The correct answer is b) m gt. When a stone of different mass Is dropped, it falls freely due to gravity.
Describe mass in mathematics with an example.
The amount of material that make up every object or body is the greatest way to understand mass. Everything that we can see has mass. Examples of objects with mass include a table, any chair, your bedroom, a football, weight glass, and even air.
As we know:
v = u + at
=> v = 0 + gt = gt
Hence change in momentum = ∆mv
=> ∆P = m∆v
=> ∆P = m (v-u)
=> ∆P = m gt
How does physics quantify mass?
The unit of measurement for mass, or mass in kilograms, is matter. A bird's bulk remains constant. No matter where you weigh something—on Heaven, the Moon, or Mars—it always weighs 15 grams.
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Complete question
A stone of mass m is dropped and falls freely under the influence of gravity. Ignoring air resistance, which of the following expressions given the momentum of the stone as function of time t? (Pleas show all work)
a) (1/2) mgt²
b) m gt
c) (1/2) gt²
d) gt
In 2017, NASA announced that _______ is the most likely place in our solar system to find extraterrestrial life, due to its abundant water and geothermal activity.
Hegskdvs a CB sksbslsvskssvsi
The correct examples of cause-and-effect relationship are both the systems speed up for the duration of the force exerted on them. Both systems stop moving for the duration of the force exerted on them. Thus, the correct options are C, D, E, and G.
What is Cause and effect relationship?Cause-and-effect relationship describes a relationship which is present between actions or events in which at least one of the action or event is a direct result of the other action or events.
The correct examples of cause-and-effect relationship are both the systems speed up for the duration of the force exerted on them. Both systems stop moving for the duration of the force exerted on them. A spring can exert a force on the dynamic cart. The force of the spring continues to act upon the cart until it stops moving.
Therefore, the correct options are C, D, E, and G.
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When the ball is halfway to the ground (at 1/2 h), is its kinetic energy more than, less than, or exactly equal to half of its maximum kinetic energy? Explain
It is common knowledge that half of the ball's potential energy is converted to kinetic energy because it fell halfway through.
Let's take an example to understand the concept clearly.
Suppose a 16 kg ball is dropped from 10 m. We need to determine the kinetic energy when the ball reaches half the ground.
Note: At height of 10 cm the ball has a certain potential energy.
As GPE = m.g.h
Similarly, so is the potential energy of the sphere
GPE = 16 . 9.81. 10
GPE = 1569.6 J
On the way, the potential energy of the sphere when the altitude changes
GPE = 16 . 9.81. 5
GPE = 784.8 J
By the law of conservation of energy, the energy is It will not destroy or disappear. This converts the ball's lost potential energy into another form of energy. Here the lost potential energy of the sphere is converted into kinetic energy of the sphere.
Therefore the kinetic energy of the ball is equal to the potential energy of the ball at minus the potential energy of the ball at his.
i.e. 1569.6 - 784.8 = 784.8
It is common knowledge that half of the ball's potential energy is converted to kinetic energy because it fell halfway. When the ball hits the ground, i.e., at h = 0m all of the ball's potential energy is converted to kinetic energy and finally to another form of energy.
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Assume |g| = 10 m/s^2
A free-body diagram of the block on the frictional part of the surface would show the force of friction acting in the opposite direction to the velocity of the block, and the force of gravity acting downward.
Using conservation of energy, the speed of the block at the base of the ramp can be found by setting the initial kinetic energy of the block (1/245^2) equal to the final kinetic energy of the block (1/2mv^2) and solving for v. v = sqrt((1/245^2)/(1/2*m)) where m is the mass of the block.
Using conservation of energy, the maximum vertical height H of the block on the ramp can be found by setting the initial potential energy of the block (mgH) equal to the final kinetic energy of the block (1/2mv^2) and solving for H. H = (1/2mv^2)/(m*g)
a) The total impulse given to the mass on the spring (mass A) during the brief collision is the product of the force exerted on the mass by the block and the time duration of the collision.
b) The speed of the mass on the spring (mass A) immediately after the collision can be determined using the conservation of momentum.
c) The velocity of the block immediately after the collision can also be determined using the conservation of momentum.
d) The spring constant can be determined by using the equation k = (2*F)/x, where F is the force exerted on the spring and x is the compression of the spring.
