A random sample of 1,000 StatCrunchU students contains 598 female and 402 males. We analyze responses to the question, "What is the total amount (in dollars) of your student loans to date?" Two sample T confidence interval: μ 1: Mean of Loans where Gender="Female" μ 2: Mean of Loans where Gender="Male" μ 1 − μ 2: Difference between two means (without pooled variances) 95% confidence interval results: Difference Sample Diff. Std. Err. DF L. Limit U. Limit μ 1 − μ 2 516.74334 368.41116 907.34739 -206.29374 1239.7804 What can we conclude from the 95% confidence interval? Check all that apply. Group of answer choices

Answers

Answer 1

Based on the information given, these are the conclusions we can draw from the 95% confidence interval.

Here, we have,

From the provided 95% confidence interval, we can make the following conclusions:

The point estimate of the difference between the mean student loans for females and males is 516.74334 dollars.

The standard error of the difference between the means is 368.41116 dollars.

The degrees of freedom (DF) associated with the confidence interval is 907.34739.

The lower limit of the confidence interval is -206.29374 dollars.

The upper limit of the confidence interval is 1239.7804 dollars.

The confidence interval does not contain zero.

Since zero is not within the interval, we can conclude that the difference between the mean student loans for females and males is statistically significant at the 95% confidence level.

Based on the information given, these are the conclusions we can draw from the 95% confidence interval.

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Answer 2

The estimated difference in the mean student loans between females and males is 516.74334.

There is a 95% confidence that the true difference in means falls within the range of -206.29374 to 1239.7804.

Based on the 95% confidence interval provided for the difference in means between the loans of female and male StatCrunchU students, we can draw the following conclusions:

The sample difference in means is 516.74334.

The standard error of the difference is 368.41116.

The degrees of freedom (DF) for the analysis is 907.34739.

The lower limit of the confidence interval is -206.29374.

The upper limit of the confidence interval is 1239.7804.

Therefore, we can conclude the following:

The estimated difference in the mean student loans between females and males is 516.74334.

There is a 95% confidence that the true difference in means falls within the range of -206.29374 to 1239.7804.

Note: Since the confidence interval includes both positive and negative values, we cannot conclude with certainty whether there is a significant difference or not in the mean student loans between females and males. The confidence interval suggests that the difference could be positive, negative, or even zero.

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Related Questions

Select all of the following statements that are true:
A. Random samples only generate unbiased estimates of long-run proportions, not long-run means.
B. You shouldnt take a random sample of more than 5% of the population size.
C. There is no way that a random sample of 100 people can be representative of all adults living in the United States.
D. If this question is voted out, the alternate option is "larger samples are always better than smaller samples, regardless of how the sample was collected."
E. Nonrandom samples are always poor representations of the population

Answers

Answer:

B. You shouldnt take a random sample of more than 5% of the population size.

Step-by-step explanation:

B. You shouldnt take a random sample of more than 5% of the population size. This is True, so as to avoid the research analysis to be more complex to interpret and analyzed

However, the following are not true statements:

A. Random samples only generate unbiased estimates of long-run proportions, not long-run means. This is False, as there may be sampling error, when picking the sample, which will lead to bias estimates in the long run proportions

C. There is no way that a random sample of 100 people can be representative of all adults living in the United States. This is False, as using the right factors such as gender, age, income, etc, in selecting the sample, 100 people is enough to use as sample of adults living in the United States

D. If this question is voted out, the alternate option is "larger samples are always better than smaller samples, regardless of how the sample was collected." This is False, larger samples are not always better than smaller samples. In fact, they are often difficult to analyze and interpret.

E. Nonrandom samples are always poor representations of the population: This is False, depending on the expected outcome of the research study. Some research studies required the research to use Nonrandom samples to reach verifiable conclusion.

what is 2/3 of 460? Just a little easy one for points​

Answers

Answer:

2/3 * 460 = 306 and 2/3

Multiply 460 by 2/3 by first multiplying 460 by 2, then divide that by 3:

460 x 2 = 920

920 /3 = 306 2/3

The answer is 306 2/3

A jury pool has 15 men and 21 women, from which 12 jurors will be selected. Assuming that each person is equally likely to be chosen and that the jury is selected at random, find the probability that the jury consists of:_____
(a) all men
(b) all women
(c) 8 men and 4 women
(d) 6 men and 6 women
Give all answers accurate to four decimal places.

