A space shuttle orbits earth at a speed of 21,000 km/he. how far will it travel in 1.4hours? Assume the shuttle is traveling on a straight path (it is actually orbiting the Earth but for this time period the path is relatively straight).

Answers

Answer 1

The space shuttle will travel as far as 29400 km in 1.4 hours

What is Speed ?

Speed is the distance travelled per time taken. It is a scalar quantity.

Given that a space shuttle orbits earth at a speed of 21,000 km/hr. Since it is assumed that the shuttle is traveling on a straight path, to know how far it will travel in 1.4 hours, we will apply the speed formula.

Speed = distance / time

21000 = distance / 1.4

distance = 21000 x 1.4

distance = 29400 Km

Therefore, the space shuttle will travel as far as 29400 km in 1.4 hours

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Related Questions

A car drives 26.8 m/s south. It
accelerates at 3.75 m/s² at a
155.0° angle. How long does it
take until the car is driving directly
west?

Answers

Answer: the time for the car to drive directly south is determined as 7.15 s.

Explanation:

The time for the car to drive directly south is determined by applying the concept of slope.

slope = Δy/Δx

a = Δv/Δt

Δt = Δv/a

Δt = (26.8)/(3.75)

Δt = 7.15 s

Thus, the time for the car to drive directly south is determined as 7.15 s.

Questions
High-speed video can record sporting events at a
frame rate of 60 frames per second (frame/s).
What is the time interval between one frame
and the next?
8
a
b
If we can see 24 frame/s as continuous motion,
by what factor can the action recorded at
60 frame/s be slowed down and still look
continuous?

Answers

The time interval between one frame and the next is 1/60 second and it needs to be slowed down by a factor of 2.5.

The unitary method's formula is to identify the value of a single unit, then multiply that value by the number of units to obtain the required value.

The frame rate of a high-speed video while recording sporting events is 60 frames per second.

Let's say the time interval between one frame and the next is x.

Using the unitary method,

60 frames → 1 sec

1 frame → x second

So, x = 1/ 60 second

Now, in continuous motion, we can see 24 frames per second.

60 frames per second need to be slowed down to 24 frames per second.

Therefore the factor will be:

= ( 60/24 ) = ( 15/6 ) = ( 5/2 ) = 2.5

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What is a magnitude of the vectors for A and B?

Answers

The magnitude of a two dimensional vector represented by r = xi + yj is  r = √(x² + y²) and The magnitude of a three dimensional vector represented by r = xi + yj + zk  is  r = √(x² + y² + z²)

What is a vector?

A vector is a physical quantity that has both magnitude and direction

What is the magnitude of a vector?

A two dimensional vector represented by r = xi + yj has the magnitude r = √(x² + y²) where

x = x component of vector r and y = y component of vector r.

Also, a three dimensional vector represented by r = xi + yj + zk has the magnitude r = √(x² + y² + z²) where

x = x component of vector r  y = y component of vector r and z = z component of vector r.

Given a vector r = 3i + 4j, we find its magnitude thus r = √(x² + y²) where

x = 3 and y = 4

So, r = √(x² + y²)

r = √(3² + 4²)

r = √(9 + 16)

r = √25

r = 25 units

Also, given a vector r = 3i + 4j + 5k, we find its magnitude thus r = √(x² + y² + z²) where

x = 3 y = 4 andz = 5

So, r = √(x² + y² + z²)

r = √(3² + 4² + 5²)

r = √(9 + 16 + 25)

r = √(25 + 25)

r = √50

r = 5√2 units

So,

The magnitude of a two dimensional vector represented by r = xi + yj is  r = √(x² + y²) and The magnitude of a three dimensional vector represented by r = xi + yj + zk  is  r = √(x² + y² + z²)

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1. A car having an initial velocity of 12 meters per
second east slows uniformly to 2 meters per
second east in 4.0 seconds. The acceleration of
the car during this 4.0-second interval is

Answers

Answer:

5/2m/s^2

Explanation:

Acceleration is change in velocity divided by change in time. You might have seen it written like this:

ΔV/Δt

in this case, your change in velocity is -10m/s and your change in time is 4s thus your acceleration is -5/2m/s^2

If there are 7.5x1013 cells in a human body and the average cell diameter is 1×10-5 meter, how long would the string of cells be if you stretched them out in a single line?

Answers

The length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

What is human cells?

Cells are the basic building blocks of all living things, including humans. The human body is composed of trillions of cells with  average cell diameter of 1 x 10⁻⁵ m.

