A uranium-235 nucleus decays by a series of alpha and beta emissions until it reaches lead-207. how many alpha emissions and how many beta emissions occur in this series of decays?

In the process of Alpha decay 226 radium decays into 222 radon plus an alpha particle. In this process the energy released is about 4.6 Mev.

For example, In the process of Alpha decay 226 radium decays into 222 radon plus an alpha particle. In this process the energy released is about 4.6 Mev.

The number of protons of ra is 88 will be reduced to 86 and the number of neutrons of rn is 38 will be reduced to 36.

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The center of mass is located at 1.6 meters from 1 kg mass.

We need to know about the center of mass to solve this problem. The center of mass is the point where total torque is zero. It can be determined by

X = ∑mi.Xi / ∑mi

where m is mass and X is coordinate on the x-axis.

From the question above, we know that

m1 = 1 kg

m2 = 4 kg

L = 2 m

Assume that zero point is from m1. Hence,

X = ∑mi.Xi / ∑mi

X = ( m1 . X1 + m2 . X2 ) / (m1 + m2)

X = ( 1 . 0 + 4 . 2 ) / (1 + 4)

X = 8 / 5

X = 1.6 meters

Hence, the center of mass is located at 1.6 meters from 1 kg mass.

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The magnitude of the tension T is = 60N

The mass of the object held at rest = 6kg

The angle of the object at rest is = 30°

The magnitude of force F acting vertically downwards = 410N

Acceleration due to gravity= 10m/s²

The magnitude of tension T = ?

Using the formula; 2T sin(α) = m × g

make T the subject of formula,

T = m × g/ 2sin(α)

T = 6 × 10/ 2 sin (30)

T= 60/2 × 0.5

T = 60/1

T= 60N

Therefore, the magnitude of the tension T is = 60N

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Answer: 20 m west

Explanation:

The properties of Sodium are as follows:

Elements are defined as any substance which cannot be split into simpler units aby a ordinary chemical process.

Elements are classified into metal, non-metals and metalloids.

Sodium one of the known 118 elements.

In the period table, sodium has the following properties:

In conclusion, sodium is an element in the periodic table.

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A ball sitting still on the pitch obeys Newton's first law.

According to the first law of the Newton, a body would continue to be at rest or in state of uniform motion unless it is acted upon by an external force.

In this case, we have a football that is sitting still on a pitch. This ball is held by the force of inertia and the forces that act on it are balanced. If on the other hand this ball is not kicked (action of eternal force), it would continue to sit still on the pitch.

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Under the circumstances of the normal synthesis and degradation of cellular proteins, the amino acids are metabolized via oxidative degradation.

In animals, amino acids undergo oxidative degradation under different metabolic circumstances.

During the process of normal synthesis as well as the degradation of cellular proteins which is otherwise called protein turnover, there occurs some kinds of amino acids that are released from the breakdown of protein and which are not needed for the synthesis of new protein tend to undergo oxidative degradation.

Oxidative degradation is considered an important step in the mechanical catabolism of amino acids which then generates a more metabolizable kind of the amino acid as well as generates ammonia as a byproduct which is toxic. The ammonia generated thus can also be neutralized into urea through the urea cycle.

In general,  the normal synthesis and also the degradation of cellular proteins take place so as to make oxidative degradation where amino acids are metabolized.

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When a medication alters the velocity of the conduction of electricity through the heart, it is said to have a Dromotropic effect.  

The word 'dromotropic' originates from the Greek word 'dromos' which means 'race' or 'running'. Dromotropic drugs are cardiac drugs that alter the conducting tissues of the heart, thereby affecting the velocity of the conduction of electricity through the heart.

Dromotropic drugs are given to patients in order to improve heart impulses. They alter the conducting tissues of the heart by changing the travelling speed of the SA node to the AV node.

Dromotropic drugs can either be negative or positive. Negative dromotropic drugs decrease the velocity of the conduction of electricity through the heart, while positive dromotropic drugs increase the velocity of the conduction of electricity through the heart.

