A police radar's effective range is 0.90 km , and your radar detector's range is 1.9 km . You're going 110 km/h in a 70 km/h zone when the radar detector beeps. At what rate must you negatively accelerate to avoid a speeding ticket?

Answers

Answer 1

Negative acceleration of 0.2 m/s^2 is needed to avoid a speeding ticket.

Negative acceleration occurs when a force causes a body's velocity to decrease. Positive acceleration occurs when the speed of something rises.

The acceleration of a slowing object is in the direction opposite from the velocity. As a result, this item is said to have negative acceleration.

Given:

Initial velocity, u = 110km/h

Final velocity, v = 70km/h

Police radar's effective range, S1 = 0.90km

Radar detector's range, S2 = 1.9km

To find:

Negative acceleration, a = ?

Formula:

v^2 = u^2 + 2aS

Calculation:

a = (v^2 – u^2) / 2(S1 - S2)

a = 70^2 – 110^2/ 2 x (0.9 – 1.9)

a = [(4900 – 12100) / (2 x -1)] / 3600^2

a = 0.2 m/s^2

Result:

0.2m/s^2 negative acceleration is required to avoid a speeding ticket.

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Related Questions

an extension cord 20m long uses no. 12 gauge copper wire (cross section area 0.033 cm ^2 resistivity 1.7×10^-8 ohms - m

Answers

If an extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, the resistance of the extension chord would be 0.1030 Ohm.

What is resistance?

Resistance is the obstruction of electrons in an electrically conducting material.

The mathematical relation for variation in resistance with length is given by

R = ρ*L/A

As given in the problem an extension cord 20 m long uses no. 12 gauge copper wire cross-section of  area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, then we have to find the resistance of the wire,

Resistance of the wire =  1.7×10⁻⁸ ×20/0.033 ×10⁻⁴

                                     =0.1030 Ohm

Thus, the resistance of the extension chord would be 0.1030 Ohm.

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The question is incomplete the complete question is,

An extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, then find the resistance of the wire?

A vector has an x component of -25.5 units and a y component of 36.6 units. Find the magnitude and direction of this vector.

Answers

the magnitude and direction of this vector is cos −1√ (−5/ 89)

Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

A constant quantity's magnitude is a numerical value for the quantity expressed in terms of a unit of measurement. For instance, the real number 2000 is the magnitude of the quantity 2 kilometers in the unit-of-measure meter.

Magnitude = (25) 2 + (40) 2 =5√89

Angle with the x-axis equals tan√ 1(y/x).

=tan −1 √ (40/−25)

=tan −1√ (−8/5)

=cos −1√ (−5/ 5 √2+6/2)

=cos −1√ (−5/ 89)

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Which term is defined as a guess informed by observations?
O theory
O law
O principle
O hypothesis

Answers

Hi !

Answer:

Which term is defined as a guess informed by observations?

O hypothesis

What are the internal resistance and voltage rating of a 420 Watt automatic washing machine that draws 1.75 Ampere?

Answers

The internal resistance of the washing machine is 137.14 Ω.

What is internal resistance?

Internal resistance is the inherent resistance of a conductor.

To calculate the internal resistance of the washing machine, we use the formula below.

Formula:

P = I²R................... Equation 1

Where:

P = Power of the washing machineI = CurrentR = Internal  Resistance of the washing machine.

Make R the subject of the equation

R = P/I²................ Equation 2

From the question,

Given:

I = 420 WR = 1.75  A

Substitute the these values into equation 2

R = 420/1.75²R = 137.14 Ω

Hence, the internal resistance of the washing machine is 137.14 Ω.

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The students in Mrs. Mangione's class attempt to guess the number of marbles in a jar to earn 2 extra credit points on their next exam. Suppose there are 1206 marbles in a jar and a student makes a guess of m marbles. Which expression represents the difference between the student's guess and the actual number of marbles.

Answers

The formula m-1206 represents the discrepancy between the student's estimation and the actual number of marbles.

The student guesses that there are m marbles given that there are 1206 marbles in the jar.

The term that best captures the discrepancy between the student's guess and the actual number of marbles must be found.

Expressions are made up of a combination of numerical values, symbols, fractions, coefficients, and other elements that lack the equals sign.

There are 1206 marbles in total.

