according to general relativity, the presence of matter curves spacetime and therefore time slows down in a gravitational field. time is universal. time is different for every object. none of the above

Answers

Answer 1

General relativity states that the existence of matter bends spacetime, which causes time to slow down in a gravitational environment.

Explain the term general relativity?

It is, in essence, a theory of gravity. The fundamental assumption is that gravity is a bending or curving of space rather than an invisible force which draws items together.

An item warps the space surrounding it more dramatically the more large it is.According to Einstein's general theory of relativity, matter or energy causes a distortion of space (or more specifically, spacetime) known as gravity. A large item produces a gravitational field by distorting the geometry of the spacetime it is located in.

Thus, general relativity states that the existence of matter bends spacetime, which causes time to slow down in a gravitational environment.

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Related Questions

A cannon is mounted on a tower above a wide, level field. The barrel of the cannon is 29.3 m above the ground below. A cannonball is fired horizontally with an initial speed of 900m/s. Assuming air resistance can be neglected, approximately how long will the cannonball be in flight before it hits the ground?
Projectile motion is a special case of kinematics, whereby an object freely moves only under the influence of gravity. To analyze an object undergoing projectile motion, one can use the kinematics equations:
x=vot+1/2at^2
v^2f=v^2o+2ax
a=vf−vo/t
where x is the displacement, v is the velocity, t is the time, and a is the acceleration. It is important to note that these equations are vector equations, and thus one must analyze the x and y components of the motion separately.

Answers

The time of flight is 2.44 seconds.

We know that third equation of motion is  [tex]S = ut + \frac{1}{2} at^{2}[/tex] where,

S = distance = 29.3 m

u = initial speed

t  = time

a = acceleration = 9.8 [tex]m/s^{2}[/tex]

In this case, the ball is fired horizontally, so vertical initial velocity is 0.

i.e. u = 0

Putting these values in above equation, we get

      29.3 = 0 + [tex]\frac{1}{2} (9.8)t^{2}[/tex]

  ⇒ t = 2.44 seconds

So the time of flight is 2.44 seconds.

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A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.

Answers

Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.

Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand  until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.

9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)

Ao = 58.2*10^-6m

9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)

comparable to case two

Ao = 40.6*10^-6m

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A block of mass m pulled with constant velocity over a floor by a force T inclined at an angle theta with the floor. The coefficient of friction between the block and the floor in mu. It is a box on floor drawn by a cord half way down fron edge at an angle of about 30 degrees from horizontal. No actual dimensions. The magnitude of the vertical component of the force exerted on the block by the floor is:a. mgb. mg-T cos thetac. mg+T cos thetad. mg-T sin thetae. T sin theta

Answers

The floor's force on the block, measured in terms of its vertical component, is expressed as follows: mg- t sin theta

What is the friction coefficient?

The resistive friction force (Fr) multiplied by the normal or horizontal force (N) forcing the objects together yields the coefficient of friction (fr), which is a numerical value. It can be represented by the equation fr = Fr/N.

What is a force?

A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the things. Newton(N) F=ma stands for the Si system of force.

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The goal of behavior modification is to
.repair troubled or broken relationships.
.unearth the origin of maladaptive behavior.
.change clients’ maladaptive or undesirable behaviors.
.modify the clients’ personality structure.

Answers

The goal of behavior modification is to change clients' maladaptive or undesirable behaviors. Behavior modification is a psychological treatment approach that focuses on changing problematic behaviors by reinforcing desirable behaviors and reducing the reinforcement of undesirable behaviors. It involves identifying the specific behaviors that need to be modified, setting goals for behavior change, and using techniques such as positive reinforcement, punishment, and extinction to modify the behaviors. The goal of behavior modification is not to repair troubled or broken relationships, unearth the origin of maladaptive behavior, or modify the clients' personality structure. These may be addressed as part of the treatment process, but they are not the primary focus of behavior modification.

if a person pulls on the rope with a constant force what is the acceleration of the system? answer in units of m/s2.

Answers

The tension in a given rope may be thought of as T = (m g) + (m a), where "g" denotes the gravitational acceleration of any items the rope is supporting and "a" denotes any additional accelerations placed on those same objects.