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The equation represents how the kinetic energy (KE) of a system relates to its gravitational potential energy (GPE) and total mechanical energy (ME) is: KE = ME - GPE; option D

The law of conservation of energy states that in a system, the total energy is conserved. This means that energy is nether created nor destroyed but can be transformed from one form to another.

The total mechanical energy in a system is composed of two parts:

gravitational potential energy, and kinetic energy

Mathematically;

Thus the equation represents how the kinetic energy (KE) of a system relates to its gravitational potential energy (GPE) and total mechanical energy (ME) is KE = ME - GPE

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The net displacement is obtained to be 3.6 m.

We know that distance is a scalar quantity and displacement is a vector quantity. Based on this fact, a scalar has a magnitude but lacks direction while vector has both magnitude and direction.

We know that the total distance could be obtained algebraically since distance is a scalar quantity hence we have the total distance as; 2 m + 3m + 4m = 9 m

The net displacement must be obtained geometrically;

Horizontal component of displacement = 4 m - 2m = 2m

Vertical component of displacement = 3m

Net displacement = √2^2 + 3^2

= 3.6 m

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When a hydrocarbon (CxHy) burns, CO₂ and H₂O are produced. C₄H₇ is the empirical formula.

moles of carbon in the mixture: 44 g x 1 mol C/mole/27.8 g CO₂ x 1 mol CO₂ in the compound, CO₂ equals 0.632 moles of C and 0.632 moles of H. 9.96 g H₂O times 1 mol H₂O and 18.g H₂O times 2 mol H/mol H2O equal 1.11 moles of H.

Total mass equals 8.69g (close enough to 8.70 so our assumption of no oxygen is correct)

We can divide both by the lowest value (0.632) to arrive at the lowest whole number of moles.

..

1.0 moles = 0.632/0.632 moles of C. H = 1.11/0.632=1.75

Now we can multiply both by 4 to get H as a whole number.

..

Molecules C = 4 Molecules H = 7

Empirical equation: C₄H₇

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It will take them 16000000 years to drift 480 Km apart

In this context, rate is defined as distance per unit time Mathematically, it can be expressed as:

Rate = distance / time

From the question given, the following data were obatined:

The time taken to drift can be obtained as follow:

Rate = distance / time

3 = 48000000 / time

Cross multiply

3 × time = 48000000

Divide both side by 3

Time = 48000000 / 3

Time = 16000000 years

Thus, it will take 16000000 years to drift 480 Km apart

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To travel a distance of 400 m the car will take a time of: 8.944 s

The formulas and procedures we will use to solve this exercise are:

Where:

Information about the problem:

Applying the final velocity formula  we have:

vf = √ (vi² + 2 * a * x)

vf = √ ((0 m/s)² + 2 * 10.0 m/s² * 400 m)

vf = √ (0 m²/s² + 8000 m²/s²)

vf = √(8000 m²/s²)

vf = 89.44 m/s

Applying the time formula we have:

t = (2 * x)/ (vi + vf)

t = (2 * 400 m)/ (0 m/s + 89.44 m/s)

t = 800 m / 89.44 m/s

t = 8.944 s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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The time taken by her to reach a speed of 2.28m/s is 1.37 s whereas, the acceleration on break to stop in 0.86s is 4.47 m/s².

( a ) To find the time we use the formula,

a = Δv / Δt

where,

a is acceleration,

Δv is change in speed

Δt is time

So with this putting the given value,

We have,

1.66m/s² =  2.28m/s / Δt

Δt = 2.28m/s / 1.66m/s²

Δt = 1.37 s

( b ) Again using same formula for acceleration

a = Δv / Δt

So,

a =  2.28m/s / 1.37 - 0.86s

a =   2.28m/s / 0.51 s

a = 4.47 m/s²

The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is also a vector quantity.