The length of the total cells in the human body when all the cells are stretched out is calculated as follows;

total length of the cells = average diameter of a cell x number of cells

total length of the cells = 1 x 10⁻⁵ m x 7.5 x 10¹³

total length of the cells = 7.5 x 10⁸ m

Thus, the length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

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Which quantity or quantities is/are increasing for the object represented by Line B?
(1 point)
O velocity and acceleration
O velocity and position
O velocity only
velocity, position, and acceleration

Answers

Answer:

Explanation:

velocity and position

Answer:

A. Velocity and position

Took the test.

Why does redshift occur?

Answers

Answer:

As an object moves away from us, the sound or light waves emitted by the object are stretched out, which makes them have a lower pitch and moves them towards the red end of the electromagnetic spectrum, where light has a longer wavelength.

Explanation:

Doppler shift example: Sound waves from a police car siren. The car is driving forwards. The sound waves in front of the car get bunched up and the sound waves behind the car get stretched out.

In the case of light waves, this is called redshift


How long does it take a skier to travel 547 m going 9.7 m/s?

Answers

Answer:

56.39 hours

Explanation:

I say this because to calculate how long something is traveling you have to divide the distance traveled by the rate or do distance/time


What is the equation for velocity?

Velocity = distance + time
Velocity = distance / time
Velkocity = distnace - time
Velocity = distance * time

Answers

Answer:

The equation for velocity is: Velocity = distance / time. Velocity is a measure of the speed at which an object moves in a specific direction. The equation for velocity states that the velocity of an object is equal to the distance it travels divided by the time it takes to travel that distance. This equation can be used to calculate the velocity of an object if the distance it travels and the time it takes to travel that distance are known.

Explanation:

Jack and Jill ran up the hill at 3.3 m/s. The horizontal component of Jill's velocity vector was 2.5 m/s.
what is the angle of the hill

Answers

Answer:

2538263

Explanation:

when I divide it this is the answer I got

A sphere of radius =0.280 m and uniform charge density 151 nC/m^3 lies at the center of a spherical, conducting shell of inner and outer radii 3.50 and 4.00, respectively. If the conducting shell carries a total charge of =−11.9 nC, find the magnitude of the electric field at the given radial distances from the center of the charge distribution.

Answers

The magnitude of the electric field at the given radial distances from the center of the charge distribution is, For the first case electric field=E₁= 1211.37N/C, For the second case electric field =E₂=762.82 N/C, For the third case electric field= E₃= 3276.7 N/C, For the fourth case electric field=E₄=555.04N/C

What is electric field?

Electric field is defined in a way that a field is present in a frame. There is two electric source is present that associated with each other and make the field electrified and source of electric. It can be shown in electric per unit area.

How can I calculate the electric field?

The conducting shell carries a total charge of=Q=−11.9 nC=11.9*10⁻⁹C

A sphere of radius=R =0.280m

A uniform charge density of a sphere=ρ₁= 151 nC/m³= 151×10⁻⁹C/m³

A uniform charge density of a spheric shell,

ρ₂=Q/(4/3)π[(4.00R)³−(3.50R)³]

Or,ρ₂=3Q/4πR³[(4.00)³−(3.50)³]

Or,ρ₂=3*11.9*10⁻⁹/4π(0.280)³[(4.00)³−(3.50)³]

Or,ρ₂=6.15*10⁻⁹ C/m³

We know the law of electric field,

E=(1/4πϵ₀)*(q/r²)

(a) r₁=0.76R

The electric field, in this case, can be given as:

E₁=(1/4πϵ₀)*(q₁/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*{(4/3)πr₁³}/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*(4/3)πr₁)

Or, E₁=9*10⁹*( 151×10⁻⁹*(4/3)π*0.76*0.280)

Or, E₁= 1211.37N/C

According to the calculation, The electric field for this case is, E₁= 1211.37N/C

(b) r₂=3.65R

The electric field, in this case, can be given as:

E₂=(1/4πϵ₀)*(q₂/r₂²)

Here, q₂=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=88.488*10⁻⁹C

Now, E₂=(1/4πϵ₀)*(q₂/r₂²)

Or, E₂=(1/4πϵ₀)*(88.488*10⁻⁹/(3.65*0.280)²)

Or, E₂=762.82 N/C

According to the calculation, The electric field for this case is, E₂=762.82 N/C

(c) r₃=2.30R

The electric field, in this case, can be given as:

