A workman stands on the roof of a 10 meter high building. Another worker tosses him a tool from the ground, which the first workman catches as the tool is falling to the ground. If the total time the tool is in the air is 2.5 seconds, what speed did the worker toss the tool into the air initially?

By applying the wave equation, the wavelength is 2.68 meters.

We need to know about wave equations to solve this problem. The displacement of the wave on the y-axis can be explained by the wave equation

y = A cos (kx - ωt)

where y is y-axis displacement, A is amplitude, k is wave number, x is x-axis displacement, ω is angular speed and t is time.

the wavenumber and angular speed of the wave equation can be determined respectively by

k = 2π / λ

ω = 2πf

where k is the wavenumber, λ is wavelength and f is frequency.

From the question above, we know that:

f = 0.5 Hz

A = 0.35 m

v = 1.34 m/s

When the amplitude is doubled, it doesn't affect the wavelength. Hence

v = λ . f

1.34 = λ . 0.5

λ = 2.68 m

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The acceleration of the car will be -5.68 m/s, and it travels 13.76 m before stopping.

Acceleration is the general term for any process where the velocity changes. There are only two ways to accelerate: either by increasing speed or decreasing direction, or both. The reason for this is that velocity includes both a speed and a direction.

You cannot possibly be accelerating if you don't also change your direction and speed, regardless of how swiftly you are travelling.

It is a vector quantity with m/s² as its SI unit.

According to the question, the given values are :

Initial speed, u=12.5 m/s,

Final speed, v=0 and,

Time, t=2.20 seconds.

Now by using equations of motion :

v= u+at

0=12.5 m/s+a(2.20 s)

a=-12.5/2.20

a= -5.68 m/s

Now distance traveled will be :

v²-u²= 2as

0-(12.5 m/s)²= 2(-5.68 m/s)²×s

s= -156.25/-11.36

s= 13.76 meters.

Hence, the acceleration of the car was -5.68 m/s² and it travelled 13.76 meters before stopping.

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Answer:

Na+ca+CO=NACo^3

Explanation:

NA Burns violently with explosions that may spatter the material. Used for making gasoline additives, electric power cable, sodium lamps, other chemicals.

The particle with a velocity of 4 m/s and with an acceleration 10 m/s2 in a sec will travel a distance of: 9 m

The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

x = (vi* t) + (a * t²)/2

Where:

Information about the problem:

Applying the distance formula, we have:

x = (vi* t) + (a * t²)/2

x = (4 m/s * 1 s) + (10 m/s² * (1 s)²)/2

x = 4 m + (10 m/s² * 1 s²)/2

x = 4 m + (10 m)/2

x = 4 m + 5 m

x = 9 m

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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According to the diameter and thickness of the gold medal, the volume of the gold medal is 8478mm³.

As a gold medal is a cylinder, so the volume of a gold medal (V) = Ah

Where h is the thickness of the medal and A is the area of the medal.

So, A = πr²               Here r is the radius = diameter÷2

V = πr²h                                                   =   60÷2

   = π × 30² × 3                                        = 30

   =8478

So the volume of the gold medal is 8478mm³.

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The rubber is stretched and firmly gripped by the nail due to the pressure inside the tire, which prevents air leakage.

The force of all gas particle/wall collisions divided by the surface area of the wall is the definition of pressure (P): One of the fundamental measurable quantities of this phase of matter, pressure is a property shared by all gases. The amount of force applied to a given area is referred to as pressure.

For instance, the weight of the snow divided by the area of the roof would represent the pressure from snow on a roof. Gases are typically where pressure in chemistry comes from. Gas is added to a balloon before it is inflated. Gas molecules collide with one another and the balloon's walls.

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Yes, we can compute by using stokes' theorem always.

By merely knowing information on the values of F along the border of S, Stokes' theorem states that we can compute the flux of curl F across surface S. On the other hand, by converting to a double integral of the curl of F over S, we may get the line integral of vector field F along the edge of surface S.

Let S be an N-unit normalized smooth surface that is orientated. Additionally, let's assume that S has a simple closed curve C as its border. If the surface is constantly on your left while you walk in the positive direction around C while directing your head in the direction of N, then the orientation of S induces the positive orientation of C. In light of this concept, we can say Stokes' theorem as,

[tex]\int\limits^0_c {F.} \, dr = \int\limits^0_s {F.} \, ds[/tex]

We can see the reference image here:

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The heat added is 348.165 kj

The enthalpy of vaporization, commonly known as the heat of vaporization or heat of evaporation, is the amount of energy required to turn a liquid material into a gas. The enthalpy of vaporization depends on the pressure at which the transition occurs.

