Answer:
Energy = mcΔt
where m the mass , c specific heat capacity
Δt is the change in temperature
1200x10^3=75x4184xΔt
Δt=3.82°
Explanation:
During a phase change,the temperature remains constant although heat is still being added. what is the best explanation for what the heat energy is being used to do
During the phase change in which heat is being added but the temperature remains constant, the heat energy is used to break the bonds in the molecules.
What is a phase change?A phase change is the conversion of one state of matter to another. e.g. solid to liquid or liquid to gas.
Substances can exists in three states namely;
solidgaseousliquidIn a change of phase, heat energy is needed to break the existing bonds between the molecules of the initial state. For example, heat energy is needed to break the bonds of ice to form water.
However, during this phase change, the temperature remains constant.
Therefore, during the phase change in which heat is being added but the temperature remains constant, the heat energy is used to break the bonds in the molecules.
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What is the average acceleration of a me
that reaches 24 m/s in 5.5 seconds?
F 0.20 m/s2
G 2.5 m/s
H 10 m/s2
J 208 m/s
Answer:
See below
Explanation:
Assuming starting from zero velocity
vfinal = at
24 = a (5.5)
a = 4.36 m/s^2 I think part of your question is missing....what was the initial velocity?
Q19. Convert 2.05 x 10^5 seconds into years
Explanation:
no. of seconds in a year = 60 × 60 × 24 × 365
= 31,536,000 seconds
so 2.05 × 10⁵ into years = 0.0065 years (approximately)
a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported
Answer:
Explanation:
You can calculate the total electric charge that passes through the conductor as [tex]q=It=(180\times 10^{-3})(5\times 60)= 54 C[/tex]. It means that the number of electron that passes through the conductor is:
[tex]n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}[/tex]
Two children are playing tetherball, in which a ball at the end of a cord spins around a pole. After a really good hit, the ball makes three complete revolutions in 2.0 s. What is the angular speed of the ball?
Answer:
3 pi R / s or 9.42 R/s or 540 degrees/sec
Explanation:
Ball covers 2 pi radians each rotation
2 pi * 3 R / 2 s = 3 pi R / s
the angular speed of the ball is 3 pi R / s or 9.42 R/s or 540 degrees/sec
What is angular speed ?Angular speed can be defined as the measures of speed of how fast the central angle of a rotating body changes with respect to time
Angular speed mainly implies how quickly the rotation of an object occur means it is described as the change in the angle of the object per unit of time.
To calculate the speed of a rotational motion the angular speed value need to be known, hence The angular speeds formula is used to calculate the distance traveled by an object in terms of rotation and revolutions per unit of time.
The unit of angular speed of an object is radian per second and Both angular speed, angular velocity are determined by using the same formula, angular velocity is vector quantity which describes both magnitude and direction.
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Which of the rays drawn above would be correct as the light goes from the air into the water?
Answer:
the answer to this question is option c
there process which eventually takes place is called refraction
Explanation:
please do consider as brainlest if useful
Which statement is true about a wave that is created by causing vibrations in
particles of matter?
A. It can travel through empty space.
B. It is not an electromagnetic wave.
C. It does not need a medium.
D. It moves through a magnetic or electric field.
Answer:
A
Explanation:
A. it can travel through empty space
What is the best definition of
work?
A. net force equals zero
B. a force exerted over a distance
a
C. pair of forces where one is of greater strength
Answer:
Work is best defined as a force exerted on a body to cause it move over a certain distance.
work=force×displacement×cosθ
Explanation:
A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to the block. The magnitude of the block's acceleration is 1.2 m/s2. If P is increased to 5.0 N, determine the magnitude of the block's
When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².
Frictional force between the block and the horizontal surfaceThe frictional force between the block and the horizontal surface is determined by applying Newton's law;
∑F = ma
F - Ff = ma
Ff = F - ma
Ff = 4 - 2(1.2)
Ff = 4 - 2.4
Ff = 1.6 N
When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;
F - Ff = ma
5 - 1.6 = 2a
3.4 = 2a
a = 3.4/2
a = 1.7 m/s²
Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².
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Physics Help anyone?
Hi there!
A)
At this point, the pilot is experiencing a DOWNWARD NET centripetal force (ALWAYS points towards the center of the circle) as well as a downward force due to gravity. Additionally, we can say that the normal force exerted by the seat on the pilot is its apparent weight.