Guessed number of marbles by the student-m

The phrase that illustrates the distinction between a student's educated guess and

The expression that shows the difference between the student's guess and the actual number of marbles is m-1206.

Hence the expression which reflects the difference between the student's guess and the actual number of marbles is m-1206.

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In school, Jarrett learned that salt lowers the freezing point of water. He wants to test this in a home experiment. He combines 1.0 grams of salt and 500 milliliters of water in a container. In an identical container, he pours 500 milliliters of water and does not add salt to it.

What should Jarrett do next?
A.
Place the salt water in a freezer and the pure water in a refrigerator.
B.
Mix the two samples of water together in a 1.0-liter container, and bring them to a boil on a stove.
C.
Place both containers in a freezer, and record the temperatures at which they begin to freeze.
D.
Place the pure water in a freezer and the salt water in a refrigerator.

Answers

Answer:

I think it's C but I'm not 100% sure

Questions:
1. Clara drives 250 km West to play a gig in Colombia City. After the gig he drives 450 km
east to jam with some musicians in Columbia. What distance did he cover? What was his
displacement?

Answers

Answer:

700km

Explanation:

going was 250km and leaving was 450

250+450=700

If you are given values for Δx, v, and Δt, which kinematic equation could be used to find v0?​

V = v0 + aΔt
Δx= (v + v0/ 2) Δt
v^2 = v0^2 2aΔx
Δx = v0Δt + 1/2 a (Δt)^2

Answers

The kinematics equation to determine v₀ is  Δx = (v + v₀/2) Δt; option B

What are kinematic equations?

Kinematic equations are equations which describe the motion of moving bodies.

Kinematic equations are also known as equations of motion.

The equations of motion are given below:

v = u + ats = (v + u/2) * tv² = u² + 2ass = ut + ¹/₂at²

where;

v is final velocity = vu is initial velocity = v₀s is distance = Δxa is accelerationt is time = Δt

Given that the values for the following are given;  Δx, v, and Δt, the equation to determine v₀ will be Δx = (v + v₀/2) Δt

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A 5kg block is resting on the table. Find the normal force acting on the block.

49 N, up
49 N
5 kg, up
49 N, down

Answers

The normal force acting on the block is 49 N in upward direction

It is given that

mass of block is 5kg

And we have to find the Normal force on block

The force surfaces apply to stop solid objects from passing through one another is known as the normal force.

A contact force is a normal force. A normal force cannot be applied between two surfaces that are not in contact.

Since, block is at rest and no other force is acting on it so only force acting on it is by the table and it is in upward direction

Force = mg = 5 x 9.8 = 49 N in upward direction

Hence, normal force acting on block is 49 N in upward direction

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A pet store surveyed 625 people to see how many own a bird, how many own a dog, and how many own a cat.
The Venn diagram below shows the results. (Each number gives the number of people who fall into that Venn diagram category.)
All people in the survey-
Own a
bird
Own a
dog
115
103
49
138
61
33
34
Own a
cat
92
(a) How many of the people own exactly two of the three types of animals?
people
(b) How many of the people don't own a dog?
people
(c) How many of the people own neither a cat nor a bird, but do own a dog?
people.

Answers

The people who own all the three animals are 33 , (b) People who don't own a dog are 244 and (c) People who neither own a cat nor a bird but own a dog are 34 in number.

What is a Venn diagram?

A Venn diagram is a representation of data in terms of figure. Where each circle represents a set of data, intersection of two or more circles shows that there is a common entity in both the sets.

What is a universal set in Venn diagram?

A universal set contains all the possible elements. In Venn diagram a universal set is represented by a rectangle.

Given:

Total number of the people surveyed = 625

People who one a cat = 115

People who own a bird = 103

People who own a dog = 34

1) To find the number of people who own all the three animals we will have to find the intersection of C, B and D.

Where,

C represents set of cat

B represents set of bird

D represents set of dog

// Represents intersection

:: Represents union

From the given data

C//B//D = 33

i.e. people who own all the three animals = 33

2) People who don't own a dog.

Now carefully look at the given diagram you will notice:

34 own D only

138 own D and C

92 own D and B

33 own all the three

Now to find who doesn't own a dog we will find who owns a dog and then minus that from total people who owns animals.