The heat of vaporization varies with temperature, yet for small temperature ranges and decreased temperature ranges, a constant heat of vaporization can be assumed. The heat of vaporization decreases with rising temperature until it totally disappears at a point known as the crucial temperature. The liquid and vapor phases are indistinguishable beyond the critical temperature, and the material is referred to as a supercritical fluid.

Given that;

M = 150g = 0.15kg

T = 75oC

Heat capacity, h =2321.1 kj/kg

Q = m h

Q = 0.15* 2321.1

Q = 348.165 kJ

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The properties of Calcium are as follows:

Elements are defined as any substance which cannot be split into simpler units aby a ordinary chemical process.

Elements are the building block of all forms of matter.

Calcium one of the known 118 elements.

In the period table, Calcium has the following properties:

In conclusion, calcium is an element in the periodic table.

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The Initial Temperature of the Iron sphere is 253.40 C.

When two items are connected by a permeable barrier and there is no net energy flow between them, they are said to be in thermal equilibrium. This does not imply that no energy passes between the objects in thermal equilibrium; rather, an equal amount of energy flows back.

Thermal equilibrium can also relate to how heat is distributed within a single, isolated body.

Given,

Specific heat of iron = 470 J/KgC

Specific heat of water = 4200 J/KgC

Temperature of Water = 10 C

Final Temperature of Iron = 30 C

Initial Temperature of Iron = T

Heat lost by Iron = Qlost

                             = Miron SΔT

                             = (200/1000) * 470 * (T-30)

Heat gain by water = Qgain

                                 = Mwater SΔT

                                 = (500/1000) * 4200 * 10

According to the thermal equilibrium,

Qlost = Qgain

=> (200/1000) * 470 * (T-30) =  (500/1000) * 4200 * 10

=> T- 30 = 223.40

=> T = 253.40 C

Thus, the Initial Temperature of the Iron sphere is 253.40 C.

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The partial pressure of [tex]$\mathrm{Cl}_2$[/tex] in the flask is [tex]$1.067 \mathrm{~atm}$[/tex]

Partial pressure can be derived through the following:

Total pressure of a gas mixture = sum of the partial pressures of individual gases

[tex]\mathrm{P}(\text { total })=\mathrm{P}\left(\mathrm{f}_2\right)+\mathrm{P}\left(\mathrm{Cl}_2\right)[/tex]

Partial pressure = Mole fraction [tex]$\times$[/tex] Total pressure

Let us represent the mass of each gas as [tex]\mathrm{m}.[/tex]

Number of moles of [tex]$F_2=\mathrm{m} / 38$[/tex] (molar mass of [tex]$\left.\mathrm{Fl}_2\right)=38 \mathrm{~g} / \mathrm{Lol}$[/tex]

Number of moles of [tex]$\mathrm{Cl}_2=\mathrm{m} / 71$[/tex](molar mass of [tex]$\mathrm{Cl}_2$[/tex] )

Mole fraction of [tex]$F_2=(\mathrm{m} / 38) /(\mathrm{m} / 38)+(\mathrm{m} / 71)=0.65$[/tex]

Mole fraction of [tex]$\mathrm{Cl}_2=(\mathrm{m} / 71) /(\mathrm{m} / 38)+(\mathrm{m} / 71)=0.35$[/tex]

Partial pressure of [tex]$\mathrm{Cl}_2=0.35 \times 3.05=1.067 \mathrm{~atm}$[/tex]

Partial Pressure of [tex]$\mathrm{F}_2=0.65 \times 3.05 =1.98 \mathrm{~atm}$[/tex]

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Answer:

moving

Explanation:

Magnetic north was drifting at a rate of up to about 9 miles (15 km) a year. Since the 1990s, however, the drift of Earth's magnetic north pole has turned into “more of a sprint,” scientists say. Its present speed is about 30 to nearly 40 miles a year (50-60 km a year) toward Siberia.

Answer:

Frictional Force

Explanation:

Resistance is the resistance that one surface or object encounters when moving over another.

Tension could only occur on a rope or something that can be stretched tight.

Kinetic Energy would allow it to continue rolling-not stop.

The frequency of the first harmonic mode in string is 13.2Hz.

