A small mass of m = 187 g hangs from a string of length l = 1.21 m.
Calculate the initial speed v the mass m should be given at the bottom, so that the string reaches a maximum angle of θ = 36.5°?

The time for which the baseball remains in the air will be 9.37 sec. Option C is correct.

It is the height achieved by the body when a body is thrown at the same angle and the body is attaining the projectile motion.

From Newton's first equation of motion;

[tex]\rm v_y= u_y+gt \\\\ 0 = usin \theta - gt \\\\ t = \frac{u sin\theta }{g}\\\\t = 4.68 \ sec[/tex]

The time the baseball remains in the air will be twice the time he travels for one side motion;

T' = 2t

T'=2 × 4.68 sec

T'= 9.37 sec

Hence for 9.37 sec, the baseball willl remains in the air. Option C is correct.

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Answer:

a community event

Explanation:

If the displacement is tripled then the spring force also is tripled.

The amount of force required to stretch or compress the spring is known as the spring force. Its unit is Newton(N).

Froom the hooks law;

F = kx

Where,

F is the applied force

x is the displacement in case 1

Case 2;

x'=3x

F'=kx'

F'=3KX

F'=3x'

Where,

x' is the displacement when the force is tripled

F' is the force in the case2

Hence, if the displacement is tripled then the spring force also be tripled.

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Answer:

50J

Explanation:

Work done=Fd

=5×10

=50J

(a)The value of W for the given condition will be 237.3 N.

(b)The distance must the fulcrum be moved to restore balance will be 0.070 m.

A location is established in relation to an object or set of objects in the center of mass. It is the system's average position across all of its components.

Given data;

Weight is applied to the right end of the rod, W₁= 225 N

Rod's weight,W₂ = 255

W₃ is the Weight at "x" distance from the left end.

x1  is the location of W₁ with respect to the left end, where L = 1.80 m

m is the location of the rod's center of mass from the left end.

The position of W from the left end; x₃ = 50 cm = 0.50 m

Xcm is the position of the center of gravity of the rod at the fulcrum from the left end;

Given that the fulcrum is balanced in this situation, the rod's center of gravity will be there.

Xcm= L - 75 cm

Xcm=1.80 m - 0.75 m

Xcm= 1.05 m

The value of x₂

x₂= 1.80 m/2 = 0.90 m

Currently, the horizontal center of gravity is determined by

[tex]\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3*x_3)}{(W_1 + W_2 + W_3)}[/tex]

Substitute the values we get;

[tex]\rm 1.05 = \fraca{ (225 \times 1.80 + 255\times 0.90 + W\times 0.50)}{(225 + 255 + W)}\\\\ W = \frac{ (225\times 1.80 + 255\times 0.90 - 480 \times 1.05)}{(1.05 - 0.50)}\\\\ W = 237.3 \ N[/tex]

After moving the fulcrum 20.0 cm to the right,

The location of the W from the left end;

x₃ = .50 cm + 20 cm

x₃  = 70 cm

x₃  = 0.70 m

W₁, W₂, W, x₁, and x₂ have fixed values. Therefore, based on these values, the new center of gravity will be:

[tex]\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3*x_3)}{(W_1 + W_2 + W_3)}[/tex]

[tex]\rm X_{cm} = \frac{(225\times 1.80 + 255\times 0.90 + 237.3\times 0.70)}{(225 + 255 + 237.3)}\\\\ X_{cm} = 1.12 m[/tex]

Fulcrum must be shifted by;

Y = (1.12 - 1.05)

Y= 0.070 meters.

W has been moved in the appropriate direction, thus the fulcrum should likewise be moved in the appropriate direction.

Hence, the value of W for the given condition will be 237.3 N. and the distance must the fulcrum be moved to restore balance will be 0.070 m.

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If Ross takes two months off from training, his fitness level will reduce in comparison to what it was two months ago.

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The work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton

a. Work done = force * change in velocity = Impulse

Note that:

Force = mg

mass = 3.8x 104 kg

g = 10m/s²

Substitute into the formula for force

Force = 3.8* 10^4 * 10= 3.8* 10^5 Newton

Change in velocity = 6700 - 4600 = 2100 m/s

Work done = force *change in velocity

Work done =  3.8* 10^5 * 2100

Work done =  7. 89 * 10^8 Joules

b. Magnitude of the force = work done ÷ distance

Force = [tex]\frac{7. 89 * 10^8 }{2.4* 10}[/tex]

Force = 3. 3* 10 ^7 Newton

Therefore, the work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton

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Answer:

D. s=3x+4y

Explanation:

The line is at the 3rd column in the 4th row.

The final speed of the nickel at the given quantity of heat is determined as 202.1  m/s.

Apply the principle of conservation of energy.

