A woman normally weighs 125 lb. If she is standing on a spring scale in an elevator that is traveling downward, but slowing down, the scale will read.

Answers

Answer 1

The reading on the spring scale will depend on the acceleration of the elevator and the direction of that acceleration.

If the elevator is traveling downward but slowing down (i.e., accelerating in the upward direction), the scale will read less than the woman's normal weight of 125 lb. This is because the upward acceleration of the elevator reduces the effective weight of the woman, making her appear lighter on the scale. To determine the reading on the scale, you would need to know the acceleration of the elevator at that particular moment. If the elevator is slowing down at a rate of, say,[tex]2 m/s^2,[/tex]then the scale would read:

Weight = mass x acceleration due to gravity

Weight =[tex]56.7 kg x (9.81 m/s^2 - 2 m/s^2)[/tex]

Weight =[tex]56.7 kg x 7.81 m/s^2[/tex]

Weight = [tex]442.5 N[/tex]

Converting this to pounds, the reading on the scale would be approximately:

Weight = [tex]442.5 N x (1 lb / 4.448 N)[/tex]

Weight[tex]≈ 99.4 lb[/tex]

So, the scale would read approximately 99.4 lb, which is less than the woman's normal weight of 125 lb.

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Related Questions

Two blocks are connected by a string as shown. The inclination of the ramp is theta = 35 degrees while the masses of the blocks are m1=2.1kg and m2=11kg. Friction is negligible.Part (a): What is the magnitude of the acceleration of each block in m/s^2?Part (b): What is the tension in the rope in newtons?

Answers

(a) The acceleration of each block is zero. (b) The tension in the rope is 97.7 N.

(a) The forces acting on each block are,

For m1,

F_net = T - mg*sin(35)

For m2,

F_net = mg*sin(35) - T

Since the two blocks are connected by a rope, they will have the same acceleration.

T - mgsin(35) = mgsin(35) - T

T = mg*sin(35)

Substituting this value of T,

F_net = T - mg*sin(35)

F_net = mgsin(35) - mgsin(35)

F_net = 0

Therefore, the net force acting on each block in the direction of motion is zero.

(b) To find the tension in the rope,

T = mg*sin(35)

T = (2.1 kg + 11 kg)9.81 m/s^2sin(35)

T = 97.7 N

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A Piece of gold alluminium alloy weighs 49N. When suspended from a spring balance and Submerged in water it weighs 39.2N What is the weight of Gold in the alloy if the specific gravity of Gold is 19.3 and that if aluminium is 2.5?​

Answers

We can start by calculating the volume of the gold in the alloy and then use its density to determine its weight.

First, let's find the weight of the alloy when it's not submerged in water:

Weight of alloy = 49 N

Next, let's find the buoyant force, which is equal to the weight of the water that's displaced by the object:

Buoyant force = weight of water displaced = 39.2 N

So, the weight of the object in water can be calculated as:

Weight in water = Weight of alloy - Buoyant force = 49 N - 39.2 N = 9.8 N

Next, let's calculate the volume of the object using its density:

Volume = Weight in water / (Density of alloy - Density of water)

Since the density of water is 1 g/cm^3, we can simplify the equation as:

Volume = 9.8 N / (Density of alloy - 1)

Since the specific gravity of Aluminium is 2.5, its density can be calculated as:

Density of Aluminium = 2.5 * Density of water = 2.5 * 1 g/cm^3 = 2.5 g/cm^3

So, the volume of the object can be calculated as:

Volume = 9.8 N / (2.5 g/cm^3 - 1 g/cm^3) = 9.8 N / 1.5 g/cm^

A plane starts from rest and accelerate along the ground before take off.It moves 600 min 12s.Find the distance moved during the 12th seconds​

Answers

Given,

Initial velocity, u = 0

Distance covered, s = 600m

Time is taken, t = 12s

We know,

[tex]s = ut +[/tex] [tex]1/2 at^{2}[/tex]

[tex]600 = 0*12 + 1/2 (a) (12)^{2}[/tex]

[tex]a = 600 * 2 / (12)^{2} \\a = 100/12\\ = 8.3m/s^{2} \\[/tex]

Uniform acceleration = [tex]8.s m/s^{2}[/tex]

now using,

[tex]v = u + at\\ = 0 + (8.3) (12)\\ = 99.6 m/s[/tex]

Hence, the speed at the end of the 12 sec is 99.6 m/s

The speed at the end of 11 sec = at = (8.3)(11) = 91.3 m/s

Distance covered by the plane in 11 sec =

[tex]2as = v^{2} - u^{2} \\s = v^{2} - u^{2} /\f2a\\= (91.3)^{2} - (0)^{2} / 2(8.3)\\= 425.29m[/tex]

