A roller coaster car may be approximated by a block of mass m
m
. The car, which starts from rest, is released at a height h
h
above the ground and slides along a frictionless track. The car encounters a loop of radius R
R
, as shown. Assume that the initial height h
h
is great enough so that the car never loses contact with the track.

Answers

Answer 1

At height h , potential energy of coaster car  having mass m = mgh .

The car will lose potential energy and gain kinetic energy.

height lost by car when it is at the top of loop of radius R

= h - 2R

potential energy lost = mg ( h - 2R )

kinetic energy gained = mg ( h - 2R )

kinetic energy = 0 + mg ( h - 2R )

= mg ( h - 2R )

b )

For the car to remain in contact with the track , if v be the minimum velocity

centripetal force at top = mg

m v² / R = mg

v² = gR

kinetic energy = 1/2 mv²

= 1/2 m x gR

= mgR /

If h be the minimum height that can give this kinetic energy

mg ( h - 2R ) = mgR / 2

h - 2R = R / 2

h = 2.5 R

Therefore, the height of the roller coaster will be 2.5 R.

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Related Questions

the distances to the nearest 100,000 or so stars can be measured by which of the following techniques? group of answer choices redshift triangulation brightness-distance techniques radar ranging measuring tape

Answers

Triangulation can be used to calculate the separations between the closest 100,000 or so stars.

What is the triangulation method of measuring distance?

A surveying technique called triangulation measures the angles of a triangle made up of three survey control sites. The additional dimensions there in triangle are determined using geometry and the reported length of always one side.

Why is the procedure of triangulation used?

A process of analyzing study results using many data collection methods is known as triangulation. It serves three key functions: to improve validity, to paint a clearer image of a study problem, and to examine various approaches to problem-solving.

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Part A
Give a combination of four quantum numbers that could be assigned to an electron occupying a 5p orbital.
Express your answers using one significant figure. Enter your answers separated by commas.
Part B
Do the same for an electron occupying a 6d orbital.
Express your answers using one significant figure. Enter your answers separated by commas.

Answers

Part A

The combination of 5 P orbital is :

n=5,l=1,ml=−1,ms=+[tex]\frac{1}{2}[/tex]

Part B

n = 6

l = 2

m​​​​​​l = 2 or 1 or 0 or -1 or -2

m​​​​​​s = +1/2  or -1/2

A total of four quantum numbers are used to fully describe the motion and orbit of each electron in an atom. The combination of all quantum numbers of all electrons in an atom is described by a wavefunction corresponding to the Schrödinger equation. Each electron in an atom has a unique set of quantum numbers. According to the Pauli exclusion principle, no two electrons can have the same combination of four quantum numbers. Quantum numbers are important because they can be used to determine the electron configuration of atoms and the putative positions of electrons in atoms. Quantum numbers are also used to understand other properties of atoms such as: B. Ionization energy and atomic radius.

Atoms have four quantum numbers. They are the principal quantum number (n), the orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms). The principal quantum number n describes the energy of an electron and its most probable distance from the nucleus. In other words, it refers to the size and energy level of the orbital in which the electron is placed. The number of subshells or l describes the shape of the orbitals. It can also be used to determine the number of angular nodes. The magnetic quantum number ml represents the energy level in the subshell and ms represents the electron spin. This is either upwards or downwards.

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Which phrase best defines momentum?
A. the change in velocity of an object over time
B. the amount of matter in an object
C. the distance traveled by and object over time
D. the motion of an object

Answers

Answer: the motion of an object

Explanation:

I just took the test

Answer:the motion of an object

Explanation:

I finished the sample work

planck introduces quantized exchange of energy between the fundamental modes of vibration in the blackbody emitter with the universe.T/F

Answers

Planck introduces quantized exchange of energy between the fundamental modes of vibration  is true statement.

In 1900, Planck proposed that the energy of the oscillators (or "modes of vibration") in a blackbody emitter could only be exchanged in discrete packets or "quanta" rather than continuously. This idea was revolutionary at the time, as it went against the classical laws of physics that had been accepted for centuries. Planck's theory was able to explain the observed blackbody spectrum much more accurately than classical theories, and it laid the foundation for the development of quantum mechanics.

However, it is important to note that Planck's theory did not fully explain the behavior of blackbody emitters. It was later refined and extended by other physicists, including Albert Einstein and Niels Bohr, who developed a more complete theory of quantum mechanics.