Q = mcΔθ

Q = (18)(0.444)(66 - 20)

Q = 367.63 J

Q = K.E = ¹/₂mv²

2K.E = mv²

v = √(2K.E/m)

where;

v = √(2 x 367.63)/(0.018))

v = 202.1 m/s

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The corresponding downward force on the top of a horizontal square is 375 lb.in

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

If the atmospheric pressure is 15 lb/in and  area 5 inches on each side is

A = 5² = 25  in²

The force applied is

15 lb/in = F /25 in²

F = 375 lb.in

Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in

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Answer:

F = G M m / R^2        gravitational force on satellite of mass m

Fma / Fmb = (ma / Ra^2) \ (mb / Rb^2) = (ma / mb) * (Rb / Ra)^2

Fma / Fmb = 1 * 4 = 4

The force on A is 4 times the force on B

By using an electric field, it is feasible to differentiate between these different forms of radiation.

A source that emits radiation like gamma, beta, and alpha rays is said to be radioactive. Using an electric field, we can discriminate between these different forms of radiation.

The field does not deflate the gamma rays, but it does deflate the alpha and beta rays, with the alpha being deflated to the field's negative portion and the beta to its positive part.

Hence, by using an electric field, it is feasible to differentiate between these different forms of radiation.

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The type of power plant burns material to make electricity is Fossil fuel. The correct option is C.

Energy is the ability to do work.

There are different kind of energies like kinetic energy, potential energy, gravitational energy and  heat energy.

The energy obtained from burning different type of materials like Coal, gas and oil and produces heat.

Fossil fuel power plants burn coal or oil to create heat and generate steam to run turbines which generate electricity.

Thus, the correct option is C.

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The force, in newtons, exerted by each of the 10 braces is 2.135 x 10⁴ N.

The force is defined as the shear stress or pressure applied per unit area.

F = P/A

Given is a 17.0-m-high and 11.0-m-long wall and its bracing under construction are shown in the figure(attached). The force is exerted by each of the 10 braces, if a strong wind exerts a horizontal force of 655 N on each square meter of the wall. Assume that the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths.

Considering the pivot at the base of wall.

From the equilibrium of forces, we have

r₁ x Fwind = r₁ x Fbsinθ

Put the values, we get

Fb = Fwind /10sin35°.............(1)

The wind force is also given by

Fwind = Horizontal force or pressure x Area

Fwind = F/A x hw

           =655 x 17 x 11

F wind = 122,485 N

From equation (1), we have

Fb = Fwind /10sin35°

Fb =  122,485 /10sin35°

Fb = 21,354.6080 N

0r Fb = 2.135 x 10⁴ N

Thus, the force exerted on each of the 10 brace is 2.135 x 10⁴ N.

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Answer:

Explanation:

There are different ways to investigate the factors that affect resistance. In this practical activity, it is important to:record the length of the wire accuratelymeasure and observe the potential difference and currentuse appropriate apparatus and methods to measure current and potential difference to work out the resistance

Typing in the commands and instructions and pressing enter will put a new command in the command prompt​.

This refers to a words or phrase which causes the computer to execute certain tasks or functions.

Typing the exact instruction and entering it will ensure that the chosen tasks are found in the command prompt.

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Answer:

1.1299 x 10^-8   second    

Explanation:

Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8  sec

Answer:

it alters the rate of chemical reaction

hope it is useful

Answer:

Approximately [tex]3.14\; {\rm rad \cdot s^{-1}}[/tex].

Explanation:

Fact: the angular velocity [tex]\omega[/tex] of a simple harmonic oscillator is the ratio between the maximum velocity [tex]v_{\text{max}}[/tex] and the maximum displacement [tex]x_\text{max}[/tex] of this oscillator. In other words:

[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}}\end{aligned}[/tex].

Derivation of the previous equation:

Let [tex]A[/tex] denote the amplitude of this oscillation, and let [tex]\omega[/tex] denote the angular velocity.

The displacement of the oscillator at time [tex]t[/tex] would be:

[tex]x(t) = A\, \sin(\omega\, t)[/tex].

The maximum displacement of this oscillator would be [tex]x_\text{max} = A[/tex].

The velocity of this oscillator at time [tex]t[/tex] is the derivative of displacement with respect to time:

[tex]\begin{aligned} v(t) &= \frac{d}{d t}\, [x(t)] \\ &= \frac{d}{d t} [A\, \sin(\omega\, t)] \\ &= A\, \omega\, \cos(\omega\, t)\end{aligned}[/tex].

The maximum velocity of this oscillator would be [tex]v_\text{max} = A\, \omega[/tex].

Notice that dividing [tex]v_\text{max} = A\, \omega[/tex] by [tex]x_\text{max} = A[/tex] would give:

[tex]\displaystyle \frac{v_\text{max}}{x_\text{max}} = \frac{A\, \omega}{A} = \omega[/tex].

