;^nC_r = \frac{n!}{r!(n-r)!}[/tex] and from question.n = 10r = 5Now, put the value of n and r in [tex]\;^nC_r[/tex] formula.
So, we get
[tex]\;^nC_r = \frac{n!}{r!(n-r)!}[/tex]
[tex]\;^{10}C_5 = \frac{10!}{5!(10-5)!}[/tex]
∵ n! = n×(n-1)×(n-2)×........................×3×2×1∴ 5! = 5×4×3×2×1∴ 10! = 10×9×8×7×6×5![tex]= \frac{10\times9\times8\times7\times6\times5!}{5! \;\;5!}[/tex]
[tex]= \frac{10\times9\times8\times7\times6}{5\times4\times3\times2\times1}[/tex]
[tex]= {\times9\times2\times7\times2}[/tex]
[tex]= {252}[/tex]
Answer:
The value of ¹⁰C₅ using [tex]\;^nC_r[/tex] formula is 252.To learn more about Combination please click on the link
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Divisibility rules for 2, 5, and 10
Answer the questions below. Be sure to mark all answers that apply.
(a) Which numbers are divisible by 2?
(b) Which numbers are divisible by 5?
(c) Which numbers are divisible by 10?
145 891
O
O
O
890
X
None of these
O
Ś
Answer:
2 is divisible by 1 and all even numbers are divisible by 2 so that means 4 but 2 is not divisible by 8 and 9 is not divisible by 2 but 1 is.
5 is not divisible by 4. 5 is divisible by 5, 5 is not divisible by 8, 9 is not divisible by 5, 1 is not divisible by 5.
10 is divisible by 1, 4 is not, 5 is not, 8 is not, 9 is not divisible by 10 but 1 is.
The formula s = √18d can be used to find the speed s of a car in miles per
hour when the car needs d feet to come to a complete stop after stepping
on the brakes. If it took a car 25 feet to come to a complete stop after
stepping on the brakes, estimate the speed of the car. Truncate the value
of √18d, when d = 25, to the tenths place.
Answer:
Substitute d=25 to the formula and use a calculator to evaluate: s=18(25 s=450 s~21,2132... Truncated to the tenths place, we have: s~21.2 miles per hour.
Step-by-step explanation:
B
Identifying Properties of Substances and Mixtures
Which properties are characteristics of pure substances, and which are characteristics of mixtures?
May be multiple states of matter
Pure Substances
Exist in the same state of matter
Can be separated physically
Have consistent properties
Cannot be separated physically
Cannot be a single element
Intro
Mixtures
Done
Properties of pure substances:
Exist in the same state of matterHave consistent propertiesCannot be separated physicallyProperties of mixtures:
May be multiple states of matterCan be separated physicallyCannot be a single elementPure substances:
Each homogenous mixture contains only pure substances. No matter how tiny the sample size, these chemicals primarily have a stable or comparable composition throughout. Water, steel, and iron are a few examples of pure materials.
Mixtures:
In chemistry, a mixture is a compound made up of two or more simpler substances. These substances may be chemical elements or compounds. You can create a mixture of gases, solids, or liquids. For instance, when sugar is added to water, it first forms a mixture before dissolving to produce a solution.
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> Read and try to solve the problem below.
Mei is building a raised bed in her garden to grow lettuce.
She wants the base of the bed to be a square with an area of
2 square meters. Find an approximate side length of the base
of the bed. Plot the value on the number line.
Side length of the base of the bed is √2.
What is square?A square is a plane shape with four equal sides and four right angles (90°). A square is an unique sort of parallelogram as well as an equilateral rectangle (an equilateral and equiangular one).
The bed's base will be square.
An area of 2 square meters.
So, the area A=a2 is 2=a2
So, the area of square is √2
Therefore, Side length of the base of the bed is √2
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7 students are sharing 4 bags of takis so that each person gets the same amount how much can each student have?
Answer:
) What is the value of x in the following simplification problem?
45% of 600 + x% of 480 = 390. A/ 30
B/ 20
C/ 25
D/ 40
40) The s
The product of powers law of exponents states to keep the ______ then _______ the powers.
A. base. A. add
B. coefficient B. subtract
C. exponent C. multiply
find the gradients of line a and b
Answer:
[tex]a = 4[/tex]
[tex]b = - 2[/tex]
Step-by-step explanation:
See the attached image above for explanation.
I hope it helpsIn the number 98.48, what will you multiply by to get rid of the decimal?
Based on the number, 98.48, the number you need to multiply by to get rid of the decimal is 100.
What number should you multiply by to remove the decimal?The number that you multiply a number with if you want to remove the decimal has to be a power of 10. The power of 10 used will depend on the number of figures after the decimal.
If there is a single number after the decimal point, then multiply by 10.
If there are two numbers after the decimal point, multiply by 100.
If there are three numbers after the decimal point, multiply by 1,000.
