ADDITIONAL 100 POINTS PLS HELP ASAP follow up question ( first question on log )

[tex]answer = 17.85 {inches} \\ solution \\ radius = 5 \: inches \\ perimeter \: of \: quarter \: circle \\ = \frac{2\pi \: r}{4} + 2r \\ = \frac{2 \times 3.14 \times 5}{4} + 2 \times 5\\ = \frac{31.4}{4} + 10 \\ = \frac{31.4 + 10 \times 4}{4} \\ = \frac{31.4 + 40}{4} \\ = \frac{71.4}{4} \\ = 17.85 \: {inches} \\ hope \: it \: helps[/tex]

Answer:

17.85 in

Step-by-step explanation:

2πr is formula for the circumference but [tex]\frac{1}{2}[/tex]×π×r is the circumference for the quarter circle.

0.5×π×5=

2.5π≈

7.85

7.85+5+5=17.85 in

Answer:

a)  "K" is proportional Constant   K= 0.0833

b)     The value of b = 99.639

Step-by-step explanation:

Explanation :-

Given   'a' is directly proportional to 'b'

                     a ∝ b

                 a  =  k b ....(i)

where "K" is proportional Constant

Case(i):-

when a =6  and b=72

              a  =  k b    

         ⇒ 6 = k (72)

       ⇒  [tex]K = \frac{6}{72} = \frac{1}{12} = 0.0833[/tex]      

Case(ii):-      

Given  a = 8.3  

          a  =  k b    

⇒   8.3 = 0.0833 ×b

⇒  [tex]b = \frac{8.3}{0.0833} = 99.639[/tex]

Final answer:-

a)"K" is proportional Constant   K= 0.0833

b)     The value of b = 99.639

Step-by-step explanation:

The last option 45 and 46

Answer:

its 4-5 not 45-46 \

Step-by-step explanation:

Answer:

  x = -1/5, x = 1

Step-by-step explanation:

Maybe you want to find x.

Subtract the right side and collect terms.

  6x^2 +4x^2 -6x -4 -(2x -2) = 0

  10x^2 -8x -2 = 0

  5x^2 -4x -1 = 0 . . . . . . divide by 2

  (5x +1)(x -1) = 0 . . . . . . factor

Solutions are the values of x that make these factors zero:

  5x +1 = 0   ⇒   x = -1/5

  x -1 = 0   ⇒   x = 1

Solutions are x = -1/5, x = 1.

Answer:

Hypotenuse = 13.798 cm, Angle1 = 27.4° and Angle2 = 62.59°

Step-by-step explanation:

The first step to help us understand the question would be to draw it out.

A right angled triangle, with the two sides that make the right angle being x and y (it does not matter which way you put x and y).

I have attached the quick sketch I will refer to.

To find the length of the hypotenuse (lets call it H) we can use Pythagoras theorem as shown below

[tex]{x^{2}+y^{2}} = H^{2}[/tex]

Substitute in our values for x and y, and solve for H

[tex]{6.35^{2}+12.25^{2}} = H^{2}[/tex]

[tex]190.385 = H^{2}[/tex]

[tex]\sqrt{190.385} = H[/tex]

H = 13.79 cm

To find the other two angles of the triangle we will use trigonometry

I will first look for angle ∅. Since we have all three sides of the triangle we can use any of the three trig functions, I chose to use Tan

Tan ∅ [tex]= \frac{opposite}{adjacent}[/tex]

Substitute in our values for x and y, and solve for ∅

Tan ∅ = [tex]\frac{6.35}{12.25}[/tex]

∅ = [tex]tan^{-1} \frac{6.35}{12.25}[/tex]

∅ = 27.4°

Now do the same for angle β. I chose to use Tan again

Tan β [tex]= \frac{opposite}{adjacent}[/tex]

Substitute in our values for x and y, and solve for β

Tan β = [tex]\frac{12.25}{6.35}[/tex]

β = [tex]tan^{-1} \frac{12.25}{6.35}[/tex]

β = 62.59°

Answer:

2, -1/2

Step-by-step explanation:

2m²-3m-2=0

2m² - 4m + 1m - 2=0

2m(m-2)+(m-2)=0

(2m+1)(m-2)=0

2m+1=0 ⇒ m= -1/2

m-2=0 ⇒ m=2

Answer:

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle [tex]\triangle ABC[/tex] with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles [tex]\angle A, \angle B, \angle C[/tex]

As per Law of cosine:

[tex]cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}[/tex]

Putting the values of a,b and c to find out angles [tex]\angle A, \angle B, \angle C[/tex].

