Answer:
Approximately [tex]3.14\; {\rm rad \cdot s^{-1}}[/tex].
Explanation:
Fact: the angular velocity [tex]\omega[/tex] of a simple harmonic oscillator is the ratio between the maximum velocity [tex]v_{\text{max}}[/tex] and the maximum displacement [tex]x_\text{max}[/tex] of this oscillator. In other words:
[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}}\end{aligned}[/tex].
Derivation of the previous equation:
Let [tex]A[/tex] denote the amplitude of this oscillation, and let [tex]\omega[/tex] denote the angular velocity.
The displacement of the oscillator at time [tex]t[/tex] would be:
[tex]x(t) = A\, \sin(\omega\, t)[/tex].
The maximum displacement of this oscillator would be [tex]x_\text{max} = A[/tex].
The velocity of this oscillator at time [tex]t[/tex] is the derivative of displacement with respect to time:
[tex]\begin{aligned} v(t) &= \frac{d}{d t}\, [x(t)] \\ &= \frac{d}{d t} [A\, \sin(\omega\, t)] \\ &= A\, \omega\, \cos(\omega\, t)\end{aligned}[/tex].
The maximum velocity of this oscillator would be [tex]v_\text{max} = A\, \omega[/tex].
Notice that dividing [tex]v_\text{max} = A\, \omega[/tex] by [tex]x_\text{max} = A[/tex] would give:
[tex]\displaystyle \frac{v_\text{max}}{x_\text{max}} = \frac{A\, \omega}{A} = \omega[/tex].
It is given that [tex]v_\text{max} = 2.76\; {\rm m\cdot s^{-1}}[/tex] while [tex]x_\text{max} = 0.0880\; {\rm m}[/tex]. Therefore:
[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}} \\ &= \frac{2.76\; {\rm m\cdot s^{-1}}}{0.0880\; {\rm m}} \\ &\approx 3.14\; {\rm s^{-1}}\end{aligned}[/tex].
(Radians per second.)
Put the steps of the scientific method in order.
A. Question -> Research -> Hypothesis -> Experiment -> Analysis -> Conclusion
B. Research -> Hypothesis -> Experiment ->Question -> Conclusion -> Analysis
C. Research -> Question -> Hypothesis -> Experiment -> Analysis -> Conclusion
D. Hypothesis -> Experiment -> Conclusion -> Question -> Research -> Analysis
Answer:
c
Explanation:
Answer:
c
Explanation:
im smart
Guillaume Amontons first took a stab at measuring absolute zero in 1702. What would be the most reasonable way it would have been done then?
A) Measure the pressure of a gas in a container at various temperatures, say from 100 °C down to maybe −20 °C, then extrapolate to the temperature at which the pressure would reach zero.
B) Measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.
C) Measure the pressure of a gas and cool it until the pressure is zero.
He would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops(option A).
What is the absolute zero?The absolute zero refers to the temperature at which the gas seems to stop moving. Recall that temperature is the measure of the average kinetic energy of the molecules of a gas. We now have to consider the options and see the one that connects temperature and speed of molecules.
Hence, if Guillaume Amontons first took a stab at measuring absolute zero in 1702, he would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.
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In which device is chemical energy transformed into electrical energy?
Answer:
A Rechargeable Battery
Explanation:
That is roughly what happens when a secondary cell is recharged (rechargeable battery.) Electric current transforms one chemical species with a lower energy level into another with a higher energy level. When the battery is loaded, this energy can be released. Strictly speaking, no conversion occurs: chemical energy is electrical energy! The energy of electrons in any particular substance, such as metal, are due to electron interactions with the nuclei in the substance and with each other. Electrons, in particular, occupy certain energy levels in metals. Because each metal has a distinct highest occupied energy level, electrons can alter their energies by traveling from one metal to another. An electrical current is made up of this movement!
When an object is placed 30.0 cm in front of a concave mirror, a real image is formed 60.0 cm
from the mirror's surface. Find the focal length.
Answer=20.0cm
I need the steps I have a final exam and I’m confused can someone help and type it please ?
