A study of the population of deer in a park finds that the population decreases by 1.2% each year. The deer population at the beginning of the study is 525. Write an equation to model the population of deer in the park after x years. After how many years will the population of deer in the park be less than 200?

The 95% confidence interval estimate of the population mean is between $50,555.51 and $51.444.49.

Confidence interval is defined as the range of values where a parameter might fall at a given confidence level. It can be calculated using the formula below.

CI = μ ± z x (SD / √n)

where CI = confidence interval

μ = sample mean

z = found by using a z-score table

SD = sample standard deviation

n = sample size

At 95% confidence level, the area in each tail of the standard normal curve is 2.5, and the cumulative area up to the second tail is 97.5.

(100 - 95) / 2 = 2.5

100 - 2.5 = 97.5

Find 0.975 in the z-table to get the value of z.

At p = 0.95, z = 1.96

Plug in the values and solve for the confidence interval.

CI = μ ± z x (SD / √n)

CI = $51,000 ± 1.96 x ($1,200 / √28)

CI = $51,000 ± $444.49

CI = [$50,555.51, $51.444.49]

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The three sides are equally distant from the center and the distance is  L/√3

Let the triangle be  ΔABC  with vertices A,B and C with length of each side L. Each angle will be 60°

L=AB=BC=CA

Draw 3 angle bisectors(or 3 altitudes or 3 medians). These all meet at a single point which is the center of the equilateral triangle. Let the centre be D.

Now consider the  ΔADB . The  ∠ADB=120°  ( ∵∠BCA=60° . The angle bisector makes  ∠DAB=∠DBA=30°)

Using Sine rule for triangles:

a/sin(A)=b/sin(B)=c/sin(C)

Where a is the length of side opp. to the side of  ∠A . Similarly, b and c are also defined as the length of side opp. to the ∠B and  ∠C  respectively.

Then, in this case, in  ΔADB

Lsin(120°)=ADsin(30°)=BDsin(30°)

⇒AD=Lsin(30°)/sin(120°)=Lx(1/2)/(√3/2)

⇒AD=L/√3

Similarly, DB=L/√3

Thus the three sides are equally distant from the center and the distance is  L/√3

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The lower bound for a 95% confidence interval for the proportion of defective iphones from this assembly line is 0.0524.

With the probability of a success of π , and a confidence level of 1-α, we have the following confidence interval of proportions:

π± z[tex]\sqrt{\frac{\pi (1-\pi }{n} }[/tex]

z is the z-score having a p-value of 1-α/2.

we have η = 605 and ρ = 0.07

So, α = 0.1 and z is the value of Z that has a pvalue of:

1 - 0.1/2 = 0.95

Z= 1.645

Now the lower limit:

π - z[tex]\sqrt{\frac{\pi (1-\pi }{n} }[/tex]

= 0.07-1.645[tex]\sqrt\frac{(0.07*0.93)}{605}[/tex]

= 0.07 - 0.01706

= 0.0524

The lower bound for a 95% confidence interval for the proportion of defective Galaxy phones from this assembly line is 0.0524

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Answer:

A

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 1) and (x₂, y₂ ) = (0, - 1) ← 2 points on the line

m = [tex]\frac{-1-1}{0-(-1)}[/tex] = [tex]\frac{-2}{0+1}[/tex] = [tex]\frac{-2}{1}[/tex] = - 2

the line crosses the y- axis at (0, - 1 ) ⇒ c = - 1

y = - 2x - 1 ← equation of line b

The point on the y-axis is (0,1) such that the distance is minimum.

Let the coordinate of the point W be (0,a)

We know that the distance from any point on the coordinate place is calculated using the distance formula.

Now let us calculate the distance of VW = √[(2-0)²+(3-a)²]

Distance XW = √[(-2-0)²+(-1-a)²]

Now the sum of the distances is given by:

VW + XW

=√[(-2-0)²+(-1-a)²] + √[(2-0)²+(3-a)²]

This can be written in the form of a function in a such that:

f(a) = √a²+2a+5 + √a²-6a+25

Now we will differentiate with respect to a to get the required first degree

f'(a) = [tex]\frac{a+1}{\sqrt{a^2+3a+5}} + \frac{a-3}{\sqrt{a^2-6a+25}}[/tex]

Now at f'(a)=0

we get a=1.

Hence the required point on the y-axis that is at a minimum distance is (0,1) .

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Step-by-step explanation:

Which values are part of the solution set based on the result of the inequality?

