A player kicks a football at an angle of 37°C with the horizontal and with an initial speed of 16ms-1. A second player standing at a distance of 33m from the first in the direction of the kick starts running to meet the ball at the instant it is kicked. How fast must he run in order to catch the ball before it hits the ground. ​

Answers

Answer 1

After considering all the given data we come to the conclusion that the top velocity at which the individual must run is 66 m/s.

In order to catch the ball before it hits the ground, the second player must run at a speed equal to the horizontal component of the ball's velocity. The horizontal component of the ball's velocity is given by:

v₀x = v₀ cos(θ)

Here,

v₀ = initial speed of the ball,

θ = angle of projection with respect to the horizontal v₀x = horizontal component of the ball's velocity.

For the given case, v₀ = 16 m/s and θ = 37°. Then,

v₀x = 16 cos(37°) ≈ 12.7 m/s

The second player is at a distance of 33 m from the first player. The time taken by the ball to reach this point can be evaluated as follows:

t = d / v₀x

Here,

d = distance between the two players

t = time taken by the ball to reach this point.

Staging d = 33 m and v₀x = 12.7 m/s, we get:

t ≈ 2.6 s

The vertical component of the ball's velocity can be evaluated as follows:

v₀y = v₀ sin(θ)

Here,

v₀y = vertical component of the ball's velocity.

The time taken by the ball to hit the ground can be evaluated as follows:

t' = 2v₀y / g

Here, g is acceleration due to gravity.

Staging  v₀y = v₀ sin(θ) and g = 9.8 m/s², we get:

t' ≈ 2.1 s

Then, for the second player to catch the ball before it hits the ground, he must run at a speed equivalent to:

v = d / (t - t')

Here,

d = distance between the two players,

t = time taken by the ball to reach this point

t' = time taken by the ball to hit the ground.

Staging d = 33 m, t ≈ 2.6 s and t' ≈ 2.1 s, we get:

v ≈ 33 / (2.6 - 2.1) ≈ 66 m/s

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Related Questions

How much energy is stored in a room 3.0 m by 4.0 m by 2.4 m due to the earthʹs magnetic field
with a strength of 5.0 × 10-5 T? (μ0 = 4π × 10-7 T · m/A)
A) 570 mJ.
B) 29 mJ.
C) 10 mJ.
D) 100 mJ.
E) 570 mJ.

Answers

The answer is (C) 10 mJ.  The energy stored in a magnetic field is given by the formula:

$U = \frac{1}{2} \mu_0 V B^2$

where $V$ is the volume of the region with magnetic field $B$, $\mu_0$ is the permeability of free space, and $B$ is the strength of the magnetic field.

In this case, the volume is:

$V = 3.0\ \text{m} \times 4.0\ \text{m} \times 2.4\ \text{m} = 28.8\ \text{m}^3$

The strength of the magnetic field is given as $B = 5.0 \times 10^{-5}\ \text{T}$.

The permeability of free space is $\mu_0 = 4\pi \times 10^{-7}\ \text{T}\cdot \text{m}/\text{A}$.

Substituting the values into the formula gives:

$U = \frac{1}{2} \mu_0 V B^2 = \frac{1}{2} \times 4\pi \times 10^{-7}\ \text{T}\cdot \text{m}/\text{A} \times 28.8\ \text{m}^3 \times (5.0 \times 10^{-5}\ \text{T})^2 \approx 10\ \text{mJ}$

Therefore, the answer is (C) 10 mJ.

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which event happens after a dipole moment in a molecule?(1 point) responses the molecule is stretched and bent. the molecule is stretched and bent. solar radiation is absorbed by the molecule. solar radiation is absorbed by the molecule. positive and negative charges in the molecule are imbalanced temporarily. positive and negative charges in the molecule are imbalanced temporarily. the molecule vibrates and releases infrared energy.

Answers

The event after a dipole moment in a molecule is E. the positive and negative charges in the molecule are imbalanced temporarily.

The charges create a small electric field, resulting in the molecule experiencing the attraction and repulsion forces of nearby charged particles. The temporarily imbalanced charges on a polar molecule, when it comes in close proximity to another polar molecule or ion, cause an interaction between the charges. The molecule interacts with its environment in several ways: van der Waals interactions, hydrogen bonding, and dipole-dipole interactions.