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The depth of snow after n hours of a snowstorm is

Answers

The depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.

A polynomial function exists as a function that examines only non-negative integer powers or only positive integer exponents of a variable in a formula like the quadratic equation, cubic equation, etc.

Given, depth of the snow after n hours of a snowstorm exists represented by the function f(n+1) = f(n) + 0.8 where, f(0) = 2.5

To find, which statement explains the sequence of numbers rendered by the function.

Given function f(n + 1) = f(n) + 0.8 where f(0) = 2.5

Hence, the depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.

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Speed of a body spinning about an axis increases from rest to 100 rpm in 5 second if a constant torque is applied. The external torque is then removed and the body comes to rest in 100sec due to friction Find the frictional torque.

Answers

All of the following are internal factors that may negatively affect an individual with dementia EXCEPT A. frustration.

What is dementia's medical condition?

Dementia is a medical condition capable of altering individual skills to remember and also to reason during decision-making, which is due to irreversible degeneration of neuronal cells in the brain that lead to a complete state or a false sense of reality in the individual according to the surrounding environmental conditions.

Dementia medical conditions are often associated with aging because they may lead to different degenerative neuronal problems, which must be treated in a proper clinical setting since the person is unable to live in normal conditions on his or her own.

Therefore, with this data, we can see that dementia medical condition that must be treated in clinical medical settings and it is associated with an irreversible loss of neuronal networks in the brain.

Complete question:

All of the following are internal factors that may negatively affect an individual with dementia EXCEPT:

Frustation

Fear and confusion

False beliefs

Fatigue

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The frictional torque of the spinning body is determined as  ( I × 2.1 ) N/m.

What is frictional torque?

Friction torque is the force between two objects that causes one of them to rotate around an axis.

Also, friction torque is the torque caused by the frictional force that occurs when two objects in contact move.

The frictional torque is calculated by applying the following equation as shown below.

τ = Iα

where;

I is the moment of inertia of the bodyα is the angular acceleration of the body

The angular acceleration of the body is calculated by applying the following equation as shown below.

α = Δω / Δt

α = ( ωf - ωi ) / ( t₂ - t₁)

where;

ωf is the final angular velocity of the body = 100 rpm ωi is the initial angular acceleration of the bodyt₁ is the initial time of motion of the bodyt₂ is the final time of motion of the body

α = ( ωf - ωi ) / ( t₂ - t₁)

ωf = 100 rev/min x 2π rad/rev x 1 min / 60s = 10.5 rad/s

α = ( 10.5 - 0 ) / ( 5 - 0 )

α = 2.1 rad/s²

The frictional torque is calculated as follows;

τ = Iα

τ = ( I × 2.1 ) N/m

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What are the indicators of motion in relation to a reference point?; What are the terms used in describing the motion?; How do you described the motion of the object?; What is describing motion and give example?; Why is it important to identify a reference point for any description of motion?; What describes the rate of motion and the direction?

Answers

Indicators of motion in relation to a reference point include distance, displacement, speed, velocity, acceleration, and deceleration.

The terms used in describing motion include linear motion, angular motion, rotational motion, and oscillatory motion.

To describe the motion of an object, one would use words such as move, accelerate, decelerate, rotate, and vibrate.

Describing motion is the process of quantifying changes in position, direction, and velocity over time. For example, when a ball is thrown, one can describe its motion by noting its initial position, the direction of its throw, and how fast it is moving.

It is important to identify a reference point for any description of motion because it provides context for the motion. Without a reference point, it would be impossible to accurately quantify motion.

Speed and velocity describe the rate of motion, and direction describes the orientation of motion.

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A motorcycle is travelling at a constant velocity of 30ms. The motor is in high gear and emits a hum of 700Hz. The speed of sound in air is 340ms, and there is no wind.Part AWhat is the period of the sound waves emitted from the motorcycle?Part BWhat is the distance travelled by the motorcycle during one period of the sound oscillation?Part CWhat is the distance travelled by a sound wave in air during one period of oscillation?Part DThe humming of the motorcycle is a sound that is emitted in all directions and, once emitted, it travels in the reference frame of the still air at the speed of sound in air. Consider the emitted sound that is moving directly out in front of the motorcycle

Answers

a) The period of the sound waves emitted from the motorcycle is  [tex]$T=1.43 \times 10^{-3} \mathrm{~s}$[/tex]

b) The distance travelled by the motorcycle during one period of the sound oscillation is  [tex]$d=0.0429 \mathrm{~m}$[/tex]

c)The distance travelled by a sound wave in air during one period of oscillation is  [tex]$\lambda=0.4857 \mathrm{~m}$[/tex]

d)The humming of the motorcycle is a sound that is emitted in all directions and, once emitted, it travels in the reference frame of the still air at the speed of sound in air is  [tex]$f_o=767.7 \mathrm{~Hz}$[/tex].

