An analytical chemist measures the amount of Elements and in four samples of an unknown Substance :

Answer:

It's about 13 mL, read it where the lowest point is,

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day :)

Answer:

About 12.7mL

Explanation:

You always have to count the dip portion of the liquid. It's okay if the number is an estimate. There won't be an exact answer. My chemistry teacher says to not round the answer. Hope this helps!

Answer:

k=0.0224 M/s

Explanation:

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The rate constant of the reaction is 0.0224 m/s. the rate constant is denoted by symbol k. The velocity and direction of a chemical reaction are quantified in chemical kinetics by the reaction rate constant, or reaction rate coefficient, k.

The proportionality constant in the equation that defines the link between the rate of a chemical reaction and the concentrations of the reacting chemicals is known as the rate constant, also known as the specific rate constant.

The rate constant provides insight into the variables that affect a reaction's rate. The dependence of the molar concentration of the reactants on the rate of reaction may be determined by knowing the rate constant.

The rate constant provides insight into the variables that affect a reaction's rate. The dependence of the molar concentration of the reactants on the rate of reaction may be determined by knowing the rate constant.

Thus, option 2 is correct.

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It takes a total of 56 days for the mass of the  chromium-51 to be reduced from  12.0 μg to 3.00 μg.

The half life of a radioactive sample refers to the time taken for only half of the radioactive substance that is originally present to decay. Now we know that radioactivity has to do with the spontaneous disintegration of a substance. This implies that the amount of the substance would continue to decreases as the time goes on.

Having said this, let us consider the question as we have it above. We all know that; the half-life of radioactive chromium-51 is 28 days then the sample of chromium-51 has a mass of 12.0 μg. We are to now obtain the number of days it will take for the mass to be reduced to 3.00 μg .

Hence;

t1/2 =  28 days

N = 3.00 μg

No =  12.0 μg

t = ?

Using;

N/No = (1/2)^t/t1/2

3/12 =  (1/2)^t/28

1/4 =  (1/2)^t/28

(1/2)^2 =   (1/2)^t/28

2 = t/28

t = 56 days

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The final temperature of an 18.0 g aluminum sample if it is initially at 22.0 C and it absorbs 48.0 calories of heat energy is 34.7°C.

The temperature of a substance can be calculated using the following formula:

Q = mc∆T

Where;

According to this question, an 18.0 g aluminum sample is initially at 22.0 C and it absorbs 48.0 calories of heat energy. The final temperature can be calculated as follows:

48 = 18 × 0.210 × {X - 22}

48 = 3.78x - 83.16

3.78x = 131.16

X = 34.7°C

Therefore, the final temperature of an 18.0 g aluminum sample if it is initially at 22.0 C and it absorbs 48.0 calories of heat energy is 34.7°C.

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Answer: 4

Explanation: There are 4 sig figs because 6 and 4 are always considered significant. And a 0 is considered a sig fig if it's between two numbers besides 0 or if it's after a decimal point.

If the concentration inside the cell is 5% and the concentration outside the cell is 6%, this solution will be hypertonic.

If the concentration inside the cell is 3% and the concentration outside the cell is 1%, this solution will be hypotonic.

Hypertonic solution is a solution that contains more dissolved particles (such as salt and other electrolytes) than is found in normal cells and blood.

A solution will be hypertonic to a cell if the outside concentration is higher than that inside the cell, and the solutes cannot cross the membrane.

Hypotonic solution is a solution that contains fewer dissolved particles (such as salt and other electrolytes) than is found in normal cells and blood.

A solution will be hypotonic to a cell if the outside concentration is lower than that inside the cell, and the solutes can cross the membrane.

Thus, if the concentration inside the cell is 5% and the concentration outside the cell is 6%, this solution will be hypertonic.

if the concentration inside the cell is 3% and the concentration outside the cell is 1%, this solution will be hypotonic.

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Answer: I believe its ice melting

Explanation: it would be ice melting because it can turn back into ice by itself with out any human doing anything to it.

Answer:

2AlCl3(aq) + 3Na2S(aq) = Al2S3(aq) + 6NaCl(aq)

Explanation:

First, you have to write down a complete equation as shown below:

AlCl3 + Na2S → Al2S3 + NaCl.

When you at the above equation is not balanced.

To balance the equation, we have to identify the number of products and reactants.

Al: 1a + 0b = 2c + 0d, we have 2 Al

Cl: 3a + 0b = 0c + 1d, we have 3Cl

Na: 0a + 2b = 0c + 1d, we have 2Na

S: 0a + 1b = 3c + 0d, we have 3S

Then we simplify to obtain the lowest whole integer value:

a = 2 (AlCl3)

b = 3 (Na2S)

c = 1 (Al2S3)

d = 6 (NaCl)

Substitute the values to our first equation giving us,

2AlCl3 + 3Na2S = Al2S3 + 6NaCl,

We then include the states. Since the reaction is in aqueous solution, we insert (aq)

2AlCl3(aq) + 3Na2S(aq) = Al2S3(aq) + 6NaCl(aq)

Since there is an equal number of each element in the reactants and products of 2AlCl3(aq) + 3Na2S(aq) = Al2S3(aq) + 6NaCl(aq), the equation is balanced.

