The angle in radians through which the wheel rotates is [tex]14207.511^{\circ}[/tex].
What is angular velocity?
In physics, angular velocity or rotational velocity, also known as angular frequency vector, is a pseudovector representation of how fast the angular position or orientation of an object changes with time.
Given
initial angular velocity [tex]$\omega_1=25 \mathrm{rad} / \mathrm{s}$[/tex]
Final Angular velocity [tex]$\omega_2=36 \mathrm{rad} / \mathrm{s}$[/tex]
time interval [tex]$t=3 \mathrm{~s}$[/tex]
using
[tex]$$\begin{aligned}& \omega_2=\omega_1+\alpha t \\& 36=25+2 \\& \alpha=1.5 \mathrm{rad} / \mathrm{s}^2\end{aligned}$$[/tex]
(b)Average angular speed [tex]$\frac{\Delta \theta}{\Delta t}$[/tex]
[tex]$$\begin{aligned}& \theta=\omega_1 t+\frac{1}{2} \alpha t^2 \\& \theta=25 \times 8+\frac{1}{2} \times 1.5 \times 8^2 \\& \theta=200+48=248 \mathrm{rad}\end{aligned}$$[/tex]
average angular speed [tex]$=\frac{\Delta \theta}{\Delta t}$[/tex]
[tex]=\frac{248}{8}=31 \mathrm{rad} / \mathrm{s}$$[/tex]
(c)Angle rotated =248 radians
(d)angles in degree [tex]$=14207.511^{\circ}$[/tex]
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A child is flying a kite. If the kite is 90 feet above the child's hand level and the wind is blowing it on a horizontal course at 5 feet per second, the child is letting out cord at _____ feet per second when 245 feet of cord are out. Assume that the cord remains straight from hand to kite.
If the kite is 90 feet above the child's hand level and the wind is blowing it on a horizontal course at 5 feet per second, The child is letting out cord at 150 feet per second.
It's miles the price of growth of y as t increases. Loosely positioned, it is the size of the tiny increase in y that could rise up from making a tiny increase to t and setting that in the components for y.
In newtonian notation and dy/dx is leibniz notation. Newton and Leibniz independently invented calculus across the equal time so they used distinct notation to represent the equal thing (rate of change in this example).
A differential dx isn't always a actual wide variety or variable. alternatively, it is a convenient notation in calculus. it can intuitively be notion of as "a completely small alternate in x", and it makes plenty of the notation in calculus appear extra realistic.
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the correct relation for the emissive power of a diffuse, gray surface, where t is the absolute temperature is___
When t is the absolute temperature, the appropriate relationship for a diffuse, gray surface's emissive power is E = εσT^4
The energy emitted by a body per unit surface area within a unit wavelength range is known as its emissive power at a specific temperature. Stefan's constant, emissivity, and absolute temperature are all present in this equation. Kirchhoff's law states that the emissive power of a perfectly black body at a given temperature is equal to the ratio of emissive power to absorptive power for a given wavelength at a given temperature for all bodies. The diffuse-gray surface theory applies to surfaces where is wavelength-independent.
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A solenoidal coil with 30 turns of wire is wound tightly around another coil with 350 turns, The inner solenoid is 20.0 cm long and has a diameter of 2.10 cm. At a certain time, the current in the inner solenoid is 0.100 A and is increasing at a rate of 1500 A/s
Part A
For this time, calculate the average magnetic flux through each turn of the inner solenoid.
Part B
For this time, calculate the mutual inductance of the two solenoids.
The average magnetic flux passing through each inner solenoid turn is 8.45966*10(-8). Because a 350-turn solenoidal coil with 30 turns of wire is firmly twisted around it.
How many magnetic lines of force are present in a specific area is determined by the magnetic flux. For instance, the magnetic flux density is lower if fewer magnetic lines cross a large area of cross section. Knowing the magnetic flux also enables us to make an educated guess about the magnitude of the magnetic field in a particular area.
Inner solenoid has a certain number of turns.
N1 = 300
In an outer solenoid, there are
N2 = 30
Internal solenoid length is
L = 21.0[cm] = 0.21[m] .21[m]
Radius of the internal solenoid
r = diameter/2=2.00[cm]/2=1.00[cm] = 0 .01[m]
Current flowing through the inner solenoid
I = 0.150[A] .150[A]
the current's rate of growth is
di/dt equals 1800[A/s].
