A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an amplitude of 0.143 mm and a frequency of 76.9 Hz and is traveling in the negative direction of an x axis. If the wave equation is of the form y(x,t) = ym sin(kx + ωt), what are (a) ym, (b) k, and (c) ω, and (d) the correct choice of sign in front of ω?

Answer:

Probably 4

Explanation:

Answer: 0.09 J

Explanation: K = 200 N/m , 1/2 X 200 N/m X (0.03 M)^2 = 0.09 J

Answer:

D

Explanation:

The student has enough information to make the determination

Measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision the student has enough information to make the determination. Thus, option D is correct.

A student drops an object from rest above a force plate that records information about the force exerted on the object as a function of time during the time interval in which the object is in contact with the force plate.

Momentum has the measure of motion of the object. Momentum is given by the product of mass and the velocity of the object. The law of conservation of momentum states that the momentum before the collision is equal to the momentum after the collision. It also states that the total momentum of a system or a body remains constant.

Therefore, Measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision the student has enough information to make the determination. Thus, option D is correct.

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Answer:

1.70108e-13 , this is the answer hope it helps

Answer:

the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Explanation:

Given;

initial velocity of the airplane. u = 34.5 m/s

distance traveled by the airplane, s = 46,100 m

final velocity of the airplane, v = 40.7 m/s

The acceleration of the airplane is calculated from the following kinematic equation;

v² = u² + 2as

[tex]2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2[/tex]

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Answer:

[tex]1200\ \text{N}[/tex]

Explanation:

F = Force on the skier = 60 N

[tex]\mu[/tex] = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

[tex]F=\mu w[/tex]

[tex]\Rightarrow w=\dfrac{F}{\mu}[/tex]

[tex]\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}[/tex]

[tex]\Rightarrow w=1200\ \text{N}[/tex]

Weight of the skier on which the force is being applied is [tex]1200\ \text{N}[/tex] .

Answer:

F = 5702.56 N

Explanation:

Given that,

Mass of a small car, m = 800 kg

Initial speed of the car, u = 27.8 m/s

Final speed, v = 0

Time, t = 3.9 s

We need to find the force did it take for the car to stop.

The force acting on an object is given by :

[tex]F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{800\times (0-27.8)}{3.9}\\\\F=-5702.56\ N[/tex]

So, the magnitude of force acting on the car to stop is 5702.56 N.

Answer:

a. 3.07 b. 1.26

Explanation:

Given that A = -3.07i + 3.17j and B = b1i + b1j and C = A + B = 0i + 4.43j

Since A + B = -3.07i + 3.17j + b1i + b2j

= (-3.07 + b1)i + (3.17 + b2)j

So,(-3.07 + b1)i + (3.17 + b2)j = 0i + 4.43j

Comparing components,

-3.07 + b1 = 0 (1) and 3.17 + b2 = 4.43 (2)

a. From (1), b1 = 3.07

b. From(2) b2 = 4.43 - 3.17 = 1.26

Answer:

Explanation:

No of atoms of Ra in 1 g of sample = 6.023 x 10²³ / 226

N = 2.66 x 10²¹

disintegration constant λ = .693 / half life

half life = 1620 x 365 x 60 x 60 x 24 = 5.1 x 10¹⁰ s

disintegration constant λ = .693 / 5.1 x 10¹⁰

radioactivity dn / dt = λN

= (.693 / 5.1 x 10¹⁰ )  x 2.66 x 10²¹

= .3614 x 10¹¹ per sec

= 3.614 x 10¹⁰ / s

Answer:

q = 1 x 10⁻⁵ C = 10 μC

Explanation:

The repulsive  force between the charges is given by Coulumb's Law:

[tex]F = \frac{kq_{1}q_{2}}{r^{2}}\\[/tex]

where,

F = Electrostatic Force = 12 N

k = Coulomb's Constat = 9 x 10⁹ Nm²/C²

r = distance between charges = 28 cm = 0.28 m

Since the values or charges are not given. We assume that both charges have same mahnitude. Therefore,

q₁ = q₂ = q = charge on each sphere = ?

Therefore,

[tex]12\ N = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})q^{2}}{(0.28\ m)^{2}} \\\\q^{2} = \frac{(12\ N)(0.28\ m)^{2}}{9\ x\ 10^{9}\ Nm^{2}/C^{2}}\\q = \sqrt{1\ x\ 10^{-10}\ C^{2}}\\[/tex]

q = 1 x 10⁻⁵ C = 10 μC

Answer:

The new volume of the ballon will be 13.345 L

Explanation:

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure, by means of a constant of proportionality that is applied directly. For a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

[tex]\frac{V}{T}=k[/tex]

It is possible to assume that you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]

In this case:

Replacing:

[tex]\frac{17 L}{200 K} =\frac{V2}{157 K}[/tex]

Solving:

[tex]V2= 157 K*\frac{17 L}{200 K}[/tex]

V2= 13.345 L

The new volume of the ballon will be 13.345 L

Answer:

1)    f’₀ / f = 1.10, the relationship between the focal length (f'₀) and the distance to the retina (image) is given by the constructor's equation

2) the two diameters have the same order of magnitude and are very close to each other

Explanation:

You have some problems in the writing of your exercise, we will try to answer.

