A thin 2.00-m string of mass 50.0 g is fixed at both ends and under a tension of 70.0 n. if it is set into small-amplitude oscillation, what is the frequency of the first harmonic mode?

Answer:

Independent variable is the variable that causes the changes in the experiment. Dependent variable is the variable that is affected by the changes.

Explanation:

C. The launch angle that would result in the same range if the launch speed is kept the same is 75⁰.

The angle of projection is calculated as follows;

R = u²sin(2θ) / g

where;

θ = 15⁰

sin 2θ = sin 2(15) = sin (30) = 0.5

θ = 90⁰ - 15⁰ = 75⁰

sin(2θ) = sin (2 x 75⁰) = sin (150⁰) = 0.5

Thus, the launch angle that would result in the same range if the launch speed is kept the same is 75⁰.

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The time taken for the object to fall the same distance in planet X is determined as 8.5 seconds.

The time taken for the object to fall the same distance on planet X is calculated as follows;

t = √2h/g

where;

t² = 2h/g

gt² = 2h

g₁t₁² = g₂t₂²

t₂² = g₁t₁²/g₂

t₂² = (g₁ x 3.8²) / (0.2g₁)

not e one-fifth = 1/5 = 0.2

t₂² = 72.2

t₂ = √72.2

t₂ = 8.5 seconds

Thus, time taken for the object to fall the same distance in planet X is determined as 8.5 seconds.

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The acceleration of the car after leaving the pit to reach a speed of 75 m / s in 9 s is 8.3 m / s²

a = v / t

a = Acceleration

v= Velocity

t = Time

v = 75 m / s

t = 9 s

a = 75 / 9

a = 8.3 m / s²

Acceleration is the rate of change of velocity with respect to time. It is denoted as a.

The given question is incomplete. The complete question is:

At an international auto race, a race car leaves the pit after a refueling stop and accelerates uniformly to a speed of 75 m/s in 9 s to rejoin the race. What is the race car's acceleration during this time?

Therefore, the acceleration of the car after leaving the pit is 8.3 m / s²

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0.125 kg

Explanation:

Acceleration of a ball rolling down hill, a = 3.5 m/s².

Given in details,

Initial velocity of ball,

u = 3 m/s

Final velocity of ball,

v = 34.5 m/s

Time taken for changing velocity,

t = 9 s

To find acceleration of ball,

a =?

Using formula,

First equation of motion

 v = u + a t

where,

v is final velocity,

u is initial velocity,

t is time taken

a is acceleration

Using this first equation of motion,

v = u + a t

34.5 = 3 + a × 9

34.5 - 3 = 9 a

31.5 = 9 a

a = 31.5 / 9

a = 3.5 m/s²

Newton's first law: the law of inertia

According to Newton's first law, if a body is at rest or moving in a straight line at a constant speed, it will continue to move at that speed or remain at rest until acted upon by a force.

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The transformer secondary turns should be 83 turns.

We need to know about the transformer to solve this problem. Transformer is a device that can increase or reduce the voltage. The changed voltage depends on the current and number of coil turns. It can be written as

Vi / Vs = Ni / Ns = Is / Ii

where Vi is input voltage, Vs is output voltage, Ni is primary turn, Ns is secondary turn, Is i output current and Ii is input current.

From the question above, we know that

Vi = 120 V

Ni = 1000 turns

Vs = 10V

By substituting the following parameters, we can calculate the secondary turns

Vi / Vs = Ni / Ns

120 / 10 = 1000 / Ns

Ns = 1000 / 12

Ns = 83 turns

Hence, the transformer secondary turns should be 83 turns.

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The energy absorbed outdoor copper sculpture heats up during the day q = 1.79 x 10⁵ J.

To find energy using formula,

q = mcΔT

where,

q is energy

m is mass

c is specific heat

ΔT is change in temperature

Given,

m = 7.8 kg

c = 390 J/kg

T₁ =  28°C

T₂ = 87°C

To find ΔT,

ΔT = T₂ - T₁

ΔT = 87° - 28°

ΔT = 59°C

Now, putting values,

q = mcΔT

q = 7.8 kg x 390 J/kg x 59

q = 1.79 x 10⁵ J

The best materials for sculpture are copper and copper alloys for a variety of reasons. They offer countless artistic possibilities because they can be molded into any desired shape. Copper components can be mechanically joined or assembled by bolting or bonded by welding, enabling works of enormous size.

