Insulin is the hormone that controls glycogenolysis to lower plasma glucose levels. Insulin is the solution as a result.
By encouraging liver glycogenolysis, cortisol, glucagon, and epinephrine all raise plasma glucose levels. Only insulin, out of all the hormones mentioned, lowers plasma glucose levels via controlling glycogenolysis. The pancreas, an organ behind the stomach, produces the hormone insulin in its beta cells. By boosting the body's cells' ability to absorb glucose, it controls the quantity of glucose in the blood. As we eat, the food's carbs are broken down into glucose, which is then absorbed into the circulation. Insulin is then released by the pancreas in response, telling the cells to either take up glucose from the blood and utilise it as fuel immediately or store it for later use. Moreover, insulin is essential for controlling how proteins and lipids are metabolized.
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The above question is incomplete. The complete question is given below-
All of the following hormones increase or decrease plasma glucose concentration by regulating glycogenolysis (converting glycogen to glucose) EXCEPT?
Cortisol
Glucagon
Epinephrine
Insulin
1. Which of the following diseases is the first to be vaccinated against?
1. smallpox
2. pertussis
3. influenza
4. polio
The 5' end of mRNA serves as a binding site for __________, which allow translation to begin.
a.The promotor proteins
b.The ‘A’ site of the large ribosomal subunit
c.tRNA
d.Initiation factors
Each mRNA molecule being translated often undergoes numerous initiations. The 5′ end of the mRNA is threaded into a new ribosome as soon as the previous ribosome has translated enough of the nucleotide sequence to move out of the way. Hence, it allows the translation to begin.
A ribosome outside the nucleus decodes messenger RNA (mRNA) during translation to produce a specific polypeptide or amino acid chain. The polypeptide performs its unique functions inside the cell after folding into a functional protein. The ribosome facilitates decoding by promoting the binding of complementary tRNA anticodon sequences to mRNA codons. The tRNAs transport certain amino acids that are linked together to form a polypeptide as the mRNA passes through and is "read" by the ribosome.
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Plant and animal cells release energy stored in the bonds of glucose molecules when they perform
OA. meiosis.
OB. metamorphosis.
OC. photosynthesis.
OD. cellular respiration.
A section of DNA codes for the sequence of nitrogenous bases of mRNA to initiate
protein synthesis as shown.
GATACGCT
(DNA)
What is the process involved in the coding?
O replication
O transcription
O transduction
O translation
CUAUGCGA
(mRNA)
The process that involves coding is called transcription. The correct option is b.
What is transcription?The process of transcription creates RNA from DNA using the non-coding strand of the DNA as a template. The resulting RNA is a replica of the coding strand of the DNA.
Proteins called transcription factors to help turn particular genes "on" or "off" by attaching to surrounding DNA. The transcription of a gene is increased by transcription factors known as activators, while the transcription of genes is decreased by repressors.
Therefore, the correct option is B. transcription.
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Part A The evolution of cuticle presented land plants with a challenge that threatened their ability to live on land. What is this challenge, and why do stomata represent a solution? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help prevent(s) Cuticle allow(s) water loss from leaves and prevent(s) entry of CO2 required for allow(s) photosynthesis. Stomata allow(s) CO2 to diffuse and can close to allow(s) water loss. Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining You filled in 2 of 4 blanks incorrectly.
The evolution of cuticles presented land plants with the challenge of preventing water loss from leaves and preventing the entry of CO2 required for photosynthesis, while stomata allow CO2 to diffuse and can close to prevent water loss.
1. Cuticle prevents water loss from leaves and prevents entry of CO2 required for photosynthesis.
2. Stomata allow CO2 to diffuse and can close to prevent water loss.
The waxy cuticle on the surface of leaves helps prevent water loss, but it also creates a barrier that prevents gases from entering and leaving the plant. This presents a problem for photosynthesis, which requires the uptake of carbon dioxide (CO2) and the release of oxygen (O2).
Stomata, have tiny pores on the leaf surface, allowing CO2 to diffuse into the leaf and O2 to diffuse out. Additionally, they can close to prevent excessive water loss through transpiration. The evolution of stomata allowed plants to thrive on land by overcoming the challenge of gas exchange while minimizing water loss.
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Complete Question:
The evolution of cuticles presented land plants with a challenge that threatened their ability to live on land. What is this challenge, and why do stomata represent a solution?