E₃=(1/4πϵ₀)*(q₃/r₃²)

In this case, electric charge enclosed by the Gaussian surface is given by: q₃=151×10⁻⁹C/m³

Now, E₃=(1/4πϵ₀)*(q₃/r₃²)

Or, E₃=(1/4πϵ₀)*(151×10⁻⁹/(2.30*0.280)²)

Or, E₃= 3276.7 N/C

According to the calculation, The electric field for this case is,  E₃= 3276.7 N/C

(d) r₄=4.50R

Here, q₄=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=88.488*10⁻⁹C

Now, E₄=(1/4πϵ₀)*(q₄/r₄²)

Or, E₄=(1/4πϵ₀)*(88.488*10⁻⁹/(4.50*0.280)²)

Or, E₄=555.04N/C

According to the calculation, The electric field for this case is, E₄=555.04N/C

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An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves without air resistance. What is the object's acceleration at t4 = 5 seconds? Write your answer in component form.

Answers

Explanation:

An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves without air resistance. What is the object's acceleration at t4 = 5 seconds? Write your answer in component form. just use the formula, if you use formula you will know how to do.

The object's acceleration at t = 5 seconds would be 2 meters/second².

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object.

An object's position in a given coordinate system is described by the vector r = t² i - (3t + 3) j,

assuming the object moves without air resistance.

displacement = t² i - (3t + 3) j

velocity = 2t i -3 j

acceleration = 2i

Thus, the object's acceleration at t = 5 seconds would be 2 meters/second².

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A ball is dropped from the top of a 82-m-high building. What speed does the ball have in falling 3.6 s?

Answers

The speed of the ball have in falling 3.6 s is 35.5 m/s.

What is the speed of the ball?

The speed of the ball is calculated using the equation of a body falling under the influence of gravity or velocity of free fall.

The equation of the motion of the body is given as follows:

v = u - gt

where;

u is the initial velocity

g = acceleration due to gravity

t = time

v = final velocity

Assuming u = 0 m/s, g = 9.8 m/s², t = 3.6 s

v = 0 - 9.8 * 3.6

v = 35.5 m/s

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Suppose the Earth had a second moon twice as far from the Earth as our present moon. Using Kepler's 3rd Law calculate the time (period) this new moon will take to orbit the Earth

Answers

The time taken for the new moon to orbit the earth is √8 times the time taken by the present moon.

According to Kepler's third law,

[tex]T_{m} ^{2}[/tex] = ( 4 π / G [tex]m_{E}[/tex] ) r³

[tex]T_{m}[/tex] = Time taken by the moon

G = Gravitational constant

[tex]m_{E}[/tex] = Mass of Earth

r = Radius of moon

r' = 2 r

r' = Radius of new moon

[tex]T'_{m} ^{2}[/tex] = ( 4 π / G [tex]m_{E}[/tex] ) ( 2 r )³

[tex]T'_{m} ^{2}[/tex] = 8 ( 4 π / G [tex]m_{E}[/tex] ) r³

[tex]T'_{m}[/tex] = √8 [tex]T_{m}[/tex]

Kepler's third law states that square of time period of a planet's orbit is equal to the cube of semi-major axis of the orbit.

Therefore, the time taken for the new moon to orbit the earth is √8 times the time taken by the present moon.

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Create a series of eight successive displacements that would program a robot to move in an octagonal path that is as close as you can get to approximating a circle. The robot should return to its starting point after the eighth displacement. What total distance does the robot move? Calculate the radius of the circle that has this distance as its circumference.

Answers

Answer:

Ex; If the robot traveled 20 cm around the octagon then the circle circumference = 20 cm

Use the equation circumference = 2 π radius to calculate radius(C = 2πr)

          If circumference = 20cm;  radius = circumference / ( 2 π) = 20/6.28= 3.18 cm. Use your scale to express your answer in meters, km, etc

now set the protractor distance measure as 3.18 cm, place the protractor's metal spike at the octagon center and draw the circle.

Explanation:

A rock is dropped from a sea cliff, and the sound of it
striking the ocean is heard 2.7 s later. If the speed of sound is 340 m/s, how high is the cliff?

Answers

The height of the cliff is 88 m.

The initial velocity of the rock, when it is dropped is V(i) = 0 m/s.

The sum of the time taken by the rock to reach the surface of the ocean from the sea cliff and the time taken by the sound of the splash of the rock to the ears of the person who threw the rock is t = 2.7 s.