This interaction may lead to the molecule being stretched and bent or vibrating and releasing infrared energy, depending on the surrounding environment, and the molecular geometry, respectively. The net dipole moment of a molecule, which is the sum of its bond dipole moments, indicates the polarity of a molecule. If the bond dipole moments cancel each other out, the molecule is nonpolar and has no net dipole moment. Therefore, the strength of the dipole moment is determined by the electronegativity difference between atoms in the molecule.

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Cual es la causa y efecto ¿Cómo cambia la rapidez de un móvil con la pendiente?

Answers

La pendiente de una superficie puede afectar la rapidez de un móvil. Cuando un móvil se desplaza en una pendiente ascendente, su velocidad tiende a disminuir, mientras que en una pendiente descendente, la velocidad tiende a aumentar.

Esto se debe a la influencia de la fuerza gravitatoria en el movimiento del móvil. La causa de cómo cambia la rapidez de un móvil con la pendiente está relacionada con la influencia de la fuerza gravitatoria. En una pendiente ascendente, la fuerza gravitatoria actúa en sentido contrario al movimiento del móvil, lo que resulta en una disminución de la velocidad. La fuerza gravitatoria tira del móvil hacia abajo, contrarrestando el avance del móvil hacia arriba.

Por otro lado, en una pendiente descendente, la fuerza gravitatoria actúa a favor del movimiento del móvil. Esto implica que la fuerza gravitatoria ayuda a acelerar el móvil mientras se desplaza hacia abajo. Como resultado, la velocidad del móvil tiende a aumentar en una pendiente descendente.

Es importante tener en cuenta que otros factores, como la fricción y la resistencia del aire, también pueden influir en la rapidez del móvil en pendientes. Sin embargo, en términos generales, la influencia principal proviene de la fuerza gravitatoria y su dirección relativa al movimiento del móvil.

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How tall must a plane mirror be in order for you to be able to see your full image in it? A) 3/4 of your height B) the same height as you C) twice your height D) 1/4 of your height E) half of your height

Answers

A plane mirror must be the same height as you in order for you to be able to see your full image in it. The answer is B)

In order to see your full image in a plane mirror, the height of the mirror must be the same as your height. A plane mirror produces a virtual image that is the same size as the object being reflected.

When you stand in front of a plane mirror, the mirror reflects light rays from your entire body, creating a virtual image that appears behind the mirror.

The virtual image is formed by the reflection of light rays that follow the law of reflection, where the angle of incidence is equal to the angle of reflection.

This reflection allows you to see an image that is a mirror reflection of yourself. If the mirror is not tall enough, it will cut off a portion of your body, and you will not be able to see your full image.

Therefore, to see your full image in a plane mirror, the height of the mirror must match your height which is option B).

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At a certain instant the current flowing through a 5.0-H inductor is 3.0 A. If the energy in the
inductor at this instant is increasing at a rate of 3.0 J/s, how fast is the current changing?
A) 0.20 A/s
B) 0.40 A/s
C) 0.10 A/s
D) 0.80 A/s

Answers

The current is changing at a rate of 0.40 A/s. Answer: \boxed{B}.

The rate of change of energy in an inductor is given by:

$\frac{dW}{dt} = \frac{1}{2}LI^2\frac{dI}{dt}$

where L is the inductance, I is the current, and $\frac{dI}{dt}$ is the rate of change of current.

We are given that L = 5.0 H, I = 3.0 A, and $\frac{dW}{dt} = 3.0$ J/s. Substituting these values into the above equation, we get:

$3.0 = \frac{1}{2}(5.0)(3.0)^2\frac{dI}{dt}$

Solving for $\frac{dI}{dt}$, we get:

$\frac{dI}{dt} = \frac{3.0}{\frac{1}{2}(5.0)(3.0)^2} = 0.40$ A/s

Therefore, the current is changing at a rate of 0.40 A/s. Answer: \boxed{B}.

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Optical engineers need to know the cone of acceptance of an optical fiber. This is the maximum angle that an entering light ray can make with the axis of the fiber if it is to be guided down the fiber. What is the cone of acceptance of an optical fiber for which the index of refraction of the core is 1.55 while that of the cladding is 1.45? You can model the fiber as a cylinder with a flat entrance face.

Answers

The cone of acceptance of an optical fiber is a crucial parameter that optical engineers need to know while designing optical communication systems.

