A plate moves 200 m in 10,000 years. What is its rate in cm/year?

Answer:−329.4 calorie

Explanation:Heat released by metal = q=m_mc_m(T_2-T1)q=m

m

​

c

m

​

(T

2

​

−T1)

m_m=50\ g\\c_m=0.108\ cal\ g^{-1}\ \degree C^{-1}\\q=50\times0.108(17-78)=-329.4\ caloriem

m

​

=50 g

c

m

​

=0.108 cal g

−1

 °C

−1

q=50×0.108(17−78)=−329.4 calorie

Here minus sign indicate that heat is released

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

[tex]Q_{metal} - Q_{water} = 0[/tex]

[tex]Q_{metal} = Q_{water}[/tex]

Where:

[tex]Q_{water}[/tex] - Heat received by water, measured in joules.

[tex]Q_{metal}[/tex] - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

[tex]m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})[/tex]

The specific heat of the metal is cleared within equation above:

[tex]c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}[/tex]

If we know that [tex]m_{water} = 0.237\,kg[/tex], [tex]m_{metal} = 0.244\,kg[/tex], [tex]c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{w,o} = 10\,^{\circ}C[/tex], [tex]T_{m,o} = 100.10\,^{\circ}C[/tex] and [tex]T = 15.30\,^{\circ}C[/tex], the specific heat of molybdenum is:

[tex]c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}[/tex]

[tex]c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}[/tex]

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Answer:

[tex]15molH[/tex]

Explanation:

Hello,

In this case, given that one mole of glucose, contains six moles of oxygen (subscript), we can also see it contains twelve moles of hydrogen (subscript), therefore, the moles of hydrogen in the sample are computed by:

[tex]0.75molO*\frac{1molC_6H_{12}O_6}{6molO}*\frac{12molH}{1molC_6H_{12}O_6}\\ \\=1.5molH[/tex]

Best regards.

Answer: My data strongly supported my hypothesis. I was right when guessed the solids density would be higher than the liquids and also that the mass affected the volume of the objects. The experiment proves that hypothesis is correct. To test further I could use different types of liquid and rocks with material.

When I predicted that solids would have a higher density than liquids and that mass would affect the volume of the objects.

I may use different sorts of fluids and rocks with stuff to test further.

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Answer:

The velocity of the ejected electron from the ionized atom is 3.6 × 10⁵ m/s

Explanation:

Using the conservation of energy, we can write that

Photon energy (E) = Ionisation energy (I.E) + Kinetic energy (K.E)

Photon  energy, E = [tex]hf[/tex]

Where [tex]h[/tex] is Planck's constant ( [tex]h[/tex] = 6.626 × 10⁻³⁴ kgm²/s)

and [tex]f[/tex] is the frequency

Also,

Kinetic energy, K.E = [tex]\frac{1}{2} mv^{2}[/tex]

Where [tex]m[/tex] is mass

and [tex]v[/tex] is velocity

Hence, we can write that

[tex]hf = I.E + \frac{1}{2}mv^{2}[/tex]

But, [tex]c = f\lambda[/tex]

where [tex]c[/tex] is the speed of light ( [tex]c[/tex] = 3.0 × 10⁸ m/s)

and λ is the wavelength

∴ [tex]f = \frac{c}{\lambda}[/tex]

Then,

[tex]\frac{hc}{\lambda} = I.E + \frac{1}{2}mv^{2}[/tex]

From the question, the first ionisation energy of sodium is 496 kJ/mol

This is the ionisation energy for 1 mole of sodium,

For 1 atom of sodium, we will divide by Avogadro's constant

∴ The ionisation energy becomes

(496 KJ/mol) / (6.02 × 10²³ molecules)

= 8.239 × 10⁻¹⁹ J

This is the ionisation energy for one atom of sodium

Now, to determine the velocity of the ejected electron from the ionized atom,

From,

[tex]\frac{hc}{\lambda} = I.E + \frac{1}{2}mv^{2}[/tex]

Then,

[tex]\frac{6.626\times 10^{-34} \times 3.0 \times 10^{8} }{225 \times 10^{-9} } = 8.239 \times 10^{-19} + \frac{1}{2}(9.109\times10^{-31} )v^{2}[/tex]

[tex]8.835 \times 10^{-19} = 8.239 \times 10^{-19} + 4.5545 \times 10^{-31}v^{2}[/tex][tex]8.835 \times 10^{-19} - 8.239 \times 10^{-19} = 4.5545 \times 10^{-31}v^{2}[/tex]

[tex]5.96 \times 10^{-20} = 4.5545 \times 10^{-31}v^{2}[/tex]

