Answer:
You are putting more force on the ball no the racket so the racket wouldnt swing back but if you hit a racket on the ground it will swing backits just the way the force reaction works
Explanation:
^^^^^^^^^^^^^^^
The racket wouldn't swing back because you were applying more power to the ball than to the racket, so the racquet swings backward when the ball hits it.
What is force?Any action that aims to maintain, modify, or deform a body's motion is considered a force in mechanics. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force (1687).
According to Newton's third law, whenever one body applies force to another, the second body also applies an equal amount of force to the first body. The action-reaction concept explains why a force tends to cause a body to deform, or change shape, whether it moves the body.
The racket wouldn't swing back because you were applying more power to the ball than to the racket, but it would if you struck the racket on the ground; that's how the force reaction operates.
Therefore, the racquet swings backward when the ball hits it.
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a delivery van has a mass of 7000 kg and a kinetic energy of 31,500 J. what is it’s speed
Answer:
The answer is
3 m/sExplanation:
The speed of an object given it's kinetic energy and mass can be found by using the formula
[tex]v = \sqrt{ \frac{2KE}{m} } [/tex]
where
KE is the kinetic energy
m is the mass
v is the speed
From the question
KE = 31,500 J
m = 7000 kg
The speed is
[tex]v = \sqrt{ \frac{2(31500)}{7000} } \\ = \sqrt{ \frac{63000}{7000} } \\ = \sqrt{ \frac{63}{7} } \\ = \sqrt{9} \: \: \: \\ = 3 \: \: \: \: \: \: \: [/tex]
We have the final answer as
3 m/sHope this helps you
50 points =) The morning after a massive snowstorm, Michaela gets into her car to drive to work. The storm caused her windows to freeze, so she first needs to defrost the car. While the engine is running, she checks the thermometer. It shows the air inside of her car has a temperature of 0 °C. Does this mean the air inside of her car has no kinetic energy? Explain your answer.
Answer:
YES!
THE AIR INSIDE A CAR THE AIR RESISTANCE WILL CONVERT SOME OF THE KINETIC ENERGY FROM THE CAR INTO THE KINETIC ENERGY IN THE AIR AS IT'S PUSHED AWAY FROM THE FRONT OF THE CAR AND SUCKED BACK INTO THE GAP BEHIND IT.this TOO DEGRADES INTO HEAT.PLEASE I NEED A BRAINLIEST
Give an example of each type of electromagnetic radiation.
Answer:
Nearly all frequencies and wavelengths of electromagnetic radiation can be used for spectroscopy. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.
Explanation:
Lesley doesn't like having to wait for other people to
A person is driving down a country lane at 25 m/s, when a deer suddenly jumps in front of the car. The deer is 75 m ahead and when the driver hits the brakes, the car slows at a rate of 4.20 m/s each second. Does the car hit the deer?
Answer:
The car does not hit the deer.
Explanation:
In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.
2as = Vf² - Vi²
where,
s = distance covered by car before stopping = ?
a = deceleration of car = - 4.2 m/s²
Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)
Vi = Initial Velocity of the Car = 25 m/s
Therefore,
2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²
s = (- 625 m²/s²)/(-8.4 m/s²)
s = 74.4 m
So, the car stops in 74.4 m, while the deer is at a distance of 75 m.
Hence, the car does not hit the deer.
Using third equation of kinematics
[tex]\boxed{\sf v^2-u^2=2as}[/tex]
[tex]\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s[/tex]
[tex]\\ \sf\longmapsto -625=-8.4s[/tex]
[tex]\\ \sf\longmapsto 8.4s=625[/tex]
[tex]\\ \sf\longmapsto s=\dfrac{625}{8.4}[/tex]
[tex]\\ \sf\longmapsto s=74.4m[/tex]
AS IT IS LESS THAN 75M HENCE CAR DOESNOT HIT THE DEAR.Suppose you wish to whirl a pail full of water in a vertical circle without spilling any of its contents. If your arm is 0.82 m long (from shoulder to fist) and the distance from the handle to the surface of the water is 18.5 cm, what minimum speed is required?
