a solution contains 161 mg of na ions per liter. how many miliosmoles are represented in the solution

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Answer 1

The total number of millimoles present in the solution containing 161 mg of Na ions are 7.04 millimoles/L.

What are millimoles?

A substance's concentration in a quantity equivalent to a thousandth of a mole (a measure of the amount of a substance). as well known as millimole.

You would need to multiply the number of moles of sodium ions (Na+) in the solution by the number of litres of solution in order to get the number of millimoles represented in the solution.

Divide the given milligrames (mg) by the molar mass of sodium ion to convert mg to moles (22.99).

Therefore, 161 mg/L is 161/22.99 = 7.04 10⁻³ moles/L.

You would now need to multiply 7.04 10⁻³ moles/L by 1000 to convert from moles/L to millimoles/L.

Thus, 7.04 10⁻³ moles/L multiplied by 1000 equals 7.04 millimoles/L.

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Related Questions

I actually can't figure this out, can someone help me?

You and your friends are at the lake on a particularly sunny day. Use specific heat capacity to explain why the sand on the shores of the lake feels so much hotter than the water in the lake even though the same solar energy is being absorbed by both materials.

Answers

Answer:

sand's specific heat capacity is low that water(i.e. 830J/kg°C) Due to it's low specific heat capacity it gets hotter easily. That's whythe sand on the shores of the lake feels so much hotter than the water in the lake even though the same solar energy is being absorbed by both materials.

calculate the concentration (% m/m) of nacl solution that was made by dissolving 40.0 g of sodium chloride in enough water to make 500.0 g of solution g.

Answers

A solution with an 8% (m/m) concentration was created by dissolving the sodium chloride in 40.0 g in 500.0 g of water. Sodium chloride, also known as table salt.

Sea salt has the chemical formula NaCl, which indicates a 1:1 ratio of sodium chloride ions, and is an ionic material despite also containing other chemical salts. With molar weights of 22.99 and 35.45 g/mol, respectively, 39.34 g of Na and 60.66 g of Cl make up 100 g of NaCl. The concentration can apply to any type of chemical mixture, even though it is most frequently used to describe solutes and solvents in solutions. Two variations of the molar (amount) concentration are the normal concentration and the osmotic concentration.

(40.0/500)*100, which equals 8, is the concentration formula.

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to what reaction does the solubility product constant, ksp, refer? table 16.1 lists ksp values for several ionic solids. for any of these ionic compounds, you should be able to calculate the solubility. what is the solubility of a salt, and what procedures do you follow to calculate the solubility of a salt? how would you calculate the ksp value for a salt given the solubility

Answers

The solubility product constant (Ksp) is a measure of the equilibrium of a salt in an aqueous solution.

What is solubility?

Solubility is the ability of a substance to dissolve in a given solvent. It is a measure of the maximum amount of a solute that can be dissolved in a solvent.

It is used to determine the solubility of an ionic solid in a given solution. Ksp is the product of the concentrations of the ions in the solution at the equilibrium state.
Table 16.1 lists Ksp values for several ionic solids. The solubility of a salt is the amount of the salt that can be dissolved in a given amount of water or other solvent. To calculate the solubility of a salt, one must first determine the Ksp value for that salt. Then, the amount of the salt that will dissolve in a given amount of solvent can be calculated from the Ksp value.
To calculate the Ksp value for a salt given the solubility, one must first calculate the concentrations of the ions in the solution. This can be done by dividing the solubility of the salt by the total volume of the solution. Once the concentrations of the ions in the solution are known, the Ksp value can be determined by taking the product of these concentrations.

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0.25 moles of a gas at 760 mmHg
and 298 K are contained in a 6.1 L
bottle. What is the pressure of the
system if the amount of gas in the
bottle is reduced to 0.13 mole and
the temperature is reduced to 100 K?

Answers

Answer: 2.3*10^3 Pa.

Explanation: We can use the ideal gas law to determine the pressure of the system: PV = nRT

where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

The ideal gas constant R = 8.314 J/mol*K

Given:

n1 = 0.25 moles

V1 = 6.1 L

T1 = 298 K

P1 = 760 mmHg

n2 = 0.13 moles

V2 = 6.1 L

T2 = 100 K

We can use the equation PV = nRT to find the new pressure P2, using the information provided:

P2 = (n2RT2)/V2

We know that the volume of the bottle remains the same and we can convert the pressure from mmHg to Pascals

P2 = (0.138.314100)/6.1 = 2.3*10^3 Pa

Therefore, the pressure of the system when the amount of gas in the bottle is reduced to 0.13 mole and the temperature is reduced to 100 K is 2.3*10^3 Pa.