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Charge,Q = 6.48 × [tex]10^-^9[/tex] C

It is given that,

Electric field strength, E = 180000 N/C

Distance from a small object, r = 1.8 cm = 0.018 m

Electric field at a point is given by :

[tex]E=\frac{KQ}{r^2}[/tex]

Q is the charge on an object

[tex]Q=\frac{Er^2}{k}[/tex]

Q = [180000 × [tex](0.018)^2[/tex]] ÷ 9 × [tex]10^9[/tex]

Q = 6.48 × [tex]10^-^9[/tex] C

So, the charge on the object is Q = 6.48 × [tex]10^-^9[/tex] C . Hence, this is the required solution.

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Explanation:

interesting let's see it is very confusing

Answer:

See below

Explanation:

Motion as the change of position of an object with respect to time.

Uniform motion covers equal distance at an equal time interval. The velocity is constant. For example, a car traveling at 55 mph constant speed for 2 hours has uniform motion

Non-uniform motion covers unequal distance at equal time intervals. For example, in heavy traffic, a car may travel at 20mph for the first 10 minutes, then 10mph for the next 10 minutes etc. Thus velocity changes over equal time periods

A boolean variable with the value "true" or "false" is what is referred to as a "flag" variable. You can either use an integer value with zero for "false" and semi for "true" or the boolean type with true or false.

CY is the carry flag's symbol. If a carry is produced during the procedure, it will be set to 1.

The procedure's outcome would be:

54 + C4 = 01010100 + 11000100

= 100011000

however because it cannot fit into the 8-bit destination register, the top bit is lost, and the actual result is 0x000110.

As a result, we can see that a carry is produced. CY will therefore equal 1.

The registers will be updated with the hexadecimal integers.

As a result, we can observe that no carry is produced. CY will therefore equal 0.

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The Law of Universal Gravitation,  states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Newton's law of gravitation, states that any particle of matter in the universe draws another with pressure varying at once as the manufactured from the loads and inversely as the rectangular.

Newton, the pressure of gravity appearing between the earth and another item is at once proportional to the mass of the earth, directly proportional to the mass of the item, and inversely proportional to the square of the distance that separates the centers of the earth and the item. Gravitational steady, G is unbiased of the nature of the particle, medium among the debris, and time. Its cost is constant anywhere within the Universe.

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Answer:

6 Newton.

Explanation:

Force (F) = Mass (M) x Acceleration (A).

Force = 2kg x 3 m/s^2

F = 6kg m/s^2 = 6 Newton. = 6N

Therefore, Force required to accelerate the body is 6N

The weight of the combined system = 1,996.3 N

Given,

Mass of the Plastic tank = 3.5 kg

Volume of the liquid water in the tank = 0.2 m³

Density of water = 1000 kg/m³  

Now,

We know

Density = Mass ÷ Volume

Thus,

Mass = Density × Volume

therefore,

Mass of the water in the tank = 1000 × 0.2

= 200 kg

Thus,

The mass of the combined system = 3.5 kg + 200 kg = 203.5 Kg

Also,

Weight in N = Mass × Acceleration due to gravity (g)

and,

g = 9.81 m/s²

Therefore,

The weight of the combined system = 203.5 kg × 9.81 m/s²

= 1,996.3 N

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Dawkins says selection acts on the variations in the populations which are responsible for increasing or decreasing the fitness of the individuals carrying them.

Variation is distributed population following Mendelian genetics. Like the law of independent assortment where variations are transferred independently of each other. When blending inheritance was discarded where traits were thought to be average of that of parents of progeny , which was not the case in many cases.

One example of unconscious selection is the loss of various traits like  loss of natural dispersal mechanisms, even  and rapid seed germination, larger propagules, simultaneous ripening, and loss of mechanical protection as well as changes in the breeding system. This loss or selection on these traits while selecting for other traits like more yield and water efficiency , resistance to diseases etc. This unconscious selection associated with other selection by humans is unconscious.

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The orbit is an ellipse for the space probe that is sent into the orbit around the sun that brings it as close as 0.3 au and as far away as 5.4 au.

Kepler’s 3rd law

According to Kepler’s Third Law, the cubes of the semi-major axes of the orbits of the planets are directly proportional to the squares of the planets’ orbital periods. As an orbiting planet’s radius increases, so does the time of its orbit around the Sun.

T = 2πr3GME Remember that the semi-major axis of an ellipse is equal to the product of the perihelion and the aphelion divided by two. The semi-major axis (a) for a circular orbit is equal to the orbital radius.

