Answer:
Paired t test
H0 : μd = 0
H1 : μd > 0
Critical value = 3.499
Test statistic = 2.230
Reject H0 if test statistic > Critical value
Kindly check explanation.
Step-by-step explanation:
Given the data :
110 90 120 98 100 100 90 110
124 100 102 120 110 110 123 120
The hypothesis :
H0 : μd = 0
H1 : μd > 0
Tcritical value, df = n - 1 = 8 - 1 = 7
Tcritical(0.01, 7) = 3.499
The difference, d = (-14,-10,18,-22,-10,-10,-33,-10)
The test statistic :
Xdbar / Sd/√n
The mean difference, Xdbar = Σx / n = - 11.375
The standard deviation of difference, Sd = 14.431
The test statistic :
-11.375 / (14.431/√8) ;
-11.375 / 5.102
= 2.230
Decison :
Reject H0 if test statistic > Critical value
Since ; 2.230 <3.499 ;
We fail to reject the null
Please answer and explain :)
Write an example for each of the following:
equation notation
set notation
interval notation
solution graph
Answer:
set notation _ A set is denoted or represented by a capital letter and enclosed in a curly bracket For example {A,B,P,Q}.
A plane traveled 4425 miles with the wind in 7.5 hours and 3675 miles against the wind in the same amount of time. Find the speed of the plane in still air and the speed of the wind
Answer:
540 miles/hr and 50 miles/hr respectively
Step-by-step explanation:
Let the speed of plane in still air be x and the speed of wind be y.
ATQ, (x+y)*7.5=4425 and (x-y)*7.5=3675. Solving it, we get x=540 and y=50
For the following exercise, calculate the desired dose. Then calculate the amount to administer. Ordered: Pergolide mesylate 100 mcg PO tid On hand: Pergolide mesylate 0.05 mg tablets what is the Desired dose?
Answer:
was assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarismwas assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarism
Step-by-step explanation:
was assigned with this problem (the reference text is attached):
Which of the following, if included in a student's paper, would NOT be an example of plagiarism?
1. In the game of baseball, which is rather boring, the batter stands on home base (Hughes 1).
2. Baseball is rather surprisingly known as "America's Favorite Pastime."
3. Baseball is "a rather boring sport played between two teams of nine players" (Hughes 1).
4. All of these are plagiarism.
The answer tells that only the third choice is NOT a plagiarism. My question is, why is the first choice a plagiarism
Sketch the region of integration and convert the polar integral to a Cartesian integral or sum of integrals. Do not evaluate the integral.
∫ ^π∫^2 r^3 sinθcosθdrd()
π/2 0
It looks like the integral in polar coordinates is given to be
[tex]\displaystyle\int_{\pi/2}^\pi \int_0^2 r^3\sin(\theta)\cos(\theta)\,\mathrm dr\,\mathrm d\theta[/tex]
Converting back to Cartesian, we take
x = r cos(θ)
y = r sin(θ)
dx dy = r dr dθ
so we can easily recover the integrand in Cartesian:
[tex]r^3\sin(\theta)\cos(\theta)\,\mathrm dr\,\mathrm d\theta = (r\sin(\theta))(r\cos(\theta))(r\,\mathrm dr\,\mathrm d\theta) = xy\,\mathrm dx\,\mathrm dy[/tex]
This leaves us with the limits:
• π/2 ≤ θ ≤ π corresponds to the second quadrant of the (x, y)-plane (that is, where x < 0 and y > 0)
• 0 ≤ r ≤ 2 correspond to the disk of radius 2 centered at the origin
Taken together, we see the region of integration is a quarter-disk of radius 2 in the second quadrant, which we can capture by the set
{(x, y) : -√2 ≤ x ≤ 0 and 0 ≤ y ≤ √(2 - x ²)}
So, in Cartesian coordinates, the integral would be
[tex]\displaystyle \boxed{\int_{-\sqrt2}^0 \int_0^{\sqrt{2-x^2}} xy\,\mathrm dy\,\mathrm dx}[/tex]
write the greatest and smallest four digit number by using 7,8,0,9 digit
Find x.
