If a swimmer swims the 50m length of a swimming pool in 15.91 second and makes the return swim in 18 seconds then the swimmer's average speed for the full swim is 2.948 metres per second.
To find the swimmer's average speed for the full swim, we need to calculate the total distance swum and the total time taken.
The swimmer swam the 50m length of the pool twice, once in 15.91 seconds and once in 18 seconds. So the total distance swum is 50m + 50m = 100m.
The total time taken is the sum of the time taken for each length: 15.91 seconds + 18 seconds = 33.91 seconds.
To find the swimmer's average speed, we divide the total distance by the total time:
Average speed = total distance ÷ total time
= 100m ÷ 33.91 seconds
= 2.948 metres per second
Therefore, the swimmer's average speed for the full swim is 2.948 metres per second. This is a relatively fast speed, but it's important to note that the swimmer's speed may vary depending on their stroke technique, physical fitness, and other factors. Nonetheless, it's an impressive achievement for the swimmer to complete the full 100m in under 34 seconds.
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A wave along a string has the following equation where x is in meters and t is in seconds. Y = 0.02 sin(24 t – 4.3 x) mm. Find the amplitude of the wave?
Answer: 0.02 mm
Explanation: General equation for wave has amplitude as the number that is multiplied by the trig ratio sine or cosine. The number in this case is 0.02. Since the y-value is in mm, the amplitude is 0.02 mm.
What is the greatest average speed of blood flow at 37∘C in an artery of radius 2.25 mm if the flow is to remain laminar? Take the density of blood to be 1025 kg/m3,
and the viscosity to be 2.084×10^−3 Pa·s.
The Hagen-Poiseuille equation may be used to determine the blood flow rate that is maximum on average at 37°C in an artery with a radius of 2.25 mm. According to this equation, the volumetric flow rate of a laminar flow is equal to the fourth-power product of the vessel's radius (r) and the pressure difference (P) divided by the fluid's viscosity ().
It also takes into account the length (L) of the vessel. The highest average blood flow rate in an artery with a radius of 2.25 mm may be computed using the information provided as follows: Q = (2.25^4 * ΔP) / (2.084*10^-3 * L) Q = (2.25^4 * ΔP) / (2.084*10^-3 * L) Q = (2.25^4 * ΔP) / (2.084*10^-3 * L) Q = (2.25^4 * ΔP) / (2.084*10^-3 * L)
Consequently, the highest average blood flow rate at Therefore, the greatest average speed of blood flow at 37∘C in an artery of radius 2.25 mm is equal to (2.25^4 * ΔP) / (2.084*10^-3 * L).
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Pretest: Unit 2
Question 17 of 25
Which of the following best defines displacement?
OA. The total length of a path traveled, regardless of th
travel
B. How far something moves in a given direction in a
The displacement is defined as the shortest distance between the starting and ending point along with the direction. Thus, option D is correct.
The displacement is defined as the shortest distance between the starting and ending point. The displacement is the vector quantity. It is also defined as the distance traveled by the object along with a particular direction. The distance is the scalar quantity and the displacement is the vector quantity. The SI unit of distance is a meter. The rate of change of displacement gives rise to velocity and the rate of distance gives rise to distance.
From, the given displacement is defined as the shortest length and direction from a starting and ending point. Thus, the correct option is D.
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Figure below shows the total acceleration and velocity of a particle moving clockwise in a circle of radius 2.5 m at a given instant of time. At this instant, find (a) the radial acceleration (b) the speed of the particle (c) its tangential acceleration.
At the given instant, the radial acceleration of the particle moving clockwise in a circle of radius 2.5 m is 21.650 m/s², its speed is 11.625 m/s, and its tangential acceleration is 12.5 m/s².
In circular motion, there are three important quantities: radial acceleration, tangential acceleration, and speed.
At the given instant, the radial acceleration (ar) can be calculated as:
ar = a cosθ
ar = 25 m/s² × cos30°
ar = 25 × 2/3
ar = 21.650 m/s²
The speed of the particle (V) can be calculated as:
V = r ×θ'
θ' = sqrt(rar/r)
θ' = sqrt(2.5×21.650/2.5)
θ' = sqrt(21.65)
θ' = 4.65 rad/s
V = r × θ'
V = 2.5 × 4.65
V = 11.625 m/s
The tangential acceleration (aθ) can be calculated as:
aθ = a sinθ
aθ = 25 m/s² ×sin30°
aθ = 25 × 1/2
aθ = 12.5 m/s²
Therefore, The particle is traveling clockwise in a circle with a radius of 2.5 m, its tangential acceleration is 12.5 m/s², its speed is 11.625 m/s, and its radial acceleration is 21.650 m/s².
