Add 10% of 300 to 50% of 20

Well, 30+23+23 = 76 which means there are only a total of 76 bags that are accounted for. 110-76 = 34 bags which we do not know if they have zips or not. If we assume they have zips, that would be 34+23 bags with zips which is 57 bags.

[tex]\begin{array}{ccll} Juice&OJ\\ \cline{1-2} \frac{2}{3}&\frac{1}{3}\\[1em] x&1 \end{array}\implies \cfrac{~~ \frac{2}{3}~~}{x}=\cfrac{~~\frac{1}{3} ~~}{1}\implies \cfrac{~~ \frac{2}{3}~~}{x}=\cfrac{1}{3}\implies \cfrac{~~ \frac{2}{3}~~}{\frac{x}{1}}=\cfrac{1}{3} \\\\\\ \cfrac{2}{3x}=\cfrac{1}{3}\implies 6=3x\implies \cfrac{6}{3}=x\implies 2=x[/tex]

Answer: 125

Step-by-step explanation: ∠4 and 55 are supplementary angles. This means that ∠4 and 55 add up to 180. We can use this to solve for ∠4.

180 - 55 = ∠4

125 = ∠4

So, ∠4 is equal to 125 degrees.

Would appreciate brainly <3

Answer:

240oz.

Step-by-step explanation:

15oz=1batch

She needs 16 batches.

15oz. x 16batches = 240oz.

Hope this helps :)

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Step-by-step explanation:

use SOHCAHTOA as shown above in the picture

Using the logarithmic function, it is found that:

a) The initial score is of 92.

b) After 6 months, the score is of 88.6.

c) After 18 months, the score is of 86.9.

The average score after t months is modeled by:

[tex]f(t) = 92 - 4\log{(t + 1)}[/tex]

Item a:

The initial score is of f(0), hence:

[tex]f(0) = 92 - 4\log{1} = 92 - 0 = 92[/tex]

The initial score is of 92.

Item b:

After 6 months, the score is of f(6), hence:

[tex]f(6) = 92 - 4\log{7} = 88.6[/tex]

After 6 months, the score is of 88.6.

Item c:

After 18 months, the score is of f(18), hence:

[tex]f(6) = 92 - 4\log{19} = 86.9[/tex]

After 18 months, the score is of 86.9.

A similar problem is given at https://brainly.com/question/24286043

Answer:

y=2x-2

You use rise/run in this problem

Answer:

I think it'

is A and B

Step-by-step explanation:

hope hwlps

Answer:

  x = -2

Step-by-step explanation:

The expression f(x) = 1 corresponds to the point on the graph that is 1 unit above the x-axis. You can locate that horizontal line and see where it intersects the graph. That point of intersection  is 2 grid squares to the left of the y-axis, where x = -2.

  f(-2) = 1

  x = -2

Answer:

Your answer would be x=2±√5

Step-by-step explanation:

Answer:

yes, the triangle are congruent by SAS

Answer:

x = 6

Step-by-step explanation:

Because we have parallel lines, we can use alternate angles are equal. Therefore, we know that 11x-6 = 10x.

Minus 11 from both sides, and we get -6 = -x, so x = 6

Answer:

C. 9x=18

Step-by-step explanation:

3x+2(3x)=18

3x+6x=18

9x=18

Answer:

Step-by-step explanation:

First get the (m) which is the gradient by using the formula y2-y1/x2-x1

Pick any random 2 values from the table. I will pick. (1,4) (2,8)

Y2=8  Y1=4   X2=2  X1=1

8-4/2-1    4/1  = 4

Y=4x+c

Answer:

y = -2x + 1

Step-by-step explanation:

Substitute  the slope and the given point into y = mx + b and solve for "b".

y = mx + b

7 = -2(-3) + b

7 = 6 + b

1 = b       the y-intercept is 1

The equation of the line is y = -2x + 1

Answer:

s=4

Step-by-step explanation:

area of square is side*side

so that means s*s=16

so s = 4

Answer

1. ΔABC ≅ ΔEFG

2. ΔMKL ≅ ΔVKU

3. ΔMLN ≅ ΔNCD (With this one I couldn't fully read the letter in the middle. I couldn't tell if it was an N or a B so just swap it for the right letter. <3)

4. ΔFGH ≅ ΔRHQ

5. ΔUVL ≅ ΔMNL

6. ΔQRS ≅ ΔVUT

Step-by-step explanation:

hope this helps. . .<3

good luck! UwU

Hello!

-5(x+2)=35

-5x-10=35

-5x=35+10

-5x=45

x=-9

Hope it helps!

