A 2.0 micr of capacitor that is initially uncharged is charged through a 50-kilo ohm resistor, it will take a time of 2.3sec to charge 90%.
What is the formula for a capacitor’s charging?C or Q may be equal. Thus, the charge needed to raise a conductor’s potential through unity is numerically equivalent to the conductor’s capacitance.
What occurs as the capacitor charges?There is no current flowing across the circuit when a capacitor is fully charged. This is true because the voltage source’s potential difference across the capacitor is also equal.
In other words, the charging current reaches zero and the capacitor voltage equals the source voltage.
The charge present on the capacitor is changing in time as follows:
q(t)=qo (1−e−tRC)
Here,
• qo is provided as the maximum charge on the capacitor.
• R=50000 Ω is the resistor value.
• C=2⋅10−6 F is the capacitance of the capacitor.
Solving for the time, we obtain:
t=−RCln(1−qq0)
Here,
• q=0.9qo is the charge on the capacitor at the moment t;
The Computation yields:
t=−5⋅10^4Ω⋅2⋅10^-6 F⋅ln(1−0.9q0)
≈0.23 s
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Find the mean velocity of helium atoms at room temperature (t~300k) and the de broglie wavelength
The mean velocity of helium atoms at room temperature (t~300k) and the de broglie wavelength is 1.3635 * 105 cm/s and 0.73 Armstrong respectively
In 1923, Louis-de-Broglie presented the notion of De-Broglie waves, that were also later tested with and proven by Davisson and Germer in 1927. These waves describe the nature of the particle-related wave.
Another variation of the de Broglie wavelength formula exists for particles having mass, such as electrons, protons, and so on, but not for photons. At non-relativistic speeds, a particle's momentum is equal to its rest mass m multiplied by its velocity v.
The de Broglie wavelength is measured in meters. Because it is so little, it is measured in nanometres or Angstroms.
Uavg = √(3KT/M)
Uavg = √((3×1.38〖×10〗^(-23)×300K)/(4×1.67×〖10〗^(-27) ))
Uavg = 1.3635 * 105 cm/s
λ = h/ mv
λ = (6.67×〖10〗^(-34))/((4×1.67×〖10〗^(-27))×(1.3635×〖10〗^3))
= 0.7323 * 10-10 m
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The discharge of water through an open channel is10.0 m3/s. what is the discharge in liters/min, gal-lons/min?
By unit conversion, the flow rate is 600,000 liters/min or 158503.23 gallons/min.
We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as
a = xb
where a is unit a, b is unit b and x is the constant of conversion.
From the question above, we know that
Q = 10 m³/s
Convert to liters / min
Q = 10 m³/s
Q = 10 x1000 liters/(1/60 min)
Q = 600,000 liters/min
Convert to US gallons/min
Q = 600,000 liters/min
Q = 600,000 x 0.264 gallons/min
Q = 158503.23 gallons/min
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100 grams of water at 75 degrees is heated at constant pressure. the water is completely vaporized. what is the heat added?
The heat added is 348.165 kj
The enthalpy of vaporization, commonly known as the heat of vaporization or heat of evaporation, is the amount of energy required to turn a liquid material into a gas. The enthalpy of vaporization depends on the pressure at which the transition occurs.
The heat of vaporization varies with temperature, yet for small temperature ranges and decreased temperature ranges, a constant heat of vaporization can be assumed. The heat of vaporization decreases with rising temperature until it totally disappears at a point known as the crucial temperature. The liquid and vapor phases are indistinguishable beyond the critical temperature, and the material is referred to as a supercritical fluid.
Given that;
M = 150g = 0.15kg
T = 75oC
Heat capacity, h =2321.1 kj/kg
Q = m h
Q = 0.15* 2321.1
Q = 348.165 kJ
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The magnetic north pole is always:
moving
cold
hot
Answer:
moving
Explanation:
Magnetic north was drifting at a rate of up to about 9 miles (15 km) a year. Since the 1990s, however, the drift of Earth's magnetic north pole has turned into “more of a sprint,” scientists say. Its present speed is about 30 to nearly 40 miles a year (50-60 km a year) toward Siberia.
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per minute) if the wheel's diameter is 40 cm ?
The magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per minute) if the wheel's diameter is 40 cm is [tex]4.418m/s^2[/tex].