Answers

Answer:

(a) all men = 3.6351 * 10^ -7

(b) all women = 2.3483* 10^ -4

(c) 8 men and 4 women = 0.0308

(d) 6 men and 6 women= 0.2170

Step-by-step explanation:

A jury pool has 15 men and 21 women, from which 12 jurors will be selected.

Total = 36 people

Probability of

(a) all men

= 15C12/36C12

= 455/1251677700

= 3.6351 * 10^ -7

(b) all women

= 21C12/36C12

= 293930/1251677700

= 2.3483* 10^ -4

(c) 8 men and 4 women

=( 15C8 * 21C4)/36C12

= (6435*5985)/1251677700

= 38513475/1251677700

= 0.0308

(d) 6 men and 6 women

= (15C6 * 21C6)/(36C12)

= (5005*54264)/1251677700

= 271591320/1251677700

= 0.2170

The table shows ordered pairs of the function y=8-2x What is the value of y when x = 8?

Answers

Answer:-8

Step-by-step explanation:

8 - 2 × 8

8 - 16

-8

Two number cubes are rolled for two separate events:


Event A is the event that the sum of numbers on both cubes is less than 10.

Event B is the event that the sum of numbers on both cubes is a multiple of 3.

Complete the conditional probability formula for event B given that event A occurs first by writing A and B in the blanks:

P ( _a0 | _a1) = P ( _a2 ∩ _ a3)
___________
P ( _a4)

Answers

Answer:  [tex]\bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}[/tex]

Step-by-step explanation:

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

[tex]P(B|A)=\dfrac{P(B\cap A)}{P(A)}[/tex]

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

          (2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

          (3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

                    (4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

                              (5, 4), (5, 3), (5, 2), (5, 1)

                                        (6, 3), (6, 2), (6, 1)

       = 30

P(B) = (1, 2), (2, 1)                                   sum = 3

          (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)    sum = 6

          (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)  sum = 9

          (6, 6)                                           sum = 12

                       

      = 12

P(A ∩ B) =  (1, 2), (2, 1)

                  (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

                  (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

             = 11

Use the following cell phone airport data speeds​ (Mbps) from a particular network. Find the percentile corresponding to the data speed 11.2 Mbps. 0.1 0.2 0.2 0.3 0.4 0.4 0.4 0.5 0.5 0.6 0.6 0.8 0.9 0.9 0.9 1.1 1.3 1.7 1.8 1.9 2.3 2.4 2.5 2.6 2.7 3.1 3.5 3.5 3.7 3.8 4.8 5.2 7.4 7.9 8.2 8.6 9.3 11.2 11.3 11.4 12.1 12.6 13.1 13.3 13.6 13.8 14.6 15.6 15.7 25.6

Answers

Answer: the percentile is 74%

Step-by-step explanation:

The given data distribution is arranged in increasing order as:

0.1 0.2 0.2 0.3 0.4 0.4 0.4 0.5 0.5 0.6 0.6 0.8 0.9 0.9 0.9 1.1 1.3 1.7 1.8 1.9 2.3 2.4 2.5 2.6 2.7 3.1 3.5 3.5 3.7 3.8 4.8 5.2 7.4 7.9 8.2 8.6 9.3 11.2 11.3 11.4 12.1 12.6 13.1 13.3 13.6 13.8 14.6 15.6 15.7 25.6

The total number of values given in the data is 50

Percentile = number of values in the distribution lesser than the given value × 100/ total number of values in the distribution

Considering the data speed of 11.2 Mbps, the number of data speed lower than 11.2 is 37

Percentile = (37 × 100)/50 = 74%

This table gives a few (x,y) pairs of a line in the coordinate plane. What is the y-intercept of the line? (full problem attached)

Answers

Answer:

(0,34)

Step-by-step explanation:

For each rise of 14 in the x direction, this graph rises by -8 in the y direction. This means that, when x is 0, and the graph intersects the y axis, the y value will be 50-8-8=34. Therefore, the y intercept of this line is (0,34). Hope this helps!

Answer:

The answer is (0,34)

Help asap giving branlist!!!

