A woman on a snowmobile moving with a constant velocity east down the road fires a flare straight upward and the snowmobile continues to move with a constant
velocity as the flare is in the air. Assume no air resistance. Where will the flare land?

A) it will hit the person on the snowmobile who fired the flare
B) Somewhere behind the snowmobile, depends on velocity
C) in front of the snowmobile
D) Impossible to know
E) behind the snowmobile in exactly the same location (relative to the ground) from which it was fired

Answer:

When moisture is removed from air, its density increases. The speed of sound in a humid air is inversely proportional to the square root of its density. Therefore, the speed of sound in moist air is humidity increases, the velocity of sound increase and vice-versa.

Hope it helps :)

Answer:

B

Explanation:

I think this is right.

If it is Good luck!

The controlled experiment includes a control group and an experiment group, this statement describes a controlled experiment, therefore the correct answer is option B.

Scientific discovery is the method of finding solutions through in-depth analysis and discovering them through the outcomes of experiments.

True experimental outcomes that can be backed up by data are incredibly important to scientific inquiry.

A regulated investigation where all sensors to measure have been held constant and the scientific element is utilized as a factor associated.

Since the statement depicts a controlled experiment with a control group and an experiment group, option B is the appropriate response.

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Answer:

A

Explanation:

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The tip of the thermometer is heated through radiation from the person's body. The particles of the thermometer tip then transfer heat by the convection of heat through the liquid inside of it. The particles inside the liquid then convert heat which causes the warmer particles to slow down, rise, and expand. Thus, the correct option is A.

The process of heat transfer from one part of a fluid to another part of the system or fluid through the actual movement of the particles of the fluid substance is called convection. Liquid and gas particles are heated through the process of convection.

The tip of the thermometer is heated by radiation from the person's body. The particles of the thermometer tip then transfer heat energy through convection of heat through the liquid inside of the thermometer. The particles inside the liquid then convert heat causing the warmer particles to slow down, rise, and expand in the thermometer.

Therefore, the correct option is A.

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Answer:

100 mph.

Explanation:

Given that,

Distance covered by an object is 500 miles in 5 hours.

We need to find the average velocity of the object. It can be given by :

[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500\ \text{miles}}{5\ \text{hour}}\\\\v=100\ \text{mph}[/tex]

Hence, the average velocity of the object is 100 mph.

Answer:

Mass and speed.

Explanation:

The amount of kinetic energy of an object depends on the object's mass and speed.

Answer:

its a motion hope this helps

Explanation:

Answer:

The answer is below

Explanation:

NSPT is an acronym for the National Service Training Program. It deals with the individual's role in society building. Most specifically, the youths in areas such as physical, ethical, virtuous, intellectual, and social well-being.

One can serve the community through the NSTP subject, by involving in creating awareness in literacy and social welfare undertakings, mostly during emergencies and mishaps, or be part of the Citizen Armed Force.

Answer:

The magnitude of the average acceleration of the ball during this time interval is 10,449.44 m/s²

Explanation:

Given;

mass of super ball, m = 50 g

initial velocity of the ball, u = 25.5 m/s

final velocity of the ball, v = -21 m/s (re-bouncing backward)

time in contact with the wall, t = 4.45 ms = 0.00445 s

The average acceleration of the ball during this time interval is given by

[tex]a = \frac{dv}{dt} = \frac{v-u}{t} \\\\a = \frac{-21-25.5}{0.00445}\\\\a = -10449.44 \ m/s^2\\\\|a| = 10,449.44 \ m/s^2[/tex]

Therefore, the magnitude of the average acceleration of the ball during this time interval is 10,449.44 m/s²

Recall that

[tex]{v_f}^2={v_i}^2+2a\Delta y[/tex]

where [tex]v_i[/tex] and [tex]v_f[/tex] are the lion's initial and final vertical velocities, [tex]a[/tex] is its acceleration, and [tex]\Delta y[/tex] is the vertical displacement.

At its maximum height, the lion has 0 vertical velocity, so we have

[tex]0={v_i}^2-2gy_{\rm max}[/tex]

where g is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that [tex]\Delta y=y_{\rm max}-0=y_{\rm max}[/tex].

Let v denote the initial speed of the jump. Then

[tex]v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}[/tex]

The initial speed will be "11.7 m/s".

Given:

We know,

→ [tex]vf^2=v_i^2+2a\Delta y[/tex]

At max. height, vertical height be zero, then

→ [tex]0 = v_i^2-2gy_{max}[/tex]

or,

→ [tex]\Delta y = y_{max} -0 = y_{max}[/tex]

now,

The initial speed,

→ [tex]v_i = v \ Sin(43.2^{\circ})[/tex]

By substituting the values,

      [tex]= \sqrt{1\times 9.8\times 3.25}[/tex]

      [tex]= 11.7 \ m/s[/tex]

Thus the solution above is correct.

