Answer:A
Step-by-step explanation:
To determine the possible values of h, we can apply the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
In this case, we have side lengths measuring 3x cm, 7x cm, and h cm. Therefore, the possible values of h must satisfy the following conditions:
h + 3x > 7x
h + 7x > 3x
3x + 7x > h
Simplifying these inequalities, we have:
h > 4x
h > -4x (since we have h + 7x > 3x, we can subtract 7x from both sides)
10x > h
From these conditions, we can conclude that h must be greater than 4x and less than 10x. So, the expression that describes the possible values of h is:
h > 4x and h < 10x
Alternatively, we can write it as:
4x < h < 10x
Therefore, the correct option is A) 4x.
The distance required for an automobile to stop is directly proportional to the square of its velocity. If a car can stop in 1800 meters from a velocity of 30 kph, what will be the required distance at 28 kph?
It is found that 15% of pupils at a school do not jog or swim or cycle, 8% do all three activities, 15% swim and cycle but do not jog, 15% do both jog and swim, 20% swim only, 18% cycle only and 42% do two or more activities
a) Define the cardinality of the complement of set
b) Workout the percentage of pupils who
i) Do both jog and cycle
ii) Swim or cycle
iii) Do not swim
iv) Do not jog, swim and cycle
Step-by-step explanation:
a) The complement of the set of pupils who do not jog or swim or cycle would be the set of pupils who do at least one of these activities.
b) We can use a Venn diagram to help us visualize the information given and answer the questions:
```
_____________
/ \
/ \
jog / A \ swim
/ \
/ \
________/_________ _______\_________
/ \ / \
/ \ / \
cycle B \ / C \ none
/ \ /
/ \____________/
/
/
/
/
/
```
- i) To find the percentage of pupils who do both jog and cycle, we look at the intersection of sets A and B, which is 8%. Therefore, 8% of pupils do both jog and cycle.
- ii) To find the percentage of pupils who swim or cycle, we add the percentages of sets B, C, and D (the parts of the circles that include swimming or cycling), which gives 8% + 15% + 18% = 41%. Therefore, 41% of pupils swim or cycle.
- iii) To find the percentage of pupils who do not swim, we add the percentages of sets A, B, and D (the parts of the circles that do not include swimming), which gives 15% + 8% + 18% = 41%. Therefore, 41% of pupils do not swim.
- iv) To find the percentage of pupils who do not jog, swim, or cycle, we look at the complement of the set of pupils who do at least one of these activities. This is given as 15%, so the percentage of pupils who do not jog, swim, or cycle is 15%.
15% of pupils do not jog, swim or cycle. Of the remaining pupils, 19% both jog and cycle, 61% either swim or cycle, and 39% do not swim. The numbers are based on a full 100% participation rate in regards to these three activities only.
Explanation:The cardinality of a complement of a set refers to the elements that are not in the original set. In context of this question, the complement of the set would be the 15% of pupils who do not partake in jogging, swimming or cycling.
To answer the other parts of the question:
The percentage of pupils who both jog and cycle can be found by adding the percentages of pupils who take part in two or more activities (42%) and then subtracting the percentage of pupils who swim and cycle but do not jog (15%) as well as those who do all three activities (8%). This gives 42% - 15% - 8% = 19%. The percentage of pupils who swim or cycle can be found by adding the percentage of those who swim only (20%), cycle only (18%), do all three activities (8%), as well as those who swim and cycle but do not jog (15%). This gives 20% + 18% + 8% + 15% = 61%. The percentage of pupils who do not swim can be found by subtracting the percentage of those who swim from 100%. This gives 100% - 61% = 39%.The percentage of pupils who do not jog, swim, or cycle is given directly as 15%.Please note that this solution is assuming that all pupils participate in at least one of these activities or none at all and that there are no other activities available.
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when selecting your schedule in school, you can choose from three math courses, four english courses, two science courses, and two history courses. how many choices do you have for your schedule if you need to select one math, one english, one science, and one history course?
You have 48 different choices for your schedule if you need to select one math, one English, one science, and one history course. It's important to note that this calculation assumes that there are no restrictions or prerequisites for the courses, and that all options are available to all students.
When selecting your schedule in school, you have to choose one math course from the three options, one English course from the four options, one science course from the two options, and one history course from the two options. To find out how many different schedule options you have, you need to multiply the number of options for each subject. So, you have:
3 options for math x 4 options for English x 2 options for science x 2 options for history = 48 possible schedule combinations.