A. 7√6/2
B. 28
C. 21/2
D. 7√6
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Answer:
A. 7√6/2
Step-by-step explanation:
The side ratios of the 30-60-90 triangle are 1 : √3 : 2. This means the horizontal line segment is 7√3.
The side ratios of the 45-45-90 triangle are 1 : 1 : √2. This means ...
x = (horizontal segment)/√2 = (√2)/2 × 7√3 = (7/2)√(2·3)
x = 7√6/2
i need y’alls help !!
Answer for this prob
Laura, Scott, and Joe served a total of 104
orders Monday at the school cafeteria. Joe served 3
times as many orders as Scott. Laura served 9
more orders than Scott. How many orders did they each serve?
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Answer:
Joe: 57Scott: 19Laura: 28Step-by-step explanation:
Let s represent the number of orders Scott served. Then we have Joe served 3s, and Laura served (s+9). The total of orders served is ...
3s +s +(s +9) = 104
5s = 95 . . . . . . . . . . . subtract 9 and collect terms
s = 19 . . . . . . . . . divide by 5
3s = 3×19 = 57
s+9 = 19+9 = 28
Joe served 57 orders, Scott served 19, and Laura served 28 orders.
Find the missing side round your answer to the nearest tenth
Answer:
x = 38.4
Step-by-step explanation:
tan(38) = 30/x
x = 30/tan(38)
x = 38.4
Answered by GAUTHMATH
Calculus II Question
Identify the function represented by the following power series.
[tex]\sum_{k = 0}^\infty (-1)^k \frac{x^{k + 2}}{4^k}[/tex]
With some rewriting, you get
[tex]\displaystyle \sum_{k=0}^\infty (-1)^k\frac{x^{k+2}}{4^k} = x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k[/tex]
Recall that for |x| < 1, you have
[tex]\displaystyle \frac1{1-x} = \sum_{k=0}^\infty x^k[/tex]
So as long as |-x/4| = |x/4| < 1, or |x| < 4, your series converges to
[tex]\displaystyle x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k = \frac{x^2}{1-\left(-\frac x4\right)} = \frac{x^2}{1+\frac x4} = \boxed{\frac{4x^2}{4+x}}[/tex]
Based on known expressions from Taylor series, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex].
How to derive a function behind the approximated formula by Taylor seriesTaylor series are polynomic approximations used to estimate values both from trascendental and non-trascendental functions. It is commonly used in trigonometric, potential, logarithmic and even rational functions.
In this question we must use series properties and common Taylor series-derived formulas to infer the expression behind the given series. Now we proceed to find the expression:
[tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]
[tex]x^{2}\cdot \sum\limits_{k = 0}^{\infty} \left(-\frac{x}{4} \right)^{k}[/tex]
[tex]x^{2}\cdot \left(\frac{1}{1+\frac{x}{4} } \right)[/tex]
[tex]\frac{4\cdot x^{2}}{4+x}[/tex]
Based on power and series properties and most common Taylor series- derived formulas, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex] represents a Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex]. [tex]\blacksquare[/tex]
To learn more on Taylor series, we kindly invite to check this verified question: https://brainly.com/question/12800011
A tank filled with water begins draining. The number of minutes t since the water began draining from the tank is a function of the number of gallons of water in the tank, v. We will call this function f so that f(t) = v.
Required:
a. Using function notation, represent the of gallons of water in me tank 4 minutes after the water darning from the Ink.
b. Suppose that f(4) = 7, what does this mean in the context of the problem?
