A police officer recorded the speeds of 100 cars in a 50-mile-per-hour zone. The results are in the box plot shown. How many cars were going between 40 and 48 miles per hour?32 20 2516

Answer:

Explanation: the kinetic energy k=1/2mv^2
K=8m
using formula
8=1/2mv^^2
v^2=16
v=4m/s

The sporting event at which you would most likely see balls traveling at over 180 mph would be a Formula One race.

Formula One, also known as F1, is the highest class of single-seater auto racing sanctioned by the Fédération Internationale de l'Automobile (FIA). Races take place on purpose-built circuits, and they feature open-wheel, open-cockpit cars. These cars are purpose-built, with the sole purpose of racing in the Formula One world championship. The cars are designed with aerodynamics in mind, featuring wings, diffusers and aero devices to help them achieve maximum downforce and speed. Formula One drivers need to be in peak physical condition, as the cars are very demanding to drive. F1 is considered the pinnacle of motorsport, with some of the world's best drivers competing in it.

Formula One racing is an international auto racing sport where cars race around a track at incredibly high speeds. These cars can reach speeds of around 200 mph, and the balls that are used to help the cars navigate the track (such as the tires) can reach speeds of over 180 mph.

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From the given position -time graph it is clear that, Amiya covers a distance of 40 meters within 12 seconds.

A position - time graph is used to determine the change in position with respect to the time. We can calculate the average speed of the object from the position -time graph.

Speed is the measure of distance covered within unit time. Hence, it is the ratio of change in position to the change in time. Speed has the unit of m/s .It can also defined as the rate of displacement of an object.

From the given plot, it is clear that the Amiya is 40 meters far after 12 seconds run. After that she stops and the position gets constant. Hence, option A is correct.

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The gauge pressure of the water at the pump 10.96 Pa.

Gauge pressure is a type of pressure measurement that is relative to atmospheric pressure. It is calculated by taking the absolute pressure of a system and subtracting the atmospheric pressure from it. Gauge pressure is often used to measure the pressure of a closed system, like a tire or an air conditioning unit, because it is easier to measure than absolute pressure.

The pressure at the pump is equal to the difference in height between the pump and the nozzle multiplied by the acceleration due to gravity (9.8 m/s2) plus the kinetic energy of the water in the hose. The kinetic energy is equal to the velocity of the water squared, divided by two.

So the pressure at the pump is:
Pump Pressure = (1.00 m * 9.8 m/s2) + (0.400 m/s)2 / 2
Pump Pressure = 9.8 + 0.160
Pump Pressure = 10.96 Pa

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The time T is identical to 0.50 seconds since one whole wave completes in 0.50 seconds. F = 1/D = 1/0.5 = 2 Hz, where T = 0.5 Frequency.

A wave, according to Webster's dictionary, is a perturbation or variation that gradually transfers energy from one place to another inside a medium. It can be a multiple and complex or a change in pressure, magnetic or electrical strength, electric potential, or heat.

Water moves in a circular pattern as a result of energy traveling through it, creating waves. Water does not, however, literally move in waves. Without obstruction, waves can potentially flow across the ocean, transmitting energy rather than water.

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An airplane whose speed in still air is 760 km/h can travel 2000 km(200) * (760 )=3800w . The speed of the wind=40.

The pace at which a distance changes over time is referred to as speed. It has a dimension of time-distance. As a result, the fundamental unit of time and all basic unit of travel are combined to form the Rectangular cross - section of speed. Thus, the metre per second (m/s) is the Input to the system of speed.

We can define our concepts first. Speed (s) is defined as the difference traveled per unit of time (d/t). Speed and furthermore a direction equals velocity.

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Except in cases where the air is supersaturated (the relative humidity is greater than 100%), smaller cloud droplets will evaporate fast.

Air that is saturated with regard to a flat surface is unsaturated with respect to a curved cloud droplet due to the curvature effect.

Even if embryonic droplets of pure water as large as 0.01 micrometers in radius formed by the chance collisions of water molecules, they would be well below the critical radius necessary for survival in air that is just a few percent supersaturated because the supersaturations that develop in natural clouds due to the adiabatic ascent of air rarely exceed a few percent.

According to the theory's premise, salt particles and other hygroscopic aerosols that become deliquescent (i.e., absorb water vapor and dissolve into aqueous solution droplets) under subsaturation are what create cloud droplets. For instance, sodium chloride particles deliquescence point is 75% RH.

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This force is directly equal to the product of a charges and inversely linked to a square of the distance between the charges.