[tex]cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ[/tex]

[tex]cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ[/tex]

[tex]cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ[/tex]

Camera 2nd has to cover the maximum angle, i.e. [tex]78.70^\circ[/tex].

Answer:

[tex]cos=\frac{4}{5}[/tex]

Step-by-step explanation:

Cosine is the adjacent side over the hypotenuse (You can remember sin, cos, and tan by using sohcahtoa or sin = opposite/hypotenuse, cos = adjacent/hypotenuse, tan = opposite over adjacent). I think a picture would help, too.

I attached a picture of what I think the triangle would look like.

If the picture is right (we're assuming it is) and going with what we're given (the triangle was addressed as triangle XYZ, meaning that angle Y is in the middle and that's the one we'll use).

Looking at my picture then:

[tex]cos=\frac{64}{80} \\cos=\frac{8}{10} \\cos=\frac{4}{5}[/tex] .

Answer:

1. Option c

2. Option d

Step-by-step explanation:

This type of survey is includes a sample made up of voluntary responses. People only choose to or do not choose to respond.

This type of sampling method is most of the time unbelievable because generally only people with strong opinions about this particular questions will respond and it is usually towards the same direction as the question and this might not reflect the opinion of the whole population making the survey biased.

Part A: The respondents are a voluntary response sample (Option C)

Part B: Responses may not reflect the opinions of the general population (Option D)

The total number of internet users = 1072

Percentage of the total number of people that chose to respond = 38%

Note that this survey does not compel all the population to respond to the survey. Responses are gotten from voluntary respondents.

Also note that a voluntary response sample is a sample that consists of participants who chose to participate in a sample group voluntarily.

In this type of survey, the people who decided to provide voluntary responses to the survey are called voluntary response samples

The percentage of those that chose to respond to this survey (38%) is less than half of the total population. This obviously shows that the responses may not reflect the opinions of the general population

Learn more on sampling methods here: https://brainly.com/question/16587013

Answer:

around 68 minutes 31 seconds.

Step-by-step explanation:

10km = miles = 6.21x11 = 68.31

Answer:

a. The mean would be 0.067

The standard deviation would be 0.285

b. Would be of 1-e∧-375

c. The probability that both of them will be gone for more than 25 minutes is 1-e∧-187.5

d. The likelihood of at least of one of the taxis returning within 25 is 1-e∧-375

Step-by-step explanation:

a. According to the given data the mean and the standard deviation would be as follows:

mean=1/β=1/15=0.0666=0.067

standard deviation=√1/15=√0.067=0.285

b. To calculate How likely is it for a particular trip to take more than 25 minutes we would calculate the following:

p(x>25)=1-p(x≤25)

since f(x)=p(x≤x)=1-e∧-βx

p(x>25)=1-p(x≤25)=1-e∧-15x25=1-e∧-375

c. p(x>25/2)=1-p(x≤25/2)=1-e∧-15x25/2=1-e∧-187.5

d. p(x≥25)=1-e∧-15x25=1-e∧-375

Answer:

a

the displacement of the plane is  [tex]- \= w[/tex]

b

The displacement of plane  from Portland to Akron with layover at Houston is  

       [tex]\= v + \= w[/tex]

c

  the vector which defines this displacement is  [tex]\= v + \= w =- 2500 \ km[/tex]

Step-by-step explanation:

From the question we are the

   The displacement from Portland, Oregon to Houston, Texas. is  [tex]\= v[/tex]