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(a)The time has taken by a commuter to reach a speed of 2.28m/s is (t)= 1.37 s. (b) If she then brakes to a stop in 0.86s,Theamount of acceleration is (a)=   2.65 m/s².

The term velocity defines that how much distance a particle covered in a given time. The term acceleration defines that change in velocity in a particular time.

( a ) To calculate the time we use the formula, v=u+at

As the particle start from rest so, u= initial velocity would be zero.

The equation becomes, v=at

t=v/a

where, we are given

a= acceleration  of the car =1.66m/s²,

v= speed of the car= 2.28m/s

We have to calculate the time=t

So now we put the given value in the above equation, We have,

t=v/a

Or, t = 2.28m/s / 1.66m/s²

Or, t = 1.37 s

According to the calculation we can say that, The time has taken by a commuter to reach a speed of 2.28m/s is (t)= 1.37 s

( b ) To calculate the acceleration we use the formula, v=u+at

As the particle start from rest so, u= initial velocity would be zero.

The equation becomes, v=at

a=v/t

where, we are given

v= speed of the car= 2.28m/s

t= The time take to break=0.86 s

We have to calculate the acceleration=a

So now we put the given value in the above equation, We have,

a=v/t

Or, a =  2.28 /0.86

Or, a = 2.65 m/s²

According to the calculation we can say that, If she then brakes to a stop in 0.86s,Theamount of acceleration is (a)=  2.65 m/s²

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It takes 15.17s time to reach its top speed.

Vo = 0m[tex]s^{-1}[/tex]

Its top speed v = 76.5 km/h

= 21.25 m/s

acceleration of the train = 1.4 m/[tex]s^{2}[/tex]

Then

V = Vo +at

21.25 = 0+ 1.4t

t = 21.25/ 1.4 = 15.17 s

The rate at which an object’s velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.

The direction of the net force applied on the item determines the object’s acceleration.

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By using inductive reactance, the current is 0.93 A.

We need to know about inductive reactance to solve this problem. The inductive reactance is the internal resistance in the inductor caused by changing current. It can be described as

XL = ω . L

where XL is inductive reactance, ω is angular speed and L is inductance.

The angular speed can be determined by

ω = 2π . f

where f is frequency.

From the question above, we know that

f = 100 Hz

L = 16 mH = 16 x 10¯³ H

V = 9.4 V

By substituting the given parameters, we get

XL = ω . L

XL = 2π . f . L

XL = 2π . 100 . 16 x 10¯³

XL = 10.06 Ω

Find the peak current

V = I . XL

9.4 = I . 10.06

I = 0.93 A

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It is feasible for a human to be heterozygous for the following gametic combinations if three genes on three distinct chromosomes are involved:

If chromosome 1 is present, the person can create 2 different types of gametes. Regarding chromosome number 2, there are also two types. The resulting equation is:

There are 2n different types of gametes, where n is the total number of chromosomes. So,

2^3 = 8.4X10^6 different gametes.

The thread-like components known as chromosomes are found in the nucleus of both animal and plant cells.

Protein and a single molecule of deoxyribonucleic acid make up each chromosome (DNA). DNA is passed down from parents to children and contains the precise instructions that give each kind of living thing its individuality.

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The zone in the map that has the greatest amount of land area suitable for people to live is zone B.

The equator is the imaginary line that divides the earth horizontally into two equal halves of North and South zones.

The countries that are located close to the equator include the following:

Ecuador, Colombia,

From the map, the zone with the greatest amount of land area suitable for people to live is the zone closest to the equator which is zone B.

The temperature of these areas are close to moderate through out the year.

The zone B also contains land mass that is part of the largest continent which is Asia.

Therefore, the zone in the map that has the greatest amount of land area suitable for people to live is zone B.

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My walking speed is 1.75 m.

Speed can be defined as the ratio of distance to time.

To calculate the walking speed, we use the formula below.