It would be possible to treble the force by doubling both charges.The force would be four times lower if the distance were doubled.These two changes together would have no effect on the force; it would remain at 0.080 N.

Force between two objects decreases by one-fourth when their distance is doubled.When an object's distance is tripled, the pressure between them is reduced by one-ninth.

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When she wears +2.0 D reading glasses, her near point is −0.57m and −0.5m is her far point when she wears glasses.

Within the eye's accommodation range, the near point in visual perception is the distance at which an object can be placed while still forming a focused image on the retina. The far point serves as the eye's other accommodation range limit.

A normal eye is thought to have a near point at 11 cm (4.3 in) or so for a person who is thirty years old.

Age has a significant impact on the near point. An individual with presbyopia or hyperopia would have a farther near point than usual.

Diopters, which represent the inverse of distance, are sometimes used to express near point (see Presbyopia Mechanism).

Part A

[tex]$ P = \frac{1}{f} = +2 D[/tex]

v given = 0.80 m

Using

1/v - 1/u = 1/f

1/0.80 - 1/u = 2D

1/0.80 - 1/u = 1/2

u = −0.57

Part B

V = ∞

f = 1/2 = 0.5

1/∞ - 1/u = 1/0.5

u = −0.5

Thus, When she wears +2.0 D reading glasses, her near point is −0.57m and −0.5m is her far point when she wears glasses.

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The electric field E? (r?) inside the sphere for r< a is given by the following expression:

Electric field is an area in which electric forces act. It is a physical quantity that is used to describe the force that is exerted on a charged particle by an electric field. Electric fields are created when electric charges are placed in a space. The electric field is a vector field, meaning it has both a magnitude and a direction. It is measured in volts per meter (V/m). Electric fields can be used to describe the behavior of electric charges, and to calculate the force between them.

E? (r?) = ?0 ? ? r? / (4?0 r3)

Where ?0 (Greek letter epsilon naught) is the permittivity of free space, ? (Greek letter rho) is the volume charge density, and r? is the position vector. This expression is derived from the Gauss' Law which states that the electric flux or the electric field emitted from a closed surface is equal to the charge contained in the closed surface.

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The electric field E (r ) inside the sphere (for r< a) in terms of the position vector r is ( ρ / 3ε_0 ) * r

An electric field is a force field created by a charged object that exerts a force on other charged objects within the field. The strength of the electric field is determined by the magnitude of the charge creating the field and the distance from the charge. Electric fields can be represented by lines of force, with the direction of the field indicated by the direction of the lines. Electric fields can be used to explain a wide range of physical phenomena, including the behavior of electric charges and the behavior of electric circuits.

The electric field inside an insulator sphere with a uniform volume charge density can be found using Gauss' law. Gauss' law states that the electric flux through a closed surface is proportional to the charge enclosed within the surface.

For an insulating sphere, the electric field is zero everywhere outside the sphere. Therefore, the electric field inside the sphere is given by:

E = (Q / (4πε₀ a³)) ₓ r

where Q is the total charge enclosed within the sphere, a is the radius of the sphere, and r is the position vector of a point inside the sphere.

Given the volume charge density (Greek letter rho), we can calculate the total charge within the sphere as:

Q = (4/3)π ₓ a³ ₓ ρ

Substituting this value of Q into the expression for the electric field, we get:

E = ( (4/3)π ₓ a^3 ₓ ρ / (4πε₀ a³)) ₓ r = ( ρ / 3ε₀ ) ₓ r

So the electric field inside the sphere (for r < a) in terms of the position vector r, the volume charge density ρ, and the electric constant ε₀ is:

E = ( ρ / 3ε₀ ) * r

Note that in this case, the electric field is radially outward, as the charge density is positive.

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"The proper way to name the range of cells located in column A row 3 through column C row 7 is A3:C7."

Each worksheet is composed of countless cells, which are rectangular shapes. A cell is the place where a row and a column meet, or the intersection of a row and a column.

A, B, and C are used to identify columns, while digits are used to identify rows (1, 2, 3). Based on its column and row, each cell has a unique name or cell address. The cell address in the example below is C5, because the chosen cell intersects column C and row 5.

Additionally, it is possible to select many cells at once. A cell range is a collection of cells. You will refer to a cell range using the cell addresses of the first and last cells in the range, separated by a colon, rather than a single cell address. Cells A1, A2, A3, A4, and A5 would be included in the range represented by the letters A1:A5.

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Charges here on upper right and lower left generate a force that is left-pointing and points toward the lower left.

The definition of the word "force" is obvious. At this point, it is perfectly acceptable to refer to a force as a push or a pull. An object doesn't "have a force in it" or "contain a force." The idea of a force encompasses both living and semi things.