Answer:
1 / f = 1 / o + 1 / i = (i + o) / o * 1
f = o * i / (o + i) = 60 * 30 / (60 + 30) = 1800 / 90 = 20 cm
Both the object and image are in positive space for a mirror
A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The positive terminals are indicated with a + sign, The values for the resistors are: R1 = R5 = 70 Ω, R2 = R6 = 106 Ω R3 = 59 Ω, and R4 = 83 Ω. The positive directions for the currents I1, I2 and I3 are indicated by the directions of the arrows. What is I3?
The I3 will be 158 A.
How to find the current through the circuit?The foundation of circuit analysis is Kirchhoff's circuit laws.We have the fundamental instrument to begin studying circuits with the use of these principles and the equation for each individual component (resistor, capacitor, and inductor).These rules aid in calculating the current flow in various network streams as well as the electrical resistance of a complicated network, or impedance in the case of AC.To calculate I3 firstly, V4 has to be calculated,
[tex]V_{4} =I_{4} R_{4}[/tex]
[tex]V_{4} = V_{2} / R_{4} + R_{5} * R_{4}[/tex]
[tex]V_{4} = 12 * 135 / 135+61[/tex]
[tex]V_{4} = 8.26V[/tex]
For I3,
[tex]I_{3} = R_{1} /(R1+R3 + (R1+R3)(R2+R6) * (V2 - V1 (R1+R2+R6/R1)[/tex]
[tex]I3=(61)/((61)(50)+(61+50)(141+141)) (12 -18 (1+(141+141)/61)) = -.158 A[/tex]
Hence, the current through I3 will be 158 A.
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What is the relative velocity of two beta particles moving in opposite directions at a speed of 0.8c?
That depends on where YOU are when you measure it.
If you're motionless in the laboratory, then you measure the particles flying apart at 1.6c .
If you're riding on one of the particles, you measure the other one flying away from you at less than c
A 7.30 kg sign hangs from two wires. The
first wire is attached to the left end, and
pulls 28.0 N directly left. What is the
x-component of the force of
the second
wire?
Answer:
[tex]28.0\; {\rm N}[/tex] to the right.
Explanation:
Since the sign is not moving, the net force on this sign should be [tex]0\; {\rm N}[/tex]. For that, the horizontal component ([tex]x[/tex]-component) of external forces on this sign should be [tex]0\; {\rm N}[/tex].
Sources of external forces on this sign include tension from the wires, as well as gravitational pull (weight) from the earth. The gravitational pull from the earth is entirely vertical ([tex]y[/tex]-component,) with a magnitude of [tex]0\; {\rm N}[/tex] in the horizontal direction. Thus, the only external forces on this sign in the [tex]x[/tex]-component would be from the two wires.
The question states that the [tex]x[/tex]-component of the force from the first wire is [tex]28.0\; {\rm N}[/tex] to the left. Thus, for the net force in the [tex]x[/tex]-direction to be [tex]0\; {\rm N}[/tex], the force from the other wire in the [tex]x\![/tex]-component needs to be [tex]28.0\; {\rm N}\![/tex] to the right (same magnitude but opposite direction.)
Using what you learned above, try to predict the missing entries in the table below. Use the simulation to check your answer and type in the correct answer.
there is no pic or whatever to show
The frequency of a waveform is found by determining the...
Select one:
a. number of crests passing a point in a given time.
b. distance from a wave's midpoint to its crest.
c. distance between two moving low points of the wave.
d. distance between a crest and a trough.
By counting the number of crests that pass a point in a specific amount of time, one may determine the frequency of a waveform. Option a is correct.
What is the frequency of the sound?A sound pressure wave's frequency, also known as pitch, is the number of times it repeats itself every second.
The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.
The frequency of a waveform is found by determining the number of crests passing a point in a given time.
Hence option a is correct.
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The internal energy of a gas is 500 J. The gas is compressed adiabatically, and its volume decreases by 100c * m ^ 3 If the pressure applied on the gas during compression is 3.00 atm, what is the internal energy of the gas after the adiabatic compressio
The internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
What is work done by gas?When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.