To find the horizontal range of the block from the end of the ramp, we can use the equations for horizontal and vertical motion of a projectile, with the angle of launch being 30 degrees, the initial speed being 6 m/s, and the final vertical position being 1m above the end of the ramp.
What is a satellite.
Answer:
According to NASA, a satellite is as follows:
A moon, planet, or object that revolves around a planet or star is called a satellite (Mae, 2015). For instance, the fact that Earth orbits the sun makes it a satellite. The moon is a satellite as well because it revolves around Earth. The term "satellite" typically refers to a device that is launched into space and orbits the Earth or another celestial body.
Explanation:
Answer:
Satellite is any heavenly body or space object that move around a planet.
Explanation:
There are two types of satellite
namely: Natural satellite and artificial satellite.
National satellite consists of the moon.
Artificial satellite consists of communication satellite, scientific satellite, weather satellite, Navigation satellite and Military satellite.
Here are a couple questions about vectors
The x and y component of the vector A are 37.4 m and 34.2 m respectively.
What is the x component of the vector A?
The x component of the vector A is calculated by applying the following formula.
Ax = A cosθ
where;
A is the magnitude of the vectorθ is the angle of the vectorAx = 52 m x cos ( 44 )
Ax = 37.4 m
The y component of the vector A is calculated as follows;
Ay = A x sinθ
Ay = 84 m x sin ( 24 )
Ay = 34.2 m
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A baby crawls towards a toy. Its motion is shown on the following graph of horizontal position x vs time t
The horizontal speed of the baby is 0.25 m/s.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Initial position of the baby ( at t=0 s) is = 1 meter.
Final position of the bay ( at t = 8s) is = 3 meter.
Hence, speed of the baby is = change in position/time interval
= (3 meter - 1 meter)/(8 s - 0s)
= (2 ÷ 8) m/s
= 0.25 m/s
Therefore, the horizontal speed of the baby is 0.25 m/s.
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Your question is incomplete, but most probably the question was:
A baby crawls towards a toy. Its motion is shown on the following graph of horizontal position x vs time t. Find horizontal speed of the baby?
earth and space chapter 19 section 1 review answer key why is atmosphiric pressure generally lower beneath a mass of warm
Atmospheric pressure is generally lower under a warm air mass than under a cold air mass because molecules move apart when heated. Fewer particles apply pressure to specific areas.
Atmospheric Pressure:
Atmospheric pressure, also called atmospheric pressure (after barometer), is the pressure in the Earth's atmosphere. Standard atmosphere (symbol: atm) is a unit of pressure defined as 101,325 Pa (1,013.25 hPa) equal to 1013.25 millibar 760 mm Hg, 29.9212 inches Hg, or 14.696 psi. The atm unit roughly corresponds to the Earth's mean atmospheric pressure at sea level. So the atmospheric pressure on Earth at sea level is about 1 atmosphere.
In most cases atmospheric pressure is approximated by the hydrostatic pressure caused by the weight of the air above the point of measurement. Air pressure decreases with altitude because the air mass above is less as altitude increases. Since the atmosphere is thin relative to the Earth's radius (especially the dense atmospheric layers at low altitudes), the Earth's gravitational acceleration as a function of altitude can be approximated as constant and contributes little to this decline. Pressure is measured as force per unit area in SI units Pascal (1 Pascal = 1 Newton per square meter, 1 N/m2). A column of air with a cross-sectional area of 1 square centimeter (cm2) measured from the mean (mean) sea level to the top of the Earth's atmosphere has an average mass of about 1.03 kilograms and exerts a force. Or a "weight" of about 10.1 Newtons, a pressure of 10.1 N/cm2 or 101 kN/m2 (101 kilopascals, kPa).
