A wind turbine with a rotor diameter of 40 m produces 90 kW of electrical power when the wind speed is 8 m/s. The density of air impinging on the turbine is 1.2 kg/m3. What fraction of the kinetic energy of the wind impinging on the turbine is converted to electrical energy

Answer:53.03

Explanation:

Answer:

Choice A. Without energy storage, the total work output of a machine will not exceed the total work input.

Explanation:

Work is the product of force and the distance travelled in the direction of that force.

Indeed, simple machines can alter the size or direction of a force. However, their work output can't exceed the work input to that machine (unless the machine stores some energy- by bending, for example.) Because of frictions and other forms of energy loss, the useful work output of a real machine can even be smaller than the work input to that machine.

The force output of some machines can certainly exceed their force input. However, at the same time, the input part of those machine needs to move a  distance that is (more than) proportionally longer compared to the output part of the machine. As a result, the useful work output would be equal to or even smaller than the total work input.

A fixed pulley is an example of a machine that applies a force in a direction different from the direction of the force applied to the machine. Pulling the string down will lift up the weight on the other side. A seesaw (a first-class lever) is another real-world example of this kind of machines.

Tongs are examples of machines where: the distance traveled by the output exceeds that of the input. However, that comes at a price: delivering the same amount of force with a pair of tongs requires more force than without a pair of tongs. That corresponds to choice D: the work output of some machines can be less than the force input to these machines.

At the same time, some extra force input might be required to overcome the friction between parts of the machine. That's another reason why the machine applies less force than the input even if it was designed to apply the same amount of force.

Answer:

A.) Do a greater amount of work than the amount of work done on the machine.

Explanation:

I took the quiz on Edge!

Hope this helped!

Answer:

0.59 seconds

Explanation:

Answer:

Velocity and Time

Explanation:

I googled it-

Answer:

I think its n u c l e a r e n e r g y.

Answer:

2.15m/26.1s is = average speed

0.08 m/s

Answer:

a) The acceleration of the sprinter is 6.521 meters per square second, b) The acceleration of 84512.16 kilometers per square hour.

Explanation:

Note: Statement is incomplete, complete description of the problem is: A sprinter accelerates from rest to [tex]9.00\,\frac{m}{s}[/tex] in 1.38 seconds. What is his acceleration in a. [tex]\frac{m}{s^{2}}[/tex] and b. [tex]\frac{km}{h^{2}}[/tex]?

a) We assume that sprinter accelerates uniformly, so that acceleration ([tex]a[/tex]), measured in meters per square second, can be obtained from this kinematic expression as function of initial and final velocities ([tex]v_{o}[/tex], [tex]v[/tex]), measured in meters per second, and time ([tex]t[/tex]), measured in seconds, as well.

[tex]v = v_{o} + a\cdot t[/tex]

[tex]a = \frac{v-v_{o}}{t}[/tex]

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 9\,\frac{m}{s}[/tex] and [tex]t = 1.38\,s[/tex], the acceleration experimented by the sprinter is:

[tex]a = \frac{9\,\frac{m}{s}-0\,\frac{m}{s} }{1.38\,s}[/tex]

[tex]a = 6.521\,\frac{m}{s^{2}}[/tex]

The acceleration of the sprinter is 6.521 meters per square second.

b) If we know that a hour is equivalent to 3600 seconds and a kilometer is equivalent to 1000 meters, the result of the previous item is converted by using two consecutive unit conversions:

[tex]a = \left(6.521\,\frac{m}{s^{2}} \right)\cdot \left(\frac{1}{1000}\,\frac{km}{m} \right)\cdot \left(3600^{2}\,\frac{s^{2}}{h^{2}} \right)[/tex]

[tex]a = 84512.16\,\frac{km}{h^{2}}[/tex]

The acceleration of 84512.16 kilometers per square hour.