Given data;
pressure(P)=3.0 atm = 303975 N/m²
The initial volume, V₁
work is done on the gas., W=?(-ve)
Change in heat, ΔQ=0
Change in the internal energy of the gas., ΔE
The work done on the gas;
W = -PΔV
W= - 303975 N/m² × 100 cm³
W = - 30.3 × 10⁶ J
The internal energy is found as;
ΔE=q+w
ΔE= 0-30.3 × 10⁶ J
ΔE= -30.3 × 10⁶ J
E₂-E₁= -30.3 × 10⁶ J
E₂ = -30.3 × 10⁶ J +500
E₂ = 30.398 × 10⁶ J
Hence, the internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
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If a current uses 31 amperes and has a voltage of 110 volts, how many watts does it dissipate?
Considering the Watt's law, if a current uses 31 amperes and has a voltage of 110 volts, it dissipates 3,410 Watts.
CurrentCurrent is the physical magnitude that expresses the amount of electricity that flows through a conductor in unit time and is measured in amps.
VoltageThe voltage is the difference between the electrical charge that leaves the source and the one that finally reaches the end of the circuit. It is expressed in volts.
Watt's LawWatt's Law refers to the electrical power of an electronic component or device and is defined as the power consumed by the load is directly proportional to the voltage supplied and the current flowing through it. The unit of power is the Watt.
Knowing the voltage and current, this law is expressed as:
P = V×I
Power in this caseIn this case, you know:
V= 110 voltsI= 31 amperesReplacing in Watt's Law:
P = 110 volts× 31 amperes
Solving:
P= 3,410 Watt
Finally, if a current uses 31 amperes and has a voltage of 110 volts, it dissipates 3,410 Watts.
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A skier (m=55.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally.
a. If h = 6.50 m and D = 11.4 m, find H.
b. Find her total kinetic energy as she reaches the ground.
a. The value of H is 11.51 m
b. The total kinetic energy as she reaches the ground is 6.21 kJ.
The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
Given is a skier (m=55.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. Value of h = 6.50 m and D = 11.4 m.
Time taken to reach the ground after take off is
t = √2h/g
t = √(2x6.50) /9.81
t =1.15 s
The speed at that time is
speed = distance /time
v = 11.4 /1.15
v = 9.913 m/s
a. From energy conservation principle,
v = √2g(H-h)
Plug the values, we get
9.913 = √(2 x 9.81 (H - 6.5)
Squaring both sides and solving, we have
H = 11.51 m
Thus, the value of H is 11.51 m.
b. The energy at the ground will be only potential energy
Total kinetic energy at the ground = mgH
T.K.E = 55 x 9.81 x 11.51
T.K.E =6.21 kJ
Thus, the total kinetic energy is 6.21 kJ.
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The position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively. Find the unit vector along r(t)
The unit vector along r(t) will be 3t–4t^2+2
A vector is a quantity with direction and magnitude that is especially useful for locating one location in space in relation to another. A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields weight are a few examples of vectors in nature.
Given the the position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively.
We have to find the unit vector along r(t)
To find the unit vector along r(t) we have to put the value of (i,j,k) = (1,1,1) in r(t)
So,
r(t) = 3tî–4t^2j+2k
r(t) = 3t(1)–4t^2(1)+2(1)
r(t) = 3t–4t^2+2
Therefore the unit vector along r(t) will be 3t–4t^2+2
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Lucia wants to change the motion map shown so that it’s shows uniform circular motion. What change should Lucia make ?
Answer:
The last one - each vector pointing towards the center of the circle must be the same length for uniform circular motion
Temperatures expressed in the Kelvin scale are ____ higher than temperatures in the Celsius scale?
A.) 200°
B.) 283°
C.) 460°
D.) 273°
Answer:
Temperatures expressed in the Kelvin scale are D.) 273° higher than temperatures in the Celsius scale.
Explanation:
This answer is 110% correct guaranteed!
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What is the force of gravity in water
Which statement about the accuracy and precision of measuring tools is
true?
OA. A tool can be both accurate and precise.
о B. Tools that are precise must also be accurate.
о C. Tools cannot be both accurate and precise.
O D. A tool that is accurate lacks precision.
The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.
What is accuracy?When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.
Precision is about comparing the values to each other then find them near to each other.
Accuracy compares the experimental value to the theoretical value.