The linear sum of all forces acting on an object is known as the net force. As a result of the fact that such a force is a vector and that two forces with identical magnitudes and opposing directions cancel each other out, the net torque is the total of all forces, or put another way.

F1 =F2

=2* k* q1* q2/r 2

=2* 9.0×10∧ 9* 1.0×10∧-9^* 2.0×10^∧-9/(7.07×10^∧-3

=7.2×10∧-4N

horizontal components,

F =2^* F1* cos⁡(45)

=2* 7.2×10^∧-5^* cos⁡(45)

=1.02×10^∧-3 N

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Becomes positively charged. When a negatively charged rod is brought near an uncharged metal ball, electrons from the rod will be attracted to the ball, giving it a positive charge.

An uncharged ball is an object that does not contain any electrical charge. This type of ball is often made of rubber, plastic, or metal, and is used in a variety of applications such as games and laboratory experiments. An uncharged ball is also known as a neutral object, which means that it has no positive or negative electrical charge. This type of ball can be used in experiments to analyze how electric fields interact with charged particles and how electric fields can affect the motion of an object. For example, when two charged balls are placed near each other, they will repel each other due to the electric fields they create. However, when two uncharged balls are placed near each other, they will not be affected by the electric fields.

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She should provide the amount of rotate in the Structure dialogue box in accordance with the provided statement.

Horizontal refers to everything that is perpendicular to the horizon. Anything that forms a 90-degree connection (lateral relationship) well with horizontal or the zenith is referred to as vertical because it's the opposite of the horizontal. The line that spans as left to right is therefore considered to be horizontal.

A line graph is one that spans the page from left to right. A horizontal line in geometry is the one that crosses the page from left to right. In the notion that white lines are parallel toward the horizon, it stems from the term "horizon." Horizontally oriented.

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If the radius of the circle is 3 meters, the minimum velocity required to maintain a uniform vertical circle would be approximately 5.4 m/s.

To maintain a uniform vertical circle, the child would need to have a minimum velocity equal to the square root of the gravitational acceleration multiplied by the radius of the circle. The equation is:

v = √(g × r)

where v is the minimum velocity, g is the gravitational acceleration on earth's surface (approximately 9.8 m/s²), and r is the radius of the circle (3 meters).

v = √(9.8 × 3)

v = √29.4

v = 5.4 m/s

Therefore the minimum velocity required to maintain a uniform vertical circle is 5.4 m/s

It is important to note that this is the minimum velocity required to maintain a uniform circle and additional velocity would be required to counteract air resistance and other external forces.

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Your question seems incomplete, but I suppose the complete question was:

"If the child could swing around in a vertical circle, what minimum velocity, in [m/s], would be required at the top of its motion to maintain a uniform circle if the radius of the circle is 3 meters?

Answer:

An antinode should be motionless by definition.

Vav = 0 m / n sec = 0 m/s

To calculate the potential difference between the origin and the point on the x-axis at x=80 cm, we can use Gauss's Law. the potential difference between the origin and the point x=80 cm is 1.74 x 10^-4 V or 1.74 microvolts

the difference in potential between two points that symbolizes the labor or energy expended during the transfer of a unit amount of electricity from one spot to another.

The flux through the top face is:

Flux_top = (50 nC/m^2) * (pi*(80 cm)^2) / (8.854 x 10^-12 C^2/Nm^2) = 1.45 x 10^-5 N

The flux through the bottom face is:

Flux_bottom = (25 nC/m^2) * (pi*(80 cm)^2) / (8.854 x 10^-12 C^2/Nm^2) = 7.24 x 10^-6 N

Since the electric field is perpendicular to the planes, the net flux is:

Flux = Flux_top - Flux_bottom = 1.45 x 10^-5 N - 7.24 x 10^-6 N = 6.76 x 10^-6 N

The electric field is then:

E = Flux / (pi*(80 cm)^2) = 6.76 x 10^-6 N / (pi*(80 cm)^2) = 2.17 x 10^-6 N/m^2

To find the potential difference, we need to integrate the electric field along the x-axis from x=0 to x=80 cm.

V = Integral(E dx) = Integral(2.17 x 10^-6 N/m^2 dx) = 2.17 x 10^-6 N/m^2 * 80 cm = 1.74 x 10^-4 V

V = 1.74 x 10^-4 V or 1.74 microvolts

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One of the top doctors and scientists of her era, Dr. Jane C. Wright examined hundreds of drugs for their ability to eradicate human tumors and investigated how these drugs could be tested in cell culture. Her body of work revolutionized both cancer research and medical practice.

