a total journey of 170 miles, in 3 hours, what would be your average velocity? (in miles/hour) *

Explanation:

Given,

Position vector, [tex]c(t)=6ti+((3t)^2)j+((t)^3)k[/tex]

We need to find the velocity vector of the given path

[tex]v=\dfrac{d(c(t))}{dt}\\\\v=\dfrac{d(6ti+((3t)^2)j+((t)^3)k)}{dt}\\\\v=\dfrac{d(6ti)}{dt}+\dfrac{d((3t)^2j}{dt}+\dfrac{d(t^3)k}{dt}\\\\v=6i+18tj+3t^2k[/tex]

Hence, this is the velocity vector of the given path.

Answer:

57.0 m

Explanation:

Assume the time it takes for the sound to reach the top of the well is negligible.

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3.41 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²

Δy = 57.0 m

Answer:

57 m

Explanation:

Answer:

Time=120seconds

Explanation:

S=300m

V=2.5m/s

t=?

V=S/t

t=S/V

t=300/2.5

t=120 second

Answer:

120 seconds

Explanation:

.....

...

.....

Answer:

The answer is

Explanation:

The speed of an object given it's kinetic energy and mass can be found by using the formula

[tex]v = \sqrt{ \frac{2KE}{m} } [/tex]

where

KE is the kinetic energy

m is the mass

v is the speed

From the question

KE = 31,500 J

m = 7000 kg

The speed is

[tex]v = \sqrt{ \frac{2(31500)}{7000} } \\ = \sqrt{ \frac{63000}{7000} } \\ = \sqrt{ \frac{63}{7} } \\ = \sqrt{9} \: \: \: \\ = 3 \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer:

YES!

PLEASE I NEED A BRAINLIEST

Answer:

Mirage is an optical illusion due to the refraction of light as it travels through different layers of air at different temperature.

Explanation:

On a clear hot afternoon, the sun heats up the ground, and the ground heats up the air immediately above it. The result is that the air directly above the ground is hotter than the air above it, leaving the air layers with different refractive indies. Since refractive index decreases with increase in temperature, the air immediately above the ground bends the light that travels through it from the sky, directly into our eyes. The image seen is perceived to be reflected from the ground, but in an actual sense is a direct image of the sky, giving one the impression of seeing a pool of water on the ground.

Answer:

Angular diameter of Mars = 15.80 * 10^5 arc seconds

The Angular diameter of Mars is 3 times the angular diameter of Jupiter

Explanation:

Average distance of the earth from sun = 150.67 * 10^6 km

assuming the radius of Mars ( average distance from sun) = 209.33 * 10^6 km

assuming the radius of Jupiter(average distance from sun) = 768.71 * 10^6 km

The small-angle formula for mars

angular diameter = ( linear diameter / distance ) * (2.06 * 10^5 )

distance between earth and mars = 54.6 * 10^6 km

linear diameter = 2 * radius = 418.66 * 10^6 km

angular diameter = ( 418.66 / 54.6 ) * 2.06 * 10^5

                             = 15.80 * 10^5 arc seconds

small angel formula for Jupiter

Angular diameter = ( linear diameter / distance ) * (2.06 * 10^5)

distance between Jupiter and earth = 588 * 10^6 km

linear diameter = 2 * radius = 1537.42 * 10^6 km

Angular diameter = ( 1537.42 / 588) * 2.06*10^5

                             = 5.39 * 10^5 arc seconds

comparing the angular diameter of the Mars and that of Jupiter :

The angular diameter of mars / angular diameter of Jupiter

= 15.80 / 5.39 = 2.931 ≈ 3

Answer:

Nearly all frequencies and wavelengths of electromagnetic radiation can be used for spectroscopy. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.