[tex]\Sigma F = F_g + F_N[/tex]
**The net force is the centripetal force.
We can assign both to be positive since they work in the same direction. (Assigning down as positive in THIS situation will make things easier).
We know that:
[tex]F_c = \frac{mv^2}{r}[/tex]
Fc = Centripetal force (N)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
[tex]F_g = mg[/tex]
Fg = Force due to gravity (N)
m = mass (kg)
g = acceleration due to gravity (9.81 m/s²)
Solve for mass. (Given weight)
[tex]m = \frac{F_g}{g}\\\\m = \frac{719}{9.8} = 73.367 kg[/tex]
Now, we have everything we need to solve.
[tex]\frac{mv^2}{r} = F_g + F_N \\\\\frac{mv^2}{r} - F_g = F_N\\\\F_N = \frac{(73.367)(225^2)}{3110} - 719 = \boxed{475.278 N}[/tex]
B)
Weightlessness is achieved when the pilot is in free fall. In this instance, FN (Normal force by the seat) = 0 N.
We can use the same setup as above.
[tex]\frac{mv^2}{r} = F_g + 0 (F_N)[/tex]
[tex]\frac{mv^2}{r} = mg[/tex]
Solve for 'v'.
[tex]\frac{v^2}{r} = g\\\\v = \sqrt{gr} = \sqrt{(9.81)(3110)} = \boxed{174.669 \frac{m}{s}}[/tex]
C)
At the BOTTOM, we have the force of gravity working DOWNWARD (Negative in this instance), while the centripetal force (NET FORCE) and normal force are upward (Positive). Do another summation of forces:
[tex]\Sigma F = F_N - F_g\\\\\\frac{mv^2}{r} + F_g = F_N \\\\F_N = \frac{(73.367)(225^2)}{3110} + 719 = \boxed{1913.278 N}[/tex]
An object moving in a straight line has a velocity v in m/s that varies with time t in s according the following function. v= 8+2.5 12 to 11. The instantaneous acceleration of the object at t = 2 sis (A) 2 m/s (B) 4 m/s (0) 6 m/s2 D) 8 m/s2 (E) 10 m/s2 12. The displacement of the object between t = 0 and t = 6 s is (A) 120 m (B) 180 m (C) 228 m (D) 242 m (E) 260 m
The instant acceleration of the object is 10 m/s² and the displacement of the object is 228 m.
Instantaneous acceleration
The instant acceleration of the object is determined by taking the derivative of the velocity as follows;
v = 8 + 2.5t²
a = dv/dt
a = 5t
a(2) = 5(2)
a(2) = 10 m/s²
Displacement of objectThe displacement of the object is determined by taking the integral of velocity as follows;
v = 8 + 2.5t²
x = ∫v
x = 8t + 2.5t³/3
x(0) = 0
x(6) = 8(6) + 2.5(6)³/3
x(6) = 228 m
Thus, the displacement of the object is 228 m.
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In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks to it. The strings are both 50.0 cm long. The upper ball has a mass of 2.20 kg and it is initially 10.0 cm higher than the lower ball, which has a mass of 2.70 kg. Find the frequency of the motion after the collision. Find the maximum angular displacement of the motion after the collision.
(a) The frequency of the motion after the collision is 0.71 Hz.
(b) The maximum angular displacement of the motion after the collision is 16.3⁰.
Speed of the 2.2 kg ball when it collides with 2.7 kg ballThe speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 0.1)
v = 1.4 m/s
Final speed of both balls after collisionThe final speed of both balls after the collision is determined from the principle of conservation of linear momentum.
Pi = Pf
m₁v₁ + m₂v₂ = vf(m₁ + m₂)
2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)
3.08 = 4.9vf
vf = 3.08/4.9
vf = 0.63 m/s
Maximum displacement of the balls after the collisionP.E = K.E
[tex]mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m[/tex]
Maximum angular displacementThe maximum angular displacement of the balls after the collision is calculated as follows;
[tex]cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0[/tex]
Frequency of the motion[tex]f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz[/tex]
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you move a 25 N object 5.0 meters. how much work did you do?
Answer:
125J
Explanation:
[tex]work \: = force \: \times distance \\ = 25 \times 5 \\ = 125joules[/tex]
A toy car, with mass of 6 Kg, is pushed with a force of 10 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration?
How far does it get pushed in 10 s?