Answers

Answer:

Option 2

Step-by-step explanation:

The question states "the width of the rectangle is 4 less than half the length."  Since we are looking for the value of w, w will be equal to the expression we create.  We start with half the length and than subtract 4 from it.  This is because it says 4 less than half the length, not half of 4-length or another variation.  In many of these problems the best way to solve them is by working backwards.

Answer:

Option 2

Step-by-step explanation:

Translating these words into math, we get w = 1/2l - 4 which is Option 2.

What’s the correct answer for this question?

Answers

Answer:

1)

Volume of pyramid = 1/3(Ab)(h)

Where Ab is the area of base, h is height

Volume of cone = 1/3(Ab)(h)

a) Their formula for finding volume is same. Also, their painting heads are same.

b) Pyramids have a tetragonal base while cones have a polygonal base

2) Pyramids

Volume of cone = (1/3) πr²h

Since Area of a circle = πr²

So

Volume of pyramid = (1/3)(A)(h)

So we can use the formula of a circle in cone's formula

Answer:

i dont know but i want points

Step-by-step explanation:

hehehe

A meteorologist reports that the chance of snow is less

than 30%. The correct inequality to represent this

comparison is s < 30. The variable s represents the

likelihood of snow

Which numbers are solutions of the inequality?

Choose all that apply.

20%

35%

17%

30%

29

%

1.5%

Answers

Answer:

1, 3, 5, 6

Step-by-step explanation:

Your solution has to be less than the number they are giving you for example if you have -3 one solution could be -16

The numbers that are solutions to the inequality are as follows: 20%, 17%, 29.5%, 1.5%.

What are the solutions of the inequality?

The solution of an inequality is the set of all possible values that could serve as the result of the expression. So, for the given problem, the set of values that would correspond to the likelihood of snow is 20%, 17%, 29.5%, and 1.5%.

In other words, these percentages are less than 30% and can be rightly represented by the variable s.

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which products have the same sign as (-2 3/7) (-6/11) check all that apply
A.) 3/8(-6/7)
B.) 1 2/9(2 16/17)
C.) -9/20(3 4/5)
D.) -1/3 (-2/3
hurry answer pls

Answers

Answer: Options B and D.

Step-by-step explanation:

We start with the equation:

(-2 3/7)*(-6/11)

now, you need to recall the signs relations:

(+)*(+) = +

(-)*(+) = -

(-)*(-) = +

Then our initial equation has a positive sign.

a)  (3/8)*(-6/7) here we have (+)*(-), so this is negative, this option is not correct.

b) (1 2/9)*(2 16/17) here we have (+)*(+), so this is positive, this option is correct.

c)  (-9/20)*(3 4/5) here we have (-)*(+), so this is negative, this option is not correct.

d) (-1/3)*(-2/3) here we have (-)*(-), so this is positive, then this option is correct.

Answer:

The awnser is B and D

Step-by-step explanation:

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 4 students' scores on the exam after completing the course: 12,7,13,11 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Step 3 of 4 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

Answer:

The 80% confidence interval for the average net change is (8.596, 12.904).

Critical value t=1.638.

Step-by-step explanation:

First, we calculate the mean and standard deviation of the sample:

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{4}(12+7+13+11)\\\\\\M=\dfrac{43}{4}\\\\\\M=10.75\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{3}((12-10.75)^2+(7-10.75)^2+(13-10.75)^2+(11-10.75)^2)\\\\\\s=\dfrac{20.75}{3}\\\\\\s=6.92\\\\\\[/tex]

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=10.75.

The sample size is N=4.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.63}{\sqrt{4}}=\dfrac{2.63}{2}=1.315[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=4-1=3[/tex]

The t-value for a 80% confidence interval and 3 degrees of freedom is t=1.638.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.638 \cdot 1.315=2.154[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 10.75-2.154=8.596\\\\UL=M+t \cdot s_M = 10.75+2.154=12.904[/tex]

The 80% confidence interval for the average net change is (8.596, 12.904).