How do you find the tension of a rope with acceleration?Because of the forces tugging on the rope from both ends, a particular strand of thread or rope will be under strain. Remember that force is defined as mass times acceleration. Any change in mass or acceleration of the objects the rope is supporting will result in a change in the tension in the rope, assuming the rope is stretched firmly. A system's components are nevertheless subject to gravity's continual acceleration even when it is at rest. The tension in a given rope may be thought of as T = (m g) + (m a), where "g" denotes the gravitational acceleration of any items the rope is supporting and "a" denotes any additional accelerations placed on those same objects. The assumption that our rope, cable, etc. is thin, massless, and incapable of being stretched or broken is made for the majority of physics problems.Consider a system where a weight is suspended from a wooden beam using only one rope as an example (see picture). The system is completely at rest because neither the weight nor the rope are moving. Due to this, we are aware that in order for the weight to be maintained in equilibrium, the tension force and the weight's gravitational force must be equal. Or, tension (Ft) Equals force of gravity (Fg) = m g.In that case, the tension force would be 10 kg x 9.8 m/s2 = 98 Newtons, assuming the weight is 10 kg.

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a 5.0 cm -thick layer of oil is sandwiched between a 2.0 cm -thick sheet of glass and a 2.4 cm -thick sheet of polystyrene plastic.

Answers

The time taken should be 0.399 ns.

What is the refractive index?

The refractive index is the measure of bending of a light ray when passing from one medium to another. It can also be defined as the ratio of the velocity of a light ray in an empty space to the velocity of light in a substance, n = c/v.

We know that

Time  taken = Thickness of the layer / speed of the light

Also,

v = speed of sound/refractive index.

Now

T1  = 0.05*1.46/3*10^8 = 2.43*10^-10 s

t2 = 0.01*1.5/3*10^8 = 5*10^-11 s

t3 = 0.02*1.59/3*10^8 = 1.06*10^-10 s

So,

total time is

=  2.43*10^-10 + 5*10^-11 + 1.06*10^-10 = 0.399*10^-9 s

= 0.399 ns

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Classify the characteristics as describing the atmosphere of Saturn, the atmosphere of Jupiter, or the atmosphere of both. Saturn's atmosphere Jupiter's atmosphere Both Answer Bank oval storm system proportionally less bellum differential rotation fewest obvious features invisible light Answer Bank oval storm systems proportionally less helium differential rotation fewest obvious features in visible light composed of mostly hydrogen and helium most colorful in visible light thinner atmosphere Image credit: NASA

Answers

Saturn's Atmosphere :-Proportionally less helium, Thinner Atmosphere, Most colorful in visible light, Composed of hydrogen and helium.

Jupiter's Atmosphere :- Oval stroma systems, Differential Rotation, Fewer observers features in light.

Electromagnetic radiation that the human eye can see is referred to as light or visible light. Typically, visible light is characterized as having wavelengths in the 400–700 nanometer (nm) range, which corresponds to frequencies of 750–420 terahertz, lying between the infrared (with longer wavelengths) and the ultraviolet (with shorter wavelengths) (with shorter wavelengths).

In physics, the term visible light" can more widely be used to refer to electromagnetic radiation of any wavelength, whether or not it is visible.

This definition of light includes gamma rays, X-rays, microwaves, and radio waves. The main characteristics of light include intensity, polarization, frequency or wavelength spectrum, and propagation direction. One of nature's basic constants is the speed of light in a vacuum, which is 299 792 458 meters per second (m/s). Visible light travels through space by, like all forms of electromagnetic energy,

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❧ What are the images formed by a plane mirror?

Answers

The following are some properties of images formed by a plane mirror are; virtual, upright, left-right reversed, the same distance from the mirror as the object's distance, and the same size as the object.

What is a plane mirror?

When a ray of light hits a surface, then it can undergo one of the following reflection, refraction, or absorption. So mirrors are polished surfaces coated with mercury such that they reflect most of the light hitting them.

Characteristics of the image formed by a plane mirrorThe image is virtual.The image is laterally inverted.The image is erect.The size of the image is the same as the size of the object.The distance between the image obtained from the mirror is the same as the distance between the object from the mirror.