Answer:

132.62

Explanation:

i got the answer correct in the program

what is the name and formula of the chemical reagent used to separate the cations of group 1 from ions in other groups.

Answers

When water K2CrO4 is added, a yellow precipitate of PbCrO4 forms, confirming the presence of Pb2+ in the aqueous solution.

What does grouping cations into compounds mean?

1. Grouping the cations into various categories. The anions supplied by the group reagents are used to precipitate the cations of each succeeding group as compounds. The precipitate from one group's cations is separated (usually by centrifugation followed by decantation).

In Group 1 Group 2 and transition metals, how are cations formed?

More electropositive elements, such as those from groups 1, 2, 13, d-block (transition metals), and actinides, typically form cations. The oxidation states of D-block elements are positive, and they can form cations.

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does any solid cu(oh)2 form when 0.075 g of koh is dissolved in 1.0 l of 1.0 × 10−3 m cu(no3)2?

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Yes, the precipitation of Cu(OH)₂ will form when 0.075 g of KOH is dissolved in 1.0 L of 1.0 X 10⁻³ M Cu(NO₃)₂.

Chemical reactions begin with reactants as well as products of a reaction are the substances that were produced. The common chemical formula can be used to represent a chemical reaction: Reaction products. During the chemical reactions, bonds shatter and reform. Also, the opposite outcome of the reaction will happen.

[OH⁻]₀ = 0.075g/56.105g/mol(1.01) = 1.34×10⁻³

Cu(OH)₂ (s) ⇄ Cu²⁺ (aq) + 2OH⁻(aq)

?                       0.0010       1.34×10⁻³

Q = [Cu²⁺][OH⁻]² =  0.0010 ×(1.34×10⁻³)² = 1.8×10⁻⁹ > Ksp 2.2×10⁻²⁰

This means that equilibrium will shift to the left, i.e., to reactants in which in turn implies that solid Cu(OH)₂ will be formed.

moles of Cu²⁺= 1.L x 1 x 10⁻³ M= 10⁻³

moles of KOH = 0.075 g/ 56.107 g/mol=0.00133

[Cu²⁺]=  10⁻³ / 1. L= 10⁻³  M

[OH⁻]=0.00133 / 1.L= 0.00133  M

Qsp=  10⁻³ (0.00133)² =1.786 x 10⁻⁹ >> Ksp ( = 2.2 x 10⁻²⁰)

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a chemist has 70 ml of 50% methane solution. how much of an 80% siolution must she add yo get a 60% solution?

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a chemist has 70ml of 50% methane solution.8.75 ml of 80% methane solution to the 70 ml of 50% methane solution to get a 60% solution.

To solve this problem, you can use the formula for mixing two solutions of different concentrations:

C1V1 + C2V2 = C3V3

Where:

C1 = concentration of the first solution

V1 = volume of the first solution

C2 = concentration of the second solution

V2 = volume of the second solution

C3 = final concentration of the mixture

V3 = final volume of the mixture

We know that:

C1 = 50% = 0.50 (as a decimal)

V1 = 70 ml

C3 = 60% = 0.60 (as a decimal)

So we can rearrange the formula to solve for V2:

V2 = (C3V3 - C1V1) / C2

Since we don't know the final volume V3, we can assume it to be V1+V2

V2 = (0.60 * (V1 + V2) - 0.50 * V1) / 0.80

Solving this equation we have,

V2 = (0.60 * (70 + V2) - 0.50 * 70) / 0.80

V2 = (42 - 35) / 0.80

V2 = 7/0.8

V2 = 8.75 ml

So the chemist needs to add 8.75 ml of 80% methane solution to the 70 ml of 50% methane solution to get a 60% solution.

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consider the combustion of hydrogen for the next two questions. 2 h2 (g) o2 (g) 2 h2o (g) reaction is at standard temperature and pressure and all reagents are in the gas phase. if we react 10 moles of hydrogen with 6 moles of oxygen. what is the limiting reagent and how much water is produced?