Answer:
Approximately [tex]3.1\; \rm m \cdot s^{-1}[/tex].
Explanation:
The content of this pail is in a centripetal motion because its path forms part of a vertical circle. Let [tex]m[/tex] denote the mass of the contents of this pail, let [tex]v[/tex] denote the (linear) velocity of the content, and let [tex]r[/tex] denote the radius of this circle. The net force on the contents of this pail will thus be:
[tex]\displaystyle F(\text{net}) = \frac{m\, v^2}{r}[/tex] towards the center of the circle.
Assume that there is no friction between the content and walls of the pail. The only two possible forces on the contents pail towards the center would be:
The downwards gravitational pull from the earth, Normal force between walls of the pail and the contents (except at the top and bottom of the circle,) andIf the rotation is fast enough, the normal force from the bottom of the pail, which also points downwards.Note that at the top of the circle, both the gravitational pull and the normal force from the bottom point towards the center of the circle. On the other hand, the normal force from the walls of the pail would be perpendicular to the line towards the center of the circle. At that point in the circle, there's no upward force to support the content of the pail. The uniform rotation will be sufficiently fast if it could allow the content to stay in the pail at the top of the circle.
Let [tex]g[/tex] denote the gravitational field strength at the top of this circle. The size of the gravitational pull on the content would be [tex]m\cdot g[/tex]. Let [tex]F(\text{normal})[/tex] denote the normal force from the bottom of the pail on the contents. The sum of these two forces should be equal to the vertical net force on the contents of this pail. That is:
[tex]F(\text{net}) = m\cdot g + F(\text{normal})[/tex].
From the centripetal motion of the content:
[tex]\displaystyle \frac{m\, v^2}{r} = m\cdot g + F(\text{normal})[/tex].
Rearrange to obtain an expression for the normal force:
[tex]\displaystyle F(\text{normal}) = \frac{m\, v^2}{r} - m\cdot g[/tex].
Note, that the normal force the bottom of the pail exerts on the contents should be greater than or equal to zero. While the pail is at the top of the circle, the normal force from the bottom of the pail cannot pull the contents upwards. Hence:
[tex]\displaystyle \frac{m\, v^2}{r} - m\cdot g = F(\text{normal}) \ge 0[/tex].
[tex]\displaystyle \frac{m\, v^2}{r} - m\cdot g \ge 0[/tex].
Rearrange and simplify to obtain:
[tex]\displaystyle \frac{v^2}{r} - g \ge 0[/tex].
[tex]v^2 \ge g\cdot r[/tex].
[tex]v \ge \sqrt{g \cdot r}[/tex].
In other words, if the gravitational field strength is [tex]g[/tex] and the radius of the circle is [tex]r[/tex], the minimum linear velocity required to keep the content in the pail at the top of the circle is [tex]\sqrt{g \cdot r}[/tex].
If [tex]g = 9.81\; \rm N \cdot kg^{-1} = 9.81\; \rm m \cdot s^{-2}[/tex] and [tex]r = 0.82 \; \rm m + 0.185\; \rm m \approx 1.005\; \rm m[/tex], then the minimum value of [tex]v[/tex] would be approximately:
[tex]\sqrt{9.81 \; \rm m \cdot s^{-1} \times 1.005\; \rm m} \approx 3.1\; \rm m \cdot s^{-1}[/tex].
Lucy took 3 hours to cover 2/3 of a journey. She covered the remaining 60 miles in 2 hours. What was the average speed for the whole journey?
The correct answer is 36 miles per hour
Explanation:
To find the average speed, the first step is to find the total time and the total distance Lucy covered because the formula for average speed is the total distance divided into the total time.
Total Distance
It is known Lucy covered 2/3 of the total distance first, and then she completed the remaining distance (60 miles). According to this, the last distance or 60 miles represents 1/3 of the total distance.
[tex]\frac{2}{3} + \frac{1}{3} = \frac{3}{3}[/tex] (Total distance)
Also, if 60 miles is equivalent to 1/3 this number can be used to find the total distance. In this case, just multiply 60 by 3 = 180 miles as 60 is one-third.