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Answer:

246ft/min

Explanation:

In this problem we are faced with unit conversion.

We are expected to convert from km/h to ft/min

Given that

1.00 m = 3.28 ft

1km(1000m)= 3280 ft

But we need to convert 4.5km to ft

Hence in ft 4.5km= 3280*4.5

= 14760ft

We now convert hour to minutes

60min make 1 hour

Therefore the convert form km/h to ft/min is

= 14760/60= 246ft/min

The answer is 246ft/min

Answer:

A: leaving a copper penny in vinegar until it turns green

Explanation:

The corrosion is from oxidation -- a chemical reaction between the metal and oxygen, water, and carbon dioxide in the air. Rust is the term used to describe this process when it happens to iron instead of other metals. I also took it on E2020. If you need further explanation, please comment below.

The laboratory activity which involves a chemical change is leaving a copper penny in vinegar until it turns green.

The chemicals are the artificially prepared or purified and a distinct compound or substance.

The corrosion is the result of oxidation that is a chemical reaction between the metal and oxygen, water, and carbon dioxide in the air. Rust is the term used to describe the corrosion process.

Corrosion also takes place in copper due to which the copper turns green when oxidized.

Thus, The laboratory activity which involves a chemical change is leaving a copper penny in vinegar until it turns green.

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Answer:

Isothermal :   P2 = ( P1V1 / V2 ) ,  work-done [tex]pdv = nRT * In( \frac{V2}{v1} )[/tex]

Adiabatic : : P2 = [tex]\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }[/tex]  , work-done =

W = [tex](3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)[/tex]

Explanation:

initial temperature : T

Pressure : P

initial volume : V1

Final volume : V2

A) If expansion was isothermal calculate final pressure and work-done

we use the gas laws

= PIVI = P2V2

Hence : P2 = ( P1V1 / V2 )

work-done :

[tex]pdv = nRT * In( \frac{V2}{v1} )[/tex]

B) If the expansion was Adiabatic show the Final pressure and work-done

final pressure

[tex]P1V1^y = P2V2^y[/tex]

where y = 5/3

hence : P2 = [tex]\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }[/tex]

Work-done

W = [tex](3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)[/tex]

Where    [tex]T2 = T1V1^(2/3)/V2^(2/3)[/tex]

Answer:

a)   S = 2.35 10³   J/m²2 ,  

b)and the tape recorder must be in the positive Z-axis direction.

the answer is 5

c) the direction of the positive x axis

Explanation:

a) The Poynting vector or intensity of an electromagnetic wave is

          S = 1 /μ₀ E x B

if we use that the fields are in phase

          B = E / c

we substitute

         S = E² /μ₀ c

let's calculate

        s = 941 2 / (4π 10⁻⁷  3 10⁸)

        S = 2.35 10³   J/m²2

b) the two fields are perpendicular to each other and in the direction of propagation of the radiation

In this case, the electro field is in the y direction and the wave propagates in the ax direction, so the magnetic cap must be in the y-axis direction, and the tape recorder must be in the positive Z-axis direction.

the answer is 5

C) The poynting electrode has the direction of the electric field, by which or which should be in the direction of the positive x axis

Answer:

A conventional bomb releases most of its energy in the form of blast. Atomic bombs on the other hand, release 50 per cent energy as blast, 35 per cent as heat and 15 per cent as nuclear radiation.

Explanation:

A conventional bomb releases most of its energy in the form of blast. Atomic bombs on the other hand, release 50 per cent energy as blast, 35 per cent as heat and 15 per cent as nuclear radiation.

Answer:

Travelled 18 km, they are 6 km from home.

Explanation:

12/2 (halfway) is 6km. So, 6 + 12 would be 18 km, total amount travelled. The total distance of the trip would be 24 km (12 km out, 12km back) if they travelled 12+6 (18km) then they only have 6 km more to go.

Answer:

Protons

Explanation:

The Proton is one of the subatomic particles that are found in the nucleus of an atom. The protons are positively charged. They have an electric charge of 1.6 * 10^-19 C. Protons have an approximately 1 atomic mass unit, or otherwise called, 1 amu.

One or more protons, at least, are found in every nucleus if an atom, as they are an essential and very necessary part of the nucleus. Ernest Rutherford, in 1920, named protons, proton

Explanation:

Given that,

A ball is tossed straight up with an initial speed of 30 m/s

We need to find the height it will go and the time it takes in the air.

At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :

v = u +at

Here, a = -g

v = u -gt

i.e. u = gt

[tex]t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s[/tex]

So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds

Let d is the maximum distance covered by it.