Total people who own an animal= (115+103+34+138+61+92-2×33)

Total people who own an animal = 475

Now people who own a dog = 34+138+92-33

People who own a dog = 231

People who don't own a dog = 475-231

People who don't own a dog = 244

3) People who neither own a cat nor a bird but own a dog = 34

Therefore, the people who own all the three animals are 33 , People who don't own a dog are 244 and People who neither own a cat nor a bird but own a dog are 34 in number.

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How many liters are in 10 U.S. gallons?
1 gallon
3.79 liters
OR
3.79 liters
1 gallon

Answers

Answer:

37.85 Liters in 10 US gallons

Explanation:

if asking for volume: volume = 3.785liters

A student performed a sphere drop experiment. The sphere was dropped from 1.50 m above the ground and the sphere has
a mass of 0.875 kg. Free fall times for the student's experiments are below.
a. Before the student calculates the acceleration due to gravity from the data, are there any trials that should be thrown
out? Justify your choice.

Answers

The experimental value of the expression due to gravity through the experiment will come out to be 7.8 u, the error in the value has Accord because of air friction.

What is Newton's law of motion?

Newton gave three laws of motion which can be utilised to find the velocity, acceleration and displacement of a body. These laws are only applicable for constant acceleration.

What is free fall?

When a body falls freely under only the force of gravitation due to the earth and no other force act on the body is known as free fall.

Given:

Mass of the sphere is 0.875 kg

Height of the free fall is 1.5 metre

Experiments are conducted in the following manner:

First the bob will be released and from the point that it is being released we will measure the distance using the inch tape we will also calculate the time it takes for the bob to hit the ground.Using the speedometer will measure the final velocity before it is  the ground.Now using Newton's first law of motion we can derive the acceleration due to gravity we know the final velocity using the speedometer the distance it has covered and the time it has taken to complete that distance.

Using Newton's first law of motion

i.e. v = u + a × t  

Where,

u is initial velocity

v is final velocity

a is acceleration due to gravity

t is time taken to cover distance

From the data given v = 15.6 m/s

t is 2 seconds

Substituting value in Newton's first law of motion we get

Value of acceleration due to the gravity = 7.8u

Therefore, The experimental value of the expression due to gravity through the experiment will come out to be 7.8 u , the error in the value has Accord because of air friction.

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An electric field of 8.5x105 V/m is desired between two parallel
plates, each of area 45 cm7 and separated by 2.45mm of air. What
charge must be on each plate?

Answers

The charge that must be on each plate is 3.53 x 10⁻⁸ C.

Electric field between two parallel plates

The electric field between two parallel plates is given as;

C = εA/d

C = Q/V

V = Ed

C = Q/Ed

Q/Ed = εA/d

Q/E = εA

Q = εEA

where;

ε is permittivity of free spaceE is electric field strengthA is the area of the plateQ is the charge

Q = (8.85 x 10⁻¹² x 8.85 x 10⁵ x 45 x 10⁻⁴)

Q = 3.53 x 10⁻⁸ C

Thus, the charge that must be on each plate is 3.53 x 10⁻⁸ C.

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At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT . At the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
1.) At what time does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
t=
2.) At what coordinate does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
x =

Answers

1. The truck overtakes the car at time t = 2vC/(aT  - aC)

2. The coordinate where the truck passes the car is  x = 2aT[vC/(aT  - aC)]²

The question has to do with equation of motion

What are the equations of motion?

The equations of motion are equations that are used to describe the motion of an object under constant acceleration.

1.) At what time does the truck pass the car?

Since at t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT.

We find the distance moved by the truck using the equation of motion d = ut + 1/2at² where

u = initial speed of truck = 0 m/s(since it starts at rest) a = acceleration of truck = aT

So, d = ut + 1/2at²

d = 0 × t + 1/2aTt²

d = 1/2aTt²

Also, at the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.

We find the distance moved by the car using the equation of motion D = ut + 1/2at² where

u = initial speed of car = vC a = acceleration of car = -aC

So, D = ut + 1/2at²

D = vCt + 1/2(-aC)t²

D =  vCt - 1/2aCt²  

The truck over takes the car when d = D

So, 1/2aTt² = vCt - 1/2aCt²  

1/2aTt²  - 1/2aCt² - vCt = 0

[(aT  - aC)t/2 - vC)]t = 0

⇒ t = 0 or (aT  - aC)t/2 - vC = 0

⇒ t = 0 or (aT  - aC)t/2 = vC

⇒ t = 0 or t = 2vC/(aT  - aC)

So, the truck overtakes the car at time t = 2vC/(aT  - aC)

2.) At what coordinate does the truck pass the car?