Answer:

A. The potential difference is given as

V =q/C=0.146uC/240pF

608.33 V

B) The area of each plate is

A =Cd/eo =9.9525*10^-3m ²

C) the electric field magnitude between the plates=V/d

608.33/0.367mm

=1.657x 10^6 N/C

D) The surface-charge density on each plate=q/A

0.146uC/9.9525 x 10^-3m ²

=1.466 x 10^-5 C/m²

Answer:

a) 28877 AU

b) 1.795 sec

Explanation:

Time it took the radio signal to reach earth = 4 hours = 4 x 3600 = 14400 s

speed of radio signal = speed of vacuum speed of light  = 3 x 10^8 m/s

Distance traveled by this signal = speed x time

distance = 3 x 10^8 x 14400 = 4.32 x 10^12 m

One Astronomic unit AU is the distance between the Earth and the sun and it is approximately equal to 1.496 x 10^8 m

The distance traveled by the signal in AU = (4.32 x 10^12)/(1.496 x 10^8) = 28877 AU

b) The minimum separation between Earth and Mars = 0.36 AU

This distance = 0.36 x 1.496 x 10^8 = 538560000 m

Time that will be taken for a radio signal to travel this distance = distance/speed

==> 538560000/(3 x 10^8) = 1.795 sec

Answer:

h = 31.9 m

Explanation:

Since, the ball took 5.1 s in the air. Hence, the time to reach maximum height will be equal to the half of this value:

t = 5.1 s /2 = 2.55 s

Now, we use 1st equation of motion between the time of throwing and the time of reaching maximum height:

Vf = Vi + gt

where,

Vf = Final Velocity = 0 m/s (since, ball momentarily stops at highest point)

Vi = Initial Velocity = ?

g = - 9.8 m/s² (negative sign for upward motion)

Therefore,

0 m/s = Vi + (-9.8 m/s²)(2.55 s)

Vi = 24.99 m/s

Now, we use second equation of motion for height (h):

h = Vi t + (0.5)gt²

h = (24.99 m/s)(2.55 s) + (0.5)(-9.8 m/s²)(2.55 s)²

h = 63.7 m - 31.8 m

h = 31.9 m

Answer: C. 7,350 J

Explanation:

Just did it in Apex

The crate's potential energy at this point will be 7,350 J.Option C is correct.

The potential energy is the energy by the virtue of the position in the system. It varies with the height of the system. The potential energy unit is the joule (j).

The given data in the problem is;

m is the mass of the crate= 75 kg

h is the height = 10 m.

a is the acceleration due to gravity = 9.8 m/s²

P is the potential energy of the crate to be found as;

[tex]\rm PE = mgh \\\\ \rm PE =75 \times 9.81 \times 10 \\\\ PE=7350 \ J[/tex]

The potential energy at this point will be 7,350 J.

Hence option C is correct.

To learn more about the potential energy refer to the link;

https://brainly.com/question/24284560

Answer:

[tex]a=-1.5\ m/s^2[/tex]

Explanation:

Given that,

Initial velocity, u = 30 m/s

Final velocity, v = 0

Time, t = 20 s

We need to find the acceleration of the car. The rate of change of velocity is equal to acceleration. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{-30}{20}\\\\a=-1.5\ m/s^2[/tex]

So, the magnitude of the acceleration of the car is [tex]1.5\ m/s^2[/tex] and it is decelerating.

Complete Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas

What is the total distance traveled over the entire trip (in km)

Answer:

The value is [tex]D = 139.02 \ km[/tex]

Explanation:

From the question we are told that

For [tex] t_1 = 55 min = \frac{55}{60} = 0.917 \ h[/tex] the speed is [tex]v_1 = 60 \ km/h[/tex]

For [tex] t_2 = 18 min = \frac{18}{60} = 0.3 \ h[/tex] the speed is [tex]v_2 = 80 \ km/h[/tex]

For [tex] t_3 = 60 min = \frac{60}{60} = 1 \ h[/tex] the speed is [tex]v_3 = 60\ km/h[/tex]

The time taken to have lunch is [tex]t _l = 25 \ min = \frac{25}{60} = 0.42 \ h[/tex]

Generally the total distance traveled over the entire trip (in km) is mathematically represented as

[tex]D = t_1 * v_1 + t_2 * v_2 + t_3 * v_3[/tex]

=>   [tex]D = 0.917  *  60 +  0.3 * 80 +  1  * 60[/tex]

=>   [tex]D = 55.02  + 24 +   60[/tex]

=>   [tex]D = 139.02 \ km[/tex]

Answer:

The equation which describes conservation of charge is [tex]Q_{initial} - Q_{final } = 0[/tex]

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = [tex]Q_{initial}[/tex]

let the sum of the final charges = [tex]Q_{final}[/tex]

[tex]Q_{initial } = Q_{final}\\\\Q_{initial } - Q_{final} = 0[/tex]

Therefore, the equation which describes conservation of charge is [tex]Q_{initial} - Q_{final } = 0[/tex]

Answer:

[tex]Q_{initial}-Q_{final}=0[/tex]

Explanation:

According to the conservation of charge "Charge can neither be created nor destoryed". This line means the net amount of charges remain conserved, no matter what happens.