-4x + 24 < -2x + 2

add 2x to both sides:

-4x + 24 + 2x < -2x + 2 + 2x

-2x + 24 < 2

subtract 24 from both sides:

-2x + 24 - 24 < 2 - 24

-2x  < -22

divide both sides by -2: [remember to flip the sign direction because you are dividing by a negative number]

-2x/-2  > -22/-2

x  > 11

or (11 , ∞)

Answer:

Particle A is a proton and particle B is a neutron

Step-by-step explanation:

Answer: About 7%

Step-by-step explanation:

(Choice A) A Same area only is the correct option about rectangles.

The perimeter and area is calculated using the formula -

Perimeter = 2 (length + breadth)

Area = length × breadth

Now, calculating the perimeter and area of each rectangle

Rectangle with dimensions 5 cm and 4 cm

Perimeter = 2 (5 + 4)

Perimeter = 2 × 9

Perimeter = 18 cm

Area = 5 × 4

Area = 20 cm²

Rectangle with dimensions 2 cm and 10 cm

Perimeter = 2 (2 + 10)

Perimeter = 2 × 12

Perimeter = 24 cm

Area = 2 × 10

Area = 20 cm²

Thus, both the rectangles will have same area.

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The population on the first day of the opening of the mall was 7723.66.

Percentage:

A relative value indicating hundredth parts of any quantity. One percent (symbolized 1%) is a hundredth part; thus, 100 percent represents the entirety and 200 percent specifies twice the given quantity.

Here it is given that there is an increase in the population of the mall by 5%

We have to find the population on the first day.

The population on the 10th day is 12581.

let x be the population on the first day.

Population on the 10th day = x( 1 + 5/100[tex])^{10}[/tex]

12581 = x [tex]1.05^{10}[/tex]

x = 12581/ 1.62889

  = 7723.66

Therefore we get the population on the first day of the mall to be 7723.66.

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Answer: Hello winstead. I'm Walter White

Step-by-step explanation:

Was this an actual question?

According one-way ANOVA, the test is false.

In the given question,

When comparing three or more populations means within a set of quantitative data that is categorized according to one​ factor/treatment, a​ one-way ANOVA is appropriate. It is also appropriate in this​ situation, however, to compare two means at a time using multiple independent two sample​ t-tests. We have to check whether this is true or​ false.

We firstly learn about one-way ANOVA

"One-Way ANOVA, also known as "analysis of variance," examines the means of two or more independent groups to see if there is statistical support for the notion that the related population means are statistically substantially different."

According to the given method it is inappropriate to compare two means at a time using multiple independent two sample​ t-tests. It will create multiple testing problem and error.

So using one way ANOVA test when comparing three or more populations means within a set of quantitative data that is categorized according to one​ factor/treatment and compare two means at a time using multiple independent two sample​ t-tests is false.

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Answer: b=12x

Step-by-step explanation:

The bakery shipped out b boxes of bagels.

Each box contained 12 bagels

b is the number o boxes

x is the number of bagels in each box

The ordered pair (x,y) obtained from the linear equations is: (-2,-12)

What is Linear Equation?

A linear equation is one that has a degree of 1 as its maximum value. No variable in a linear equation, thus, has an exponent greater than 1. A linear equation's graph will always be a straight line.

Definition of a Linear Equation: Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason. A linear equation is expressed using the linear equation formula. There are several ways to accomplish this. A linear equation, for instance, can be written in standard form, slope-intercept form, or point-slope form. To discover how a linear equation is stated in its standard form, let's take an example.

The equation is given:

8x-3y=20

5x-y=2

Using the substitution method for solving the linear equations:

From the equation:

5x-y=2;

we can transform this equation as:

⇒-y = 2-5x;

⇒y = 5x-2;

Now substituting the value of y in the other equation: we get;

⇒8x-3(5x-2)=20

⇒8x -15x+6 = 20;

⇒-7x=14;

x = -2;

Now putting the value of x in the equation to get the value of y;

So,

y = 5(-2) -2;

y = -12;

Hence the value of x and y are -2 and -12 respectively;

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Answer:

11units (Brainliest?)

Step-by-step explanation:

(20-9)²

(11)²

(cancel squares by square rooting both sides)

11

The circumference and the area of the circle in terms of "π" are 24π and 144π.

We are given a circle. The coordinates of the center of the circle are (12, -1). The circle passes through a point. The coordinates of the passing point are (0, -1). We need to find the circumference and area of the circle.