The inner solenoid's average magnetic flux through each revolution is
B.A is equal to μ*(N/L)*i.A is equal to [4(pi)*10-7]*[300/0.21]*[0.15]*&
pi;*(0.01) = 8.45966*10^(-8)
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❧ What is Newton’s Rainbow colored disc?
Answer:
there are 7 component white light colors
What is the density of a cube that has a mass of 12.6 and a measured side length of 4.1 cm?
Answer: 0.183 g/cm³
Explanation:
density = mass/volume = m/v
m = 12.6 g (I assume grams? you didn't provide the unit)
cube has equal sides, so volume of the cube = 4.1³ = 68.9 cm³
density = 12.6g/68.9 cm³ = 0.183 g/cm³
the vectors d and e are [-4,1] and [1,4] respectively .find the angle b/n and e (Use dot product )
determine the modulus of elasticity of a composite material if the strain on the material was 0.09 and the following data are known:
If a composite material underwent a 0.09 strain, the material's modulus of elasticity be is 6.48*10⁶ psi
Ef=10.5*10⁶ psi
Em=0.45*10⁶ psi
Vf=0.6
Vm=1-Vf=0.4
Modulus of elasticity is
E=Vf.Ef+Vm.Em
=0.6*10.5*10⁶ psi+0.4*0.45*10⁶
=6.48*10⁶ psi
Therefore Modulus of elasticity E is 6.48*10⁶ psi
Young's modulus, also known as elastic modulus, tensile modulus, or modulus of elasticity in tension, is the ratio of stress to strain and is equivalent to the slope of a material's stress-strain diagram. Young's modulus is sometimes referred to as the modulus of elasticity and is equal to the longitudinal stress divided by the strain.
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a free-falling object has a speed of 30 m/s at one instant. exactly 2 seconds later its speed will be
The velocity of the freely falling body after the time 2 second is found as 49.6 m/s.
Explain the term acceleration due to gravity?Gravitational acceleration is the rate at which the speed of a body falling freely increases. Gravitational acceleration is measured in SI units of m/s², m/s², m/s².A body is considered to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.For the given question-
The freely falling body has the speed at an instant as u = 30 m/s.
Acceleration due to gravity g = 9.8 m/s².
After time t = 2 sec, the final velocity v m/s.
Using equation of motion,
v = u + gt
v = 30 + 9.8 x 2
v = 49.6 m/s.
Thus, the velocity of the freely falling body after the time 2 second is found as 49.6 m/s.
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A 2.3 kg , 20-cm-diameter turntable rotates at 150rpm on frictionless bearings. Two 550 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.What is the turntable's angular velocity, in rpm, just after this event
The turntable's angular velocity, in rpm, just after this event is ω(f) = 78.40 rpm
I'll suppose that the turntable is a solid disc with a moment of inertia of 0.5Mr2 and that the blocks stick out from the edge of the turntable, each 10cm (0.10 m) from the turntable's centre. This is the conservation equation:
0.5Mr²ω(i) = 0.5Mr²ω(f) + m₁r²ω(f) + m₂r²ω(f) ----(but m₁ = m₂ = m)
Mr²ω(i) = Mr²ω(f) + 4mr²ω(f)
Mr²ω(i) = ω(f)r²(M + 4m)
ω(f) = Mω(i) / (M + 4m)
ω(f) = (2.3kg)(150 rpm) / [2.3kg + (4 x 0.55 kg)]
The turntable's angular velocity, in rpm, just after this event is ω(f) = 78.40 rpm
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this photograph shows three rock layers separated by two disconformities, as exposed in the walls of the grand canyon. one disconformity is above the reddish lens of devonian sedimentary rocks, and the other disconformity is below the reddish lens of devonian sedimentary rocks. drag the events so that they are in the correct order, from oldest at the bottom (6) to youngest at the top (1).
1 . Erosion that formed the Grand Canyon in which the layers are exposed
2. Deposition of Devonian ‘sedimentary rocksDeposition of the Mississippian Limestone .
3 .Withdrawal of the seas and erosion that formed the lower disconformity
4. Deposition of Cambrian Limestone.
Sedimentary rocks form at or near the surface of the earth, in contrast to metamorphic or igneous rocks that form deep within the earth. The main geological processes leading to the formation of sedimentary rocks are erosion, weathering, dissolution, precipitation and petrification.