It is the maximum angle that a light ray can make with the axis of the fiber if it is to be guided down the fiber. To calculate the cone of acceptance of an optical fiber, we need to consider the refractive index of the core and cladding. If the refractive index of the core is higher than that of the cladding, then the cone of acceptance is larger, and vice versa.
In this case, the refractive index of the core is 1.55, while that of the cladding is 1.45. We can calculate the cone of acceptance using the formula:
sinθ = n2/n1
Where θ is the half-angle of the cone of acceptance, n1 is the refractive index of the core, and n2 is the refractive index of the cladding. Substituting the given values, we get:
sinθ = 1.45/1.55
sinθ = 0.9355
θ = sin^-1(0.9355)
θ = 68.7 degrees
Therefore, the cone of acceptance of the optical fiber is approximately 68.7 degrees. Optical engineers can use this information to design optical fibers and communication systems that are optimized for high-speed data transfer and minimal signal loss.

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Which of the following affect the rate of diffusion of a substance? (Select all that apply.)
a) presence of other solutes
b) temperature
c) concentration gradient
d) direct supply of metabolic energy (ATP)

Answers

Option a, b, c affects rate of diffusion. The rate of diffusion of a substance is influenced by several factors, including the presence of other solutes, temperature, and concentration gradient.

The presence of other solutes can impede the diffusion of a substance by creating a crowded environment, making it difficult for the substance to move through the medium. T

emperature can also affect the rate of diffusion, as higher temperatures increase the kinetic energy of molecules, making them move faster and facilitating diffusion. Additionally, the concentration gradient plays a crucial role in diffusion as the greater the concentration gradient, the faster the rate of diffusion.

However, the direct supply of metabolic energy (ATP) does not affect the rate of diffusion as diffusion is a passive process that occurs spontaneously down the concentration gradient. The factors affecting the rate of diffusion of a substance include the presence of other solutes (a), temperature (b), and concentration gradient (c).

The presence of other solutes may alter the rate due to interactions or competition for space. Temperature affects the kinetic energy of particles, with higher temperatures leading to increased movement and faster diffusion. The concentration gradient drives diffusion, as substances move from areas of high concentration to areas of low concentration. Direct supply of metabolic energy (d) does not typically impact passive diffusion, but may affect active transport processes in cells.

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identify x in the following nuclear transmutation: x(α,n)126c

Answers

In the nuclear transmutation x(α, n)126C, x represents Carbon-13 (13C) undergoing an alpha particle reaction resulting in the emission of a neutron.


In this nuclear transmutation, an alpha particle (α) interacts with an unknown nucleus (x) to produce a Carbon-12 nucleus (126C) and a neutron (n). To identify x, we need to apply the conservation of mass and atomic numbers. An alpha particle consists of 2 protons and 2 neutrons, so its mass number (A) is 4, and its atomic number (Z) is 2. Carbon-12 has a mass number of 12 and an atomic number of 6.
Conserving mass number: A(x) + A(α) = A(126C) + A(n)
Conserving atomic number: Z(x) + Z(α) = Z(126C) + Z(n)
Using these conservation equations:
A(x) + 4 = 12 + 1
Z(x) + 2 = 6 + 0
Solving the equations, we get A(x) = 13 and Z(x) = 4. Therefore, x is Carbon-13 (13C) with a mass number of 13 and an atomic number of 6.

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some lobes of radio galaxies are in fact moving faster than the speed of light.
T/F

Answers

The statement "some lobes of radio galaxies are in fact moving faster than the speed of light." is false.

According to Einstein's theory of relativity, the speed of light in a vacuum, denoted by "c," is a fundamental constant in the universe. It represents the maximum speed at which information or matter can travel.

In the context of galaxies, their apparent motion can sometimes appear to exceed the speed of light due to a phenomenon called "cosmological redshift." This occurs because the space between distant galaxies is expanding, causing the light emitted by those galaxies to stretch, resulting in a shift towards longer wavelengths.

However, it's important to note that this redshift does not imply that the galaxies themselves are physically moving faster than light. Instead, it is the result of the expanding space between them. In other words, the galaxies are not violating the fundamental limit set by the speed of light.

So, while the apparent recession speed of galaxies can exceed the speed of light due to the expansion of the universe, it does not imply that the galaxies themselves are moving faster than light in their local frames of reference.

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Sphere A with a charge of +2x10^-4 C is 12 meters apart from Sphere B with a charge of -8x10^-4. What is the magnitude of the electrostatic force exerted on sphere A?