Answer:
[tex](a)\ f(4) = v[/tex]
(b) There are 7 gallons left in the tank after 4 minuted
Step-by-step explanation:
Given
[tex]f(t) = v[/tex]
[tex]t \to[/tex] time since water began draining
[tex]v \to[/tex] gallons in the tank
Solving (a): Notation for gallons remaining at 4 minutes
This means that [tex]t=4[/tex]
[tex]f(t) = v[/tex] becomes
[tex]f(4) = v[/tex]
Solving (b): Interpret f(4) = 7
We have:
[tex]f(t) = v[/tex]
[tex]t \to[/tex] time since water began draining
[tex]v \to[/tex] gallons in the tank
This means that:
[tex]t =4[/tex]
[tex]v =7[/tex]
It can be interpreted as:
There are 7 gallons left in the tank after 4 minuted
which ecpression is the simplest form of 3(3x-4)-5(x+3)
[tex]\boxed{ \sf{Answer}} [/tex]
[tex] \sf \: 3(3x - 4) - 5(x + 3) \\ \sf =( 3 \times 3x) - (3 \times 4) + ( - 5 \times x) +( - 5 \times 3 ) \\ \sf = 9x - 12 - 5x - 15 \\ \sf = 9x - 5x - 12 - 15 \\ = \underline{ \bf 4x - 27}[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
[tex]\\ \sf\longmapsto 3(3x-4)-5(x+3)[/tex]
[tex]\\ \sf\longmapsto 9x-12-5x-15[/tex]
[tex]\\ \sf\longmapsto 9x-5x-15-12[/tex]
[tex]\\ \sf\longmapsto (9-5)x-27[/tex]
[tex]\\ \sf\longmapsto 4x-27[/tex]
Consider an urn initially containing n balls, numbered 1 through n, and suppose that balls will be randomly drawn from the urn, one by one, and without replacement (so that after n draws, it is empty). Letting X be the number of successes that will occur, where a success is considered to occur on the ith draw if the ball obtained is numbered i or smaller, give the expected value of X. (E.g., if n = 5, and the balls are drawn in the order 3, 1, 5, 4, 2, then x = 3, because the 2nd, 4th, and 5th draws result in successes, but the 1st and 3rd draws don’t.)
[tex]\sqrt{25}[/tex]=?
[tex]Hello[/tex] [tex]There[/tex]
The answer is...
[tex]5.[/tex]
[tex]HopeThisHelps!![/tex]
[tex]AnimeVines[/tex]
4y-3 answer please I’ll mark the brainiest
Answer:
4y-3=0
4y = 3
y = 3/4
Step-by-step explanation:
1. equal to zero so you can start moving to the other side
2. bring three over becomes positive.
3. divide by 4 to let y stand alone, remember you are solving for the y.
that's all!
I need help on this 20 points
Answer:
4^15
Step-by-step explanation:
We know a^b^c = a^(b*c)
4^3^5
4^(3*5)
4^15
The diameter of a sphere is 4 cm. Which represents the volume of the sphere?
32/3 πcm^3
8 πcm^3
64/3 πcm^3
16 π cm^3
Answer:
V = 32/3 pi cm^3
Step-by-step explanation:
The volume of a sphere is given by
V = 4/3 pi r^3
The diameter is 4 so the radius is d/2 = 4/2 = 2
V = 4/3 pi (2)^3
V = 32/3 pi cm^3
Which of the following expressions is equal to tan205°?
tan55°
tan25°
tan25°
Answer:
the write answer to your question is tan 25 degree
The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the improper integral L{f(t)}(s) = infinity 0 e-st.f(t)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of as a fixed constant)
1. Find L{t}. (hint: remember integration by parts)
A. 1
B. -1/s2
C. 0
D. 1/s2
E. -s2
F. None of these
2. Find L{1}.
a.1/s
b. 1
c. 0
d. -s
e. -1/s
f. none of these
(1) D
[tex]L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt[/tex]
Integrate by parts, taking
[tex]u = t \implies \mathrm du=\mathrm dt[/tex]
[tex]\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}[/tex]
Then
[tex]L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}[/tex]
(2) A
[tex]L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}[/tex]
write your answer in simplest radical form
Answer:
s = 17
Step-by-step explanation:
Using the tangent ratio in the right triangle and the exact value
tan60° = [tex]\sqrt{3}[/tex] , then
tan60° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{17\sqrt{3} }{s}[/tex] = [tex]\sqrt{3}[/tex] ( multiply both sides by s )
s × [tex]\sqrt{3}[/tex] = 17[tex]\sqrt{3}[/tex] ( divide both sides by [tex]\sqrt{3}[/tex] )
s = 17
What is the solution to log (9x)-log, 3 - 3?