Thus, distance covered during 12th sec = distance covered in 12s - distance covered in 11s = 600 - 425.29 m = 174.71 m

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Magnets and electric charges show certain similarities. For example, both magnets and electric charges can exert a force on their surroundings. This force, when produced by a magnet, is called a magnetic field. When it is produced by an electric charge, the force is called an electric field. It has been observed that the strength of both magnetic fields and electric fields is inversely proportional to the square of the distance between a magnet or an electric charge and the objects that they affect. Below, three scientists debate the relationship between electricity and magnetism.
Scientist 1:
Electricity and magnetism are two different phenomena. Materials such as iron, cobalt, and nickel contain magnetic domains: tiny regions of magnetism, each with two poles. Normally, the domains have a random orientation and are not aligned, so the magnetism of some domains cancels out that of other domains; however, in magnets, domains line up in the same direction, creating the two poles of the magnet and causing magnetic behavior.

In contrast, electricity is a moving electric charge which is caused by the flow of electrons through a material. Electrons flow through a material from a region of higher potential (more negative charge) to a region of lower potential (more positive charge). We can measure this flow of electrons as current, which refers to the amount of charge transferred over a period of time.

Scientist 2:
Electricity and magnetism are similar phenomena; however, one cannot be reduced to the other. Electricity involves two types of charges: positive and negative charge. Though electricity can occur in a moving form (in the form of current, or an electric charge moving through a wire), it can also occur in a static form. Static electricity involves no moving charge. Instead, objects can have a net excess of positive charge or a net excess of negative charge—because of having lost or gained electrons, respectively. When two static positive electric charges or two static negative electric charges are brought close together, they repel each other. However, when a positive and a negative static charge are brought together, they attract each other.

Similarly, all magnets have two poles. Magnetic poles that are alike repel each other, while dissimilar magnetic poles attract each other. Magnets and static electric charges are alike in that they both show attraction and repulsion in similar circumstances. However, while isolated static electric charges occur in nature, there are no single, isolated magnetic poles. All magnets have two poles, which cannot be dissociated from each other.

Scientist 3:
Electricity and magnetism are two aspects of the same phenomenon. A moving flow of electrons creates a magnetic field around it. Thus, wherever an electric current exists, a magnetic field will also exist. The magnetic field created by an electric current is perpendicular to the electric current's direction of flow.

Additionally, a magnetic field can induce an electric current. This can happen when a wire is moved across a magnetic field, or when a magnetic field is moved near a conductive wire. Because magnetic fields can produce electric fields and electric fields can produce magnetic fields, we can understand electricity and magnetism as parts of one phenomenon: electromagnetism.

In an experiment, an iron bar that showed no magnetism was heated and allowed to cool while aligned North-South with the Earth's magnetic field. After it cooled, the iron bar was found to be magnetic. Scientist 1 would most likely explain this result by saying which of the following?
Possible Answers:
1. Interference occurred between the electric field of the bar and the magnetic field of the Earth, causing the bar to become magnetic.
2. The experiment caused the magnetic domains of the bar to move out of alignment with each other.
3. The experiment induced an electric current in the bar, causing the bar to become magnetic.
4. The experiment allowed the magnetic domains of the bar to line up, causing the bar to become magnetic.
5. The experiment caused the two magnetic poles of the bar to move so that they were aligned with the Earth's magnetic field.

Answers

Scientist 1 would most likely explain this result by saying, The experiment allowed the magnetic domains of the bar to line up, causing the bar to become magnetic.

Scientist 1 would most likely explain this outcome as follows: The experiment caused the magnetic domains of the bar to align, leading the bar to become magnetic.

Because, according to Scientist 1, magnetism originates when magnetic domains in a material align. Because the iron bar initially exhibited no magnetism, we may suppose that its magnetic domains were oriented randomly at first, with no magnetic poles. When the iron bar became magnetic after being heated and chilled, the heating and chilling process most likely reoriented the magnetic domains in the iron, resulting in two magnetic poles.

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The specific heat of copper is 387 J/kg C. The temperature of a 0.35-kg sample of copper decreases from 74.0 °C to 21.0 °C. How much heat flows out of
the copper sample during this temperature drop?

Answers

The amount of heat that flows out of the copper sample during this temperature drop is approximately 4,953.75 J.

What is the amount of heat flowing out?

The amount of heat that flows out of the copper sample can be calculated using the formula:

Q = mcΔT

where;

Q is the amount of heat transferred, m is the mass of the copper sample, c is the specific heat of copper, and ΔT is the change in temperature of the sample.