1. Cuticle ___ water loss from leaves and ___ entry of CO2 required for photosynthesis.
2. Stomata ____ CO2 to diffuse and can close to ______ water loss.
Fill the blanks with allow or prevent appropriately.
carbon cycle are they always parts of the same compound?
No, the carbon cycle involves the movement of carbon in different forms and compounds, including both organic and inorganic compounds.
What happens in a carbon cycle?
In the carbon cycle, carbon moves between the atmosphere, the oceans, the land, and living organisms. Carbon can be present in different forms, such as carbon dioxide (CO2) in the atmosphere, dissolved inorganic carbon (DIC) in the oceans, and organic carbon in living organisms and in dead organic matter in soils and sediments.
Carbon also exists in various organic compounds, such as carbohydrates, proteins, and lipids, which make up the living tissues of organisms. As organisms respire, they release carbon dioxide back into the atmosphere or into the water, and when they die, their remains decompose, releasing carbon into the soil or water.
In short, the carbon cycle involves the movement of carbon in various forms and compounds, and it is not limited to a single compound or form.
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Helpp!! Brainlesst take and help!
Explain the process of photosynthesis and its importance to life on Earth.
What is the most common antibiotic-resistant bacteria?
MRSA (Methicillin-resistant Staphylococcus aureus) is the most common antibiotic-resistant bacteria.
More about MRSA:
MRSA is usually spread through a wound, or when someone shares an infected object that has come in contact with an infected person, with a person who is not infected.
MRSA is also a mutation of staph.
Image found at: https://kidshealth.org/en/teens/mrsa.html
I apologize if I was wrong. I hope you have a lovely day! :)
Answer:
MRSA
Explanation:
The most common antibiotic-resistant bacteria is methicillin-resistant Staphylococcus aureus (MRSA). MRSA is a type of staph infection that is resistant to many commonly used antibiotics, including methicillin and other beta-lactam antibiotics. This makes MRSA infections difficult to treat and can increase the risk of serious health problems, such as sepsis and pneumonia. MRSA is most commonly found in healthcare settings, such as hospitals and nursing homes, but it can also occur in communities. It is important to practice good hygiene, such as washing your hands frequently and covering your nose and mouth when you cough or sneeze, to help reduce the spread of MRSA and other antibiotic-resistant bacteria.
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Allen
Think and discuss: What can a scientist do to improve the accuracy of their cladograms?
Cladograms are diagrams used in biology to show the evolutionary relationships between different species or groups of organisms, and some ways that a scientist can improve the accuracy of their cladograms are by using multiple sources of data, choosing appropriate outgroup species, using statistical methods, considering convergent evolution, etc.
To construct an accurate cladogram, it is important to use multiple sources of data, such as physical traits, DNA sequences, and fossil records. An outgroup species is a species that is closely related to the group being studied but not a part of it. By choosing an appropriate outgroup species, scientists can better identify shared characteristics that are unique to the group being studied and therefore construct a more accurate cladogram.
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Which middle eastern plateau is surrounded by mountains and contains two uninhabitable deserts?a. Saudi arabia's central plateaub. Iran's interior plateauc. The anatolian plateaud. The gaza strip please select the best answer from the choices provided. Abcd.
The Middle Eastern plateau that is ringed by mountains and has two inhospitable deserts is known as Iran's Interior Plateau, thus the correct choice is B.
Numerous plateaus are formed as magma from deep within the Earth pushes towards the surface but is unable to break through the crust. Instead, the magma raises the enormous, flat, impervious rock above it. Geologists believe that a magma cushion may have provided the Colorado Plateau with its last lift beginning around ten million years ago. The Iranian plateau is bordered to the west by the Zagros Mountains, to the north by the Caspian Sea, to the south by the Persian Gulf, and to the east by the Indo-Gangetic Plains.
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The complete question is:
Which Middle Eastern plateau is surrounded by mountains and contains two uninhabitable deserts?
A. Saudi Arabia's Central Plateau
B. Iran's Interior Plateau
C. The Anatolian Plateau
D. The Gaza Strip
Answer:B.
Iran's Interior Plateau
took the test. B is correct
Explanation:correct on edg
The diagram of the human spine shows the locations of cartilaginous discs and vertebrae.
A. Identify one function of the cartilaginous discs in a healthy human spine.
B. Identify one function of the vertebrae besides protecting the spinal cord.
A herniated discs is a serious injury because it often presses on the spinal cord.