This means the total distance is 180 miles
Total Time
It is known the first part of this journey took 3 hours and the second took 2 hours. This means the total time was 5 hours (3 + 2 = 5)
Find the average speed
[tex]Average speed =\frac{Distance}{time}[/tex]
[tex]Average speed = \frac{180 m}{5 h}[/tex]
[tex]Average speed = 36m/h[/tex]
Determine the velocity vector of the given path. c(t)=6ti+((3t)^2)j+((t)^3)k
Explanation:
Given,
Position vector, [tex]c(t)=6ti+((3t)^2)j+((t)^3)k[/tex]
We need to find the velocity vector of the given path
[tex]v=\dfrac{d(c(t))}{dt}\\\\v=\dfrac{d(6ti+((3t)^2)j+((t)^3)k)}{dt}\\\\v=\dfrac{d(6ti)}{dt}+\dfrac{d((3t)^2j}{dt}+\dfrac{d(t^3)k}{dt}\\\\v=6i+18tj+3t^2k[/tex]
Hence, this is the velocity vector of the given path.
If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d = A + Bt^2, the SI units of A and B must be:_______
Answer:
The SI units of the “A” is m (meters)
The SI units of the “B” is m/s^2
Explanation:
Given the distance = d meters.
Time taken to travel = t (seconds)
Function of the distance, d = A + Bt^2
Now we have given the above information and from the given distance function, we have to find the SI units of the A and B. Here, below are the SI units.
Thus, the SI units of the “A” is = m (meters)
The SI units of the “B” is = m/s^2
a car speeds up from 8.50 m/s to 22.2 m/s in 3.84 s. what is the acceleration of the car
Answer:
3.57
Explanation:
22.2-8.50=13.7
13.7/3.84=3.57
Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.
A train accelerated from 10km/hr to 40km/hr in 2 minutes. How much distance does it cover in this period? Assume that the tracks are straight?
A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging swing upward l an arc. Determine the vertical and horizontal components of the pendulum's maximum displacement.
Answer:
V = 0.15m
H = 0.85m
Explanation:
We will be using the conservation of momentum to solve the problem.
m(i).v(i) = m(f).v(f) where
0.028 * 190 = 3.1 * v(f)
v(f) = 5.32/3.1
v(f) = 1.72 m/s
next, we use the conservation of energy to find the vertical displacement.
½mv² = mgh
½v² = gh, making h the subject of formula, we have
h = v²/2g
h = 1.72²/ 2 * 9.81
h = 2.9584 / 19.62
h = 0.15 m
The height, h is the vertical displacement.
Next, we find the angle of the pendulum at the top of the swing.
Φ = cos^-1 [(2.5 - 0.15)/2.5] *the height at which the pendulum is hanging is not given, so I assumed it to be 2.5m, yo can substitute that for whatever it is
Φ = cos^-1(2.35/2.5)
Φ = cos^-1 (0.94)
Φ = 19.95°
This gotten angle is used to find the horizontal displacement
x = 2.5 sinΦ
x = 2.5 sin 19.95
x = 2.5 * 0.34
x = 0.85 m
Galileo's telescopes were not of high quality by modern standards. He was able to see the moons of Jupiter, but he never reported seeing features on Mars. Use the small-angle formula to find the angular diameter of Mars when it is closest to Earth. How does that compare with the maximum angular diameter of Jupiter? (Assume circular orbits with radii equal to the average distance from the sun.)
Answer:
Angular diameter of Mars = 15.80 * 10^5 arc seconds
The Angular diameter of Mars is 3 times the angular diameter of Jupiter
Explanation:
Average distance of the earth from sun = 150.67 * 10^6 km
assuming the radius of Mars ( average distance from sun) = 209.33 * 10^6 km
assuming the radius of Jupiter(average distance from sun) = 768.71 * 10^6 km
The small-angle formula for mars
angular diameter = ( linear diameter / distance ) * (2.06 * 10^5 )
distance between earth and mars = 54.6 * 10^6 km
linear diameter = 2 * radius = 418.66 * 10^6 km
angular diameter = ( 418.66 / 54.6 ) * 2.06 * 10^5
= 15.80 * 10^5 arc seconds
small angel formula for Jupiter
Angular diameter = ( linear diameter / distance ) * (2.06 * 10^5)
distance between Jupiter and earth = 588 * 10^6 km
linear diameter = 2 * radius = 1537.42 * 10^6 km
Angular diameter = ( 1537.42 / 588) * 2.06*10^5
= 5.39 * 10^5 arc seconds
comparing the angular diameter of the Mars and that of Jupiter :
The angular diameter of mars / angular diameter of Jupiter
= 15.80 / 5.39 = 2.931 ≈ 3
What is the velocity of a plane that traveled 1500 miles from New York City to Orlando in 10.0 hours?