O X
col 00
8
X =
3
O x=3
OX=9
Answer:
x = 8/3
Step-by-step explanation:
Log₂(9x) – Log₂3 = 3
The value of x can be obtained as follow:
Log₂(9x) – Log₂3 = 3
Recall
Log M – Log N = Log (M/N)
Thus,
Log₂(9x) – Log₂3 = 3
Log₂(9x/3) = 3
Log₂3x = 3
3x = 2³
3x = 8
Divide both side by 3
x = 8/3
An urn contains 5 blue marbles and 4 yellow marbles. One marble is removed, its color noted, and not replaced. A second marble is removed and its color is noted.
(a) What is the probability that both marbles are blue? yellow?
(b) What is the probability that exactly one marble is blue?
Answer:
(a)The probability that both marbles are blue=5/18
The probability that both marbles are yellow=1/6
(b)The probability that exactly one marble is blue=5/9
Step-by-step explanation:
Blue marbles=5
Yellow marbles=4
Total marbles=5+4=9
(a)
Probability of drawing first blue marble=5/9
Probability of drawing second blue marble without replacement=4/8
The probability that both marbles are blue
[tex]=\frac{5}{9}\times \frac{4}{8}=\frac{5}{18}[/tex]
Probability of drawing first yellow marble=4/9
Probability of drawing second yellow marble without replacement=3/8
The probability that both marbles are yellow
[tex]=\frac{4}{9}\times \frac{3}{8}=\frac{1}{6}[/tex]
(b)
The probability that exactly one marble is blue
=Probability of first blue marble (Probability of second yellow marble)+Probability of first yellow marble (Probability of second blue marble)
The probability that exactly one marble is blue
=[tex]\frac{5}{9}\times \frac{4}{8}+\frac{4}{9}\times \frac{5}{8}[/tex]
=[tex]\frac{5}{18}+\frac{5}{18}[/tex]
=[tex]\frac{10}{18}=\frac{5}{9}[/tex]
An empty freight train traveled 60 miles from an auto assembly plant to an oil refinery. There, its tank cars were filled with petroleum products, and it returned on the same route to the plant. The total travel time for the train was 4 1 2 hours. If the train traveled 20 mph slower with the tank cars full, how fast did the train travel in each direction
Answer:
On the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.
Step-by-step explanation:
Since an empty freight train traveled 60 miles from an auto assembly plant to an oil refinery, and there, its tank cars were filled with petroleum products, and it returned on the same route to the plant, and the total travel time for the train was 4.5 hours, if the train traveled 20 mph slower with the tank cars full, to determine how fast did the train travel in each direction the following calculation must be performed:
60/20 = 3
60/40 = 1.5
60/20 = 3
3 + 1.5 = 4.5
Therefore, on the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.
Find the area of the quadrilateral and round to the nearest tenth
Answer:
24
Step-by-step explanation:
(4+8)×4/2
= 12×4/2
= 24
Answered by GAUTHMATH
When the F test is used to test the overall significance of a multiple regression model, if the null hypothesis is rejected, it can be concluded that all of the independent variables x1, x2, . . . , xk are significantly related to the dependent variable y.
A. True
B. False
Answer:
False
Step-by-step explanation:
When the Ftest is used to test the overall significance of a multiple regression model, it evaluates the significance of independent variables to the outcome of the regression model. The null hypothesis of an Ftest when used for multiple regression is that, the independent variables aren't significant in the outcome of the regression model while the alternative Hypothesis claims that the independent variables are significant .
For the overall significance evaluation, once one of the independent variables proves significant, then the overall Ftest is significant, that is it does not require that all individual independent variables are significant. The null only stands when all the independent variables are insignificant.
Therefore, the overall Ftest for significance isn't enough to prove that all individual. Independent variables are significant when the null is rejected.
