A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.
Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.
A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is
A. 1350 J
B. 8820 J
C. 4410 J
D. 0 J
and his velocity is
E. 4.5 m/s
F. 0 m/s
G. 3.2 m/s
H. 9.9 m/s
Please help will mark brainliest
Answers
[tex]\\ \sf\longmapsto GPE=mgh[/tex]
[tex]\\ \sf\longmapsto GPE=90(5)(9.8)[/tex]
[tex]\\ \sf\longmapsto G PE=4410J[/tex]
Now
It's converted to kinetic energy while reaching ground.
[tex]\\ \sf\longmapsto K.E=4410[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410[/tex]
[tex]\\ \sf\longmapsto 90v^2=8820[/tex]
[tex]\\ \sf\longmapsto v^2=98[/tex]
[tex]\\ \sf\longmapsto v=9.9m/s[/tex]
Done
Answer:
Hope it will help you a lot.
Related Questions
An object is moving with a constant velocity of 311 m/s. How long will it take it to travel 9000 m?
Answers
[tex]\text{Given that,}\\\\\text{Velocity, v= 311 m s}^{-1}\\\\\text{Displacement, s = 9000 m}\\\\\text{Since velocity is constant,}\\\\s=vt\\\\\implies t =\dfrac{s}v = \dfrac{9000}{311} = 28.94 ~ \text{sec}.[/tex]
Physicists call any change in energy an impulse true or false?
Answers
.!.7:&//‘is sis sis did is
What did Ernest Rutherford expect to happen when he aimed a beam of particles at a thin gold foil
Answers
Answer:
he expected a fire to happen I think
Answer:
When Ernest Rutherford aimed a beam of particles at a thin gold foil he expected that the particles would be deflected slightly after passing through the foil.
Explanation:
hope it helped
the graph is tied to the reading
here is the reading for the question
students in a physics class observing the race note that each runner maintains the same acceleration from the start ofthe 8.0 second interval until they each reach the finish line where each of the runners slows to a stop. Two students inthe class make the following claims about the runners’ accelerations from the start of the 8.0 second interval until bothrunners are at rest.
Student 1:“Runner A has a positive acceleration until reaching the finish line and then a negative acceleration aftercrossing the finish line in order to “undo” all of the positive velocity she gained. Since Runner B neverhad any positive acceleration, she doesn’t need any negative acceleration to slow to a stop; heracceleration will be zero the whole time.”
Student 2:“But negative values mean away south in this case – how could runner A be turning around? I think bothrunners must have positive accelerations the whole time since they are always moving north.”
For part (c), do not simple repeat the students’ arguments in your answers.
here are the questions:
i.Which aspects of student 1’s reasoning, if any, are correct? Explain your answer.
ii.Which aspects of student 1’s reasoning, if any, are incorrect? Explain your answer.
iii.Which aspects of student 2’s reasoning, if any, are correct? Explain your answer.
iv.Which aspects of student 2’s reasoning, if any, are incorrect? Explain your answer
THANK YOU THANK YOU THANK YOU
Answers
ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.
iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.
iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?
A. F2
B. 1/2F
C. 0.1F
D. 2F/5
E. 5F
J. 10F
Please help will mark brainliest
Answers
If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is
F' = G (5m₁) (2m₂) / d²
F' = 10 Gm₁m₂ / d²
but this is really just F' = 10F. So J is the correct choice.
Hi there!
Using Newton's Law of Universal Gravitation:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]
Fg = Force of gravity (N)
G = Gravitational Constant
m₁ = mass of object 1 (kg)
m₂ = mass of object 2 (kg)
d = distance between the objects (m)
There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:
[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]
Thus, the correct answer is J. 10Fg.
how much brighter is Vega than the Sun? (astronomy)
Answers
Answer: 60 times brighter
which term is defined by the interaction between two charged particles?
Answers
Answer: Electromagnetism
The term which is defined by the interaction between two charged particles is known as electromagnetism.
What is an electromagnet?The study of charge and the fields and forces it generates is known as electromagnetism. Electromagnetism has two components: electricity and magnetism.
The special theory of relativity, developed by Albert Einstein in 1905, proved beyond a shadow of a doubt that both are components of the same reality. But in reality, magnetic and electric forces behave very differently and are modeled by various equations. Electric charges can produce forces whether they are stationary or moving. On the other hand, magnetic forces are only created by moving charges and only affect charges that are moving.