Answer:
v = (1500/10) = 150 [miles/h]
Explanation:
The velocity can be easily calculated using the following kinematics expression:
v = x/t
where:
v = velocity [miles/h]
t = time = 10 [hr]
x = distance = 1500 [miles]
v = (1500/10) = 150 [miles/h]
A certain ultrasound device can measure a fetal heart rate as low as 50 beats per minute. This corresponds to the surface of the heart moving at about 4.0 x 10-4 m/s. If the probe generates ultrasound that has a frequency of 2.0 MHz (1 MHz = 1 megahertz = 106 Hz), what frequency shift must the machine be able to detect
Answer:
The. Machine must detect a shift of
1 Hz
Explanation:
Frequency shift is given as
={ ( Vsound +V/ V sound -V) -1}f emitted
So by substitution we have
= { 1540+4E-4/1540-4E)-1) 2*10^6
= 1Hz
An observer in frame S sees lightning simultaneously strike two points 100 m apart. The first strike occurs at xx1 = yy1 = zz1 = tt1 = 0 and the second at xx2 = 100 mm, yy2 = zz2 = tt2 = 0. (a) What are the coordinates of these two events in a frame S’ moving in the standard configuration (motion along the common xx − xx’ axis) at 0.70c relative to S? (b) How far apart are the events in S’? (c) Are the events simultaneous in S’? If not, what is the difference in time between the events, and which event occurs first?
Answer:
a) 0, = -0.33 us
b) 140m
c) No, The event are not simultaneous i.e they did not occur at the same time, the second even (-0.33 usec) occurs 0.33 usec earlier than the first event.
Explanation:
a)
the lorentz factor expression is written as;
y = 1₀ / √(1 - (v²/c²))
where v is the relative speed of an observer and c is the speed of light
so we were given that relative speed to be o.7c
therefore
y = 1 / √(1 - ((0.7c)² / c²))
y = 1 / √(1 - (0.49c² / c²))
y = 1 / √(1 - 0.49)
y = 1 / 0.7141
y = 1.4
1 - the coordinates of the first event, the s' frame of reference is,
x1 ' = y(x1 - vt1) = 0
y1 ' = y1, z1' = z1 and
t1 ' = y [t1 - v/c²x1]
= 0
2 - the coordinates of the second event, the s ' frame of reference is'
x2 ' = y(x2-vt2)
= 1.4(100m - 0)
= 140m
y2 ' = y2, z2 ' = z2
t2 ' = y [ t2 - v/c²x2 ]
= 1.4 [ 0 - 0.7c/c²(100) ]
using speed of light c as 3*10^8
1.4 [ 0 - (0.7*3*10^8) / (3*10^8)²(100) ]
= -0.33 us
b)
distance between
delltaX' = X2' - X1'
= 140m - 0
= 140m
c)
No, The event are not simultaneous i.e they did not occur at the same time.
the second even (-0.33 us) occurs 0.33 us earlier than the first event.
A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
Answer:
57.0 m
Explanation:
Assume the time it takes for the sound to reach the top of the well is negligible.
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 3.41 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²
Δy = 57.0 m
Answer:
57 m
Explanation:
What is the difference between mass and weight?
A) Mass measures the force of gravity and weight measures volume.
B) Mass is measured in metric units and weight is measured in US Standard System.
C) Mass measures amount of matter in an object and weight measures the force of gravity.
D) Mass measures volume and weight measures the force of gravity.