Answers

if we react 10 moles of hydrogen with 6 moles of oxygen. Oxygen is the limiting reagent and 10moles of  water is produced

The limiting reagent is the reactant that runs out first, limiting the amount of product that can be produced. In order to determine the limiting reagent, we need to compare the stoichiometry of the reactants with the balanced equation. We can see that for every 2 moles of H2, 2 moles of H2O are produced. Also for every 1 mole of O2, 2 moles of H2O are produced.To determine the limiting reagent we have to find out which reactant is in excess, for that we can divide the number of moles of each reactant by its coefficient in the balanced equation. 10 moles of H2 / 2 moles of H2/1 mole of H2 = 5 moles of H2O are produced 6 moles of O2 / 2 moles of H2O/1 mole of O2 = 3 moles of H2O are producedSince 3 moles of H2O are produced, we can see that oxygen (O2) is the limiting reagent. So we can't produce more than 3 moles of H2O and the amount of water produced is 3 moles.

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write a nuclear equation for the fusion of h−3 with h−1 to form he−4.

Answers

rgashkjaehahnfpv kagjmpahjmsnklsmnn

This reaction releases a large amount of energy, which is what makes it useful in nuclear fusion reactors.

What is nuclear fusion?

Nuclear fusion is a process in which two or more atomic nuclei join together to form a single, heavier nucleus.

The nuclear equation for the fusion of h-3 with h-1 to form he-4 is:
3H-1 + 1H-3 -> 4He-2 + 1n0
This equation describes the fusion of two hydrogen atoms to form a helium atom and a neutron. The first hydrogen atom (H-1) has a mass of 1, while the second hydrogen atom (H-3) has a mass of 3. When the two hydrogen atoms fuse together, they form a helium atom (He-2) with a mass of 4 and a neutron (n0) with a mass of 1. This reaction releases a large amount of energy, which is what makes it useful in nuclear fusion reactors.

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determine the mass of ammonium nitrate (in g) that has the same number of nitrogen atoms as 2.5 liters of liquid nitrogen (n2). density of liquid nitrogen is 0.808 g/ml.

Answers

The mass of ammonium nitrate (in g) that has the same number of nitrogen atoms as 2.5 liters of liquid nitrogen (n2) is 72.10g.

Given the volume of liquid nitrogen (V) = 2.5L = 2500ml

The liquefied form of the element nitrogen, known as liquid nitrogen, is created commercially through fractional distillation of liquid air.

The density of liquid nitrogen is (d) = 0.808 g/ml.

Let the mass of ammonium nitrate = m

We know that density = mass/volume

mass = density x volume

The molecular weight of liquid nitrogen = 28.0134g

m = (0.808 x 2500) x 1 mole N2/28.0134 = 72.10g

Hence the required mass of ammonium nitrate is 72.10g

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automobiles burn gasoline (c8h18) in order to provide the energy they need to move. when they do, carbon dioxide (co2) is released. what chemical equation is the most accurate model for the reaction?

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The chemical equation which can be formulated as the most accurate model for the reaction of burning gasoline which is 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(g)

A car is designed in such a way where it utilizes fuel as its source of energy. This fuel actually contains all the chemicals where the engine of the car breaks down via combustion to facilitate the process of its functioning. Kinetic energy can be defined as the process of the form of mechanical energy produced as a result of motion. A moving object which individual etc uses kinetic energy to do so.

The fuel (gasoline) which is being supplied into the car's engine makes the car able to move from their place, therefore, we can say that the chemical energy present in the fuel is being converted to kinetic energy that is observable in the car on motion along with the release of heat by the engine.

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n the atmosphere, small water droplets are suspended in the air, forming an aerosol. can form under these conditions, as shown in reaction 2, represented below. reaction 2: which of the following predicts the effect that the formation ofwill have on the equilibrium shown in reaction 1, and why? (a) the equilibrium of reaction 1 will shift toward the formation of more product, because is removed when it reacts to form . (b) the equilibrium of reaction 1 will shift toward the formation of more product, because acts as a catalyst for reaction 1. (c) the equilibrium of reaction 1 will shift toward the formation of more reactants, because the product is removed when it reacts to form . (d) the equilibrium of reaction 1 is not affected, because neither norare gases.