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which of the following evaluation tools for documenting direct observations is the least subjective?
Least subjective evaluation tool for documenting direct observation is anecdotal record.
What do you mean by evaluation tool?There are several evaluation tools that can be used to assess the quality and effectiveness of documentation in physics. Some examples include:
Peer review: This involves having other experts in the field review the documentation and provide feedback on its accuracy, clarity, and completeness.
User testing: This involves having users test the documentation and provide feedback on its usability and effectiveness in helping them understand and use the information.
Metrics: This involves measuring various aspects of the documentation, such as readability, accuracy, and completeness, and using these metrics to evaluate its quality.
Surveys: Surveys can be used to gather feedback from users on the documentation, including their satisfaction with the information provided and how well it met their needs.
Heuristic evaluation: This is an evaluation method which uses a set of predetermined heuristics or guidelines to evaluate the usability and user experience of a product or service.
Cognitive walkthrough: This is an evaluation method in which a user is observed as they use the documentation, and the evaluator looks for any issues that might make it difficult for them to understand and use the information.
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einstein contradicted classical galilean relativity when he proposed that the speed of light in a vacuum.
a. true
b. false
A) True. Einstein contradicted classical Galilean relativity by proposing Theory of Special Relativity.
Einstein contradicted classical Galilean relativity when he proposed that the speed of light in a vacuum is constant and independent of the motion of the observer. This idea, known as the theory of special relativity, was first published by Einstein in 1905 and fundamentally changed our understanding of space and time. According to classical Galilean relativity, the laws of physics should be the same for all observers moving at a constant velocity relative to one another. However, Einstein's theory of special relativity showed that this is not the case when it comes to the speed of light.
In special relativity, the laws of physics are the same for all observers in uniform motion relative to one another, but the speed of light is always the same for all observers. This means that the speed of light is not affected by the motion of the source or the observer, and is the same for all observers in any inertial frame of reference. This contradicts the classical Galilean relativity, where the speed of light was considered to be relative to the observer, and it was thought that the laws of physics should be the same for all observers in uniform motion relative to one another.
In summary, Einstein's theory of special relativity proposed that the speed of light in a vacuum is constant and independent of the motion of the observer, which contradicts classical Galilean relativity and fundamentally changed our understanding of space and time.
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PLEASE HELP ASAP! 100 PTS! 5 QUESTIONS - Pls Show Your Work!!!!
1. Two carts are pushed apart with a spring attached to one of the carts. The carts have masses of 1.2 kg and 2.5 kg. The 2.5 kg cart (Cart B) has a velocity of 1.5 m/s after they spring apart. Find the velocity of the 1.2 kg. cart.
2. An 6,000 kg train car moves at 20.0 m/s until it bumps into a stationary 6,000 kg car and latches onto it. What is the speed of the two cars linked together?
3. A single 1,000 kg train car moving at 5.0 m/s collides with the back of two 1,000 kg train cars linked together. It latches onto the car it strikes as the two parts of the coupled cars exert forces on each other. What is the speed of the cars immediately afterward?
4. A 15.0 kg cart and a 20 kg cart are locked together with a compressed spring between them. They are then released so that the spring pushes the two carts apart. The 20 kg cart is moving at 5.0 m/s afterward. How fast is the 15.0 kg cart moving?
5. A firecracker stuck into a 150 g apple explodes and sends five apple fragments in different directions. The vector sum of momenta 1, 2, 3, and 4 is found from a video of the event to have components px = 1.20 kg m/s, py = 0.80 kg m/s (with no other component). The mass of the fifth fragment is 0.050 kg. What is its velocity right after the explosion?
The final velocity of the 1.2 Kg cart is 3.1 m/s. The final velocity of the coupled mass of cars can be determined using the conservation of momentum. The final velocity is 10 m/s.
What is momentum ?Momentum of an object is the product of mass and velocity of the object. In a collision, the total momentum is conserved.
Here, initially the carts were rest. Hence, their initial momentum is zero.
then (1.2 kg × v) + (2.5 kg × 1.5 m/s) = 0
then , velocity of 1.2 kg = (2.5 × 1.5)/1.2 = 3.1 m/s.