[tex]v^{2} = \frac{5.96 \times 10^{-20}}{4.5545 \times 10^{-31}}[/tex]

[tex]v^{2} = 1.3086 \times 10^{11}[/tex]

[tex]v = \sqrt{1.3086 \times 10^{11} }[/tex]

[tex]v = 361745.77 m/s[/tex]

[tex]v = 3.6 \times 10^{5} m/s[/tex]

Hence, the velocity of the ejected electron from the ionized atom is 3.6 × 10⁵ m/s

Answer:

a

[tex]a_o  = 4.95 *10^{-8} \  cm  [/tex]

b

[tex]r =  1.7500 *  10^{-8} \  cm[/tex]

Explanation:

From the question we are told that

   The  density of  lead is  [tex]\rho_l =  11.36 \  g/cm^3[/tex]

   The atomic weight is  [tex]M_w  =  207.19 \  g/mol[/tex]

    The  Avogadro's number is  [tex]N_a  =  6.022 *  10^{23} \  \frac{atom}{mol}[/tex]

Generally for FCC the number of  atom is  n  =  4

 Generally the volume of a unit FCC cell is mathematically represented

          [tex]V =  \frac{n  *  M_w }{N_a  *  \rho_l }[/tex]

          [tex]V =  \frac{4  *  207.19 }{ 6.022 *  10^{23}  *  11.36 }[/tex]

         [tex]V = 1.211 5 *10^{-22} \  cm^3[/tex]

Generally the lattice parameter is mathematically represented as

      [tex]a_o  = \sqrt[3]{V } [/tex]

     [tex]a_o  = \sqrt[3]{1.211 5 *10^{-22} } [/tex]

=>   [tex]a_o  = 4.95 *10^{-8} \  cm  [/tex]

Generally the radius of the lead is mathematically represented as

        [tex]r =  \frac{a_o  *  \sqrt{2}  }{4}[/tex]

=>      [tex]r =  \frac{4.95 *10^{-8}  *  \sqrt{2}  }{4}[/tex]

=>      [tex]r =  1.7500 *  10^{-8} \  cm[/tex]

Answer:

A. Density of object = 0.86 g/mL

B. The object will float in the water.

Explanation:

The following data were obtained from the question:

Volume of water = 6.2 mL

Mass (m) of object = 1.2 g

Volume of water + Object = 7.59 mL

Density of object =?

Density of water = 1 g/mL

Next, we shall determine the volume of the object. This can be obtained as follow:

Volume of water = 6.2 mL

Volume of water + Object = 7.59 mL

Volume of object =?

Volume of object = (Volume of water + Object) – (Volume of water)

Volume of object = 7.59 – 6.2

Volume of object = 1.39 mL

Therefore, the volume of the object is 1.39 mL

A. Determination of the density of the object.

Mass (m) of object = 1.2 g

Volume (V) of object = 1.39 mL

Density (D) of object =?

Density = mass /volume

Density = 1.2/1.39

Density of object = 0.86 g/mL

B. Determination of whether the object will float or sink.

Density of object = 0.86 g/mL

Density of water = 1 g/mL

From the above, we can see that the density of water is greater than that of the object. This implies that the object is lighter than water. Therefore, the object will float in the water.

Answer:

152.4 g

Explanation:

Step 1: Given data

Number of H atoms: 8.334 × 10²⁴ atoms

Step 2: Calculate the moles of H corresponding to 8.334 × 10²⁴ atoms of H

We will use Avogadro's number, that is, there are 6.022 × 10²³ atoms of H in 1 mole of H.

8.334 × 10²⁴ atom × (1 mol/6.022 × 10²³ atom) = 13.84 mol

Step 3: Calculate the moles of ammonium acetate (NH₄CH₃CO₂) that contain 13.84 moles of H

The molar ratio of NH₄CH₃CO₂ to H is 1:7. The moles of NH₄CH₃CO₂ that contain 13.84 moles of H are 1/7 × 13.84 mol = 1.977 mol.

Step 4: Calculate the mass corresponding to 1.977 moles of NH₄CH₃CO₂

The molar mass of NH₄CH₃CO₂ is 77.08 g/mol.

1.977 mol × 77.08 g/mol = 152.4 g

Answer:

Molar concentration of the Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.