Thus our required equation is

2AlCl3(aq) + 3Na2S(aq) = Al2S3(aq) + 6NaCl(aq)

Answer:

Which statement describes a step in the formation of an ionic bond? An attraction occurs between two ions that have the same charge.

Explanation:

The number of atoms of hydrogen present in 1.255 g of aluminum hydroxide, Al(OH)₃ is 2.89×10²² atoms

Mole = mass / molar mass

Mole of Al(OH)₃ = 1.255 / 78

Mole of Al(OH)₃ = 0.016 mole

1 mole of Al(OH)₃ contains 3 moles of H.

Therefore,

0.016 mole of Al(OH)₃ will contain = 0.016 × 3 = 0.048 mole of H

From Avogadro's hypothesis

1 mole of hydrogen = 6.02×10²³ atoms

Therefore,

0.048 mole of hydrogen = (0.048 mole × 6.02×10²³ atoms) / 1 mole

0.048 mole of hydrogen = 2.89×10²² atoms

Thus, we can conclude that 2.89×10²² atoms of hydrogen are present in 1.255 g of Al(OH)₃

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Answer:

3.01 x 10²⁴ atoms Mn

Explanation:

To find the number of manganese (Mn) atoms, you need multiply the given mole value by Avogadro's Number. Avogadro's number is a ratio which represents the number of atoms per every 1 mole. It is important to arrange the ratio in a way that allows for the cancellation of units (moles should be in the denominator to cancel the units of the given value). The final answer should have 3 sig figs like the given value (5.00 = 3 sig figs).

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

5.00 moles Mn           6.022 x 10²³ atoms
-------------------------  x  --------------------------------  = 3.01 x 10²⁴ atoms Mn
                                              1 mole

Answer:

A. Add 40 and 44

Explanation:

mass number = protons + neutrons

protons = electrons

so mass number = 40 + 44

The  temperature in the flask in kelvin is 577.3 K.

The relationship between volume, temperature, moles and pressure of a gas is given by the ideal gas equation written below:

where;

For the gas:

P = 120 kPa

n = 0.25 moles

V = 10 dm³

R = R = 8.314 dm³.kPa/mol.K

T = ?

T = PV/nR

T = 120 * 10/8.314 * 0.25

T = 577.3 K

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Answer:

Neutralization refers to aa chemical reaction where an acid and a base react with each other quantitatively.

Example:

Hydrochloric acid + Sodium hydroxide → Sodium chloride + Water ( word equation)

Explanation:

Though we haven't been asked to write down chemical equation, it is good to know.

Here is the equation:

HCl(aq) + NaOH(aq) → NaCl (aq)+ H2O (l)

The amount of heat (in J) required for the temperature change is 26752 J.

The amount of heat required to raise the temperature of water from 25°C to 89°C is calculated as follows:

Mass of water = volume * density

density of water = 1 g/mL

volume of water = 100 mL

mass of water = 100 mL * 1 g/mL

mass of water = 100 g

heat capacity of water = 4.18 J/g°C

Temperature change = 89 - 25 = 64 °C

Heat required = 100 * 4.18 * 64

Heat required = 26752 J

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1)The limiting factor in this lab simulation are biotic is Predator and Food.

2)The limiting factor in the lab simulation are abiotic is Pollution.

3)The limiting factor impacted the cricket frog population the most is Predator.

4)The limiting factor impacted the cricket frog population least is pollution.

1)The predator and Food are the biotic  limiting factor in this simulation because predator can eat the population of cricket frog and will reduce the population of cricket frog. animals eaten by food is biotic.

2)  Pollution in the lab simulation is abiotic factor because it is non living things.  

3) The limiting factor impacted the cricket frog population most is predator because for the predator , the cricket frog were the good source of food.

4) Pollution is the limiting factor which affect the cricket frog population because their growth was not much affected by pollution.

5) The cricket frog plays an important role in limiting the spread of mosquito - borne illness like west Nile virus and Malaria because cricket frog consumes mosquitoes and decrease the population of contaminated mosquitoes.

6)  The long term effects of these limiting factors on the cricket frog population in the pond eco system is that if the predators increases the population of cricket frog decreases and if the food sources decreases (mosquitoes) then cricket frog die and population decreases and vice - versa.

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Alpha decay of Plutonium-238 into Uranium-234. Therefore, A = 234, Z = 92, X = U

A radioactive process known as "alpha decay" releases a particle made up of two protons and two neutrons when an unstable nucleus transforms to another element. The helium nucleus that is being expelled is known as an alpha particle. Positive charge and a substantial mass characterize alpha particles.

An atomic nucleus emits an alpha particle (the helium nucleus), which causes it to change or "decay" into another atomic nucleus with a mass number that is decreased by four and the atomic number is reduced by two. This process is known as alpha decay or α-decay.