    The displacement  from Houston, Texas to Akron, Ohio.  is [tex]\= w[/tex]a

a

   The motion of the plane in question a is in the opposite direction to vector [tex]\= w[/tex]

So the displacement of the plane is  [tex]- \= w[/tex]

b

The motion of Portland to Houston to Akron is in the direction of both vector [tex]\= v[/tex] and  [tex]\= w[/tex]  so

The displacement of plane  from Portland to Akron with layover at Houston is  

       [tex]d = \= v + \= w[/tex]

c

From the question we are told that the plane flies over Portland to get to  Anchorage, Alaska which implies that it is moving in opposite direction to the vector [tex]\= v[/tex]

   Give that distance from Portland to Houston is  [tex]\= v = 3000 km[/tex]

           and the distance from Portland to  Anchorage is [tex]\= w = - 5500[/tex]km

Then the vector which defines this displacement is mathematically represented as

   [tex]\= v + \= w = 3000 -5500[/tex]

    [tex]\= v + \= w =- 2500 \ km[/tex]

Answer:

  D.  x is all real numbers

Step-by-step explanation:

The graph only goes from -11 to +11 in the horizontal direction, but that domain is not a choice. Apparently, we're to assume the graph extends to infinity both to the left and the right.

The domain is the horizontal extent of the function, so is ...

  x is all real numbers

Answer:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]   we can conclude that the  function is an increasing function.

Step-by-step explanation:

Given that:

[tex]\dfrac{dC}{dt}= r-kC[/tex]

[tex]\dfrac{dC}{r-kC}= dt[/tex]

By taking integration on both sides ;

[tex]\int\limits\dfrac{dC}{r-kC}= \int\limits \ dt[/tex]

[tex]- \dfrac{1}{k}In (r-kC)= t +D[/tex]

[tex]In(r-kC) = -kt - kD \\ \\ r- kC = e^{-kt - kD} \\ \\ r- kC = e^{-kt} e^{ - kD} \\ \\r- kC = Ae^{-kt} \\ \\ kC = r - Ae^{-kt} \\ \\ C = \dfrac{r}{k} - \dfrac{A}{k}e ^{-kt} \\ \\[/tex]

[tex]C(t) =\frac{ r}{k} - \frac{A}{k}e^{ -kt}[/tex]

where;

A is an integration constant

In order to determine A, we have C(0) = C0

[tex]C(0) =\frac{ r}{k} - \frac{A}{k}e^{0}[/tex]

[tex]C_0 =\frac{r}{k}- \frac{A}{k}[/tex]

[tex]C_{0} =\frac{ r-A}{k}[/tex]

[tex]kC_{0} =r-A[/tex]

[tex]A =r-kC_{0}[/tex]

Thus:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

b ) Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer

[tex]C_{0} < \lim_{t \to \infty }C(t)[/tex]

[tex]C_0 < \dfrac{r}{k}[/tex]

[tex]kC_0 <r[/tex]

The equation for C(t) can therefore be re-written as :

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k} - \left (+ve \right )e^{ -kt} \\ \\C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]

Thus; we can conclude that the above function is an increasing function.

Answer:

  4.  the set of all natural numbers, the set of all whole numbers, the set of all integers, the set of all rational numbers, and the set of all real numbers

Step-by-step explanation:

√9 = 3

3 is every kind of number except irrational. It belongs to the sets of ...

Answer:

Step-by-step explanation:

p(x)=2x^2

q(x)=x-3

(p•q)(x)=2(x-3)^2

2(x^2-6x+9)

2x^2-12x+18

Answer:

Step-by-step explanation:

Let s, b, a represent the numbers of servings of steak, baked eggs, and acorn squash, respectively. Then the equations we want to solve are ...