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a barrel will rupture when the gauge pressure within it reaches 350 kpa. it is attached to the lower end of a vertical pipe, with the pipe and barrel filled with oil \rho

Answers

The pipe will be 40.1 meter  if the barrel is not to rupture.

What is fluid pressure?

The pressure exerted by a fluid at equilibrium at any point due to the force of gravity is known as fluid pressure.

Given that: fluid pressure is: p = 350 kPa = 350 * 1000 Pa = 350000 Pa.

Density of fluid is: ρ = 890 kg/m^3.

Let the height of the pipe is h.

Hence, from the formula of  P = hρg we get: the height of the pipe is:

h = P/ρg

= 350000/(890×9.8) m

= 40.1 meter.

So, the pipe is 40.1 m long.

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if you know the car's potential energy and its kinetic energy, you can determine its mechanical energy through the formula .

Answers

The formula to calculate mechanical energy is ME=PE+KE. If you are aware of the kinetic and potential energies of the vehicle.

Simply put, what is kinetic energy?

The energy an entity has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

What makes kinetic energy so crucial?

The capacity to perform work is arguably the most significant characteristic of kinetic energy. Force flowing on an object while it is moving is referred to as work. Energy and work are interchangeable because of their tight relationship.

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a 1.90 kg , horizontal, uniform tray is attached to a vertical ideal spring of force constant 200 n/m and a 300 g metal ball is in the tray. the spring is below the tray, so it can oscillate up-and-down. the tray is then pushed down 16.4 cm below its equilibrium point (call this point a) and released from rest.
(a) How high above point A will the tray be when the metal ball leaves the tray?
(b) How much time elapses between releasing the system at point A and the ball leaving the tray?
(c) How fast is the ball moving just as it leaves the tray?

Answers

a)When the metal ball leaves the tray, the tray will be 10.78 cm above point A.

b) The total time between the system being released at point A and the ball leaving the tray is 0.086 seconds.

c) The speed of the ball as it exits the tray is 1.175 m/s.

Given,

Mass of tray , m_t=1.90 kg

spring of force constant, k = 200N/m

mass of the ball, m_b = 300 g

Height below the equilibrium point A = 16.4 cm

a)

The tray's height above point A when the metal ball leaves it- The total mass of the tray and ball is 2.2 kg (1.90kg+0.3 kg). The spring force is equal to the product of the spring constant and displacement.Thus,

f=kx

but we know that, f=mg

equating both the equations

[tex]mg=kx\\\\2.2*9.8=200*x\\\\21.56=200x\\\\x=\frac{21.56}{200}\\\\x=0.1078 m=10.78 cm[/tex]

As a result, the tray is pushed down 17.4 cm below its equilibrium point (point A) and released from rest. Thus, the tray's position above point A is h=16.4+10.78=27.18 cm.

b)

The total amount of time that passes between releasing the system at point A and the ball leaving the tray.

The formula for the simple harmonic function of a spring is as follows:

[tex]y=Acos(\sqrt{\frac{k}{m}}-\phi)[/tex]

Here,

y= displacement = 10.78 cm

A=amplitude i.e 16.4 cm

k= spring constant = 200 N/m

m= total mass = 2.2 kg

and [tex]\phi = 0 \degree[/tex]

[tex]10.78=16.4cos(\sqrt{\frac{200}{2.2}}t-0)\\\\\frac{10.78}{16.4}=cos(\sqrt{90.909}t)\\\\0.657=cos(9.534t)\\\\cos^{-1}(0.657)=9.5434t\\\\0.829=9.543 t\\t=\frac{0.829}{9.543}\\\\t=0.086 s[/tex]

c)

The speed at which the ball moves as it exits the tray

The total mechanical energy for simple harmonic motion of a spring can be given as,Here, take the distance measurements in meters

[tex]\frac{1}{2}mv_y^2+\frac{1}{2}ky^2=\frac{1}{2}kA^2\\\\v_y^2=k\frac{A^2-y^2}{m}\\\\v_y^2=200*\frac{0.164^2-0.1078^2}{2.2}\\\\v_y^2=90.909(0.0268-0.0116)\\\\v_y^2=1.38\\\\v_y=1.175 m/s[/tex]