As, we know

[tex]v = \sqrt{\frac{T}{u} }[/tex]

where, v = velocity

T = tension in string

[tex]v = \sqrt{\frac{70(2)}{0.050}[/tex]

v = 52.9m/s

Also,

f = v / λ

where, f = frequency

v = velocity

λ = amplitude

f = 52.9 / 4

f = 13.2Hz

Therefore,  frequency of the first harmonic mode in string is 13.2Hz.

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The wavelength of electromagnetic waves is 2.88 meters.

We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic waves in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as

c = λ . f

where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.

From the question above, we know that

f = 104.3 MHz = 104.3 x 10⁶ Hz

By substituting the given parameter, we can calculate the frequency of radiowaves

c = λ . f

3 x 10⁸ = λ . 104.3 x 10⁶

λ = (3 x 10⁸) / (104.3 x 10⁶)

λ = 2.88 m

Hence, the wavelength of radiowaves is 2.88 meters.

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The density of the material is p =5.6 sl/ft^3 .

What is density?

The substance's mass per unit of volume is known as its density (volumetric mass density or specific mass). Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho). Density is mathematically defined as mass divided by volume.

The difference between an object's weight in a normal atmosphere and its weight inside water determines the force of buoyancy for an object of any shape:

Fb = Fw atm - Fw water

= 8.05 lb - 5.26 lb

=2.79 lb

We may determine the density of an object's structure by knowing its weight in the standard atmosphere, buoyant force, and water density:

p = (p h2o. Fw atm)/ Fb

putting the values and calculating we get :

p =5.6 sl/ft^3

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Thermal insulators stop the loss of accumulated heat, metal flat plates absorb solar radiation, and tubes absorb solar energy with the least amount of heat loss.

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The complete table representing the energy description at different stages is

Least Potential Energy                                  [2]

Most Potential Energy                                    [1]

Potential Energy to Kinetic energy               [4]

Kinetic energy to Potential Energy              [3]

Potential energy of a body that is due to its position. To be more precise, the potential energy of a body of mass 'm' at height 'h' will be -

P[E] = mgh

Kinetic Energy of a body is the energy due to virtue of its motion. Mathematically -

K[E] = 1/2 mv²

Given is a image of a roller coaster ride and a table describing the energy magnitude theoretically.

As mentioned, Potential energy of a body that is due to its position and is given by - P[E] = mgh. Let's complete the energy table given -

1 → Location with least potential energy

From the formula -

P[E] = mgh

mg = constant

P[E] [tex]\alpha[/tex] h

Now, the point 2 represents the minimum height, therefore Point 2 is the location with least potential energy.

2 → Location with most potential energy

We know -

P[E] [tex]\alpha[/tex] h

The point with maximum height is 1, therefore it will represented by Point 1.

3 → Conversion of potential to kinetic energy

Assume that the velocity of the roller coaster is v. Now at point 1, the velocity will be zero. Therefore, the total energy of the roller coaster will be purely potential energy. When it starts to move from point 1 to point 4, its height will decrease and its velocity will increase. Therefore - at this stage (point 4), the potential energy will start to convert into kinetic energy.

4 → Conversion of kinetic to potential energy

Use the same concept discussed in part - 3. In this case it is moving from lower point to higher point. So, height will increase and velocity will decrease. Therefore, the point 3 represents the stage at which kinetic energy will start to convert into potential energy.

Therefore, the complete table representing the energy description at different stages is

Least Potential Energy                                  [2]

Most Potential Energy                                    [1]

Potential Energy to Kinetic energy               [4]

Kinetic energy to Potential Energy              [3]

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The speed of the plane at the end of the runway is 59.065 m/s.

The equations of position and velocity in function of time of an object moving in a straight line together  constant acceleration are the following:

x = x₀ + v₀ · t + 1/2 · a · t²

v = v₀ + a · t

Where:

x = position of the plane at time t.

x₀ = initial position.

v₀ = initial velocity.

t = time.

a = acceleration.

v = velocity of the plane at time t.

If we place the origin of the frame of reference at the starting point, then x₀ = 0. Since the plane originate from rest, v₀ = 0. Then, the equation gets reduced to this:

x = 1/2 · a · t²

Let's find how much time it takes a plane to travel 500 m:

500 m = 1/2 · 6.99 m/s² · t²

2 · 500 m / 6.99 m/s² = t²

t = 8.45 s

Now, let's use the equation of velocity to solve the speed of the plane at t = 8.45 s (the time at which the plane is at the end of the runway):

v = v₀ + a · t    (v₀ = 0)

v = a · t

v = 6.99 m/s² · 8.45 s

v = 59.065 m/s

The speed of the plane at the end of the runway is 59.065 m/s.