Explanation:

Answer:

360000

Explanation:

Answer:

360000 milliseconds

Explanation:

I have this remembered dont worry homie i got chu

Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, [tex]F_1[/tex] = 140 N

let the second force = [tex]F_2[/tex]

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

[tex]F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N[/tex]

[tex]F_2 = 280 \ East[/tex]

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

[tex]F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N[/tex]

[tex]F_2 = 560 \ West[/tex]

Answer:

hello your question lacks the required diagram attached below is the complete question with the required diagram

answer : Qtotal = 807.4 Mw

Explanation:

Given Data :

disk properties :

∈ = 0.65

D = 200 mm

Ts = 400⁰c

attached below is the detailed solution

The total rate of Heat transferred from the disk

Qtotal = 807.4 Mw

Answer:

V = 0.15m

H = 0.85m

Explanation:

We will be using the conservation of momentum to solve the problem.

m(i).v(i) = m(f).v(f) where

0.028 * 190 = 3.1 * v(f)

v(f) = 5.32/3.1

v(f) = 1.72 m/s

next, we use the conservation of energy to find the vertical displacement.

½mv² = mgh

½v² = gh, making h the subject of formula, we have

h = v²/2g

h = 1.72²/ 2 * 9.81

h = 2.9584 / 19.62

h = 0.15 m

The height, h is the vertical displacement.

Next, we find the angle of the pendulum at the top of the swing.

Φ = cos^-1 [(2.5 - 0.15)/2.5] *the height at which the pendulum is hanging is not given, so I assumed it to be 2.5m, yo can substitute that for whatever it is

Φ = cos^-1(2.35/2.5)

Φ = cos^-1 (0.94)

Φ = 19.95°

This gotten angle is used to find the horizontal displacement

x = 2.5 sinΦ

x = 2.5 sin 19.95

x = 2.5 * 0.34

x = 0.85 m

Answer:

v = (1500/10) = 150 [miles/h]

Explanation:

The velocity can be easily calculated using the following kinematics expression:

v = x/t

where:

v = velocity [miles/h]

t = time = 10 [hr]

x = distance = 1500 [miles]

v = (1500/10) = 150 [miles/h]

Answer:

BELTS

Explanation:

why would you need belts for running and stuff

Belts are not an important part of exercise clothing.

An exercise is a physical activity performed to increase strength and agility of the muscles as well as to enhance fitness.

During an exercise, it is important to wear clothes that will not hinder movement or cause injury.

Some items of clothing needed in exercise include:

Therefore, belts are not important during exercise.

Learn more about exercise at: https://brainly.com/question/13490156

Answer:

48.9°, 29°

Explanation:

We kno that snell's law States that

( sin i / sin r ) = ( n 2 / n 1 )

And here

i = 90 - α

r = 90

n 2 = n a = 1.00029

n 1 = n = 1.52

So

( sin ( 90 - α ) / sin 90 ) = (1.00029 / 1.52 )

= 0.658

sin ( 90 - α ) = 0.658

90 - α = sin -1 ( 0.658 )

= 41.15

α = 90 - 41.15

= 48.9°

( b ) to find angle when prism immerssed in water

Using snell's law again

( sin i / sin r ) = ( n 2 / n 1 )

here i = 90 - α

r = 90

n 2 = n w = 1.33

n 1 = n = 1.52

So

( sin ( 90 - α ) / sin 90 ) = (1.33 / 1.52 )

= 0.875

sin ( 90 - α ) = 0.875

90 - α = sin -1 ( 0.875 )

= 61

α = 90 - 61

= 29°

Answer:

The value is [tex]W_N = 11849 \ J [/tex]

Explanation:

From the question we are told that

The mass of the external weight is [tex]m = 51 \ kg[/tex]

The height through which the mass drops is [tex]h = 5.6 \ m[/tex]

     The  number of revolution made is   [tex]N  = 10100 \  kg[/tex]

    The  diameter of the free moving piston is     [tex]d  = 0.51 \  m \  kg[/tex]

     The distance moved by the free moving piston is   [tex]s  = 0.71 \  m \  kg[/tex]

     The  atmospheric pressure is  [tex]P  = 101 \ kPa = 101*10^{3}\ Pa [/tex]

Generally the workdone by the  external weight is mathematically represented as

      [tex]W_w  =m *  g   *  h[/tex]

=     [tex]  51 *  9.8  *  5.6 [/tex]

=     [tex]2799 N  [/tex]

Generally the workdone by the free moving piston  is mathematically represented as  

        [tex]W_p  =P *  A  *  s[/tex]