Therefore, you have 48 different choices for your schedule if you need to select one math, one English, one science, and one history course. It's important to note that this calculation assumes that there are no restrictions or prerequisites for the courses, and that all options are available to all students.
To determine the number of possible schedules, you need to multiply the number of choices for each subject together. You have three math courses, four English courses, two science courses, and two history courses. The formula for calculating the total number of choices is:
Total choices = (Math choices) x (English choices) x (Science choices) x (History choices)
Total choices = (3) x (4) x (2) x (2) = 48
So, you have 48 different possible schedules when selecting one math, one English, one science, and one history course.
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two balls are drawn simultaneously from a bag containing 2 yellow and 4 green balls. what is the probability of drawing 2 green balls
The probability of drawing 2 green balls simultaneously from a bag containing 2 yellow and 4 green balls can be determined using the following method:
First, calculate the total number of balls in the bag. There are 2 yellow balls and 4 green balls, so the total is 6 balls.
Now, let's find the probability of drawing 2 green balls. To do this, consider the number of green balls (4) and the total number of balls (6). When drawing the first green ball, there are 4 green balls out of 6 total balls. Therefore, the probability of drawing one green ball is 4/6.
Since the balls are drawn simultaneously, there's no change in the number of balls for the second draw. So, the probability of drawing a second green ball remains 4/6.
Now, we can calculate the probability of both events occurring simultaneously by multiplying the probabilities:
(4/6) * (4/6) = 16/36
To simplify the fraction, divide both numerator and denominator by their greatest common divisor (4):
16/36 = 4/9
So, the probability of drawing 2 green balls simultaneously is 4/9.
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Determine the missing dimension of the area is 112 in.²
The missing dimension of the rectangle is 8 inches.
To determine the missing dimension of an area of 112 in.², we need to know at least one of the dimensions. Let's assume we know the length of the rectangle is 14 inches.
We can then use the formula for the area of a rectangle, which is length multiplied by width, to solve for the missing dimension.
We can rearrange the formula to solve for the width by dividing both sides by the length: width = area/length. Plugging in the values we know, we get: width = 112 in.² / 14 in. = 8 inches.
It's important to note that if we had started with the width instead of the length, we would have used the same formula but rearranged it to solve for the length instead. The formula for the area of a rectangle is very useful for solving these types of problems.
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4. a) Verify that DEF is a right triangle.
E(-2, 2)
D(1,4)
F(3,1)
b) Describe another method that you could
use to answer part a).
Answer:To verify whether triangle DEF is a right triangle, we can use the slope formula and the perpendicularity criterion.
a) Verification of DEF as a right triangle:
Calculate the slopes of the two sides:
Slope of DE = (y2 - y1) / (x2 - x1) = (4 - 2) / (1 - (-2)) = 2 / 3
Slope of EF = (y2 - y1) / (x2 - x1) = (1 - 2) / (3 - (-2)) = -1 / 5
Check if the product of the slopes is -1 (perpendicular lines):
(Slope of DE) * (Slope of EF) = (2 / 3) * (-1 / 5) = -2 / 15
Since the product of the slopes is not -1, the sides DE and EF are not perpendicular. Therefore, triangle DEF is not a right triangle.
b) Another method to determine if triangle DEF is a right triangle:
Another method to answer part a) is by calculating the lengths of the three sides DE, EF, and DF. Then, we can check if the Pythagorean theorem holds true.
Calculate the lengths of the sides:
Length of DE = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((1 - (-2))^2 + (4 - 2)^2) = sqrt(9 + 4) = sqrt(13)
Length of EF = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((3 - 1)^2 + (1 - 4)^2) = sqrt(4 + 9) = sqrt(13)
Length of DF = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((3 - (-2))^2 + (1 - 2)^2) = sqrt(25 + 1) = sqrt(26)
Apply the Pythagorean theorem:
If DF^2 = DE^2 + EF^2, then triangle DEF is a right triangle.
DF^2 = (sqrt(26))^2 = 26
DE^2 + EF^2 = (sqrt(13))^2 + (sqrt(13))^2 = 13 + 13 = 26
Since DF^2 equals DE^2 + EF^2, the Pythagorean theorem holds true, indicating that triangle DEF is a right triangle.