What is  frequency?'

Frequency is the number of occurrences of a repeating event per unit of time. It is also occasionally referred to as temporal frequency for clarity, and is distinct from angular frequency. Frequency is measured in hertz which is equal to one event per second.

(a)

We know time period is inverse of frequency:

Mathematically:

[tex]$$\begin{aligned}& T=\frac{1}{f} \\& T=\frac{1}{700} \\& T=1.43 \times 10^{-3} \mathrm{~s}\end{aligned}$$[/tex]

(b)

Distance travelled by the motorcycle during one period of sound oscillation:

[tex]$$\begin{aligned}& d=v_s . T \\& d=30 \times 1.43 \times 10^{-3} \\& d=0.0429 \mathrm{~m}\end{aligned}$$[/tex]

(c)

The distance travelled by the sound during the period of one oscillation is its wavelength.

[tex]$$\begin{aligned}& \lambda=\frac{S}{f} \\& \lambda=\frac{340}{700} \\& \lambda=0.4857 \mathrm{~m}\end{aligned}$$[/tex]

(d)

observer frequency with respect to a stationary observer:

According to the Doppler's effect:

[tex]$\frac{f_0}{f_u}=\frac{S+v_0}{S-v_n}$[/tex]

where:

[tex]$f_o \& v_o$[/tex] are the observed frequency and the velocity of observer respectively.

Here, observer is stationary.

[tex]\therefore v_o=0 \mathrm{~m} \cdot \mathrm{s}^{-1}$$[/tex]

Now, putting values in eq. (1)

[tex]$$\begin{aligned}& \frac{f_a}{700}=\frac{340+0}{340-30} \\& f_o=767.7 \mathrm{~Hz}\end{aligned}$$[/tex]

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Which describes an object in a projectile motion?; What is projectile motion ?; What direction does gravity act on a projectile?; How do you describe a path in projectile motion?

Answers

Projectile motion is the movement of an object in the curved path toward the ground as it has both a horizontal force and the downward force of gravity acting on it.

Projectile motion is the movement of an item thrown or projected into the air, situation to only the acceleration of gravity. The item is referred to as a projectile, and its path is referred to as its trajectory.

The path of a projectile is parabolic. at some point in the motion, the acceleration of the projectile is steady and acts vertically downwards being identical to g.

Projectile movement is the movement of an item thrown up within the air at a perspective from the horizontal (or floor) with the item shifting below gravitational acceleration pointed vertically downwards, Now depending on the perspective of projection.

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A certain force 1 gives an object an acceleration of 6×10^6 m. Another force F2 gives the same object an acceleration of 15×10^6 m. What is the acceleration of the object if the two forces act on the object at 90°to each other?​

Answers

The total acceleration of the object is 3×10^6 m/s.

To find the total acceleration, we can use the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle (c) is equal to the sum of the squares of the other two sides (a and b). In this case, the magnitudes of the two accelerations (a and b) are 6×10^6 m/s^2 and 15×10^6 m/s^2, respectively.

Therefore, we can use the formula a^2 + b^2 = c^2 to find the magnitude of the total acceleration:

6×10^6 m/s^2 + 15×10^6 m/s^2 = c^2

c = sqrt(6×10^6 m/s^2 + 15×10^6 m/s^2)

= sqrt(21×10^6 m/s^2)

= 3×10^6 m/s

So, the total acceleration of the object is 3×10^6 m/s. This is the result of the two forces acting on the object at 90 degrees to each other.

The total acceleration of the object is 3×10^6 m/s.

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Answer:

1.5x10⁷ m/s²

Explanation:

Acceleration is a vector, so this is a case of vector addition.  Let R = resultant vector.