Plugging in the given values, we get:

Q = (0.35 kg) x (387 J/kg C) x (74.0 °C - 21.0 °C)

Q = 4,953.75 J

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A coil of wire made of 500 circular loops of radius r=25.0cm is in a uniform magnetic field B=0.200T. The surface of the loop is initially perpendicular to the magnetic field when it is moved within 0.250s such that the surface of the loop then makes an angle of 45 degrees with respect to the magnetic field.
(a) What is the change in magnetic flux, in Tesla-square meters, on the coil of wire?
(b)What is the induced emf, in Volts, on the coil of wire?

Answers

Answer:

1.3 and 2.5

Explanation:

I did mental math

Answer:

(a) The change in magnetic flux is equal to the product of the magnetic field strength, the area of the coil, and the cosine of the angle between the magnetic field and the surface of the loop. Therefore, the change in magnetic flux is equal to 0.200T x (π x (25.0cm)^2) x cos(45°) = 7.85 x 10^-3 Tesla-square meters.

(b) The induced emf is equal to the change in magnetic flux divided by the time taken for the change to occur. Therefore, the induced emf is equal to 7.85 x 10^-3 Tesla-square meters / 0.250s = 3.14 Volts.

= 1.2M²₂// then taking a penedy A constant force of 5N ads to 5 sec. on a mass of 5 kg initially at rest. calculate the final momentum!​

Answers

The final momentum is 25 Kg m/s

What is the momentum?

In physics, momentum is a measure of an object's motion, calculated by multiplying the object's mass by its velocity. Mathematically, momentum is represented by the symbol "p" and can be expressed as:

p = mv

where "p" is momentum, "m" is mass, and "v" is velocity. Momentum is a vector quantity, meaning that it has both a magnitude (the amount of momentum) and a direction (the direction of the motion).

Given that;

Ft = mv - mu

It then follows that;

F = force

m = mass

v and u are the initial and the final velocities

Thus;

5 * 5 = 5v

v = 25/5

= 5 m/s

The final momentum is thus;

5 m/s * 5 Kg

= 25 Kg m/s

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Find the equivalent​ resistance between points A and B of the resistor combination shown in this figure for the following​ values: R1=1.1Ω,R2=2.1Ω,R3=3.1Ω,R4=4.1Ω,R5 =4.9Ω​. (b) If a potential difference of 11.6V is applied between points A and B, find the potential difference across resistor R4.

Answers

(a) The equivalent resistance between points A and B is 16 Ω.

(b)  The potential difference across resistor R4 is 3 V.

What is the equivalent resistance between points A and B?

To find the equivalent resistance between points A and B, we can use the formula for the equivalent resistance of a series circuit:

R_eq = R1 + R2 + R3 + R4 + R5

Substituting the given values:

R_eq = 1.1 Ω + 2.1 Ω + 3.1 Ω + 4.1 Ω + 4.9 Ω = 16 Ω

To find the potential difference across resistor R4, we can use Ohm's law.

V = IR

I = V / R_eq

I = 11.6 V / 16 Ω = 0.725 A

Since R4 is in series with the other resistors, the same current flows through R4 as through the rest of the circuit. So we can use Ohm's law to find the voltage across R4:

V_R4 = I  x R4

= 0.725 A  x  4.1 Ω

= 3 V

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if 120 waves produced per minute find the frequency​

Answers

The frequency of the wave, given that 120 waves were produced per minutes is 2 Hertz

How do I determine the frequency of the wave?

Frequency is defined as the number of complete oscillations made in 1 second.

From the question given above, the following were obtained:

Frequency (in per minute) = 120 waves per minuteFrequency (in per second) =?

Thus, to obtain the frequency (in per second), we shall convert 120 waves per minute to per second. Details below:

1 wave per minute = 1/60 wave per second

Therefore,

120 wave per minute = 120 × 1/60

120 wave per minute = 2 waves per second

120 wave per minute = 2 Hertz

Thus, we can conclude from the above calculation that the frequency is 2 Hertz

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A laser beam of wavelength 700 nanometers, traveling at a speed of 3.0 x 108 m/s,

is shot from outer space toward earth. What is the frequency of the laser beam?

A. 3.0 x 10^8 Hz

B. 700 x 10^-9 Hz

C. 210 Hz

D. 4.3 x 10^14 Hz

E. 233 x 10^-17 Hz

Answers

Answer:

The correct option is D. 4.3×10¹⁴ Hz

Explanation:

It is because the frequency and the wavelength are inversely proportional to each other.

So, c=f × lambda

And, frequency = velocity/wavelength

The frequency of the laser beam is D. 4.3×10¹⁴ Hz

What is the difference between frequency and hertz (Hz)?