Erosion and weathering include the effects of wind and rain that slowly break large rocks down into smaller rocks. Erosion and weathering turn rocks and even mountains into sediments such as sand and mud. Dissolution is a form of weathering, chemical weathering. During this process, the slightly acidic water slowly wears away the stone. These three processes create new sedimentary rock sources.
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a pile driver lifts a 200 kg weight and then lets it fall onto the end of a steel pipe that needs to be driven into the ground. a fall of 1.5 m before striking the pipe drives the pipe in 45 cm. What is the average force exerted on the pipe?
The average force exerted on the steel pipe due to the mass is 8666.7 N.
The mass that the pile driver lift up is 200kg up to a height of 1.5 m and then it is dropped on a steel pipe to dig it till a distance of 45cm.
So, we can write,
Work done by the mass = world done on the steel pipe
MgH = Fx
Where,
M is the mass,
g is the gravitational acceleration,
H is the height to which the mass is lifted,
F is the average force exerted on the steel pipe,
x is the distance to which the steep pipe goes down.
Putting values,
200(10)(1.95) = F(0.45)
F = 8666.7 N.
The average force exerted on the pipe is 8666.7N.
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(True or False) the energy carried by a photon of ir radiation is greater than the energy carried by a photon of uv radiation.
Answer:
false
ir = infrared radiation ....? right?
Two long parallel copper wires carry currents of 5A each in opposite directions. If the wires are separated by a distance of 0.5m , then the force between the two wires is
A. 10â5N, attractive
B. 10â5N repulsive
C. 2Ã10â5N, attractive
D. 2Ã10â5N,repulsive
The force between the two wires is 10^-5 N repulsive. option B is the correct answer
The force is repulsive because the currents are in opposition.
From the question, we have
force (F)= μ*i1*i2/2πd
=2*10^-7*5*5/0.5
=10^-5 N
The force between the two wires is 10^-5 N repulsive.
Force:
Physics defines a force as an influence that has the power to change an object's motion. When changing its velocity, such as when moving away from rest, a massed object may accelerate as a result of a force. Being pushed or pulled is a simple way to convey force. Given its magnitude and direction, a force is a vector quantity. Using the newton SI unit, it is computed (N). The letter F represents force. As pushes or pulls are seen as forces, this can provide a clear explanation of how forces are described.
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imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g
Mass of the Earth, M = 6 * 10²⁴
m = 200 kg
R = 6.4 * 10⁶
G = 6.67 * 10¹¹ Nm²/kg²
Height of the satellite, h = 300 km = 3 * 10⁵ m
Total energy of the satellite at height h = 1/2mv² + [G(M*m)/(R+h)]
Orbital velocity of the satellite, v = √[ (G*M) / (R+h) ]
Total energy at height h = 1/2[ (G*M) / (R+h) ]
The negative sign indicates that the satellite is bound to the Earth.
Energy required to send the satellite out of its orbit = – (Bound energy)
= GM*m/ 2(R+h)
= 6.67*10⁻¹¹ * 6*10²⁴* 200 / 2(6.4*10⁶ + 0.3*10⁶)
= 11.9*10⁹ J
If the satellite just escapes from the gravitational field, then total energy of the satellite is zero.
Therefore, we have to supply 11.9*10⁹ J of energy to just escape it.
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[NOTE:THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g. The mass of satellite is 200 kg. How much energy must be expended to rocket the satellite out of the earth's gravitational influence?]
measure and record the output voltage from the rc low-pass fi lter for each of the frequencies listed below. (use the oscilloscope to measure the output voltage.) next, calculate the decibel attenuation offered by the fi lter at each frequency.
Passive RC filters “filter-out” unwanted signals by separating and allowing to pass only sinusoidal input signals based upon their frequency. Here the most simple passive low pass filter network is utilized.
Filters are named according to the frequency range of signals allowed to pass through them, while blocking or “attenuating” the rest. Here are some common filter designs.
The Low Pass Filter : only allows low frequency signals from 0Hz to its cut-off frequency.
The High Pass Filter : only allows high frequency signals from its cut-off frequency.
The Band Pass Filter : allows signals falling within a certain frequency band setup between two points to pass through.
The question is incomplete. Answer is written giving basics of the concepts used in the question.
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Miguel (m=72) and Fernando (89 kg) board the bumper cars at the local carnival. Miguel is moving at a velocity of 4 m/s when he rear-ends Fernando who is at rest in his path. Fernando and his 125-kg car lunge forward at 2 m/s. Determine the post-collision velocity of Miguel and his 125-kg car.