What happens when electric flux is zero?

This leads us to the Gauss's Law, which says that the electrical flux going through a closed surface, is that the sum of all charges Q inside that closed surface, divided by permittivity of free space E0. If that flux is zero, meaning there is no net charge inside the shape.

What is a electric flux in closed surface?

The net flux through a closed surface is a quantitative measure of the net charge inside a closed surface. 2. the web electric flux through any closed surface surrounding a net charge 'q' is independent of the shape of the surface.

For which surface electric flux will be zero?

The flux of an electrical field through a closed surface will be always zero if and only if there is no net charge in the volume enclosed by the surface. the quantity of electric flux is always proportional to the charges inside the surface

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The energy obtained when 44 g of carbon is irradiated is 5.89 × [tex]10^{5}[/tex] J if each carbon atom emits one photon.

E = h ν = h c / λ

n = m / Mol * Avogadro's constant

E = Energy

h = Planck's constant

c = Speed of light

λ = Wavelength

n = Number of atoms

m = Mass

mol = Molar mass

h = 6.626 * [tex]10^{-34}[/tex] J s

λ = 745 nm = 7.45 * [tex]10^{-7}[/tex] m

c = 3 * [tex]10^{8}[/tex] m / s

m = 44 g C

mol = 12.01 g C

Avogadro's constant = 6.022 * [tex]10^{23}[/tex]

Energy emitted per photon, [tex]E_{1}[/tex] = ( 6.626 * [tex]10^{-34}[/tex] * 3 * [tex]10^{8}[/tex] ) / 7.45 * [tex]10^{-7}[/tex]

[tex]E_{1}[/tex] = 2.67 × [tex]10^{-19}[/tex] J

Total energy emitted, E = [tex]E_{1}[/tex] * n

E = ( 2.67 × [tex]10^{-19}[/tex] * 44 * 6.022 * [tex]10^{23}[/tex] ) / 12.01

E = 5.89 × [tex]10^{5}[/tex] J

Therefore, the energy obtained when 44 g of carbon is irradiated is 5.89 × [tex]10^{5}[/tex] J

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Answer:

The reason that the Greeks might not have had any questions to the evidence that heavier objects fall faster than light objects is because they would be questioning statistics which is that heavier objects and lighter objects do not fall at different rates but at the same its just the pending on the weight ex. a brick and a feather you drop a brick it falls quick because of its weight and a feather because of it's weight it falls a lot slower but at the measurement of the objects falling quicker than the other they don't its irrelevant.

Roman government comprised Members of the military, consuls, magistrates, and senate.

The two consuls, who had taken the king's place, were principally generals tasked with commanding Rome's legions in battle. Rome selected a dictator in lieu of the consuls in times of military necessity, when the unity of command was occasionally required. The dictator, however, could not wield supreme military command for more than six months at a period.

The Senate, which may have existed during the monarchy and acted as the king's advisory council, now provided advice to both magistrates and the Roman populace. Although the Senate simply provided advice and the people were the sole source of authority in theory, in reality, the Senate had tremendous power due to the status enjoyed by all of its members.

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But the query isn't complete. The hammer traveled 4.26 meters horizontal distance

we have following the given data

Hammer speed is 4 m/s.

30° is the angle the roof makes with the horizontal.

Roof's minimum height above ground is equal to 10 m g/10 m/s2.

Find the hammer's horizontal distance traveled.

Considering the vertical y-direction to establish the Time (t)

s = ut + 1/2at²

-10 = -4×sin30×t + 1/2×10t²

10 = 2t + 5t²

5t² + 2t - 10 = 0 (i)

Resolve equation (i)

t = 1.228  sec

This formula is used to compute the horizontal distance.

4 (cos 30°) t = 4×cos 30×1.228 = 4.26 m

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Answer:

7.39

Explanation:

plug in the right numbers and solve

The angle to make should be 68 degree.

What is a projectile motion?

A projectile is any object thrown into space upon which the only acting force is gravity.

When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration directed towards the center of the earth. The path such a particle takes is called projectile and the motion is called projectile motion.

From the equation we have initial velocity as 16.8 m/s

angle= 56 degrees

R1= V² sin2∅1/g

R2= V² sin2∅2/g

R1=R2

V² sin2∅1/g= V² sin2∅2/g

sin2∅1/g= sin2∅2/g

∅2= sin2∅2

∅2= sin(2* 56)

∅2= 68 degrees

When a particle is projected in the air with some speed the only force acting on it during its time in the air is the acceleration due to gravity (g).