One hertz (Hz) equals one cycle per second. A complete AC or voltage wave is called a cycle. The first half of the cycle is alternating. Period is the time it takes a waveform to complete a complete cycle. Frequency is essentially how often something repeats.

The rate at which the current changes direction in one second is called the frequency. Expressed in hertz (Hz), the international unit of measurement. One hertz equals one cycle per second. 

It is because the frequency and the wavelength are inversely proportional to each other.

So, c=f × lambda

And, frequency = velocity/wavelength

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Complete Question is:

A laser beam of wavelength 700 nanometers, traveling at a speed of 3.0 x 108 m/s,

is shot from outer space toward earth. What is the frequency of the laser beam?

[tex]A. 3.0 x 10^8 HzB. 700 x 10^-9 HzC. 210 HzD. 4.3 x 10^14 HzE. 233 x 10^-17 Hz[/tex]

A 9. 0-v battery is connected to a resistor so that there is a 0. 50-a current through the resistor.

Answers

A resistor is connected to a 9.0V battery with a 0.50A current flowing through it. Then the resistance is 18 Ω.

When a 9.0-volt battery is connected to a resistor, an electric field is created that pushes electrons through the resistor. The voltage of the battery represents the potential energy that each electron has when it enters the circuit, while the resistor creates a resistance that slows down the flow of electrons. According to Ohm's law, the current (I) through a resistor is directly proportional to the voltage (V) applied across it and inversely proportional to the resistance (R) of the resistor. The relationship can be expressed as:

I = V / R

In this case, the current is given as 0.50 A, and the voltage of the battery is 9.0 V.

= R

= V / I

= 9.0 V / 0.50 A

= 18 Ω

So the resistor in the circuit has a resistance of 18 ohms, and it is causing a current of 0.50 A to flow through it when the 9.0-volt battery is connected.

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Question - A 9. 0-v battery is connected to a resistor so that there is a 0. 50-a current through the resistor. Then the resistance is?

A child of mass 30 kg sits on a wooden carosel. The wooden horse is 7.0m from the center of the carousel, which rotates at a constant rate and completes one revolution every 14.1 seconds. What are the magnitude and direction D|p|/dt, the parallel component dp/dt for the child?

Answers

The magnitude of the parallel component of the velocity is 1.4 m/s

The direction is in the direction of rotation of the carousel.

What is the velocity of the child?

The velocity of the child can be calculated using the equation for centripetal acceleration:

a = v^2 / r

where

a = centripetal acceleration (m/s^2)v = velocity of the child (m/s)r = distance from the center of the carousel to the child (m)

Rearranging the equation to solve for velocity:

v = √(ar)

The centripetal acceleration is equal to the square of the angular velocity, w, multiplied by the radius:

a = w^2 x r

where

w = angular velocity (radians/s)

Since the carousel completes one revolution every 14.1 seconds, the angular velocity can be calculated as:

w = 2π / T

w = 2π / 14.1

Now we can calculate the centripetal acceleration:

a = w^2 x r

a = (2π / 14.1)^2 x 7.0

a = 1.41 m/s²

Finally, we can use this value to calculate the velocity of the child:

v = √(ar)

v = √(1.41 x 7.0)

v = 3.14 m/s

The magnitude of the velocity is the scalar value, or the size of the velocity vector without direction.

The direction of the velocity is perpendicular to the radial line connecting the child to the center of the carousel. It is in the direction that the child is moving.

The parallel component of the velocity is in the direction of the rotation of the carousel and can be calculated using the projection of the velocity onto a line tangent to the circle.

dp/dt = v dθ/dt

where

dθ/dt = angular velocity (radians/s)

Substituting the values for velocity and angular velocity:

dp/dt = vw

= 3.14 x (2π / 14.1)

v = 1.4 m/s

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Kangaroos have been clocked at speeds of 65 km/h
How far can a kangaroo hop in 3.90 minutes at this speed?
(part a)
How long will it take a kangaroo to hop 0.20 km
at this speed?
(part b)

Answers

a) 4225m or 4.225km b) 11.1s

For part a; convert 65km/h to km/min, to do so all you do is divide 65/60 as there are 60 minutes per hour. Afterwards, multiply by 3.90 to find the distance travelled in 3.90mins.

For part b; convert km/h to km/s, in this one we divide 65/3600 as there are 3600 seconds in one hour. Then, using the S = D/T, where S = speed, D = distance and T= time, we isolate for T and get T = D/S. So then we sub for T=0.20/0.018 (0.018 is the product of 65/3600) and we get T=11.1s.