Let the radius, circumference, and area of the circle be denoted by the variables "r", "C", and "A", respectively. The radius is the distance between the center of the circle and a point on its boundary. We will use the distance formula.

r = √[(12 - 0)² + (-1 - (-1))²]

r = √[144 + 0]

r = 12

The radius of the given circle is 12 units.

The circumference of the circle is calculated below.

C = 2πr

C = 2π×12

C = 24π

The area of the circle is calculated below.

A = πr²

A = π(12)²

A = 144π

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Answer:

x = 7

Step-by-step explanation:

2 (-4x + 2) + 5x - 2 = -19       Distribute 2 to -4x and 2

-8x + 4 + 5x - 2 = -19            Combine like terms

-3x + 2 = -19                          Subtract 2 from both sides

-3x = -21                                To get x by itself, divide -3 on both sides

x = 7

The measure of angle 3 is 22.5°.

Given,

∠1 = (x-18)°

∠2 = (3x+36)°

∠1 + ∠2 = 180°  (Straight Line)

x - 18 + 3x + 36 = 180

            4x + 18 = 180

                   4x = 180 - 18

                   4x = 162

                     x = 162/4

                     x = 40.5

∠3 = ∠1 (Alternate opposite angles)

    = x - 18

    = 40.5 - 18

    = 22.5

Hence, ∠3 is 22.5°.

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The values of the elements of the matrix will ψ(t)⟩=e−iE1t/ℏ|2⟩

Let's say the block matrix is used to represent the 2n by 2n matrix A.

Displaystyle A="begin" "bmatrix" "a&b" "c&d" "end"

where n-by-n matrices a, b, c, and d. The requirement that b and c be symmetric and that a + dT = 0 are similar to the requirement that A be Hamiltonian. The fact that A is of the form A = JS with S symmetric is another equivalent requirement.

Two Hamiltonian matrices can be added together (as can any linear combination), and their commutator is also Hamiltonian. The space of all Hamiltonian matrices is hence a Lie algebra, indicated by the symbol sp (2n). Sp(2n) has a dimension of 2n2 + n.

H^=E0(|1⟩⟨1|+|3⟩⟨3|)+E1|2⟩⟨2|+A(|1⟩⟨3|+|3⟩⟨1|)H^=E0(|1⟩⟨1|+|3⟩⟨3|)+E1|2⟩⟨2|+A(|1⟩⟨3|+|3⟩⟨1|)

It is then straightforward to see that :

• |2⟩|2⟩ is an eigen state with eigen value E1E1 as you have already noticed. Hence if the initial state is |2⟩|2⟩ then

|ψ(t)⟩=e−iE1t/ℏ|2⟩

• (|1⟩+|3⟩)(|1⟩+|3⟩) and (|1⟩−|3⟩)(|1⟩−|3⟩) are eigen states with respective eigen values of E0+AE0+A and E0−AE0−A. Hence if the initial state is |3⟩=12[(|1⟩+|3⟩)−(|1⟩−|3⟩)]|3⟩=12[(|1⟩+|3⟩)−(|1⟩−|3⟩)], then

|ψ(t)⟩=12[e−i(E0+A)t/ℏ(|1⟩+|3⟩)−e−i(E0−A)t/ℏ(|1⟩−|3⟩)]

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incomplete question: complete question is

Let

⎡⎣⎢E00A0E10A0E0⎤⎦⎥[E00A0E10A0E0]

be the matrix representation of the Hamiltonian for a three-state system with basis states |1>,|2>and |3>|1>,|2>and |3>.

a. If the state of the system at time tt = 00 is |ψ(0)>=|2>|ψ(0)>=|2> what is |ψ(t)>|ψ(t)>?

b. If the state of the system at time tt = 00 is |ψ(0)>=|3>|ψ(0)>=|3> what is |ψ(t)>|ψ(t)>?

The smallest number of rectangles required will be  30.

Given:- The sides of the rectangle are in the ratio of 5:4

let, length=5x

breadth=4x

Area = 20x²

Area of smaller rectangle =2*3

                                           =6cm²

Now, take numbers which are in the ratio of 5:4;

suppose, Case 1=10:8

                 Case2 = 15:12

For Case 1;

number of rectangles needed =10*8/2*3

                                                     =13.3333

This means it is overlapping hence, not possible.

For Case 2;

number of rectangles needed=15*12/2*3

                                                  =30

therefore, the smallest number will be 30.

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There can be up to 12 lots which could be made out of 2 acre land.

What is acre?

Acre is a measurement unit which is used to measure length of land .

In the British Imperial and United States Customary systems, 1 acre equal to 43,560 square feet.