Similarly the total initial momentum of the two car of mass 6000 kg is equal to the their final momentum.
The initial momentum of the stationary car is zero.
then (6000 kg × 20 m/s) + 0 = (6000 + 6000 kg)v.
The final velocity of the coupled mass v is then calculated as:
v = (6000 kg × 20 m/s)/12000 kg = 10 m/s.
Therefore, the final velocity of the coupled mass will be 10 m/s.
Using conservation of momentum concept all others can be found.
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Four point charges, (Q = +7.1 μC and q = +1.4 μC), are arranged such that each is at a corner of a square. The sides of the square are x = 0.19 m. What is the magnitude of the net force (in newtons) on the sphere of charge q?
(round to nearest hundredth)
The net magnitude of electric force on the sphere of charge q is 4.74 Newton.
What is electric force?Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.
Q = +7.1 μC = 7.1 × 10⁻⁶ C
q = +1.4 μC = 1.4 × 10⁻⁶ C
The net magnitude of electric force on the sphere of charge q is
= 9 × 10⁹ × 7.1 × 10⁻⁶ × 1.4 × 10⁻⁶ { √2/(0.19)² + 1/(0.19 × √2)² Newton
= 4.74 Newton.
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A particle of charge +q is released from rest at position B, which is a distance 2d from the center of a fixed nonconducting sphere that has a charge of -Q distributed uniformly throughout its volume, as shown in the figure above. When the particle reaches position A, which is a distance d from the center of the charged sphere, its kinetic energy is K0 . The same particle is now released from rest at position C, which is a distance 4d from the center of the nonconducting sphere. The kinetic energy of the particle when it again reaches position A is
The kinetic energy of the particle when it reaches position A will be K0 * (2d/4d)^2 = K0/4 , when the particle is released at position C.
What is the the kinetic energy of the particle when it reaches position A?The particle at position B is attracted to the negatively charged sphere, and as it gets closer to the sphere (as it moves towards position A), it gains kinetic energy.The same particle, released at position C, is initially farther away from the negatively charged sphere, so it has less potential energy to begin with.As the particle moves towards position A, it loses kinetic energy due to the force of attraction to the negatively charged sphere.So the kinetic energy of the particle when it reaches position A will be less when it is released from position C compared to when it is released from position B.The kinetic energy at position A is inversely proportional to the square of the distance between the point of release and position A .So the kinetic energy of the particle when it reaches position A will be K0 * (2d/4d)^2 = K0/4 , when the particle is released at position C.To learn more about particles refer:
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Philosophy 203 how much importance do you think duty ought to have in relation to morality
By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.
What is Mortality?The first involves a salesman who, even though he is aware of the customer's inexperience, does not overcharge them because he does not want to risk damaging his reputation by being found out.
Because the salesman was not driven by a sense of obligation to treat the consumer fairly, Kant claims that this is not a moral issue.
The second claim is that "an action performed out of obligation has its moral significance not in the goal that it is intended to achieve.
Therefore, By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.
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using the data presented in the accompanying pressure-versus-volume graph, estimate the magnitude of the work done when the system changes from a to b to c along the path shown. (b) determine whether the work is done by the system or on the system and, hence, whether the work is positive or negative.
The work done by the system along the path from a to b to c is zero and it's not positive or negative.
What is the work done by system ?The work done by a system can be determined by the area enclosed by the system's pressure-volume graph.The area enclosed by the path from a to b to c represents the work done by the system.In this case, the path from a to b to c is a closed loop, so the work done by the system is zero.It's necessary to determine whether the work is done by the system or on the system.Since the path is a closed loop, the work done by the system is equal in magnitude but opposite in direction to the work done on the system.The work is done by the system is zero. So, it's neither positive nor negative.In summary, the work done by the system along the path from a to b to c is zero and it's not positive or negative.To learn more about work done refer:
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a 80.9-kg boy and a 65.7-kg girl, both wearing skates face each other at rest on a skating rink. the boy pushes the girl, sending her to the left with a velocity of -2.65 m/s. neglecting friction, determine the subsequent velocity of the boy to the right.