Therefore, the two methods of verification provide conflicting results. One method (using the perpendicularity criterion) suggests that DEF is not a right triangle, while the other method (using the Pythagorean theorem) suggests that it is a right triangle. In such cases, it is important to double-check the calculations and verify the accuracy of the given points to resolve the discrepancy.
Step-by-step explanation:
explain step by step
Answer:
(a) $ 315000
(b) $ 3103448.28
Step-by-step explanation:
(a)
tax = 45% of buying price
Buying price = $700000
tax = 45% × 700000
= $ 315000
(b)
Final price = $4500000
145% = 4500000
buying price = 100%
= 4500000/145 × 100
= 3103448.28
x and y intercept for x-2y=32
Answer:
The x-intercept is (32, 0),The y-intercept is (0, -16).------------------------
Set one variable to 0 and solve for the other.
For the x-intercept, set y = 0 and solve for x:
x - 2(0) = 32 x = 32For the y-intercept, set x = 0 and solve for y:
0 - 2y = 32 -2y = 32 y = -16The x-intercept is (32, 0) and the y-intercept is (0, -16).
Whats the answer and how do i show work
The measure of <1 is 147 degree.
Given:
m∠2 = 12x - 15
m∠7 = 3x + 21
Since angles 2 and 7 are alternate Exterior angles, they are congruent.
So, 12x - 15 = 3x + 21
12x - 3x = 21 + 15
9x = 36
x = 4
So, <2 = 12x - 15= 48 - 15 = 33
Now, <1 + <2 = 180 (Linear Pair)
<1 + 33 = 180
<1 = 147 degree
Thus, the measure of <1 is 147 degree.
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Calculate the double integral ∫∫R 2x/1+xy dA, where R = [0,2] x [0,1].
The double integral ∫∫R 2x/(1+xy) dA over R = [0,2] x [0,1] is equal to -4ln(3) + 4.
We have:
∫∫R 2x/(1+xy) dA = ∫[0,2]∫[0,1] 2x/(1+xy) dy dx
Using u-substitution with u = 1 + xy, we have du/dy = x. Solving for x, we get x = du/dy / y. Substituting this into the integral, we get:
∫∫R 2x/(1+xy) dA = ∫[0,2]∫[0,1] 2u/(u) * (1/u) du dx
Simplifying and evaluating the inner integral, we get:
∫∫R 2x/(1+xy) dA = ∫[0,2] (-2ln|1+xy|)[y=0]^{y=1} dx
= ∫[0,2] -2ln(1+x) dx
= [-2(xln(1+x)-x)]_{x=0}^{x=2}
= -4ln(3) + 4
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Question 18
YARDWORK Each week Imani and Demond must mow their 4-acre yard. When they use both their 36-inch mower and 42-inch mower, it
takes them 2 hours. When the 36-inch mower is out for repairs, it takes them 3 hours. How long would the job take if the 42-inch mower
were broken?
Answer:
6/12
Step-by-step explanation:
this is because if you do the math it is 6/12
In the figure below, Z is the center of the circle. Suppose that QR = 14, SR = 14, UZ = 3x + 5, and VZ = 23. Find the following.
Answer:
x=6
Step-by-step explanation:
VZ=UZ
3x+5=23
3x=18
x=6
Help me with this please
Answer:
2/3
Step-by-step explanation:
3 times 2/3 will equal 2 (A - B)
4.5 times 2/3 will equal 3 (B - C)
6 times 2/3 will equal 2 (C - D)
to find the fraction just divide any of the numbers on the dialated figure (right side) by it's parallel side
find a value of c so that p(z ≥ c) = 0.55.
To find a value of c such that P(z ≥ c) = 0.55, we need to use a standard normal distribution table or calculator.From the standard normal distribution table, we find that the z-score corresponding to a right-tailed area of 0.55 is approximately 0.126.
Therefore, we have:
P(z ≥ c) = 0.55
P(z ≤ c) = 1 - P(z ≥ c) = 1 - 0.55 = 0.45
Using the standard normal distribution table, we find that the z-score corresponding to a left-tailed area of 0.45 is approximately -0.126.
So, c = -0.126.
Therefore, the value of c that satisfies P(z ≥ c) = 0.55 is approximately -0.126.
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Which question was answered with variable data?