R² = a-F₁² + a-F₂²

R = √(6x10⁶)² + (15x10⁶)²

R = √2.25x10¹⁴ = 1.5x10⁷ m/s²

part a part complete what is the amplitude of this wave? express your answer in centimeters to two significant figures. a

Answers

The particle's maximum displacement from its mean position is measured by its amplitude, which in the graph equals 6 cm. The wavelength is 1.20 nm, and the frequency is 1.67 hz.

A periodic wave's wavelength, or the distance over which the wave's shape repeats, is its spatial period. It is the separation between adjacent spots on a wave that correspond to the same phase. Displacement refers to the idea that something has moved or been shifted. The term "displacement" refers to a shift in an object's position. The following equation serves as a mathematical definition of it: is used to describe the final position's value.

f = 1/T f = 1/0.6 f = 1.67 mHz is the frequency.

Wavelength and frequency are combined to form the wave's speed.

v = f (lamda) lamda = v/f

lamda = v/f

lamda = 2/1.67

lamda = 1.20m

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The complete question is -

part a part complete what is the amplitude of this wave? express your answer in centimeters to two significant figures.

A) What is the amplitude of this wave?

B) What is the frequency of this wave? Express your answer to three significant figures and include the appropriate units.

C) What is the wavelength of this wave?

24. Circle each letter beside something that continues to happen as long as the
switch is closed in the primary circuit.
a. A current flows in the secondary circuit.
b. A voltage is applied across the secondary circuit.
c. A magnetic field exists around the primary coil.
d. A magnetic field exists around the secondary coil.

Answers

When the switch in the primary circuit is closed, the following continue to happen:

1. the current flows in the secondary circuit

2. voltage is supplied across the secondary circuit and

3. A magnetic field exist around the primary coil.

What happens when the primary circuit is closed?

Closing the switch in the primary circuit produces a constant electric current in the conducting wire. This constant electric current produces a magnetic field in the primary coil. The soft-iron ring enhances the strength of the magnetic field, and the ring itself becomes magnetized.

The primary circuit refers to the input section of an isolated power supply, which is connected to the AC mains. This section of the power supply has dangerous voltage levels and not designed to be directly accessed by users.

Therefore when the primary circuit switch is closed, the current flows in the secondary circuit, a voltage is supplied across the secondary circuit and a magnetic field exist around the primary coil.

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determine the force in members ge gc and bc state if the members are in tension or compression 10 10 10 10 1000 lb

Answers

The force in members ge gc and bc state if the members are in tension or compression Fge = 666.66 lb (C),Fgc = 417.4 lb (T),Fbc = 333.33 lb (T)

The forces:

∑Fy = 0        

Va+Vb = 1000

∑Fx = 0

MOD = 0

Va*30 - 1000*10 = 0

Va=333.33 lb

Vd=666.67 lb

take section X-X

∑Fx = 0

Fge+ Fgc cos45 + Fbc = 0

∑Fy = 0

Fgc cos45 - 333.33 = 0

Fgc = 333.33/cos45

Fgc = 471.4 lb

MOG = 0

333.33*10 - Fbc*10=0

Fbc = 333.33 lb

From equation above

Fge+471.4*cos45+333.33 = 0

Fge = -666.66 lb

Answer

Fge = 666.66 lb (C)

Fgc = 417.4 lb (T)

Fbc = 333.33 lb (T)

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everything looks red through a red filter because everything looks red through a red filter because the filter reflects red light and transmits other colors. the filter emits red light and absorbs other colors. the filter absorbs red light and emits other colors. the filter transmits red light and absorbs other colors.

Answers

Everything looks red through a red filter because the filter transmits red light and absorbs other colours

The perception of colour is generated because of the difference in the frequencies or wavelengths of light that enter into our eyes. Different colours are characterized by different frequencies.

The colour of light reflected back by an object determines the colour of that object. For example, if an object absorbs all the colours of white light except red, then it will appear red in colour. If the light striking that object does not contain a red component, then no light will be reflected by the object and that object will appear black in colour.

Similarly, a filter works by filtering out one or more colours from light that passes through it. The colour that appears through a filter is the one that is allowed by a filter.

Hence, a red filter will only allow red light to pass through it and will block out the rest.

So, Option (d) is the correct choice.