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Answer:

866.142 inches

Explanation:

By formula

The specific heat capacity of the metal rod weighing 123g is 0.14 J/gºC (option B).

The specific heat capacity of a metal substance can be calculated using the following formula:

Q = mc∆T

Where;

However, in a calorimeter, the metal and water relationship is given as follows:

Q (water) = - Q (metal)

mc∆T (water) = - mc∆T (metal)

Mass of water = density × volume

Mass of water = 1g/mL × 75mL = 75g

75 × 4.184 × {29°C - 25°C} = - {123 × c × (29 - 100)}

1255.2 = 8733c

c = 1255.2/8733

c = 0.144J/g°C

Therefore, the specific heat capacity of the metal rod weighing 123g is 0.14 J/gºC.

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If 0.459 g of an unknown sugar is dissolved in 100.0 mL of water its osmotic pressure is found to be 0.0824 atm. The molar mass of the sugar (in g/mol) is  \M = 3.0067.

"Molar mass of many compounds can be calculated by dividing the mass of the compound by the number of moles of the compound."

Given, that the mass of unknown sugar= 0.459 g

Volume of water =  100.0 mL

Osmotic pressure to be 0.0824 atm

The temperature of the solution = 298 K

Calculating the moles

PV = nRt

R =  8.314, constant

0.0824 X 100.0 = n x 8.314 x  298

8.24 = n x 2477.57

n = 300.67

Now, calculating the molar mass

Molar mass = n  / V

300.67 /  100.0

M = 3.0067

Thus, the molar mass of the sugar is 3.0067

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Answer:

0.0996 M (3 s.f.)

Explanation:

Molarity is the number of moles per litre.

Let's find the number of moles of sucrose.

[tex]\boxed{\text{Moles= Mass}\div\text{Mr}}[/tex] , where Mr is the molecular weight of the compound.

[tex]\text{Mr of C}_{12}\text{H}_{22}\text{O}_{11}[/tex]

= 12(12)+22(1)+11(16)

= 342

Moles of sucrose

= 143 ÷342

= 0.41813 mol (3 s.f.)

This means that in 4.20L of solution, we have approximately 0.41813 moles of sucrose. We can now calculate the amount of sucrose in 1L of solution.

Molarity

= 0.41813 ÷4.2

= 0.099555 mol/L (5 s.f.)

= 0.0996 M (3 s.f.)

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Set 1 is difficult.

The formula for thermal energy is given as:

Q = mcΔT

Where m is the mass of the item, c is specific heat capacity and ΔT is the change in temperature when the item is heated.

For Set 1:

5 g of iron at 45°C and 10 g of iron at 45 °C

In this case, the mass of iron is different at the same temperature. Since there is no change in temperature hence the metal is not heated. Another reason is that the mass of iron is different in this case. Hence, this set will be difficult to find thermal energy.

Set 2:

10 g of water at 30°C and 10 g of water at 50° C

The mass of water at both temperatures is the same, and the water is heated from 30°C to 50° C The thermal energy can be easily calculated using the formula Q = mcΔT.

Set 3:

2 g of copper at 50°C and 32 g of nickel at 50°C ​

The mass of copper remains unchanged, also the temperature doesn't change. Since copper is not heated and the temperature remains constant. Hence the thermal energy will be zero.

Therefore, Set 1 will be the most difficult to find the thermal energy.

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Since it contains a phenol group, acetaminophen will give a positive phenol test when ferric chloride is added. Salicylic acid remains unreacted and causes a color change when it reacts with ferric chloride.

Phenol is primarily used in the manufacture of phenolic resins as well as nylon and other synthetic fibers.

It is also used as a disinfectant and antiseptic, as well as in medicinal preparations such as mouthwash and sore throat lozenges.

Acetaminophen will give a positive phenol test when ferric chloride is added because it contains a phenol group. When salicylic acid reacts with ferric chloride, it remains unreacted and causes a color change.

Thus, it can be concluded that yes, positive phenol test can be taken in case of acetaminophen.

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Taking into account the reaction stoichiometry, 120.615 kg of HNO₃ are consumed to produce 112 kg Ca(H₂PO₄)₂.

In first place, the balanced reaction is:

Ca₃(H₂PO₄)₂ + 4 HNO₃  → Ca(H₂PO₄)₂ + 2 Ca(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction (being 1000 g= 1 kg):

The following rule of three can be applied: If by reaction stoichiometry 0.234 kg of Ca(H₂PO₄)₂ is produced from 0.252 kg of HNO₃, 112 kg of Ca(H₂PO₄)₂ is produced from how much mass of HNO₃?

mass of HNO₃= (112 kg of Ca(H₂PO₄)₂× 0.252 kg of HNO₃)÷ 0.234 kg of Ca(H₂PO₄)₂

mass of HNO₃= 120.615 kg

Finally, 120.615 kg of HNO₃ are consumed to produce 112 kg Ca(H₂PO₄)₂.

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Answer:

2-1

Explanation:

=1