Here   A is the cross-sectional area with value  

        [tex] A  =  \pi *  \frac{d^2}{4}[/tex]

        [tex] A  =  3.142 *  \frac{0.51^2}{4}[/tex]

So

       [tex]W_p  =101*10^{3} * 3.142 *  \frac{0.51^2}{4}  *  0.71[/tex]

=>       [tex]W_p  = 14651 [/tex]

So

   The net workdone is mathematically evaluated as

        [tex]W_N   = -W_w+W_p  [/tex]

The negative sign shows that it is acting in opposite direction to [tex]W_N[/tex]

So

       [tex]W_N   = -2799+14651  [/tex]

      [tex]W_N   = 11849 \ J   [/tex]

Answer:

The car does not hit the deer.

Explanation:

In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

s = distance covered by car before stopping = ?

a = deceleration of car = - 4.2 m/s²

Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity of the Car = 25 m/s

Therefore,

2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²

s = (- 625 m²/s²)/(-8.4 m/s²)

s = 74.4 m

So, the car stops in 74.4 m, while the deer is at a distance of 75 m.

Hence, the car does not hit the deer.

Using third equation of kinematics

[tex]\boxed{\sf v^2-u^2=2as}[/tex]

[tex]\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s[/tex]

[tex]\\ \sf\longmapsto -625=-8.4s[/tex]

[tex]\\ \sf\longmapsto 8.4s=625[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{625}{8.4}[/tex]

[tex]\\ \sf\longmapsto s=74.4m[/tex]

The correct answer is 36 miles per hour

Explanation:

To find the average speed, the first step is to find the total time and the total distance Lucy covered because the formula for average speed is the total distance divided into the total time.

Total Distance

It is known Lucy covered 2/3 of the total distance first, and then she completed the remaining distance (60 miles). According to this, the last distance or 60 miles represents 1/3 of the total distance.

[tex]\frac{2}{3} + \frac{1}{3} = \frac{3}{3}[/tex]  (Total distance)

Also, if 60 miles is equivalent to 1/3 this number can be used to find the total distance. In this case, just multiply 60 by 3 = 180 miles as 60 is one-third.

This means the total distance is 180 miles

Total Time

It is known the first part of this journey took 3 hours and the second took 2 hours. This means the total time was 5 hours (3 + 2 = 5)

Find the average speed

[tex]Average speed =\frac{Distance}{time}[/tex]

[tex]Average speed = \frac{180 m}{5 h}[/tex]

[tex]Average speed = 36m/h[/tex]

Answer:

C.  Mass is independent of the force acting on the mass.

Weight depends on the gravitational force acting on the mass.

Example:  A mass of 1 kg on the earth still has a mass of 1 kg on the moon;

whereas the weight of that mass on earth is 9.8 N and only 1/6 of that amount on the moon.

Answer:

We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass)

Answer:

The. Machine must detect a shift of

1 Hz

Explanation:

Frequency shift is given as

={ ( Vsound +V/ V sound -V) -1}f emitted

So by substitution we have

= { 1540+4E-4/1540-4E)-1) 2*10^6

= 1Hz

Answer:

Approximately [tex]3.1\; \rm m \cdot s^{-1}[/tex].

Explanation:

The content of this pail is in a centripetal motion because its path forms part of a vertical circle. Let [tex]m[/tex] denote the mass of the contents of this pail, let [tex]v[/tex] denote the (linear) velocity of the content, and let [tex]r[/tex] denote the radius of this circle. The net force on the contents of this pail will thus be:

[tex]\displaystyle F(\text{net}) = \frac{m\, v^2}{r}[/tex] towards the center of the circle.

Assume that there is no friction between the content and walls of the pail. The only two possible forces on the contents pail towards the center would be:

Note that at the top of the circle, both the gravitational pull and the normal force from the bottom point towards the center of the circle. On the other hand, the normal force from the walls of the pail would be perpendicular to the line towards the center of the circle. At that point in the circle, there's no upward force to support the content of the pail. The uniform rotation will be sufficiently fast if it could allow the content to stay in the pail at the top of the circle.