Answers

The magnitude of the electrostatic force exerted on Sphere A is approximately 999 N. By using formula of force  F = k * (|q1 * q2|) / r^2

To calculate the magnitude of the electrostatic force exerted on Sphere A, we can use Coulomb's Law, which states:
F = k * (|q1 * q2|) / r^2
where F is the electrostatic force, k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the spheres, and r is the distance between them.
Given:
q1 = +2 x 10^-4 C
q2 = -8 x 10^-4 C
r = 12 meters
Step 1: Calculate the product of the charges.
|q1 * q2| = |(+2 x 10^-4 C) * (-8 x 10^-4 C)| = 1.6 x 10^-7 C^2
Step 2: Calculate the square of the distance between the spheres.
r^2 = (12 m)^2 = 144 m^2
Step 3: Apply Coulomb's Law.
F = (8.99 x 10^9 Nm^2/C^2) * (1.6 x 10^-7 C^2) / (144 m^2)
F ≈ 9.99 x 10^2 N
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no terriers wander among the zodiac. nothing that does not wander among the zodiac is a comet. nothing but a terrier has a curly tail. therefore, no comet has a curly tail. is this a logical statement?

Answers

the statement is logical and follows the rules of deductive reasoning. However, it may seem a bit convoluted or abstract because it uses specific terms and conditions to arrive at its conclusion.
1. No terriers wander among the zodiac.
2. Nothing that does not wander among the zodiac is a comet.
3. Nothing but a terrier has a curly tail.The premises establish that only terriers have curly tails and comets are not associated with terriers or the zodiac. Therefore, it logically follows that no comet has a curly tail.

1. The first premise states that "no terriers wander among the zodiac." This means that terriers do not belong to the group of objects or beings that are associated with the zodiac, such as the 12 astrological signs.

3. The third premise states that "nothing but a terrier has a curly tail." This means that only terriers possess the physical characteristic of having a curly tail.

4. From these three premises, we can draw the conclusion that "no comet has a curly tail." This is because comets do not belong to the group of objects associated with the zodiac, and anything that is not associated with the zodiac cannot be classified as a comet. Additionally, terriers are the only objects that possess curly tails, and comets are not terriers.


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a proper crosswind landing on a runway requires that, at the moment of touchdown, the

Answers

At the moment of touchdown during a crosswind landing, the aircraft's nose should be aligned with the runway centerline. This means that the aircraft's longitudinal axis (the direction the aircraft is pointing) should be parallel to the runway centerline.

To achieve this, the pilot must use a technique known as "crabbing" or "sideways slip" during the final approach. The crabbing technique involves using the aircraft's rudder to align the nose of the aircraft with the runway centerline while maintaining a constant heading with the wings level.

This compensates for the crosswind and prevents the aircraft from drifting sideways off the runway.

As the aircraft approaches the runway for landing, the pilot initiates a transition from the crabbing/sideways slip to a technique called "wing-low" or "cross-control."

In the wing-low technique, the pilot applies aileron input to lower the upwind wing, which effectively causes the aircraft to roll into the wind. This helps to counteract the crosswind and prevent the aircraft from drifting laterally.

Ideally, just before touchdown, the pilot smoothly and progressively reduces the wing-low input, allowing the aircraft to align with the runway centerline while maintaining a straight heading.

The touchdown should be made with the aircraft's longitudinal axis aligned parallel to the runway centerline, ensuring a safe and controlled landing in crosswind conditions.

It's important for pilots to receive proper training and practice to perform crosswind landings safely and effectively, as they require skill and technique to execute correctly.

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How long a tuning fork vibrates when its handle is held against a table is most related to
A. its frequency
B. resonance
C. the conservation of energy
D. the length of its prongs

Answers

The correct answer is A. The duration of vibrations of a tuning fork when its handle is held against a table is related to its frequency. The frequency of a tuning fork is determined by the length of its prongs and the material from which it is made.

The frequency of a tuning fork is the number of oscillations or vibrations it produces per second, and is measured in hertz (Hz). When a tuning fork is struck, it vibrates at its natural frequency and produces sound waves. When the handle of the tuning fork is held against a table, the table provides a medium for the sound waves to travel through, which helps sustain the vibrations of the tuning fork. The length of the prongs of a tuning fork affects its natural frequency, and longer prongs produce lower frequencies, while shorter prongs produce higher frequencies. Therefore, the duration of vibrations of a tuning fork when its handle is held against a table is most related to its frequency.