C. Describe the main function of the spinal cord.
D. Identify one likely symptom caused by herniated discs and explain why the herniated dics causes the symptoms you identified.
Between the vertebral endplate and the nucleus pulposus (NP), the cartilaginous endplate (CEP), a thin layer of hyaline cartilage, serves as both a mechanical barrier and a passageway for nutrient delivery into the disc.
What is Cartilaginous plate?Despite being crucial to disc nourishment and degeneration, the CEP's morphology has not been thoroughly studied.
The goal of this work was to use an MRI FLASH (rapid low-angle shot) pulse sequence to measure CEP thickness and visualize and describe observations of the CEP's three-dimensional shape.
The biggest avascular tissue in the body, the intervertebral disc experiences the most severe aging and degeneration of any tissue and is linked to low back pain.
Therefore, Between the vertebral endplate and the nucleus pulposus (NP), the cartilaginous endplate (CEP), a thin layer of hyaline cartilage, serves as both a mechanical barrier and a passageway for nutrient delivery into the disc.
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What are examples of diseases/disorders that are transmitted through mitochondrial inheritance?
Diseases/disorders that are transmitted through mitochondrial inheritance include Leigh syndrome, Pearson syndome, MELAS, etc.
What are mitochondrial inheritances?Mitochondrial inheritance refers to the transmission of genetic material exclusively from the mother's mitochondria to her offspring. Some examples of diseases or disorders that are caused by mutations in mitochondrial DNA and are therefore transmitted through maternal inheritance include:
Leber's hereditary optic neuropathy (LHON)Mitochondrial encephalomyopathy, lactic acidosis, and stroke-like episodes (MELAS)Myoclonus epilepsy with ragged-red fibers (MERRF)Kearns-Sayre syndrome (KSS)Leigh syndromeNARP syndrome (neuropathy, ataxia, and retinitis pigmentosa)Pearson syndrome (pancytopenia and exocrine pancreatic insufficiency).Overall, mitochondrial inheritance is relatively rare and is only responsible for a small fraction of inherited genetic diseases.
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A student runs an experiment to figure out if the size of a wire changes how well i
the resistance in the wires.
s electricity. She uses 5 different widths of copper wire and attaches each to a multimeter to measure the resistance in the wires. The data collected is shown below:
Wire 1- 12 Ohms
Wire 2- 17 Ohms
Wire 3- 9 Ohms
Wire 4- 14 Ohms
Wire 5- 6 Ohms
What is the independent variable in this experiment?
A The multimetet.
B. The resistance values.
C. The material of the wires, copper.
D. The widths of the wires.
The widths of the wires was the independent variable in the experiment.
define resistance ?Resistance is a measure of the degree to which an object opposes the flow of electric current through it. It is the ratio of the voltage applied to a conductor or circuit to the resulting current that flows through it, and is typically measured in units of ohms (Ω). The higher the resistance of a material, the more difficult it is for electric current to flow through it. Factors that can affect resistance include the material of the conductor, its temperature, and its dimensions.
Resistance is an important concept in understanding and designing electrical circuits, as it can impact the overall performance and efficiency of a system. The widths of the wires was the independent variable in the experiment.
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Male patterned baldness is a sex-linked recessive disorder that
causes people to lose their hair at a younger age. It occurs more
often in males than females. A father who is not bald and a mother
who is a carrier for this trait have offspring. Select all of the
possible genotypes for their kids.
Choose all that apply:
X B x b
X b X b
X B Y
YY
The possible genotypes of the offspring are given below: XY, XXb, XY, XXb
What are sex-linked recessive disorders?Genetic disorders connected to mutations in genes on the X chromosome are referred to as having X-linked or sex-linked recessive inheritance. Because he contains just one X chromosome, a male who carries this mutation will be affected. A female who carries a gene mutation in one X chromosome but has a normal gene on the other X chromosome usually has no symptoms.
The possible genotypes of the offspring of a father who is not bald and a mother who is a carrier for this trait is given below:
XY x XXb ---> XY, XXb, XY, XXb
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QUESTION: Can you hypothesize different uses
for sedimentary rock in our society?
Answer:
please like
Explanation:
Our main energy sources, coal, natural gas, oil, and uranium, are created in and come from sedimentary rocks. Sediment provides sand and gravel for construction. Stone used in construction includes sandstone and limestone. Plaster is produced using rock gypsum.
A solution of potassium chlorate, KClO3, has 10 grams of the salt dissolved in 100 grams of water at 40 ºC. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?