P2 = a3, which means that the period of an orbit (P) squared is equal to Kepler’s Third Law.

As per Kepler's law and his explanation of eccentricity,

Eccentricity = Distance to the focus/ Distance to the directrix.

According to Kepler, an elliptical orbit is a Kepler orbit with an eccentricity of less than 1 and for a circular orbit, it is exactly 0 eccentricity.

So here Eccentricity = 0.3/5.4

= 0.055

So according to this, the space probe is moving in an ellipse orbit.

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The big o notation of the worst-case scenario of pushing back an

element into a queue implemented using a list is Array or a Linked list.

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The complexity of your algorithm is O(nm).

Algorithmic complexity is a measure of how long an algorithm would take to complete given an input of size n. If an algorithm has to scale, it should compute the result within a finite and practical time bound even for large values of n. For this reason, complexity is calculated asymptotically as n approaches infinity.

Now,

Text: T

Pattern: s

Algorithm   String Matching(T,s)

n=len(T)

m=len(s)

for i = 0 to n-m

j=0

while j<m and s[j]=T[ i + j]

j=j+1

if j==m

  return i

end if

end while

return -1

end for

the complexity of your algorithm: O(nm)

reason: nested loop runs one run (n-m) times and second run m times. so it becomes (n-m)(m) = (nm-m2) = O(nm)

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14.8m/s is  minimal horizontal velocity must the cliff divers leave the top of the cliff is they are to miss the rock.

Ledge divers in Acapulco leap into the water from a 36-meter-high cliff. A rock protrudes 10.4 meters horizontally from the water, level. 9.8 m/s2 is the acceleration of gravity. If the cliff divers are to miss the rock, they must depart from the top of the cliff with a minimal horizontal velocity.

from above statements, we assume that

there is no initial vertical velocity, then we calculate the time it takes to reach the water, then divide the horizontal distance by that time to get the minimum required horizontal speed.

h=gt^2/2

h= 36 m

t = [tex]\sqrt{2h/g}[/tex]

put h = 36 m g = 9.8 m/s^2

t=2.7 second

Then the minimum required horizontal velocity is

v = d/t

by putting value

v= 10.4 m/2.7 s

v=14.8m/s

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The average velocity of the ball is - 14 m / s if it rolls from x = 10 to x = - 25 in 2.5 seconds.

We know that,

v = Δd / t

where,

v = Average velocity

Δd = Displacement

t = Time taken

Given that,

t = 2.5 sec

Δd = - 25 - 10

Δd = - 35 m

v = - 35 / 2.5

v = - 14 m / s

Average velocity is the average value of velocity from the starting point to ending point in a given amount of time.

Therefore, the average velocity of the ball is - 14 m / s

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By using uniform motion, in 0.04 second the player will spend in the top 13.7cm .

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

hmax = 74.8 cm = 0.748 m

h = 13.7 cm = 0.137 m

g = 9.8 m/s²

Find the initial speed by using hmax (vt = 0 m/s)

vt² = vo² + 2a . s

0² = vo² - 2g . hmax

2 . 9.8 . 0.748 = vo²

vo² = 14.6608

vo = 3.83 m/s

Find the vt when h is 13.7 cm

vt² = vo² + 2a . s

vt² = 3.83² - 2g . h

vt² = 3.83² - 2. 9.8 . 0.137

vt² = 11.98

vt = 3.46 m/s

Find the time taken

vt = vo + a . t

3.46 = 3.83 - g . t

9.8t = 0.37

t = 0.04 second

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The square of the distance has an adverse relationship with the electrical force.

The square of the distance has an adverse relationship with the gravitational force.

The fundamental distinction between electrostatic and gravitational forces is that gravitational force is the force that draws objects to the earth based on mass. This force is conservative. While an object's electrostatic force is its force as a result of charge. Moreover, it is a conservative force.

Electric force is the attractive or repulsive interaction between any two charged bodies. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.

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The magnitude of the acceleration of the ball while it is on the ramp is 2.4 m/s² approximately

Acceleration is the rate at which velocity changes. It is a vector quantity.

Given that a ball is given a brief push and then is allowed to roll up a ramp. It travels 53.1 cm up the ramp before stopping and rolling back down. It takes a total of 1.34 s to roll up and back down to its initial position.

Let us take the account of rolling down.