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a short circuit is one where needed connections are missing, such as when a wire breaks. a. True b. False

Answers

The statement "a short circuit is one where needed connections are missing, such as when a wire breaks" is false. A short circuit is a type of electrical circuit in which the current flows through a path of low resistance, bypassing the intended load or electrical device.

This can occur when two conductors in a circuit accidentally touch each other, or when the insulation between two conductors breaks down.

On the other hand, a missing connection, such as when a wire breaks, would result in an open circuit, which would prevent the flow of current through the circuit altogether.

Therefore, a short circuit and an open circuit are two distinct types of electrical faults, and they have different causes and effects on the electrical system.

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A solenoid having N turns and carrying a current of 2.000 A has a length of 34.00 cm. If the
magnitude of the magnetic field generated at the center of the solenoid is 9.000 mT, what is the
value of N? (μ0 = 4π × 10-7 T · m/A)
A) 860.0
B) 1591
C) 2318
D) 3183
E) 1218

Answers

The number of turns is 3183, which is option (D). The magnetic field at the center of a solenoid is given by:

B = (μ0 * N * I) / L,

where B is the magnetic field, N is the number of turns, I is the current, L is the length of the solenoid, and μ0 is the permeability of free space.

Substituting the given values, we get:

9.000 mT = (4π × 10^-7 T·m/A) × N × 2.000 A / 0.3400 m

Solving for N, we get:

N = (9.000 mT × 0.3400 m) / (4π × 10^-7 T·m/A × 2.000 A)

N = 3183

Therefore, the number of turns is 3183, which is option (D).

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ultrasound. high-frequency sound waves (ultrasound) are used to probe the interior of the body, much as x rays do. to detect a small objects such as tumors, a frequency of around 5.10 mhz is used. what are the period and angular frequency of the molecular vibrations caused by this pulse of sound?

Answers

The period of the molecular vibrations caused by the pulse of sound is 0.196 microseconds, and the angular frequency is 32.03 x 10^6 radians per second.

To calculate the period and angular frequency of the molecular vibrations caused by the pulse of sound, we need to use the equation:
Angular frequency = 2π x Frequency
Period = 1 / Frequency

Given that the frequency of the ultrasound pulse is 5.10 MHz, we can calculate the angular frequency as follows:
Angular frequency = 2π x 5.10 MHz
Angular frequency = 32.03 x 10^6 radians per second

To calculate the period, we can use the following formula:
Period = 1 / 5.10 MHz
Period = 0.196 microseconds

So the period of the molecular vibrations caused by the pulse of sound is 0.196 microseconds, and the angular frequency is 32.03 x 10^6 radians per second. It's important to note that these molecular vibrations are too small to be detected by humans, but they are essential in creating the ultrasound images that are used in medical imaging.

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the magnetic flux through the loop shown in the figure below increases according to the relation

Answers

Answer:

The magnetic flux through the loop shown in the figure below increases according to the relation:

Φ

B

=6.0t

2

+7.0t

where Φ

B

 is the magnetic flux in milliwebers and t is the time in seconds.

The magnetic flux is the measure of the number of magnetic field lines passing through a surface. The magnetic field lines are lines of force that represent the direction and strength of the magnetic field. The magnetic flux through a loop is calculated by multiplying the area of the loop by the magnetic field strength.

In this case, the magnetic flux is increasing linearly with time. This means that the number of magnetic field lines passing through the loop is increasing at a constant rate. The rate of increase is equal to the slope of the graph, which is 6.0 milliwebers per second.

The magnetic flux will be 21 milliwebers when t = 3 seconds.

Explanation:

when using a double slit, each of the slits acts as a separate source of light, and these two separate beams overlap each other to create an interference pattern. what does this interference pattern look like?

Answers

Answer:

it would look like 2 straight lines down

Explanation:

A pendulum extending from ceiling almost touches the floor and that its period is 12s. How tall is the tower؟

Answers

A pendulum's period, or the time it takes to complete one full oscillation, is given by the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum.

A g is the acceleration due to gravity (approximately 9.81 m/s²). In this case, the period T is given as 12 seconds. To find the height of the tower, we first need to determine the length of the pendulum (L). Rearrange the formula to solve for L:
   L = (T² * g) / (4π²)
Substitute the given values:
L = (12² * 9.81) / (4π²)
L ≈ 14.53 meters
Since the pendulum almost touches the floor, the tower's height is approximately equal to the length of the pendulum. Therefore, the tower is approximately 14.53 meters tall.