Since the distance moved by the truck is d = x - 0

= 1/2aTt², where x = coordinate where truck passes car.

To find the coordinate where the truck passes the car, we susbstitute the time where the truck passes the car into d. So, t =  2vC/(aT  - aC)

So,  x - 0 = 1/2aTt²

x = 1/2aT[2vC/(aT  - aC)]²

x = 2aT[vC/(aT  - aC)]²

So, the coordinate where the truck passes the car is  x = 2aT[vC/(aT  - aC)]²

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A car crash gives out great force. These are reasons for the great force EXCEPT:

A- high car speed
B- a long time to stop
C huge car weight
D- huge deceleration

Answers

Since we know force= mass times acceleration, the cars weight and acceleration/ deceleration play the biggest role in force.
Thus the current answer is b

A 120 V power supply is used to power a TV. If the TV draws 0.25 A of current and the TV is used for 1.20 h, how much energy, in kilojoules, is used?

Answers

The amount of energy used by the TV is 129.6 kJ.

What is electric energy?

Electric energy is the product of charge and potential difference.

To calculate the amount of electric energy used, we use the formula below.

Formula:

E = Vit................................. Equation 1

Where:

E = Electric energyV = Voltagei = Currentt = time

From the question,

Given:

V = 120 Vi = 0.25 At = 1.2 h = (1.2×3600) = 4320 s

Substitute these values into equation 1

E = 120×0.25×4320E = 129600 JE = 129.6 kJ

Hence, the amount of energy used by the TV is 129.6 kJ.

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please help me solve this worksheet its graded

Answers

The unit conversion of 1.5 x 10⁸ Gm to m =  1.5 x 10¹⁷ m.

The unit conversion of 2.6 x 10⁻⁵ nm =  2.6 x 10⁻²⁰ Mm.

The unit conversion of 2.72 x 10⁻⁵ μm =   2.72 x 10⁻¹¹ m.

The unit conversion of 2.56 x 10⁻³ cm =  2.56 x 10⁻⁸ km.

The unit conversion of 2 hr =  7,200 seconds.

The unit conversion of 2 h 30 min  = 9,000 seconds.

What is unit conversion?

Unit conversion involves the change of unit of a substance from one base to another.

Converting 1.5 x 10⁸ Gm to m

1.5 x 10⁸ Gm = 1.5 x 10⁸ x 10⁹ m = 1.5 x 10¹⁷ m

Converting 2.6 x 10⁻⁵ nm to Mm

2.6 x 10⁻⁵ nm = 2.6 x 10⁻⁵ x 10⁻⁹ x 10⁻⁶ m = 2.6 x 10⁻²⁰ Mm

Converting 2.72 x 10⁻⁵ μm to m

2.72 x 10⁻⁵ μm =  2.72 x 10⁻⁵  x 10⁻⁶ m =  2.72 x 10⁻¹¹ m

Converting 2.56 x 10⁻³ cm to km

2.56 x 10⁻³ cm = 2.56 x 10⁻³ x 10⁻² m x 10⁻³ km/m = 2.56 x 10⁻⁸ km

Converting 2 hours to seconds

2 hr = 2 x 3600 s = 7,200 seconds

Converting 2 h 30min to seconds

2 h 30 min = 7,200 seconds + 1800 s = 9,000 seconds

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A toy rocket is fired horizontally at 12.0 m/s from a 30.0 m tall building. The engine of the rocket provides an acceleration along the horizontal such that () = −(1.6 m/s3).. Find the time it takes for this toy rocket to land on the ground.

Answers

The time taken by the toy rocket that was fired horizontally to land on the ground is 2.47 seconds

s = ut + 1 / 2 at²

s = Distance

u = Initial velocity

t = Time

a = Acceleration

[tex]u_{x}[/tex] = 12 m / s

[tex]u_{oi}[/tex] = 0

[tex]s_{y}[/tex] = 30 m

[tex]a_{x}[/tex] = - 1.6 m / s²

[tex]a_{y}[/tex] = g = 9.8 m / s²

[tex]s_{y}[/tex] = [tex]u_{oi}[/tex] t + 1 / 2 gt²

30 = 0 + ( 0.5 * 9.8 * t² )

t = √ ( 30 / 4.9 )

t = 2.47 s

The initial velocity of a horizontal projectile motion is in x-direction is constant throughout the motion whereas in y-direction the initial velocity is zero and the final velocity varies.