Thus, the speed of ball is 1.175 m/s

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a particle of mass slides without friction on the inside of a cone in a circular orbit of radius at height above the base of the cone. the cone is rotating about the vertical axis with angular velocity . the velocity of the particle as observed in the rotating reference frame is given by . here both and are magnitudes (positive quantities). the axis of the cone is vertical and gravity points downward. the apex half-angle of the cone is

Answers

the apex half-angle of the cone is  [tex]\frac{V^{2} }{g}[/tex]

Calculation :

Ncosθ = mg   ---1

Nsinθ =[tex]\frac{mv^{2} }{r}[/tex]

divide eqn 1 and 2

tanθ = V²/rg ---3

now tan θ = h/r ---4

fro eqn 3 and 4

h=  [tex]\frac{V^{2} }{g}[/tex]

A cone is a three-dimensional geometric shape that tapers from a flat base (often not necessarily circular) to a point called the vertex or apex.

A cone is formed by a series of line segments, half-lines, or lines that connect a point (vertex) common to all points on the base in a plane that does not contain vertices. Depending on the author, the basis may be restricted to a circle, a one-dimensional square in the plane, a closed his one-dimensional figure, or any of the above plus all enclosed points. A cone is a solid object if the base contains the enclosed points. Otherwise, it is a 2D object in 3D space. For solids, the boundaries formed by these lines or partial lines are called faces. If the sides are unlimited, it is a conical surface.

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write the magnetic flux through a single turn of the coil as a function of time. remember to use si units.

Answers

Weber (Wb) and tesla meter squared (Tm2), which is called after German scientist Wilhelm Weber, is the SI unit for magnetic flux.

How can you determine the magnetic flux passing through a coil?

Using Faraday's law, it is possible to determine the size of the induced emf.The long coil's magnetic field has the formula B = 0(N/l)I.NBA = 0(N2/l)IA is the flow through the coil.

What's the formula again for rate at which magnetic flux changes over time?

Emf=Nt is the equation for the induced emf brought on by an change in magnetic flux.Faraday's law of duction is the name given to this connection.Volts are used as usual as the emf measurement units.

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match the feature on mars with the best terrestrial analogy. be sure to think broadly. the analogy can be geological, chemical, or conceptual.

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The two planets are similar in size, inclination, structure, composition, and the presence of water on their surfaces. They also have many key differences.

While Earth has 23h 56m and 4 s period of rotation, Mars's period of rotation is about 24 hours and 40 minutes. Mars is inclined on its axis, similar to Earth., It is inclined at 25.19° to its orbital plane.

They are both terrestrial planets. This means that both have a dense metallic core and also an overlying mantle and crust, which is composed of less dense materials (like silicate rock).

Mars also has a surface covered by a mountain range. Ice water exists beneath much of the Martian surface. Radar data and soil samples have confirmed the presence of shallow subsurface water at the middle latitudes as well.

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The coefficient of static friction between the incline and the 200-1b crate in (Figure 1) is pe = 0.3. Part A Determine the force P that must be applied to the rope to begin moving the crate up the incline. Express your answer in pounds to three significant figures. Figure < 1 of 1> IVO AEO J1 vec ? P = lb Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining

Answers

The force applied due to friction is 32.2 N.

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.

Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.

To solve for the minimum force, let us assume it to be F (N)

So

F=mg sin A

But

=>>>> coefficient of static friction x (F + mg cos A

=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)

So making F subject of formula

F + 24.0 = 56.2

F = 32.2N

Therefore, the force applied due to friction is 32.2 N.

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the term mechanical weathering refers to changes in a rock that are physical; there is little or no chemical change. True or False ?

Answers

The term which is called as mechanical weathering always refers to the changes in a rock which are physical and there is no or very little chemical change. So, it's True.

Mechanical weathering (additionally known as bodily weathering) breaks rock into smaller portions. These smaller portions are similar to the larger rock, simply smaller. That means the rock has modified bodily with out converting its composition. Mechanical weathering is likewise called bodily weathering. In this kind of weathering, a huge rock is disintegrated into smaller portions of rocks.

