A stone of mass 5g is projected with a rubber catapult. if the catapult is stretched through a distance of 7cm by an average force of 70 North, calculate the instantaneous velocity of the stone when released ​

Answer:

Explanation:

Distributive property:

A(B+C)=AB+AC

(4x-2)2

Switch sides.

→ 2(4x-2)

Multiply.

⇒ 2*4x=8x

⇒ 2*2=4

Rewrite the problem down.

⇒ = 8x-4

[tex]\Longrightarrow: \boxed{\sf{8x-4}}[/tex]

I hope this helps you! Let me know if my answer is wrong or not.

Answer: 8x - 4

Explanation:

(4x -2)*2

apply distributive property

2* 4x - 2 * 2

Multiply the monomials = 8x

2*4x - 2*= 8x-2*2

calculate =

8x-4

Answer: 8x - 4

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

then the direction is one is left and other one is right so thats my hint

Answer:

P =  ρ g H       explains the pressure of a uniform column of density ρ

P = ρ H            where ρ is given as a weight density

P = 9800 N/m^3 * .60 m = 5880 (5900) N / m^2

Note N/m^2 = Force / Area      the definition of pressure

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)

Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
          = 123.90*105.8/283.89
          = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .

In a chemical equation, the substance or substances to the left of the arrow are referred to as reactants. A substance that is present when a chemical reaction first begins is known as a reactant.

Products refer to the material or substances to the right of the arrow. A substance that is present after a chemical reaction is complete is called a product.

Given Data:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)

Then it is given by:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

The equation becomes :

m(P4) = M(P4)*m(P4O10)/M(P4O10)

         = 123.90*105.8/283.89

         = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)

               = 10*122.55*105.8/283.89/3

               = 149 (grams).

Thus, 149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .

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Hi there!

A)

At this point, the pilot is experiencing a DOWNWARD NET centripetal force (ALWAYS points towards the center of the circle) as well as a downward force due to gravity. Additionally, we can say that the normal force exerted by the seat on the pilot is its apparent weight.

[tex]\Sigma F = F_g + F_N[/tex]

**The net force is the centripetal force.

We can assign both to be positive since they work in the same direction. (Assigning down as positive in THIS situation will make things easier).

We know that:
[tex]F_c = \frac{mv^2}{r}[/tex]

Fc = Centripetal force (N)
m = mass (kg)
v = velocity (m/s)

r = radius (m)

[tex]F_g = mg[/tex]

Fg = Force due to gravity (N)
m = mass (kg)
g = acceleration due to gravity (9.81 m/s²)

Solve for mass. (Given weight)

[tex]m = \frac{F_g}{g}\\\\m = \frac{719}{9.8} = 73.367 kg[/tex]
Now, we have everything we need to solve.

[tex]\frac{mv^2}{r} = F_g + F_N \\\\\frac{mv^2}{r} - F_g = F_N\\\\F_N = \frac{(73.367)(225^2)}{3110} - 719 = \boxed{475.278 N}[/tex]

B)
Weightlessness is achieved when the pilot is in free fall. In this instance, FN (Normal force by the seat) = 0 N.

We can use the same setup as above.

[tex]\frac{mv^2}{r} = F_g + 0 (F_N)[/tex]

[tex]\frac{mv^2}{r} = mg[/tex]

Solve for 'v'.

[tex]\frac{v^2}{r} = g\\\\v = \sqrt{gr} = \sqrt{(9.81)(3110)} = \boxed{174.669 \frac{m}{s}}[/tex]

C)
At the BOTTOM, we have the force of gravity working DOWNWARD (Negative in this instance), while the centripetal force (NET FORCE) and normal force are upward (Positive). Do another summation of forces:
[tex]\Sigma F = F_N - F_g\\\\\\frac{mv^2}{r} + F_g = F_N \\\\F_N = \frac{(73.367)(225^2)}{3110} + 719 = \boxed{1913.278 N}[/tex]

For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as

F=1711 N

dF= 135 degrees

Generally, the equation for the components of F1   is mathematically given as

For The x axis

1210 - F2x = 0

F2x = 1210

For the y axis

F2y = R

F2y = 1210

In conclusion

F = sqrt(2)*1210

F=1711 N

Fopt the direction of F2

dF= 90 + 45

dF= 135 degrees

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Answer:

0.73kg

Explanation:

Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.

Substitute:

[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]

Answer:

when it has a fewer amount of electrons than protons

Hi there!

Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]

Begin by taking the derivative of the electric potential function using basic power and constant rules.

Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]

[tex]\frac{dy}{dx}(C) = 0[/tex]

Differentiate the function, and take its negative.

[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]

The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]

Answer:

After 1 decay it has .9375 of its value left  

.9375^n = 1/2

What is the value of n (number of decays)

n log .9375 = -.693

n =.693 / .0645 = 10.7

After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left

1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min

average velocity= tot displacement/total time

avg v = 20/(20+60+5+10+5)=20/100=0.2 m/s

The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.

The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.

emf = N(dФ/dt)

where;

Ф = BA

where;

emf = NBA/t

A = πr²

A = π x (0.13)²

A = 0.053 m²

emf = NBA/t

emf = (1 x 3.746 x 0.053)/(1.16)

emf = 0.171 V

Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.