An additional 26 grams of potassium chlorate could be added before reaching the saturation point.
How did we get this assertion?The solubility of potassium chlorate in water at 40 ºC can be found using reference tables. According to those tables, the solubility of potassium chlorate in water at 40 ºC is approximately 36 grams per 100 grams of water.
Since the solution already contains 10 grams of potassium chlorate, this means that an additional 26 grams of potassium chlorate could be added before reaching the saturation point.
It's important to note that the solubility of a salt in water can be affected by various factors, including temperature, pressure, and the presence of other ions in solution, so these values should be taken as approximate.
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13. Linus Pauling proposed a DNA structure in which the prophase groups were tightly packed on the molecule's inside, leaving the nitrogenous bases sticking outward.
a) Which scientist's findings did Linus Pauling need to propose the correct 3D-structure DNA?
b) If DNA replication occurred in this structure, how would it differ from what you know is the actual process? Explain your reasoning
14. While working with a particular strain of E. coli, you discover that it transcribes the lac genes at a high level when no lactose is present in the cell's medium.
a) Explain how the lac operon functions typically.
b) List the possible causes of this abnormal activity.
c) Then design an experiment to determine which of these possible causes is the case with your bacterial colony.
The lac operon follows a negative, inducible mode of regulation. This means that the transcription of the operon is turned OFF in the absence of lactose and is only induced into activity when lactose is present in the medium.
What is lac operon?
a) If the genotype of the lac operon is normal, i.e. it does not contain any mutations, then,If lactose is present in the medium:-When lactose is present in the medium, it is translocated into the cell because the operon always produces a small amount of permease. The allolactose molecule binds to the repressor molecule and inactivates it.An inactivated repressor can no longer bind to the operator and as a result all genes are transcribed, i.e. the operon is turned on.Also, the absence of glucose leads to the production of large amounts of cAMP in the cell, which binds to the CAP protein. This complex then binds to the CAP site and increases the rate of transcription of the operon.If lactose is not present in the medium:-In the absence of lactose, the repressor remains active and binds to the operator. This prevents RNA polymerase from binding to the promoter and the operon is not transcribed, i.e. the operon is turned off.When both lactose and glucose are present:-Glucose will be used first because it is the preferred energy source and during this time there will be minimal transcription of the lac operon.b) If the lac operon is expressed at high levels even in the absence of lactose, it means that it shows constitutive expression, i.e. it is expressed regardless of the availability of lactose in the medium.This can be possible for two reasons:-1) A mutated lacI gene (lacI-) that produces an inactive or mutant repressorIn this case, the mutation alters or alters the promoter region of the lac1 gene, since this gene has a promoter separate from that of the structural genes. This means that if the promoter of that gene is altered so that it can no longer bind to the RNA polymerase enzyme, that gene will not be transcribed or expressed. As a result, the repressor protein will not be produced and the operon will therefore be constitutively active.2) Mutation operator, i.e. operator Oc In this mutation, the repressor binding site on the operator is mutated in such a way that it cannot bind to the repressor protein even in the absence of lactose. If the repressor cannot bind to the operator, then the operon will be expressed regardless of the presence or absence of lactose.C)In the case of a mutant lacI gene, we know that the promoter of this gene will be changed so that it can no longer bind to the RNA polymerase enzyme and the gene will not be transcribed. that is, this gene will not produce any mRNA or repressor protein in the absence of lactose, whereas the normal operon does,In the case of a constitutive operator, the operator will not be able to bind the repressor even in the absence of lactose. Thus, even if lactose is not available in the medium, there will be a higher concentration of free repressor protein in the cytoplasm of the cell.This means that in the case of the lacI- mutant there will be no repressor protein, while in the case of the Oc mutant there will be a high concentration of the repressor protein in the cell cytoplasm.Thus, this difference in the presence of the repressor protein can be used to distinguish between a cell with a normal and a lacI-mutated operon by Western Blot analysis.This is because this technique tests for the presence of specific proteins present in the cell sample using complementary antibodies that specifically bind to the target protein and are conjugated to a marker enzyme that stains the chromogenic substrate blue.To know more about lac operon, click the link given below:
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Put the following in order from smallest to largest:
Giardia lamblia protozoa (7µm)
Bacterial Plasmids (20nm)
Mastadenovirus (30nm)
Cionorchis sinensis trematode (5mm)
Gram-pos bacteria (6µm)
All together from littlest to biggest: Bacterial Plasmids (20nm)<Mastadenovirus (30nm) < Gram-pos microscopic organisms (6µm) < Giardia lamblia protozoa (7µm) < Cionorchis sinensis trematode (5mm)
Anything more modest than 200 nm can't communicate with noticeable light. Losing on the stage is excessively simple. Noticeable light is just great at frequencies under 390 nm.