Thus, the term is known as electromagnetism.
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19. A beach ball is rolling in a straight line toward you at a speed of 9 m/sec. Its momentum is 3 kg'm/sec.
What is the mass of the beach ball? moss - 0.33
aroto from 10mle to speed of 14 m/s The mass of the bicycle
Answers
The mass of the beach ball is 0.33 kg
From the question,
We are to determine the mass of the beach ball.
Using the formula
ρ = mv
Where ρ is the momentum
m is the mass
and v is the velocity
From the given information,
ρ = 3 kg m/sec
v = 9 m/sec
Putting the parameters into the formula, we get
3 = m × 9
∴ m = 3 ÷ 9
m = 0.33 kg
Hence, the mass of the beach ball is 0.33 kg
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A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center, as shown above. The coin doesn’t slip and the time it takes for the coin to make a complete revolution is 1.5 s.
A)The figure below shows the disk and coin as viewed from above. Draw and label vectors on the figure below to show instantaneous acceleration and linear velocity vectors for the pin when it is at the position shown below.
B)Determine the linear speed of the coin
C)The rate of rotation of the disk is gradually increased. The coefficient of stats if friction between the coin and the disk is 0.50. Determine the linear speed of the coin when it just begins to slip.
D)If the experiment in part c were repeated with a second, identical coin glued to the top of the first coin, how would this affect the answer to part c? Explain.
Answers
A) Figure attached below
B) The linear speed of the coin = 0.59 m/s
C) Linear speed as coin begins to slip = 0.83 m/s
D) The tangential speed will remain the same as seen in part C
Given data :
mass of coin = 0.0050 kg
Distance of coin from the center of disk = 0.14 m
Time to make a complete revolution = 1.5 s
A) Diagram showing the vectors on the figure is attached below
B) Determine the Linear speed of the coinLinear speed of coin = 2 * π * ( 0.14 ) / 1.5
= 0.59 m/s
C) Determine the linear speed of the coin when it just begins to slipgiven that: friction between coin and disk = 0.50
Friction becomes maximum when coin begins to slip
Maximum frictional force (Fmax) = uV
where V = mg
∴ Fmax = u*mg ---- ( 1 )centripetal force = [tex]\frac{mv^{2} }{r}[/tex] ---- ( 2 )Equating equations ( 1 ) and ( 2 ) to determine the linear speed ( v )
v² = u*r*g
∴ v = √(u*r*g ) = √( 0.5 * 0.14 * 9.8 )
= 0.83 m/s
D) If the experiment is repeated with a second coin glued to the top of the first coin the tangential speed will remain the same
Hence we can conclude that The linear speed of the coin = 0.59 m/s Linear speed as coin begins to slip = 0.83 m/s , The tangential speed will remain the same as seen in part C
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The weight of a person in an elevator at rest = 500 N. Acceleration due to gravity is 9.8 m/s2. When lift accelerated, the tension force is 750 N. What is the acceleration of lift.
Answers
Answer:If the elevator accelerated downward then the tension force smallest then 500 N. Otherwise, if the elevator accelerated upward then the tension force larger then 500 N.
The tension force = 750 N because the elevator accelerated upward. Force acts upward has plus sign and force acts downward has minus sign.
T – w = m a
750 – 500 = 50 a
250 = 50 a
a = 250 / 50
a = 5.0 m s–2
Explanation:
The function of the liver in the metabolism of amino acids is to
Answers
Answer:
Produce energy, or make carbohydrates or fats.
Explanation:
A car weighing 8000N is traveling at 45 m/s on a perfectly flat, frictionless road. If the driver slams on the brakes, how far will thw car slide before it comes to a stop?
Answers
Without friction, the car cannot stop...
Why do magnets move objects in different ways?
Answers
Answer:
Magnets have two poles, called north and south. The like poles are attracted to unlike poles, but like poles repel each other. For example, the north pole of one magnet is attracted to the south pole of another. ... To make objects move with a magnet attach a piece of metal, or another magnet, to it.
A machine does 2500 J of work in 1 min. What is the power developed by the machine?
Answers
Answer:
41.7 watts
Explanation:
power=work done/time
2500/60seconds
=41.6666
Compare and contrast synthesis and decomposition reactions.