Equation will be of the form:

Initial Charge =Final Charge

It can also be written as:

Initial Charge- Final Charge=0

Let Q be the charge:

[tex]Q_{initial}-Q_{final}=0[/tex]

The above equation describes conservation of charge.

Answer:

a) 5000 g

b) 5250 g

c) 5150 g

Explanation:

For easier calculations, the formulas will be converted from g/cm³ to kg/m³, and then back when we're done.

Density of pure water is 1 g/cm³

1 g/cm³ = 1 * 0.001/0.000001

1 g/cm³ = 1000 kg/m³, and thus,

Density of pure blood

1.05 g/cm³ = 1050 kg/m³

Density of seawater

1.03 g/cm³ = 1030 kg/m³

Recall that, Density = mass / volume, and as such, mass = density * volume.

Converting our volume from L to m³

1 m³ = 1000 L, and as such

1 L = 0.001 m³

5 L = 0.005 m³

Mass of pure water = 1000 * 0.005

Mass of pure water = 5 kg

Mass of pure blood = 1050 * 0.005

Mass of pure blood = 5.25 kg

Mass of seawater = 1030 * 0.005

Mass of seawater = 5.15 kg

Converting these masses back to g, we have

Mass of pure water = 5 kg * 1000 g

Mass of pure water = 5000 g

Mass of pure blood = 5.25 kg * 1000 g

Mass of pure blood = 5250 g

Mass of seawater = 5.15 kg * 1000 g

Mass of seawater = 5150 g

Answer:

i try B

Explanation:

Answer:

The magnitude of the velocity is approximately 11.45 units

Explanation:

Since they give us the x and y components of the vector velocity, we can find its magnitude via the Pythagorean theorem:

[tex]|v|=\sqrt{9.5^2+(-6.4)^2} \approx 11.45[/tex]

Answer:

Thus simply tells us that The nut has no net charge and so therefore, There will be a negative charge on the left side, and an equal positive charge on the right side

This basically means that the nut has no net charge and thus will have a negative charge on the left side and an equal positive charge on the right side.

When an object has more protons than electrons, its net charge is positive.

If there are more electrons than protons in an object, the net charge is negative. If the object has an equal number of protons and electrons, it is electrically neutral.

The total charge on a body is the algebraic sum of all the charges on it. Every atom is electrically neutral because it contains the same number of electrons as protons.

This basically means that the nut has no net charge and thus has a negative charge on one side and an equal positive charge on the other.

Thus, this can be implied as per the given scenario.

For more details regarding net charge, visit:

https://brainly.com/question/8233653

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Answer:

[tex]v^2 = v_{ox}^2 + 2a(x - o_x)[/tex]

Explanation:

The options are not well presented; However, the questions can still be solved

Given

[tex]Initial\ Velocity= V_{ox}[/tex]

[tex]Initial\ Displacement = X_{o}[/tex]

[tex]Time = t[/tex]

Required

Determine the final displacement

This question will be answered using the following equation of motion

[tex]v^2 = u^2 + 2as[/tex]

Where s represent the total distance

s is the distance between the initial and final displacements and is calculated as thus;

[tex]s = x - o_x[/tex]

Where x represents the final displacement

Substitute [tex]V_{ox}[/tex] for [tex]u[/tex] ---- The initial velocity

[tex]v^2 = v_{ox}^2 + 2as[/tex]

Substitute [tex]x - o_x[/tex] for s

[tex]v^2 = v_{ox}^2 + 2a(x - o_x)[/tex]

Hence, the above equation can be used to determine the final displacement by solving for x

Answer:

It's not -7.6

Explanation:

All I can tell you

Answer:

9.1m/s  

Explanation:

Nate throws a straight ball to Kayla who is standing at a balcony 3.8m above Nate

When she catches the ball, it is still moving upward with a speed of 2.8m/s

v = 2.8m/s

u = ?

s = 3.8m

a= -9.8(The acceleration has a negative sign because the speed of the ball is declining)    

Therefore the initial speed at which Nate threw the ball can be calculated as follows

v^2= u^2 + 2as

2.8^2= u^2 + 2(-9.8)(3.8)

7.84= u^2 + (-74.48)

7.84= u^2 - 74.48

u^2= 7.84 + 74.48

u^2= 82.32

u= √82.32

u = 9.1m/s    

Hence the initial speed at which Nate threw the ball is 9.1m/s

Answer:

* I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty.