When rocks crumble or split with out experiencing any alternate of their chemical composition, it's far called mechanical weathering. The assertion approximately mechanical weathering that isn't genuine is includes a chief alternate withinside the mineral composition of the weathered material. Mechanical weathering breaks rocks down into smaller fragments, and will increase the floor location of the over all material. By growing the floor location, chemical strategies may also act extra without problems upon the rock floor.

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the loop is in a magnetic field 0.40 t whose direction is perpendicular to the plane of the loop. at t=0, the loop has area A=0.285 m2

Answers

The emf induced in the loop at t = 0 is

Part a)

[tex]$$\text { EMF }=14 \times 10^{-3} \mathrm{~V}$$[/tex]

The emf induced in the loop at t = 1.00 s

Part b)

[tex]$$E M F=15.67 \times 10^{-3} \mathrm{~V}$$[/tex]

What is emf induced ?

As we know that magnetic flux through the loop is given as [tex]$\phi=B . A$[/tex]

now we have

[tex]$$\phi=B \pi r^2$$[/tex]

now rate of change in flux is given as

[tex]\frac{d \phi}{d t}=B(2 \pi r) \frac{d r}{d t}$$[/tex]

now we know that

[tex]$$\begin{aligned}& A=\pi r^2 \\& 0.285=\pi r^2 \\& r=0.30 m\end{aligned}$$[/tex]

Now plug in all data

[tex]$$\begin{aligned}& E M F=(0.20) \times 2 \pi \times(0.30) \times(0.037) \\& E M F=14 \times 10^{-3} V\end{aligned}$$[/tex]

Now the radius of the loop after [tex]$t=1 \mathrm{~s}$[/tex]

[tex]$$\begin{aligned}& r_1=r_0+\frac{d r}{d t} \\& r_1=0.30+0.037 \\& r_1=0.337 m\end{aligned}$$[/tex]

Now plug in data in above equation

[tex]$$\begin{aligned}& E M F=(0.20) \times 2 \pi \times(0.337) \times(0.037) \\& E M F=15.67 \times 10^{-3} V\end{aligned}$$[/tex]

Complete question:The loop is in a magnetic field 0.40 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A = 0.285 square m.Suppose the radius of the elastic loop increases at a constant rate, dr/dt = 3.70 cm/s .

A) Determine the emf induced in the loop at t = 0.

B)Determine the emf induced in the loop at t = 1.00 s .

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A spring has an unstretched length of 10 cm. It exerts a restoring force F when stretched to a length of 11 cm.
a. For what length of the spring is its restoring force 3F?
b. At what compressed length is the restoring force 2F
a) The length for 3F force is : 13 cm
b) The length for 2F force is : 8 cm

Answers

The required length and compressed length of the spring at the given force values are 13 cm and 8 cm respectively.

Explanation:

F = ke

k = spring constant ;

e = extension;

e = (Final length - Initial length)

Initial length, l = 10

Final length = L1 = 11

F = k(11 - 10)

F = k;

Length for a restoring force of 3F ;

3F = k(Final length - Initial length)

k = F

3F = F(L1 - 10)

3F = - 10F + F(L1)

F(L1) = 3F + 10F

F(L1) = 13F

L1 = 13

Hence, required length ls 13 cm

B.)

Let compressed length = c

2F = F(initial length - compressed length)

2F = F(10 - c)

2F = 10F - F(c)

F(c) = 10F - 2F

F(c) = 8F

c = 8F / F

c = 8 cm

Therefore, the required compressed length ls 8 cm

Spring:

A spring is an elastic body that stores mechanical energy. Coil springs are often used in daily life, but there are many different types of springs. Modern quills are usually made of spring steel, but non-metallic items like bows are also quills.

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What forces are acting on an airplane as it flies at a constant velocity through the air?; When the plane is flying at a constant height which two forces must be balanced?; Which two forces must be balanced if the airplane is to fly at a constant forward velocity?; Is an airplane cruising in level flight a balanced or unbalanced force?