Therefore, the time taken by the toy rocket that was fired horizontally to land on the ground is 2.47 seconds

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You make a capacitor by cutting the 14.5-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.35 mm , and connecting them across a 6.00 V battery.



If you disconnect the battery and separate the plates to a distance of 3.50 cm without discharging them, what will be the potential difference between them?

Express your answer to three significant figures with the appropriate units.

Answers

From the definition of capacitance, the potential difference between them will be 6.24v

What is Capacitance of a capacitor ?

The capacitance of a capacitor is the ratio of charge to the voltage supplied. It is measure in Farad.

If you make a capacitor by cutting the 14.5-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.35 mm , and connecting them across a 6.00 V battery, the cross sectional A = πr²

where r = 14.5/2 = 7.25 cm

r = 7.25/100 = 0.0725 m

The distance d = 3.35 mm = 3.35/1000 = 0.00335 m

A = πr²

A = 22/7 × 0.0725²

A = 0.0165 m²

Capacitance is proportional to the area of the plate and inversely proportional distance between them. That is,

C = ξA/d

where ξ = 8.5 × 10^-12 C²/Nm²

C = (8.5 × 10^-12 × 0.0165) / 0.00335

C = 4.19 × 10^-11 F

From Charge Q = CV

Q = 4.19 × 10^-11 × 6

Q = 2.5 × 10^-10 C

If you disconnect the battery and separate the plates to a distance of 3.50 cm without discharging them, the capacitance will be

C = ξA/d

C = (8.5 × 10^-12 × 0.0165) / 0.0035

C = 4.007 × 10^-11

From Q = CV

V = Q/C

V = 2.5 × 10^-10 / 4.007 × 10^-11

V = 6.24 v

Therefore, the potential difference between them will be 6.24v

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what is shielding effect due to hollow charged surface

Answers

Answer:

Electrostatic shielding

Explanation:

Positive and negative charges that are out of balance cause static electricity. One substance becomes positively charged and one becomes negatively charged when two dissimilar materials are rubbed together. Materials have been rated according on how well they can hold or release electrons. The triboelectric series is the name given to this order. These materials include paper, plastic, glass, hair, nylon, wool, and silk.

Electrons are merely transferred from one location to another when we charge anything with static electricity. There are no new or lost protons or electrons. The overall or net electric charge does not change. The "conservation of charge" principle refers to this.

An electric field is produced around charged items. The amount of charge, the distance involved, and the form of the items are just a few of the variables that affect how strong this field is. When dealing with huge items, this may get rather problematic. We may thus deal with "point sources" of charge to make things simpler. Point sources, also known as sources of insignificant dimensions, are charged objects that are much, much smaller than the space between them. The word "static" comes from the fact that an electric charge exists even when the electrons are not moving.

In the 1780s, French scientist Charles Coulomb (1736–1806) gave the first detailed account of electric field intensities. He discovered that the electrical force for point charges directly changes with the product of the charges. In other words, the field is stronger the higher the charges. Additionally, the field changes inversely with the square of the charge separation. This implies that the force weakens with increasing distance.

Because a significant charge may harm fragile electronic components like MOSFETs, CMOS ICs, Computer cards, TTL chips, and even LEDs, static electricity presents challenges for experimenters and electronics makers.

In a laboratory, there are a few fairly easy techniques to prevent static charges. The lab's air is made more humid, which reduces static electricity. Dry environments are better for electron accumulation. A thin coating of water molecules covers the majority of surfaces during humid days, allowing electrons to flow more easily and making nearly everything conductive and static-free. As a result, shocks are less frequent on these days.

Some factory employees must adhere to stringent dress codes, avoiding sweaters and headgear that can promote static. Technicians may wear wrist bands that deliver additional electrons into the earth by connecting them to the floor with a metal wire.

In factories, "air ionizers" are also used to regulate electron behavior. The devices release ions, or molecules with an excess of electrons, into a space. Ions are molecules with one or more missing electrons. The electrons find their opposites as they align with them as they drift around the room looking for equilibrium. Ionizers stop the accumulation of static electricity.