Acceleration and change in velocity has both magnitude and acceleration because it is a vector quantity. Units are used to describe magnitude. The factors that affect acceleration include time, velocity, force, and many others. Both translation and rotation are possible.
The vector's magnitude determines its length. The vector's direction determines its direction. As a result, the acceleration's magnitude matches the acceleration vector's magnitude, and its direction matches the acceleration vector's direction.
Acceleration of speck of clay
[tex]a_R=V^2/R[/tex]
[tex]a_R=(\omega R^2)/R[/tex]
[tex]a_R=\omega R[/tex]
Given, the frequency of Potters wheel
f=45rpm
f=45(1min/60sec)
f=45/60 revolution/sec
ω=2πf
ω=2(3.14)(45/60)
ω=4.7 rad/sec
[tex]a_R=(4.7 rad/sec)^2(0.40/2 m)[/tex]
[tex]a_R=4.418m/s^2[/tex]
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______ resources include biodiversity, energy, land and
soil, and water resources.
Answer : Natural
Explanation : Natural resources are the resources that are found in the environment and are developed without the intervention of humans
One strategy in a snowball fight is to throw
a snowball at a high angle over level ground.
While your opponent is watching this first
snowball, you throw a second snowball at a
low angle and time it to arrive at the same
time as the first.
Assume both snowballs are thrown with
the same initial speed 16.8 m/s. The first
snowball is thrown at an angle of 56◦
above
the horizontal. At what angle should you
throw the second snowball to make it hit the
same point as the first?
The angle to make should be 68 degree.
What is a projectile motion?
A projectile is any object thrown into space upon which the only acting force is gravity.
When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration directed towards the center of the earth. The path such a particle takes is called projectile and the motion is called projectile motion.
From the equation we have initial velocity as 16.8 m/s
angle= 56 degrees
R1= V² sin2∅1/g
R2= V² sin2∅2/g
R1=R2
V² sin2∅1/g= V² sin2∅2/g
sin2∅1/g= sin2∅2/g
∅2= sin2∅2
∅2= sin(2* 56)
∅2= 68 degrees
When a particle is projected in the air with some speed the only force acting on it during its time in the air is the acceleration due to gravity (g).
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What is Einstein’s equation ?
He has derived a lot of equations but the most common one is E=mc^2
(Energy=Mass×Speed of light squared)
If we have 50 reported cases of angina and we want to select 5 for further review, then how many ways can we select these cases if order of selection matters?
We can select the cases in the order of selection matters 254,251,200
Permutation is the act of putting all the members of a set into a sequence or order in mathematics. In other words, if the set is already sorted, the act of reordering its pieces is known as permuting. Permutations may be found in practically every branch of mathematics, at varying degrees of prominence. They frequently appear when alternative orderings on finite sets are examined. The permutation formula is as follows.
nPr = ((n!) )/((n-r)!)
nPr = ((50!) )/((50-5)!)
nPr = ((50!) )/((45)!)
nPr = ((50*49*48*47*46*45)!)/((45)!)
nPr = 11441304000/45
nPr = 254,251,200
Therefore, there are 254,251,200 ways to select these cases if order of selection matters.
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A water wave has a frequency 0.50 hz, an amplitude of 0.35 m and a speed of 1.34 m/s. what is the value of the wavelength if the amplitude doubles?
By applying the wave equation, the wavelength is 2.68 meters.
We need to know about wave equations to solve this problem. The displacement of the wave on the y-axis can be explained by the wave equation
y = A cos (kx - ωt)
where y is y-axis displacement, A is amplitude, k is wave number, x is x-axis displacement, ω is angular speed and t is time.
the wavenumber and angular speed of the wave equation can be determined respectively by
k = 2π / λ
ω = 2πf
where k is the wavenumber, λ is wavelength and f is frequency.
From the question above, we know that:
f = 0.5 Hz
A = 0.35 m
v = 1.34 m/s
When the amplitude is doubled, it doesn't affect the wavelength. Hence
v = λ . f
1.34 = λ . 0.5
λ = 2.68 m
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Please help me write binary ionic compound to number 1
Answer:
Na+ca+CO=NACo^3
Explanation:
NA Burns violently with explosions that may spatter the material. Used for making gasoline additives, electric power cable, sodium lamps, other chemicals.