If two bowling balls were to collide head on and bounce off one another, with no loss in kinetic energy, the collision would be considered a(n) ___________ collision.
A.Reversable
B.Cushy
C.Perfectly Inelastic
D.Elastic​

Answers

D. Elastic because that's what an elastic collision is.

You will now use the observations you have made so far to predict what the strength of the field will be at point (0, 50).A. Using the right-hand rule, which direction is the magnetic field at (0, 50)?B. Since the magnetic field of the Earth and the induced field are at right angles, you can use the Pythagorean Theorem to determine the strength of the combined field.

Answers

In A. part, the magnetic field at (0, 50) is in west direction. In B. part, the strength of the field at (0,50) is 2.06 G.

A. The current is flowing up for west as shown by the front view figure at the bottom of the gadget. Your fingers will curve to the west if you wrap your right hand around the wire with your thumb up. Put a compass at (0,50) to check the direction as well. It indicates west.

B. By using the Pythagorean Theorem to determine the strength of the combined field, the strength of the field at (0,50) is 2.06 G.

The earth's magnetic field strength= 0.50 G

The induced current magnetic field strength= 2.0

B is given by=

[tex]\sqrt{0.50^{2} - 2.00^{2} }\\ =\sqrt{0.25-4.00}\\ =2.06[/tex]

Hence, we can also check by putting the probe on (0,50) and the probe reads 2.06 G.

Therefore, the strength of the field at (0,50) is 2.06 G.

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Could you please help with the attached question?

Answers

the work done by the ball is 38.72 J.

define work done ?

In physics, work is defined as the product of force and displacement. It is a measure of the energy transferred when a force is applied over a distance, resulting in the displacement of an object. Mathematically, work is represented by the formula:

Work = Force x Distance x Cos(theta)

where Force is the applied force, Distance is the displacement of the object, and theta is the angle between the force and the displacement vectors. The unit of work is the Joule (J), which is equivalent to one Newton-meter (N·m). Work can be positive, negative, or zero, depending on the direction of the force and displacement. If the force is in the same direction as the displacement, work is positive, and if the force is in the opposite direction to the displacement, work is negative. If the force and displacement are perpendicular, the work is zero.

Work = Force x Distance x Cos(theta)

where:

Force = 484 N (given)

Distance = 8 cm = 0.08 m (given)

Cos(theta) = 1 (since the force and displacement are in the same direction)

Plugging in the values, we get:

Work = 484 N x 0.08 m x 1

Work = 38.72 Joules (J)

Therefore, the work done by the ball is 38.72 J.

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what kind of Electromagnetic energy does a car light have

Answers

Answer:

Halogen

Explanation:

Answer:

A car light emits visible light, which is a type of electromagnetic energy.

Explanation:

(iii) The area of the piston is 5.0 x 10-³m². Calculate the weight that is added to the piston.(the initial pressure is 105000 and the final is 140000, the air decreases from 860 cm3 to 645cm3)​

Answers

The weight added to the piston is 175 N.

What is the weight that is needed?

The weight that is added to the piston can be calculated using the Ideal Gas Law, which states that PV = nRT

where;

P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature.

Since the initial pressure, volume, and temperature are known, we can use the Ideal Gas Law to find the number of moles of gas, n.

Then, we can use the equation for pressure force, to find the weight added to the piston.

F = PA

where;

A is the area of the piston, .

First, we'll find the initial number of moles of gas:

P1V1 = nRT

n = P1V1 / RT

T = 298 K is the temperature (room temperature)

n = (105000 Pa x 860 cm^3) / (8.31 J/mol.K  x 298 K)

Next, we'll find the final number of moles of gas:

P2V2 = nRT

n = P2V2 / RT

n = (140000 Pa x 645 cm^3) / (8.31 J/mol.K  x  298 K)

Now, we have the number of moles of gas for both the initial and final conditions, and we can calculate the change in number of moles of gas, ∆n:

∆n = n2 - n1

Finally, we can use the equation for pressure force to find the weight added to the piston:

F = PA

∆F = P2A - P1A

∆F = (140000 Pa - 105000 Pa) x 5.0 x 10^-3 m^2

∆F = 35000 Pa x 5.0 x 10^-3 m^2

∆F = 175 N

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Which of the following statements concerning momentum is true?* A.Momentum is a scalar quantity. B.The momentum of an object is always positive. C.Momentum is a force. D.Momentum is a vector E.The SI unit of momentum is the Newton.​

Answers

The correct answer is D

A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 4.0 m/s. Two seconds later the bicyclist hops on his bike and accelerates at 2.2 m/s2 until he catches his friend.
How much time does it take until he catches his friend (after his friend passes him)?
(part a)
How far has he traveled in this time?
(part b)
What is his speed when he catches up?
(part c)

Answers

a) It takes the bicyclist 9.09 seconds to catch up to his friend.

b) The bicyclist has traveled 40.0 meters in 9.09 seconds to catch up to his friend.

c) The bicyclist is moving at a speed of 20.0 m/s when he catches up to his friend.