[tex]d=ut-\dfrac{1}{2}gt^2[/tex]

Putting all values

[tex]d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m[/tex]

Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.

Answer:

The equation is missing in the question. The equation is [tex]$10 m + 5(m/s^2)t^2+3(m/s^3)t^3$[/tex]

a). [tex]$v=10 t +9t^2$[/tex] , the horse will not turn.

b). a(t) = 10 + 18t

Explanation:

Given :

[tex]$x(t)=10 m + 5(m/s^2)t^2+3(m/s^3)t^3$[/tex]

∴ At t =0, x = 10 m

a). Velocity as a function of time

[tex]$v = \frac{dx}{dt} $[/tex]

  = [tex]$10 t +9t^2$[/tex]

Turning velocity must be zero.

v(t) = 0

[tex]$10 t +9t^2=0$[/tex]

[tex]$\therefore t = 0 \text{ or}\ t =-\frac{10}{9}$[/tex]

Taking the positive value of time.

The horse will not turn.

b). Acceleration as a function of time.

[tex]$a(t)=\frac{dv}{dt}$[/tex]

     = 10 + 18t

∴ a(t) = 10 + 18t

Answer: Always accelerates in a downward direction

Explanation: Gravity is pulling the ball downward

Answer:

the correct  is a  Strongly ATTRACTIVE

Explanation:

For this exercise we must use that charges of the same sign repel and charges of the opposite sign attract, the attraction is strong if they are charged or weak if the charges are induced.

Let's apply this to our case.

The test load T is attracted by the sphere A, this implies that the charges are of different sign

the test charge T is repelled by the sphere B, therefore the charges are of equal sign

As the test charge cannot change the sign, this implies that the spheres A and B are of different sign, therefore attractive forces.

Now let's analyze the intensity, as in the exercise they indicate that spheres A and B are charged and are insulators, these charges cannot move, so the attraction must be Strong.

When reviewing the statements, the correct one is a  Strongly ATTRACTIVE

Answer: Regardless of their weight, before opening their parachutes, the guys fell at the same velocity.

According to the data, the acceleration due to gravity is 9.8 m/s/s

Opening the parachutes provided air resistance and changed their velocity.

Explanation:

When in free fall, mass does not affect the speed of moving objects (only gravitational force is acting upon it).

If you take a look at the data, you can see that the velocity is increasing at a constant rate in intervals of 9.8. This is the acceleration which makes sense because acceleration is the change of velocity divided by time.

Think about it: parachutes slow down the object that is falling because it creates a barrier between the object falling and the gravitational force it encounters. The change in the effects of the gravitational force will alter the velocity.

I hope this was helpful. Have a nice day!

Answer:

The voltage drop across the wire is 2 V

Explanation:

Given;

length of wire, L = 10 m

current density, I/A, μ = 4 x 10⁶ (A/m²)

wire conductivity, σ = 2 x 10⁷ (S/m)

The resistivity of wire is given by;

[tex]\rho = \frac{RA}{L} \\\\But \ R = V/I\\\\\rho = \frac{VA}{IL}[/tex]

Conductivity, σ = ¹/ρ

[tex]\sigma = \frac{IL}{VA}\\ \\V = \frac{IL}{ A \sigma}\\\\V = (\frac{I}{A})\frac{L}{\sigma}\\ \\V = (\mu)\frac{L}{\sigma}\\\\V = (4*10^{6} )*\frac{10}{2*10^{7} } \\\\V = 2 \ V[/tex]

Therefore, the voltage drop across the wire is 2 V

Answer:

a. a = eb/2ε₀m b. b = 8.91 × 10⁻¹⁸ kg/V

Explanation:

a. Using Gauss' law

ε₀∫E.dA = q where E = electric field and q = charge enclosed.

Now , the charge has  a spherical symmetric charge density ⍴(r) = b/r, the total charge enclosed at distance r is given by

q = ∫∫∫ρ(r)r²sinθdrdθdΦ

q = ∫∫∫(b/r)r²sinθdrdθdΦ

q = ∫∫∫brsinθdrdθdΦ

we integrate r from 0 to r, θ from 0 to π and Φ from 0 to 2π

q = ∫∫br[∫sinθdθ]drdθdΦ

q = ∫∫br[-cosθ]drdΦ

q = ∫∫br-[cosπ - cos0]drdΦ

q = ∫∫br-[-1 - 1]drdΦ

q = ∫2brdr∫dΦ

q = ∫2brdr[Φ]

q = ∫2brdr[2π - 0]

q = 4πb∫rdr

q = 4πb[r²/2]

q = 4πb[r²/2 - 0]

q = 2πbr²

The let side of the equation is

ε₀∫E.dA = ε₀E∫dA = ε₀E4πr² since there is spherical symmetry

Equating both sides of the equation

ε₀E4πr² =  2πbr²

E =  2πbr²/ε₀4πr²

E = b/2ε₀

Now, the force acting on the electron , F = ma where m = mass of electron and a = acceleration of electron.