Moving at 1.2 m/s inside the opposite direction following the collision.
Define collision.
A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
The law of momentum conservation can be used to calculate Miguel's post-collision velocity.
Mass times velocity equals momentum, that is a vector quantity (p=mv). Well before collision, the system's momentum.
Miguel and Fernando's car—was equal to 782 kg*m/s (m1=72 kg) (v1=4 m/s) + (m2=125 kg) (v2=0 m/s). Just after collision,
The system's momentum is equal to 782 kg*m/s (m1=72 kg) (v1=? m/s) + (m2=125 kg) (v2=2 m/s).
We can calculate Miguel's post-collision velocity to be -1.2 m/s by solving for v1.
Miguel is therefore moving at 1.2 m/s inside the opposite direction following the collision.
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An audio speaker producing a steady sound at an outdoor concert is 42 ft away from you. If you move to a position where the speaker is 77 ft distant, by what factor will the amplitude of the sound change?
One of the phenomena whose strength changes with the square root of the inverse of the distance from the source is sound.
define amplitude ?
A periodic variable's amplitude measures its change over a single period (such as time or spatial period). A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several definitions of amplitude (see below), all of which depend on how much the extreme values of the variable deviate from one another. The phase of a periodic function is frequently referred to as the amplitude in older publications.
=(42/77)^2
=(0.545)^2
=0.297025
Thus, the sound increases in volume by around 8% from its initial level.
(The noise level has been lowered by 10.98 dB.)
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A metal object with a mass 5.50 kg is connected to a spring with a force constant of 225 N/m, and it oscillates horizontally with an amplitude of 4.20 cm. (a) What is the total mechanical energy (in J) of the object-spring system? (b) What is the maximum speed (in m/s) of the oscillating object? m/s (c) What is the maximum magnitude of acceleration (in m/s) of the oscillating object? m/s²
a) Total mechanical energy of the object-spring system = 0.198 J
b) Maximum speed of the oscillating object = 0.269 m/s
c) Maximum magnitude of acceleration of the oscillating object = 1.72 m/s2
What is acceleration?
Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.
Mass of the object = m = 5.5 kg
Force constant of the spring = k = 225 N/m
Amplitude of the motion = A = 4.2 cm = 0.042 m
Total mechanical energy of the object-spring system = E
Total mechanical energy is equal to the maximum potential the spring can store in this motion.
(a) [tex]$E=\frac{1}{2} \times 300 \times 0.037^2$[/tex]
[tex]$$E=0.20535 \text { Joules }$$[/tex]
Maxmium speed, [tex]$v_{\max }=$[/tex] AeO
[tex]$$\begin{gathered}\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{300}{5.5}} \\\omega=7.3855 \mathrm{rad} / \mathrm{s} \\v_{\max }=0.037 \times 7.3855 \\V=0.273 \mathrm{~m} / \mathrm{s}\end{gathered}$$[/tex]
(C) Maximim acceleration, [tex]$a_m=A \omega^2$[/tex]
[tex]$$\begin{aligned}a_{\max } & =0.037 \times 7.3855^2 \\a_{\max } & =2.018 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]
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which of these is a risk of speeding? a. Tire Damage b.Greater likelihood of being distracted c.longer barking distance d.mechanical failure
All of the above are risks of speeding.
Speeding is a type of aggressive driving behavior. Speeding is more than just breaking the law. The consequences are far-ranging:
Greater potential for loss of vehicle control;Reduced effectiveness of occupant protection equipment;Increased stopping distance after the driver perceives a danger;Increased degree of crash severity leading to more severe injuries;Economic implications of a speed-related crash; andIncreased fuel consumption/cost.Speed also affects your safety even when you are driving at the speed limit but too fast for road conditions, such as during bad weather, when a road is under repair, or in an area at night that isn’t well lit.
Speeding endangers not only the life of the speeder, but all of the people on the road around them, including law enforcement officers. It is a problem we all need to help solve.
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A sound wave travels through water. What best describes the direction of the water particles?
The water particles move perpendicular to the source of the sound wave.
The water particles move in the same direction as the vibrating source of the sound wave.
The water particles move in random patterns because the sound is diffracted in many directions.
The water particles do not move because the sound wave does not have enough energy.
Answer:
The water particles move in the same direction as the vibrating source of the sound wave.
Explanation:
Answer:
The correct option is B.