Objective Focal point or Mathematical Opening This piece of a compound magnifying instrument is the focal point nearest to the example.
The level stage is where you place your slides. Stage cuts hold the slides set up. Spinning Nosepiece or Turret: This is the part that holds at least two objective focal points and can be pivoted to change power without any problem.
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As light travels through the eye, it passes through several structures/chambers before reaching the retina. Which list below gives those structures in the correct order?
Option D, The correct order of structures/chambers that light passes through as it travels through the eye is: cornea, lens, iris, aqueous humor, vitreous humor
The clear, dome-shaped tissue covering the front of the eye that helps to focus light. Aqueous humor the clear, watery fluid that fills the space between the cornea and the lens. Pupil the opening in the center of the iris that controls the amount of light entering the eye. Lens the transparent structure behind the iris that changes shape to focus light on the retina. Vitreous humor the gel-like substance that fills the space between the lens and the retina. Retina the light-sensitive tissue lining the back of the eye that contains the cells responsible for vision. Therefore, the correct order of the structures/chambers that light passes through as it travels through the eye is: cornea, lens, iris, aqueous humor, vitreous humor.
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The complete Question is:
As light travels through the eye, it passes through several structures/chambers before reaching the retina. Which list below gives those structures in the correct order?
a) cornea, iris, lens, vitreous humor, aqueous humor
b) iris, cornea, lens, aqueous humor, vitreous humor
c) lens, cornea, iris, aqueous humor, vitreous humor
d) cornea, lens, iris, aqueous humor, vitreous humor
Explain the 4 types of human blood type. What is present in each
Answer:
Explanation:There are 4 main blood groups defined by the ABO system:
blood group A – has A antigens on the red blood cells with anti-B antibodies in the plasma
blood group B – has B antigens with anti-A antibodies in the plasma
blood group O – has no antigens, but both anti-A and anti-B antibodies in the plasma
blood group AB – has both A and B antigens, but no antibodies
Question 13 (1 point)
What would be the pressure if a Jack Hammer exerts 30,000 N of force on the stree
asphalt to break open a 0.500 m^2 area hole in the street below?
29,9995 Pa
15,000 Pa
60,000 Pa
30,000.5 Pa
The Jack Hammer applies 60,000 Pa of pressure on the pavement. The right response is C.
What exactly is pressure and what does its SI unit mean?The thrust (perpendicular force on a surface) acting per unit area of a body is referred to as pressure. Mathematically, it can be expressed as follows: The SI unit of pressure is the Pascal (Pa). One Newton of force exerts one Pascal of pressure on a square inch of ground.
The following formula can be used to determine the pressure:
pressure = force/area
Substituting the given values:
pressure = 30,000 N / 0.500 m²
= 60,000 Pa
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Which lipid is responsible for stabilizing a plasma membrane?
Cholesterol
Triglyceride
Phospholipid
Saturated fatty acid
Answer: phospholipid Bilayer
Explanation:
When does the egg begin the 2nd round of meiosis?
A) when the egg was first made
B) before it is released from the ovary
C) after a sperm enters the egg cell
Answer: After ovulation the oocyte is arrested in metaphase of meiosis II until fertilization. At fertilization, the secondary oocyte completes meiosis II to form a mature oocyte (23,1N) and a second polar body.
Explanation:
mutate a yeast so that its tRNA for methionine no longer works. All of the yeast's proteins will now:
A Be missing all methionine
B No longer be made as methionine is the first amino acid in all proteins
C All proteins will have methionine replaced with cysteine, which is "close enough"
Write 5 sentences OR a list of numbered steps to explain the process of DNA replication. You’ll also complete sketch notes to supplement your written understanding.
Your writing must incorporate the following components
Direction DNA is synthesized
Description of how DNA replication is considered semiconservative
Role and location of helicase
Role and location of topoisomerase
Role and location of RNA primers
Role and location of DNA polymerase
Distinguishing between leading/lagging strand and identifying which strand replicates continuously and which replicated discontinuously
Okazaki fragments
Role and location of ligase
This results in the formation of small fragments known as Okazaki fragments. The role of the ligase is to seal the gaps between the Okazaki fragments and join them to form a continuous strand.