8. A coin flicked across a table will stop, because or due to of what kind of force______________.
Frictional force
Tension force
Kinetic energy
Answer:
Frictional Force
Explanation:
Resistance is the resistance that one surface or object encounters when moving over another.
Tension could only occur on a rope or something that can be stretched tight.
Kinetic Energy would allow it to continue rolling-not stop.
(buoyancy) an irregularly shaped piece of a solid material weighs 8.08 lb in air and 5.66 lb when completely submerged in water. determine the density of the material.
The density of the material is p =5.6 sl/ft^3 .
What is density?
The substance's mass per unit of volume is known as its density (volumetric mass density or specific mass). Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho). Density is mathematically defined as mass divided by volume.
The difference between an object's weight in a normal atmosphere and its weight inside water determines the force of buoyancy for an object of any shape:
Fb = Fw atm - Fw water
= 8.05 lb - 5.26 lb
=2.79 lb
We may determine the density of an object's structure by knowing its weight in the standard atmosphere, buoyant force, and water density:
p = (p h2o. Fw atm)/ Fb
putting the values and calculating we get :
p =5.6 sl/ft^3
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A local fm radio station broadcasts at 104.3 mhz. what is the wavelength (in m)of the radio waves?
The wavelength of electromagnetic waves is 2.88 meters.
We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic waves in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as
c = λ . f
where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.
From the question above, we know that
f = 104.3 MHz = 104.3 x 10⁶ Hz
By substituting the given parameter, we can calculate the frequency of radiowaves
c = λ . f
3 x 10⁸ = λ . 104.3 x 10⁶
λ = (3 x 10⁸) / (104.3 x 10⁶)
λ = 2.88 m
Hence, the wavelength of radiowaves is 2.88 meters.
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A flask contains equal masses of f2 and cl2 with a total pressure of 3.05 atm at 298k. what is the partial pressure (in atm) of cl2 in the flask?
The partial pressure of [tex]$\mathrm{Cl}_2$[/tex] in the flask is [tex]$1.067 \mathrm{~atm}$[/tex]
Partial pressure can be derived through the following:
Total pressure of a gas mixture = sum of the partial pressures of individual gases
[tex]\mathrm{P}(\text { total })=\mathrm{P}\left(\mathrm{f}_2\right)+\mathrm{P}\left(\mathrm{Cl}_2\right)[/tex]
Partial pressure = Mole fraction [tex]$\times$[/tex] Total pressure
Let us represent the mass of each gas as [tex]\mathrm{m}.[/tex]
Number of moles of [tex]$F_2=\mathrm{m} / 38$[/tex] (molar mass of [tex]$\left.\mathrm{Fl}_2\right)=38 \mathrm{~g} / \mathrm{Lol}$[/tex]
Number of moles of [tex]$\mathrm{Cl}_2=\mathrm{m} / 71$[/tex](molar mass of [tex]$\mathrm{Cl}_2$[/tex] )
Mole fraction of [tex]$F_2=(\mathrm{m} / 38) /(\mathrm{m} / 38)+(\mathrm{m} / 71)=0.65$[/tex]
Mole fraction of [tex]$\mathrm{Cl}_2=(\mathrm{m} / 71) /(\mathrm{m} / 38)+(\mathrm{m} / 71)=0.35$[/tex]
Partial pressure of [tex]$\mathrm{Cl}_2=0.35 \times 3.05=1.067 \mathrm{~atm}$[/tex]
Partial Pressure of [tex]$\mathrm{F}_2=0.65 \times 3.05 =1.98 \mathrm{~atm}$[/tex]
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How will you increase the solubility of oxygen in water? the partial pressure of oxygen
The solubility of oxygen in water increases with the increase in the partial pressure of oxygen at a constant temperature and concentration.
What is solubility in water?The amount of chemical substance that can dissolve in water at a specific temperature can be known as the solubility in water. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million).
In the water the oxygen gets dissolved when the Oxygen is absorbed in water by direct diffusion and by surface-water agitation. The Solubility of oxygen in water is so small and by diffusion process alone in still water, it was calculated that it would take 6 years for oxygen to diffuse from surface to a depth of 6 meters in quiet water.