Formula:

Where:

From the question,

Substiotute these values into equation 1

Hence, my walking speed is 1.75 m.

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Answer:

Replication is vital to science. It helps make science a self-correcting system. Any time a result is surprising, research­ers will try to replicate it, to see if the phenom­enon is dependable or just a fluke

Explanation:

The height of a cliff is 8.26 m

We changed this for our required

[tex]y_{0}[/tex] = - [tex]V_{0}[/tex]t - 1/2 ^2                (1)

Now, t = 2.35s

a = -9.8 m/[tex]S^{2}[/tex]

Substitute this value in equation (1)

[tex]y_{0}[/tex] = - [tex]V_{0}[/tex]t - 1/2 ^2  

[tex]y_{0}[/tex] = -(8.00m/s) (2.355) - 1/2 (-9.8m/s) [tex]2.35^{2}[/tex]

[tex]y_{0}[/tex] = 8.26 m

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The equivalent resistance of the combination is 30ohms

When two nodes share terminal connections, resistors are said to be in parallel. The smallest parallel resistor is smaller than the equivalent overall resistance. To find the equivalent resistance, after adding the reciprocal values together, take the reciprocal once more.

So, [tex]\frac{1}{R} = \frac{1}{R_{1} } +\frac{1}{R_{2} } +\frac{1}{R_{3} }[/tex]

[tex]\frac{1}{R} = \frac{1}{5} } +\frac{1}{10} } +\frac{1}{15} }[/tex]

[tex]\frac{1}{R} = \frac{1}{30} }[/tex]

R = 30 ohms

Therefore, the equivalent resistance of the combination is 30ohms.

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By using power, the maximum current is (c) 5 mA.

We need to know about power to solve this problem. Power is the energy dissipated because of resistance. The magnitude of power is proportional to current and voltage. It can be determined as

P = I . V

where P is power, I is current and V is voltage.

By using Ohm's Law, power also can be calculated using resistance.

P = I² . R

where R is resistance.

From the question above, we know that

P = 2 W

R = 80 kΩ = 80,000 Ω

By substituting the following parameters, we get

P = I² . R

2 = I² . 80,000

I² = 2 / 80,000

I² = 25 x 10¯⁶ A

I = 5 x 10¯³ A

I = 5 mA

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Moving from the element with atomic number 10 to atomic number 11 on the periodic table, the following which are true include the following:

A. reactivity increases

C. neon has another shell (energy level, orbit), meaning the atom will be larger.

E. valence electrons in sodium are farther from the nucleus

F. atomic number 11 does not have a full electron shell.

This is referred to as the tabular arrangement of elements into rows which is referred to as period or column which is referred to as group.

The reactivity increases in this scenario and atomic number 11 does not have a full electron shell because there is one valence electron which means it doesn't have stable octet configuration.

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The sprinter's changing speed, as well as the speed of any other moving object or person, is displayed on a velocity-time graph. The slope of the graph line on a velocity-time graph is used to represent acceleration.

Velocity's rate of change with time, both in terms of speed and direction. A point or object going straight ahead is accelerated when it accelerates or decelerates. m/s2 is the unit of acceleration. The term "constant acceleration" refers to the pace at which a particle's velocity changes.

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Agatha requires (c) 10 hours of sleep each night.

Children in middle school ideally require average 9-12 hours of sleep each night. If the number of hours of sleep each night is compromised, it will show effect on the concentration and health of the child.

Because sleep is crucial to your physical health, it is crucial that you receive enough of it every night. For instance, your heart and blood arteries are able to recover and repair themselves as you sleep. An increased risk of heart disease, renal disease, high blood pressure, diabetes, and stroke has been related to chronic sleep deprivation. For the brain and body to operate properly the following day, doctors and specialists advise children to receive at least 9 to 12 hours of sleep each night.

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The molarity is 0.018M and the percentage is 8.46%.