Answers

Thrust, drag, lift, and weight is the forces that act on all aircraft in flight.

Thrust is the forward force produced by the propulsion unit/propeller or rotor.

Drag is the backward force caused by the disturbance of airflow by the wing, rotor, fuselage, and other objects.

When the plane is flying at a constant height, the force of thrust must equal the opposite force of drag, then only the airplane can experience uniform motion in one direction.

All four forces act on an airplane must equate to each other for an airplane to fly straight and level at a constant speed, the lift it creates balances its weight, and the thrust it creates balances its drag.

An unbalanced force changes the equilibrium state of a body. As with an aircraft cruising in level flight, the weight of the aircraft will equally lift and thrust will equal drag. So, the plane experiences a balanced force.

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heat is transferred at a rate of 2 kw from a hot reservoir at 775 k to a cold reservoir at 300 k. calculate the rate at which the entropy of the two reservoirs changes. (round the final answer to six decimal places.) the rate at which the entropy of the two reservoirs changes is kw/k. is the second law satisfied? (click to select)

Answers

the rate at which the entropy of the two reservoirs changes is 0.004081 KW/K

Yes, the second law is satisfied.

claculation :

ΔS = Q/T (entropy formula)

ΔS1 = 2/300 = 0.006667 KW/K

ΔS2 = 2/715 = 0.002580

Δs = 0.006667 - 0.002580

Δs = 0.004081 KW/K

Yes, the second law is satisfied.

Entropy is a scientific concept and a measurable physical property most commonly associated with states of disorder, randomness, or uncertainty. The term and concept are used in a variety of fields, from classical thermodynamics, where it was first recognized, to microscopic descriptions of nature in statistical physics, to principles of information theory. It finds a wide range of applications in information systems, including information transmission in chemistry and physics, the relationship between biological systems and life, cosmology, economics, sociology, weather science, climate change, and communications.

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find the speed se of the spacecraft when it crashes into the earth. express the speed in terms of me , re , and the universal gravitational constant g .

Answers

Speed of the spacecraft right before the collision:[tex]\sqrt{} \frac{2G.Me}{Re}[/tex] .

Assumption: the earth is exactly spherical with a uniform density.

What is the magnitude of the gravitational force acting on the Earth due to the sun?The magnitude of the gravitational force acting on the Sun due to the Earth is 3.52×1022 3.52 × 10 22 Newtons.

This question could be solved using the conservation of energy.

The mechanical energy of this spacecraft is the sum of:

the kinetic energy of this spacecraft, and

the (gravitational) potential energy of this spacecraft.

Let  denote the mass of this spacecraft. At a distance of  from the center of the earth (with mass ), the gravitational potential energy () of this spacecraft would be:

[tex]GPE=\frac{G.Me.M}{R}[/tex]

Initially,  (the denominator of this fraction) is infinitely large. Therefore, the initial value of  will be infinitely close to zero.On the other hand, the question states that the initial kinetic energy () of this spacecraft is also zero. Therefore, the initial mechanical energy of this spacecraft would be zero.Right before the collision, the spacecraft would be very close to the surface of the earth. The distance  between the spacecraft and the center of the earth would be approximately equal to , the radius of the earth.The  of the spacecraft at that moment would be:Subtract this value from zero to find the loss in the  of this spacecraft:Assume that gravitational pull is the only force on the spacecraft. The size of the loss in the  of this spacecraft would be equal to the size of the gain in its .Therefore, right before collision, the  of this spacecraft would be:On the other hand, let  denote the speed of this spacecraft. The following equation that relates  and  to :Rearrange this equation to find an equation for :It is already found that right before the collision, . Make use of this equation to find  at that moment:

[tex]\sqrt{} \frac{2KE}{M}[/tex]=[tex]\sqrt{\frac{2G.Me}{Re} }[/tex]

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You want to siphon rainwater and melted snow from the cover of an above-ground swimming pool. The cover is 2.1 m above the ground. You have a plastic hose of 1.5 cm radius with one end in the water on the pool cover and the other end on the ground.
If you want to empty the pool cover in half the time, how much wider should the hose be?​

Answers

Answer:

Below

Explanation:

You will need a hose with double the cross sectional area

 Area = pi r^2    

          pi * (1.5)^2 = 2.25 pi

  now double it to 4.5 pi and solve for r

           4.5 pi = pi r^2

             4.5 = r^2     r = 2.12 cm radius

2.12 - 1.5 = the hose radius should be increased .621 cm

                      this would be .621 * 2 = 1.24 cm wider

in today's demonstration, a nonmoving ball placed at the top of the ramp is an example of question 5 options: chemical energy gravitational potential energy elastic potential energy kinetic energy

Answers

Gravitational Potential Energy is demonstrated by a stationary ball put at the top of a ramp. The energy that a body has or acquires is known as gravitational potential energy.

because when something is in a gravitational field, it changes position. It is, to put it simply, energy that results from gravitational force or gravity. Taken two pencils is the most typical illustration. If one pencil is set down on a table and the other is raised above it, the pencil raised will have more gravitational potential energy than the pencil set down on the table. The equation U = mgh is used to compute it. The mass, m, is expressed in kilograms.

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If the bond energies of X2 and C-X are 151.9 kJ and 2763 kJ, respectively, and the bond energies of C-C and C-c are 338 kJ and 604 kJ, respectively, give an estimate of AE for the reaction below: C2H4 + X2 => c2H4X2 (in kJ). (Enter your answer as the nearest whole number without units)

Answers

= [ 4 (C-H) + 1 (C=C) + 1 (X2) ] - [ 2 (C-X) + 1 + (C-C) + 4 (C-H)

= [ (C=C) +(X2) ] - [ 2 (C-X) + 1 (C-C) ]

= [ 604 +151.9 ] - [ 2 (276.3) + (338)]

= -134.7 KJ

= -135 KJ

Bond energies depend on the number of bonds between atoms. Even though π bonds are weaker than σ bonds, a double bond, which consists of a σ and π is bond, is stronger than a single bond because there are  bonds.

A quantity of strength, equal to the distinction among the energies of the Bond energies depend on the number of bonds between atoms. Atoms and the energies of the separated atoms, is released, usually as warmness. that is, the bonded atoms have a lower strength than the character atoms do.

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What are acceleration vs. time graphs?

Answers

The acceleration versus time graphs are the mathematical representation of the variation of acceleration with time.

There are several methods of representing the variation of two quantities one such method is graphs.

When the variation of the acceleration of the object and the time taken by the object to reach at acceleration are plotted on a graph the provides us with a few certain quantities.

For an example the slope of the acceleration-time graph tell us about the sudden change in acceleration at that particular instant.

Also the area under the acceleration vs. time graph represents the change in velocity of the object.

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the output of the supply must be electrically isolated from the source and must contain some type of switching converter. the system is to use a feedback control to maintain proper output voltage throughout the full range of input voltages and frequencies.

Answers

The supply's output must have some sort of switching converter and must be electrically insulated from the source. Throughout the whole range of input voltages and frequencies, the system is to apply a feedback control to ensure proper output voltage.

Voltage, also referred to as electric tension, electric pressure, or (electric) potential difference, is the difference in electric potential between two places. It is equivalent to the labor required to transfer a test charge between two places in a static electric field. The derived unit for voltage in the metric system is referred to as a volt. One volt equals one joule (of work) for one coulomb, which is how to work per unit charge is defined in SI units (of charge). Power and current were employed in the earlier SI definition for the volt; starting in 1990, the quantum Hall and Josephson effect was applied; and most recently (as of 2019), fundamental physical constants were added to the definitions of all SI units and their derivative units.

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in a certain 2-slit combined interference and diffraction experiment, the fifth interference maximum and the first diffraction minimum are located at the same angle relative to the center of the screen.

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In a two-slit interference and diffraction experiment, the fifth interference maximum and the first diffraction minimum can occur at the same angle relative to the center of the screen under certain conditions.

In a diffraction experiment, light waves passing through the two slits can also diffract and spread out, producing a pattern of bright and dark fringes on the screen. The position of the dark fringes, also known as diffraction minima, is determined by the wavelength of the light and the size of the slits.