The boy will move to the right with a velocity of -2.16 m/s after pushing the girl to the left with a velocity of -2.65 m/s.
How to calculate the subsequent velocity ?Newton's Third Law of Motion
Using the conservation of momentum, the velocity of the boy to the right is calculated as follows:
Boy's initial momentum = 0
Girl's initial momentum = (65.7 kg)(-2.65 m/s) = -174.34 kgm/s
Total initial momentum = -174.34 kgm/s
Boy's final momentum = (80.9 kg)(V)
V = (174.34 kgm/s) / (80.9 kg)
V = 2.16 m/s (to the right)
This is due to Newton's Third Law of Motion, which states that for every action there is an equal and opposite reaction.
The girl has a mass of 65.7 kg and a velocity of -2.65 m/s. Using the equation for momentum, the momentum of the girl can be calculated as follows:
Momentum = Mass x Velocity
Momentum of girl = 65.7 kg x -2.65 m/s = -174.25 kg m/s
As the momentum of the girl and the boy must be equal and opposite, the momentum of the boy can be calculated as:
Momentum of boy = -174.25 kg m/s
Using the same equation for momentum, the velocity of the boy can be calculated as follows:
Velocity of boy = Momentum/Mass
Velocity of boy = -174.25 kg m/s/80.9 kg
Velocity of boy = -2.16 m/s
Therefore, the boy will move to the right with a velocity of -2.16 m/s after pushing the girl to the left with a velocity of -2.65 m/s.
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d) How could you leave an electroscope charged after all other objects had been taken away?
An electroscope can be recharged by bringing a charged object near it without touching it.
What are some common methods for charging an electroscope?There are several common methods for charging an electroscope, including: rubbing the electroscope with a cloth, using a static generator, or bringing the electroscope into contact with a charged object. Rubbing the electroscope with a cloth, such as silk or fur, is a simple method that transfers electrons from the cloth to the electroscope. Using a static generator, such as a Van de Graaff generator, can create a large charge on the electroscope. Bringing the electroscope into contact with a charged object, such as a charged rod or balloon, can also transfer charge to the electroscope. Additionally, some electroscopes are designed to be charged by simply turning a knob or flipping a switch.
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which of the following free-body diagrams could be used to analyze the forces exerted on the moon when it is at the position indicated in the figure? responses
The choice with the gravity arrow pointing to the right, option F, is the correct diagram.
how does the moon go around a planet?A moon experiences the gravitational pull of a planet. The near side of the moon suffers a stronger pull than the far side, causing it to be drawn into a somewhat stretched form. Because of the moon's analogous differential attraction to the Earth, we have tides in the oceans.The gravitational force of the Moon and Earth caused this particular case of tidal locking (called synchronous rotation).One orbit of the Sun by the Earth takes 365 1/4 days, or one year. As the Earth rotates around the Sun, so does the Moon. The Moon spends 27 1/2 days in orbit.The complete question is A moon orbits a planet in a nearly circular orbit of radius R, as shown in the figure.
Which of the following free-body diagrams could be used to analyze the forces exerted on the moon when it is at the position indicated in the figure?
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1. the time response of the coil current after the switch s is closed, as a function of the precharge voltage vx. (some types of stimulation require a field with a fast rise time and a slow fall time.)
Pre-charge circuits typically shut off pre-charge mode when the circuit voltage reaches 90% or 95% of the operating voltage. When pre-charging is finished, the pre-charge resistance is disconnected from the power supply circuit and switched back to a low-impedance power source for normal mode.
A current-limiting circuit known as pre-charge reduces the charging rate of the bus capacitors during power-up in a pulse width modulated (or PWM) VFD. (For more information on bus capacitors, go HERE) The input power devices would be harmed otherwise by the early inrush. To control this inrush current and gradually charge the downstream capacitance, a precharge circuit is employed. For components to function properly and be protected in high-voltage applications, it is essential.