Answers

An aerosol is a suspension of tiny water droplets in the atmosphere. Due to the removal of N2O5(g) reacting to produce HNO3, reaction 1's equilibrium will change production of additional product (aq).

Describe aerosol.

A suspension of tiny liquid or solid particles in air or even another gas is known as an aerosol. Aerosols can be created naturally or artificially. Fog or mist, dust, lesion from forests, and geothermal steam are a few instances of natural aerosols.

Are aerosols bad for you?

Numerous aerosol sprays contain dangerous substances like formaldehyde and xylene, which are used to protect anatomical objects in jars. In addition to being exceedingly dangerous for adults, kids, and household pets, these toxic substances now include carcinogens and carcinogen.

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argon has a normal boiling point of 87.2 k and a melting point (at 1 atm) of 84.1 k. its critical temperature is 150.8 k, and its critical pressure is 48.3 atm. it has a triple point at 83.7 k and 0.68 atm. sketch the phase diagram for argon. which has the greater density, solid argon or liquid argon?

Answers

Solid argon is thick than liquid argon because the emulsion wind has a positive pitch, and the solid phase is stable at advanced pressure.

 The critical temperature for a pure substance is the temperature above which the gas cannot come liquid, anyhow of the applied pressure.

For a pure substance, the critical pressure is defined as the pressure above which liquid and gas cannot attend at any temperature. The critical temperature for a pure substance is the temperature above which the gas cannot come liquid, anyhow of the applied pressure.

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The concept that electrostatic repulsion between electron pairs surrounding an atom causes these pairs to beseparated as far as possible is the foundation ofa. VSEPR theory. b. the hybridization model. c. the electron-sea model.d. Lewis theory.

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The concept that the electrostatic repulsion between electron pairs surrounding an atom causes these pairs to be separated as far as possible is the foundation of VSEPR theory.

The premise of VSEPR is that valence pairs surrounding atoms tend to repel each other, so we adopt configurations that minimize this repulsion. This reduces the molecule's energy, increases its stability, and determines the shape of the molecule. The main assumptions of VSEPR theory are:

The shape of a molecule depends on the number of electron pairs in the valence shell around the central atom. ii The electron pairs in the valence shell repel each other because the electron cloud is negatively charged. VSEPR theory is used to predict the shape of a molecule from the electron pairs surrounding the central atom of the molecule.

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the ratio of the rate of diffusion of an unknown gas to oxygen is 0.85. what is the molar mass of the unknown gas

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Molar mass of oxygen = 32 g/mo is the ratio of the rate of diffusion of an unknown gas to oxygen is 0.85.

What is oxygen explain?

Oxygen is a chemical element with an atomic number of 8 (it has eight protons in its nucleus). Oxygen forms a chemical compound (O2) of two atoms which is a colorless gas at normal temperatures and pressures. Four representations chemists use for molecular oxygen.

Do you breathe in O2?

We breathe in oxygen and some of this carbon dioxide. When we exhale, we breathe out less oxygen but more carbon dioxide than we inhale. The carbon we breathe out as carbon dioxide comes from the carbon in the food we eat.

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A 1.2 M solution of H2S reacts with a 0.80 M solution of NH2-. What volume of H2S is needed to neutralize 45mL of NH2-?

Answers

The volume of H2S needed to neutralize 45mL of NH2- is 0.053 L

What do you mean by neutralization reaction?

A neutralization reaction, in which an acid and a base react to form water and salt.

The reaction between H2S and NH2- is a neutralization reaction. The balanced equation for the reaction is:

H2S(aq) + NH2-(aq) → NH4HS(aq)

We know that the concentration of H2S is 1.2 M and the concentration of NH2- is 0.80 M and we are trying to find the volume of H2S needed to neutralize 45mL of NH2-.

The number of moles of H2S can be calculated by using the formula:

moles = molarity x volume

The volume of H2S needed to neutralize 45mL of NH2- is equal to the number of moles of NH2- in 45mL, divided by the concentration of H2S.

moles of NH2- = 0.080 L * 0.80 mol/L = 0.064 mol

volume = moles of NH2- / molarity of H2S

volume = 0.064 mol / 1.2 mol/L = 0.053 L

Therefore, the volume of H2S needed to neutralize 45mL of NH2- is 0.053 L.

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