The hypotenuse of a right triangle is two more than the length of one of its legs. Find the side lengths of the right triangle given the perimeter= 60 and it's area= 120
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Answer:
10 and 24
Step-by-step explanation:
We know that some of the Pythagorean triples that appear in math problems are (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17).
These have (perimeter, area) values of (12, 6), (30, 30), (56, 84), (40, 60).
For some scale factor n, we want (p·n, a·n²) = (60, 120). Of the triangles listed, we see that the (5, 12, 13) triangle scaled by n=2 will satisfy the problem requirements. (30·2, 30·2²) = (60, 120)
The side lengths are 10 and 24.
__
Check
For the side lengths we found, the perimeter is 10+24+26 = 60; the area is 1/2(10)(24) = 120. The hypotenuse is 2×13 = 26 = 24+2.
__
In the attached, one side is x, the other is y. The hypotenuse is (x+2). The square root equation comes from ...
x² +y² = (x+2)² ⇒ y² = (x² +4x +4) -x² ⇒ y² = 4x +4 = 4(x +1)
_____
Additional comment
The graph shows the solution of the various constraints. At least, the combination of constraints will give a quadratic equation in x. They can be combined in a way that gives a cubic equation in x. Either way, we prefer the graphical or "guess and check" approach (above) as being easier to do.
Using the third equation in the attachment to write an expression for y, we have ...
y = 58 -2x
Substituting that into the second equation gives ...
(x(58 -2x)/2 = 120
29x -x² = 120
x² -29x +120 = 0
(x -5)(x -24) = 0 . . . . x = 5 or 24.
The root x=5 is a legitimate solution to the pair of equations we chose to solve. The line y=58-2x intersects the hyperbola xy/2 = 120 in two places. However, (x, y) = (5, 48) does not satisfy the hypotenuse requirement that x+2 > y.
A particle moves along line segments from the origin to the points (3, 0, 0), (3, 4, 1), (0, 4, 1), and back to the origin under the influence of the force field F(x, y, z) = z^2i + 4xyj + 5y^2k. Use Stokes' Theorem to find the work done.
Answer:
the first option because I took the test
What is the solution of log3x + 4 4096 = 4?
Step-by-step explanation:
X= - 1
X=0
X=4/3
X=3
We solve for x by simplifying both sides of the equation, then isolate the variable.
Answer :
C (x=4/3)
help again please i need to pass this
√50x³y
= √5²×2×x²×x×y
= 5x√2xy
d is the correct answer
Answer:
here
Step-by-step explanation:
A record store owner finds that 20% of customers entering her store make a purchase. One morning 180 people, who can be regarded as a random sample of all customers, enter the store.
a. What is the mean of the distribution of the sample proportion of customers making a purchase?
b) What is the variance of the sample proportion?
c) What is the standard error of the sample proportion?
d) What is the probability that the sample proportion is less than 0.15?
Answer:
a) 0.2
b) 0.0009
c) 0.0298
d) 0.0465 = 4.65% probability that the sample proportion is less than 0.15.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
20% of customers entering her store make a purchase.
This means that [tex]p = 0.2[/tex]
180 people
This means that [tex]n = 180[/tex]
a. What is the mean of the distribution of the sample proportion of customers making a purchase?
By the Central Limit Theorem, [tex]\mu = p = 0.2[/tex].
b) What is the variance of the sample proportion?
The standard deviation is:
[tex]s = \sqrt{\frac{0.2*0.8}{180}} = 0.0298[/tex]
Variance is the square of the standard deviation, so:
[tex]s^2 = (0.0298)^2 = 0.0009[/tex]
c) What is the standard error of the sample proportion?
As found in the previous item, 0.0298.
d) What is the probability that the sample proportion is less than 0.15?
This is the p-value of Z when X = 0.15. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.15 - 0.20}{0.0298}[/tex]
[tex]Z = -1.68[/tex]
[tex]Z = -1.68[/tex] has a p-value of 0.0465.
0.0465 = 4.65% probability that the sample proportion is less than 0.15.