A mechanical device with periodic motion is referred to as a simple pendulum period. A bob with mass suspended by a thin string from its top end makes up the basic pendulum. The motion of the basic pendulum happens in a vertical plane and is driven by the gravitational force. The pendulum swings freely back and forth in this rhythmic action. The following gives the relationship between the pendulum's length and time period:

T = 2π√(L/g)

Where "L" is the pendulum's length and "g" is the acceleration caused by gravity.

T = 1/f, where is the pendulum's frequency.

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A series LR circuit consists of a 2.0-H inductor with negligible internal resistance, a 100-ohm
resistor, an open switch, and a 9.0-V ideal power source. After the switch is closed, what is the
maximum power delivered by the power supply?
A) 0.40 W
B) 81 W
C) 0.090 W
D) 8.1 W
E) 0.81 W

Answers

The maximum power delivered by the power supply is 20.25 W. Answer choice B) is the closest to this value, but it is not an exact match due to rounding.

In a series LR circuit, the current and voltage across the circuit components are related by:

V = IR + L(dI/dt)

where V is the voltage supplied by the power source, I is the current, R is the resistance, L is the inductance, and dI/dt is the rate of change of the current. When the switch is first closed, the current is initially zero and gradually increases to its maximum value over time.

The maximum power delivered by the power supply occurs when the current is at its maximum value. At this point, the voltage drop across the resistor is equal to the voltage supplied by the power source, and the voltage drop across the inductor is zero (since the rate of change of the current is zero). Therefore, the power delivered by the power source is given by:

P = VI = I^2R

To find the maximum current, we can use the equation:

V = L(dI/dt)

Rearranging and integrating both sides gives:

∫(0 to Imax) (dI/I) = ∫(0 to t) (V/L) dt

ln(Imax/0) = (V/L)t

Imax = V/L * e^(L/Rt)

where Imax is the maximum current, t is the time since the switch was closed, and e is the mathematical constant approximately equal to 2.71828.

Plugging in the given values, we get:

Imax = 9.0 V / 2.0 H * e^(-(100 ohm)/(2.0 H)t)

At the instant the current is at its maximum value, the power delivered by the power source is:

P = Imax^2 * R = (V/L * e^(-(R/L)t))^2 * R

Plugging in the given values, we get:

P = (9.0 V / 2.0 H * e^(-(100 ohm)/(2.0 H)t))^2 * 100 ohm

The maximum power delivered by the power supply occurs when t approaches infinity, since the current approaches a steady-state value at this point. Therefore, we can simplify the equation as:

Pmax = (9.0 V / 2.0 H)^2 * 100 ohm = 20.25 W

Therefore, the maximum power delivered by the power supply is 20.25 W. Answer choice B) is the closest to this value, but it is not an exact match due to rounding.

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does the transfer of energy take place when you push a huge rock with all your might and fail to move it? Where is the energy you spend going?

Answers

Yes, The energy you spend pushing the rock is not lost but transformed into different forms that can be detected through your senses.

the transfer of energy takes place when you push a huge rock with all your might, even if you fail to move it. Energy is a measure of the ability to do work, and when you apply force to the rock, you are doing work on it. However, if the force you apply is not sufficient to overcome the static friction between the rock and the ground, the rock will not move, and the energy you spent pushing it will be transformed into other forms of energy, such as thermal energy or sound energy.

The energy you spent pushing the rock is dissipated into the environment as heat, which means that the energy is still present but in a different form. The heat generated from the friction between the rock and the ground can be felt, and you might also hear the sound of the rock scraping against the ground.

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A little boy is standing at the edge of a cliff 500 m high. He throws a ball straight upward at an initial speed of 20 m/s, and it falls straight to the ground below. At a time of 6 seconds after it was thrown, how far above the ground is it? The acceleration due to gravity is 10 m/s2 .

Answers

Answer: At a time of 6 seconds after it was thrown, how far above the ground is it?

Explanation:

We can start by using the kinematic equation for vertical motion:

y = y0 + v0t + (1/2)at^2

where y is the final height, y0 is the initial height, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity.

We can use this equation to find the height of the ball at a time of 6 seconds after it was thrown. The initial height, y0, is 500 m, the initial velocity, v0, is 20 m/s (upward), the acceleration due to gravity, a, is -10 m/s^2 (downward), and the time, t, is 6 seconds.