Based on the type of equations in the system, what is the greatest possible number of solutions? StartLayout Enlarged left-brace 1st Row x squared + y squared = 9 2nd row 9 x + 2 y = 16 EndLayout

Answers

Answer:

2

Step-by-step explanation:

Given the system of equations:

[Tex]x^2+y^2=9\\9x+2y=16[/tex]

Comparing [Tex]x^2+y^2=9[/tex] with the general standard equation of a circle [Tex](x-h)^2+(y-k)^2=r^2[/tex].

The first equation is an equation of a circle centred at (0,0) with a Radius of 3.

The second equation 9x+2y=16 is a straight line equation.

A straight line can only intersect a circle at a maximum of 2 points.

Therefore the greatest possible number of solutions to the equations in the system is 2.

Answer:

2

Step-by-step explanation:

and jj is gay of outer banks

Calculating the standard deviation (σ) for a list of n data values: 1. Calculate the average value. 2. Subtract the average value from each individual data value and enter the results in a column to the right of the data values. 3. Square each of the results obtained in step 2, and enter these in a new column to the right. 4. Sum the squares obtained in step 3. 5. Divide the result from step 4 by (n - 1) (the total number of measurements minus 1). 6. Take the square root of the result from step 5. This is the standard deviation. Expressed as an equation, the standard deviation of n measurements of data value x is: σ = ( Σ (x - xavg)2 / (n - 1) )1/2 Using the 6 steps above (or the spreadsheet function), calculate the standard deviation for the six values on page 16 and enter your answer below. Enter your result with only one sig fig, and remember to use a zero before the decimal point for values less than 1, for example 0.05 or 0.01.

Answers

Answer:

Step-by-step explanation:

The missing list of the data values for the question are as follows:

1             1.03

2             1.01

3             0.96

4             0.96

5             0.99

6             1

7             1.01

8             0.98

9             1.02

10            1.03

11             1

12             0.99

13             1

14             0.97

15             1.01

               [tex]x_i[/tex]                          [tex](x_i - \bar x)[/tex]                              [tex](x_i - \bar x)^2[/tex]

1             1.03                         0.03                                  0.0009

2             1.01                         0.01                                   0.0001

3             0.96                        -0.4                                   0.0016

4             0.96                        -0.4                                   0.0016

5             0.99                        -0.1                                   0.0001

6             1                               0.0                                   0.0

7             1.01                           0.1                                   0.0001

8             0.98                        -0.2                                   0.0004

9             1.02                          0.2                                   0.0004

10            1.03                          0.3                                   0.0009

11             1                               0.0                                   0.0

12             0.99                        -0.1                                   0.0001

13             1                               0.0                                   0.0

14             0.97                        -0.03                                   0.0009

15             1.01                           0.1                                   0.0001

The average value for x is calculated as:

[tex]\bar x = \dfrac{14.96}{15}[/tex]

[tex]\bar x = 0.997 \\ \\ \bar x \approx 1.00[/tex]

[tex]\sum (x-x_i)^2 = 0.0072[/tex]

[tex]\dfrac{\sum (x-x_i)^2 }{n-1}= \dfrac{0.0072}{15-1} \\ \\ = \dfrac{0.0072}{14} \\ \\ = 0.00051[/tex]

[tex]\sigma = \sqrt{\dfrac{\sum (x-x_i)^2 }{n-1}} = \sqrt{0.00051} \\ \\ \sigma =0.0226 \\ \mathbf { \\ \sigma =0.02 \ to \ one \ significant \ figure}[/tex]

A statistics professor receives an average of five e-mail messages per day from students. Assume the number of messages approximates a Poisson distribution. What is the probability that on a randomly selected day she will have five messages

Answers

Answer:

The probability that on a randomly selected day the statistics professor will have five messages is 0.1755.

Step-by-step explanation:

Let the random variable X represent the number of e-mail messages per day a statistics professor receives from students.

The random variable is approximated by the Poisson Distribution with parameter λ = 5.

The probability mass function of X is as follows:

[tex]P(X=x)=\frac{e^{-5}\cdot 5^{x}}{x!};\ x=0,1,2,3...[/tex]

Compute the probability that on a randomly selected day she will have five messages as follows:

[tex]P(X=5)=\frac{e^{-5}\cdot 5^{5}}{5!}[/tex]

               [tex]=\frac{0.006738\times 3125}{120}\\\\=0.17546875\\\\\approx 0.1755[/tex]

Thus, the probability that on a randomly selected day the statistics professor will have five messages is 0.1755.

