abc has a $5 million liability at december 31, 2018, of which $1 million is payable in each of the next five years. abc reports the liability on the balance sheet as a:

Answer:

Using the concept of linear equations, we find that we need 40 gallons of the 65% antifreeze and 10 gallons of the 90% antifreeze.

Step-by-step explanation:

Let x = amount of 20% antifreeze

Let y = amount of 70% antifreeze

Given that the total amount of antifreeze is 80 gallons

So, x + y = 80

Also given that the purity of the total antifreeze is 60%.

0.65x + 0.90y = 0.70(x + y)

65x + 90y = 70(x + y)

Simplify and solve the system of equations

65x + 90y = 70x + 70y      

65x -70x+ 90y-70y = 0    

-5x + 20y = 0      

Now we have the following system of equations:

x + y = 50

-5x + 20y = 0

Multiply the first equation by 5 to get opposite coefficients for x;  

add the equations to eliminate x

5x + 5y - 5x + 20y = 250

25y = 250

y = 10              

Since the total mixed gallons is 50,

x = 50 - 10 = 40

So we need 40 gallons of the 65% antifreeze and 10 gallons of the 90% antifreeze

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Answer:

C.

Step-by-step explanation:

Adding 2 fractions results in a fraction.

Answer:

B: The sum is a non-terminating and a non-reapeating decimal

Step-by-step explanation:

-11/4 +5/g

There is 15 steps you have to do after (look in the picture)

but this is what you get:

[tex]-\frac{11g-20}{4g}[/tex]

The exponential model best represents the data is B. f(x) = 5(0.2)^x

From the table of values, we have the following points:

(x, y) = (0,5) and (1,1)

An exponential model is represented as:

y = ab^x

Substitute (x, y) = (0,5)

5 = ab^0

5 = a

This gives

a = 5

So, we have:

y = 5b^x

Substitute (x, y) = (1,1)

1 = 5b^1

This gives

5b = 1

Divide by 5

b = 0.2

Substitute b = 0.2 in y = 5b^x

y = 5(0.2)^x

Hence, the exponential model best represents the data is B. f(x) = 5(0.2)^x

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Answer:

(x,y)—>(6,2)

Step-by-step explanation:

Add both equations to eliminate y

9x=54

x=6

plug x=6 into either equation

2(6)+6y=24

6y=24-12

y=12/6=2

[tex]\left\{\begin{array}{ccc}y=2x&(1)\\3x+4y=22&(2)\end{array}\right[/tex]

Put (1) to (2):

[tex]3x+4(2x)=22\\3x+8x=22\\11x=22\qquad|\text{divide both sides by 11}\\\boxed{x=2}[/tex]

Substitute the value of x to (1):

[tex]y=2\cdot2\\\boxed{y=4}[/tex]

Solution:

[tex]\huge\boxed{\left\{\begin{array}{ccc}x=2\\y=4\end{array}\right}[/tex]

Answer: 360

Step-by-step explanation: 6 times 6 times 10 = 360

Answer:

x ≈ 12.182

Step-by-step explanation:

1 - 2lnx = - 4 ( subtract 1 from both sides )

- 2lnx = - 5 ( divide both sides by - 2 )

lnx = 2.5

x = [tex]e^{2.5}[/tex] ≈ 12.182 ( to the nearest thousandth )

Answer:

x = 12.182  (nearest thousandth)

Step-by-step explanation:

Given equation:

[tex]1-2 \ln x=-4[/tex]

Subtract 1 from both sides:

[tex]\implies 1-1 -2 \ln x =-4-1[/tex]

[tex]\implies -2 \ln x=-5[/tex]

Divide both sides by -2:

[tex]\implies \dfrac{-2 \ln x}{-2}=\dfrac{-5}{-2}[/tex]

[tex]\implies \ln x = \dfrac{5}{2}[/tex]

[tex]\textsf{As }\: \ln x=\log_ex \:\:\textsf{}[/tex], the natural logarithm can be canceled by giving both sides a base of e (Euler's number):

[tex]\implies e^{\ln x}= e^{\frac{5}{2}[/tex]

[tex]\implies x= e^{\frac{5}{2}[/tex]

[tex]\implies x=12.182\:\: \sf (nearest\:thousandth)[/tex]

Answer:

(-3, 0, 4, 6) (option D)

Step-by-step explanation:

The "range" of a function is all possible y-values. In this image, there are x's entered on the left side--which I know to be x values because a function, f(x) is essentially the outcome of what happens when x is entered.