Answers
Answer:
Synthesis reactions are chemical reactions where two elements combine to make a product. Decomposition reactions are chemical reactions where a reactant produces another product, usually two, or even more. This is when the bonds in the compound are broken apart to make new compounds.
Explanation:
The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
Answers
Answer:
F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2
F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons
F = 3.53E22 N
[tex] \huge \rm༆ question ༄[/tex]
Calculus proof of second equation of motion ~
Answers
Newton's second equation of motion :-
S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]
This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.
So let's see what pieces of information (bundles of equations) do we have with us, initially.
We have, a very primary equation with us,
dS/dt = v… (I)
(Considering motion in a straight line only)
And we also have the equation
dv/dt = a…(II)
Simply replacing the v in eqn (II) by eqn (I), we find
d2S/dt^2 = a…(III)
This is what we need to solve. It's easy.
You know,
d2S/dt^2 = d/dt(dS/dt) = a
⟹ dS/dt = ∫adt = at+c1
Since, dS/dt is the velocity of the particle,
Therefore, at t = 0, dS/dt|t = 0 = u
⟹ u = a∗0 + c1 = c1
⟹ c1 = u
Therefore, dS/dt = u + at
Thus, S = ∫(udt + atdt)
⟹ S = ut + 1/2at^2 +c^2
If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0
This makes S = S0 +ut + 1/2at^2
Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),
We get
S = ut + 1/2at^2
Hope it helps :)
Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters
Answers
These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).
What clusters of galaxies likely to have irregular shapes?In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.
When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.
Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.
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3. Suppose Earth orbited a star whose mass was double the mass of the sun. If the radius of Earth's orbit remained
the same as it is now, then compared with gravitational force between Earth and the sun, the gravitational force
between Earth and the star would be -
A. half as much
B. the same
C. two times as much
D. four times as much
Answers
Answer:
F1 = G M m / R^2 current force on earth
F2 = G M * 2 m / R^2 force if mass were doubled
F2 / F1 = 2 the force would be twice as large
The gravitational force between two objects not only depends on the mass but also the distance between them. If the distance to the star is same as to sun, then by doubling mass force also doubles. Thus option C is correct.
What is universal law of gravitation?Gravitational force is the attractive force by which an object attracts other objects into its centre of mass. We are all standing in the ground because of the gravitational pull by earth.
The gravitational force between two objects of mass M1 and M2 at a distance r is written as follows:
g = G M1 M2/ r ² . where, G is gravitational constant.
As per this relation, gravitational force is directly proportional to the mass and inversely proportional to the square of the distance.
If the star has a distance from earth equal to the distance between sun and earth, but its mass is double the mass of sun, then the gravitational force will be two times compared with the sun.
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What process primes a molecule to change in a way that increases its activity, produces motion, or does work
Answers
Answer:
cellular respiration.
explanation: cellular respiration, the process by which organisms combine oxygen with foodstuff molecules, diverting the chemical energy in these substances into life-sustaining activities and discarding, as waste products, carbon dioxide and water.
sue and betti both ski straight down a hill, both starting from rest. sue weighs more than betti. neglecting friction and wind resistance, which skier will be moving the fastest at the bottom of the hill?
Answers
Answer:
They are both moving at the same speed since they will have the same acceleration
F = M a describes acceleration
M a = M g sin theta where theta is the slope
One can easily see that
a = g sin theta and the weight does not enter into the equation
A father places his daughter in a swing that is 0.60\,\text{m}0.60m0, point, 60, start text, m, end text above ground. Then he raises the swing to a height of 1.3\,\text{m}1.3m1, point, 3, start text, m, end text and lets go. The girl and the swing have a combined mass of 14\,\text{kg}14kg14, start text, k, g, end text. Assume friction is negligible and use g = 9.8\,\text{m/s}^2g=9.8m/s
2
g, equals, 9, point, 8, start text, m, slash, s, end text, squared.
Calculate the girl’s fastest speed.
Answers
This question involves the concepts of the law of conservation of energy and kinetic energy.
The girl's fastest speed is "3.7 m/s".