Math item stem image
CLEAR CHECK
Answer:
Question 1
only, because there are many cards in a standard deck of playing cards.
Question 2
only, because the snowfall was not the same for every month.
Neither question, because in each data set, there is only one outcome.
Both questions, because each one has more than one answer.
The term "Variable data" refers to data that can vary or change. It typically includes numerical data that can take on different values or measurements, such as temperature, height, weight, or time.the correct answer is "Neither question, because in each data set, there is only one outcome."
Neither question was answered with variable data, because in each data set, there is only one outcome.
The term "variable data" refers to data that can vary or change. It typically includes numerical data that can take on different values or measurements, such as temperature, height, weight, or time.
In this case, neither question involves variable data. Question 1 is about the number of cards in a standard deck of playing cards, which is a fixed quantity and does not vary. Question 2 is about the total snowfall for each month, but each month has a single, fixed value, so there is no variation in the data.
Therefore, the correct answer is "Neither question, because in each data set, there is only one outcome."
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HELP ASAP PLEASE :(((
The values of the third side that would make this a right triangle are C. √ 73 m.
Which values make this a right triangle ?The value that should make the shape a right triangle would be the value that obeys the Pythagorean Function which is:
Longest side ² = Side A ² + Side B ²
Picking √ 73, we have a value of :
= 8. 544 m
Plugging into the formula, we have:
8. 544 ² = 3 ² + 8 ²
72. 99 = 9 + 64
73 = 73
This shows that the value would be 8. 544 or any value that is around 8. 5 m as this can be rounded off.
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Jackson was solving a two-step equation. Which property justifies the work done between steps one and two?
The work done between steps one and two is justified by applying the Addition Property of Equality.
In step one, we start with the equation 3x - 2 = 10.
To isolate the variable, we can use the Addition Property of Equality, which allows us to add 2 to both sides of the equation.
This yields 3x = 12 (step two).
The Addition Property of Equality states that if the same value is added to both sides of an equation, the equality remains true.
Hence, the property utilized between these steps is the Addition Property of Equality.
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Please help with this i need this quick
Answer:
x = 11.0
Step-by-step explanation:
Since this is a right triangle, we can find the measure of x using one of the trigonometric ratios.
If we allow ∠A to represent the reference angle, we see that BC is the opposite side and AB is the hypotenuse. Thus, we can use the sine ratio, which is sin (reference angle) = opposite/hypotenuse.We can plug in everything into the sine ratio and solve for x:sin (27) = BC / AB
sin (27) = 5 / x
x * sin (27) = 5
x = 5 / sin (27)
x = 11.01344632
x = 11.0
the slope of line that passes through the points (20,30) and (40,14) is
a) -5/4
b) -4/5
c) 4/5
d) 5/4
Answer:
B
Step-by-step explanation:
calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (20, 30 ) and (x₂, y₂ ) = (40, 14 )
m = [tex]\frac{14-30}{40-20}[/tex] = [tex]\frac{-16}{20}[/tex] = - [tex]\frac{4}{5}[/tex]
HELP ASAP ! Write a function rule for the table.
A. ƒ(x) = 3x
B. ƒ(x) = x + 3
C. ƒ(x) = –3 – x
D. ƒ(x) = x – 3
Answer:
The correct answer is D. ƒ(x) = x – 3.
The function rule for a table is a mathematical expression that relates the input values to the output values. In this case, the input values are the numbers in the first column of the table, and the output values are the numbers in the second column of the table.
To find the function rule, we can look for a pattern in the table. We can see that each output value is 3 less than the corresponding input value. For example, when the input value is 1, the output value is -2. When the input value is 2, the output value is -1.
This pattern can be expressed mathematically as ƒ(x) = x – 3. This function rule tells us that the output value is equal to the input value minus 3.
Step-by-step explanation:
Use a double integral to find the area of the region.
The region inside the circle
(x +3)^2 + y^2 = 9
and outside the circle
x^2 + y^2 = 9
The area of the region is (27π/4) square units.
We have,
To find the area of the region inside the circle (x + 3)² + y² = 9 and outside the circle x² + y² = 9, we can use a double integral in polar coordinates.
The region is an annulus (a region between two concentric circles) with the smaller circle centered at (-3,0) and radius 3, and the larger circle centered at the origin and radius 3.