1) The equation to be used in geometric optics is the constructor equation

          [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where p and q are the distance to the object and the image, respectively, f is the focal length

* For the normal eye and with presbyopia

the object is at infinity (p = inf) and the image is on the retina (q = 15 mm = 1.5 cm)

        [tex]\frac{1}{f'_o} = 1/ inf + \frac{1}{1.5}[/tex]

        f'₀ = 1.5 cm

this is the focal length for this type of eye

* Eye with myopia

the distance to the object is p = 15 cm the distance to the image that is on the retina is q = 1.5 cm

           1 / f = 1/15 + 1 / 1.5

           1 / f = 0.733

            f = 1.36 cm

this is the focal length for the myopic eye.

In general, the two focal lengths are related

         f’₀ / f = 1.5 / 1.36

         f’₀ / f = 1.10

The question of the relationship between the focal length (f'₀) and the distance to the retina (image) is given by the constructor's equation

2) For this second part we have a diffraction problem, the point diameter corresponds to the first zero of the diffraction pattern that is given by the expression for a linear slit

          a sin θ= m λ

the first zero occurs for m = 1, as the angles are very small

          tan θ = y / f = sin θ / cos θ

for some very small the cosine is 1

          sin θ = y / f

where f is the distance of the lens (eye)

           y / f = lam / a

in the case of the eye we have a circular slit, therefore the system must be solved in polar coordinates, giving a numerical factor

           y / f = 1.22 λ / D

           y = 1.22 λ f / D

where D is the diameter of the eye

          D = 2R₀

          D = 2 0.1

          D = 0.2 cm

the eye has its highest sensitivity for lam = 550 10⁻⁹ m (green light), let's use this wavelength for the calculation

* normal eye

the focal length of the normal eye can be accommodated to give a focus on the immobile retian, so let's use the constructor equation

      \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

sustitute

       [tex]\frac{1}{f} = \frac{1}{25} + \frac{1}{1.5}[/tex]

       [tex]\frac{1}{f}[/tex]= 0.7066

        f = 1.415 cm

therefore the diffraction is

        y = 1.22  550 10⁻⁹  1.415  / 0.2

        y = 4.75 10⁻⁶ m

this is the radius, the diffraction diameter is

       d = 2y

       d_normal = 9.49 10⁻⁶ m

* myopic eye

In the statement they indicate that the distance to the object is p = 15 cm, the retina is at the same distance, it does not move, q = 1.5 cm

       [tex]\frac{1}{f} = \frac{1}{15} + \frac{1}{ 1.5}[/tex]

        [tex]\frac{1}{f}[/tex]= 0.733

         f = 1.36 cm

diffraction is

        y = 1.22 550 10-9 1.36 10-2 / 0.2 10--2

        y = 4.56 10-6 m

the diffraction diameter is

        d_myope = 2y

         d_myope = 9.16 10-6 m

         [tex]\frac{d_{normal}}{d_{myope}}[/tex] = 9.49 /9.16

        \frac{d_{normal}}{d_{myope}} =  1.04

we can see that the two diameters have the same order of magnitude and are very close to each other

Answer:

Answer B. Adding carts increases the mass and increases the total energy in the system.

Explanation:

By adding carts, the mass of the system is larger, and therefore, both the potential energy and the kinetic energy of the system will increase, thus contributing to larger final velocities as the carts roll down the tracks.

The correct answer is therefore the one shown in answer B:

Adding carts increases the mass and increases the total energy in the system.

Answer:the witch has nothing to do with the problem

Explanation:

Answer:

O

Explanation:

Because your product will not work well so people will not buy it  and it could be a defect and explode

Answer:

c

Explanation:

Answer:

V = V₁ + V₂ + V₃ + ... + Vₙ

Explanation:

When the resistors are connected end to end such that there is only one path for the current to follow, it is called a series arrangement of resistors. In the series arrangement of the resistors, the current across each resistor is the same as the current applied across the circuit.