In the case of 98.48, there are two number after the decimal point so you'll multiply by 100 to get:
= 98.48 x 100
= 9,848
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need someone to help me quick please
Answer:
the answer is no relation
For these data, which measures of central tendency take more than one value? Choose all that apply
Answer:
Step-by-step explanation:
In a sample of 1100 U.S. adults, 203 think that most celebrities are good role models. U.S. adults are selected from this sample without replacement. Complete parts (a) through (c). (a) Find the probability that both adults think most celebrities are good role models. The probability that both adults think most celebrities are good role models is nothing. (Round to three decimal places as needed.) (b) Find the probability that neither adult thinks most celebrities are good role models. The probability that neither adult thinks most celebrities are good role models is nothing. (Round to three decimal places as needed.) (c) Find the probability that at least one of the two adults thinks most celebrities are good role models. The probability that at least one of the two adults thinks most celebrities are good role models is nothing. (Round to three decimal places as needed.)
Using the hypergeometric distribution, the probabilities are given as follows:
a) 0.034 = 3.4%.
b) 0.665 = 66.5%.
c) 0.3352 = 33.5%.
What is the hypergeometric distribution formula?The formula is:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.N is the size of the population.n is the size of the sample.k is the total number of desired outcomes.For this problem, the parameters are given as follows:
N = 1100, k = 203, n = 2.
In item a, the probability is P(X = 2), hence:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 2) = h(2,1100,2,203) = \frac{C_{203,2}C_{897,0}}{C_{1100,2}} = 0.034[/tex]
For item b, the probability is P(X = 0), hence:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 0) = h(0,1100,2,203) = \frac{C_{203,0}C_{897,2}}{C_{1100,2}} = 0.665[/tex]
For item c, the probability is:
P(X >= 0) = 1 - P(X = 0) = 1 - 0.665 = 0.335.
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How many portions of 8 ¾ ounces each can be made from a boneless roast weighing 28 pounds? (Remember, 1 pound = 16 ounces.)
portions
The portions of 8 ¾ ounces that can be made from a boneless roast weighing 28 pounds is 51.2 portions.
How to calculate the value?1 pound = 16 ounces
Therefore, 28 pounds will be:
= 28 × 16
= 448. ounces
Therefore the number of portions will be:
= 448 / 8 3/4
= 448 / 8.75
= 51.2 portions
Therefore, the portions of 8 ¾ ounces that can be made from a boneless roast weighing 28 pounds is 51.2 portions.
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Where’s 1 7/10 on a number line?
The location of 17/10 on the number line is given below .
A number line provides a "picture" of what a number is. Visually see where your number is and other numbers nearby. Large numbers are always on the right and small numbers are always on the left.Small marks along the line represent the next highest or next lowest number. In most cases, the small marks are one count apart. There is no problem. The arrows at the ends of the number line mean infinite left and right movement, just like numbers move infinitely.
The fraction 17/10 is equals 1.7 .
Also note that minus 17/10 is the same distance from 0, but to the left of 0 instead of to the right.
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Write the given equation in slope-intercept form.
Given: 3x + 2y
A Y У
BY
c) Y
DY
3
===x-5
2²
=
3232
=
232
2x+5
x-5
2⁰t
2²+5
10
Я люблю тебя так сильно, что не знаю, как это сделать Я люблю тебя так сильно, что не знаю, как это сделать Я люблю тебя так сильно, что не знаю, как это сделать vvvvЯ люблю тебя так сильно, что не знаю, как это сделать Я люблю тебя так сильно, что не знаю, как это сделать vЯ люблю тебя так сильно, что не знаю, как это сделать Я люблю тебя так сильно, что не знаю, как это сделать Я люблю тебя так сильно, что не знаю, как это сделать vvvvЯ люблю тебя так сильно, что не знаю, как это сделать vvЯ люблю тебя так сильно, что не знаю, как это сделать Я люблю тебя так сильно, что не знаю, как это сделать
=3
Diego is moving to a new apartment and plans to rent a 16-foot moving truck for the
day. When he checks the cost of different rental companies, he finds that Rent-A-
Truck costs $59.95 a day plus $0.49 per mile. Sam's U-Drive costs $81 per day plus
$0.38 per mile. Austin needs to determine the mileage at which it is better to rent
from Rent-A-Truck and the mileage at which it is better to rent from Sam's U-Drive.
Let m represent the miles driven and let c represent the total cost. Write a system of
equations that represents this situation
Write the system. You do not need to solve.
Answer:
Rent-A-Truck-> 59.95+0.49m=c
Sam's U-Drive-> 81+0.38m=c
please help with math problem.
The cups of water needed to fill one container is 1 1/8. The expression is 1 1/8 cups
The container of water needed to fill one cup is 8/9. The division expression is 2/3 ÷ 3/4
How much cup and container is needed?A fraction is a non-integer that is made up of a numerator and a denominator that is separated by a line. An example of a fraction is 1/2. 1 is the numerator and 2 is the denominator.
In order to determine the cups of water that is needed to fill one container, divide the fraction of a cup that is needed to fill 2/3 of the container by 2/3.
Water needed to fill one container = 3/4 ÷ 2/3
3/4 x 3/2 = 9/8 = 1 1/8 cups
In order to determine the container that is needed to fill one cup, divide the fraction of a container that is needed to fill 2/3 of the container by 3/4.