So, the solubility of oxygen in water increases with the increase in the partial pressure of oxygen at a constant temperature and concentration.
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A hot iron sphere of 200g is kept in 500g of water at 10°C.As a result, the final temperature of water becomes 30°C.Find the initial temperature of the iron sphere.(specific heat capacity of iron =470J/kg°C.
The Initial Temperature of the Iron sphere is 253.40 C.
When two items are connected by a permeable barrier and there is no net energy flow between them, they are said to be in thermal equilibrium. This does not imply that no energy passes between the objects in thermal equilibrium; rather, an equal amount of energy flows back.
Thermal equilibrium can also relate to how heat is distributed within a single, isolated body.
Given,
Specific heat of iron = 470 J/KgC
Specific heat of water = 4200 J/KgC
Temperature of Water = 10 C
Final Temperature of Iron = 30 C
Initial Temperature of Iron = T
Heat lost by Iron = Qlost
= Miron SΔT
= (200/1000) * 470 * (T-30)
Heat gain by water = Qgain
= Mwater SΔT
= (500/1000) * 4200 * 10
According to the thermal equilibrium,
Qlost = Qgain
=> (200/1000) * 470 * (T-30) = (500/1000) * 4200 * 10
=> T- 30 = 223.40
=> T = 253.40 C
Thus, the Initial Temperature of the Iron sphere is 253.40 C.
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A mechanic applies a force of 200n at the end of a snappnes of length 20cm. what is the moment applied to the nut?
The moment applied is 40 Nm.
We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as
τ = F x r
where τ is torque, F is perpendicular force and r is radius.
From the question above, the parameter given are
F = 200 N
r = 20 cm
Convert radius to meter
r = 20 cm
r = 20 x 10¯² m = 0.2 m
By substituting the parameters, we get
τ = F x r
τ = 200 x 0.2
τ = 40 Nm
Hence, the moment applied is 40 Nm
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Which of the five zones shown on the map has the greatest amount of land area suitable for people to live?
I have to get it done right now... I'm not playing no games.. I need help with this ASAP
The zone in the map that has the greatest amount of land area suitable for people to live is zone B.
What is equator?The equator is the imaginary line that divides the earth horizontally into two equal halves of North and South zones.
The countries that are located close to the equator include the following:
Ecuador, Colombia,
Brazil, Sao Tome & Principe, Gabon, Republic of the Congo, Democratic Republic of the Congo,Uganda, Kenya, Somalia, Maldives, Indonesia and Kiribati.From the map, the zone with the greatest amount of land area suitable for people to live is the zone closest to the equator which is zone B.
The temperature of these areas are close to moderate through out the year.
The zone B also contains land mass that is part of the largest continent which is Asia.
Therefore, the zone in the map that has the greatest amount of land area suitable for people to live is zone B.
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Find the length of the shortest curve between (1, 0, 0) and (1, 1, 1) on the surface x 2 y 2 = z 2 1. be sure to explain why your answer is correct.
The length of the shortest curve would be √2.
CalculationThe paraboloid x2 + y2 = z2 + 1 is a doubly ruled surface, which means, it can be swept out by a moving the line in space in two different ways.
So, then we have to verify the fact that the line defined by the two given points lies entirely on the surface of the paraboloid.
The vector valued function that describes the straight line connecting the points (1, 0, 0) and (1, 1, 1) is
r (t) = < 1, t, t >, t ∈ R
and it can be stated by inspection that this satisfies the equation of the paraboloid.
Thus, it is found that the length of the line segment connecting the points is √2
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A thin 2.00-m string of mass 50.0 g is fixed at both ends and under a tension of 70.0 n. if it is set into small-amplitude oscillation, what is the frequency of the first harmonic mode?
The frequency of the first harmonic mode in string is 13.2Hz.
As, we know
[tex]v = \sqrt{\frac{T}{u} }[/tex]
where, v = velocity
T = tension in string
[tex]v = \sqrt{\frac{70(2)}{0.050}[/tex]
v = 52.9m/s
Also,
f = v / λ
where, f = frequency
v = velocity
λ = amplitude
f = 52.9 / 4
f = 13.2Hz
Therefore, frequency of the first harmonic mode in string is 13.2Hz.