Explanation:
Help please!
Zach drives his car with an average velocity of 24 m/s toward the east. How long will it take him to drive 560 km on a perfectly straight highway?
A fellow student with a mathematical bent tells you that the wave function of traveling wave on a thin rope is y(x,t) = 2.20 mm cos((6.99rad/m)x+(753 rad/s)t).Being more practical, you measure the rope to have a length of 1.50 m and a mass of 0.00338 kg. You are then asked to determine the following.(a) amplitude(b) frequency(c) wavelength(d) wave speed(e)direction the wave traveling(f) tension in the rope(g)average power transmitted by the wave
a) The amplitude is given by the coefficient of the cosine function, which is 2.20 mm.
b) The frequency is given by 120 Hz.
c) The wavelength is given by lambda 0.906 m.
d) The wave speed is given by 107.9 m/s.
e) The wave is traveling in the positive x direction since the coefficient of x is positive.
f) The linear density is given by mu = mass/length 0.00225 kg/m.
g) The average power transmitted by the wave per unit length of the rope is 270.0 W/m.
(a) The amplitude of the wave is the maximum displacement of the rope from its equilibrium position. In this case, the amplitude is given by the coefficient of the cosine function, which is 2.20 mm.
(b) The frequency of the wave is the number of oscillations per second. It is related to the angular frequency, which is given by the coefficient of t in the wave function. In this case, the angular frequency is 753 rad/s, and the frequency is given by:
f = 753 rad/s / (2 × pi) = 120 Hz
(c) The wavelength of the wave is the distance between two consecutive peaks or troughs. It is related to the angular wave number, which is given by the coefficient of x in the wave function. In this case, the angular wave number is 6.99 rad/m, and the wavelength is given by:
lambda = 2 × pi / 6.99 rad/m = 0.906 m
(d) The wave speed is the speed at which the disturbance travels along the rope. It is related to the angular frequency and the angular wave number by the equation:
v = omega / k
where v is the wave speed, omega is the angular frequency, and k is the angular wave number. In this case, the wave speed is given by:
v = 753 rad/s / 6.99 rad/m = 107.9 m/s
(e) The direction of the wave traveling can be determined from the signs of the coefficients in the wave function. In this case, the wave is traveling in the positive x direction, since the coefficient of x is positive.
(f) The tension in the rope is the force per unit length that is needed to maintain the wave. It can be calculated using the mass per unit length of the rope (the linear density) and the wave speed:
T = mu × v²
where T is the tension, mu is the linear density, and v is the wave speed. In this case, the linear density is given by:
mu = mass / length = 0.00338 kg / 1.50 m = 0.00225 kg/m
Substituting this into the equation for tension, we get:
T = 0.00225 kg/m × (107.9 m/s)² = 2.50 N/m
(g) The average power transmitted by the wave is the rate at which energy is transferred through the wave. It can be calculated using the tension in the rope and the wave speed:
P = T × v
Substituting in the values we calculated above, we get:
P = 2.50 N/m × 107.9 m/s = 270.0 W/m
This is the average power transmitted by the wave per unit length of the rope.
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a rock climber stands on top of a 50 m -high cliff overhanging a pool of water. he throws two stones vertically downward 1.0 s apart and observes that they cause a single splash. the initial speed of the first stone was 1.6 m/s.
A) How long after the release of the first stone does the second stone hit the water? (in seconds) B) What was the initial speed of the second stone? (in m/s) C) What is the speed of the first stone as it hits the water? (in m/s) D) What is the speed of the second stone as it hits the water? (in m/s)
(a) The second stone hit after 2.91 seconds
(b) The initial velocity of the second stone must be 15.8 m/s vertically downward.
(c) The velocity of each stone when they reach the water is: First stone : -30.7 m/s Second stone: -34.5 m/s
The height and velocity of the stones can be calculated using the following equations:
y = y0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
y = height at time "t".
y0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).
v = velocity at time "t".
a) If we place the origin of the frame of reference on the water, then, the height of both stones when they hit the water will be 0. Using the equation of height for the first stone, we can obtain the time when the height is 0:
y = y0 + v0 · t + 1/2 · g · t²
0 = 50.0 m -1.91m/s · t - 1/2 · 9.81 m/s² · t²
0 = 50.0 m - 1.91 m/s · t - 1.6 m/s² · t²
Solving the quadratic equation:
t = 2.91 s
The two stones hit the water 2.91 s after the release of the first stone.