F also equal F = eE where e = electron charge and E = electric filed acting on electron

So, eE = ma

a = eE/m

a = eb/2ε₀m

b. I(f the electron is released from rest and is to reach the center of the earth, it covers a distance of the radius of the earth. Using s = ut + 1/2at² where s = radius of earth = R = 6400 km = 6.4 × 10⁶ m  , u = initial velocity = 0 m/s. and a = eb/2ε₀m. Substituting these values into s we have

R = 0t + 1/2(eb/2ε₀m)t²

R = ebt²/4ε₀m

making b subject of the formula, we have

b = 4ε₀mR/et²

when t = 12 s and e = 1.609 × 10⁻¹⁹ C, ε₀ = 8.854 × 10⁻¹² F/m and m = 9.109 × 10⁻³¹ kg.

Substituting these values into b we have

b = (4 × 8.854 × 10⁻¹² F/m × 9.109 × 10⁻³¹ kg × 6.4 × 10⁶ m)/(1.609 × 10⁻¹⁹ C × 12²)

b = 2064.67/ 231.696 × 10⁻¹⁸

b = 8.91 × 10⁻¹⁸ Fkg/C

b = 8.91 × 10⁻¹⁸ kg/V

Answer:

in pretty sure the last one

The qualities of objects do gravity depend on Each object's mass and the distance between them. Hence the correct option is (4).

Gravity is the force of attraction between two objects with mass. The strength of the gravitational force depends on the mass of each object and the distance between them.

The mass of an object refers to the amount of matter it contains. The greater the mass of an object, the stronger its gravitational pull.

The distance between two objects is also a crucial factor. The gravitational force weakens as the distance between the objects increases. In other words, the force of gravity decreases with increasing distance.

So, the two qualities that gravity depends on are each object's mass and the distance between them.

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Answer: D (2000 J)

Explanation: p= 200 W

t= 10 s

E=pt

E=200 W * 10s

E= 2000 J

Answer:

it is D.

Explanation:

Answer:

just trace a picture of it.

Answer:

[tex]H_1 =39.05 \ m[/tex] OR [tex]H_2 =14.5 \ m)[/tex]

Explanation:

From the question we are told that

The constant speed of the balloon is [tex]v = 6.60 \ m/s[/tex]

The height of the balloon is [tex]h = 11.0 \ m[/tex]

The initial speed of the pellet is [tex]u = 30 \ m/s[/tex]

Generally the height of the balloon at the point it is the same altitude with the pellet is mathematically represented as

[tex]H = h + v * (t)[/tex]

Note: vt is the distance covered by the balloon before the pellet got to it

Generally the height of the pellet when it is the same height with the balloon is mathematically represented using kinematics equation

[tex]s = ut + \frac{1}{2} gt^2[/tex]

So

H = s

=> [tex] ut + \frac{1}{2} gt^2 = h + v * (t)[/tex]

=> [tex] 30t + \frac{1}{2} *( -9.8)t^2 = 11 + 6.60t[/tex]

=> [tex] 4.9t^2 -23.4t + 11= 0[/tex]

using the quadratic formula to solve the above equation

From the quadratic formula calculation

[tex]t_1 = 4.25 \ s[/tex]

   OR

     [tex]t_1 =  0.529  \  s[/tex]

So the height of this two place above the ground is mathematically evaluated as

[tex]H_1 = h + v * (4.25)[/tex]

[tex]H_1 = 11 + 6.60 * (4.25)[/tex]

[tex]H_1 =39.05 \ m[/tex]

OR

[tex]H_2 = h + v * ( 0.529)[/tex]

[tex]H_2 = 11 + 6.60 * (0.529)[/tex]

       [tex]H_2  =14.5 \  m)[/tex]

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. [tex]1/r^2[/tex].

e. [tex]r^2[/tex].

Answer:

The  correct option is  C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

    [tex]V  =  \frac{k  Q  }{r }[/tex]

Here we can deduce that the electric potential varies inversely with the distance i.e

      [tex]V  \  \alpha \  \frac{1}{r}[/tex]

So

The potential should vary with distance from the point charge r should be option c. 1/r.

The point charge with respect to the electric potential should be expressed in

V = KQ/r

Here we can say that the electric potential should be varied oppositely with the distance

Here is the electric file with respect to the point charge should be obtained from the Coulomb law. It should be radially outward from the point charge in all types of directions.

Therefore, the option c is correct.

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