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For a parallel-plate capacitor the energy density is uniform in the region between the plates, except near the edges of the plates. Is this also true for a spherical capacitor?.
No. this is not true for a spherical capacitor.
A spherical capacitor can be thought of as what is shown in the attached figure.That phenomenon for the parallel plate capacitor occurs because of the sudden change in the electric field intensity. Between the plates, the electric field intensity is constant and uniform and that uniformity changes at the edges.Such a uniform field intensity is not found in a spherical capacitor.The field at a given distance from the sphere is a function of that distance so it changes from place to place.So the energy density is not uniform in a region between 2 spherical surfaces.Therefore, what is true for spherical capacitors is that the energy density is like that at the edges of a parallel plate capacitor.#SPJ4
A swimmer can swim at a speed of 0.7 m/s with respect to the water. She wants to cross a river which is 50m North and has a current of 0.5 m/s East. (a) If she wishes to land on the other bank directly at a point directly across from her starting point, in what direction must she swim? How long will it take? (b) 1,5g instead decides to cross in the shortest possible time, in what direction must she swim? How far down stream will she be?
(a) If she wishes to land on the other bank directly at a point directly across from her starting point, the direction she must swim is 50.3⁰ north east.
(a. ii) The time of her motion is 111.8 seconds.
(b) If she wishes to cross the shortest possible time, then she must swim the shortest possible distance. Her direction must be 90 degrees and she will swim 50 m north.
Time of motion of the swimmer
The time taken for the swimmer to land on the other bank directly at a point directly across from her starting point is calculated as;
(V₁t)² = (d²) + (V₂t)²
where;
V₁ is the speed of the swimmerd is the vertical distance between the swimmer and the river bankV₂ is the speed of the rivert is time of motion of the river0.7t² = 50² + 0.5t²
0.7t² - 0.5t² = 50²
0.2t² = 2500
t² = 2500/0.2
t² = 12,500
t = √12,500
t = 111.8 seconds
Resultant displacement = V₁t = 0.7 m/s x 111.8 s = 78.26 m
Direction of the swimmercos θ = adjacent side / hypotenuse side
cos θ = 50 m / 78.26 m
cos θ = 0.6389
θ = arc cos(0.6389)
θ = 50.3⁰
Thus, if she wishes to land on the other bank directly at a point directly across from her starting point, the direction she must swim is 50.3⁰.
If she wishes to cross the shortest possible time, then she must swim the shortest possible distance. Her direction must be 90 degrees and she will swim 50 m north.
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What reason might the Greeks have had not to
question the evidence that heavier objects fall
faster than lighter objects?
Answer:
The reason that the Greeks might not have had any questions to the evidence that heavier objects fall faster than light objects is because they would be questioning statistics which is that heavier objects and lighter objects do not fall at different rates but at the same its just the pending on the weight ex. a brick and a feather you drop a brick it falls quick because of its weight and a feather because of it's weight it falls a lot slower but at the measurement of the objects falling quicker than the other they don't its irrelevant.
A particle has a velocity of v = 4 m/s and acceleration a = 10 m/s2. what is the distance traveled in 1 sec? 7 m 9 m 14 m 25
The particle with a velocity of 4 m/s and with an acceleration 10 m/s2 in a sec will travel a distance of: 9 m
The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:
x = (vi* t) + (a * t²)/2
Where:
x = distancea = acceleration vi = initial velocityt = timeInformation about the problem:
vi= 4 m/sa= 10 m/s²t = 1 sx= ?Applying the distance formula, we have:
x = (vi* t) + (a * t²)/2
x = (4 m/s * 1 s) + (10 m/s² * (1 s)²)/2
x = 4 m + (10 m/s² * 1 s²)/2
x = 4 m + (10 m)/2
x = 4 m + 5 m
x = 9 m
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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Find the work done on a 50 Kg student by the elevator in 2 seconds, if the elevator is :
1) Accelerating upwards from rest at a rate of 2 ms-2
2) Accelerating downwards from rest at a rate of 2 ms-2
3) Decelerating upwards from an initial speed of 4 ms-1 at a rate of 2 ms-2
4) Decelerating downwards from an initial speed of 4 ms-1 at a rate of 2 ms-2
5) Moving upwards at a speed of 2 ms-1
6) Moving downwards at a speed of 2 ms-1
( Let g = 10 ms )
The work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻² would be
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance.