Changes (mutations) to the DNA within cells are what lead to cancer. A cell's DNA is organized into a large number of distinct genes, each of which carries a set of instructions directing the cell's various functions as well as its growth and division.

Drugs are used in chemotherapy to kill cancer cells. radiation treatment High-powered energy beams, like X-rays or protons, are used in radiation therapy to kill cancer cells. Radiation therapy devices can either be placed inside or outside of your body (external beam radiation) (brachytherapy)

Her work was simply about how to eradicate cancer.

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Answer:

1.6 m/s

Explanation:

Avg. Speed =  total distance/total time

d1 = speed x time = (2 m/s)(30 s) = 60 m

d2 = (1.5 m/s)(120 s) = 180 m

d-total = 60 m + 180 m = 240 m

t-total = 30 s + 120 s = 150 s

Avg speed = 240 m / 150 s = 1.6 m/s

If a powerful motorcycle can reach 13.57m/s² (58 mi/h) from rest in under 1.90 seconds, its average acceleration is 4.20 m/s2, and it will travel 24.51 m.

The rate at which velocity varies is termed acceleration. Acceleration usually signifies a shift in speed, but not usually. An item that follows a circular course while maintaining a constant speed is still moving forward as the direction of its motion is fluctuating.

given,

initial speed,u = 0 m/s

final speed,v = 25.8 m/s

time, t= 1.90 s

a) acceleration,

a =  v-u/t

a = 25.8-0/1.90

a = 13.57 m/s²

(b) distance to travel in that time

using equation of motion

v² = u² + 2 as

  25.8² = 0² + 2 x 13.57 x s

      13.57 s = 332.7

         s = 24.51 m

the motorcycle will travel 24.51 m

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The telescope. The telescope is one of humankind's most important inventions. The earliest known telescope arose in 1608 in the Netherlands. Galileo invented it to prove that they were more than one planets.

Galileo Galilei was an Italian astronomer, physicist and engineer. He is popularly known as the "father of observational astronomy", "father of modern physics", "father of the scientific method", and the "father of modern science". He used to work by using the telescope for scientific observations of celestial objects.

The rings of Saturn are visible in even the smallest telescope at 25x. A good 3-inch scope at 50x can show them as a separate structure detached on all sides from the ball of the planet.

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The bulb should be placed on parabolic focus to ensure a perfect beam of light

The point on a parabola known as the parabolic focus is where all parallel light rays are reflected at a single point or when all rays travelling through the focus are reflected parallel to the axis of symmetry. The focus of a parabolic reflector is the location at which the reflected light congregates.

The parabola point is equally spaced from the directrix and the vertex, to use mathematical terminology. An equation for a parabola is presented in standard form. Therefore, a parabola lying sideways and facing right with an extremum of will serve as the visual representation in the given example in Cartesian (2; -3). Given that 13 is the focal parameter, the focus will be at (2+0.5p; -3) or (8,5; -3).

Complete Question:

Gabriella is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by (y+3)^2=26(x-2) where x and y are measured in inches. Where should she place the bulb to ensure a perfect beam of light?

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a) The time taken to make the first revolution is calculated to be 0.63 s.

b) The angular acceleration in rad/s² is calculated to be 31 rad/s².

Given that,  

Time t = 0.81 s

Angular displacement in the time t is Δθ = 4 π

Initial angular speed ω₀ = 0 rad/s

The disk moves with a circular motion, so to find the time it takes to make a complete revolution we must find the angular acceleration α,

Δθ = ω₀ t + α t²/2

As ω₀ = 0 rad/s, Δθ = α t²/2

On re-arranging, we have, α = 2 Δθ/t² = (2 × 4π)/0.81² = 31 rad/s²

a) The time it takes to make its first revolution is,

Δθ = α t²/2

2 π = α t²/2

t² = 4 π/α

t = √(4 π/α) = 0.63 s

b) The angular acceleration in rad/s² is 31 rad/s².

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Answer:

Only (i) is true.

I (solid sphere) = 2/5 M R^2

I (spherical shell) = 2/3 M R^2   (hollow)

The hollow sphere has the greater momentum

By applying the time period formula, it is possible to calculate that 0.389 kg of mass must be added to the item in order to shift the era to 2.00 s.

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the force exerted on it. The change caused by a force applied is smaller the more mass a body has.

A: A three-dimensional object's volume is the area it takes up, and it is expressed in cubic units. Cm3 and in3 are two such examples of cubic units. On the other, mass The hand is a unit of measurement for volume in an object. The weight of an object is a common way to determine mass.