Explanation:

When you make a calibration curve in a spectrophotographic analysis you are applying the Lambert-Beer law that states the concentration of a compound is directely proportional to its absorbance:

A = E*l*C

Where A is absorbance, E is molar absorption coefficient, l is optical path length and C is molar concentration

Using the equation of the line you obtain:

y = 4541.6X + 0.0461

Where Y is absorbance and X is concentration -We will assume concentration is given in molarity-

As absorbance of the unknown is 0.410:

0.410 = 4541.6X + 0.0461

X = 8.01x10⁻⁵M

Answer:

[tex]m_{SO_2}=0.175gSO_2[/tex]

Explanation:

Hello,

In this case, since the first step is to write the properly balanced chemical reaction:

[tex]P_4S_3 (s) + 8O_2 (g)\rightarrow P_4O_{10}(s) + 3SO_2 (g)[/tex]

We can see that given the 0.200 g of P4S3 (molar mass 220 g/mol) the mole ratio between it and SO2 (molar mass 64 g/mol) is 1:3, therefore, the produced mass of SO2 turns out:

[tex]m_{SO_2}=0.200gP_4S_3*\frac{1molP_4S_3}{220gP_4S_3} *\frac{3molSO_2}{1molP_4S_3} *\frac{64gSO_2}{1molSO_2} \\\\m_{SO_2}=0.175gSO_2[/tex]

Best regards.

Answer:

10

Explanation:

no explanation need thats the right answer i gotchu g

Answer:10

Explanation:

no explanation need thats the right answer

Answer:

SO42 - Trigonal planar ion

Explanation:

The SO4^2- ion is tetrahedral and not trigonal planar because the sulphur atom has four regions of electron density which includes the lone pair of electrons on sulphur atom.

This accounts for the observed tetrahedral arrangement of electron pairs around the central sulphur atom in SO4^2- ion, hence the answer.

Answer:

A.

Explanation:

It’s just right

Answer:

true

Explanation:

Answer:

True

Explanation:

Observation is objective while inference is subjective.

Answer:

Sublimation is when a solid transitions into a gas, without turning into liquid.

Decantation is when a mixture of liquids is allowed to separate, such that an element of the mixture may be removed.

Answer:

A. np and nf

Explanation:

The electron distribution into energy levels or sublevels of atoms can be shown in their sublevel notations. This shows the sequence of filling electrons into the orbitals of the sublevels as guided by some principles such as the Aufbau Principle, Pauli Exclusion Principle, Hund's Rule of Maximum Multiplicity e.t.c

The maximum number of electrons in the orbitals of sublevels are two for s-sublevel(one orbital), six for p-level (three orbitals), ten for d-sublevel (five orbitals), and fourteen for f-sublevel (seven orbitals). This explains that the maximum number of electrons in an orbital is two.

Answer:

The correct  option is E

Explanation:

Generally the a base with the highest [tex]K_b[/tex] is the strongest base and from the data given

       [tex]C_2H_5NH_2[/tex] has the highest value of [tex]K_b[/tex] so [tex]C_2H_5NH_2[/tex]  is the strongest base while  [tex](NH_2)_2CO[/tex] has the lowest value of [tex]K_b[/tex] so [tex](NH_2)_2CO[/tex]  is the weakest base

  Generally the conjugate acid of a weak base is always a strong acid

So

  For  [tex](NH_2)_2CO[/tex] which the weakest base it conjugate acid which is [tex][NH_2NH_3CO]^+[/tex] will be the strongest acid

Answer:

Heating water with an open flame

Explanation:

Remember, we are told in the label that Acetone is a "flammable liquid and vapor." Being flammable means the substance can easily be set on fire, and we would expect an open flame from heating water to trigger an explosion (a disaster) in which the Acetone is set on fire causing life-threatening dangers to the second group of students.

Answer:

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Explanation:

Let's consider the double displacement reaction in which aqueous silver nitrate reacts with aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate.

AgNO₃(aq) + NiCl₂(aq) ⇒ AgCl(s) + Ni(NO₃)₂(aq)

We have 2 atoms of Cl on the left side, so we will add a stoichiometric coefficient 2 to AgCl.

AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, we have 2 atoms of Ag on the right side, so we will add a stoichiometric coefficient 2 to AgNO₃.

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, the equation is balanced.

The balanced chemical equation for the reaction is

2AgNO₃(aq) + NiCl₂(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)

To write a balanced chemical equation for the reaction between aqueous silver nitrate and aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate

First, we will write the chemical formula for the each of the reactants and products

That is,

Silver nitrate - AgNO₃

Nickel(II) chloride - NiCl₂

Silver chloride - AgCl

Nickel(II) nitrate - Ni(NO₃)₂

Now, for the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

2AgNO₃(aq) + NiCl₂(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)

Hence, the balanced chemical equation for the reaction is 2AgNO₃(aq) + NiCl₂(aq) → 2AgCl(s) + Ni(NO₃)₂(aq)

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Explanation:

The animals and plants eventually die. Decomposers break down the dead organisms and return the carbon in their bodies to the atmosphere as carbon dioxide by respiration. In some conditions, decomposition is blocked. The plant and animal material may then be available as fossil fuel in the future for combustion.