The speed of sound in air is V(s) = 340 m/s.

The acceleration due to gravity is g = 10 m/s².

The displacement made by the rock during this period will be as follows if we use the kinematic equation for translational motion under gravity and assume that the time it takes the rock to reach the ocean's surface is t₁ :

d = 0 − h = V(i) × t₁ + (1/2) × (− g ) × ( t₁ )²

Since the positions of the rock are taken from the surface of the ocean.

Substituting the values in the equation.

t₁ = √ [ 2h/g ]

( t₁ )² = 2h / g

Since sound moves through the medium at a constant speed, the following is how long it will take for the sound to reach the rock-thrower:

t₂ = h / V(s)

h = V(s) × t₂

Therefore,

( t₁ )² = ( 2 × V(s) × t₂) / g

Now, since t = t₁ + t₂ , therefore, t₂ = t − t₁ .

( t₁ )² = ( 2 × V(s) × ( t - t₁ ) ) / g

( t₁ )² = 2 × ( 340 ) ×( 4.5 − t₁ ) / 10

( t₁ )² = 306 − 68 t₁

Now,

( t₁ )² - 306 + 68t₁ = 0

By using the quadratic formula,

t₁ = { − 68 ± √ [( 68 )² − 4 × ( 1 ) × ( − 306 )] } / 2 × ( 1 )

t₁ = − 68 ± 76.47 / 2

( t₁ = − 68 + 76.47 / 2 = 4.24 s) and;

( t₁ = − 68 − 76.47 / 2 = − 72.24 s )

Since time can't be negative,

t₁ = 4.24 s.

Therefore,

t₂ = t − t₁

t₂ = 4.5 s − 4.24 s

t₂ = 0.26 s

Now,

h = V(s) × t₂

h = ( 340 m / s ) × ( 0.26 s )

h ≈ 88 m

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In general, what goes on the y-axis of a graph?
O the constant variable
O the independent variable
O the control variable
O the dependent variable

Answers

Answer:

O the dependent variable

Explanation:

The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis (vertical line).

Hi,

In general, what goes on the y-axis of a graph?

O the dependent variable

According to Pascal, pressure applied to a fluid __.

Answers

According to Pascal, pressure applied to a fluid is transmitted equally in all directions.

P = F / A

P = Pressure

F = Force

A = Area

Pressure is in Pa ( Pascals ).

Force is in N ( Newtons )

Area is in m² ( Meter² )

Pascal's law states that, pressure applied to an incompressible fluid enclosed in a container is transmitted equally throughout the fluid without any change in magnitude.

Therefore, According to Pascal, pressure applied to a fluid is transmitted equally in all directions.

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What element has 31 neutrons and is in group 10

Answers

Answer:

Nickel is the correct answer here.

Which of the following statements is TRUE?
A. When muscles contract they become longer.
B. Involuntary muscle can be identified by its unique striped appearance.
C. The biceps and quadriceps are an antagonistic pair.
D. The origin of a muscle is attached to the bone that does NOT move.

Answers

D the origin of a muscle is attached to the bone that does not move

The tailgate of a car is supported by the hydraulic lift BC. If the lift exerts a 132-lb force directed along its centerline on the ball and socket at B, determine the moment of the force about A.

Answers

The moment of the force about point A found using the moments formula, [tex]|M| = |F| \cdot \: d \perp[/tex] is 67.695 ft–lb.

What is the moment of a force?

The moment of a force is the turning effect of the force about a point.

The moment of the force is given by the formula;

[tex]|M| = |F| \cdot \: d \perp[/tex]

Where;

d = The perpendicular distance from the point to the line of action of the force.

The length of the sides of ∆ABC are;

AB = √(20.5²+4.38²) ≈ 20.9626907

BC = √(17.2²+7.62²) ≈ 18.812347

AC = √((7.62+4.38)²+(20.5-17.2)²) ≈ 12.4454811

The semi–perimeter of triangle ABC = (20.9626907 + 18.812347 + 12.4454811)/2 ≈ 26.1102594

The area, A, of triangle ∆ABC found using Heron's formula is therefore;

A = √((26.1102594×(26.1102594-20.9626907)×(26.1102594-18.812347)×(26.1102594-12.4454811)) ≈ 115.773

The perpendicular distance, d, from point A to BC is therefore;

d = A/(BC)

Which gives;

d = 115.773/18.812347 ≈ 6.15409696

The magnitude of the moment about point A is therefore;

M = 132 lb × 0.51284138 ft. ≈ 67.695 ft.–lb

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What would the motion look like for a person starting 0.4 m away and walking at a constant speed of 0.5 m/s away from the motion detector?