We can rewrite the equations of the circles in polar coordinates as:
(x + 3)² + y² = 9
And,
r² + 2r cos(theta) + 9 = 9
r² + 2r cos(theta) = 0
r = -2 cos(theta)
And,
x² + y² = 9
r² = 9
The region can be described as 0 ≤ r ≤ 3 and -π/2 ≤ θ ≤ π/2 since we are only interested in the part of the region above the x-axis.
The area of the region can be calculated using the following double integral:
A = ∫∫R r dr dθ
where R is the region in polar coordinates.
We can integrate with respect to r first:
A = ∫(-π/2)^(π/2) ∫0³ r dr dθ
= ∫(-π/2)^(π/2) [(1/2) r²]_0³ dθ
= ∫(-π/2)^(π/2) (9/2) dθ
= (9/2) [θ]_(-π/2)^(π/2)
= (9/2) [π - (-π/2)]
= (9/2) (3π/2)
= (27π/4)
Thus,
The area of the region is (27π/4) square units.
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y=3x+10
what is the y-intercept
Answer: (0,10)
Step-by-step explanation:
To find the y-intercept, substitute in 0 for x and solve for y.
Answer:
The y-intercept is 10. Also can be thought of as the point (0, 10).
Step-by-step explanation:
This equation is in Slope-Intercept form. The y is all by itself on the left side of the equal sign. On the right, there is an x term. The number next to the x (the co-efficient of x) is the slope. The constant, the number all by itself is the y-intercept.
In the equation,
y = 3x + 10 the slope is 3 and the y-intercept is 10.
This is where the graph crosses the y-axis, the point (0,10)
For any equation you can find the y-intercept by letting x = 0.
y = 3(0) + 10
y = 0 + 10
y = 10
Complete the proof.
Given: ZADB and ZBDC form a linear pair and ZADB = ZBDC.
Prove: ZADB and BDC are right angles.
Statements
1. ZADB and ZBDC form a linear pair and
ZADB ZBDC.
2. ZADB and ZBDC are Select Choice
3. m2ADB+ m2BDC = 180°
4. mzADB= mzBDC
5. mzADB+mzADB = 180°
6. 2mZADB= 180°
7. m2ADB= 90°
8. m2DBC= 90°
9. ZADB and ZDBC are right angles.
1. Given
Reasons
2. Linear Pair Theorem
3. Select Choice
4. Definition of congruence
5. Substitution
6. Substitution
7. Division Property of Equality
8. Congruent angles have the same measure
9. Select Choice
We can conclude that mZADB = mZBDC = 90° (statement 7) because a right angle is defined as an angle that measures 90° (statement 9). Thus, ZADB and ZBDC are both right angles (statement 9).
1. Given reasons
2. Linear Pair Theorem
3. Angle Addition Postulate
4. Definition of congruence
5. Substitution
6. Division Property of Equality
7. Simplification
8. Simplification
9. Definition of a right angle
Proof:
We are given that ZADB and ZBDC form a linear pair and that their measures are congruent. By the Linear Pair Theorem, we know that the measures of these two angles add up to 180° (statement 2). Let mZADB = x and mZBDC = x, then we can use the Angle Addition Postulate to write mZADB + mBDC = mZBDC (statement 3).
By substituting x for mZADB and mBDC, we get 2x = x + x, which simplifies to 2x = 2x. Using the Division Property of Equality (statement 6), we get x = x, which simplifies to 1 = 1. Therefore, we can conclude that mZADB = mZBDC = 90° (statement 7) because a right angle is defined as an angle that measures 90° (statement 9). Thus, ZADB and ZBDC are both right angles (statement 9).
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Find the magnitude of vector AB where A=(-10,-9) and B(-7,4) . Round to the thousandths
Answer:
√((-10 - (-7))^2 + (-9 - 4)^2)
= √((-3)^2 + (-13)^2)
= √(169 + 9) = √178 = 13.342
The solution is (-6,0). Which statement best describes the flaw in David's reasoning? (В D David's answer is correct, but he should have graphed the lines. David's answer for x should be 0 because x - x (in line two of his work) is 0. David should have stopped when he calculated -6=-6. This means there are no solutions because the slopes are equal. David should have stopped when he calculated -6=-6. This means there are an infinite number of solutions because it is a true statement.