Main body:

so 1 acre = 43560 feet ²

So in 2 acre of land = 2*43560

                                 = 87120 sq. ft.

Width of 1 plot = 72.5 feet

Depth of 1 plot = 100 feet

Area of 1 plot = 100*72.5

                      = 7250 sq. ft.

Total no. of plots = Total are of land / area of 1 plot

                            = 87120/ 7250

                            ≈12

Hence total plots that can be made out of 2 acre land is 12.

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Answer:

Q29. ∠CAD = (180° - 92°) ÷ 2 (angle sum of triangle; base angles of an isosceles triangle)

                    = 44°

Q30. Since triangle ACD is an isosceles triangle,

∴ ∠ACD = ∠CAD = 44°

Q31. ∠ACB = 180° - 44° (adjacent angles on a straight line)

                   = 136°

Q32. ∠ABC = (180 °- 136°) ÷ 2 (angle sum of triangle; base angles of an isosceles triangle)

                   = 22°

Using the equation of line, the equation parallel to y=5 and passing through (3,-5) is y+5=0.

In the given question,

We have to find an equation parallel to y=5 and passing through (3,-5).

The equation parallel to y=5.

Point is (3,-5).

We firstly find the slope of y=5

Expressing the equation in the general form

y=0×x+5

On comparing to the y=mx+c, we get slope(m) = 0.

The given point is (3,-5) in which [tex]x_{1}[/tex]=3 and [tex]y_{1}[/tex]= -5

Now finding the equation.

So the Equation of line is

y - [tex]y_{1}[/tex] = m(x - [tex]x_{1}[/tex])

Now putting the value

y-(-5)=0(x-3)

Simplifying

y+5=0

Hence, the equation parallel to y=5 and passing through (3,-5) is y+5=0.

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Answer:

YesTheorem 8.3: If two angles are complementary to the same angle, then these two angles are congruent.

A and B are complementary, and C and B are complementary.

Correct option is D)

We shall label the figure as shown below:

The simplest parallelograms are ABML, BCNM, COON, DEFO, OFGH, NOHl, MNIJ and LMJK i.e. 8 in number.

The parallelograms composed of two components each are ACNL, BDOM, CEFN, LNIK, MOHJ, NFGI, ABJK, BCLJ, CDHI and DEGH i.e. 10 in number.

The parallelograms composed of three components each are ADOL, BEFM, LOHK and MFGJ i.e. 4 in number.

The parallelograms composed of four components each are AEFL, LFGK, ACIK, BOHJ and CEGI i.e. 5 in number.

The parallelograms composed of six components each are ADHK and BEGJ i.e. 2 in number. AEGK is the only parallelograms composed of eight components.

Total number of parallelograms in the figure =8+10+4+5+2+1=30

Hence, the answer is (D).

Answer:

Option D is correct

Step-by-step explanation:

...

Answer:

4+1.5n=c

9+0.5n=c

5 hours

Step-by-step explanation:

(n) represents the number of hours

(c) represents the total cost

Bike shop A)    $4+$1.5n=c

Bike shop Z)    $9+$0.5n=c

4+1.5n=9+0.5n

n=5                  Both shops would charge the same amount at 5 hours.

Answer:

When the boat is 6 m from the dock, it is approaching the dock at the rate of √37/6 m/sec.

Step-by-step explanation:

Let x = distance of the boat from the dock at time t

    y = length of rope at time t

Draw a right triangle with horizontal leg x, vertical leg 1, and hypotenuse y.

We know that dy/dt = -1 and want to find dx/dt when x = 6.

By the Pythagorean Theorem, x2 + 12 = y2.

   2x(dx/dt) = 2y(dy/dt)

        dx/dt = y(dy/dt) / x     When x = 6, y2 = 36 + 1 = 37

                                                            So, y = √37

         dx/dt = -√37 / 6

When the boat is 6 m from the dock, it is approaching the dock at the rate of √37/6 m/sec.

Answer:

[tex]\frac{7}{b+4}[/tex]

Step-by-step explanation:

[tex]\frac{7}{b^2+5b+4}[/tex] × [tex]\frac{b^2+8b+7}{b+7}[/tex] ← factor quadratics on numerator/ denominator

= [tex]\frac{7}{(b+1)(b+4)}[/tex] × [tex]\frac{(b+1)(b+7)}{b+7}[/tex]

cancel factors (b+ 1) and (b + 7) on numerator/ denominator

= [tex]\frac{7}{b+4}[/tex] × 1

= [tex]\frac{7}{b+4}[/tex]