I think the actual question is,
The figure shows( find at the bottom of this answer) the total acceleration and velocity of a particle moving clockwise in a circle of radius 2.5 m at a given instant of time. At this instant, find:
(a) the radial acceleration,
(b) the speed of the particle and
(c) its tangential acceleration.
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what is the similaries between parallel and series circuits
Answer:
same power source
can have more than 1 light bulb in a circuit
requires a source of energy
Explanation:
A pendulum takes 43.6 seconds to complete 10 full swings. What is the length of the pendulum?
4.72 m
5.51 m
6.80 m
9.44 m
The length of the pendulum can be calculated using the formula:
T = 2π√(L/g)
Where T is the period of the pendulum, L is the length of the pendulum, and g is the acceleration due to gravity.
We can rearrange this formula to solve for L:
L = gT^2 / (4π^2)
Given that the pendulum takes 43.6 seconds to complete 10 full swings, the period of the pendulum is:
T = (43.6 seconds) / (10 swings) = 4.36 seconds/swing
The acceleration due to gravity is approximately 9.8 m/s^2.
Substituting these values into the formula, we get:
L = (9.8 m/s^2) × (4.36 s/swing)^2 / (4π^2) = 5.51 m
Therefore, the length of the pendulum is 5.51 m.
Answer: L = 4.72 m
Explanation:
t=43.6 seconds, n=10
T= t/n = time period
= 43.6s/10 = 4.36s
t = 2pie square root of L/g
L= length
L = t^2/4pie^2g
4.36^2 x 9.8/4(22/7)^2
L = 4.791 m
L = 4.72 m
Connecting Clauses with Colons and Semicolons
Quaynisha Perry's strategy was interesting: ask everyone in the room to be part of the decision-making process.
The statement has been corrected of the capitalization error.
What is capitalization error?
Capitalization errors is said to take place when the writer capitalizes a word that does not require a capital letter or when the writer does not capitalize a word the requires one.
In all cases, Capitalization errors hinder the reader's experience with the writing and must be avoided at all cost.
It is pertinent to note that you should always capitalize the first letter of the first word in a sentence, no matter what the word is.
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One effective way to develop the "feeling" function in your personality is to
A. plan out a detailed schedule for each week.
B. ignore the consequences of your actions.
C. imagine how other people might feel in a situation.
D. spend more time alone.
The 'feeling' function in one's personality can be effectively developed through empathy, primarily by imagining how others might feel in various situations. This enhances one's ability to connect with others emotionally.
Explanation:One effective way to develop the 'feeling' function in your personality can be achieved through increased levels of empathy. The best choice among the provided options would be 'C. Imagine how other people might feel in a situation'. This behavior enables you to consider and understand circumstances from the perspectives of other people, thereby enhancing your capabilities to connect with them on an emotional level. It's important to note that this doesn't involve ignoring the consequences of your actions or spending more time alone. In contrast, it's about actively engaging in understanding and empathizing with others and their experiences.
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Find the equivalent capacitance of the
following combination as shown in figure. C₁
In which C₁ = C₂2 = C3 = C4 = C5 = 100 μF
=C4
C3
C₂
The effective capacitance of the following combination with capacitors C₁, C₂, C₃, C₄, C₅ = 100μF is 350 μF.
Capacitors are the energy storage device in the form of electrical energy. The amount of charge (Q) stored in the capacitors is linearly proportional to the applied Voltage (V). Capacitance equals the ratio of charge and voltage. The unit of capacitance is Farad (F). Capacitors are connected in series and parallel connections. In series connections, the capacitance is 1/C(eff) = 1/C₁ + 1/C₂. In parallel connections, the effective capacitance C(eff) = C₁ + C₂.
From the figure,
The capacitances, C₁, C₄, C₂ are parallelly connected whereas C₃ and C₅ are in series connections.
C(eff) = C₁ + C₂ + C₄ = 100 + 100 + 100 = 300 μF
The capacitance C₅ and C₃ are in series connections, then
1/C(eff) = 1/C₅ + 1/C₃ = 1/100 + 1/100 = 2/100 = 1/50
C(eff) = 50 μF
The effective capacitance = 300 + 50 = 350 μF.
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The unit of power is the
a. Joules
b. m/s
C. Watts
d. Newtons
Answer:
It could be both Joules or Watts, Watts for electrical measurements and Joules for power measuremnets.