Sometimes we need a completely electrostatic-free environment for a piece of equipment to function extremely effectively, and the only definite way to achieve this is by creating a kind of enclosure that the equipment is designed to operate in. It could take up a whole room or perhaps just a metal box in a lab. A FARADAY'S CAGE is what it is called. It was created by British scientist Michael Faraday (1791–1867) and protects the contents from static electric forces.

The term comes from the fact that these enclosures resemble cages in many ways. Some are as straightforward as metal or chain-link enclosures. Some people employ a thin metallic mesh. No matter how they look exactly, all Faraday cages spread electrostatic charges or even specific forms of electromagnetic radiation around the cage's surface, keeping the interior free of them. (The metal mesh must contain holes that are shorter than the wavelength that is to be filtered in order to screen against electromagnetic radiation.) In essence, a Faraday cage is merely a "hollow conductor," with the charge only remaining on the cage's outside.

An airplane is the greatest illustration of a Faraday's Cage. Lightning frequently strikes airplanes when they are in the air. Despite the fact that it occurs frequently, neither the passengers nor the plane are harmed. This is so because the plane's metal body acts as a Faraday cage. Lightning strikes harmlessly over the surface of the airplane, causing no harm to the avionics, communications, or passenger electronics.

Thanks,

Eddie

A student is running at her top speed of 5.5 m/s to catch a bus, which is stopped at the bus stop. When the student is still a distance 40.4 m from the bus, it starts to pull away, moving with a constant acceleration of 0.173 m/s^2.
(a) For how much time does the student have to run at 5.5 m/s before she overtakes the bus?
(b) For what distance does the student have to run at 5.5 m/s before she overtakes the bus?
(c) When she reaches the bus, how fast is the bus traveling?
(d) If the student's top speed is 2.70 m/s , will she catch the bus?

Answers

(a) The time taken before the student catches the bus is 11.52 seconds.

(b) The distance the student have to run before she overtakes the bus is 63.36 m.

(c) The speed of the bus is 2.0 m/s.

(d) If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.

Time elapsed before the student over takes the bus

Apply the principle of relative velocity as follows;

(Vs - Vb)t = D

where;

Vs is the velocity of the studentVb is the velocity of the bust is the time in which the student catches the busD is the distance between them

(Vs - at)t = D

where;

a is the acceleration of the bus

(5.5 - 0.173t)t = 40.4

5.5t - 0.173t² = 40.4

0.173t² - 5.5t + 40.4 = 0

solve the quadratic equation using formula method;

a = 0.173, b = -5.5, c = 40.4

t = 11.52 seconds or 20.27 seconds

so the minimum time taken by the student to over take the bus is 11.52 seconds

Distance the student have to run to overtake the bus

d = vt

d = 5.5 m/s x 11.52 s = 63.36 m

Speed of the bus

v = at²

v = 0.173 x (11.52)

v = 2.0 m/s

If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.

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I need help in this…

Answers

Diffraction is the spreading out of waves past small openings and the bending of waves around small obstructions.

What is diffraction ?

Diffraction is the process by which light spreads out after passing through a small space or bends around an obstruction. Diffraction can occur in waves of any kind, including sound, radio, and water.

What is diffraction in sound wave?

When an object has dimensions that are close to or smaller than the sound wave's wavelength, it causes a sound wave to move around it.

Waves spread out as they move through an aperture or around objects, which is known as diffraction. It happens when the aperture's or obstacle's size is of the same order of magnitude as the wave's wavelength. Nearly all of the wave is blocked at very small aperture sizes.

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need answer and showed work to question number 1

Answers

Answer:

can u show question 1?

Explanation:

There are numerous starting points that a composer could use when writing a piece of music.
A. True
B. False, dynamics and tempo are the only starting points
C. False, composers never us a starting point
D. False, structure is the only starting point

Answers

There are numerous starting points that a composer could use when writing a piece of music. True.

Composers write, direct, and create tunes for numerous genres. they will produce compositions, scores, and preparations for theatre, movies, television, and even video games. Composers have fantastic musical ears and frequently advocate for musicians.

A music style or subgenre may be described by using the musical techniques, the cultural context, and the content material and spirit of the themes. The geographical foundation is once in a while used to perceive a song style, even though a single geographical category will often encompass a wide style of subgenres.