b) The second stone reaches the water in (2.91 s - 1.00 s) 1.91 s after released (remember that it was released 1.00 s after the first stone but both reached the water simultaneously). Then, using the equation of height, we can obtain the initial velocity knowing that at t = 1.91 s, y = 0:
y = y0 + v0 · t + 1/2 · g · t²
0 = 48.0 m + v0 · 1.91 s - 1/2 · 9.81 m/s² · (1.91 s)²
(-48.0 m + 1/2 · 9.81 m/s² · (1.91 s)²) / 1.91 s = v0
v0 = -15.8 m/s
The initial velocity of the second stone must be 15.8 m/s vertically downward.
c) We have to use the equation of velocity for each stone. We already know the time when the stones reach the water and the initial velocities:
First stone:
v = v0 + g · t
v = -2.18 m/s - 9.81 m/s² · 2.91 s
v = -30.7 m/s
Second stone:
v = v0 + g · t
v = -15.8 m/s - 9.81 m/s² · 1.91 s
v = -34.5 m/s
The velocity of each stone when they reach the water is:
First stone : -30.7 m/s
Second stone: -34.5 m/s
Therefore, the velocity of the first and second stones are -30.7 m/s and -34.5 m/s.
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the fact that the force times the distance on one side of a lever's fulcrum equals the force times the distance on the other side of the fulcrum, is represented in the .
The force times the distance on the other side of the fulcrum, is represented in the moments.
What is fulcrum equals?
Calculate the mechanical advantage [tex]MA[/tex]using the equation [tex]MA = Fr/Fe.[/tex] For a class I lever, calculate the distance [tex]dr[/tex] of the fulcrum from the load using[tex]dr= L / (MA + 1)[/tex]. For a class II lever, determine the distance [tex]dr[/tex]of the fulcrum from the load using [tex]dr = L / MA[/tex].
How do you calculate the force of a fulcrum?
Class I Levers trial one: de = dr
In a class one lever the force of the effort (Fe) multiplied by the distance of the effort from the fulcrum (de) is equal to the force of the resistance (Fr) multiplied by the distance of the resistance from the fulcrum (dr).
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a 0.50 kg book is being pushed on a horizontal table. the force pushing the book is 6n and the frictional force between the book and the surface has magnitude f
The magnitude of the frictional force is f = μ * 4.9 N.
What is magnitude?
Magnitude is a term used in physics to describe an object's maximum size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have only magnitude by definition. Those quantities with both direction and magnitude are considered vector quantities. An earthquake's size is measured in terms of its length, breadth, and width. It is calculated based on the earthquake's actual size. A single magnitude is thought to exist for an earthquake. Due to variables like the type of material surface and distance from the epicentre, the magnitude of the shaking brought on by the earthquake varies depending on where it occurs.
The frictional force between the book and the surface is the resistive force pushing back against the pushing force of 6N. The magnitude of this resistive force depends on the coefficient of friction between the book and the table surface, as well as the normal force, which is equal to the weight of the book (0.50 kg * 9.8 m/s2 = 4.9 N).
The magnitude of the frictional force (f) can be calculated using the equation f = μ * N, where μ is the coefficient of friction and N is the normal force. Thus, the magnitude of the frictional force is f = μ * 4.9 N.
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based on fundamental laws of motion and gravity, which of the following best explains why kepler's second law (planets move faster in the parts of their orbit that are closer to the sun and slower when they are farther from the sun) is true? based on fundamental laws of motion and gravity, which of the following best explains why kepler's second law (planets move faster in the parts of their orbit that are closer to the sun and slower when they are farther from the sun) is true? the strength of gravity is inversely proportional to the square of the distance between two objects. the speed of a planet at any point in its orbit depends on its temperature, which varies with distance from the sun. the gravitational influence of other planets determines the speed of any particular planet's orbit. a planet's angular momentum must be conserved as it moves around its orbit.
The strength of gravity is inversely proportional to the square of the distance between two objects.
Kepler's Second Law characterizes the the rate of a planet alongside its elliptical path. Kepler's Second Law says says that a line jogging from the solar to the planet sweeps out same regions of the ellipse in same times. This manner that the planet hastens because it tactics the solar and slows down because it departs from it.
Newton's regulation states: The gravitational appeal pressure among factor loads is immediately proportional to the made from their loads and inversely proportional to the rectangular in their separation distance. The pressure is usually appealing and acts alongside the road becoming a member of them.