Hope this helps :)
Pls brainliest...
The unit for work is the
a. Calories
b. Celsius degrees
c. Kilogram
d. Joules
(3.1.4)
The work done is the amount of energy transferred by the force to move an object. Work done equals the product of force and displacement. It is the scalar quantity.
Work done, W = F.d, where F is the force and d is the displacement of the object. The unit of work done is N/m or joule. Hence, the unit of work done is the joule. Thus, the correct option is option D.
Energy is defined as the ability to do work. Energy is of two types and they are potential and kinetic energy. Potential energy is the energy possessed by the object when the object is at rest and the kinetic energy is the energy possessed by the object when it is in motion.
Thus, the kinetic energy is maximum at X and Z. Thus, the ideal solutions are options B and D. The potential energy is maximum at W. Hence, the correct option is A.
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ver-P = W
(Remember these are metric units!)
Work-W = Fd
I. Solve and show your work
a. If a man carries a 44 pound box of books up a flight of stairs and he has a mass of 100
kg himself. How much work is done if the distance up is 10 meters?
*(remember he must lift himself and the box up the stairs)
b. How much power is necessary to do this in only I minute?
A. The work done, given that the distance is 10 meters is 11756.08 Joules
B. The power necessary to do the work is 195.93 W
A. How do i determine the work done?First, we shall convert 44 pound to Kg. Details below:
1 pound = 0.4536 Kg
Therefore,
44 pound = 44 × 0.4536
44 pound = 19.96 Kg
Finally, we shall determine the work done. Details below:
Mass of book = 19.96 KgMass of man = 100 KgTotal mass (m) = 19.96 + 100 = 119.96 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) = mg = 119.96 × 9.8 = 1175.608 NDistance (d) = 10 metersWorkdone (Wd) =?Work done (Wd) = force (F) × distance (d)
Work done (Wd) = 1175.608 × 10
Work done (Wd) = 11756.08 Joules
B. How do i determine the power?The power necessary to do the work can be obtain as follow:
Work done (Wd) = 11756.08 JTime (t) = 1 minute = 1 × 60 = 60 secondsPower (P) = ?Power is defined according to the following formula:
Power = Work done / time
P = Wd / t
P = 11756.08 / 60
Power = 195.93 W
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Gia is creating an ad for her new workout studio. She wants to appeal to people in the area to give her studio a try. Which is an example of an emotional appeal?
A.
Regular exercise can decrease a person’s health risks and increase their life span.
B.
Buying a membership will save a person 30 percent off as opposed to paying per visit.
C.
Our community will be brighter, happier, and healthier if everyone becomes a member!
D.
You deserve to feel good about yourself! Working out at my studio can do that for you!
In a case whereby Gia is creating an ad for her new workout studio. She wants to appeal to people in the area to give her studio a try an example of an emotional appeal is D.You deserve to feel good about yourself! Working out at my studio can do that for you!
What is emotional appeal?An debate an be won through thepeocess of emotional appeal, beaue it is an emotional manipulation, as opposed to utilizing reason and logic.
An informal fallacyan be described a the argumentum ad passiones tht encopass the process of appealing to the recipient's emotions in attempt to win an argument, particularly in the absence of factual evidence.
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is a thermopoteota unicellular or multicellur
Answer:
unicellular
Explanation:
it's a archea so its unicellular
Define one standard kilogram
The standard kilogram is a physical object which weighs exactly 1 kilogram and is used as the primary reference for the kilogram unit of mass.
What is standard kilogram?The standard kilogram, also known as the international prototype of the kilogram (IPK), is a physical artifact. It is kept at the international bureau of weights and measures and is used as the primary standard for the kilogram unit of mass.
The international prototype of the kilogram (IPK), is a cylindrical shape with a height of 39 mm and a diameter of 39 mm, and it has a mass of exactly 1 kilogram (1000 grams).
Thus, the standard kilogram is a physical object which weighs exactly 1 kilogram and is used as the primary reference for the kilogram unit of mass.
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Mr. Bateman creates a standing wave in the front of the classroom with the spring. S nodes form. The distance from Mr. Bateman to the cabinet is 6m. If a student times the spring moving back and forth and gets 0.2s for one cycle of the spring, how fast are the
waves moving?
Answer:
The speed of a wave is equal to the wavelength divided by the period. The wavelength is the distance between two consecutive nodes, and the period is the time it takes for one complete cycle of the wave.
In this case, the wavelength is 6 m and the period is 0.2 s. Therefore, the speed of the wave is 30 m/s.