Answers

The motion of the person on a velocity time graph would show a flat portion which indicates that there is no change in the speed.

What is constant velocity?

If the person moves at constant velocity, it implies that the velocity is not changing with time. This implies that the person does not change speed and that the acceleration of  the person is zero.

Accordingly, the motion of the person on a velocity time graph would show a flat portion which indicates that there is no change in the speed of the object with time as the person moves.

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We desire to make an LC circuit that oscillates at 100 Hz using an
inductance of
2.5H. We also need a capacitance of

Answers

The capacitance needed in the LC circuit is 1 μF.

Capacitance needed to make the LC circuit

The capacitance needed to make the LC circuit is calculated as follows;

capacitive reactance = inductive reactance

Xc = Xl

1/2πfC = 2πfL

2πfC(2πfL) = 1

4π²f²LC = 1

LC = 1/4π²f²

C = 1/(4π²f²L)

where;

L is the inductancef is the frequencyC is the capacitance

Substitute the given parameter and solve for the capacitance as follows;

C = (1)/(4π² x 100² x 2.5)

C = 1.01 x 10⁻⁶ F

C ≈ 1 μF

Thus, the capacitance needed in the LC circuit is 1 μF.

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A helicopter’s speed increases from 30 m/s to 40 m/s in 5 seconds.

What is the acceleration of this helicopter?

Answers

Answer:

2 m/s²

Explanation:

To calculate the acceleration of an object, we use the following formula:

[tex]\boxed{a = \frac{v - u}{t}}[/tex],

where:

• a = acceleration

• v = final speed

• u = initial speed, and

• t = time taken

We are told in the question that the final speed of the helicopter is 40 m/s, its initial speed is 30 m/s, and that the time it took to get from 30 m/s to 40 m/s is 5 seconds.

Therefore, using this information, as well as the formula above, we can evaluate the acceleration of the helicopter:

[tex]a = \frac{40 - 30}{5}[/tex]

  [tex]= \frac{10}{5}[/tex]

  [tex]= \bf 2 \: m/s^2[/tex]

So the acceleration of the helicopter is 2 m/s².

At 10–10 s during the evolution of the universe,
formed, which are elementary particles that make up protons and neutrons.

Answers

At 10⁻¹⁰ s during the evolution of the universe, quarks formed, which are elementary particles that make up protons and neutrons.

The three subatomic particles.

Generally, an atom comprises three (3) distinct subatomic particles and these include the following

Protons.Neutrons.Electrons.

What are protons?

Protons can be defined as the positively charged subatomic particles that are found in the nucleus of a chemical element and they have a magnitude of +1. Also, the number of protons in the nucleus of a chemical element always the same as its atomic number.

What are quarks?

Quarks can be defined as the elementary particles that make up both protons and neutrons, and they are the basic component of matter. Also, quarks have a charge that's approximately equal to 1.07 × 10⁻¹⁹ Coulomb.

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Complete Question:

At 10⁻¹⁰ s during the evolution of the universe, ________ formed, which are elementary particles that make up protons and neutrons.

We are in an elevator going down at constant speed. All these forces are acting on us, except:

A- air drag
B- a torque
C- gravity
D- a reaction from the elevator floor

Answers

In an elevator going down at constant speed. All these forces are acting on us, except option B. a torque.

Torque is the rotational equivalent of a linear force. In some fields of study, it is also called moment, moment of force, rotational force, or rotational effect. It describes the ability of a force to effect a change in the rotational motion of an object.

Torque is the torque that interacts with the torque of the motor and measures how much of that torque is available when the motor is exerting itself. Torque is present in everyday events. B. Turning a doorknob, opening a soda bottle, using a wrench, pedaling a bicycle.

Constant speed means that the velocity does not change at all for each second of movement. The example of driving a car with cruise control shows constant speed. Constant acceleration means that the velocity increases at the same constant rate every second of his.

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A tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes. How far would it have traveled?

Answers

If a tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes, then it would have traveled 37.49 meters

What is speed?

The total distance covered by any object per unit of time is known as speed.

It depends only on the magnitude of the moving object.

As given in the problem a tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes.