Answer:
Step-by-step explanation:
the anser is 16
In California, each automobile license plate consists of a single digit followed by three letters, followed by three digits. How many distinct license plates can be formed if the first number cannot be zero and the three letters cannot form "DOG"?
Answer: How many distinct license plates can be formed if the first number cannot be zero and the three letters cannot form "DOG"?
Step-by-step explanation:
Since the first digit cannot be 0, there are 9 choices for the first digit.
For the three letters, there are 26 choices for the first letter, 26 choices for the second letter, and 25 choices for the third letter (since we cannot use "D", "O", or "G").
For the last three digits, there are 10 choices for each digit.
Therefore, the total number of distinct license plates can be formed is:
9 x 26 x 26 x 25 x 10 x 10 x 10 = 16,290,000
So there are 16,290,000 distinct license plates that can be formed if the first number cannot be zero and the three letters cannot form "DOG".
{I Hope This Helps! :)}
leanna needs no more than 2.5 hours to finish her homework. which inequality represents the number of hours, x, leanna needs to finish her homework?
This means that the value of x should not exceed 2.5, as Leanna needs no more than 2.5 hours to complete her homework.
The inequality that represents the number of hours, x, Leanna needs to finish her homework is: x ≤ 2.5.
The inequality x ≤ 2.5 means that the value of x should not exceed 2.5. Since Leanna needs no more than 2.5 hours to finish her homework, we can use this inequality to represent the possible values of x. If x is greater than 2.5, then Leanna would take more than 2.5 hours to finish her homework, which contradicts the given condition. Therefore, the inequality x ≤ 2.5 is the correct representation of the number of hours Leanna needs to finish her homework.
In conclusion, the inequality x ≤ 2.5 represents the number of hours, x, Leanna needs to finish her homework. This means that the value of x should not exceed 2.5, as Leanna needs no more than 2.5 hours to complete her homework.
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let $s$ be a subset of $\{1,2,3,...,50\}$ such that no pair of distinct elements in $s$ has a sum divisible by $7$. what is the maximum number of elements in $s$?
The maximum number of elements in $s$ is $\boxed{7}$, which we can achieve by choosing one element from each of the residue classes modulo $7$.
To find the maximum number of elements in $s$, we need to consider the elements of $\{1,2,3,...,50\}$ that are congruent to each residue class modulo $7$. There are seven residue classes modulo $7$, namely $\{0,1,2,3,4,5,6\}$. Since the sum of two elements from the same residue class modulo $7$ will also be in the same residue class modulo $7$, we cannot include more than one element from each residue class in $s$.
We can include one element from the residue class $0$, which gives us one element. For the other six residue classes, we can choose at most one element from each of them without violating the condition that no pair of distinct elements in $s$ has a sum divisible by $7$. This gives us a total of $1+6=7$ elements in $s$.
Therefore, the maximum number of elements in $s$ is $\boxed{7}$, which we can achieve by choosing one element from each of the residue classes modulo $7$.
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Select the true statement about trend lines.
A. The distance between each point and the line is always the same.
B. The distance from the points to the line should be as small as
possible.
OC. A trend line connects the points.
D. A trend line goes through the first and last points.
The true statement about trend lines include the following: B. The distance from the points to the line should be as small as possible.
What is a trend line?In Mathematics and Statistics, a trend line is sometimes referred to as a line of best fit and it can be defined as a statistical tool which is commonly used in conjunction with a scatter plot, in order to determine whether or not there's any form of correlation (either positive or negative) between a given data.
Generally speaking, the line of best fit or trend line should be very close to the data points as much as possible. This ultimately implies that, a characteristics of a trend line is that the distance from each of the data points to the line must be as small as possible i.e closer to the line.
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Two angles, ∠A and ∠B, are complementary. If sin A = 4/7, what is cos B?
A. 74
B. 47
C. 37
D. √44/7
The Value of cos B is,
⇒ cos B = 0.64
We have to given that;
Two angles, ∠A and ∠B, are complementary.
And, sin A = 4/7
Now, We can simplify as;
sin A = 4/7
A = sin⁻¹ 4/7
A = 39.8°
Since, Two angles, ∠A and ∠B, are complementary.
Hence, We get;
∠A + ∠B = 90°
39.8° + ∠B = 90°
∠B = 90 - 39.8°
∠B = 50.2°
Thus, Value of cos B is,
⇒ cos B = cos 50.2° = 0.64
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