Residents of a community currently pay a fee for recreational services in their neighborhood, such as tennis courts, running trails, a pool. To assess whether there is support for raising a fee for the upcoming summer, a random sample of 50 residents is contracted and asked this question: “Would you support a $10 increase in the recreational fee to support programs for the health and well-being of the children in the community?” Of the 50 residents contacted, 42 approved of the fee increase. Which statement describes a likely source of bias present in survey results?
A likely source of bias in the survey is undercoverage bias because some parts of the community may not be represented in the survey results.
Bias present in the surveyThe bias present in the survey may lead to error in the result obtained from the random sampling survey.
Source of bias in the surveyOne of the likely source of bias in the survey is undercoverage.
It is not possible to ascertain the accurate opinion of the entire community from the 50 residents chosen for the survey.
Thus, a likely source of bias present in survey is undercoverage bias because some parts of the community may not be represented in the survey results.
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Answer:
B. Question wording bias may be present because the question leads those responding toward a certain response.
Explanation:
Difine Ripple Factor
-,- ty!!
Answer:
The answer is in the picture above.
Two horses pull horizontally on ropes attached to a stump. The two forces Fu and F2 that they apply to the stump are such that the net (resultant) force R has a magnitude equal to that of Fu and makes an angle of 90° with Fu. Let F1 = 1300 N and R = 1300 N also. Find the magnitude of F and its direction (relative to Fi)
For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as
F=1711 N
dF= 135 degrees
What is the magnitude of F and its direction?
Generally, the equation for the components of F1 is mathematically given as
For The x axis
1210 - F2x = 0
F2x = 1210
For the y axis
F2y = R
F2y = 1210
In conclusion
F = sqrt(2)*1210
F=1711 N
Fopt the direction of F2
dF= 90 + 45
dF= 135 degrees
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.. In the reaction 238 92U ---- X + 2 4 He, the particle represented by X is . answer choices . 234 90 Th. 234 92 U. 238 93 Np. 242 94Pu. ... Which conditions are required
My question
• Complete the following reaction:
238 92U = ______ + ________ + 4 2He
…Is this the same question as the answer
Answer:
234 90 +energy
Explanation:
because alpha decrease by 4 2helium
Which nucleus completes the following equation?
Answer:
I think that CL IS THE ONLY BEST ANSWER
Explanation:
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
How long does it take a photon to escape the sun?
Answer:
About 5000 years.
Explanation:
Answer:
Explanation:
it will take more than half a million years for the photon to escape the sun. If you think it's about a centimeter, then it will take about 5,000 years for the photon to get outside the su
Find the magnitude of the sum of these two vectors:
Answer:
Explanation:
You can decompose those vectors into their components in x and y direction. For the first vector:
[tex]\vec{r}_{1}=r_{1}\cos 30\hat{i}+r_{1}\sin 30\hat{j}=3.14(\frac{1}{2}\sqrt{3}\hat{i}+\frac{1}{2}\hat{j})=1.57\sqrt{3}\hat{i}+1.57\hat{j}[/tex]
For the second vector:
[tex]\vec{r}_{2}=r_{2}\cos 60\hat{i}-r_{2}\sin60 \hat{j}=1.355\hat{i}-1.355\sqrt{3}\hat{j}[/tex]
The sum of two vectors will be:
[tex]\vec{r}=\vec{r}_{1}+\vec{r}_{2}=(1.57\sqrt{3}+1.355)\hat{i}+(1.57-1.355\sqrt{3})\hat{j}\approx 4.0711\hat{i}-0.77415\hat{j}[/tex]
The magnitude of the sum of two vectors is:
[tex]r=\sqrt{(4.0711)^{2}+(-0.77415)^{2}}\approx 4.14[/tex] meter
Answer:
4.14m
Explanation:
The three types of cones in the human eye are
a
red, yellow, green
b
red, green, blue
c
red, blue, cyan
d
yellow, cyan, magenta
Answer:
the answer is B I hope it helps out
1. A drag racer accelerates from rest at 18ft/sec^2. How long does it take to acquire a speed of 60mph? What is required?
2. A contestant ran a 100-m dash in 10.6sec. What was his speed a) In feet per second and b) in miles per hr?
(1) The time taken for the drag racer to accelerate is 4.89 s
(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.
(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.