The answer is 30 m/s.
Explanation:
Linearise the following equations, also indicate (with the aid of a sketch) what would be plotted on the y- and x-axis and what would be obtained from the slope and intercept. Variables are indicated in brackets. Y=aX¹ C=aT + BT² (i) (ii) (Y, X) (C, T) [6]
i) The slope of the line (m) would be ln(a), and the intercept (c) would be 0.
ii) The slope and intercept obtained from the linearized equations provide valuable information about the relationship between the variables involved.
To linearize the given equations, we need to rewrite them in a linear form. Let's work through each equation:
(i) Y = aX¹
To linearize this equation, we can take the natural logarithm (ln) of both sides:
ln(Y) = ln(aX¹)
Using the logarithmic property, we can simplify it as:
ln(Y) = ln(a) + ln(X¹)
Now, we can introduce a new variable, let's say ln(Y), and rewrite the equation as:
ln(Y) = ln(a) + X¹ln(X)
Now, we have a linear equation in the form Y' = mX' + c, where Y' = ln(Y), X' = ln(X), m = ln(a), and c = 0. In this linearized form, Y' would be plotted on the y-axis, and X' would be plotted on the x-axis. The slope of the line (m) would be ln(a), and the intercept (c) would be 0.
(ii) C = aT + BT²
To linearize this equation, we can introduce a new variable, let's say Z, defined as Z = C/T. Now, we can rewrite the equation as:
Z = a + BT
Now, we have a linear equation in the form Z = mT + c, where Z = C/T, m = B, and c = a. In this linearized form, Z would be plotted on the y-axis, and T would be plotted on the x-axis. The slope of the line (m) would be B, and the intercept (c) would be a.
By linearizing the equations, we can transform the nonlinear relationships into linear relationships, which allows for easier analysis and interpretation of the data. The slope and intercept obtained from the linearized equations provide valuable information about the relationship between the variables involved.
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The winter sport of curling involves sliding a large granite stone on ice with the objective of placing it closest to the center of the ring. The curler causes the path of the stone to curve by giving it an initial circular rotation. Sweepers use brooms to sweep the path in front of the stone. How does the motion of the sweepers relate to the conservation of angular momentum?
The sweepers minimize friction between the stone and ice which helps maintain the angular momentum.
The sweepers motion creates circular air motion which adds to the angular momentum.
The sweepers motion adds torque to the stone's angular momentum.
The sweepers create circular patterns in the ice to increase the angular momentum.
Answer:
The sweepers motion adds torque to the stone's angular momentum.
Explanation:
This is due to angular momentum law.
1. Multiple light bulbs are connected in series across a 120.0 V
source of emf. The current in the circuit is 1.25 A. If each light
bulb has a resistance of 3.00 £2, how many light bulbs are in
the circuit?
2. If the resistance of bulb A is 6 2, the resistance of bulb B is
18 02, and the equivalence resistance of the circuit is 1202,
what is the resistance of bulb C?
1) Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs: n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs. There are 32 light bulbs in the circuit.
2) The total resistance is equal to the sum of individual resistances: R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω. The resistance of bulb C is 96 Ω.
In a series circuit, the total resistance is equal to the sum of individual resistances. Using Ohm's Law, we can find the total resistance:
R = V/I = 120.0 V/1.25 A = 96 Ω
Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs:
n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs
Therefore, there are 32 light bulbs in the circuit.
In a series circuit, the total resistance is equal to the sum of individual resistances:
R_eq = R_A + R_B + R_C
Substituting the given values:
120 Ω = 6 Ω + 18 Ω + R_C
Solving for R_C:
R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω
Therefore, the resistance of bulb C is 96 Ω.
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Question
Tina set a goal to run a 5k race, so she set a mileage goal each week. She
became more and more confident that she would be able to finish the race.
This is an example of which of the following?
OA Physiological states
OB. Verbal persuasion
C. Performance accomplishments
OD. Vicarious experience
SUBMIT
The example provided is most closely related to option C: Performance accomplishments.
Setting a mileage goal each week and becoming more confident about finishing the race indicates that Tina is actively working towards her goal of running a 5k race. By gradually increasing her mileage and gaining confidence, she is achieving performance accomplishments, which involve personal achievements and successful experiences.
Physiological states refer to the influence of one's physical and emotional condition on their confidence and motivation. Verbal persuasion involves receiving encouragement or positive feedback from others. Vicarious experience entails gaining confidence by observing and learning from others' successes.