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A sailor strikes the side of his ship just below the waterline. He hears the
echo of the sound reflected from the ocean floor directly below 2.02 s later
How deep is the ocean at this point? (Speed of sound in water=1500m/s)

Answers

At this location, the ocean lies 1515 meters deep.

What does "sound" mean in physics?

Particles that are vibrating make up sound waves. These collide with other particles, causing them tp vibrate, which allows the sound to escape the source. Your ear drums vibrate as a result of air vibrations, which allows you to perceive sound. This vibration is transformed into messages, which proceed to your brain via a nerve.

Briefing:

Let the sound speed in sea water be 1500 m/s.

If he hears the echo 3.5s after the strike,

then the sound would have traveled a distance of:

                         1500 * 2.02 = 3030 m to the bottom and back.

This would mean the ocean is 3030 / 2 = 1515 m deep.

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b(4+a) ;where a = 6 and b - 2

Answers

= 2(4+6)

= 2×10

= 20

HOPE IT HELPS !!!!!!!!

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A mass oscillates on a spring with a period T and an amplitude 0.48 cm. The mass is at the equilibrium position x = 0 at t = 0, and is moving in the positive direction. Where is the mass at the times (a) t = T/8, (b) t = T/4, (c) t = T/2 and (d) t = 3T/4? (e) Plot your results for parts (a)through (d) with the vertical axis representing position and the horizontal axis representing time.

Answers

On a spring, mass oscillates with an amplitude and a time T. at T=3t/4 the mass will be at 0.48cm away from its mean postion.

What is SHM?

Simple harmonic motion is described as the periodic motion of a point across a single direction with an acceleration that is always toward a fixed point in that lines and a distance from that point that is proportional to that acceleration.

Briefing:

Mass at the time t = 3T/4

Given T=T, A=0.48cm

φ = -π/2 , x=0, t=0

ω = 2π/T

The position of SHM is given by:

x(t) = Acos(ωt+φ)

x(3T/4) = 0.48cos((2π/T)(3T/4)+(-π/2))

x = 0.48cos(π) = -0.48

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A parallel plate capacitor using a dielectric material having a dielectric constant of 2.5 has a plate separation of 1-mm. If another material having a dielectric constant of 4.0 is used and the capacitance is to be unchanged, what must be the new spacing between the plates?

Answers

The new spacing between the plates is 1.6mm

What is capacitor?

A capacitor is a device that uses the accumulation of electric charges on two nearby surfaces that are electrically isolated from one another to store electrical energy in an electric field. It has two terminals and is a passive electrical component. The effect of a capacitor is known as capacitance.

What is dielectric constant?

A substance or material's capacity to hold electrical energy is indicated by its dielectric constant. It is a measurement of how much electric flux a substance can hold or concentrate.

Dielectric constant k = 2.5

Separation between the plates d = 1 mm

Dielectric constant k ' = 4

let new separation between the plates = d '

We know C = k A / d

In both cases C ,A are constant .

So, ( k ' / k ) = ( d ' / d)

d ' = d ( k ' / k )

= 1.6 mm

The new spacing between the plates is 1.6mm

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A water tank is 1/8 full. the tank is 3/4 full when 42 gallons of water are added to the tank. how much water can the tank hold?

Answers

The tank can hold a water of volume 67.2gallons

What is volume?

Volume is defined as the space occupied within the boundaries of an object in three-dimensional space. It is also known as the capacity of the object.

The capacity of an object can be measured in litres, gallon , cm³ e.t.c.

The tank is 1/8 full, when 42 gallons of water is added it is 3/4 full.

Therefore the fraction of water added is 3/4-1/8= 5/8.

This means 5/8 of the tank is 42 gallons. Therefore if 5/8 of the tank = 42gallons,

full tank will be 42× 8/5

= 67.2 gallons

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a 0.35-kgkg croquet ball is initially at rest on the grass. when the ball is struck by a mallet, the average force exerted on it is 230 nn.

Answers

The mallet is in contact with the croquet ball in the grass for 0.005 seconds long.

The mass of the croquet ball = 0.35 kg

The speed at which the ball struck = 3.1 m/s

The force exerted on the ball = 230 N

The total time when the mallet is in contact with the ball can be found using the formula,

                    F = mv/t

where F is the force

           m is the mass of the ball

           v is the speed at which the ball is struck

           t is the time

Let us rearrange it,

                  t = mv/F

Let us substitute the known values in the above equation, we get

                 t = 0.35 x 3.1 / 230

                   = 1.085 / 230

                   = 0.005 seconds

The total time when the mallet is in contact with the ball is 0.005 seconds

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one end of a spring is attached to a wall. a 20 n pull on the other end causes the spring to stretch by 2.6 cm .