It is given that [tex]v_\text{max} = 2.76\; {\rm m\cdot s^{-1}}[/tex] while [tex]x_\text{max} = 0.0880\; {\rm m}[/tex]. Therefore:

[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}} \\ &= \frac{2.76\; {\rm m\cdot s^{-1}}}{0.0880\; {\rm m}} \\ &\approx 3.14\; {\rm s^{-1}}\end{aligned}[/tex].

(Radians per second.)

Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific topic.Option A is correct.

A scientific hypothesis is the main element in the scientific method and experiment.

It is said that a hypothesis is a scientific hypothesis. The majority must agree on it, or it must be done after thorough experimentation.

Only scientific inquiries can have their answers provided by scientific endeavor. Scientific concerns have an impact on the research's design as well.

Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific question.

Hence option A is correct.

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The statement best describes how upwelling occurs is Upwelling causes nutrients, minerals, and tiny organisms to rise. The correct option is C.

Upwelling occurs when winds push surface water away from the shore and deeper water rises to fill the gap.

The upwelling is a cycle that shows up in the water bodies all over the planet. This cycle is basically addressing the ascending of the virus waters towards the surface where there's hotter environment, subsequently hotter water also.

With the ascent of the virus waters towards the surface, everything with it ascend also. The virus waters are plentiful in supplements and minerals, as well as minuscule creatures, like the Phyto-microscopic fishes.

This is a cycle that is vital for the presence of the environments in the bigger water bodies.

Thus, the correct option is C.

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Answer:

V = 6.53 × 10^14

h = 6.626 × 10^-34

E = hV

E = (6.626 × 10^-34) (6.53 × 10^14)

E = 4.33 × 10^-19

Answer:

CSP

Explanation:

CSP systems store energy through Thermal Energy Storage technologies (TES), so power can be used when there isn't enough sunlight. PV systems, however, can't store thermal energy because they use direct sunlight, rather than heat. For this reason, CSP systems are better for energy storage and efficiency.

The charge on each sphere is 742 n

In physics, Charge, also known as electric charge is a electrical charge, or electrostatic charge and symbolized q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.

According to the question,

Distance = 15cm or 0.15m

Force =  0.22N

[tex]K=9*10^{9} kgm^2/c^2[/tex] ( this is a constant value of K)

By using the formula,

F = [tex]\frac{kQq}{d^{2} }[/tex]

0.220 N = 8.99

N·m²/C² * Q² / (0.15m)²

Q = 7.42e-7

C = 742 n

C is the charge of each sphere .

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a)The velocity of the object when it hits the ground will be 1.12 × 10⁵ m/sec

b) The time taken for the object to reach the ground will be 11.4 × 10³ sec.

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The velocity in the x-direction;

[tex]\rm v_x = (vcos \theta)^2 +2gh \\\\ v_x = (50 cos 30)^2+ 2 \times 9.81 \times 4000 \\\\ v_x = 80355 m/sec[/tex]

Velocity in y-direction;

[tex]\rm v_ y = (vsin \theta)^2 + 2gh \\\\ v_ y = (25)^2+2 \times 9.81 \times 4000 \\\\ v_y =79105 \ m/sec[/tex]

The resultant velocity is found as 1.12 × 10⁵ m/sec.

The time taken to reach the ground is found as;

[tex]\rm v = u+gt \\\\ 1.12 \times 10^5 \ m/sec = 50 \ m/sec + 9.81 \times t \\\\ t = 11.4 \times 10^3 \ sec[/tex]

Hence, the velocity of the object when it hits the ground will be 1.12 × 10⁵ m/sec, and the time taken for the object to reach the ground will be 11.4 × 10³ sec.

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Answer:

B. Outside the nucleus.

Explanation:

Electrons orbit the nucleus of the atom.

Answer:

(D)6 times

Explanation:

Hello !

Because when we see the equation of momentum P=mv, where p=momentum

m=mass of the object&

v=velocity of the object

And, p is directly propositional to both mass and velocity.

Thus, p=mv

Therefore, we can conclude by when the mass is tripled and the velocity is doubled the momentum is increased by 6 units.

The gauge pressure at bottom of vaccine solution will be 16 kPa

Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.

Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.

We have to find the gauge pressure at bottom of vaccine solution

Since the 5N force is applied to vaccine solution the pressure exerted will be much more

Hence the gauge pressure at bottom of vaccine solution will be 16 kPa

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The total time the ball is in the air is 1.47 s and the maximum horizontal distance covered is 58.7 m.

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

55 = (50sin37)t + ¹/₂(9.8)t²

55 = 30.1t + 4.9t²

4.9t² + 30.1t - 55 = 0

Solve using formula method;

t = 1.47 s

X = vxt

where;

X = (50 x cos37) x 1.47

X = 58.7 m

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