For the planets, as they cross across the Sun, their loads do not extrade however their distances from the Sun do. As they get in the direction of the Sun (distance receives smaller) they orbit faster (better velocity). The product of those portions stays unchanged, therefore angular momentum is conserved.
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how fast would a(n) 73 kgkg man need to run in order to have the same kinetic energy as an 8.0 gg bullet fired at 430 m/sm/s ?
The velocity of the 73 Kg man needed for him to have the same kinetic energy as the 8.0 g bullet fired at 430 m/s is 4.5 m/s
How do I determine the velocity of the man?First, we shall obtain the kinetic energy of the bullet. This can be obtained as follow:
Mass (m) = 8 g = 8 / 1000 = 0.008 KgVelocity (v) = 430 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.008 × 430²
KE = 739.6 J
Finally, we shall determine the velocity of the 73 Kg man. Details below:
Mass of man (m) = 73 KgKinetic energy (KE) = 739.6 JVelocity of man (v) = ?KE = ½mv²
739.6 = ½ × 73 × v²
739.6 = 36.5 × v²
Divide both side by 36.5
v² = 739.6 / 36.5
Take the square root of both side
v = √(739.6 / 36.5)
v = 4.5 m/s
Thus, the velocity man is 4.5 m/s
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two wires carry equal currents in opposite directions, as in (figure 1). the field is 2.0 mt at a point below the lower wire. the distance between the wires is twice the distance between this point and the lower wire.
We cover the idea of the magnetic discipline produced with the aid of a modern-day wearing wire. Now remember the separation among the
2 wires to D. The direction is out of the page.
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Magnetic discipline can also be into the page, and on the way to be me or now not. I over to a birthday celebration. So this becomes minus of times may not I over to party. Now let's consider this. That equation from equation one, we will write the magnetic discipline electricity at .1 is- of two instances three/2 instances.
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Disclaimer:- your question is incomplete, please see below for the comlete question.
Two wires carry equal currents in opposite directions, as in (Figure 1). The field is 2.0 mT at a point below the lower wire. The distance between the wires is twice the distance between this point and the lower wire. What is the strength of the field at point 1? Express your answer with the appropriate units. What is the direction of the field at point 2 (the same distance above the upper wire as the 2.0 mT point is below the lower wire)? into the page out of the page What is the strength of the field at point 2? Express your answer with the appropriate units.
Figure shows a closed loop of wire that consists of a pair of equal semicircles, of radius 3.7 cm, lying in mutually perpendicular planes.The loop was formed by folding a flat circular loop along a diameter until the two halves became perpendicular to each other. A uniform magnetic field B of magnitude 76 mT is directed perpendicular to the fold diameter and makes equal angles (of 45°) with the planes of the semicircles. The magnetic field is reduced to zero at a uniform rate during a time interval of 4.5 ms. During this interval, what are the (a) magnitude and (b) direction (clockwise or counterclockwise when viewed along the direction of B) of the emf induced in the loop?
(a) Magnitude of the average emf induced in the loop is 0.20 mV.
(b) direction is perpendicular to the field.
Average emf induced in the circular loop is given by;-
The magnitude of average emf induced in the loop is calculated as follows are;
emf = NA(B₁ - B₂)/t
by using the formula of the induced emf we calculate the average emf.
A = area of the loop
N =number of turns
B1 = initial magnetic field
B2 = final magnetic field
t=time
A = πr² = π(0.37)²
= 5.027 x 10⁻³ m²
emf = (1)(5.027 x 10⁻³)(0.45 - 0.37)/7.6
emf = 2.01 x 10⁻⁴ V
emf = 0.201 mV
Therefore, magnitude of the average emf is induced in the loop = 0.20 mV.
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What is an example of a constant rate?
In an expression, a graph, or perhaps a table of values, the steady rate of change can indeed be observed. The slope of an equation can be thought of as the constant rate of change.
What is meant by "constant rate of change"?The rate of variation is considered to be constant if the ratio pf output to input remains unchanged at any given point along function. Constant change rate is also known as slope. Linear functions will have a consistent rate of change.
What is a steady rate, specifically?When anything moves at a fixed, steady pace or at an average speed, it is said to be moving at a constant rate, also known as a uniform rate. For instance, 3 hours pass while driving. In the first hour, it travels 30 miles, in the second hour, 45 miles, and in the third hour, 75 miles.
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