A series RLC circuit with R = 10 Ω, C = 80 μF, and L = 10 mH is connected across a 200 Hz, 15 V ac source. The total impedance, expressed in polar form

Answers

Answer 1

The total impedance, expressed in polar form will be 10.337 * e^(j 14.676°).

How to calculate the impedance?

R = 10 Ω,

C =  80 μF = 80 x 10⁻⁶ F

L = 10 mH  = 10 x10⁻³ F

XL  = 2πfL

= 2π (200)10 * 10⁻³

= 4π

= 12.566

Xc = 1 /2πfC

= Xc = 1/2π(200)80 x 10⁻⁶

= Xc =  9.947

The total impedance = R + jXL - jXc

= 10  + j(12.566  -  9.947)

= 10 + j 2.619

The total impedance   is 10 + j 2.619

| Z | = 10.337

Ф = tan⁻¹ ( 2.619 /10) = 14.676°

Polar Form = 10.337 * e^(j 14.676°)

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A series RLC circuit with R = 10 Ω, C = 80 μF, and L = 10 mH is connected across a 200 Hz, 15 V ac source. The total impedance, expressed in polar form, is?


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