The distance traveled by the tumbleweed = speed ×time

                                                                       =  16.3 meters/minute×minutes

                                                                       =37.49 meters

Thus, the distance traveled would be 37.49 meters.

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You hike two thirds of the way to the top of a hill at a speed
of 3.5 mi/h and run the final third at a speed of 6.5 mi/h.

Answers

The correct answer is 4.14456 mi/hour.

The entire distance that an object travels in a given amount of time is the definition of average speed for that object. You can figure it out by dividing the overall distance traveled by the overall journey time.

When an object travels a distance at a variety of speeds, its average speed is the speed at which, if the object moves uniformly, it will travel the same distance in the same amount of time.

average speed= total distance / total time

total distance = 1 mile

The total time = 2 / ( 3 × 3.5 ) = 0.190 hour

time for coming = 1 / (3 × 6.5 ) = 0.05128 hour

Thus the average speed = 1 / ( 0.190 + 0.05128 ) = 1 / 0.24128 = 4.14456 mi/hour.

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Particle 1 is moving on the x-axis with
an acceleration of 3.37 m/s² in the positive
x-direction. Particle 2 is moving on the y-
axis with an acceleration of 5.18 m/s² in the
negative y-direction. Both particles were at
rest at the origin at t = 0 s.
Find the speed of particle 1 with respect to
particle 2 at 2.83 s.
Answer in units of m/s.

Answers

The speed of particle 1 with respect to particle 2 which is moving perpendicular to each other at 2.83 s is 20.89 m / s

a = v / t

v = x / t

[tex]a_{1}[/tex] = 3.37 m / s²

[tex]a_{2}[/tex] = 5.18 m / s²

t = 2.83 s

[tex]v_{1}[/tex] = [tex]a_{1}[/tex] * t

[tex]v_{1}[/tex] = 3.37 * 2.83

[tex]v_{1}[/tex] = d[tex]x_{1}[/tex] / dt = 9.54 m / s

[tex]v_{2}[/tex] = [tex]a_{2}[/tex] * t

[tex]v_{2}[/tex] = 5.18 * 2.83

[tex]v_{2}[/tex] = d[tex]x_{2}[/tex] / dt = 14.66 m / s

[tex]x_{1}[/tex] = [tex]v_{1}[/tex] * t

[tex]x_{1}[/tex] = 9.54 * 2.83

[tex]x_{1}[/tex] = 27 m

[tex]x_{2}[/tex] = [tex]v_{2}[/tex] * t

[tex]x_{2}[/tex] = 14.66 * 2.83

[tex]x_{2}[/tex] = 41.49 m

Since they are moving perpendicular to each other, they make a right angled triangle. According to Pythagoras theorem,

[tex]x_{3} ^{2}[/tex] = [tex]x_{1} ^{2}[/tex] + [tex]x_{2} ^{2}[/tex]

On differentiating with respect to t,

2[tex]x_{3}[/tex] d[tex]x_{3}[/tex] / dt = 2[tex]x_{1}[/tex] d[tex]x_{1}[/tex] / dt + 2[tex]x_{2}[/tex] d[tex]x_{2}[/tex] / dt

41.49 ( d[tex]x_{3}[/tex] / dt ) = 27 ( 9.57 ) + 41.49 ( 14.66 )

d[tex]x_{3}[/tex] / dt = ( 258.4 + 608.24 ) / 41.49

d[tex]x_{3}[/tex] / dt = [tex]v_{12}[/tex] = 20.89 m / s

Therefore, the speed of particle 1 with respect to particle 2 at 2.83 s is 20.89 m / s

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A peregrine falcon dives at a pigeon. The falcon starts downward from rest and falls with free-fall acceleration. If the pigeon is 68.6 m below the initial position of the falcon, how long does the falcon take to reach the pigeon? Assume that the pigeon remains at rest. The acceleration of gravity is 9.8 m/s².​

Answers

The falcon take 14 seconds to reach the pigeon.

What are equation of motion ?

A mathematical expression that expresses the location, speed, or acceleration of a body in relation to a specified frame of reference is called as Equation of motion,

By using equation of motion

s = [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

where, s = total distance travelled by an object = 68.6 m

g = acceleration of gravity = 9.8m/[tex]s^{2}[/tex]

t = time taken to travel the distance = ?

Therefore, t = [tex]\sqrt{2s/g}[/tex]

t = [tex]\sqrt{2*68.6/9.8}[/tex]

t = 14 seconds

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