  40s +20b +4a = 64 . . . . grams of protein

  10s +2b +20a = 29 . . . . grams of carbohydrate

  1s +20b +32a = 72.5 . . . milligrams of vitamin A

There are any number of calculators or web sites that will solve this system of equations for you. The solution is ...

  s = 0.5

  b = 2

  a = 1

The dietitian should provide 1/2 serving of steak, 2 servings of baked eggs, and 1 serving of acorn squash.

Answer:

56%

Step-by-step explanation:

Any number out of 100 is that number's percent.

If it's for say 0.1/100, its 0.1%.

Answer:

360 x 30% = answer

30% = 30/100 = 0.3

360 x 0.3 = 108

108 is the answer

Hope this helps

Step-by-step explanation:

Answer:

108 pages

Step-by-step explanation:

30% of 360=108

360*.30=108

Answer:

Step-by-step explanation:

Answer:

972^1/4 = 4 ⁴√3

448^1/3 = 4 ³√7

3528^1/2 = 42√2

4050^1/4 = 3 ⁴√50

Hope this helps.

Answer:

A. (I) v = 46.42 m/s; (ii) v = 47.35 m/s; (III) v = 48.09 m/s; (iv) v = 48.26 m/s; (v) v = 58.28 m/s

B. v = 48.28 m/s

Note: the question is missing some values. The full Question is provided below:

If an arrow is shot upward on Mars with a speed of 52 m/s, its height in meters t seconds later is given by y = 52t − 1.86t2. (Round your answers to two decimal places.)

(a) Find the average speed over the given time intervals. (i) [1, 2] m/s (ii) [1, 1.5] m/s (iii) [1, 1.1] m/s (iv) [1, 1.01] m/s (v) [1, 1.001] m/s

(b) Estimate the speed when t = 1. m/s

Step-by-step explanation:

Height, y = 52t - 1.86t²

Velocity = ∆y/∆t = 52 - 1.86 * 2t = 52- 3.72t

A. Average velocity = (v1 + v2)/2

(i) At t = 1, 2

Average velocity = (52 - 3.72*1 + 52 -3.72*2)/2 = 46.42 m/s

(ii) At t = 1,1.5

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.5)/2 = 47.35 m/s

(iii) At t = 1,1.1

Average velocity = (52 - 3.72*1 + 52 -3.72*1.1)/2 = 48.09m/s

(iv) At to = 1, 1.01

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.01)/2 = 48.26 m/s

(iv) At t = (1, 1.001)s

Average velocity = (52 - 3.72*1 + 52 - 3.72*1.001)/2 = 48.28 m/s

B. Speed at t = 1s

Velocity = 52 - 3.72 * 1 = 48.28 m/s

Answer:

1/4845

Step-by-step explanation:

The probability of selecting a defective cog first is

1/5

The second cog is

3/19

The third cog is

1/9

And the fourth cog is

1/17

Multiplying these together we get

1/5 * 3/19* 1/9 * 1/17  = 1/4845

The probability of selecting 4 cogs from the 20 produced where all are defective is approximately 0.000206.

Probability is a measure of how likely an event is to occur. Many events are impossible to predict with absolute certainty.

The probability of selecting 4 defective cogs from the 20 produced can be calculated as follows:

P(4 defective cogs) = (Number of ways to select 4 defective cogs) / (Total number of ways to select 4 cogs from 20)

The number of ways to select 4 defective cogs can be found by selecting 4 defective cogs out of the 4 defective cogs produced, and 0 non-defective cogs out of the remaining 20-4=16 non-defective cogs. This can be expressed mathematically as:

Number of ways to select 4 defective cogs = (4 choose 4) * (16 choose 0) = 1

The total number of ways to select 4 cogs from 20 can be found by selecting 4 cogs out of the 20 produced. This can be expressed mathematically as:

Total number of ways to select 4 cogs from 20 = (20 choose 4) = 4845

Therefore, the probability of selecting 4 defective cogs from the 20 produced is:

P(4 defective cogs) = (Number of ways to select 4 defective cogs) / (Total number of ways to select 4 cogs from 20) = 1/4845

Thus, the probability of selecting defective cogs is approximately 0.000206.