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Since you face north and look down at the compass in your hands. The north end of the compass needle would be pointing in front of you if you are facing north and looking down at the compass in your hands.

A compass is a navigation tool that uses a magnetized needle to indicate the direction of magnetic north. The needle is suspended within a casing, which typically has a rotating bezel or housing marked with cardinal directions such as north, south, east, and west. The north end of the needle is typically painted or labeled differently than the south end to help identify it.

Therefore, When you face north and look down at the compass in your hands, the north end of the needle will point in the direction of magnetic north. Since you are facing north, the north end of the needle will point in front of you, towards the direction you are facing. This is because the needle aligns itself with the Earth's magnetic field and points towards the magnetic north pole.

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a) The momentum after collision of the ball Q is 12.8 m/s

b) The impulse on the ball P is 0.448 Ns.

We know that the momentum of the object can be obtained as the product of the mass and the velocity of the object. In this case, we can see that we have; Ball P of mass of 0,16kg moving east at a speed of 10m.s collide head on with another ball Q of mass 0,2kg moving west at a speed of 15m.s.

Given that;

Momentum before collision = Momentum after collision

(0.16 * 10) + (0.2 * 15) = (0.16 + 0.2) v

V = velocity after Collison

v = 1.6 + 3/0.36

v = 12.8 m/s

What is the impulse;

Impulse = Mv - Mu

Impulse = 0.16(12.8 - 10)

= 0.448 Ns

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True that a three-dimensional isotropic harmonic oscillator with Hamiltonian is an instance of quantum mechanical systems where a particle is exposed to a spherically-symmetric potential.

The defining matrix referring of U has a component called the N-dimensional isotropic harmonic oscillator (N). The energy is confined, similar to the one-dimensional situation. Using the analogy of N separate one-dimensional oscillators, we would anticipate that the ground state energy is N times the one-dimensional ground energy.

The Hamiltonian is given the form H = p2 2m + m2 x2 2, resulting in the Hamiltonian operator, H = p2 2m + m2 x2 2. thus gives the Hamiltonian operator, H = p2 2m + m2 x2 2, which is one of the most real challenges in quantum mechanics. 

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Image separation approximately -7.75 cm. The above mirror's focal length measures -10.33 cm.

The focal length of your camera seems to be the range (in millimeters) between its point of convergence and the sensor or film used to capture the image. How much of a scene that camera can record depends on the telephoto lens of a films or internet camera lens.

The maximum aperture of the lens, which is often given in millimeters, is really the length between the perspective and the sensor when the image is in focus. The minimal and maximum lens lengths of telephoto lenses are specified, for instance, 18-55 mm.

magnification = image / object

= - distance of image / distance of object

m = 1/4

= -di/31

di = -7.75 cm

image distance = 7.75 cm

lens equation,

1/f = 1/v + 1/u

1/f = - 1/7.75 + 1/31

f = -10.33 cm

focal length = 10.33 cm

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1) At exactly 12:00 noon, the oscillations will the pendulum have completed 2165 oscillations.

2) Its amplitude at noon is 88.3m.

The process of any quantity or measure repeatedly varying around its equilibrium value in time is referred to as oscillation. Another way to describe oscillation is as a periodic change in a substance's value between two values or around its midpoint.

1)The pendulum's period is the length of time it takes for one full revolution to occur.

Keep in mind that a pendulum's period is denoted by the following:

T = 2pi√(L/g)

Here, we know that  L = 11.4m

The pendulum's period will then be:

T = 2×3.14×√(11.4m/9.8m/s²) = 6.28×√1.14

T = 6.28×1.06 = 6.65s

So one complete oscillation takes 6.65seconds.

We are aware that the pendulum swings at 8:00 am.

Four hours after the pendulum begins to swing, or 12:00 noon, is the time we're interested in.

So, we're interested in finding out how many full oscillations occur in a period of 4 hours.

It takes 6.65 seconds for each oscillation.

The product of the total time (4 hours) and the period will yield the total number of oscillations.

First, since 1 hour equals 3600 seconds, we must write both of these in the same units.

then,

4 hours = 4(3600 seconds) = 14,400 s

There were a total of: oscillations during that period,

N = 14,400s/6.65s = 2165.41

N = 2165

The pendulum does 2165 oscillations between 8:00 am and 12:00 noon.

2) Amplitude x(t) = A exp (-bt/2m)

x(t) = 1.7 exp (0.010(4(3600/1)))/2(110)

x(t) = 0883(10⁻²)/1

x(t) = 88.3m.

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