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The magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per minute) if the wheel's diameter is 40 cm is [tex]4.418m/s^2[/tex].

Acceleration and change in velocity has both magnitude and acceleration because it is a vector quantity. Units are used to describe magnitude. The factors that affect acceleration include time, velocity, force, and many others. Both translation and rotation are possible.

The vector's magnitude determines its length. The vector's direction determines its direction. As a result, the acceleration's magnitude matches the acceleration vector's magnitude, and its direction matches the acceleration vector's direction.

Acceleration of speck of clay

[tex]a_R=V^2/R[/tex]

[tex]a_R=(\omega R^2)/R[/tex]

[tex]a_R=\omega R[/tex]

Given, the frequency of Potters wheel

f=45rpm

f=45(1min/60sec)

f=45/60 revolution/sec

ω=2πf

ω=2(3.14)(45/60)

ω=4.7 rad/sec

[tex]a_R=(4.7 rad/sec)^2(0.40/2 m)[/tex]

[tex]a_R=4.418m/s^2[/tex]

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The moment applied is 40 Nm.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

From the question above, the parameter given are

F = 200 N

r = 20 cm

Convert radius to meter

r = 20 cm

r = 20 x 10¯² m = 0.2 m

By substituting the parameters, we get

τ = F x r

τ = 200 x 0.2

τ = 40 Nm

Hence, the moment applied is 40 Nm

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282.84m/s is the speed if the tension is halved.  The speed of the wave is doubled since it is related to the square root of the tension.

The wave depends on the following:-

The formula we will use is:-

[tex]$$v=\sqrt{\frac{T}{p}}$$[/tex]

According to the question, the speed of the tension is as follows

Where v Is the speed of the wave, T is the tension In the wire, and [tex]$\rho$[/tex] Is the density of the wire.

when tension is doubled.

[tex]&\mathbf{T}=\mathbf{2} \mathbf{T}_0 \\[/tex]

[tex]$v=\sqrt{\hat{a} \frac{2 T_{\hat{\theta}}}{I}}$[/tex]

[tex]$v=\sqrt{2} \frac{T \hat{a}}{I}$[/tex]

[tex]$v=\frac{2}{\text { vô }}$[/tex]

After calculating, the value of v get,

[tex]$$v=\sqrt{2} * 200$$[/tex]

The value [tex]$\mathrm{v}=282.84 \mathrm{~m} / \mathrm{s}$[/tex].

The correct question is,

The wave speed on a string under tension is 200 m/s. What is the speed if the tension is doubled?

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The water in both pots will boil at the same temperature as long as the pressure is consistent. Both pots' water will reach boiling point at the same temperature.

The point at which the pressure that a liquid is subjected to from its environment equals the pressure that the liquid's vapor is subjected to; in this situation, the addition of heat causes the liquid to turn into its vapor without rising the temperature.

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The solubility of oxygen in water increases with the increase in the partial pressure of oxygen at a constant temperature and concentration.

The amount of chemical substance that can dissolve in water at a specific temperature can be known as the solubility in water. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million).

In the water the oxygen gets dissolved when the Oxygen is absorbed in water by direct diffusion and by surface-water agitation. The Solubility of oxygen in water is so small and by diffusion process alone in still water, it was calculated that it would take 6 years for oxygen to diffuse from surface to a depth of 6 meters in quiet water.

So, the  solubility of oxygen in water increases with the increase in the partial pressure of oxygen at a constant temperature and concentration.

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Water flows at a rate of 3.11 kilograms / seconds through a hose with a diameter of 3 centimetres. then the speed of the water in the hose would be 4.40 meters / second.

The total displacement covered by any object per unit of time is known as velocity. The velocity of an object depends on the magnitude as well as the direction of the object.

As given in the problem if Water flows at a rate of 3.11 kg/s through a hose with a diameter of 3 cm.

Area of the hose = πD²/4

                            =3.14*3*3/40000

                            =7.065×10⁻⁴ meter²

The discharge of the water = 3.11/1000

                                              =3.11×10⁻³ meter³

The discharge of the water = area of hose ×velocity

3.11×10⁻³ meter³ = 7.065×10⁻⁴ meter²×velocity

velocity = 3.11×10⁻³ /  7.065×10⁻⁴

             =4.40 metes/ second

Thus,the speed of the water in the hose would be 4.40 metes/ second.

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