For more details regarding probability, visit:

https://brainly.com/question/30034780

#SPJ7

Answer:

No roots

Step-by-step explanation:

the discriminant Δ = 12²-4×(-10)×(-9) = -216

since ∆ is negative then the equation -10x^2 + 12x − 9 = 0 has no solution .

Answer:

The test statistic for the hypothesis test is -1.202.

Step-by-step explanation:

We are given that a report on the nightly news broadcast stated that 10 out of 129 households with pet dogs were burglarized and 23 out of 197 without pet dogs were burglarized.

Let [tex]p_1[/tex] = population proportion of households with pet dogs who were burglarized.

[tex]p_2[/tex] = population proportion of households without pet dogs who were burglarized.

SO, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1=p_2[/tex]     {means that both population proportions are equal}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1\neq p_2[/tex]     {means that both population proportions are not equal}

The test statistics that would be used here Two-sample z-test for proportions;

                           T.S. =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of households with pet dogs who were burglarized = [tex]\frac{10}{129}[/tex] = 0.08

[tex]\hat p_2[/tex] = sample proportion of households without pet dogs who were burglarized = [tex]\frac{23}{197}[/tex] = 0.12

[tex]n_1[/tex] = sample of households with pet dogs = 129

[tex]n_2[/tex] = sample of households without pet dogs = 197

So, the test statistics  =  [tex]\frac{(0.08-0.12)-(0)}{\sqrt{\frac{0.08(1-0.08)}{129}+\frac{0.12(1-0.12)}{197} } }[/tex] 

                                     =  -1.202

The value of z test statistics is -1.202.

Answer:

A whole number that can be made by multiplying other whole numbers.

Example: 18 can be made by 3 × 6 so is a composite number.

16 can be made by 4 x 4 so it is a square root and a composite number

14 can be made by 2 x 7 so is is a composite number.

It is not a prime number as all Composite Number have factors other than 1 and itself). The first few composite numbers (sometimes called "composites" for short) are 4, 6, 8, 9, 10, 12, 14, 15, 16,

Answer:

We need to examine the natural numbers.

The natural numbers are the counting numbers,

1, 2, 3, 4, 5, 6, ...

The number 1 is neither prime nor composite.

All natural numbers greater than 1 are either prime or composite.

A prime number is a number that has exactly two factors, itself and 1.

A composite number has more than 2 factors.

A composite number is a natural number greater than 2 that is not a prime number.

Examples:

Prime: 2, 3, 5, 7, 11, ...

Composite: 4, 6, 8, 9, 10, 12, ...

Answer:

A. or every 1 ton increase in precompression stress, the shear strength of the joint is estimated to increase by 0.987 tons.

Step-by-step explanation:

Hello!

The engineers created a regression model to estimate the relationship between the "shear strength of masonry joints" (Y), measured in tons, and the "precompression stress" (X), measured in tons.

^Y= a + bXi

Using the regression output:

Estimate of the y-intercept: a= 1.192

Estimate of the slope: b= 0.987

In general terms you can interpret the slope as:

"Is the modification of the estimated mean of Y when X increases one unit"

In this case it means that every time the precompression stress increases one ton, the shear strength of the joint is estimated to increase 0.987 tons.

I hope this helps!

Answer: [tex]\frac{21}{4}[/tex]

Step-by-step explanation:

Multiply each side by 2 to get rid of the fraction on the right side. That basically gets rid of the 1/2 and the 2.

Youre now stuck with 2x + y = 21. They gave us y which is 2x. 2x + 2x = 4x

You now have 4x = 21

Divide each side by 4 to get x = 21/4

Answer:

It is c he revived 10.21

Step-by-step explanation:

Answer:

P = 8000

t = 2

I = p × r × t

400 = 8000 × r/100 × 2

r = 400/160 per year

r = 40/16 = 2.5 %

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

This is a two tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 2.35

μ2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.8246

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.0746

Since alpha, 0.05 < than the p value, 0.0746, then we would fail to reject the null hypothesis.