Answers

One end of a spring is attached to a wall and its other end is pulled by a 20N force. The spring is strething until it reach 2.6 cm. Based on Hooke's Law, the spring constant is 769.23 N/m.

Hooke's Law states that when a spring is compressed or extended by a force, the force is proportional to the length strecth.

Spring constant represents the spring's stiffness. It describes the force needed per unit of spring extension. Spring constant and force have relationship where:

F = -k.x

F = force working on the spring

k = the spring constant

x = the spring's displacement from its equilibrium position

Based on the case, we know that:

F  = 20N

x = 2.6 cm = 0.026m

k = ?

We will use the spring constant formula to find the spring constant:

F = k.x

k = F/x

k = 20N/0.026m

k = 769.23 N/m

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Complete Question:

One end of a spring is attached to a wall. A 20N pull on the other end causes the spring to strecth by 2,6 cm. What is the spring constant?

what is the only force that can act on an object in free fall? gravity friction air resistance speed; increasing which factor will cause the gravitational force between two objects to decrease?; what determines the strength of the gravitational force of an object in space; what are the units of mass and weight; which factors affect the gravitational force between two objects select all that apply; if siobhan hits a 0.25 kg volleyball with 0.5 n of force, what is the acceleration of the ball? m/s2; what is the weight, on earth, of a book with a mass of 1.5 kg? 1.5 n 6.5 n 11.3 n 14.7 n

Answers

In Newtonian physics, free fall refers to any motion of a body in which gravity is the only force acting on it.

What are the forces at work on a falling object?

In addition, gravity is pulling something down as it falls. The force of gravity is an unbalanced force at the beginning of the fall. As a result, the object accelerates or picks up speed. It runs into aerodynamic drag or air resistance as it accelerates.

What is the force responsible for an object falling to the ground?

All objects on Earth experience weight, or a gravitational pull that is proportional to their mass and is imposed by the planet's mass. Gravity is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second.

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An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s. What is the maximum height the object reaches? What is the object's final velocity as it hits the ground? (use g=9.8 m/s^2)

Answers

The maximum height the object reaches be 5.81 m.

The object's final velocity as it hits the ground be 10.67 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s.

So, maximum height obtained by it be: H  = 5 m + (4²/2×9.8) m = 5.81 m.

The object's final velocity as it hits the ground = √(2gH)

= √(2×9.8×5.81) m/s

= 10.67 m/s.

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you know that you are following the straightest possible path through spacetime if you know that you are following the straightest possible path through spacetime if you are standing still. you are moving directly from one place to another. you are weightless.

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Your worldline is travelling through spacetime in the straightest feasible direction if you are free to move around.

If you experience weight, you are not travelling in the most direct manner.You can move around if your worldline is moving across spacetime in the most straight-line possible path. Weight means that you are not moving as directly as possible.The four dimensions of spacetime consist of one temporal dimension and three spatial dimensions, collectively known as space. We refer to our speed, which includes four components and a direction, as velocity. The four-velocity is represented by the vector U = (c,v x,v y,v z), where is the Lorentz factor.The worldline of the Earth is not round and is helical in spacetime (a curve in four dimensions).If a person could only move through space during spacetime, then space would be where they would move the fastest. Time won't exist for him, and distance will seem like a singularity to him. Since it would need an infinite amount of energy to accelerate a mass to this speed, only massless particles are capable of travelling through space at this speed.

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derive an equation for the tension string connected to the two blocks in terms of ; any physical constants

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The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension.

How do we measure tension?

When a body is suspended from items like chains, cables, strings, etc., tension is simply the drawing force at work on the body. T is used to signify it (occasionally also symbolised as Ft).