Dynamics manner how quietly or loudly a bit of track ought to be performed. Dynamics are an essential way of conveying the mood of a bit and your use of dynamics is a marked detail of your performance. Composers use dynamics to trade the temper.

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12. (a)
(i) What is meant by the term artificial radioactivity?

Answers

Induced radioactivity, also called artificial radioactivity or man-made radioactivity, is the process of using radiation to make a previously stable material radioactive.

in physics, a blank is a group of related objects that interact with eachother and form a complex whole

Answers

In physics, a system is a group of related objects that interact with each other and form a complex whole.

What is a system?

In sciences (i.e., physics, chemistry and biology) a system can be defined as an interrelated group of different elements or parts that work together to perform a given function.

In conclusion, in physics and science disciplines in general, a group of related objects that interact in order to form a complex whole is commonly referred as a system.

Complete question:

Fill in the blank. In physics, a ____ is a group of related objects that interact with each other and form a complex whole.

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How many generations passed if a generation is 1/3 lifetime and approximate lifetime is 70 years

Answers

88 generations have passed.

A generation is a collective term for all individuals who were born and are still alive at around the same period. The average time frame, commonly regarded to be between 20 and 30 years, during which children are born, grow up, become adults, and start having children is another way to put it. It is a structural term used to describe the parent-child relationship in kinship terminology.

In social science, the terms "generation" and "cohort" are sometimes used interchangeably to refer to "individuals within a defined population who experience the same key events over a certain period of time." These birth cohorts, usually referred to as "social generations," are frequently employed in popular culture and have served as the foundation for sociological study.

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A CT scan uses a rotating X-ray source mounted on a circular ring to capture three dimensional images of a body (see Figure
43.2 on page 521 of the textbook). One rotation of the X-ray source produces one sliced image of the body.
A specific CT scan machine has a circular ring with radius 44 cm (diameter 88 cm), and the mass of the X-ray source mounted
on the circular ring is 26 kg. The ring rotates at a constant rate of 21 rad/s. Answer the following questions.

(a) What is the tangential speed of the X-ray source in m/s?

(b) How many degrees does the X-ray source turn in 100 milliseconds?

(c) What is the magnitude of the centripetal force on the X-ray source?

(d) How many seconds does it take to take one image?

(e) What is the frequency of the rotation of the X-ray source in the unit of Hz?

Answers

Answer:

rsgc

Explanation:

bsf xg

A car initially has a velocity of 29 m/s starts to increase its velocity at a constant rate of 2.4 m/s2, for a distance of 22 m. What is its final velocity?

Answers

Answer:

vf=43.55m/s

Explanation:

Data:

vi=29m/s

S=22m

a=2.4 m/s^2

vf=? we are supposed to find final velocity.

we will use following equation of motion:

Formula:

[tex]2as=vf^{2} -vi^{2}[/tex]

put values

[tex]2(2.4)(22)=vf^2-(29)^2\\[/tex]

solving for [tex]vf^2[/tex].

taking [tex](29)^2[/tex] on the other side .

[tex]vf^2=2(2.4)(22)+(29)^2[/tex]

solve square first.

[tex]vf^2=2(24)(22)+841[/tex]

multiply the terms.

[tex]vf^2=1056+841[/tex]

add the terms

[tex]vf^2=1897[/tex]

taking square root on both sides.

[tex]\sqrt{vf^2}=\sqrt{1897}[/tex]

square root of [tex]vf^2[/tex] will be cancelled out .

[tex]vf=43.55m/s[/tex]

Two particles are at the same point at the same time, moving in the same direction. Par- ticle A has an initial velocity of 7.7 m/s and an acceleration of 1.8 m/s². Particle B has an initial velocity of 2.9 m/s and an acceleration of 5.7 m/s². At what time will B pass A? Answer in units of s.​

Answers

The particle B will pass particle A in 1.10s.

Equation :

Using kinematic formula,

d = Vini x t + 1/2 at²

where,

d is distance

Vini is velocity initial

a is acceleration

t is time

So, putting values

7.7 t + 1/2 x 1.8 t^² = 2.9 t + 1/2 x 5.7 t²

7.7 t + 2.7 t² = 2.9 t + 8.55 t²

t + t² / t + t² = 2.9 + 8.55 / 7.7 + 2.7

t = 1.10s

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