So, the y-values are featured on the right. All of these values are the possible values for y, or, what we call the range.

Meaning that the range of this function is (-3, 0, 4, 6)

Answer:

D

Step-by-step explanation:

Answer:

-150

or 150 degrees below 0

Step-by-step explanation:

The temp is -110. Dropping another 40 degrees means subtracting 40.

-110 - 40 = -150

Answer:

[tex]x = -\frac{15}{2}[/tex]

Step-by-step explanation:

Hello!

The formula for the AOS is given to you, and you simply have to plug in the information given by the equation.

Equation of a Parabola (Standard): [tex]y = ax^2 + bx + c[/tex]

Comparing it to our equation:

Plug it in to the AOS formula:

You only have to input 15 in to the correct box since the negative sign is already placed for you.

Graph (A) represents the equation of the line 5y = x + 5 shown in the graph option (A) is correct.

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the equation of the line:

5y = x + 5

After plotting the line on the coordinate plane.

The above line passes through:

(-5, 0), (0,1), and (5,2)

And the line rises from (-8, -0.5), (-5, 0), (0,1), and (5,2)

Thus, graph (A) represents the equation of the line 5y = x + 5 shown in the graph option (A) is correct.

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Answer:  A. A line is graphed in an x y plane, where the x and the y axes range from negative 8 to 8 in increments of 2. The line rises through (negative 8, negative 0.5), (negative 5, 0), (0, 1), and (5, 2).

Step-by-step explanation:

perimeter of octagon

Now area

Area of square

Area of shaded region

Answer:

C.  647 square units

Step-by-step explanation:

To find the shaded area, subtract the area of the unshaded square from the area of the octagon.

Area of the octagon

[tex]\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}[/tex]

where:

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}[/tex]

[tex]\implies \textsf{Area}=\sf \dfrac{1631.76}{2}[/tex]

[tex]\implies \textsf{Area}=\sf 815.88\:\:square \:units[/tex]

Area of the square

[tex]\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units[/tex]

Area of the shaded region

= area of the octagon - area of the square

= 815.88 - 169

= 646.88

= 647 square units (nearest square unit)

Answer:

x=9

if

a^b = a^c

then b=c

so in this case x=9

Answer:

48 Square Centimeters

Step-by-step explanation:

The red triangular exterior pieces are all equilateral triangles with some side length.

We don't need to know what that side length is. It doesn't matter.

The area of one red equilateral triangle is some area A.

There are 6 of these red triangles, so the red exterior triangular parts combine to a total area of 6*A.

The hexagon is composed of equilateral triangles as well.

Each of these blue equilateral triangles is congruent to any outer red triangle because the side length is the same.

Therefore, the 6 blue equilateral triangles composing this hexagon combine to get a total area of 6*A

The area of the star overall is 12*A because we have 6 blue triangles combining with the 6 red triangles.

There is a total of 12 triangles.

Answer:

x=21°

Step-by-step explanation:

40°+5x+14°+x=180°

5x+x=180°-40°-14°

6x=126°

x=21°

Answer:

x = 21

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

x + 40 + 5x+14 = 180

Combine like terms

6x+54 =180

Subtract 54 from each side

6x+54-54 = 180-54

6x =126

Divide each side by 6

6x/6 =126/6

x = 21

The linear equation is y = (1/7)*x + 11/7.

The general linear equation is:

y = a*x + b

Where a is the slope.

Here we know that a = (1/7), then the line is:

y = (1/7)*x + b

We also know that the line contains the point (-4, 1), this means that when x = -4, we must have y = 1.

Replacing that, we get:

1 = (1/7)*(-4) + b

1 + 4/7 = b

7/7 + 4/7 = b

11/7 = b

So the linear equation is:

y = (1/7)*x + 11/7.

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The equation of the linear function of the line is: y = 1/7x + 11/7.

A linear function equation is modelled as, y = mx + b, where m is the slope and b is the y-intercept.