Water needed to fill one cup = 2/3 ÷ 3/4
2/3 x 4/3 = 8/9
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(8, -4) (3,8)
distance
Answer:
distance = 13
Step-by-step explanation:
The formula used to calculate the distance between two points given their coordinates is:
[tex]\boxed{\mathrm{distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}}[/tex],
where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are the given coordinates.
In this question, we are given the coordinates (8, -4) and (3, 8).
Using these coordinates and the formula above, we can calculate the distance between the points:
[tex]\mathrm{distance = \sqrt{(3 - 8)^2 + (8- (-4))^2}}[/tex]
[tex]= \sqrt{(-5)^2+(12)^2}[/tex]
[tex]= \sqrt{25 + 144}[/tex]
[tex]= \sqrt{169}[/tex]
[tex]= \bf 13[/tex]
Therefore, the distance between the two points is 13 units.
A model rocket is launched with an initial upward velocity of 39 m/s. The rocket's height / (in meters) after t seconds is given by the following?
For t = 0.8 seconds and t = 7 seconds, the height of the rocket will be 28 m.
We are given that:
Initial velocity of the rocket = 39 m / s
Time = t seconds
h = 28 m
The equation of relationship between height and time is given as:
h = 39 t- 5 t²
Substituting the value of h is the equation, we get that:
28 = 39 t - 5 t²
5 t² - 39 t + 28 = 0
Using middle term splitting to find the values of t, we get that:
5 t² - 35 t - 4 t + 28 = 0
5 t ( t - 7 ) - 4 ( t - 7 ) = 0
(5 t - 4 ) ( t - 7 ) = 0
5 t - 4 = 0 and t - 7 = 0
5 t = 4 and t = 7
t = 0.8 and t = 7.
Therefore, for t = 0.8 seconds and t = 7 seconds, the height of the rocket will be 28 m.
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Your question was incomplete. Please refer the content below:
A model rocket is launched with an initial upward velocity of 39 m/s. The rocket's height (in meters) after t seconds is given by the following.
h = 39 t- 5 t²
Find all values of t for which the rocket's height is 28 meters. Round your answer(s) to the nearest hundredth.
An isolated agricultural country has two distinct regions: a lowland plain and an upland of rugged hills. On one unit of land on the PLAIN, a farmer can raise 10 bushels of grain or graze 10 sheep. On one unit of land in the HILLS, a farmer can raise 2 bushels of grain or graze 4 sheep.
Determine which region has the absolute advantage for sheep production. Explain your answer.
Because food grows more quickly in the hills when exposed to heat and rain rather than sunlight all day. Then for 1 sheep 1 bushel is required in the hills.
What are statistics?The practice or science of organizing and interpreting numerical data in big quantities, particularly for the objective of concluding proportions in a whole from those in an expected sample.
Given that a remote agricultural nation is divided into two distinct geographic areas: a lowland plain and an upland of rough hills. A farmer can grow 10 bushels of grain or pasture 10 sheep on one unit of land on the plain. A farmer in the hills can pasture 4 sheep or grow 2 bushels of grain on one unit of land.
As opposed to being exposed to sunlight all day, food develops more quickly in the hills when it is exposed to heat and rain.
For uphills = 10 sheeps = 10 bushels
For uphills = 1 sheeps = 1 bushels
For down plain = 4 sheeps = 2 bushels
For down plain = 1 sheeps = (1 / 2 ) bushels
Therefore, then for 1 sheep 1 bushel is required in the hills.
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If f ( x ) = – 2 x + 3 then f ( 3 ) – f ( 4 ) =
For the function f ( x ) = – 2 x + 3, the value of f ( 3 ) – f ( 4 ) will be 2
What is a function?A function in mathematics from a set X to a set Y allocates precisely one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.
Given,
f ( x ) = – 2 x + 3
f(3) = -2(3) + 3
= -6 + 3
f(3) = -3
f(4) = -2(4) + 3
= -8 + 3
= -5
f ( 3 ) – f ( 4 ) = -3 + 5
= 2
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In ALMN, l= 97 cm, m = 52 cm and ZN=39°. Find ZL, to the nearest degree.
Answer: In ALMN, l= 97 cm,
m = 52 cm,
ZN=39°,
ZL= 66°
Step-by-step explanation:
Given data,
In ALMN, l= 97 cm, m = 52 cm and ZN=39°.
The law of cosines can be used to find the missing side.
n² = m² +n² -2ml·cos(L)
n² = [tex]52^{2}[/tex] + [tex]97^{2}[/tex] - 2(52)(97). cos (39°)
n² = 9409 + 2704 - 2(52)(97). cos (39°)
n² = 12113 - 2(52)(97). cos (39°)
n² = 12113 - 10088 cos (39°) (eq - 1)
So, that cos (39°) = 0.777
Substitute cos (39°) value in this equation 1
So,
We can write,
n² = 12113 - 10088* 0.777
n² = 12113 - 7838.3
n² = 4274.62
n = √4274.62
n = 65.38 ≅ 66
Therefore,
In ALMN, l= 97 cm,
m = 52 cm,
ZN=39°,
ZL= 66°
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