Answer:
C. Mass is independent of the force acting on the mass.
Weight depends on the gravitational force acting on the mass.
Example: A mass of 1 kg on the earth still has a mass of 1 kg on the moon;
whereas the weight of that mass on earth is 9.8 N and only 1/6 of that amount on the moon.
A force vector points due east and has a magnitude of 140 newtons. A second force is added to . The resultant of the two vectors has a magnitude of 420 newtons and points along the (a) east/ (b) west line. Find the magnitude and direction of . Note that there are two answers. (a) Number newtons (b) Number newtons
Answer:
(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East
(b) When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West
Explanation:
Given;
a force vector points due east, [tex]F_1[/tex] = 140 N
let the second force = [tex]F_2[/tex]
let the resultant of the two vectors = F
(a) When the resultant force is pointing along east line
the second force must be pointing due east
[tex]F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N[/tex]
[tex]F_2 = 280 \ East[/tex]
(b) When the resultant force is pointing along west line
the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.
[tex]F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N[/tex]
[tex]F_2 = 560 \ West[/tex]
How long would it take for Sofia to walk 300 meters if she is walking at a velocity of 2.5 m/s?
Answer:
Time=120seconds
Explanation:
S=300m
V=2.5m/s
t=?
V=S/t
t=S/V
t=300/2.5
t=120 second
Answer:
120 seconds
Explanation:
.....
...
.....
Convert 47 meters to gigameters
Answer: 4.7× 10-8 gigameter.
Exgiga meter. Hope this helps :)
A truck moving at 13.3 m/s hits a concrete wall. As a result of the collision, a 6-kg wrench moves forwards and strikes the wall of the tool compartment. If the wrench stops after being in contact with the wall for 0.07 s, what is the average force exerted on the wrench by the wall
Answer:
Explanation:
The velocity of the wrench must be equal to the velocity of the truck . So momentum of the wrench before it hits the wall
= mv = 6 x 13.3 = 79.8 kg m /s
If resisting force of wall be F , impulse on the wrench = F x time
= F x .07
Impulse = change in momentum of the wrench = mv - 0 = mv = 79.8 kgm/s
So F x .07 = 79.8
F = 1140 N .
The amount of space between two points is measure in unit?
The measurement of distance is the length between two places. To measure is to establish the distance between two geometric objects. With a ruler, you can measure distance the most frequently. Ordinarily, eighth-inch (or 0.125 in) segments make up inch rulers.
What space between two points is the measure unit?When calculating the distance to stars, many astronomers choose to use parsecs (abbreviated pc). This is due to the definition's tight connection to a technique for determining the separation between stars. The distance at which 1 AU subtends an angle of 1 arc sec is measured in parsecs.
A unit of measurement is a specific magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.
Therefore, Any additional amount of that type can be stated as a multiple of the measurement.
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A cruise ship sails due south at 2.50 m/s while a coast guard patrol boat heads 19.0° north of west at 4.80 m/s. What are the x-component and y-component of the velocity of the cruise ship relative to the patrol boat? (Assume that the +x-axis is east and the +y-axis is north. Enter your answers in m/s.)
Answer:
Explanation:
We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .
velocity of cruise ship
Vcs = - 2.5 j
Vpb = - 4.8 cos 19 i + 4.8 sin 19 j = - 4.54 i + 1.56 j
velocity of the cruise ship relative to the patrol boat
= Vcs - Vpb
= - 2.5 j - ( - 4.54 i + 1.56 j )
= - 2.5 j + 4.54 i - 1.56 j
= 2.04 i - 1.56 j .
x-component of the velocity of the cruise ship relative to the patrol boat
= 2.04 m /s
y-component of the velocity of the cruise ship relative to the patrol boat
= - 1.56 m /s .
Which of the following is NOT an important part of exercise clothing? A belts B. shoes C. shirts D. socks
Answer:
BELTS
Explanation:
why would you need belts for running and stuff
Belts are not an important part of exercise clothing.
What is exercise?An exercise is a physical activity performed to increase strength and agility of the muscles as well as to enhance fitness.
During an exercise, it is important to wear clothes that will not hinder movement or cause injury.