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a particle of mass m rests on a rough inclined plane that makes an angle with the horizontal if the coefficient of static friction find the least horizontal force acting transcerse to the slope of the plane that will cause the particle to move
So the least horizontal force that is required to cause the particle to move is:
F = μs * N = μs * mg * cos(θ)
Give explanation to support your answer.The coefficient of static friction, s, multiplied by the normal force, N, exerted on the particle results in the minimum horizontal force, F, needed to move it.
The weight of the particle, mg, multiplied by the cosine of the angle of inclination,, results in the normal force, N:
N= mg*cos()
Therefore, the smallest horizontal force needed to move the particle is:
F = sin(s*N) = sin(s*mg*cos(s))
It is significant to remember that the substance of the particle as well as the plane affects the coefficient of static friction, which is a dimensionless number with a value between 0 and 1.
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which of the following sources of energy transforms kinetic energy to electricity without using heat energy?
Sources include renewable energy sources such as the sun, wind, water, and geothermal heat.
In which energy sources kinetic energy is converted into electrical energy?A sequence of blades installed on a rotor shaft in a turbine generator are pushed by a flowing fluid, such as air, water, steam, combustion gases, or water. A generator's rotor shaft revolves or spins due to the fluid's force on the blades.
In turn, the generator transforms the rotor's mechanical (kinetic) energy into electrical energy.A machine that transforms a form of energy into electricity is called an electric generator.
Electricity generators come in a variety of designs. According to Michael Faraday's 1831 discovery that rotating a magnet inside a coil of wire causes (induces) an electric current to flow in the wire, the majority of the world's power is produced by generators. On the basis of this relationship, he created the first electrical generator known as a Faraday disc.
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Two identical conducting sphere, fixed in place, attract each other with an electrostatic force of 0.108 N when their center-to-center separation is 50.0 cm. The sphere are then connected by a thin conducing wire. When the wire is removed, the sphere repel each other with an electrostatic force of 0.0360 N. Of the initial charges on the sphere, with a positive net charge, what was the negative charge on one of them?
The negative charge on one of the identical spheres in a pair of conducting, fixed, and attracted to each other by an electrostatic force spheres is -1.00*10^-6 C. We can calculate this using Coulomb's law.
We can begin by using Coulomb's law, which states that the electrostatic force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Coulomb's law can be mathematically written as:
F = k * (q1 * q2) / r^2
where F is the force, k is the Coulomb constant, q1 and q2 are the charges on the two spheres, and r is the distance between their centers.
Given that the force of attraction is 0.108 N when the spheres are 50.0 cm apart, we can use the Coulomb's law to find the product of the charges on the spheres.
0.108 N = (9 * 10^9 N*m^2/C^2) * (q1 * q2) / (0.50 m)^2
The product of the charges on the two spheres is q1q2 = (0.108 N * (0.50 m)^2) / (9 * 10^9 Nm^2/C^2) = 1.2 * 10^-7 C^2
We can use this value to find the charges on the spheres when they are connected by a thin conducting wire and repelling each other with an electrostatic force of 0.0360 N.
0.0360 N = (9 * 10^9 N*m^2/C^2) * (q1 * q2) / (0.50 m)^2
q1q2 = (0.0360 N * (0.50 m)^2) / (9 * 10^9 Nm^2/C^2) = 4.0 * 10^-8 C^2
Since the product of the charges q1*q2 is now smaller, we can assume that one of the charges (let's say q1) is now smaller and the other charge (q2) is now bigger, hence have opposite charges.
We can use the formula q1q2 = 1.210^-7 C^2 / 4.0*10^-8 C^2 = 3q1q2
q2 = 3q1 and q1q2 = 4*10^-8 C^2
Substituting, we get q1 = (410^-8 C^2) / 3q1 = 1.3310^-8 C
The negative charge on one of the sphere is 1.33*10^-8 C
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When we say object is in equilibrium condition?