The Time, Distance and Speed involved

a) To find out how much time it takes for the bicyclist to catch up to his friend, we need to use the equation for motion with constant acceleration:

d = v_0 t + 0.5 a t^2

where d is the total distance traveled,

v_0 is the initial velocity (0 m/s in this case),

t is the time, and a is the acceleration (2.2 m/s^2).

Since the friend was already moving at a constant speed of 4.0 m/s when the bicyclist started pedaling, we know that the total distance d that the bicyclist has to travel to catch up is equal to 4.0 m/s * t + 0.5 * 2.2 m/s^2 * t^2.

Setting d equal to 4.0 m/s * t, we can solve for t:

4.0 m/s * t = 4.0 m/s * t + 0.5 * 2.2 m/s^2 * t^2

0.5 * 2.2 m/s^2 * t^2 = 0

t = sqrt(0 / (0.5 * 2.2 m/s^2)) = 0 s

Since the square root of zero is zero, the time t is also zero. This means that the bicyclist starts moving at the same time as the friend, so he needs to accelerate for the entire time to catch up.

Using the equation for motion with constant acceleration, we can find the time t it takes for the bicyclist to catch up:

d = v_0 t + 0.5 a t^2

d = 4.0 m/s * t

4.0 m/s * t = 0 m/s * t + 0.5 * 2.2 m/s^2 * t^2

4.0 m/s = 0.5 * 2.2 m/s^2 * t

t = 4.0 m/s / (0.5 * 2.2 m/s^2) = 9.09 s

So it takes the bicyclist 9.09 seconds to catch up to his friend.

b) To find out how far the bicyclist has traveled in this time, we can use the equation for motion with constant acceleration again:

d = v_0 t + 0.5 a t^2

d = 0 m/s * 9.09 s + 0.5 * 2.2 m/s^2 * 9.09 s^2

d = 40.0 m

So the bicyclist has traveled 40.0 meters in 9.09 seconds to catch up to his friend.

c) To find out the bicyclist's speed when he catches up, we can use the equation for velocity:

v = v_0 + a * t

v = 0 m/s + 2.2 m/s^2 * 9.09 s

v = 20.0 m/s

So the bicyclist is moving at a speed of 20.0 m/s when he catches up to his friend.

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A ball strikes the floor for 0.0105 s and experiences a change in momentum of 1.52 kg·m/s. What is the force experienced by the ball?​

Answers

Answer:The concept of momemtum will be used to solve this question.A moving body's momemtum, which is generally equal to the product of the body's mass and velocity, is a quality that the body has as a result of its mass and motion.

Explanation:

A wagon is push on a frictionless surface with a force of 10 Newtons. The acceleration of the wagon is measure to be 10/m/s/s. The same wagon is then pushed on a frictionless surface with a force of 20 Newtons. What is the new acceleration of the wagon? Explain why you chose your answer.

Answers

The new acceleration of the wagon is 20 m/s.

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

Thus, the acceleration of the wagon pushed with a force of 10 Newtons can be calculated using the formula:

                                               a = F/m

Where,

a is the acceleration,

F is the net force, and

m is the mass of the wagon.

Given that the force is 10 Newtons and the acceleration is 10 m/s/s, we can solve for the mass of the wagon, which is:

                             m = F/a = 10 N / 10 m/s = 1 kg

Now, if the same wagon is pushed with a force of 20 Newtons, the new acceleration can be calculated using the same formula:

                                               a' = F'/m

Where,

a' is the new acceleration,

F' is the new net force, and

m is the mass of the wagon.

Substituting the values, we get:

a' = 20 N / 1 kg = 20 m/s/s

Therefore, the new acceleration of the wagon is 20 m/s/s when it is pushed with a force of 20 Newtons on a frictionless surface.

This result shows that the acceleration of the wagon is directly proportional to the net force acting on it, as predicted by Newton's Second Law.

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a cyclist while negotiating a circular path with speed of 20m/s is found to be bend at angel of 30° with vertical what is the radius of the circular path​

Answers

The minimum radius of the circular path for the cyclist traveling at a speed of 20 m/s and a tilt angle of 30° is approximately 17.32 meters.

What is the radius of the circular path​?

The formula for the minimum radius of a circular path for a cyclist traveling at a certain speed can be determined using the relationship between the speed, the angle of tilt, and the gravitational force acting on the cyclist.