So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.
Thus, the correct option is C.
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Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
The force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N
What is gravity?The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.
Given, a 1 kg box located at a point 1.3 × 10⁷ m from the center of Earth. The Earth has the acceleration due to gravity, g = 9.81 m/s².
Force of gravity F = GMm/R²
where G = gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg² and R is the distance between two masses.
The Mass of Earth M= 5.98 × 10²⁴ kg
Substituting the values, we get
F = (6.67 x 10⁻¹¹ N.m²/kg² x 1kg x 5.98 × 10²⁴ kg)/ ( 1.3 × 10⁷ m)²
F = 2.36 N
Therefore, the force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N
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One principle of civil engineering is that when you design a highway you should have traffic flow in
the same direction and avoid interruptions to that flow as much as possible. Exit ramps tend to be
curved so that cars don't have to stop rather than having 90-degree angles that force stops and
starts. This is an application of which Gestalt principle?
The good continuation is an application of the Gestalt principle.
What is good continuation?
According to the Law of Good Continuation, figures with smooth edges are more likely to be perceived as continuous than those with abrupt or sharp angles.
One rule of civil engineering is that while designing a highway, traffic should move in one direction and be as free of interruptions as feasible.
Instead of having 90-degree angles that require stops and starts, exit ramps typically incorporate curves to prevent motorists from having to halt. Applying the Gestalt concept to a good continuation
Hence the good continuation is an application of the Gestalt principle.
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A stationary 0.750kg ball is thrown up by doing 2.50J of work on it. What is the velocity of the ball?
When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.
What is Work energy theorem?It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J
The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be
W= ΔK.E = K.Ef - K.Ei
According to work energy theorem, work done is
W = 2.5J = 1/2 x 0.750 x (v)² -0
v =2.6 m/s
Thus, the velocity of the ball is 2.6 m/s
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the projectile thrown with the same initial velocity , one at an angle theta and the other at an angle 90-theta can both projectiles strike at the same distance from the projection point? can both projectiles be in air for the same time interval?
Answer:
If theta is equal to 90, then both projectiles strike at the same distance from the projection point and projectiles are in air for the same time interval.
Explanation:
If a crane worker lifts a crate with a mass of 250 kg from the ground to a
shipping container that is 20 meters off the ground, by how much has the
worker increased the gravitational potential energy of the crate? (Recall that g
= 9.8 m/s²)
A. 75,000 J
B. 61,000 J
C. 83,000 J
D. 49,000 J
D.
The gravitational of a body is possessed by the body due to the virtue of its position.
The formula for gravitational potential energy is,
P.E = mgh joules
Substituting the values
196*9.8*250= 49k
A 50 N force is applied to the free end of a spiral spring of force constant, 100 Nm
Calculate the work done by the force to stretch the spring.
The work done by the force to stretch the spring is determined as 12.5 J.
Work done by the forceThe work done by the force to stretch the spring is calculated as follows;
W = ¹/₂Fx
F = kx
W = ¹/₂F(F/k)
W = ¹/₂F²/k
W = ¹/₂ x (50²)/100
W = 12.5 J
Thus, the work done by the force to stretch the spring is determined as 12.5 J.
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NGC 300 is the name of a spiral galaxy that looks similar to our Milky Way galaxy. It contains billions of stars. How is NGC 300 different from our solar system?
NGC 300 is different from our solar system because of its smaller size.
How is NGC 300 different from our solar system?NGC 300 galaxy is different from our solar system because of its size. NGC 300 is smaller than our solar system which means that it has less number of stars as compared to our solar system.
So we can conclude that NGC 300 is different from our solar system because of its smaller size.
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Set up the Applied Force (force exerted) on both crates with the current Friction setting at 350 N. On Part 2, draw a force diagram that includes all external forces acting on the two crates
The acceleration will be constantly equal to 1 m/s².Option c is correct.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Given data;
Force,F = 350 N
Friction force,f=350 N
F=f
Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².
Hence option c is correct.