An object is said to be in equilibrium condition when the net force acting on it is zero, meaning that the sum of all forces acting on the object is equal to zero. This means that the object is either at rest or moving with a constant velocity, and there is no acceleration. In other words, an object in equilibrium is not changing its speed or direction of motion. Additionally, an object in equilibrium is also not rotating, meaning the net torque acting on it is also zero.
It's important to note that an object can be in equilibrium even if it is in motion. The key is that the net force on the object is zero.
A 0.060 kg tennis ball, moving with a speed of 5.50 m/s, has a head-on collision with a 0.090 kg ball initially moving in the same direction at a speed of 3.00 m/s. Assuming a perfectly elastic collision, determine the speed and direction of each ball after the collision.
The speed and direction of each ball after the collision is :
a) Speed of the first ball after the collision = 2.5 m/s same initial direction
b) Speed of the second ball after the collision = 5.0 m/s same initial direction
A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
Let us consider the initial direction of velocity of the first ball as the right side which we will take to be positive.
The second ball is moving in the same direction as that of the first ball therefore it's velocity is also directed to the right.
Mass of the first ball = [tex]M_{1}[/tex] = 0.06 kg
Mass of the second ball = [tex]M_{2}[/tex] = 0.09 kg
Initial velocity of the first ball = [tex]V_{1}[/tex] = 5.5 m/s
Initial velocity of the second ball =[tex]V_{2}[/tex] = 3 m/s
Velocity of the first ball after the collision = [tex]V_{3}[/tex]
Velocity of the second ball after the collision = [tex]V_{4}[/tex]
The collision is elastic.
Coefficient of restitution = e = 1
e = [tex]\frac{V_{4} - V_{3}}{V_{1} - V_{2}}[/tex]
1 =[tex]\frac{V_{4} - V_{3}}{5.5 - 3}[/tex]
2.5 =[tex]V_{4} - V_{3}[/tex]
[tex]V_{4} = V_{3} + 2.5[/tex]
By conservation of linear momentum,
[tex]m_{1}V_{1} + m_{2}V_{2} = m_{1}V_{3} + m_{2}V_{4}[/tex]
(0.06)(5.5) + (0.09)(3) = [tex](0.06)V_{3} + (0.09)(V_{3} + 2.5)[/tex]
0.33 + 0.27 = [tex]0.06V_{3} + 0.09V_{3}[/tex] + 0.225
[tex]0.15V_{3}[/tex] = 0.375
V3 = 2.5 m/s
[tex]V_{4} = V_{3} +[/tex] 2.5
[tex]V_{4} =[/tex] 2.5 + 2.5
[tex]V_{4} =[/tex] 5.0 m/s
The velocities of the both the balls after the collision are positive therefore the direction of the balls are moving after the collision is the same as the initial direction of motion.
a) Speed of the first ball after the collision = 2.5 m/s same initial direction
b) Speed of the second ball after the collision = 5.0 m/s same initial direction
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Summarise Specific Heat Capacity in 10 sentences
FILL IN THE BLANK a mass is undergoing simple harmonic motion. when its displacement is 0, it is at its equilibrium position. at that moment, its speed is _________ and its acceleration is _________ .
A mass is undergoing simple harmonic motion. when its displacement is 0, it is at its equilibrium position. at that moment, its speed is maximum and its acceleration is 0 .
The rule of conservation of energy can be used to calculate the mass's speed in simple harmonic motion. In actuality, the kinetic energy and elastic potential energy make up the entire mechanical energy of the mass-spring system:
[tex]E=K+U=\frac{1}{2}mv^{2} +\frac{1}{2}kv^{2}[/tex]
where
The mass is m.
The speed is v.
The spring constant is k.
The displacement is x.
As we can see, the term representing the kinetic energy is at its highest when the displacement is zero (x=0), and consequently, v (the speed) is at its maximum as well.
Hook's law states that the acceleration of a mass in simple harmonic motion is inversely proportional to the restoring force exerted on the mass.
[tex]a\:\alpha\: F=-kx[/tex]
where
The spring constant is k.