Let [tex]g[/tex] denote the gravitational field strength at the top of this circle. The size of the gravitational pull on the content would be [tex]m\cdot g[/tex]. Let [tex]F(\text{normal})[/tex] denote the normal force from the bottom of the pail on the contents. The sum of these two forces should be equal to the vertical net force on the contents of this pail. That is:

[tex]F(\text{net}) = m\cdot g + F(\text{normal})[/tex].

From the centripetal motion of the content:

[tex]\displaystyle \frac{m\, v^2}{r} = m\cdot g + F(\text{normal})[/tex].

Rearrange to obtain an expression for the normal force:

[tex]\displaystyle F(\text{normal}) = \frac{m\, v^2}{r} - m\cdot g[/tex].

Note, that the normal force the bottom of the pail exerts on the contents should be greater than or equal to zero. While the pail is at the top of the circle, the normal force from the bottom of the pail cannot pull the contents upwards. Hence:

[tex]\displaystyle \frac{m\, v^2}{r} - m\cdot g = F(\text{normal}) \ge 0[/tex].

[tex]\displaystyle \frac{m\, v^2}{r} - m\cdot g \ge 0[/tex].

Rearrange and simplify to obtain:

[tex]\displaystyle \frac{v^2}{r} - g \ge 0[/tex].

[tex]v^2 \ge g\cdot r[/tex].

[tex]v \ge \sqrt{g \cdot r}[/tex].

In other words, if the gravitational field strength is [tex]g[/tex] and the radius of the circle is [tex]r[/tex], the minimum linear velocity required to keep the content in the pail at the top of the circle is [tex]\sqrt{g \cdot r}[/tex].

If [tex]g = 9.81\; \rm N \cdot kg^{-1} = 9.81\; \rm m \cdot s^{-2}[/tex] and [tex]r = 0.82 \; \rm m + 0.185\; \rm m \approx 1.005\; \rm m[/tex], then the minimum value of [tex]v[/tex] would be approximately:

[tex]\sqrt{9.81 \; \rm m \cdot s^{-1} \times 1.005\; \rm m} \approx 3.1\; \rm m \cdot s^{-1}[/tex].

The measurement of distance is the length between two places. To measure is to establish the distance between two geometric objects. With a ruler, you can measure distance the most frequently. Ordinarily, eighth-inch (or 0.125 in) segments make up inch rulers.

When calculating the distance to stars, many astronomers choose to use parsecs (abbreviated pc). This is due to the definition's tight connection to a technique for determining the separation between stars. The distance at which 1 AU subtends an angle of 1 arc sec is measured in parsecs.

A unit of measurement is a specific magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind.

Therefore, Any additional amount of that type can be stated as a multiple of the measurement.

Learn more about measure here:

https://brainly.com/question/4725561

#SPJ2

Answer:

Explanation:

W=?

Mass=1800kg

g=(9.8m/s^2 constant)

W=mg

W=1800*9.8

W=17649N

Answer:

You are putting more force on the ball no the racket so the racket wouldnt swing back but if you hit a racket on the ground it will swing backits just the way the force reaction works

Explanation:

^^^^^^^^^^^^^^^

The racket wouldn't swing back because you were applying more power to the ball than to the racket, so the racquet swings backward when the ball hits it.

Any action that aims to maintain, modify, or deform a body's motion is considered a force in mechanics. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force (1687).

According to Newton's third law, whenever one body applies force to another, the second body also applies an equal amount of force to the first body. The action-reaction concept explains why a force tends to cause a body to deform, or change shape, whether it moves the body.

The racket wouldn't swing back because you were applying more power to the ball than to the racket, but it would if you struck the racket on the ground; that's how the force reaction operates.

Therefore, the racquet swings backward when the ball hits it.

To know more about Force:

https://brainly.com/question/13191643

#SPJ2

Answer:

Explanation:

The velocity of the wrench must be equal to the velocity of the truck . So momentum of the wrench before it hits the wall

= mv = 6 x 13.3 = 79.8 kg m /s

If resisting force of wall be F , impulse on the wrench = F x time

= F x .07

Impulse = change in momentum of the wrench = mv - 0 = mv = 79.8 kgm/s

So F x .07 = 79.8

F = 1140 N .