If the fifth interference maximum and the first diffraction minimum occur at the same angle relative to the center of the screen, it means that the path difference between the waves passing through the two slits is equal to the wavelength of the light. This can be achieved by adjusting the separation between the slits, the distance between the slits and the screen, and the wavelength of the light.

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a fixed amount of a monatomic ideal gas is taken through the following cyclic process. originally (a) it is near atmospheric pressure (100 kpa) with a volume of 0.50 m3 and a temperature of 375 k. then it is isothermally compressed to half its volume (b). then its volume triples (c) during an isobaric expansion.

Answers

The qualitative sketch of the process on the PV plane is attached below:

What is  ideal gas equation?

The ideal gas law (also called the perfect gas law), the relationship between pressure P, volume V, and temperature T of a gas in the boundary region between low pressure and high temperature. Gas molecules move almost independently. each other. In such cases, all gases obey an equation of state known as the ideal gas law.

PV = nRT, where n is the number of moles of gas and R is the universal (or complete) gas constant, 8.31446261815324 joules/kelvin/mol (the universal gas constant is defined as Avogadro's number NA multiplied by Boltzmann's constant k) . ) In the International System of Units, energy is measured in joules, volume in cubic meters (m3), force in newtons (N), and pressure in pascals (Pa). where 1 Pa = 1 N/m2. A force of 1 Newton moving a distance of 1 meter does 1 Joule of work. Therefore, the dimension of both products PV and nRT is work (energy).

The qualitative sketch of the process is drawn on the PV plane.

At A,

P₁ = 100 kPa

V₁ = 0.50 m³
T₁ = 375 K

At B,

T₂ = 375 K

V₂ = 0.25 m³
P₁V₁ = P₂V₂

So, P₂ = (100× 10³ ×0.50)/ 0.25

= 200 kPa

At C,

P₃ = 200 kPa

V₃ = 0.75 m³

We know, V₂/ T₂ = V₃/ T₃

So,

T₃ = V₃T₂/ V₂

= (0.75 × 375)/ 0.25

= 1125 K

At D,

P₄ = 100 kPa

T₄ = 1125 K

V₄ = P₃V₃/ P₄

= (200 × 0.75)/ 100

= 1.5 m³

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The complete question is:

A rocket fired horizontally at 50m/s breaks into 2 equal masses. One mass, m1, deflects 30ᴼ above the horizontal while the other mass, m2, deflects 60ᴼ below the horizontal. Find the velocities for m1 and m2 at that moment.

Answers

Answer:When a rocket is fired horizontally at 50 m/s and breaks into two equal masses, m1 and m2, the velocities of the two masses at the moment of separation can be determined using the principles of conservation of momentum and conservation of kinetic energy.

According to the principle of conservation of momentum, the total momentum of an isolated system remains constant, unless an external force is applied. This means that the total momentum of the two masses before and after the separation must be the same. Since the two masses are equal and the initial velocity of the rocket is 50 m/s, the total initial momentum of the system is 50 m/s x 2 masses = 100 m/s.

After the separation, the momentum of m1 is equal to the initial momentum of the system, since the direction of motion has not changed. This means that the velocity of m1 is 50 m/s.

The momentum of m2, however, has changed due to the deflection of 60ᴼ below the horizontal. The direction of motion of m2 is now perpendicular to the initial direction of the rocket, and the magnitude of the momentum is equal to the initial momentum of the system. Using the law of cosines, we can determine the magnitude of the velocity of m2 as follows:

v2 = (100 m/s) / (cos 60ᴼ)

v2 = 50 m/s

Therefore, the velocities of m1 and m2 at the moment of separation are 50 m/s and 50 m/s, respectively.

Explanation:

a car is traveling at 16 m/s . part a how fast would the car need to go to double its kinetic energy? express your answer with the appropriate units.

Answers

Answer: 22.63 m/s

Explanation:

Not sure if this is the right answer.

[tex]\frac{1}{2} m(v)^2=2(\frac{1}{2} m(16)^2 )[/tex]

[tex]\frac{1}{2} (v)^2=(16)^2[/tex]

[tex]v = 22.63 \frac{m}{s}[/tex]

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