The minimum radius of the circular path can be calculated using the formula:

r = (v^2) / gtan(θ)

where:

r = radius of the circular path (m)v = speed of the cyclist (m/s)g = acceleration due to gravity (9.8 m/s^2)θ = angle of tilt (30° in this case)

Plugging in the values, we get:

r = (20^2) / (9.8 x tan(30°))

r ≈ 17.32 m

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A transformer has a primary coil with 175 turns of wire and a secondary coil with 700 turns. An AC voltage source connected across the primary coil has a voltage given by the function
Δv = (200 V)sin(t).
What rms voltage (in V) is measured across the secondary coil?

Answers

The rms voltage measured across the secondary coil is 565.68 V.

What does rms value mean?

The root mean square (RMS) value of an alternating current (AC) or voltage is the equivalent steady direct current (DC) value that produces the same heating effect or power dissipation in a resistor. In other words, it is the DC voltage or current that would produce the same amount of heat as the AC voltage or current over a given time period.

The rms voltage (V_rms) across the secondary coil can be calculated using the formula:

V_rms,secondary = (N_secondary/N_primary) * V_rms,primary

where N_secondary is the number of turns in the secondary coil, N_primary is the number of turns in the primary coil, and V_rms,primary is the rms voltage across the primary coil.

The rms voltage across the primary coil can be found from the given voltage function:

V_rms,primary = (1/√2) * V_peak,primary

where V_peak,primary = 200 V is the peak voltage across the primary coil.

Substituting the values, we get:

V_rms,primary = (1/√2) * 200 V = 141.42 V

Now, using the formula above, we can calculate the rms voltage across the secondary coil:

V_rms,secondary = (700/175) * 141.42 V = 565.68 V

Therefore, the rms voltage measured across the secondary coil is 565.68 V.

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What things would be difficult or impossible if you were born deaf? One teacher of the deaf said that being deaf is analogous to being in a soundproof booth while a person outside is trying to teach you Japanese. Actually, she said, you (as a hearing person) have the easier job because you know what you are expected to do, and you can hear yourself speaking. The deaf child does not and cannot.

Answers

Answer:

you would have difficulty hearing on a daily basis, as mentioned in the example, but you would also have trouble getting jobs, you would have fewer educational opportunities, and also a lack of awareness of your everyday surroundings.

Explanation:

Which of the following are properties of conductors?

I. Holes in the lattice allow the electricity to flow through.
II. Electricity flows easily through this type of material.
III. A few electrons in every atom are loosely held by the nuclei.

A. I only
B. II only
C. I and II
D. II and III

Answers

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Lets examine all three properties stated here ~

I) holes in lattice allow the electricity to flow through ?

- holes aren't a majority charge carrier in a conductor, in conductors electricity is conducted by free elecrons. so this statement is incorrect.

ll) Electricity flows easily through this type of material?

- That's true, conductors (usually metals) have free electrons to conduct electricity, which is responsible for good electricity Conductivity.

lll) A few electrons in every atom are loosely held by the nuclei.

- That's also true, Conductors (mainly metals) have a few electrons (say, 1, 2 or maybe 3) in there valence shell which experience quite less force of attraction from nucleus, hence they are free to move around the whole conductor randomly, making a sea of electrons.

So, the correct choice will be : D) ll and lll

Sandra who is a Level 200 student of SoE and also a snowboarder starts from rest at the top of a double black diamond hill. As she rides down the slope, GPS coordinates are used to determine her displacement as a function of time: x=0.5t3 + 6t2 +3t where x is in metres and t is in seconds. where x and t are expressed in feet and seconds, respectively. a) Determine the position of the boarder when t = 4 s b) Determine the velocity of the boarder when t = 4s c) Determine the acceleration of the boarder when t = 4s 2021/22​

Answers

Explanation:

a) To determine the position of the snowboarder when t = 4 seconds, we can substitute t = 4 into the equation x = 0.5t^3 + 6t^2 + 3t:

x = 0.5 * 4^3 + 6 * 4^2 + 3 * 4

x = 64 + 96 + 12

x = 172

So when t = 4 seconds, the snowboarder's position is 172 meters.

b) To determine the velocity of the snowboarder when t = 4 seconds, we'll need to find the first derivative of the displacement function x = 0.5t^3 + 6t^2 + 3t with respect to time:

dx/dt = 3 * 0.5 * t^2 + 2 * 6 * t + 3

Next, we can substitute t = 4 into this expression to find the velocity when t = 4 seconds:

dx/dt = 3 * 0.5 * 4^2 + 2 * 6 * 4 + 3

dx/dt = 72 + 48 + 3

dx/dt = 123

So the velocity of the snowboarder when t = 4 seconds is 123 meters per second.