~Just a determined gal

#CarryOnGainingKnowledge

[tex]MysteriousNature[/tex]

Answer:

x = -9

Step-by-step explanation:

-5(x + 2) = 35

~Distribute

(-5 * x) + (-5 * 2) = 35

~Simplify

-5x - 10 = 35

~Add 10 to both sides

-5x = 45

~Divide -5 to both sides

x = -9

Best of Luck!

Answer:

33

Step-by-step explanation:

What are you asking?

Answer:

2 parks

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

There would be 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20

Answer:

The traditional scale consists of two plates or bowls suspended at equal distances from a fulcrum. One plate holds an object of unknown mass (or weight), while known masses are added to the other plate until static equilibrium is achieved and the plates level off, which happens when the masses on the two plates are equal. The perfect scale rests at neutral. A

Answer:

where is the problem to solve. please tell me

Answer:

5/4 and 7/4 are the two solutions.

Answer:

1. 0.74 = 74%

4. 0.617 = 61.7

6. 68% = 0.68

9. 175% = 1.75

2. 0.15 = 15%

5. 0.834 = 83.4%

7. 34% = 0.34

10. 200% = 2.00

3. 0.09 = 9%

8. 58.5% = 0.585

Step-by-step explanation:

Answer:

E

Step-by-step explanation:

Like and give 5 star rating

Usando técnicas de conteo, se encuentra que

1. Un cliente puede ordenar una comida de 784 formas.

2. 420 grupos de 4 letras se pueden formar con las letras de la palabra TECNICA.

3. 840 números de 4 dígitos se pueden formar con los primeros 7 números naturales.

4. 10 partidos distintos se pueden realizar.

5. Pueden colocarse de 3,628,800 formas.

6. 1260 señales distintas pueden indicarse.

Item 1:

La técnica usada es el principio fundamental de conteo, que afirma que si hay n cosas, cada una con [tex]n_1, n_2, \cdots, n_n[/tex] maneras de seren realizadas, el número total de maneras de ser realizadas es:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

En este problema, [tex]n_1 = 14, n_2 = 8, n_3 = 7[/tex], por eso:

[tex]T = 14 \times 8 \times 7 = 784[/tex]

Un cliente puede ordenar una comida de 784 formas.

Item 2:

El orden es importante, ya que TECN es una palabra diferente de NCET, por lo tanto, la fórmula de permutaciones se usa para resolver este problema.

Fórmula de permutaciociones:

El número de permutaciones de x elementos en un conjunto de n elementos es dada por:

[tex]P_{n,x} = \frac{n!}{(n - x)!}[/tex]

En este problema, 4 letras de 7, enconteces:

[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]

La letra C se repite dos veces, o sea:

[tex]T = \frac{P_{7,4}}{2} = \frac{840}{2} = 420[/tex]

420 grupos de 4 letras se pueden formar con las letras de la palabra TECNICA.

Item 3:

Permutaciones de 4 dígitos de 7, sin repeticiones, o sea:

[tex]P_{7,4} = \frac{7!}{3!} = 840[/tex]

840 números de 4 dígitos se pueden formar con los primeros 7 números naturales.

Item 4:

El orden no es importante, ya que Time 1 x Time 2 es la misma partida de Time 2 x Time 1, por lo tanto, la fórmula de combinaciones se usa para resolver este problema.

Fórmula de combinaciones:

El número de combinaciones de x elementos en un conjunto de n elementos es dada por:

[tex]C_{n,x} = \frac{n!}{x!(n - x)!}[/tex]

En este problema, combinaciones de 2 elementos de un conjunto de 5, entonces:

[tex]C_{5,2} = \frac{5!}{2!3!} = 10[/tex]

10 partidos distintos se pueden realizar.

Item 5:

El número de arreglos de n elementos viene dado por

[tex]A_n = n![/tex]

En este problema, arreglo de 10 elementos, o sea:

[tex]A_{10} = 10! = 3628800[/tex]

Pueden colocarse de 3,628,800 formas.

Item 6:

El número de arreglos de n elementos, con repeticiones de [tex]n_1, n_2, \cdots n_n[/tex] elementos viene dado por

[tex]A_n^{n_1,n_2,\cdots,n_n} = \frac{n!}{n_1!n_2! \cdots n_n!}[/tex]

En este problema, [tex]n = 9, n_1 = 3, n_2 = 2, n_3 = 4[/tex], por eso:

[tex]A_9^{3,2,4} = \frac{9!}{3!2!4!} = 1260[/tex]

1260 señales distintas pueden indicarse.

Un problema similar es dado en https://brainly.com/question/19022577

Answer:

62

Step-by-step explanation:

SA=2(5x2)+2(5x3)+2(3x2)

SA=20+30+12

SA=62