Answer:  Coastal dunes are a ridge, or a series of ridges, that form at the rear of a beach and differ from most other constructional coastal landforms in that they are formed by the movement of air (aeolian transport) rather than by tidal, wave, or current action.A coastal plain is a flat, low-lying piece of land next to the ocean. Coastal plains are separated from the rest of the interior by nearby landforms, such as mountains. In western South America, a large coastal plain lies between the Andes Mountains and the Pacific Ocean.

Explanation:

Answer:  Both have low elevation.

Explanation:

hope it helped xx

The best option which describes the burning of a house from a thermo

dynamical standpoint is ∆H > 0, ∆S > 0

Increase in temperature in a system will cause an increase in the heat

energy and a corresponding increase in the entropy of a system and are

denoted by ∆H and ∆S respectively.

∆H  and ∆S  being greater than zero signifies an increase in both

conditions. Heat energy and the degree of randomness will be increased

when the house is burning which makes ∆H > 0, ∆S > 0 correct.

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Answer:

pH = 1.05

Explanation:

A solution of sulfuric acid, H₂SO₄, dissociates in water as follows:

H₂SO₄ → 2H⁺ + SO₄²⁻

That means per mole of H₂SO₄ you will have 2 moles of H⁺

pH = -log [H⁺]

As [H₂SO₄] = 0.045M and [H⁺] = 2×[H₂SO₄]

[H⁺] = 0.090M

pH = -log [0.090M]

Given :

Some compounds :

[tex]A)\ CH_3Cl\ B)\ CH_3I\ C)\ CH_3Br\ D)\ CH_4[/tex] .

To Find :

Which of the following compounds has the most deshielded protons .

Solution :

Deshielded means nucleus whose chemical shift has been increased due to removal of electron density, magnetic induction, or other effects .

In simple words deshielding means the ability to shift protons .

Now , among Cl , I , Br and H . Cl is the most electron negative .

Therefore , deshielding will be more in [tex]CH_3Cl[/tex] .

Hence , this is the required solution .

The compound with the presence of most deshielded protons has been [tex]\rm \bold{CH_3Cl}[/tex]. Thus, option A is correct.

Diesheilded protons have been explained as the shift in the protons of the central atom with the bonding to a more electronegative element.

The electronegative element has been possessing the negative charge and is attracted to the positive charge.There has been a shift in the protons in the sample that has been resulted in the de-shielded protons.

In the given compounds, the anions bonded to the methyl groups are Cl, C, Br, and H. Among the following, the most electronegative atom has been chlorine.

Thus, the molecule of [tex]\rm \bold{CH_3Cl}[/tex] has been consisted of the most de-shielded protons. Thus, option A is correct.

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Answer:

[MA4B2]2+

Explanation:

Octahedral species are species that has a coordination number of of six. This means that six ligands are attached to the central metal atom/ion.

For any octahedral specie to exhibit geometrical or cis-trans isomerism, it must have the formula EX2Y4 as in [MA4B2]2+, hence the answer above.

Answer:

CaBr2 and CaCl2 solubility increases with increase in pH while the solubility of Ca(OH)2 and MgCl2 increases with decrease in pH.

Explanation:

Yes, solubility of compounds change with ph. The solubility of CaBr2 increases with the increase occurs in pH. The solubility of CaCl2 also increases with the increase in pH of a solution. On the other hand, the higher pH, decreases the solubility of Ca(OH)2 while with low pH, Ca(OH)2 solubility increases. MgCl2 solubility also increases with the decrease occurs in pH. There are different solubilities for different compounds , some compounds having highest solubility in acidic and some in basic.

When the CaBr2 and CaCl2 solubility rises with an increase in pH while the solubility of Ca(OH)2 and also MgCl2 increases with a reduction in pH.

Yes, When the solubility of combinations changes with ph. When The solubility of CaBr2 expansions with the increase occurs in pH. Then, The solubility of CaCl2 also increases with the accumulation in pH of a solution. On the different indicators, the higher pH decreases the solubility of Ca(OH)2 while with low pH, Ca(OH)2 solubility increases. MgCl2 solubility also increases with the decrease transpiring in pH. So, There are different solubilities for different compounds, When some compounds have the highest solubility in acidic and also some in basic.

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Answer:

312.5J

Explanation:

K.E=1/2*mv°2

=1/2*25*25

=312.5