* I willl draw a dot-and-whisker plot for both. Since they overlap, I can conclude that they are equal within the uncertainty

Explanation:

The value of all physical measurement has an uncertainty, so it is within a range of values, in this case we must compare the range of values ​​of the resistors

The nominal value is 100 ± 5 Ω

therefore its range of possible values ​​is between

             95 <= R <= 105

For the experimentally measured value

          88 <= R <= 96

as the values ​​overlap we must conclude that they are the same.

When reviewing the different options we have two statements that are correct

* I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty.

* I willl draw a dot-and-whisker plot for both. Since they overlap, I can conclude that they are equal within the uncertainty

Answer:

He examined covered and uncovered meat to determine that maggots came from eggs.

In other other words A

Answer: Hypothesis

Explanation:

For each experiment involving nanotechnology, Gerry  and Lena will test a hypothesis.

Gerry and Lana will use the Scientific method for their nanotechnology research and a key stage in the scientific method is to come up with a Hypothesis.

A hypothesis gives a researcher direction because it is a theory that they formulate that is meant to explain the phenomenon that they are researching.

They will then test this theory to either disprove or approve it and in so doing will be able to come up with conclusions to the research. Gerry and Lana will therefore have to test a hypothesis for each experiment in order to continue with their research.

Explain how they interact with each other. I'm not a chem genius but taht would make the most sense.

Hope it helps! Comment if you have any questions and have an amazing day!

Answer:

a)   t = 57.14 s

b)    x = 27711.4 m

Explanation:

This is a missile throwing exercise

a) They ask us for the time to the maximum reach, this corresponds to when it reaches the ground y = 0, let's use

          y =  [tex]v_{oy}[/tex] t - ½ g t²

Let's use trigonometry to find the vertical initial velocity

         sin θ = v_{oy} / v₀

         v_{oy} = v₀ sin θ

we substitute

         y = v₀ sin θ t - ½ g t²

since the height is zero

          0 = t (v₀ sin θ - ½ g t)

This equation has two solutions

*  t = 0 which corresponds to the moment of launch

*

         v₀ sin 30 - ½ g t = 0

        t = v₀ sin 30    2/g

let's calculate

         t = 560 sin 30  2 / 9.8

         t = 57.14 s

b) with this time we can calculate the distance traveled

          x = v₀ₓ t

let's use trigonometry for velocity

          cos θ = v₀ₓ / v₀

          v₀ₓ = v₀ cos 30

we substitute

         x = v₀ cos 30     t

let's calculate

         x = 560 cos 30 57.14

         x = 27711.4 m

Answer:

60 km/hr

Explanation:

220 km is covered at 92km/hr in the round trip

There is 1 hour lunch break

During the return of the round trip 220 km is covered at 55km/hr

The first step is to calculate the total distance

= 220km + 220km

= 440km

The time spent during the entire round trip can be calculated as follows

= (220/92) + 1 + (220/55)

= 2.3913 + 1 + 4

= 7.3913

Therefore the average speed can be calculated as follows

= distance/ time

= 440/7.3913

= 59.52

= 60km/hr (approximated to 2 significant figures)

Hence the average speed is 60 km/hr

Answer:

7.05479

Explanation:

Answer:

200 grams:     ounces:7.05479239 that's the answer

Explanation:

Answer:

Explanation:

Using the equation of motion expressed as v = u+gt where;

v is the  final velocity of the ball

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

Given

u = 9m/s

v = 0m/s

t = 6.4s

Required

acceleration due to gravity g

Since the rock is thrown up, g will be a negative value.

v = u+(-g)t

0 = 9-6.4g

-9 = -6.4g

6.4g = 9

divide both sides by 6.4

6.4g/6.4 = 9/6.4

g = 1.40625m/s²

Hence the acceleration due to gravity on the planet is  1.40625m/s²