Alex is paid $30/hr at full rate, and $20/hr at a reduced rate. The hours of work are paid at a ratio of 2:1, full rate : reduced rate. For example, if he worked 3 hours, he would be paid 2 hours at full rate and 1 hour at reduced rate. Calculate his pay for 4 hours of work

Answers

Answer:

His pay for 4 hours of work is $106.67.

Step-by-step explanation:

2:1, full rate : reduced rate.

This means that for each 2+1 = 3 hours that he works, 2 he has full pay and 1 he has reduced pay.

4 hours

How much are full pay?

For each 3, 2 are full pay. For four?

3 hours - 2 full pay

4 hours - x full pay

[tex]3x = 8[/tex]

[tex]x = \frac{8}{3}[/tex]

So for [tex]\frac{8}{3}[/tex] hours he makes the full pay($30) and for [tex]4 - \frac{8}{3} = \frac{12}{3} - \frac{8}{3} = \frac{4}{3}[/tex] he makes reduced pay($20).

Calculate his pay for 4 hours of work

[tex]30*\frac{8}{3} + 20*\frac{4}{3} = 106.67[/tex]

His pay for 4 hours of work is $106.67.

A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute. A fire hydrant with a green cap provides water at a rate of 1,000 gallons per minute. A fire hydrant with a purple cap provides water at half the rate of a fire hydrant with a green cap. What is the equation in fraction form

Answers

Answer:

Fire hydrant with a purple cap (with respect to a fire hydrant with a green cap):

[tex]\dot Q_{purple} = \frac{1}{2}\cdot \dot Q_{green}[/tex]

Step-by-step explanation:

The volume rate of the fire hidrant with a purple cap is equal to the product of the proportion factor and the volume rate of the fire hydrant with a concrete cap.

[tex]\dot Q_{i} = k \cdot \dot Q_{j}[/tex]

There are two different solutions:

Fire hydrant with a purple cap (with respect to a fire hydrant with a green cap):

[tex]\dot Q_{purple} = \frac{1}{2}\cdot \dot Q_{green}[/tex]

Fire hydrant with a purple cap (with respect to a fire hydrant with a blue cap):

[tex]\dot Q_{purple} = \frac{1}{2} \times \frac{1000\,gpm}{1500\,gpm}\cdot \dot Q_{blue}[/tex]

[tex]\dot Q_{purple} = \frac{1}{3}\cdot \dot Q_{blue}[/tex]

At a gas station, 50% of the customers use regular gas, 30% use mid-grade gas and 20% use premium gas. Of those customers using regular gas, only 30% fill their tanks. Of those customers using mid-grade gas, 60% fill their tanks, whereas of those using premium, 50% fill their tanks. If the next customer fills the tank, what is the probability that he uses premium gas

Answers

Answer:

The probability is 0.2326 or 23.26%.

Step-by-step explanation:

The probability that a random customer fills their tank with premium gas is:

[tex]P( prem\ \&\ fill) = 0.2*0.5=0.10[/tex]

The probability that a random customer fills their tank is given by:

[tex]P(fill)=P( reg\ \&\ fill)+P( mid\ \&\ fill)+P( prem\ \&\ fill)\\P(fill) = 0.5*0.3+0.3*0.6+0.2*0.5\\P(fill) = 0.43[/tex]

Therefore, the probability that a customer used premium gas given that hey have filled their tank is:

[tex]P(prem| fill) = \frac{P( prem\ \&\ fill) }{P(fill)} \\P(prem| fill) =\frac{0.10}{0.43}=0.2326[/tex]

The probability is 0.2326 or 23.26%.

A driver and a passenger are in a car accident. Each of them independently has probability 0.3 of being hospitalized. When a hospitalization occurs, the loss is uniformly distributed on [0, 1]. When two hospitalizations occur, the losses are independent. Calculate the expected number of people in the car who are hospitalized, given that the total loss due to hospitalizations from the accident is less than 1.