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The diagram shows two circuits.
Which statement correctly describes each circuit?
A. The bulbs in both circuits are connected in series.
B. The bulbs in Circuit 1 are connected in parallel, and the bulbs in Circuit 2 are connected in series.
C. The bulbs in both circuits are connected in parallel.
D. The bulbs in Circuit 1 are connected in series, and the bulbs in Circuit 2 are connected in parallel.
Answer:
(D is correct
The diagram below shows snapshots of an
oscillator at different times. What is the amplitude
of the oscillation?
C
A
B
D
t=0.0 s t=0.30 s t=0.45 s t=0.90 s
+0.10 m.
www.
0
-0.10 m
(Unit = m)
E
t=1.35 s
www
F
t=1.80 s
0
The amplitude of the oscillation is +0.10 m, as shown in snapshots A and E.
Oscillation refers to a repetitive back-and-forth or up-and-down motion of an object or system about an equilibrium position. This motion can be periodic or non-periodic.
The amplitude of an oscillation is the maximum displacement of the object or system from its equilibrium position during one cycle of motion. It is the distance between the equilibrium position and either the crest or trough of the wave. The amplitude determines the energy of the oscillation, with larger amplitudes corresponding to greater energy. In the context of waves, amplitude can also refer to the maximum displacement of the medium from its rest position.
Therefore, The amplitude of the oscillation is +0.10 m, as shown in snapshots A and E.
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Question 4 of 20
Planets A and B have the same size, mass, and direction of travel, but planet
A is traveling through space at half the speed of planet B. Which statement
correctly explains the weight you would experience on each planet?
OA. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
B. You would weigh the same on both planets because your mass
would adjust depending on the planet's speed.
OC. You would weigh more on planet B because it is traveling twice as
fast as planet A.
OD. You would weigh less on planet B because it is traveling twice as
fast as planet A.
SUBMIT
On two planets with the same size, mass, and direction of travel, your weight will be the same on both planets. Option A.
Weight of objects on different planetsThe weight of an object depends on its mass and the strength of the gravitational force acting on it.
Since planets A and B have the same size and mass, their gravitational forces will be the same. Therefore, an object placed on either planet will experience the same gravitational force and hence the same weight.
The speed of the planets has no effect on the weight of an object on them. Therefore, options (B), (C), and (D) are incorrect.
In other words, you would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.
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which type of electromagnetic wave has more energy than ultraviolet waves?
A Visible light
B Infrared
C Microwaves
D X-rays
Answer:
D. X-rays have more energy than ultraviolet waves.
Gerry max does great effort to stay awake studying all night long. he decides to make a cup of coffee by first placing a 200W electric immersion heater in 0.32kg of water. How much energy is needed to totally vaporize the water being heated
After considering all the given data we conclude that the the amount of energy needed to vaporize the water completely is 722.24 kJ.
The energy needed to vaporize water is reffered to as the heat of vaporization. The heat of vaporization of water is 2257 kJ/kg³.
Here we have to apply the principles of vaporization to derive a formula to evaluate the energy needed to vaporize 0.32 kg of water,
Then
Energy = Heat of vaporization x Mass of water
Energy = 2257 kJ/kg x 0.32 kg
Energy = 722.24 kJ
Then, the energy needed to totally vaporize the water being heated is 722.24 kJ.
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Using atleast 4 sentences. Please share three facts you have learned this year in Physical Education and how you will adapt what you have learned to your everyday life.
Three facts I have learned this year in Physical Education are:
a) The importance of stretching before and after exercising.
b) The benefits of cardiovascular exercise.
c) The importance of staying hydrated during exercise.
Firstly, I have learned the importance of stretching before and after exercising. Stretching helps prevent injury and improves flexibility. I will make sure to incorporate stretching into my daily routine, whether it's through a short stretching session in the morning or by taking a few minutes to stretch before and after a workout.
Secondly, I have learned the benefits of cardiovascular exercise. Cardiovascular exercise, such as running or cycling, helps improve heart health and endurance. I will try to incorporate more cardiovascular exercise into my daily routine, such as going for a run or bike ride after work.
Lastly, I have learned the importance of staying hydrated during exercise. Dehydration can lead to fatigue and muscle cramps, so it's important to drink plenty of water before, during, and after exercise. I will make sure to carry a water bottle with me throughout the day and refill it regularly to ensure that I am staying hydrated.
In summary, by incorporating stretching, cardiovascular exercise, and staying hydrated into my daily routine, I hope to improve my overall physical health and well-being.