Tension formula is articulated as

T=mg+ma

Where,

T= tension (N or kg-m/s2)

g = acceleration due to gravity (9.8 m/s2)

m =Mass of the body

a = Acceleration of the moving body

For mass m, the forces are given as

T−mg=ma                                          ...... (1)

Similarly, for mass M, the forces are given as

Mg−T=Ma                                               ...... (2)

From equation (1), we have

T=mg+ma          

Substituting equation (3) in (2) we get

Mg−mg−ma=Ma

g(M−m)=a(M+m)

a=( M+m / M−m )g

T=m×( M+m / M−m )g+mg

T = g( Mm - m² +  m² + Mm / M + m) = g( 2Mm / M+m )

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Dario, a prep cook at an Italian restaurant, spins a salad spinner 20.0 times in 5.00 seconds and then stops spinning it. The salad spinner rotates 6.00 more times before it comes to rest. Assume that the spinner slows down with constant angular acceleration. What is the angular acceleration of the salad spinner as it slows down? Express your answer numerically in radians per second per second.ω = θ / t ω = 20 * 2 * π / 5.00 ω = 8π ω = 25.13272 radians/s now I can solve for α using a kinematic equation: ω2f = ω20 + 2α(θ) 02 = 25.132722 + 2 * α * (2 * π * 6.00) 0 = 631.6536 + 75.39816α 75.39816α = -631.6536 α = -8.37757 radians/s2

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The angular acceleration, which is frequently denoted by the symbol and stated in radians per second per second, is the rate at which the angular velocity changes over time. = t and = 0 for the scenario when the angular velocity is constant (nonvarying).

In layman's words, what is angular acceleration?

A spinning object's change in angular velocity per unit of time is expressed quantitatively as angular acceleration, also known as rotational acceleration. It is a vector quantity with either one of two predetermined directions or senses and a magnitude component.

What is the basic angular acceleration formula?

The rate at which angular velocity changes is referred to as angular acceleration. Angular acceleration is written as the equation: =t = t, where is the change in angular velocity and t is the change in time.

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as a care package falls from a high-flying stationary helicopter, its velocity increases and its acceleration___

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A care package drops from a stationary high-flying helicopter with increased velocity and decreased acceleration.

An item that falls through a vacuum is exposed to only one external force, the gravitational force, represented as the weight of the object. An item that is moving simply because of the influence of gravity is said to be free falling and its motion is defined by Newton’s second law of motion. With algebra we can solve for the acceleration of a free falling item. The acceleration is constant and equal to the gravitational acceleration g which is 9.8 meters per square second at sea level on the Earth. The weight, size, and form of the item are not a consideration in characterizing a free fall. A beach ball falls with the same velocity as an airplane in a vacuum.

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a friend of yours is loudly singing a single note at 386 hz while racing toward you at 23.9 m/s on a day when the speed of sound is 347 m/s .

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He hears a frequency of 413.02 Hz, and your friend hears a frequency of 409.16 Hz if you start singing at 386.

What is speed, and what is the scientific term for it?

Speed refers to the rate with which a distance varies over time. There is some degree of temporal separation. As a result, a SI unit representing speed is created by fusing the foundational unit of time with the fundamental part of distance. As a result, it appears that the Si-derived metric of speed is the meter per second.

Briefing:

n' = n ( V - V₀ ) / ( V - V s)

where V is indeed the sound's velocity.

V₀ is the velocity of observer

Vs is the velocity of source

a) n' = 386 * ( 347 ) /( 347 - 23.9 ) = 413.02 Hz

b) n' = 386 * ( 347 +23.9 ) /(347 ) = 409.16 Hz

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The complete question is-

A friend of yours is loudly singing a single note at 386 Hz while racing toward you at 23.9 m/s on a day when the speed of sound is 347 m/s.

Part A: What frequency do you hear?

Part B: What frequency does your friend hear if you suddenly start singing at 386 ?

Why does the Sun rise in the East and set in the West?

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Answer:

Below

Explanation:

Because the earth rotates from west to east .....so eastern areas will be pushed into  sunlight earlier than western portions

car b is stopped at a light when car a crashes into it moving with speed v. if the coefficient of restitution is 0, find the speeds of the two cars at the end of the impact in terms of p and v.

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Both the cars A as well as car b has zero speed after the impact.

Car b is stopped at the light when car a is crashes into it which is moving with a speed V the coefficient of restitution is given to be zero.

Because the coefficient of restitution is zero it means that the collision is perfectly inelastic in nature.

So, if the car a was moving with a speed v.

As it is already mentioned that after the collision ka bi has come to rest Swasthya the impact the speed of car b is new and because the collision is perfectly inelastic the speed of car a will also be zero.

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