According to the law of conservation of energy, the girl will have the fastest speed at mean position, which will be calculated as follows:
Loss in Potential Energy = Gain in Kinetic Energy
[tex]mg\Delta h=\frac{1}{2}mv^2\\\\v=\sqrt{2g\Delta h}[/tex]
where,
v = maximum speed = ?
g = acceleration due to gravity = 9.81 m/s²
Δh = change in height = 1.3 m - 0.6 m = 0.7 m
Therefore,
[tex]v=\sqrt{2(9.81\ m/s^2)(0.7\ m)}[/tex]
v = 3.7 m/s
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Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
All rights reserved
Answers
The order of the location of each process in the carbon cycle are as follows;
Ingestion → Decomposition → Fossilization → CombustionReasons:
Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which
are energy rich chemical substances are ingested by herbivores.
Decomposition; The plants and animals die and undergo decomposition.
Fossilization; A long period the decomposed plants and animals manifest
into hard petrified materials, with their parts transformed to fossils.
Combustion; The remains of plants and animals, subjected to heat and
pressure due to compression, as when as bacteria decomposition that
removes several other elements, leaving a carbon and hydrogen rich
sludge that can be processed into fuel used for combustion. The
combustion process produces carbon dioxide which restarts the cycle.
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1 kg ball has eight joules of kinetic energy. what is its speed?
Answers
[tex]\\ \sf\Rrightarrow KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 8=\dfrac{1}{2}v^2[/tex]
[tex]\\ \sf\Rrightarrow v^2=16[/tex]
[tex]\\ \sf\Rrightarrow v=√16[/tex]
[tex]\\ \sf\Rrightarrow v=4m/s[/tex]
Answer:
the answer is 4m/s
It requires a 70.4 N force (parallel to the inclined plane) to pull a 5.86 kg box up a 58.1° inclined plane with a rope at a constant speed. (a) What is the coefficient of kinetic friction between the inclined plane and the box?
(b) If the rope were to break, what acceleration would the box experience as it slid down the ramp?
Answers
Answer:
0.667; 4.965
Explanation:
Look at the picture I attached for the force analysis.
a) The coefficient=Friction/Normal Force. Because it's at constant speed, the force of friction + mgsin58.1° (because it's on an inclined plane and has split forces) is equal to the applied force (70.4N). Normal force is not equal to weight force though, because the box is on an inclined plane; it's equal to mgcos58.1°.
b) If it were to break, then the box no longer has an applied force, and the direction of friction has changed to up the inclined plane. F=m/a, so acceleration = mgsin58.1°- Friction/mass
pls help it's due today
Answers
Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D
An object is dropped from a 42 m tall building. How long does it take to reach the ground?
Answers
Answer:
2.1 seconds
Explanation:
let D represent the height in meters
let g represent gravity in meters per second squared
let t represent time in seconds
D= -42 meters (negative because it falls down)
g= -9.8m/s^2
t= [tex]\frac{-42 meters}{9.8 m/s^2}[/tex]
this gives t= 4.2857 s^2
the meter units cancel out in the division
now we must simplify the units to singular seconds so...
[tex]\sqrt{4.3 s^{2} }[/tex] which simplifies to [tex]\sqrt{4.3}[/tex] x [tex]\sqrt{s^{2} }[/tex]
this equals 2.1 seconds
Is mechanical energy the result of both kinetic and potential energy?
Answers
Answer:
Yes
Explanation:
Because putting them together would make a type of energy making the answer yes
Explanation:
The mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy).
The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy. This sum is simply referred to as the total mechanical energy.
A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?
Answers
The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.
Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).
mass m = 42g = 42/1000 = 0.042kg
initial velocity before collision u = 7 m/s
It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,
velocity after collision v = 7 m/s
To calculate the magnitude of the racquetball's change in momentum, we will use the formula below
Change in momentum = Mv - Mu
Since momentum is a vector quantity, we will consider the direction.
Change in momentum = 0.042 x 7 - ( 0.042 x - 7)
Change in momentum = 0.294 + 0.294
Change in momentum = 0.588 kgm/s
Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.
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Which particles within the atom are electricity charged?
a. Electrons only.
b. Neutrons only.
c. Protons only.
d. Electrons and protons.
e. Protons and neurons.
Answers
Answer:
I think b sorry if wrong
Explanation:
it b sorry if wrong
Answer:
Given that these particles make up atoms, they are often referred to as subatomic particles. There are three subatomic particles: protons, neutrons and electrons. Two of the subatomic particles have electrical charges: protons have a positive charge while electrons have a negative charge:
