An areosynchronous
satellite orbits
Mars (mass = 6.42 x 1023 kg) once
every Martian day, 88640 s. At what
radius does it orbit?
[?] x 10
Coefficient (green)
[?]
m
Exponent (yellow)
Enter
E

An Areosynchronoussatellite OrbitsMars (mass = 6.42 X 1023 Kg) Onceevery Martian Day, 88640 S. At Whatradius

Answers

Answer 1

The satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters

How to solve for the time that the satellite orbits Mars

= [(T²GM)/(4π²)]¹/³)

Substituting the given values:

r = [(88640²)(6.67430 x 10⁻¹¹)(6.42 x 10²³) / (4π²)]¹/³

Calculating this expression, we find:

r = 2.043 x 10⁷ meters

Therefore, the satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters

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Related Questions

If the density of the object varies linearly with x-that is, ρ=αx , where α is a positive constant-calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .

Answers

The  x-coordinate of the center of mass of the object if the density of the object varies linearly with x-that is, ρ=αx is X = 2L/3

What is center of mass?

The center of mass of an object is the position at which the mass of the object appears to be concentrated.

If the density of an object varies linearly with x-that is, ρ=αx , where α is a positive constant. Calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .

We proceed as follows

The x-coordinate of the center of mass is given by

X = ∫xdM/∫dM where

x = coordinate of differential element dM,dM = ρdx where ρ = density of object = αx and dx = differential length element

So, substituting these into the equation, we have

X = ∫xdM/∫dM

X = ∫xρdx/∫ρdx

X = ∫x(αx)dx/∫αxdx

X = ∫αx²dx/∫αxdx

X = α∫x²dx/α∫xdx

X = ∫x²dx/∫xdx

We integrate x from x = 0 to x = L. So, we have

X = ∫x²dx/∫xdx

X = x²⁺¹/(2 + 1)/x¹⁺¹/(1 + 1)

X = [x³/3]₀ˣ/[x²/2]₀ˣ

X = [L³/3 - 0³/3]/[L²/2 - 0²/3]

X = [L³/3 - 0³/3]/[L²/2 - 0²/3]

X = [L³/3 - 0]/[L²/2 - 0]

X = L³/3/L²/2

X = 2L/3

So,the x-coordinate is X = 2L/3

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During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger

Answers

During an earthquake, it is important to take appropriate steps to ensure safety

Steps you can follow in two different scenarios

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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What's Kinetic energy Give definition

Answers

Answer:

Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work

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