Answers

Answer:

0.534

Step-by-step explanation:

p(0 losses) = 0.7² = 0.49

p(1 loss) = 2 x 0.3 x 0.7 = 0.42

p(2 losses) = 0.09

This is a conditional probability problem. If the number of people hospitalized is 0 or 1, then the  total loss will be less than 1. However, if two people are hospitalized, the probability that the  total loss will be less than 1 is 0.5. we need to exclude the 50% x 0.09 chance of a double loss costing more than 1. So

P(Cost < 1)

= 0.49 + 0.42 +0.045

= 0.955

P(0 losses | Cost < 1)

= P(0 losses and Cost < 1) / P(Cost < 1)

= 0.49 / 0.955 = 0.513

P(1 loss | Cost < 1)

= 0.42 / 0.955 = 0.440

P(2 losses | Cost < 1) = 0.045 / 0.955 = 0.047

Now take the expectation:

E[X] = (0)(0.513) + (1)(0.440) + (2)(0.047)

= 0.440 + 0.094

= 0.534

I need the answers for 21 and 22

Answers

Answer:

21.b

22.c

Step-by-step explanation:

idk how to explain it lol I did mental math

Solve for x: 3x - 5 = 2x + 6.
Your answer

Answers

Answer:

3x-5=2x+6

x-5=6

x=11

3x-2x - 5 = 6
3x- 2x = 6+5
X = 11

m^2-3m+2/m^2-m. Simplify

Answers

Answer:

Step-by-step explanation:

factor out the numerator and demoninator

(m-2)(m-1)/m(m-1)

= (m-2)/m

Round $0.6683 to the nearest cent

Answers

Answer:

0.67

Step-by-step explanation:

0.668 is close to 0.67 than 0.66

The correct answer is $0.67

which of the following are solutions to the quadratic equation check all that apply x ^ 2 + 10x + 25 = 7​

Answers

Answer:

the Answers are : B and E

Step-by-step explanation:

From the given quadratic equation [tex]x^2 + 10x + 25 = 7[/tex] Thus, the solution is x = -1 and -9.

How to find the roots of a quadratic equation?

Suppose that the given quadratic equation is

[tex]ax^2 + bx + c = 0[/tex]

Then its roots are given as:

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

We have been given a quadratic equation

[tex]x^2 + 10x + 25 = 7[/tex]

[tex]x^2 + 10x + 25 - 7=0\\\\x^2 + 10x + 18[/tex]

The solution of the given equation;

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-10 \pm \sqrt{10^2 - 4\times 18}}{2}\\\\x = \dfrac{-10 \pm \sqrt{100- 36}}{2}\\\\x = \dfrac{-10 \pm \sqrt{64}}{2}\\\\x = \dfrac{-10 \pm 8}{2}\\[/tex]

Therefore, the solution are x = -1 and -9.

Learn more about finding the solutions of a quadratic equation here:

https://brainly.com/question/3358603

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There are 10 balls in a bag, 4 red balls and 6 black balls. If you pick one red ball, you will take it without replacement. If you pick one black ball, you will return it into the bag. Now you pick two times and each time you can only take one ball. What is the probability that you will pick two red balls

Answers

Answer:

The probability of selecting two red balls is 0.132.

Step-by-step explanation:

In a bag there are 10 balls in a bag, 4 red balls and 6 black balls.

The conditions of selecting a ball are:

If you pick one red ball, you will take it without replacement. If you pick one black ball, you will return it into the bag.

It is also provided that only one ball can be picked at a time.

Now, it is given that two balls are picked.

The number of ways to select a red ball in the first draw is: [tex]{4\choose 1}=4\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the first draw as follows:

[tex]P(\text{First ball is Red})=\frac{{4\choose 1}}{{10\choose 1}}=\frac{4}{10}=0.40[/tex]

Now as a red ball is selected it will not be replaced.

So, there are 9 balls in the bag now.

The number of ways to select a red ball in the second draw is: [tex]{3\choose 1}=3\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the second draw as follows:

[tex]P(\text{Second ball is Red})=\frac{{3\choose 1}}{{9\choose 1}}=\frac{3}{9}=0.33[/tex]

Compute the probability of selecting two red balls as follows:

[tex]P(\text{Two Red balls})=P(\text{First ball is Red})\times P(\text{Second ball is Red})[/tex]

                            [tex]=0.40\times 0.33\\\\=0.132[/tex]

Thus, the probability of selecting two red balls is 0.132.