c) To determine the acceleration of the snowboarder when t = 4 seconds, we'll need to find the second derivative of the displacement function x = 0.5t^3 + 6t^2 + 3t with respect to time:

d^2x/dt^2 = 6 * 0.5 * t + 2 * 6

Next, we can substitute t = 4 into this expression to find the acceleration when t = 4 seconds:

d^2x/dt^2 = 6 * 0.5 * 4 + 2 * 6

d^2x/dt^2 = 24 + 12

d^2x/dt^2 = 36

So the acceleration of the snowboarder when t = 4 seconds is 36 meters per second squared.

A rope of length L is clamped at both ends. Which one of thefollowing is not a possible wavelength for standing waves on thisrope?

a. L/2
a. 2L/3
c. L
d. 2L
e. 4L

Answers

If rope of length L is clamped at both ends then, 4L is not a possible wavelength for standing waves on this rope.

A string's shortest wavelength is L = λ/2. There is a node where the rope is clamped; at this point, the rope is fixed at zero and cannot travel up or down. Therefore, this is λ/2 if the rope's midsection is oscillating up and down. There are two visible loops if there is a node in the middle of the rope, which indicates that there are 2λ/2. The options are 3λ/2, 4λ/2, etc. So, aside from b, all other methods work.

You would have 2/3 of a wavelength if b were accurate. One of the nodes would have to be moving up and down as a result.

Every circle in my lovely image is a node; they appear every half-wavelength. Note that the square, which is at a wavelength of 2/3, is not a node. A standing wave cannot contain wavelengths that are divided into thirds.

Only standing waves whose length is an integral multiple of half wavelength can occur in a string that is fixed at both ends.

L = n* (λ/2)

Only in instance (e) is n = 1/2, and that is unacceptable.

(e) is the proper response.

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A soccer ball is kicked with a speed of 15.6 m/s
at an angle of 52.5 ∘
above the horizontal.
If the ball lands at the same level from which it was kicked, for what amount of time was it in the air?

Answers

According to the question the soccer ball was in the air for a total of 2.26 seconds.

What is air?

Air is a mixture of gases made up of nitrogen (78%), oxygen (21%), and other trace gases like argon and carbon dioxide (1%). This mixture of gases makes up a unseen fluid we call air. It is all around us, surrounding us and filling the space between us and the Earth.

The time that the soccer ball was in the air can be determined using the kinematic equations of motion. First, we need to calculate the initial vertical and horizontal velocity components of the ball when it is kicked. The vertical velocity component is given by Vy = V*sin(angle) = 15.6 m/s * sin(52.5°) = 11.2 m/s.

The horizontal velocity component is given by Vx = V*cos(angle) = 15.6 m/s * cos(52.5°) = 9.2 m/s.

Now we can solve for time using the equation t = (2*Vy)/g, where Vy is the vertical velocity component and g is the acceleration due to gravity (9.8 m/s2). Thus, t = (2*11.2 m/s)/9.8 m/s2 = 2.26 s.

Therefore, the soccer ball was in the air for a total of 2.26 seconds.

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. You are standing on a bathroom scale inside an elevator. Your weight is 140 lb, but the reading of
the scale is 120 lb. The scale reads the magnitude of the normal force. Note: 1 lb = 4.448 N.
a) What is the magnitude and direction of the acceleration of the elevator? {1.40 m/s²}
b) Can you tell whether the elevator is speeding up or slowing down? EXPLAIN.

Answers

The magnitude of the acceleration of the elevator is approximately 1.40 m/s², and it is directed downwards.

What is acceleration?

Every procedure where the velocity varies is referred to as acceleration. There are only two methods to accelerate because velocity is a function of both speed and direction: changing your speed, changing your direction, or changing both.

Since the scale reads the magnitude of the normal force, we can equate the normal force with the weight of the person:

N = mg

N = (140 lb) * (4.448 N/lb) = 622.72 N

The scale reads 120 lb, which is equivalent to:

N' = (120 lb) * (4.448 N/lb) = 533.28 N

The magnitude of the acceleration can be calculated as:

ma = mg - N'

a = (g * m) - (N' / m) = [(9.81 [tex]m/s^2[/tex]) * (63.5 kg)] - (533.28 N / 63.5 kg) ≈ 1.40 [tex]m/s^2[/tex]

The elevator could be moving downwards at a constant velocity or accelerating downwards at a rate that is less than the acceleration due to gravity.

Thus, 1.40 [tex]m/s^2[/tex]  is the magnitude and direction of the acceleration and

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