Some items of clothing needed in exercise include:
shoes shirts socksTherefore, belts are not important during exercise.
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A piston-cylinder device containing a fluid is fitted with a paddle wheel stirring device operated by the fall of an external weight of mass 51kg. As the mass drops by a height of 5.6m, the paddle wheel makes 10100 revolutions. Meanwhile the free moving piston (frictionless and weightless) of 0.51m diameter moves out by a distance of 0.71m. Determine the net work for the system if atmospheric pressure is 101 kPa.
Answer:
The value is [tex]W_N = 11849 \ J [/tex]
Explanation:
From the question we are told that
The mass of the external weight is [tex]m = 51 \ kg[/tex]
The height through which the mass drops is [tex]h = 5.6 \ m[/tex]
The number of revolution made is [tex]N = 10100 \ kg[/tex]
The diameter of the free moving piston is [tex]d = 0.51 \ m \ kg[/tex]
The distance moved by the free moving piston is [tex]s = 0.71 \ m \ kg[/tex]
The atmospheric pressure is [tex]P = 101 \ kPa = 101*10^{3}\ Pa [/tex]
Generally the workdone by the external weight is mathematically represented as
[tex]W_w =m * g * h[/tex]
= [tex] 51 * 9.8 * 5.6 [/tex]
= [tex]2799 N [/tex]
Generally the workdone by the free moving piston is mathematically represented as
[tex]W_p =P * A * s[/tex]
Here A is the cross-sectional area with value
[tex] A = \pi * \frac{d^2}{4}[/tex]
[tex] A = 3.142 * \frac{0.51^2}{4}[/tex]
So
[tex]W_p =101*10^{3} * 3.142 * \frac{0.51^2}{4} * 0.71[/tex]
=> [tex]W_p = 14651 [/tex]
So
The net workdone is mathematically evaluated as
[tex]W_N = -W_w+W_p [/tex]
The negative sign shows that it is acting in opposite direction to [tex]W_N[/tex]
So
[tex]W_N = -2799+14651 [/tex]
[tex]W_N = 11849 \ J [/tex]
Consider a thin circular disk that has been heated up to 400 °C and then left inside a chamber to cool down. The chamber surface is kept at 40 °C and the air inside is maintained at 25 °C. Assume that the disk is held at the center of the chamber, and we can ignore heat conduction effects in this problem. The disk surface property is known as ε=0.65. For the diameter of D=200 mm, what is the total rate of heat transferfrom the disk?
Answer:
hello your question lacks the required diagram attached below is the complete question with the required diagram
answer : Qtotal = 807.4 Mw
Explanation:
Given Data :
disk properties :
∈ = 0.65
D = 200 mm
Ts = 400⁰c
attached below is the detailed solution
The total rate of Heat transferred from the disk
Qtotal = 807.4 Mw
A neutral atom of sodium has 12 neutrons and 11 protons. How many electrons does this sodium have? a.1 b.11 c.12 d.23
Answer:
We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass)
The most common type of mirage is an illusion that light from faraway objects seem to be reflected by a pool of water that is not really there. Mirages are generally observed in deserts, when there is a hot layer of air near the ground. The index of refraction of air is lower at higher temperature. What physical phenomena explains how mirages are formed? Give a brief explanation of the phenomena as your LPE.
Answer:
Mirage is an optical illusion due to the refraction of light as it travels through different layers of air at different temperature.
Explanation:
On a clear hot afternoon, the sun heats up the ground, and the ground heats up the air immediately above it. The result is that the air directly above the ground is hotter than the air above it, leaving the air layers with different refractive indies. Since refractive index decreases with increase in temperature, the air immediately above the ground bends the light that travels through it from the sky, directly into our eyes. The image seen is perceived to be reflected from the ground, but in an actual sense is a direct image of the sky, giving one the impression of seeing a pool of water on the ground.
What is the weight in newtons of lily’s convertible, which has a mass of 1800 kg?
Answer:
Explanation:
W=?
Mass=1800kg
g=(9.8m/s^2 constant)
W=mg
W=1800*9.8
W=17649N