Here are the five sentences to explain the process of DNA replication:The process of DNA replication involves the synthesis of new DNA strands by copying the existing DNA strands.This process is considered semi-conservative since each daughter DNA molecule is composed of one parent strand and one newly synthesized strand.
During DNA replication, the enzyme helicase is responsible for unwinding the double helix by breaking hydrogen bonds between the base pairs.The enzyme topoisomerase relieves the tension that arises ahead of the replication fork.
DNA polymerase is the enzyme responsible for adding nucleotides to the growing DNA strand. It can only add nucleotides to the 3’ end of the strand.There are two strands in DNA:
the leading strand and the lagging strand. The leading strand replicates continuously, while the lagging strand replicates discontinuously. The RNA primers are located on the lagging strand and are responsible for providing a free 3’ OH group for DNA polymerase to add nucleotides.
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soon, life insurance companies, health insurance companies,employers, and the government will have the tools to predict our future health. Is this too much information for them to have? is there any way to stop it
Life insurance companies, health insurance companies,employers, and the government will have the tools to predict our future health which is too much information for them to have.
What is Insurance?
This is referred to as a means of protection by which a company or the state undertakes to provide a guarantee of compensation for specified loss, damage, illness, or death in return for payment of a specified premium.
Insurance companies, health insurance companies,employers, etc having the tools to predict our future health which is too much information for them to have because it is meant to be confidential and it ca be stopped by amendment of laws.
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Helppppp it’s due today
Stablizing selection is represented in graph A, and distructive selection is represented in graph B. Thus, option B is correct.
What will be the equation?
Given inequality is,
x + 2y ≤ 47
This inequality has a sign of less than equal to ( ≤ ). Properties of this inequality when graphed will be sign of equal to in the given inequality shows that the graph of the line will be a solid line.
Sign of less than represents the shaded region below the line.The graph lying in first quadrant and graph of horizontal line lying in the fourth quadrant are representing functions.
Thus, Stablizing selection is represented in graph A, and distructive selection is represented in graph B. Thus, option B is correct.
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3. In Jimsonwed, purple flower (P) is dominant to.white (p), and spiny pods
(S) are dominant to smooth(s). In a cross between a Jimsonweed
homozygous for white flowers and spiny pods and one homozygous for
purple flowers and smooth pods, what are all possible phenotypes and
genotypes of the offspring?
The possible offspring are:
PP, Ss - This offspring would have purple flowers and spiny pods. Its genotype would be heterozygous for both traits.
Pp, Ss - This offspring would also have purple flowers and spiny pods, but it would be heterozygous for only the flower color trait.
Pp, ss - This offspring would have purple flowers and smooth pods. Its genotype would be heterozygous for only the pod trait.
pp, ss - This offspring would have white flowers and smooth pods. Its genotype would be homozygous for both traits.
What is a Jimsonweed?Jimson weed (Datura stramonium) is a plant species in the nightshade family (Solanaceae). It is also commonly known as thorn apple, devil's trumpet, and locoweed.
The possible phenotypes are purple flowers with spiny pods, purple flowers with smooth pods, white flowers with spiny pods, and white flowers with smooth pods. The possible genotypes are heterozygous for both traits, heterozygous for only the flower color trait, heterozygous for only the pod trait, and homozygous for both traits.
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A disease kills the mice. Explain how the maize harvest will be affected.
maize ->mice->snakes->
Answer:
Two hshshehdhehwjwkwkwooeidudd
Atoms that have the same number of protons
and electrons are electrically neutral because
_____.
A. their electrons are not found in the nucleus
B. they have neutrons that cancel both positive and negative
charges
C. the positive charges on the protons and the negative charges
on the electrons cancel each other out
D. their electrons have much less mass than their protons
Atoms that have the same number of protons and electrons are electrically neutral because the positive charges on the protons and the negative charges on the electrons cancel each other out. Therefore, the correct option is C.
What are atoms?An atom is the basic unit of matter and the defining structure of elements. They are composed of a nucleus, which is made up of protons and neutrons. The electrons, orbit the nucleus in shells.
The electrons in an atom are negatively charged, while the protons are positively charged. If the number of protons are equal to the number of electron in an atom, the atom is considered to be electrically neutral. Therefore, the correct option is C.
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