The displacement is x.
the net when x = 0, F = 0,
hence there is no net force on the mass. As a result, this also implies that the mass's acceleration is zero: a = 0.
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Assuming that the initial pressure of X(2)(the 2 is at the bottom) was 0.10 bar, calculate the value of K for the decomposition.
The forward reaction and the reverse reaction have the same pace when a reaction is at equilibrium.
What is a short review of equilibrium and Kc?At equilibrium, the forward and backward reactions continue to take place while the concentrations of the reaction's constituents remain constant.For a reaction taking place at a specific temperature, the ratio of concentrations at equilibrium is defined by equilibrium constants. To denote equilibrium constants, we typically use the symbols KK or c K c K, start subscript, start text, c, end text, and end subscript. The subscript c in the symbol c K c K, start subscript, start text, c, end text, and end subscript denotes that all concentrations are stated in terms of molar concentration, or mol solute L of solution L of solution mol solute start.Divided by, start text, L, space, o, f, space, s, o, l, u, t, I o, n, end text, end fraction. start fraction, start text, m, o, l, space, s, o, l, u, t, e.To Learn more About equilibrium refer to:
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puck with initial velocity Vo slides up and down a long; frictionless inclined plane, as seen below: Which of the following is true regarding the motion of the puck? It has a smaller acceleration while moving up the plane and a greater acceleration when moving down the plane It has a constant acceleration while moving up the plane and smaller acceleration when moving down the plane_ It moves with constant velocity both up and down the plane It has the same acceleration as it moves up and down the plane It has continually varying acceleration as it moves up and down the plane:
It will accelerate continuously. The acceleration put on by gravity will be that. Thus, correct option is: It has the same acceleration as it moves up and down the plane.
What is gravity?The force that pulls items toward the centre of a planetary or other body is known as gravity. The gravitational pull maintains each of the planet in orbit about the sun. The degree to which a coordinate in space-time is invisibly bent determines the intensity of the gravitational "field" at any given place in space or time. Massive items tumble down these bends in the direction of one another. The stronger the attraction between items, the more matter there is, and the closer together things are. And unlike electricity and magnetism, which may either repel or attract, gravity always draws objects together.
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The complete question is as follows:
the drawing at the right represents a toy airplane moving in a horizontal circle at constant speed, i.e., it is moving with uniform circular motion. the airplane is suspended from a string that sweeps out a cone as the plane flies around. a system moving in this fashion is called a conical pendulum. in this lab newton's laws will be applied to the conical pendulum to determine the theoretical speed of the pig compared to the measured speed. then determine the tension in the support string.
A conical pendulum is a ball twirled on a string that makes an angle with the vertical. Only the horizontal component of the tension contributes to the centripetal force keeping the ball in a circle. Forces in the vertical direction are balanced.
What is meant by Force?
The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.The net force acting on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original formulation. This law suggests that an object's acceleration is directly proportional to the net force acting on it, is in the direction of the net force, and is inversely proportional to the mass of the object if the object's mass is constant.To learn more about Force refer to
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As the two atoms get attracted more to one another due to them having a higher attractive force so they will have an attractive force. they will eventually reach a point where they will have a higher repulsive force and repulse one another so they change into a repulsive force. True or False
Two atoms get attracted more to one another due to them having a higher attractive force so they will have an attractive force.Atom will eventually reach a point where they will have a higher repulsive force and repulse one another so they change into a repulsive force.Yes it is true .
Covalent bonding occurs when each atom shares its electrons to form a chemical bond, which results in a force of attraction or repulsion. Two nonmetal atoms are shown to form a covalent bond. When electrons are shared between two atoms or an ion, covalent bonds are created. The molecular bond is another name for the covalent bonds that are created. Covalent bonding is the force of attraction or repulsion between two atoms when they share a pair of electrons.When they are bound together and when they are separated, the majority of the atoms have lower potential energy. Consider two isolated hydrogen atoms that are sufficiently distanced from one another to avoid any contact between them. Potential energy is equal to zero at this point.
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