The potential difference across each resistor is different in the series arrangement of the resistors. But the sum of potential differences across each of the resistors in the series arrangement of resistors is equal to the total potential difference applied by the battery or source. Therefore, if n number of resistors are connected in a series arrangement with a source of potential V, the:

V = V₁ + V₂ + V₃ + ... + Vₙ

Answer:

Angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;

∅₁ = 0.8439°

∅₂ = 0.1688°

∅₃ = 0.2533°

Explanation:

Given that;

wavelength λ = 560 nm = 560 × 10⁻⁹

Separation between slits d = 0.380 mm = 0.00038

n = first three orders = 1st order, 2nd order and 3rd oder.

we know that for constructive interference;

λn = dsin∅

sin∅ = λn/d

∅ = sin⁻¹ ( λn/d )

where λ is wavelength, ∅ is the angle, d is the distance between slits, n is the order of constructive interference.

now;

-First order;  n = 1

∅₁ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(1) /0.00038 )

∅₁ = sin⁻¹( 0.001473) = 0.8439°

-2nd order;  n = 2

∅₂ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(2) /0.00038 ) =

∅₂ = sin⁻¹( 0.002947) = 0.1688°

-3rd order;  n = 3

∅₃ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(3) /0.00038 ) =

∅₃ = sin⁻¹( 0.004421) = 0.2533°

Therefore, angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;

∅₁ = 0.8439°

∅₂ = 0.1688°

∅₃ = 0.2533°

Answer:

Superman's delivered impulse : 108,000 kg m/s

New momentum of the airplane: 1,108,000 kg m/s

Explanation:

Recall that impulse can be estimated by multiplying the applied force times the duration of time the force was applied. Therefore, the impulse added by Superman was:

1,200,000 * 0.09 = 108,000 kg m/s

and then, the new momentum of the plane is the addition:

1000000 + 108000 = 1,108,000 kg m/s

Answer:

1200 J

Explanation:

option 1 should be the answer

Answer:

The change in momentum is 0

Explanation:

Step one:

given data

mass of ball = 1.4kg

initial velocity of ball u = 9.7m/s

final velocity of ball v = 9.7m/s

Required

the change in momentum

Step two:

From the expression for momentum

P=mv

the change in momentum

Δp= mu-mv

Δp= 1.4*9.7-1.4*9.7

Δp= 13.58-13.58

Δp=0

There is no change in momentum

Answer:

Hello your question is incomplete hence I will give you a general answer as regards to tectonic plates sliding past each other in a sideways direction

answer : The Transform boundary is been demonstrated by the students when sliding tectonic plates past each other in sideways directions

Explanation:

The event that can be demonstrated by the students using blocks to represent tectonic plates and sliding the clocks past each other in sideways direction is Transform Boundary of the tectonic plates

Answer:

1.8 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature of the wood. This can be obtained as follow:

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Change in temperature (ΔT) =.?

ΔT = T₂ – T₁

ΔT = 57 – 32

ΔT = 25 °C

Finally, we shall determine the heat capacity of the wood. This can be obtained as follow:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) =?

Q = MCΔT

67500 = 1500 × C × 25

67500 = 37500 × C

Divide both side by 37500

C = 67500 / 37500

C = 1.8 J/gºC

Thus, the heat capacity of the wood is 1.8 J/gºC

Answer:

1.6675×10^-16N

Explanation:

The force of gravity that the space shuttle experiences is expressed as;

g = GM/r²

G is the gravitational constant

M is the mass = 1.0 x 10^5 kg

r is the altitude = 200km = 200,000m

Substitute into the formula

g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²

g = 6.67×10^-6/4×10^10

g = 1.6675×10^{-6-10}

g = 1.6675×10^-16N

Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N

Answer:

Just like lightning, the spark you see is the discharge of static electricity that equalizes the charges.  When you touch a metal object and get a shock, electrons are travelling in between you and the object to equalize the charges of the two objects.  The light that is seen is the plasma created by electrons jumping between objects which heats the air surrounding them.  

Answer:

4.01 seconds

Explanation:

Given that:

Mass of ball = 15kg

Initial velocity, u = 3m/s

Final velocity, v = 0

Force, F= 11.2 N

Change in velocity, dv = 3 - 0 = 3

Time force must act on the ball before stopping it:

Using the relation :

F = ma

a = (v - u) / t

Ft = m(v - u)

11.2 * t = 15 * 3

11.2t = 45

11.2t = 45

t = -+¯ 45 / 11.2

t = 4.01

t = 4 seconds.

Answer:

0.0314secs

Explanation:

The standard equation of a wave is expressed as;

y(x,t) = Asin(2πx/λ+2πft)

compare and contrast with the equation  y(x,t)=0.003(20x+200t)

2πft = 200t

2πf = 200

f = 200/2π

f = 100/π

Since period T = 1/f

T = π/100

T = 3.14/100

T = 0.0314secs

hence the period of the wave is 0.0314secs

Answer:

F' = 162 units

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

[tex]F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\[/tex]

where,

F = gravitational force = 18 units

G = Gravitational Constant

m₁ = mass of object 1

m₂ = mass of object 2

r = distance between objects

Therefore,

[tex]18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\[/tex]

Now, if we change the value of distance to one-third of original value, then:

r' = r/3

[tex]F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})[/tex]

using eqn (1):

F' = 9(18 units)

F' = 162 units

Answer:

Reflection of sound

Explanation:

Sound waves bounce back from hard surface's.