Slope (m) = 1/7, and the line passes through (-4, 1), therefore, substitute (x, y) = (-4, 1) and m = 1/7 into y = mx + b:

1 = 1/7(-4) + b

1 = -4/7 + b

1 + 4/7 = b

11/7 = b

b = 11/7

Plug in the values of m and b into y = mx + b:

y = 1/7x + 11/7

The equation of the linear function is: y = 1/7x + 11/7

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Answer:

The correct answer would be 20.92

Answer:

Hello auggggh nice to meet you!

Step-by-step explanation:

Answer:

z⁴

Step-by-step explanation:

(z x z x z x z x z x z) / (z x z)

z⁶ / z² = z⁴

Answer:

C

Step-by-step explanation:

= The square root of (5^2+2^2)= The square root of 29 ---> C

Any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.

The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In △ABD and △ACB,

∠A = ∠A (common)

∠ADB = ∠ABC (both are right angles)

Thus, △ABD ∼ △ACB (by AA similarity criterion)

Similarly, we can prove △BCD ∼ △ACB.

Thus △ABD ∼ △ACB,

Therefore, AD/AB = AB/AC.

We can say that AD × AC = AB².

Similarly, △BCD ∼ △ACB.

Therefore,

CD/BC = BC/AC.

We can also say that

CD × AC = BC².

Adding these 2 equations, we get

AB² + BC² = (AD × AC) + (CD × AC)

AB² + BC² =AC(AD +DC)

AB² + BC² = AC²

Hence proved

Thus, any triangle with one angle equal to 90⁰ produces a Pythagoras triangle and the Pythagoras equation can be applied in the triangle.

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Answer:

2/9 or 0.22222

Step-by-step explanation:

Answer:

7.21

Step-by-step explanation:

There is a formula to find the area of a side of a rhombus given 2 diagonals.

It is:  [tex]\frac{\sqrt{p^{2}+q^{2} } }{2}[/tex]

64 + 144 = 208

[tex]\sqrt{208}[/tex] = 14.42

14.42 / 2 =

7.21

The simplification of the algebraic expression to its simplest form is -3x³ + 2x² + 13x - 10

The simplest form of an algebraic expression is a stage at which the expression can no longer be further simplified.

From the given expression:

= -(x − 2)(3x² + 4x − 5)

= (-x +2)(3x² + 4x − 5)

Open brackets

= -3x³ - 4x² + 5x +6x² + 8x - 10

= -3x³ + 2x² + 13x - 10

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Answer:

no solutions

Step-by-step explanation:

we use the quadratic formula.

for an equation ax²+bx+c=0, the solutions for x are:

x = (-b±sqrt(b²-4ac))/2a

in our case, a=2, b=-6 and c=5, so:

x= (6±sqrt(36-40))/4

we see that we get a negative number inside the sqrt, so we have no real solutions

Answer:

No solution

Step-by-step explanation:

1) Use the quadratic formula

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

[tex]2x^2-6x+5=0[/tex]

[tex]a=2\\b=-6\\c=5[/tex]

[tex]x=\frac{-(-6)\pm\sqrt{(-6)^2-4*2*5} }{2*2}[/tex]

2) Simplify

Evaluate the exponent:

[tex]x=\frac{6\pm\sqrt{(-6)^2-4*2*5} }{2*2}[/tex]

[tex]x=\frac{6\pm\sqrt{36-4*2*5} }{2*2}[/tex]

Multiply the numbers:

[tex]x=\frac{6\pm\sqrt{36-4*2*5} }{2*2}[/tex]

[tex]x=\frac{6\pm\sqrt{36-40} }{2*2}[/tex]

Subtract the numbers:

[tex]x=\frac{6\pm\sqrt{36-40} }{2*2}[/tex]

[tex]x=\frac{6\pm\sqrt{-4} }{2*2}[/tex]

Multiply the numbers

[tex]x=\frac{6\pm\sqrt{-4} }{2*2}[/tex]

[tex]x=\frac{6\pm\sqrt{-4} }{4}[/tex]

3) No real solutions because the discriminant is negative

The square root of a negative number is not a real number

[tex]d=-4[/tex]

Result

No solution