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lodine trichloride, IC13, is made by reacting iodine with chlorine.
12(s) + Cl2(g) → 2IC(s); AH = +14kJ mol¹
ICl(s) + Cl2(g) → IC¹(s); AH = −88 kJ mol-¹
By using the data above, what is the enthalpy change of the formation for solid iodine trichloride?
The enthalpy change of the formation for solid iodine trichloride is -74 kJ/mol. This indicates that the formation of solid iodine trichloride is exothermic
The enthalpy change of the formation for solid iodine trichloride (ICl3) can be calculated using Hess's law, which states that the total enthalpy change of a chemical reaction is independent of the route by which the reaction occurs.
First, we need to write the balanced chemical equation for the formation of solid ICl3 from its elements:
I2(s) + 3Cl2(g) → 2ICl3(s)
According to Hess's law, the enthalpy change of this reaction is equal to the sum of the enthalpy changes of the following two reactions:
I2(s) + Cl2(g) → 2ICl(g) ΔH1
ICl(g) + Cl2(g) → ICl3(s) ΔH2
where ΔH1 is the enthalpy change for the reaction between iodine and chlorine to form gaseous iodine trichloride, and ΔH2 is the enthalpy change for the condensation of gaseous iodine trichloride to form solid iodine trichloride.
The enthalpy change for the first reaction is given as ΔH1 = +14 kJ/mol, and the enthalpy change for the second reaction is given as ΔH2 = -88 kJ/mol. Therefore, the enthalpy change of the formation for solid iodine trichloride can be calculated as:
ΔHf°(ICl3,s) = ΔH1 + ΔH2
= (+14 kJ/mol) + (-88 kJ/mol)
= -74 kJ/mol
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0% OF PEOPLE HAVE ANSWERED THIS CORRECTLY
Particles q1= -66.3 μC, q2 = +108 μC, and q3 = -43.2 μC are in a line. Particles q1 and q2 are separated by 0.550 m and particles q2 and q3 are separated by 0.550 m. What is the net force on particle q2?
Remember:
Negative forces (-F) will point Left
Positive forces (+F) will point Right
Will mark brainliest IF answer is correct.
Refer to the attached images.
The force between two charged particles can be calculated using Coulomb's Law:
[tex]F = (k * |q1 * q2|) / r^2[/tex]
F is the force, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the particles, and r is the separation distance between them.
For q1 and q2:
[tex]F1 = (k * |q1 * q2|) / r1^2\\= (8.99 x 10^9 N m^2/C^2) * (66.3 x 10^-{6} C) * (108 x 10^{-6 }C) / (0.550 m)^2[/tex]
For q2 and q3:
[tex]F2 = (k * |q2 * q3|) / r2^2\\= (8.99 x 10^9 N m^2/C^2) * (108 x 10^{-6} C) * (43.2 x 10^{-6} C) / (0.550 m)^2[/tex]
The net force on q2 is the vector sum of F1 and F2:
Net Force = F2 - F1
By calculating these values, we can determine the net force on particle q2.
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Calculate the height (in m) of a cliff if it takes 2.37 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.03 m/s. (Enter a number.)
(b)
How long (in s) would it take to reach the ground if it is thrown straight down with the same speed? (Enter a number.)
A) The height of the cliff is approximately 18.93 meters if it takes 2.37 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.03 m/s.
B) It would take approximately 1.63 seconds for the rock to hit the ground if it is thrown straight down with the same speed.
A) To calculate the height of the cliff, we can use the kinematic equation:
h = vi*t + (1/2)at^2
where h is the height of the cliff, vi is the initial velocity, t is the time taken, and a is the acceleration due to gravity (-9.8 m/s^2).
Substituting the given values, we get:
h = 8.032.37 + (1/2)(-9.8)*(2.37)^2
h = 18.93 meters
Therefore, the height of the cliff is approximately 18.93 meters.
B) To determine how long it would take for the rock to reach the ground if it is thrown straight down with the same speed, we can use the same kinematic equation, but with a negative initial velocity:
h = vi*t + (1/2)at^2
where vi is now -8.03 m/s.
Substituting the values, we get:
0 = -8.03t + (1/2)(-9.8)*t^2
Solving for t, we get:
t = 1.63 seconds
Therefore, it would take approximately 1.63 seconds for the rock to hit the ground if it is thrown straight down with the same speed.
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Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air?
Answer:
Two tuning forks with frequencies of 256 Hz and 512 Hz are struck. Which of the sounds will move faster through the air? Neither, the speed of sound is constant in air.