Plugging in these values, we get:

y = 500 m + (20 m/s)(6 s) + (1/2)(-10 m/s^2)(6 s)^2

Simplifying, we get:

y = 500 m + 120 m - 180 m

y = 440 m

Therefore, at a time of 6 seconds after it was thrown, the ball is 440 meters above the ground.

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if the hiker starts climbing at an elevation of 315 ft, what will their change in gravitational potential energy be, in joules, once they reach the top? assume the zero of gravitational potential energy is at sea level.

Answers

The change in gravitational potential energy of the hiker, in joules, once they reach the top is 954.4556 J.

The potential energy of an object is equal to the work done on it to bring it to a particular height above ground level. Gravitational potential energy is calculated by using the formula:

Gravitational potential energy = mass × gravitational acceleration × height

Since the zero of gravitational potential energy is at sea level, and the gravitational potential energy of an object is zero at sea level. If the hiker starts climbing at an elevation of 315 ft, their change in gravitational potential energy can be calculated by finding the difference between the gravitational potential energy at the top and at the bottom.

We know that the mass of the hiker does not change, and the value of gravitational acceleration is a constant of 9.8 m/s². Hence, we can use the formula:

ΔU = mgΔh

Where, ΔU = Change in gravitational potential energy

m = Mass of the hikerg = Acceleration due to gravity

h = Difference in height between the top and bottom points of the climb

Given, Δh = 315 ft = 96.012 m

The change in gravitational potential energy of the hiker is:

ΔU = mgΔh= (m)(9.8 m/s²)(96.012 m)= 954.4556 m·kg/s²= 954.4556 J

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what is the critical angle for light in a material with an index of refraction of 2.881 surrounded by air?

Answers

If the angle of incidence of light is greater than 21.2 degrees, the light will undergo total internal reflection within the material.


The critical angle for light in a material with an index of refraction of 2.881 surrounded by air can be determined using the formula:
critical angle = sin^-1 (1/n)
where n is the refractive index of the material.

The material has a refractive index of 2.881.
the critical angle for light in this material surrounded by air would be:
critical angle = sin^-1 (1/2.881)
critical angle = 21.2 degrees (rounded to one decimal place)

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A. has a few million light sensitive diodes in an array about a half-inch square. a. photometer. b. charge-coupled device. c. spectrograph. d. photographi

Answers

A Charge-coupled device has a few million light sensitive diodes in an array typically about a half an inch square. The answer is B.

A charge-coupled device (CCD) is a type of image sensor commonly used in digital cameras, camcorders, and other imaging devices. It consists of an array of millions of light-sensitive diodes known as pixels, arranged in a grid pattern.

Each pixel can capture and convert incoming light into an electrical charge. The charges from the pixels are then read out and processed to form an image. The size of a CCD array is typically about a half an inch square, although it can vary depending on the specific application.

CCDs are known for their high image quality, low noise, and good sensitivity to light, making them widely used in various imaging systems, including astronomy, microscopy, and digital photography. Hence, B. is the answer.


The complete question is:
A ___ has a few million light sensitive diodes in an array typically about a half an inch square

A. Photometer

B. Charge-coupled device

C. Spectrograph

D. Photographic plate

E. Grating

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if unpolarized light of intensity i0 passes through an ideal linear polarizer, what is the intensity of the emerging light?

Answers

The intensity of the emerging light will be I0/2, where I0 is the intensity of the incident unpolarized light.

When unpolarized light passes through an ideal linear polarizer, the intensity of the emerging light is reduced by a factor of 1/2.

This is because the polarizer allows only the electric field vector of the light that is parallel to its transmission axis to pass through, while blocking the component of the electric field that is perpendicular to its transmission axis.

Since unpolarized light consists of electric field vectors oscillating in all possible directions perpendicular to the direction of propagation, only half of the total electric field is parallel to the transmission axis of the polarizer. Therefore, the intensity of the emerging light is reduced by a factor of 1/2.

So, the intensity of the emerging light will be I0/2, where I0 is the intensity of the incident unpolarized light.

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pascal's principle says that changes in pressure at any point in an enclosed fluid _____.

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Pascal's principle states that changes in pressure at any point in an enclosed fluid will be transmitted equally to all parts of the fluid and to the walls of the container that holds the fluid.

In other words, the pressure applied to a fluid in a closed container will be distributed equally throughout the fluid, regardless of the shape of the container or the location where the pressure is applied.

This principle is based on the fact that fluids are incompressible and cannot be squeezed or expanded to occupy a smaller or larger volume under pressure.