The work done is the multiplication of applied force with displacement.
Work Done = Force × Displacement
As given in the problem we have to find the work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻²,
Lets us first calculate the displacement of the elevator in 2 seconds if it is accelerating upwards from rest at a rate of 2 ms⁻².
s = ut + 0.5at²
= 0 + 0.5×2×2²
= 4 meters
The work done on the elevator = mgh
=50×9.81×4
=1962 joules
Thus, the work done on the elevator would be 1962 joules.
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A car travels straight down a highway with cruise control set to 100 km/h. how far does it travel during 14.2 minutes?
230km far does it travel during 14.2 minutes.
A car travels straight down a highway with cruise control set to = 100 km/h
how far does it travel during 14.2 minutes
so, now we use
Distance = velocity [tex]\times[/tex] time
1 min = 1/60 hour
14.2 min = 14.2 / 60 hour
= 0.23 hour
now,
Distance = 1000[tex]\times[/tex]0.23 km
= 230km
so. 230km it travel in 14.2 minutes
Distance is the length of the path between two points. and it's standard unit is meter while displacement is shortest distance between final position and initial position and it also has meter as a standard unit.
written as m.
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Carbon emits photons at 745 nm when exposed to blackbody radiation. How much energy would be obtained if 44g of carbon were irradiated? Assume each carbon atom emits one photon.
The energy obtained when 44 g of carbon is irradiated is 5.89 × [tex]10^{5}[/tex] J if each carbon atom emits one photon.
E = h ν = h c / λ
n = m / Mol * Avogadro's constant
E = Energy
h = Planck's constant
c = Speed of light
λ = Wavelength
n = Number of atoms
m = Mass
mol = Molar mass
h = 6.626 * [tex]10^{-34}[/tex] J s
λ = 745 nm = 7.45 * [tex]10^{-7}[/tex] m
c = 3 * [tex]10^{8}[/tex] m / s
m = 44 g C
mol = 12.01 g C
Avogadro's constant = 6.022 * [tex]10^{23}[/tex]
Energy emitted per photon, [tex]E_{1}[/tex] = ( 6.626 * [tex]10^{-34}[/tex] * 3 * [tex]10^{8}[/tex] ) / 7.45 * [tex]10^{-7}[/tex]
[tex]E_{1}[/tex] = 2.67 × [tex]10^{-19}[/tex] J
Total energy emitted, E = [tex]E_{1}[/tex] * n
E = ( 2.67 × [tex]10^{-19}[/tex] * 44 * 6.022 * [tex]10^{23}[/tex] ) / 12.01
E = 5.89 × [tex]10^{5}[/tex] J
Therefore, the energy obtained when 44 g of carbon is irradiated is 5.89 × [tex]10^{5}[/tex] J
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A cannonball is dropped off a 65 m high castle wall. how long will the cannonball be in the air before striking the ground?
The cannonball dropped of a 65 m high castle wall will be in the air a time of: 3.642 s
The free fall formula and the procedure we will use is:
t = √[ (2*h) / g]
Where:
t = time takenh = height traveledg = acceleration due to gravityInformation of the problem:
h = 65 mg = 9.8 m/s²t = ?Applying the time formula we get:
t = √[ (2*h) / g]
t = √[ (2*65 m) / 9.8 m/s²]
t = √[ 130 m / 9.8 m/s²]
t = √[ 13.265 s²]
t = 3.642 s
What is free fall?It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.
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Predict the effects of a drug that blocks the sympathetic nervous system on blood pressure and heart rate. how would this drug affect the three factors that determine blood pressure?
It would decrease cardiac output, peripheral resistance, and blood volume.
Cardiac output (CO), the volume of blood the heart pumps each minute, is the mechanism through which blood circulates throughout the body, particularly supplying the brain and other crucial organs with blood flow. When exercising, for example, the body's need for oxygen fluctuates, and changing both heart rate (HR) and stroke volume affects cardiac output (SV).
As a result, a complicated mechanism combining the autonomic nervous system, endocrine, and paracrine signaling pathways is responsible for controlling cardiac output. Every tissue in the body depends on the heart to pump blood to it in order to survive, hence any cardiovascular failure could have a large negative impact on morbidity and mortality.
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