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Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

Answer:

speed of the friend that is 8m from the center:

0.8π m/s

the distance she will travel in one rotation is:

10

Her speed compared to you is faster because, she is farther away from the axis compared to you.

Explanation:

for the speed, it says the farther you are from the axis the greater your speed is, and for the person who was 4m from the axis of rotation their speed was 0.4 because they are closer to the axis so therefore their speed is slower. so for the friend that is 8m from the axis of rotation its most likely their speed would be 0.8 m/s.

in one revolution you travel 8m your original distance from the axis was 4m so, 8-4 = 4, which means one revolution is plus 4 to your original distance. since the question is asking for rotation and not revolution you can do 4 ÷ 2 which is 2, so for rotation you need to add 2 to your original distance, so 8 + 2 = 10

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

[tex]E_{1}=\frac{kQ_{1}}{R_{1}^{2}}[/tex]

[tex]E_{2}=\frac{kQ_{2}}{R_{2}^{2}}[/tex]

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = [tex]k=9\times 10^{9}[/tex] in [tex]Nm^{2}/C^{2}[/tex], we can obtain:

[tex]E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}[/tex] N/C (+)

[tex]E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}[/tex] N/C (-)

So: the Electric Field at P : [tex]E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}[/tex] N/C in magnitude

The kinetic energy of the charged particle is equal to the work done to bring it from the distance of 1 m. Hence, the total electric force here is 0.025 N. Therefore, the charge on the fixed particle is  approximately + 6.7 µC.

According Coulomb's law the electrostatic force between two charges is given by ,

F =  k q1 q2 /r²

Where q1 and q2 be the charges and r be the distance between them, k be the constant equal to 8 × 10⁹ N m²/C².

Given q1 = + 5  µC

r = 1 m.

the kinetic energy in bringing the charge of  5 µC from 2 m is given 50 mJ.

then F = 0.05 J/2 m = 0.025 N

Then q2 = F r²/ (q1 K)

q2  = 0.025 N / ( + 5  µC × 8 × 10⁹ N m²/C²)

      =  6 µC.

Therefore, option b is the approximate charge of the fixed particle.

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We can confirm that the clothes are sticking together due to static forces created by the heat and friction of the dryer.

The clothes are stuck together due to static forces that arise when these materials are heated and the friction from the dryer cycle. Adding a light spray of water can help with this situation given that water is a strong conductor of electricity, which will help to dispel the charges that hold the clothes together.

Therefore, we can confirm that clothes are sticking together due to static forces created by the heat and friction of the dryer, which a light spray of water can help to dispel and separate the clothes.

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According to a periodic table, Krypton was created during the fission of Uranium.

Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. [tex]\blacksquare[/tex]

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Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics.

Answer:

When a body is immersed fully or partially in a fluid, it experience is an upward force that is equal to the weight of the fluid displaced by it.

Answer:

Forces

Explanation:

1) A Force

2) Balanced

3) Unbalanced

4) Any object moving at a constant speed, Any object in 0 motion, A balanced see-saw (no net torque/forces)

5) Any object accelerating, Someone pushing a box

Answer:

the answer is B I hope it helps out

Hi there!

We can use Ampère's Law:

[tex]\oint B \cdot dl = \mu_0 i_{encl}[/tex]

B = Magnetic field strength (B)
dl = differential length element (m)
μ₀ = Permeability of free space (T/Am)

Since this is a closed-loop integral, we must integrate over a closed loop. We can integrate over a rectangular-enclosed area of the rim of the solenoid - ABCD - where AD and BC are perpendicular to the solenoid.

Thus, the magnetic field is equivalent to:
[tex]\oint B \cdot dl = \int\limits^A_B {B} \, dl + \int\limits^B_C {B} \, dl + \int\limits^C_D {B} \, dl + \int\limits^D_A {B} \, dl[/tex]

Since AD and BC are perpendicular, and since:
[tex]\oint B \cdot dl = B \cdot L = BLcos\phi[/tex]

[tex]BLcos(90) = 0[/tex]

If perpendicular to the field, the equation equals 0.

Additionally, since AB is outside of the solenoid, there is no magnetic field present, so B = 0. The only integral we integrate now is:
[tex]\oint B \cdot dl = \int\limits^C_D {B} \, dl[/tex]

Which is horizontal and inside the solenoid. Let the distance between C and D be 'L', and the enclosed current is equivalent to the number of loops multiplied by the current:

[tex]B L = \mu_0 Ni[/tex]

N = # of loops per length multiplied by the length, so:
[tex]BL = \mu_0 nL i \\\\B = \mu_0ni[/tex]

Plug in the given values and solve. Remember to convert # of loops to # of loops per unit length.

[tex]B = \mu_0 (100/0.1)(2) = (4\pi *10^{-7})(1000)(2) = \boxed{0.00251 T}[/tex]

Answer:

the answer to this question is option c

there process which eventually takes place is called refraction

Explanation:

please do consider as brainlest if useful

Answer:

Explanation:

The velocity of sound from the plucked string in the tennis racquet is:

[tex]v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}[/tex]

Then the frequency will be:

[tex]f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz[/tex]

Explanation:

Curd is made from milk . ( True )

Curd is made by bacterial fermentation of milk.

Answer:

very true

curd is made from warm milk and a bacterial youghurt starter and it aslo has been used for many years

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