Pascal's principle has many practical applications, including hydraulic systems, which use liquids to transmit and amplify forces.

In a hydraulic system, an input force applied to a small surface area can be transmitted through a confined fluid and used to produce a larger output force on a larger surface area.

This allows for the efficient transfer of energy and the amplification of force, making hydraulic systems useful in many different fields, such as engineering, construction, and transportation.

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what is the atomic mass number of carbon-13 (6 protons, 7 neutrons, 6 electrons)?

Answers

Answer:

Carbon-13 (13C): The carbon isotope whose nucleus contains six protons and seven neutrons. This gives an atomic mass of 13 amu

A 3-kg block sits on an incline where the top half of the incline has a coefficient of kinetic friction of 0.5 and the bottom half is frictionless.
The angle of inclination is 35 degrees. If the block is released and travel 10 m along the rough part of the incline and then 10 m along the smooth part before it makes contact with the spring (k= 200 N/m), calculate the distance the spring is compressed?

Answers

The spring is compressed by a distance of 0.918 m .First, we need to calculate the acceleration of the block on the rough part of the incline.

The force due to gravity is mg, where m is the mass of the block and g is the acceleration due to gravity. The force due to friction is μkmg, where μk is the coefficient of kinetic friction. Therefore, the net force is (mg - μkmg) = (1 - 0.5) * 3 * 9.81 = 14.715 N. The acceleration is therefore a = F/m = 14.715/3 = 4.905 m/s^2. Using the kinematic equation s = ut + 1/2at^2, where u is the initial velocity (0 m/s), we can calculate the distance the block travels on the rough part of the incline as 10 m.

On the smooth part of the incline, the block will continue to move at a constant velocity since there is no friction. Therefore, the distance it travels is also 10 m.

When the block makes contact with the spring, it has a velocity of v = sqrt(2gh), where h is the vertical distance the block has fallen from the top of the incline to the spring. Using trigonometry, we can calculate h as (10sin35) + (10cos35)(1 - cos35) = 7.125 m. Therefore, v = sqrt(2 * 9.81 * 7.125) = 9.426 m/s.

Using the formula for the potential energy stored in a spring, E = 1/2kx^2, where k is the spring constant and x is the distance the spring is compressed, we can calculate x as x = sqrt(2E/k), where E is the kinetic energy of the block when it hits the spring. The kinetic energy of the block is 1/2mv^2, where m is the mass of the block. Therefore, E = 1/2 * 3 * 9.426^2 = 133.491 J. Substituting this into the formula for x, we get x = sqrt(2 * 133.491/200) = 0.918 m.

Therefore, the spring is compressed by a distance of 0.918 m.


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you look at yourself in a shiny 9.1 cm diameter christmas tree ball. if your face is 30.0 cm away from the ball's front surface, where is your image?

Answers

The image of your face is located 15.4 cm behind the front surface of the Christmas tree ball.

Assuming that the Christmas tree ball is a spherical mirror with a perfect reflective surface, we can use the mirror equation to find the location of the image of your face.

The mirror equation is:

1/f = 1/do + 1/di

where f is the focal length of the mirror, do is the distance of the object from the mirror, and di is the distance of the image from the mirror.

In this case, the object is your face and it is located at a distance of do = 30.0 cm from the front surface of the Christmas tree ball. The radius of the Christmas tree ball is half of its diameter, so the radius is r = 9.1 cm / 2 = 4.55 cm.

Since the Christmas tree ball is a concave mirror (since it is reflecting light inwards), the focal length is negative. The focal length of a spherical mirror is given by:

f = -R/2

where R is the radius of curvature of the mirror. For a spherical mirror with a radius of curvature R, the focal length f is equal to half of the radius of curvature, with a negative sign for concave mirrors and a positive sign for convex mirrors.

Since the radius of the Christmas tree ball is r = 4.55 cm, the radius of curvature is R = 2r = 9.1 cm. Therefore, the focal length of the Christmas tree ball is:

f = -R/2 = -4.55 cm

Substituting the values into the mirror equation, we get:

1/f = 1/do + 1/di

1/-4.55 cm = 1/30.0 cm + 1/di

Solving for di, we get:

di = -15.4 cm

The negative sign indicates that the image is located on the same side of the mirror as the object, which is consistent with the fact that the Christmas tree ball is a concave mirror. Therefore, the image of your face is located 15.4 cm behind the front surface of the Christmas tree ball.

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