Formula:
t = (v-u)/a........... Equation 1Where:
t = timev = Final velocityu = initial velocitya = acceleration.From the question,
Given:
a = 18 ft/sec² = (18×0.3048) = 5.4864 m/s²v = 60 mph = (60×0.44704) = 26.82 m/su = 0 m/s ( from rest)Substitute these values into equation 1
t = (26.82-0)/5.4864t = 4.89 seconds(2) To calculate the speed of the contestant, we use the formula below
Formula:
s = d/t............ Equation 1Where:
s = speed of the contestantd = distancet = time.From the question,
Given:
d = 100 mt = 10.6 sSubstitute these values into equation 1
s = 100/10.6s = 9.43 m/s(a) In feet = (9.43/0.3048) = 30.94 ft/s
(b) in miles per hr = (9.43×2.24) = 21.12 miles per hr
Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.
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What does the atomic numbers equal? A number of protons in the atomic nucleus B number of protons and neutrons in the atomic nucleus C number of neutrons in the atomic nucleus
number of protons
explanation:the atomic number of an atom is equal to the number of protons
When a speeding truck hits a stationary car, the car is deformed and heat is generated. What can you say about the kinetic energy of the system after the collision?
nothing
Explanation:
we can say that it was certainly bad for the shopkeeper obviously and we should not be making questions about the physics behind that accident and should call the cops or 911
Can a machine multiply both force and speed at same time??
Answer:
No
Explanation:
It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.
It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.
a 56-kg student runs at 6.2m/s, grabs a hanging 10.0m long rope, and swings out over a lake. He releases the rope when his velocity is zero.
a) what is the tension in the rope just before he releases it?
b) what is the maximum tension in the rope during the swing?
Answer:
0.52 8.9
Explanation:
calc.
The tension in the rope just before the student releases it is 576 N.
What is tension?Tension is defined in physics as the pulling force transmitted axially by a string, rope, chain, or similar object.
Just before the student releases the rope, his velocity is zero. At this point, all of his kinetic energy has been converted into potential energy. Therefore, we can write:
1/2 m [tex]v^2[/tex] = mgh
h = [tex]v^2[/tex] / (2g) = [tex](6.2 m/s)^2[/tex] / (2 x 9.8 [tex]m/s^2[/tex]) ≈ 1.95 m
m g = 56 kg x 9.8 [tex]m/s^2[/tex] ≈ 549 N
The tension required to keep the rope taut is equal to the horizontal component of the force due to the weight of the student, which is:
T = m g / cos(θ)
tan(θ) = h / L
tan(θ) = 1.95 m / 10.0 m ≈ 0.195
θ ≈ 10.9°
So, T = m g / cos(θ) ≈ 576 N
To find the maximum tension in the rope during the swing, we can use conservation of angular momentum.
L = I ω
I = (1/3) m [tex]L^2[/tex]
I = (1/3) x 10.0 kg x [tex](10.0 m)^2[/tex] ≈ 3333.3 kg[tex]m^2[/tex]
The angular velocity of the rope just after the student releases it is:
ω = v / L
ω = 6.2 m/s / 10.0 m ≈ 0.62 rad/s
L = I ω ≈ 2070 N m s
Thus, the angular momentum of the system just after the student releases the rope is 2070 N m s.
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A simple circuit has a voltage of 8V and a current of 3A. Find the resistance (R) in the
circuit.
Answer:
2.67 ohm
Explanation:
V=IR
R=V/I
In which V is voltage and I is current and R is resistance
why do fennec fox have big ears? explain why in big detail!
Answer:
Explanation:
The fennec may be the world's smallest fox, but it sports outlandishly large ears! In fact, relative to body size, it has the largest ears of any member of the canid family. It uses those big ears to listen for sounds of prey in the sand. The ears also help dispel body heat to keep the fox cool.
at 27 degrees C and 750 mmhg a sample of hydrogen occupies 5.0 L how much space will occupy at STP
Answer:
Explanation:
The number of mole of the hydrogen sample at 27 C and 750 mmHg pressure is:
[tex]n=\frac{PV}{RT}=\frac{(0.9898\times 10^{5})(5\times 10^{-3})}{(8.314)(27+273)}\approx 0.0198[/tex] mol
This number of mole will be the same although we change the pressure and temperature. For STP (Temperature = 0 C = 273 K, and Pressure = 760 mmHg = 76 cmHg = 1 Bar = 1.01 x [tex]10^{5}[/tex] Pa):
[tex]P'V'=nRT' \rightarrow V'=\frac{nRT'}{P'}=\frac{0.0198(8.314)(273)}{1.01\times 10^{5}}\approx 44.49 \times 10^{-5}[/tex] in [tex]m^{3}[/tex]. But in L, we find that V' = 0.4449 L