Net ionic reaction is

[tex]$\mathrm{Cr} 2 \mathrm{O}^{2-}+6 \mathrm{Fe}^{2+}+14 \mathrm{H}^{+} \rightarrow 6 \mathrm{Fe}^{3+}+2 \mathrm{Cr}^{3+}+7 \mathrm{H} 2 \mathrm{O}$[/tex]

[tex]$1 \mathrm{~mol}$[/tex] of [tex]$\mathrm{Cr} 2 \mathrm{O} 7(-2)$[/tex] reacts with [tex]$6 \mathrm{~mol}$[/tex]of [tex]$\mathrm{Fe}(2+)$[/tex] to form [tex]$6 \mathrm{~mol}$[/tex]of [tex]$\mathrm{Fe}(3+)$[/tex] and [tex]$2 \mathrm{~mol}$[/tex] of [tex]$\mathrm{Cr}(3+)$[/tex]

Find molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]

Molarity = moles of[tex]$\mathrm{K} 2 \mathrm{Cr} 207 /$[/tex] Volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7(\mathrm{~L}$[/tex] )

Moles of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex] = grams of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$[/tex] molar mass of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]

[tex]$=1.2275 \mathrm{~g} / 294.19 \mathrm{~mol}=0.0042 \mathrm{~g} / \mathrm{mol}$[/tex]

Molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7=$[/tex] moles of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]/ Volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex](L)

[tex]$=0.0042 \mathrm{~g} / \mathrm{mol} / 0.250 \mathrm{~L}=0.017 \mathrm{M}$[/tex]

Find molarity of [tex]$\mathrm{Fe}$[/tex] (II)

Molarity of [tex]$\mathrm{Fe}(\mathrm{II})=6 \times$[/tex]molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 \times$[/tex]volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$[/tex]volume of [tex]$\mathrm{Fe}$[/tex] (II)

[tex]$=6 \times 0.017 \mathrm{M} \times 0.03598 \mathrm{~L} / 0.200 \mathrm{~L}$[/tex]

[tex]$=0.018 \mathrm{M}$[/tex]

Find moles of [tex]$\mathrm{Fe}(\mathrm{II})$[/tex]

Moles of [tex]\mathrm{Fe}($ II) =[/tex]molarity of [tex]$\mathrm{Fe}$[/tex] (II) [tex]$\times$[/tex] volume of [tex]$\mathrm{Fe}$[/tex] (II)

[tex]=0.018 \mathrm{M} \times 0.200 \mathrm{~L}=0.004 \mathrm{~mol}[/tex]

Find mass of Fe(II)

Mass of [tex]\mathrm{Fe}( II )=[/tex] moles of [tex]\mathrm{Fe}( II[/tex]) [tex]\times[/tex] molar mass of [tex]$\mathrm{Fe}(\mathrm{II})$[/tex]

[tex]$=0.004 \mathrm{~mol} \times 55.85 \mathrm{~g} / \mathrm{mol}$[/tex]

[tex]$=0.205 \mathrm{~g}$[/tex]

Find [tex]$\% \mathrm{Fe}(\mathrm{II})$[/tex] in unknown sample

[tex]$$\begin{aligned}\% \mathrm{Fe} &=(\text { mass of } \mathrm{Fe} / \text { weight of unknown sample }) \times 100 \\&=(0.205 \mathrm{~g} / 2.4234 \mathrm{~g}) \times 100 \\&=8.46 \%\end{aligned}$$[/tex]

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Answer:

Determining the charge. Electroscopes like we all know are used to detect or determine the charge present in an atom.

Answer:

A rotating magnetic field is produced and the rotor begins rotating and the induction motor starts.

Explanation:

[tex]\huge\qquad\underline{{\tt Answer : }} -[/tex]

As the name suggests, the induction motor is started by connecting it directly to three-phase supply. In this method, the motor draws a high starting current (about 4 to 7 times of the rated current) and at low power factor. Therefore, DOL starting is suitable for relatively small motors (up to 10 kW)

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