A newborn baby whose Apgar score is over 6 is classified as normal and this happens in 80% of births. As a quality control check, an auditor examined the records of 100 births. He would be suspicious if the number of normal births in the sample of 100 births fell below the lower limit of "usual." What is that lower limit?

Answers

Answer:

The lower limit is 72.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is more than 2 standard deviations from the mean, it is unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question, we have that:

[tex]n = 100, p = 0.8[/tex]

So

[tex]\mu = 0.8, s = \sqrt{\frac{0.8*0.2}{100}} = 0.04[/tex]

He would be suspicious if the number of normal births in the sample of 100 births fell below the lower limit of "usual." What is that lower limit?

2 standard deviations below the mean is the lower limit, so X when Z = -2.

Proportion:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]-2 = \frac{X - 0.8}{0.04}[/tex]

[tex]X - 0.8 = -2*0.04[/tex]

[tex]X = 0.72[/tex]

Out of 100:

0.72*100 = 72

The lower limit is 72.

Please answer this question I give brainliest thank you! Number 16

Answers

Answer:

4a

Step-by-step explanation:

The mean is found by adding all of the data set together and then dividing by the amount of individual pieces of data in the set.

(2+3+3+8) = 16

16/4=4

The answer is 4a.

The perimeter of an equivalent triangle is 15 inches. A side of the triangle is x-2. What is the length of each side of the triangle

Answers

Answer:

5

Step-by-step explanation:

We have x-2 = 5

x-2 = 5 we separate parenthesis.

x(-2) = 5(+2)

x = 7

We can check this as what the x-2 is saying is  7-2 = 5

Answer:

Since it is an equilateral triangle,

Perimeter = 3s = 3 x side

=> 15 = 3 X (x - 2)

=> 15 = 3(x - 2)

=> 15 = 3x - 6

=> 3x = 15 + 6

=> 3x = 21

=> x = 21/3

=> x = 7

When x = 7,

=> Side = 7 - 2 = 5 inches

Since, it is an equilateral triangle all sides are of 5 inches each.

According to market research, a business has a 75% chance of making money in the first 3 years. According to lab testing, of a certain kind of experimental light bulb will work after 3 years. According to experts, the likelihood of a car needing major repairs in the first 3 years is 0.7. 1. Write the scenarios in order of likelihood from least to greatest after three years: the business makes money, the light bulb still works, and the car needs major repairs.

Answers

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Here are some scenarios:

According to market research, a business has a 75% chance of making money in the first 3 years.

According to lab testing, 5/6 of a certain kind of experimental light bulb will work after 3 years.

According to experts, the likelihood of a car needing major repairs in the first 3 years is 0.7.

1. Write the scenarios in order of likelihood from least to greatest after three years: the business makes money, the light bulb still works, and the car needs major repairs.

Answer:

The correct order in terms of likelihood from least to greatest would be

P(Car repair) = 0.70 -> P(Business) = 0.75 -> P(Light bulb) = 0.83

Car needs major repairs -> Business makes money -> Light bulb still works

Step-by-step explanation:

We are given probabilities of three different events.

According to market research, a business has a 75% chance of making money in the first 3 years.

P(Business) = 75% = 0.75

According to lab testing, 5/6 of a certain kind of experimental light bulb will work after 3 years.

P(Light bulb) = 5/6 = 0.83

According to experts, the likelihood of a car needing major repairs in the first 3 years is 0.7.

P(Car repair) = 0.70

We are asked to write these scenarios in order of likelihood from least to greatest after three years.

Which means that the events with least probability is less likely to occur.

The least probability is of car repair, then business and then light bulb.

So the correct order in terms of likelihood from least to greatest would be

P(Car repair) = 0.70 -> P(Business) = 0.75 -> P(Light bulb) = 0.83

Car needs major repairs -> Business makes money -> Light bulb still works

what is the radius of the circle that has an area of [tex]81*x*pi[/tex] degrees

Answers

Answer:

R=9

Step-by-step explanation:

the formula for area of a circle is pi r squared

where r denotes the radius of the circle

equating the formula for area with the area of the circle provided

p\i r squared = 81 p\i

r squared = 81

r = radical 81

r =9 inches

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