The magnitude of the acceleration of the ball while it is on the ramp can be calculated by using the below formula

s = ut + 1/2at²

Substitute all the parameters into the formula

0.531 = 0 + 1/2 × a × 0.67²

0.531 = 0.22445a

a = 0.531/0.22445

a = 2.365 m/s²

Therefore, the magnitude of the acceleration of the ball while it is on the ramp is 2.4 m/s² approximately

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150 will be: stratified sample.

The partitioning of a population into smaller subgroups known as strata is a key component of the sampling technique known as stratified random sampling. In stratified random sampling, also known as stratification, the strata are created based on the shared traits or features of the members, such as wealth or level of education. Numerous uses and advantages of stratified random sampling include examining life expectancy and population demography.

Proportional or quota random sampling are other names for stratified random sampling. Researchers can produce a sample population that most accurately represents the whole population under study using stratified random sampling. Sampling is the process of drawing conclusions about a population using a small sample.

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Galileo’s astronomical observations  that were best explained by a heliocentric model is "The phases of Venus can only occur the way they do if Venus is orbiting the Sun".

What about the heliocentric model was accurate?

Instead of Earth, as was previously thought to be the case according to the geocentric model, the heliocentric concept puts the Sun at the core of the solar system. Our increased grasp of astronomy was built on this advancement, which brought us closer to the true nature of the solar system and the universe.

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Since motion under gravity only act on the vertical component of the velocity, the answer for both vertical and horizontal variables are;

a.) 9.8 m/s², 0

b.) 0, 18 m/s

c.) 21.2 m/s, 0

d.) 23 m, 39 m

e.) 2.2 s

Motion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

From the question, the following parameters are given.

a.) The vertical acceleration will be equal to acceleration due to gravity which is equal to 9.8 m/s². While the horizontal acceleration will be equal to zero.

b.) The vertical initial velocity is zero. Vertically, it will be assumed that the stone is dropped. While the given initial velocity is the horizontal initial velocity which is 18 m/s

c.) The vertical final velocity V can be calculated by using the formula

V² = U² + 2gH

V² = 0 + 2 × 9.8 × 23

V² = 450.8

V = √450.8

V = 21.23 m/s

Motion under gravity only act on the vertical component of the velocity. so, horizontal final velocity is equal to zero.

d.) Vertical distance = 23 m

While the horizontal distance = Range = ut

e.) Both the vertical and horizontal time will be the same. We can calculate the time by using the formula

h = ut + 1/2gt²

Vertically, u = 0

23 = 0 + 1/2 × 9.8 × t²

23 = 4.9t²

t² = 23/4.9

t² = 4.694

t = √4.69

t = 2.166 s

t = 2.2 s

so, the range = 18 × 2.166 = 38.997 m

Therefore, the time taken is 2.2 and the range is approximately 39 m.

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The electric potential from proton 52.92 pm from a proton is 27.21 V that is the average distance between the proton and electron.

Electric potential is the effort required to transport a unit charge from one point to another in the presence of an electric field.

Earth is typically chosen as the reference point, but any location outside the range of the electric field charge can be used.

The work required to accelerate a unit positive charge from infinity to a specific point in an electric field is known as the electric potential (or potential) at that location.

Electric potential is the amount of labor or energy that an electric charge can produce. A 1.5 V battery, for instance, has an electric potential of 1.5 volts.

Distance from proton,

r= 52.92pm

= 52.92 x 10^(-12)

Charge on a proton

q = 1.6 x 10^(-19) C

Therefore, electric potential at distance r from a proton is

Vp = Kq/r

=Vp = (9x 10^3 x 1.6 x 10^(-19)) / 52.92 x 10^(-12) volts

Vp = 27.21 V

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It is a physical field occupied by a charged particle on another particle in its surrounding .The magnitude of electric field will be -0.0241 MN/C.

What is electric field?

A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. It can also refer to the physical field surrounding a system of charged particles. Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.

The electric force in an electric field is given by the equation,

 [tex]E = \frac{F}{Q}[/tex]

Since electric field is balanced by the weight of the plastic sphere, the electric force is equal to weight of the sphere.

[tex]F = mg[/tex]

So the equation becomes

[tex]E = \frac{mg}{Q}[/tex]

Putting the value from the question,

m = 0.0074 kg

Q = (-3.0) Nc

g (gravitational acceleration) = 9.8 m/s^2

So, we get

[tex]E = \frac{(9.8)(0.0074)}{(-3.0)}[/tex]

[tex]E = -0.0241 MN/C[/tex]

Hence, the electric field is -0.0241 MN/C.

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