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Determine the speed at which the medicine leaves the needle
The speed at which the medicine leaves the needle is 2.462 m/s
What is Bernoulli's theorem?When an incompressible, ideal fluid is flowing through a tube or pipe, the total energy remains constant.
p₁ /ρg + v₁²/2g +z₁ = p₂ /ρg + v₂²/2g +z₂
Where, p/ρg = pressure energy
v²/2g = kinetic energy
z = potential energy
Given is during an injection, pressure in the barrel of syringe is 1.03 atm while pressure in the needle section is 1.00 atm. Assuming the syringe lays horizontally and mass density of the liquid medicine ρ =1000 kg/m³.
The fluid is initially at rest.
Using the Bernoulli's equation, we have
v₁² - v₂²= 2 x (p₂ -p₁) / ρ
Substituting the values, we get
0 - v₂² = 2 x (1.00 -1.03) x 1.01 x 10⁵ /1000
v₂² = 6.06
v₂ = 2.462 m/s
Thus, the speed at which the medicine leaves the needle is 2.462 m/s
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An object has a displacement of 45
degrees. Convert this displacement
to minutes.
[?] minutes
Answer:
45° to min.
1° ----> 60 min
45° ----> ?.
45 * 60
2700 min
2700 minExample 3 :
A liquid with relative density 0.9 and dynamic viscosity of 0.06 Pas
flows in a cast iron pipe of length 100 m and diameter 120 mm.
Determine the friction factor using formula method, and then
calculate the head loss using the answer obtained then using
friction factor formula when the velocity is:
a) 1 ms-1
b) 3 ms-1
The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.
How to determine the friction factorUsing the formula
μ = viscosity = 0. 06 Pas
d = diameter = 120mm = 0. 12m
V = velocity = 1m/s and 3m/s
ρ = density = 0.9
a. Velocity = 1m/s
friction factor = 0. 52 × [tex]\frac{0. 06}{0. 12* 1* 0. 9}[/tex]
friction factor = 0. 52 × [tex]\frac{0. 06}{0. 108}[/tex]
friction factor = 0. 52 × 0. 55
friction factor [tex]= 0. 289[/tex]
b. When V = 3mls
Friction factor = 0. 52 × [tex]\frac{0. 06}{0. 12 * 3* 0. 9}[/tex]
Friction factor = 0. 52 × [tex]\frac{0. 06}{0. 324}[/tex]
Friction factor = 0. 52 × 0. 185
Friction factor [tex]= 0.096[/tex]
Loss When V = 1m/s
Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter
Head loss = 0. 289 × [tex]\frac{1}{2*6. 6743 * 10^-11}[/tex] × [tex]\frac{1^2}{0. 120}[/tex] × [tex]\frac{1}{100}[/tex]
Head loss = 1. 80 × 10^8
Head loss When V = 3m/s
Head loss = [tex]0. 096[/tex] × [tex]\frac{1}{1. 334 *10^-10}[/tex] × [tex]\frac{3^2}{0. 120}[/tex] × [tex]\frac{1}{100}[/tex]
Head loss = 5. 3× 10^8
Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.
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what type of energy does a pv cell create ?
Answer: Solar Photovoltaic (PV) cells generate electricity by absorbing sunlight and using that light energy to create an electrical current. There are many PV cells within a single solar panel, and the current created by all of the cells together adds up to enough electricity to help power your school, home and businesses.
--Cited from Solar Schools
. Bobby and Alice are pushing a stalled car in the same direction. The mass of the car is 2,000 kg. Bobby applies 400 N to the car while Alice applies 300 N. A force created by friction is 500 N in the opposite direction. What is the acceleration of the car?
Bobby and Alice are pushing a stalled car in the same direction. The mass of the car is 2,000 kg. Bobby applies 400 N to the car while Alice applies 300 N. A force created by friction is 500 N in the opposite direction is the acceleration of the car is 0.1 m/sec.
What is acceleration?An acceleration, fee at which pace adjustments with time, in phrases of each velocity and direction. A factor or an item shifting in a direct line is expanded if it hurries up or slows down.
Is summarized via way of means of the equation: Force (N) = mass (kg) × acceleration (m/s²).The mass = 2000 kg and force= 1200 N. So mass / force = 2000/1200 = 0.1 m/sec.
Thus, the acceleration of the car s 0.1 m/sec.
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