Answer:
o.75
Explanation:
A train moving at a velocity of 15 m/s is accelerated to 24m/s over a 12 second period, time traveled by the train is 12 seconds.
The initial velocity u of the train is 15 m/s, the final velocity v is 24 m/s, and the time t is 12 seconds. The train is undergoing uniform acceleration.
We can use the kinematic equation to relate the initial velocity, final velocity, acceleration, and time:
v = u + at
Solving for t:
[tex]\[ t = \dfrac{v - u}{a} \][/tex]
Given that a is the acceleration and is calculated as:
[tex]\[ a = \dfrac{v - u}{t} \][/tex]
Substitute the given values:
[tex]\[ a = \dfrac{24 \, \text{m/s} - 15 \, \text{m/s}}{12 \, \text{s}} \][/tex]
[tex]\[ a = \dfrac{9 \, \text{m/s}}{12 \, \text{s}} \\\\= 0.75 \, \text{m/s}^2 \][/tex]
Now substitute the calculated acceleration back into the equation for \( t \):
[tex]\[ t = \dfrac{v - u}{a} \\\\= \dfrac{24 \, \text{m/s} - 15 \, \text{m/s}}{0.75 \, \text{m/s}^2} \][/tex]
[tex]\[ t = \dfrac{9 \, \text{m/s}}{0.75 \, \text{m/s}^2} \\\\= 12 \, \text{s} \][/tex]
Thus, the time traveled by the train is 12 seconds.
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Your question seems incomplete, the probable complete question is:
A train moving at a velocity of 15 m/s is accelerated to 24m/s over a 12 second period. Determine the time travelled​
